Month: May 2024
Teams Access Permission
Hello
Please i need your help on this issue.
We created a Notetaker account and bought a Microsoft Teams Essential license for Microsoft Teams – however, now when we try to login it says “You don’t have the required permissions to access this org”.
When we try to assign the Teams Essential license last month and we get still the above error message. But now the Teams Essential license has expired and i dont want to purchase another Teams Essential license then it does not work
As of now we only have Microsoft 365 Business Basic license for one seat count which has been assigned to a user and Microsoft 365 Business Standard for four seat count which has been assigned to four users.
Since we do not have any other license available and our Teams essential license has expired. We dont want to purchase another Teams Essential license then it does not work
Is there another way out or is it possible to get another Teams exploratory license or Teams free license.
Previously we had a Teams Exploratory license but is it possible to get another Teams Free license.
Do you know why this might be? Thank you!
Hello Please i need your help on this issue. We created a Notetaker account and bought a Microsoft Teams Essential license for Microsoft Teams – however, now when we try to login it says “You don’t have the required permissions to access this org”.When we try to assign the Teams Essential license last month and we get still the above error message. But now the Teams Essential license has expired and i dont want to purchase another Teams Essential license then it does not work As of now we only have Microsoft 365 Business Basic license for one seat count which has been assigned to a user and Microsoft 365 Business Standard for four seat count which has been assigned to four users. Since we do not have any other license available and our Teams essential license has expired. We dont want to purchase another Teams Essential license then it does not work Is there another way out or is it possible to get another Teams exploratory license or Teams free license. Previously we had a Teams Exploratory license but is it possible to get another Teams Free license. Do you know why this might be? Thank you! Read More
How to Resolve Accounting Software Desktop Error 40001
I’ve been encountering an accounting software desktop error 40001 while using QuickBks. The error appears during updates, and I’m unable to process payrll for my employees. How can I resolve this issue? Any help would be greatly appreciated.
I’ve been encountering an accounting software desktop error 40001 while using QuickBks. The error appears during updates, and I’m unable to process payrll for my employees. How can I resolve this issue? Any help would be greatly appreciated. Read More
Crank-Nicholson method
I am trying too apply Crank-Nicholson method for the following example;
and I have applied the following scheme
I have written the following code but the error is very big and I can’t see where is my mistake
clear all
close all
clc
% Parameters
L = 1; % Length of the rod
T = 1; % Total time
Nx = 10; % Number of spatial grid points
Nt = 50; % Number of time steps
a = 1; % Thermal diffusivity
dx = L / (Nx); % Spatial step size
dt = T / Nt; % Time step size
x = linspace(0, L, Nx); % Spatial grid
t = linspace(0, T, Nt); % Time grid
lx = linspace(0, L, Nx); % Spatial grid
lt = linspace(0, T, Nt);
Exc = @(x,t) x.^2.*exp(t);
[X,T] = meshgrid(lx,lt);
figure(1)
subplot(1,2,1)
surf(X,T,Exc(X,T))
xlabel(‘Space’)
ylabel(‘Time’)
zlabel(‘Temprature’)
title(‘The Exact solution of heat equation ‘)
subplot(1,2,2)
plot(lx,Exc(lx,0),’b’,lx,Exc(lx,0.02),lx,Exc(lx,0.04),lx,Exc(lx,0.06))
grid on
title(‘The Exact at different time level’)
xlabel(‘x’)
ylabel(‘u’)
% Initial condition
u = zeros(Nx,Nt);
% Boundary conditions (assumed zero for simplicity)
u( 1,:) = 0;
u( end,:) = exp(t(:));
%initial condition
u(2:Nx-1,1) = x(2:Nx-1).^2;
% Source term function
f = @(x, t) x.^2-2.*exp(t); % Example source term
% Construct the matrices A and B
Lambda = a * dt / (2 * dx^2);
A = diag((1 + 2*Lambda) * ones(Nx-2, 1)) + diag(-Lambda * ones(Nx-3, 1), 1) + diag(-Lambda * ones(Nx-3, 1), -1);
B = diag((1 – 2*Lambda) * ones(Nx-2, 1)) + diag(Lambda * ones(Nx-3, 1), 1) + diag(Lambda * ones(Nx-3, 1), -1);
% Time-stepping loop
for n = 1:Nt-1
% Source term at time levels n and n+1
f_n = f(x(2:end-1), t(n));
f_np1 = f(x(2:end-1), t(n+1));
% Right-hand side vector
b = B * u(2:end-1,n) + 0.5 * dt * (f_n’ + f_np1′);
% Solve the linear system A * u_new = b
u(2:end-1,n+1)=bA;
%u(2:end-1,n+1) = inv(A)*B*u(2:end-1, n) + 0.5 *dt*inv(A)*(f_n’ + f_np1′);
end
u;
% Visualization
figure(3)
subplot(2,2,1)
surf(x,t,u’)
colormap(‘pink’);
title(‘The approximate solution by Euler forward method for lambda =’,Lambda)
xlabel(‘Space’)
ylabel(‘time’)
zlabel(‘Temperature’)
grid on
subplot(2,2,2)
plot(x,u(:,1),’o’,lx,Exc(lx,0),’b’,x,u(:,round(Nt/4)),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(:,round(Nt/2)),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(:,round(3*Nt/4)),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(:,end),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
%plot(x,u(1,:),’o’,lx,Exc(lx,0),’b’,x,u(round(Nt/4),:),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(round(Nt/2),:),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(round(3*Nt/4),:),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(end,:),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
title(‘Temperature at different time level’)
xlabel(‘x’)
ylabel(‘T’)
grid on
legend(‘num sol at t=0′,’Exact sol at t=0′,’num sol at t=0.02′,’Exact sol at t=0.02′,’num sol at t=0.04′,’Exact sol at t=0.04′,’num sol at t=0.06′,’Exact sol at t=0.06’)
subplot(2,2,3)
AE=abs(Exc(lx,lt(1))-u(:,1));
AE1=abs(Exc(lx,lt(round(Nt/4)))-u(:,round(Nt/4)));
AE2=abs(Exc(lx,lt(round(Nt/3)))-u(:,round(Nt/3)));
AE3=abs(Exc(lx,lt(round(Nt/2)))-u(:,round(Nt/2)));
AE4=abs(Exc(lx,lt(round(3*Nt/4)))-u(:,round(3*Nt/4)));
AE5=abs(Exc(lx,lt(end))-u(:,end));
lt1=lt(1);
plot(x,AE,’–‘,x,AE1,’o’,x,AE3,’b’,x,AE4,’g’,x,AE5,’LineWidth’,1)
title(‘Absolute error at different time level’)
grid on
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
subplot(2,2,4)
RE=AE./Exc(lx,lt(1));
RE1=AE1./Exc(lx,lt(round(Nt/4)));
RE2=AE2./Exc(lx,lt(round(Nt/3)));
RE3=AE3./Exc(lx,lt(round(Nt/2)));
RE4=AE4./Exc(lx,lt(round(3*Nt/4)));
RE5=AE5/Exc(lx,lt(end));
plot(x,RE,x,RE1,’–‘,x,RE3,’*’,x,RE4,’b’,x,RE5,’r’,’LineWidth’,1)
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
grid on
title(‘Relative error at different time level’)I am trying too apply Crank-Nicholson method for the following example;
and I have applied the following scheme
I have written the following code but the error is very big and I can’t see where is my mistake
clear all
close all
clc
% Parameters
L = 1; % Length of the rod
T = 1; % Total time
Nx = 10; % Number of spatial grid points
Nt = 50; % Number of time steps
a = 1; % Thermal diffusivity
dx = L / (Nx); % Spatial step size
dt = T / Nt; % Time step size
x = linspace(0, L, Nx); % Spatial grid
t = linspace(0, T, Nt); % Time grid
lx = linspace(0, L, Nx); % Spatial grid
lt = linspace(0, T, Nt);
Exc = @(x,t) x.^2.*exp(t);
[X,T] = meshgrid(lx,lt);
figure(1)
subplot(1,2,1)
surf(X,T,Exc(X,T))
xlabel(‘Space’)
ylabel(‘Time’)
zlabel(‘Temprature’)
title(‘The Exact solution of heat equation ‘)
subplot(1,2,2)
plot(lx,Exc(lx,0),’b’,lx,Exc(lx,0.02),lx,Exc(lx,0.04),lx,Exc(lx,0.06))
grid on
title(‘The Exact at different time level’)
xlabel(‘x’)
ylabel(‘u’)
% Initial condition
u = zeros(Nx,Nt);
% Boundary conditions (assumed zero for simplicity)
u( 1,:) = 0;
u( end,:) = exp(t(:));
%initial condition
u(2:Nx-1,1) = x(2:Nx-1).^2;
% Source term function
f = @(x, t) x.^2-2.*exp(t); % Example source term
% Construct the matrices A and B
Lambda = a * dt / (2 * dx^2);
A = diag((1 + 2*Lambda) * ones(Nx-2, 1)) + diag(-Lambda * ones(Nx-3, 1), 1) + diag(-Lambda * ones(Nx-3, 1), -1);
B = diag((1 – 2*Lambda) * ones(Nx-2, 1)) + diag(Lambda * ones(Nx-3, 1), 1) + diag(Lambda * ones(Nx-3, 1), -1);
% Time-stepping loop
for n = 1:Nt-1
% Source term at time levels n and n+1
f_n = f(x(2:end-1), t(n));
f_np1 = f(x(2:end-1), t(n+1));
% Right-hand side vector
b = B * u(2:end-1,n) + 0.5 * dt * (f_n’ + f_np1′);
% Solve the linear system A * u_new = b
u(2:end-1,n+1)=bA;
%u(2:end-1,n+1) = inv(A)*B*u(2:end-1, n) + 0.5 *dt*inv(A)*(f_n’ + f_np1′);
end
u;
% Visualization
figure(3)
subplot(2,2,1)
surf(x,t,u’)
colormap(‘pink’);
title(‘The approximate solution by Euler forward method for lambda =’,Lambda)
xlabel(‘Space’)
ylabel(‘time’)
zlabel(‘Temperature’)
grid on
subplot(2,2,2)
plot(x,u(:,1),’o’,lx,Exc(lx,0),’b’,x,u(:,round(Nt/4)),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(:,round(Nt/2)),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(:,round(3*Nt/4)),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(:,end),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
%plot(x,u(1,:),’o’,lx,Exc(lx,0),’b’,x,u(round(Nt/4),:),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(round(Nt/2),:),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(round(3*Nt/4),:),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(end,:),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
title(‘Temperature at different time level’)
xlabel(‘x’)
ylabel(‘T’)
grid on
legend(‘num sol at t=0′,’Exact sol at t=0′,’num sol at t=0.02′,’Exact sol at t=0.02′,’num sol at t=0.04′,’Exact sol at t=0.04′,’num sol at t=0.06′,’Exact sol at t=0.06’)
subplot(2,2,3)
AE=abs(Exc(lx,lt(1))-u(:,1));
AE1=abs(Exc(lx,lt(round(Nt/4)))-u(:,round(Nt/4)));
AE2=abs(Exc(lx,lt(round(Nt/3)))-u(:,round(Nt/3)));
AE3=abs(Exc(lx,lt(round(Nt/2)))-u(:,round(Nt/2)));
AE4=abs(Exc(lx,lt(round(3*Nt/4)))-u(:,round(3*Nt/4)));
AE5=abs(Exc(lx,lt(end))-u(:,end));
lt1=lt(1);
plot(x,AE,’–‘,x,AE1,’o’,x,AE3,’b’,x,AE4,’g’,x,AE5,’LineWidth’,1)
title(‘Absolute error at different time level’)
grid on
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
subplot(2,2,4)
RE=AE./Exc(lx,lt(1));
RE1=AE1./Exc(lx,lt(round(Nt/4)));
RE2=AE2./Exc(lx,lt(round(Nt/3)));
RE3=AE3./Exc(lx,lt(round(Nt/2)));
RE4=AE4./Exc(lx,lt(round(3*Nt/4)));
RE5=AE5/Exc(lx,lt(end));
plot(x,RE,x,RE1,’–‘,x,RE3,’*’,x,RE4,’b’,x,RE5,’r’,’LineWidth’,1)
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
grid on
title(‘Relative error at different time level’) I am trying too apply Crank-Nicholson method for the following example;
and I have applied the following scheme
I have written the following code but the error is very big and I can’t see where is my mistake
clear all
close all
clc
% Parameters
L = 1; % Length of the rod
T = 1; % Total time
Nx = 10; % Number of spatial grid points
Nt = 50; % Number of time steps
a = 1; % Thermal diffusivity
dx = L / (Nx); % Spatial step size
dt = T / Nt; % Time step size
x = linspace(0, L, Nx); % Spatial grid
t = linspace(0, T, Nt); % Time grid
lx = linspace(0, L, Nx); % Spatial grid
lt = linspace(0, T, Nt);
Exc = @(x,t) x.^2.*exp(t);
[X,T] = meshgrid(lx,lt);
figure(1)
subplot(1,2,1)
surf(X,T,Exc(X,T))
xlabel(‘Space’)
ylabel(‘Time’)
zlabel(‘Temprature’)
title(‘The Exact solution of heat equation ‘)
subplot(1,2,2)
plot(lx,Exc(lx,0),’b’,lx,Exc(lx,0.02),lx,Exc(lx,0.04),lx,Exc(lx,0.06))
grid on
title(‘The Exact at different time level’)
xlabel(‘x’)
ylabel(‘u’)
% Initial condition
u = zeros(Nx,Nt);
% Boundary conditions (assumed zero for simplicity)
u( 1,:) = 0;
u( end,:) = exp(t(:));
%initial condition
u(2:Nx-1,1) = x(2:Nx-1).^2;
% Source term function
f = @(x, t) x.^2-2.*exp(t); % Example source term
% Construct the matrices A and B
Lambda = a * dt / (2 * dx^2);
A = diag((1 + 2*Lambda) * ones(Nx-2, 1)) + diag(-Lambda * ones(Nx-3, 1), 1) + diag(-Lambda * ones(Nx-3, 1), -1);
B = diag((1 – 2*Lambda) * ones(Nx-2, 1)) + diag(Lambda * ones(Nx-3, 1), 1) + diag(Lambda * ones(Nx-3, 1), -1);
% Time-stepping loop
for n = 1:Nt-1
% Source term at time levels n and n+1
f_n = f(x(2:end-1), t(n));
f_np1 = f(x(2:end-1), t(n+1));
% Right-hand side vector
b = B * u(2:end-1,n) + 0.5 * dt * (f_n’ + f_np1′);
% Solve the linear system A * u_new = b
u(2:end-1,n+1)=bA;
%u(2:end-1,n+1) = inv(A)*B*u(2:end-1, n) + 0.5 *dt*inv(A)*(f_n’ + f_np1′);
end
u;
% Visualization
figure(3)
subplot(2,2,1)
surf(x,t,u’)
colormap(‘pink’);
title(‘The approximate solution by Euler forward method for lambda =’,Lambda)
xlabel(‘Space’)
ylabel(‘time’)
zlabel(‘Temperature’)
grid on
subplot(2,2,2)
plot(x,u(:,1),’o’,lx,Exc(lx,0),’b’,x,u(:,round(Nt/4)),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(:,round(Nt/2)),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(:,round(3*Nt/4)),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(:,end),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
%plot(x,u(1,:),’o’,lx,Exc(lx,0),’b’,x,u(round(Nt/4),:),’o’,lx,Exc(lx,lt(round(Nt/4))),’–g’,x,u(round(Nt/2),:),’o’,lx,Exc(lx,lt(round(Nt/2))), x,u(round(3*Nt/4),:),’o’,lx,Exc(lx,lt(round(3*Nt/4))),’:b’,x,u(end,:),’o’,lx,Exc(lx,lt(end)),’LineWidth’,1)
title(‘Temperature at different time level’)
xlabel(‘x’)
ylabel(‘T’)
grid on
legend(‘num sol at t=0′,’Exact sol at t=0′,’num sol at t=0.02′,’Exact sol at t=0.02′,’num sol at t=0.04′,’Exact sol at t=0.04′,’num sol at t=0.06′,’Exact sol at t=0.06’)
subplot(2,2,3)
AE=abs(Exc(lx,lt(1))-u(:,1));
AE1=abs(Exc(lx,lt(round(Nt/4)))-u(:,round(Nt/4)));
AE2=abs(Exc(lx,lt(round(Nt/3)))-u(:,round(Nt/3)));
AE3=abs(Exc(lx,lt(round(Nt/2)))-u(:,round(Nt/2)));
AE4=abs(Exc(lx,lt(round(3*Nt/4)))-u(:,round(3*Nt/4)));
AE5=abs(Exc(lx,lt(end))-u(:,end));
lt1=lt(1);
plot(x,AE,’–‘,x,AE1,’o’,x,AE3,’b’,x,AE4,’g’,x,AE5,’LineWidth’,1)
title(‘Absolute error at different time level’)
grid on
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
subplot(2,2,4)
RE=AE./Exc(lx,lt(1));
RE1=AE1./Exc(lx,lt(round(Nt/4)));
RE2=AE2./Exc(lx,lt(round(Nt/3)));
RE3=AE3./Exc(lx,lt(round(Nt/2)));
RE4=AE4./Exc(lx,lt(round(3*Nt/4)));
RE5=AE5/Exc(lx,lt(end));
plot(x,RE,x,RE1,’–‘,x,RE3,’*’,x,RE4,’b’,x,RE5,’r’,’LineWidth’,1)
legend(‘Error at t=0′,’Error at 1/4 of the time’,’Error at 1/2 of the time’,’Error at 3/4 of the time’,’Error at end of the time’)
grid on
title(‘Relative error at different time level’) mathematics, nonlinear, differential equations MATLAB Answers — New Questions
How do I fit a 3rd order polynomial Basis using fitrgp?
Hello,
I am trying to fit a 3rd order polynomial basis using fitgrp for my signal (1×1503). From the instructions, it looks like I would pass hfcn but don’t quite understand how to implement this for the 3rd order polynomial. How would I do this?
Here is code but at the moment it is only implementing a quadratic:
t_observed = (0:length(dodWavelet(:,1))-1)/10;
y_observed = dodWavelet(:,1);
gprMdl1 = fitrgp(t_observed’,y_observed,’Basis’,"pureQuadratic");
[ypred1] = predict(gprMdl1,t_observed’);Hello,
I am trying to fit a 3rd order polynomial basis using fitgrp for my signal (1×1503). From the instructions, it looks like I would pass hfcn but don’t quite understand how to implement this for the 3rd order polynomial. How would I do this?
Here is code but at the moment it is only implementing a quadratic:
t_observed = (0:length(dodWavelet(:,1))-1)/10;
y_observed = dodWavelet(:,1);
gprMdl1 = fitrgp(t_observed’,y_observed,’Basis’,"pureQuadratic");
[ypred1] = predict(gprMdl1,t_observed’); Hello,
I am trying to fit a 3rd order polynomial basis using fitgrp for my signal (1×1503). From the instructions, it looks like I would pass hfcn but don’t quite understand how to implement this for the 3rd order polynomial. How would I do this?
Here is code but at the moment it is only implementing a quadratic:
t_observed = (0:length(dodWavelet(:,1))-1)/10;
y_observed = dodWavelet(:,1);
gprMdl1 = fitrgp(t_observed’,y_observed,’Basis’,"pureQuadratic");
[ypred1] = predict(gprMdl1,t_observed’); functions, curve fitting, fitrgp MATLAB Answers — New Questions
Need Help with Date Formatting for SharePoint Event List
Hello everyone,
I have a requirement where I need to save data to a SharePoint event list using a modal form and display the data as cards on a webpage. However, I’m encountering an issue with date formatting. The dates are not displaying correctly.
I have tried several approaches, including:
Saving the date in UTC format and converting it to local time when displaying.Using ISO format for date storage and display.
Despite these efforts, the dates are still not showing correctly. Has anyone faced a similar issue or have suggestions on how to resolve this?
Thank you in advance for your help!
Hello everyone, I have a requirement where I need to save data to a SharePoint event list using a modal form and display the data as cards on a webpage. However, I’m encountering an issue with date formatting. The dates are not displaying correctly. I have tried several approaches, including: Saving the date in UTC format and converting it to local time when displaying.Using ISO format for date storage and display.Despite these efforts, the dates are still not showing correctly. Has anyone faced a similar issue or have suggestions on how to resolve this? Thank you in advance for your help! $().SPServices( { operation: “UpdateListItems”, async: false, webURL: webURL, batchCmd: “New”, listName: “Events”, valuepairs: [ [“Title”, Title], [“EventDate”, EventDate], [“EndDate”, EndDate], [“Location”, Location], [“Category”, Category], [“Description”, Description] ], completefunc: function(xData, Status) { EventId = $(xData.responseXML).SPFilterNode(“z:row”).attr(“ows_ID”); if(EventId > 0){ GetEventData(); } } }); Read More
How to download Excel Formula worksheet
I have needed Microsoft Excel Formula for personal guidance
I have needed Microsoft Excel Formula for personal guidance Read More
How to delay sending of ALL emails ?
Ok, this shouldn’t have to be asked, but I can find no way in MS Office Pro Outlook 2021 to set a delay time in minutes to hold sent messages in the outbox before sending. How to do this?
Thanks.
Ok, this shouldn’t have to be asked, but I can find no way in MS Office Pro Outlook 2021 to set a delay time in minutes to hold sent messages in the outbox before sending. How to do this? Thanks. Read More
When is Network Profile Issue for Domain Controllers going to be at least acknowledged?
Since the insider builds from 25398 to the latest 26227 all have the same bug where the domain controller on the builds will show the network category as Public instead of DomainAuthenticated and the only way to fix it is to disable and re-enable the NIC after each reboot.
There has been a few bug reports submitted in the feedback hub and in this community many months ago. It would be at least be nice to be acknowledged.
Since the insider builds from 25398 to the latest 26227 all have the same bug where the domain controller on the builds will show the network category as Public instead of DomainAuthenticated and the only way to fix it is to disable and re-enable the NIC after each reboot. There has been a few bug reports submitted in the feedback hub and in this community many months ago. It would be at least be nice to be acknowledged. Read More
How to find curvature(k) of plane curve have having using it’s position points (x & y) equally spaced with arc length s.
Dear Seniors,
I’m researching on a topic and from many days, i’m so confused, i’m learning to get strong programmming skills, but rightnow i don’t know how to get out of this. I used ”diff” and ”syms” to solve, but it is not effective.
I have a cubic spline curve having arrays of psition x and y equally parsmertize with arclength s. I want to get derivative of x points with respect to s, derivative of y point w.r.t s. and then put in formula to find curvature (k), but i can’t get dy/ds & dx/ds.
points(x&y)=[328.1228 201.8773; 326.2455 203.7545; 324.3683 205.6317; 322.4910 207.5090; 320.6138 209.3826; 318.7365 211.22634; 316.8593 213.1407; 314.9820 215.0180; 313.1048 216.8952; 311.2276 218.7725; 309.3504 220.6489; 307.4731 222.5269; 305.5958 224.4041; 303.7189 226.2818; 301.8424 228.1598]; each position is equally spaced difference of s=2.6548.
for continues acrlength w.r.t position(x&y) along curve i used
acrlen=sqrt((diff(points(:,1))).^2+(diff(points(:,2))).^2);
s=[0 cumsum(arclen’)];Dear Seniors,
I’m researching on a topic and from many days, i’m so confused, i’m learning to get strong programmming skills, but rightnow i don’t know how to get out of this. I used ”diff” and ”syms” to solve, but it is not effective.
I have a cubic spline curve having arrays of psition x and y equally parsmertize with arclength s. I want to get derivative of x points with respect to s, derivative of y point w.r.t s. and then put in formula to find curvature (k), but i can’t get dy/ds & dx/ds.
points(x&y)=[328.1228 201.8773; 326.2455 203.7545; 324.3683 205.6317; 322.4910 207.5090; 320.6138 209.3826; 318.7365 211.22634; 316.8593 213.1407; 314.9820 215.0180; 313.1048 216.8952; 311.2276 218.7725; 309.3504 220.6489; 307.4731 222.5269; 305.5958 224.4041; 303.7189 226.2818; 301.8424 228.1598]; each position is equally spaced difference of s=2.6548.
for continues acrlength w.r.t position(x&y) along curve i used
acrlen=sqrt((diff(points(:,1))).^2+(diff(points(:,2))).^2);
s=[0 cumsum(arclen’)]; Dear Seniors,
I’m researching on a topic and from many days, i’m so confused, i’m learning to get strong programmming skills, but rightnow i don’t know how to get out of this. I used ”diff” and ”syms” to solve, but it is not effective.
I have a cubic spline curve having arrays of psition x and y equally parsmertize with arclength s. I want to get derivative of x points with respect to s, derivative of y point w.r.t s. and then put in formula to find curvature (k), but i can’t get dy/ds & dx/ds.
points(x&y)=[328.1228 201.8773; 326.2455 203.7545; 324.3683 205.6317; 322.4910 207.5090; 320.6138 209.3826; 318.7365 211.22634; 316.8593 213.1407; 314.9820 215.0180; 313.1048 216.8952; 311.2276 218.7725; 309.3504 220.6489; 307.4731 222.5269; 305.5958 224.4041; 303.7189 226.2818; 301.8424 228.1598]; each position is equally spaced difference of s=2.6548.
for continues acrlength w.r.t position(x&y) along curve i used
acrlen=sqrt((diff(points(:,1))).^2+(diff(points(:,2))).^2);
s=[0 cumsum(arclen’)]; partial derivative, curvature (k) MATLAB Answers — New Questions
Why do I receive the error ‘We are unable to validate this email address. Specify a different email address.’?
Why do I receive the error ‘We are unable to validate this email address. Specify a different email address.’ when creating a MathWorks Account or resetting my password?Why do I receive the error ‘We are unable to validate this email address. Specify a different email address.’ when creating a MathWorks Account or resetting my password? Why do I receive the error ‘We are unable to validate this email address. Specify a different email address.’ when creating a MathWorks Account or resetting my password? MATLAB Answers — New Questions
Extend Copilot for Sales with custom data and insights from your own apps
Optimize the sales process by integrating internal and external data with Copilot for Sales. Create enriched email summaries, customized meeting prep documents, and actionable meeting recaps to improve customer interactions. Copilot uses AI to generate insights and suggest actions based on comprehensive data, ensuring sales teams have all the necessary information at their fingertips. Create custom AI experiences using Copilot Studio with zero code. By adding Copilot extensions, users can connect to external data sources and build tailored AI skills.
Eric Boocock, Copilot for Sales Principal Program Manager, shares how Copilot for Sales works and how to build Copilot extensions to connect with other systems for personalized experiences.
Strengthen and inform the sales process.
Bring in data from connected services that provide critical customer intelligence. Check out Copilot for Sales.
Generate personalized meeting prep docs and meeting recaps.
Save time using Copilot for Sales.
Connect data from external systems.
See how to create Copilot extensions with zero code from Copilot Studio using Copilot Actions.
Watch the video here:
QUICK LINKS:
00:00 — Copilot for Sales
00:36 — Baseline experiences
02:13 — Bring in external data
03:26 — Use Copilot to respond to emails
03:54 — Meeting prep and meeting recap
04:52 — Security and Responsible AI
06:27 — Copilot extensions
09:09 — Publish Copilot extensions
09:40 — Wrap up
Link References
Check out https://aka.ms/CopilotforSalesExtensibility
Stay updated on monthly releases at https://aka.ms/CopilotforSalesUpdates
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Video Transcript:
-What if you could go beyond the insights available in your CRM and collaboration tools to easily bring in data from connected services that provide critical customer intelligence to strengthen and inform the sales process.
-Today, we’ll look at how this is possible using generative AI with Copilot for Sales, grounded with information from both your internal and external systems. And the zero-code way to light the experience up with Copilot Studio to connect to your data with extensions and build custom AI skills using Copilot actions.
-Let’s start with your baseline experience using Copilot for Sales, which if you haven’t looked at it in a while, enriches your Copilot for Microsoft 365 experience. For example, email summaries are enriched with data from your CRM. There are suggested CRM updates found in the email to ensure no action is missed and CRM data is current and simple to update from the context of Outlook.
-Then, to close the loop, suggested email response prompts are geared towards closing a deal that draw on all the context of the email and data from your CRM. Meeting prep documents are more customized with content generated using information from CRM records, along with details from referenced upcoming meetings in Microsoft 365.
-The brief is formatted to include who the participants are, the opportunity summary, recent meeting insights, email thread summaries, related records from the CRM, and any open customer service cases that the team should be aware of going into our upcoming call. Additionally, Copilot for Sales shares the meeting prep in Teams as team members join meetings.
-And meeting recaps are made more relatable and actionable with the rich AI capabilities of Copilot for Microsoft 365, used to summarize the meeting and Copilot for Sales, bringing in sales-specific actions like follow-up tasks to create in CRM, as well as a record of questions asked, conversational KPIs, and keywords mentioned. In these examples, we ground your generative AI experience with information from your CRM and Microsoft 365. Next, let me show you how your experience is enriched further by bringing in data from external connected systems and tailored custom skills.
-As I open an email from a prospective customer, Alberto, in addition to what we just saw, we’ve created an extension, Contoso Customer Intelligence, which surfaces additional details about the customer, including other people at Contoso he’s worked with in the past, as well as product pages he’s favorited while signed into our company website. And in a moment, I’ll show you how we enabled this in Copilot Studio.
-Within the Copilot for Sales sidecar, the custom extension Contoso Customer Intelligence displays expanded company insights and suggested actions to update opportunity details and schedule a meeting. Given the prior work history with Alberto’s company, Fourth Coffee, I can use the Copilot chat experience within Outlook to then prompt for past opportunities and agreements with Fourth Coffee. And I can find the details about Fourth Coffee’s previous purchases with us.
-These results also include information from our Contoso Customer Intelligence connected app. With all this context, I can respond to Alberto’s email mentioning those additional details. I’ve used Copilot to start an email here, along with an invitation to a meeting to discuss the espresso machines that he’s interested in. I’ve also been able to proactively include a 5% discount opportunity if Alberto completes his purchase this month.
-So, as I’ve shown, generative AI can now gain context from available information across my CRM, Microsoft 365, and Connected Systems, to inform and improve my customer interactions. And there’s even more that Copilot for Sales can do to help me save time with additional insights. With Copilot in Word, I can generate personalized meeting prep documents connected to my CRM and external applications through Copilot for Sales. In my case, I’ll use Copilot with a forward slash, to reference an upcoming sales meeting called Follow-Up: Fourth Coffee.
-This generated document includes details about the meeting, participant information, topics for the discussion, and even account-specific information extracted from CRM and our connected external app, as well as open tasks all within seconds. Also, moving ahead to the day of the meeting, I can use the integrated meeting recap to take care of follow-up actions.
-Here, the after-call summary captures notes including integrated follow-up tasks with our Copilot extension. That’s one example of a connected and integrated Copilot for Sales experience. Now, since this is Mechanics, let me explain how the different surfaces were connected, enabling Copilot to securely access the information it needed to inform responses.
-The Copilot for Sales system is comprised of large language models, along with the Microsoft Graph, with user-level activities and data, and Microsoft 365 app experiences, and it connects to your sales data in CRM systems from either Salesforce or Dynamics 365, as well as connected external systems using Copilot extensions. With the right grounding data, including external data that’s accessible, here’s how responses are then generated. Beginning with the prompt, Copilot utilizes Retrieval Augmented Generation to orchestrate information search from the Microsoft Graph, CRM system, and connected external systems.
-Copilot for Sales also incorporates AI-generated skills to guide it through multi-step tasks like proposal creation, where it gathers data from diverse sources using its orchestrator and predefined logic. The gathered information is then presented to the language model, temporarily enriching its knowledge to generate an informed response. Note that the contextual information provided to the LLM remains separate and is never used in its training.
-And, of course, Copilot for Sales follows Microsoft’s documented practices for responsible AI. All services are designed to meet regulations required in your country, region, and industry, in the same way that other Microsoft Cloud services do. When you use Copilot for Sales, it includes integrated scenarios with Microsoft 365 and your CRM out of the box.
-That said, to connect to data from external systems, you’ll use Copilot extensions. Let me first show you how you’d create one with zero code from Copilot Studio, using Copilot actions to build a custom AI experience using your external data. Now, remember the email summary we showed you before? I’m going to show you how we extended that experience. For that, I need to head over to Copilot Studio to hook into our customer intelligence application. To get to Copilot Studio, you can navigate to copilotstudio.microsoft.com.
-Next, I’ll expand the left menu and move to Copilot for Sales. I’ll add an action. From there, I’ll select my connector, which is a Copilot extension type for my customer intelligence application. I’ll paste in the action name and description. In this case, the extension exposes related marketing data as well as public data, including news and events associated to key customers. This description is important because Copilot for Sales will use it to figure out when to invoke this action.
-Next, I’ll choose from the connector’s available actions to pull the right insights from our email summary with get engagement insights. I can add an action name, then a description for what it does. Again, this description is important because it is used by the AI as the instructions for what to do.
-Here, we are saying to look into our Contoso Customer Intelligence data set for insights related to an email in Outlook. To save some time, I’ll skip a few of the options and optional steps here. I can repeat this process if I want to add additional actions. You can then optionally add conversation starters, which are suggested prompts, but in this case, to save a little time, I’ll skip this.
-From here, I can test it out to make sure everything is working as expected. I’ll enter a test prompt, and make sure it responds as expected, and even dig into more details about the logic and information connected with our extension. Everything looks good. And optionally, I can also test this out in microsoft365.com or Outlook. Now, I can finalize and publish it. You can do that from the add connector action experience in the manage tab in Copilot Studio.
-I’ll continue in the wizard, and to save time, I’ve added the icon images and background color already, as well as who has permissions to use it. So I just need to hit skip and publish, and everything is published in Copilot for Sales. And there’s one more thing to do to get it working in Copilot for Microsoft 365. From the new actions tab, I’ll hit publish, and then I’ll choose Copilot for Microsoft 365. And from there, I can publish it so that it’s available in both Copilot experiences.
-And by the way, if you’re an ISV or partner building Copilot actions, the same process applies. Plus, you can get your solutions certified using the Microsoft Partner Center, and make them discoverable by organizations in the Microsoft 365 admin center. So that was a quick tour of how Copilot for Sales can optimize the sales process using generative AI, the mechanics of how it works, and how to build Copilot extensions to connect with other systems for even more personalized experiences.
-For more information, check out aka.ms/CopilotforSalesExtensibility. And to stay up to date on monthly releases, check out aka.ms/CopilotforSalesUpdates. Keep watching Microsoft Mechanics for all the latest AI updates, and thanks for watching.
Microsoft Tech Community – Latest Blogs –Read More
how do i combine two bar graphs
I have tried to combine these two graphics in many ways but nothing works for me, just as the creation of the legends gives me an error. I need help for this because neither the combination nor the legends want to serve me, Thank you!
b1=bar(app.CasosUIAxes,data1.dateRep,data1.cases);
hold on
%grafica de barras 2
b2=bar(app.CasosUIAxes,data2.dateRep,data2.cases);
hold off
legend(app.CasosUIAxes,[b1 b2],’Bar Chart 1′,’Bar Chart 2′)I have tried to combine these two graphics in many ways but nothing works for me, just as the creation of the legends gives me an error. I need help for this because neither the combination nor the legends want to serve me, Thank you!
b1=bar(app.CasosUIAxes,data1.dateRep,data1.cases);
hold on
%grafica de barras 2
b2=bar(app.CasosUIAxes,data2.dateRep,data2.cases);
hold off
legend(app.CasosUIAxes,[b1 b2],’Bar Chart 1′,’Bar Chart 2′) I have tried to combine these two graphics in many ways but nothing works for me, just as the creation of the legends gives me an error. I need help for this because neither the combination nor the legends want to serve me, Thank you!
b1=bar(app.CasosUIAxes,data1.dateRep,data1.cases);
hold on
%grafica de barras 2
b2=bar(app.CasosUIAxes,data2.dateRep,data2.cases);
hold off
legend(app.CasosUIAxes,[b1 b2],’Bar Chart 1′,’Bar Chart 2′) bar-chart matlab mlapp MATLAB Answers — New Questions
Email Notification for failed Scheduled Pipleline runs on azure devops for Specific Env CD BUild
Hello All,
I have a pipeline running to do a certain task and when the pipeline fails I get an email stating the build failed. However, I’m also scheduling this pipeline to run at 1am every day only for XX Env CD build in this case even if the build fails I don’t get any notification email at all.
I need to set up extra alert to get notified to my email if my schuduled build fails at Env Level.
referd this but here I can do any Custome to have aaddition filter for My Env:https://learn.microsoft.com/en-us/azure/devops/organizations/notifications/manage-your-personal-notifications?view=azure-devops
Thank you.
Hello All, I have a pipeline running to do a certain task and when the pipeline fails I get an email stating the build failed. However, I’m also scheduling this pipeline to run at 1am every day only for XX Env CD build in this case even if the build fails I don’t get any notification email at all.I need to set up extra alert to get notified to my email if my schuduled build fails at Env Level. referd this but here I can do any Custome to have aaddition filter for My Env:https://learn.microsoft.com/en-us/azure/devops/organizations/notifications/manage-your-personal-notifications?view=azure-devops Thank you. Read More
Getting Error : 400 Bad Request and invalidRequest While creating OneDrive Documents versions Graph
Here going to create versions (version history) of a document using this type of curl
POST /v1.0/drives/{drive-id}/items/{item-id}/versions
Content-Type: application/json
{
“content”: {
“@odata.type”: “#microsoft.graph.fileContent”,
“sourceUrl”: “data:text/plain;base64,SGVsbG8gV29ybGQhCg==”
}
}
but in the response I am getting following error:
{
“error”: {
“code”: “invalidRequest”,
“message”: “Invalid request”,
“innerError”: {
“date”: “2024-05-29T20:10:45”,
“request-id”: “c1899a5f-e6d6-445d-b563-efb03268175c”,
“client-request-id”: “c1899a5f-e6d6-445d-b563-efb03268175c”
}
}
}
What am I doing wrong? Is there any other Microsoft Graph API or method for creating documents versions.
In the response I expect ‘Created’ or 201 code, that means a new version of file or document added in version history. Please help me to resolve this error. Thanks in Advance !
Here going to create versions (version history) of a document using this type of curlPOST /v1.0/drives/{drive-id}/items/{item-id}/versions
Content-Type: application/json
{
“content”: {
“@odata.type”: “#microsoft.graph.fileContent”,
“sourceUrl”: “data:text/plain;base64,SGVsbG8gV29ybGQhCg==”
}
}but in the response I am getting following error:{
“error”: {
“code”: “invalidRequest”,
“message”: “Invalid request”,
“innerError”: {
“date”: “2024-05-29T20:10:45”,
“request-id”: “c1899a5f-e6d6-445d-b563-efb03268175c”,
“client-request-id”: “c1899a5f-e6d6-445d-b563-efb03268175c”
}
}
}What am I doing wrong? Is there any other Microsoft Graph API or method for creating documents versions.In the response I expect ‘Created’ or 201 code, that means a new version of file or document added in version history. Please help me to resolve this error. Thanks in Advance ! Read More
Scaling of Filter Coefficients in “fir1” function
Hello Everyone,
I had a quick question.
I was looking through the "fir1" function’s implementation to see how the coeffs are being scaled. I came across this function:
function b = scalefilter(b,First_Band,ff,L)
%SCALEFILTER Scale filter to have passband approx. equal to one.
if First_Band
b = b / sum(b); % unity gain at DC
else
if ff(4)==1
% unity gain at Fs/2
f0 = 1;
else
% unity gain at center of first passband
f0 = mean(ff(3:4));
end
b = b / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
end
end
Since there is no documentation for this particular line, I was curious to know where the following equation comes from:
scalingFactor = 1 / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
Does anyone know?Hello Everyone,
I had a quick question.
I was looking through the "fir1" function’s implementation to see how the coeffs are being scaled. I came across this function:
function b = scalefilter(b,First_Band,ff,L)
%SCALEFILTER Scale filter to have passband approx. equal to one.
if First_Band
b = b / sum(b); % unity gain at DC
else
if ff(4)==1
% unity gain at Fs/2
f0 = 1;
else
% unity gain at center of first passband
f0 = mean(ff(3:4));
end
b = b / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
end
end
Since there is no documentation for this particular line, I was curious to know where the following equation comes from:
scalingFactor = 1 / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
Does anyone know? Hello Everyone,
I had a quick question.
I was looking through the "fir1" function’s implementation to see how the coeffs are being scaled. I came across this function:
function b = scalefilter(b,First_Band,ff,L)
%SCALEFILTER Scale filter to have passband approx. equal to one.
if First_Band
b = b / sum(b); % unity gain at DC
else
if ff(4)==1
% unity gain at Fs/2
f0 = 1;
else
% unity gain at center of first passband
f0 = mean(ff(3:4));
end
b = b / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
end
end
Since there is no documentation for this particular line, I was curious to know where the following equation comes from:
scalingFactor = 1 / abs( exp(-1i*2*pi*(0:L-1)*(f0/2))*(b.’) );
Does anyone know? digital signal processing, dsp, filter, signal processing, signal MATLAB Answers — New Questions
3D geometry issues with specifyCoefficients (PDE Toolbox)
Hello everyone! I am trying to prepare a heat transfer simulation in an adiabatic pipe. There is a specific formula that I would like my students to compare results with by setting coefficients for the generalized form of the equations solved by PDE Toolbox. Please look at the code below – I would really appreciate your help!
I noticed this error:
Incorrect number or types of inputs or outputs for function specifyCoefficients.
When I checked the documentation, it turns out that my nonconstant coefficients are the correct format, but the model I am specifying is a femodel class as opposed to PDEmodel (requested by the first argument). I made the 3D geometry in house, and I was initially associating it to the model by using femodel(AnalysisType, Geometry), which you can see commented out below.
I then tried to add model_adiabatic.Geometry = g3 hoping that would keep model_adiabatic as a PDEmodel and not a femodel, but it still shows as a femodel when I use class(model) and I am getting another error on top.
I have seen examples with specifyCoefficients used on 3D geometries, but they use importGeometry from external files. I do not have that and I was hoping to keep the code simple and transferable.
Could anybody kindly suggest a fix or anything I have missed?
Thank you!
Michela
% Setting Adiabatic Model
R = 0.05; %m
rho = 1000; %kg/m3
cp = 4182; %J/kgC
model_2 = createpde("thermal","steadystate");
% Geometry
pdecirc(0,0,R);
g = decsg(gd,sf,ns);
g2 = fegeometry(g);
g3 = extrude(g2,1);
model_adiabatic.Geometry = g3
figure;
% model_adiabatic = femodel(AnalysisType="thermalSteady", …
% Geometry=g3);
pdegplot(model_adiabatic,EdgeLabels="on",FaceLabels="on")
title(‘Pipe’)
class(model_adiabatic)
model.MaterialProperties=materialProperties(ThermalConductivity=k,MassDensity=rho, SpecificHeat=cp);
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0Hello everyone! I am trying to prepare a heat transfer simulation in an adiabatic pipe. There is a specific formula that I would like my students to compare results with by setting coefficients for the generalized form of the equations solved by PDE Toolbox. Please look at the code below – I would really appreciate your help!
I noticed this error:
Incorrect number or types of inputs or outputs for function specifyCoefficients.
When I checked the documentation, it turns out that my nonconstant coefficients are the correct format, but the model I am specifying is a femodel class as opposed to PDEmodel (requested by the first argument). I made the 3D geometry in house, and I was initially associating it to the model by using femodel(AnalysisType, Geometry), which you can see commented out below.
I then tried to add model_adiabatic.Geometry = g3 hoping that would keep model_adiabatic as a PDEmodel and not a femodel, but it still shows as a femodel when I use class(model) and I am getting another error on top.
I have seen examples with specifyCoefficients used on 3D geometries, but they use importGeometry from external files. I do not have that and I was hoping to keep the code simple and transferable.
Could anybody kindly suggest a fix or anything I have missed?
Thank you!
Michela
% Setting Adiabatic Model
R = 0.05; %m
rho = 1000; %kg/m3
cp = 4182; %J/kgC
model_2 = createpde("thermal","steadystate");
% Geometry
pdecirc(0,0,R);
g = decsg(gd,sf,ns);
g2 = fegeometry(g);
g3 = extrude(g2,1);
model_adiabatic.Geometry = g3
figure;
% model_adiabatic = femodel(AnalysisType="thermalSteady", …
% Geometry=g3);
pdegplot(model_adiabatic,EdgeLabels="on",FaceLabels="on")
title(‘Pipe’)
class(model_adiabatic)
model.MaterialProperties=materialProperties(ThermalConductivity=k,MassDensity=rho, SpecificHeat=cp);
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0 Hello everyone! I am trying to prepare a heat transfer simulation in an adiabatic pipe. There is a specific formula that I would like my students to compare results with by setting coefficients for the generalized form of the equations solved by PDE Toolbox. Please look at the code below – I would really appreciate your help!
I noticed this error:
Incorrect number or types of inputs or outputs for function specifyCoefficients.
When I checked the documentation, it turns out that my nonconstant coefficients are the correct format, but the model I am specifying is a femodel class as opposed to PDEmodel (requested by the first argument). I made the 3D geometry in house, and I was initially associating it to the model by using femodel(AnalysisType, Geometry), which you can see commented out below.
I then tried to add model_adiabatic.Geometry = g3 hoping that would keep model_adiabatic as a PDEmodel and not a femodel, but it still shows as a femodel when I use class(model) and I am getting another error on top.
I have seen examples with specifyCoefficients used on 3D geometries, but they use importGeometry from external files. I do not have that and I was hoping to keep the code simple and transferable.
Could anybody kindly suggest a fix or anything I have missed?
Thank you!
Michela
% Setting Adiabatic Model
R = 0.05; %m
rho = 1000; %kg/m3
cp = 4182; %J/kgC
model_2 = createpde("thermal","steadystate");
% Geometry
pdecirc(0,0,R);
g = decsg(gd,sf,ns);
g2 = fegeometry(g);
g3 = extrude(g2,1);
model_adiabatic.Geometry = g3
figure;
% model_adiabatic = femodel(AnalysisType="thermalSteady", …
% Geometry=g3);
pdegplot(model_adiabatic,EdgeLabels="on",FaceLabels="on")
title(‘Pipe’)
class(model_adiabatic)
model.MaterialProperties=materialProperties(ThermalConductivity=k,MassDensity=rho, SpecificHeat=cp);
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0
% Boundary Conditions
model_adiabatic.FaceLoad(3) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(4) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(5) = faceLoad(Heat = 0); % adiabatic wall
model_adiabatic.FaceLoad(6) = faceLoad(Heat = 0); % adiabatic wall
T1 = 40;
model_adiabatic.FaceBC(1) = faceBC(Temperature = T1); % entrance temperature, z = 0 pde toolbox MATLAB Answers — New Questions
Multiple outputs using Legacy Toolbox
Hi, i’m currently working on a project and I have to create a s-function written in C language. I have multiple outputs (V, m, h & fm) and multiple inputs(q1, q2, qe & qo). Here’s my main file:
#include "Reservoir.h"
#include <math.h>
double Reservoir(double q1,
double q2,
double qe,
double qo,
double *V,
double *m,
double *h,
double *fm)
{
*V = q1 + q2 + qe – qo;
*m = 1875.0 * q1 + 1667.0 * q2 + 1000.0 * qe – 1468.48 * qo;
*h = sqrt(*V + 1) – 1;
*fm = ((3000.0) * (1 – 1000.0)) / ((3000.0 – 1000.0) * (*m/*V))
}
And here’s my header file :
#ifndef RESERVOIR_H_INCLUDED
#define RESERVOIR_H_INCLUDED
double Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm);
#endif // RESERVOIR_H_INCLUDED
I’M also working with Legacy Toolbox to generate a tlc file and the s-function. I’m using these lines to generate the s-function :
def = legacy_code(‘initialize’)
def.SFunctionName = ‘S_function1’
def.OutputFcnSpec = ‘Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)’
def.HeaderFiles = {‘Reservoir.h’}
def.SourceFiles = {‘main.c’}
legacy_code(‘sfcn_cmex_generate’, def)
When i execute the last line, i receive this error :
Error using legacycode.LCT.legacyCodeImpl
Unrecognized elements in the function specification:
–> Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)
Error in legacy_code (line 103)
[varargout{1:nargout}] = legacycode.LCT.legacyCodeImpl(action, varargin{1:end});
Thus, I was wondering what i’ve done wrong ? Thanks for your help.Hi, i’m currently working on a project and I have to create a s-function written in C language. I have multiple outputs (V, m, h & fm) and multiple inputs(q1, q2, qe & qo). Here’s my main file:
#include "Reservoir.h"
#include <math.h>
double Reservoir(double q1,
double q2,
double qe,
double qo,
double *V,
double *m,
double *h,
double *fm)
{
*V = q1 + q2 + qe – qo;
*m = 1875.0 * q1 + 1667.0 * q2 + 1000.0 * qe – 1468.48 * qo;
*h = sqrt(*V + 1) – 1;
*fm = ((3000.0) * (1 – 1000.0)) / ((3000.0 – 1000.0) * (*m/*V))
}
And here’s my header file :
#ifndef RESERVOIR_H_INCLUDED
#define RESERVOIR_H_INCLUDED
double Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm);
#endif // RESERVOIR_H_INCLUDED
I’M also working with Legacy Toolbox to generate a tlc file and the s-function. I’m using these lines to generate the s-function :
def = legacy_code(‘initialize’)
def.SFunctionName = ‘S_function1’
def.OutputFcnSpec = ‘Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)’
def.HeaderFiles = {‘Reservoir.h’}
def.SourceFiles = {‘main.c’}
legacy_code(‘sfcn_cmex_generate’, def)
When i execute the last line, i receive this error :
Error using legacycode.LCT.legacyCodeImpl
Unrecognized elements in the function specification:
–> Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)
Error in legacy_code (line 103)
[varargout{1:nargout}] = legacycode.LCT.legacyCodeImpl(action, varargin{1:end});
Thus, I was wondering what i’ve done wrong ? Thanks for your help. Hi, i’m currently working on a project and I have to create a s-function written in C language. I have multiple outputs (V, m, h & fm) and multiple inputs(q1, q2, qe & qo). Here’s my main file:
#include "Reservoir.h"
#include <math.h>
double Reservoir(double q1,
double q2,
double qe,
double qo,
double *V,
double *m,
double *h,
double *fm)
{
*V = q1 + q2 + qe – qo;
*m = 1875.0 * q1 + 1667.0 * q2 + 1000.0 * qe – 1468.48 * qo;
*h = sqrt(*V + 1) – 1;
*fm = ((3000.0) * (1 – 1000.0)) / ((3000.0 – 1000.0) * (*m/*V))
}
And here’s my header file :
#ifndef RESERVOIR_H_INCLUDED
#define RESERVOIR_H_INCLUDED
double Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm);
#endif // RESERVOIR_H_INCLUDED
I’M also working with Legacy Toolbox to generate a tlc file and the s-function. I’m using these lines to generate the s-function :
def = legacy_code(‘initialize’)
def.SFunctionName = ‘S_function1’
def.OutputFcnSpec = ‘Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)’
def.HeaderFiles = {‘Reservoir.h’}
def.SourceFiles = {‘main.c’}
legacy_code(‘sfcn_cmex_generate’, def)
When i execute the last line, i receive this error :
Error using legacycode.LCT.legacyCodeImpl
Unrecognized elements in the function specification:
–> Reservoir(double q1, double q2, double qe, double qo, double *V, double *m, double *h, double *fm)
Error in legacy_code (line 103)
[varargout{1:nargout}] = legacycode.LCT.legacyCodeImpl(action, varargin{1:end});
Thus, I was wondering what i’ve done wrong ? Thanks for your help. legacy, code, c language MATLAB Answers — New Questions
I am getting Negative speed in PMSM FOC using MTPA controller block.
I am trying to implement Field oriented control under field weakening condition for PMSM motor. Manually setting value of Id to negative values, I am getting desired results of speed and Torque but when i try to use MTPA Controller block, speed always get negative to certain RPM and then saturates (see image below). I have attached images of parameters used in MTPA and Motor block, please help me in following what I am doing wrong and how to resolve it. P=0.05 and I = 4 for all PI controllers here i used.
Block Diagram:
Block Parameters:
Result:I am trying to implement Field oriented control under field weakening condition for PMSM motor. Manually setting value of Id to negative values, I am getting desired results of speed and Torque but when i try to use MTPA Controller block, speed always get negative to certain RPM and then saturates (see image below). I have attached images of parameters used in MTPA and Motor block, please help me in following what I am doing wrong and how to resolve it. P=0.05 and I = 4 for all PI controllers here i used.
Block Diagram:
Block Parameters:
Result: I am trying to implement Field oriented control under field weakening condition for PMSM motor. Manually setting value of Id to negative values, I am getting desired results of speed and Torque but when i try to use MTPA Controller block, speed always get negative to certain RPM and then saturates (see image below). I have attached images of parameters used in MTPA and Motor block, please help me in following what I am doing wrong and how to resolve it. P=0.05 and I = 4 for all PI controllers here i used.
Block Diagram:
Block Parameters:
Result: electric_motor_control, pmsm, foc, mtpa, field_weakening_control, field_oriented_control MATLAB Answers — New Questions
Going to be out of touch for a while
My Wife is very sick and just got her out of the hospital so going to be very busy taking care of her needs until I can get her back up on her feet. Keep up the great Job and God Bless you All!
My Wife is very sick and just got her out of the hospital so going to be very busy taking care of her needs until I can get her back up on her feet. Keep up the great Job and God Bless you All! Read More
Deleting and or Consolidating Date info for Pivot Tables
Folks,
I am a little new to excel’s data processing features. I’ve done all the basic stuff for years, but I am diving in deeper. I am having trouble with correlating data streams from multiple sources that have specific time stamps. I need to utilize the date and hour times with the associated data, but I can’t figure out how to correlate this between multiple data streams. I am having trouble trying to associate the time values between different data streams. I am sure there is a way to do this. Each data stream has a unique time stamp with DATE HH:MM:SS. I need to match up the dates and hours on the different streams. I want to plot multiple data streams on one graph or interactive pivot table. I can’t figure out how to get excel to ignore minutes and seconds between readings and incorporate it together. I really just want one hourly reading instead of the 6 reading every ten-ish minutes.
For Example. I have this record. My other records are a few seconds or minutes off. Some data missing for hours or days. I cannot figure out how to correlate this sort of data together. Any advice would be appreciated.
TimeLevel Sensor 1 [ft]Temperature Sensor 2 [°F]2024-05-08T09:05:58.800-07:00 2024-05-08T13:09:23.000-07:000322024-05-08T13:24:03.000-07:0012.532.92024-05-08T13:34:02.000-07:0011.8 2024-05-08T13:44:02.000-07:0011.2 2024-05-08T13:54:02.000-07:0010.5 2024-05-08T14:04:01.000-07:0010.5 2024-05-08T14:14:01.000-07:0010.2 2024-05-08T14:24:01.000-07:0010.2 2024-05-08T14:34:01.000-07:009.8 2024-05-08T14:35:16.000-07:009.8 2024-05-08T14:45:57.000-07:009.8 2024-05-08T14:55:56.000-07:009.8 2024-05-08T15:05:56.000-07:009.5 2024-05-08T15:15:57.000-07:009.5 2024-05-08T15:25:56.000-07:009.5 2024-05-08T15:35:56.000-07:009.5 2024-05-08T15:45:56.000-07:009.5 2024-05-08T15:55:55.000-07:009.5 2024-05-08T16:05:55.000-07:009.2 2024-05-08T16:15:55.000-07:009.5 2024-05-08T16:25:54.000-07:009.2 2024-05-08T16:35:54.000-07:0017.1 2024-05-08T16:45:53.000-07:008.9 2024-05-08T16:55:53.000-07:009.2 2024-05-08T17:05:54.000-07:009.2 2024-05-08T17:15:53.000-07:009.5 2024-05-08T17:25:53.000-07:009.5 2024-05-08T17:35:53.000-07:009.5 2024-05-08T17:45:52.000-07:009.5 2024-05-08T17:55:52.000-07:009.5 2024-05-08T18:05:52.000-07:009.5 2024-05-08T18:15:51.000-07:009.5 2024-05-08T18:25:51.000-07:009.5 2024-05-08T18:35:51.000-07:009.5 2024-05-08T18:45:50.000-07:009.5 2024-05-08T18:55:50.000-07:009.5 2024-05-08T19:05:51.000-07:009.5 2024-05-08T19:15:50.000-07:009.5 2024-05-08T19:25:50.000-07:009.5 2024-05-08T19:35:51.000-07:009.2 2024-05-08T19:45:49.000-07:009.5 2024-05-08T19:56:50.000-07:009.2 2024-05-08T20:06:49.000-07:009.2 2024-05-08T20:16:48.000-07:009.2 2024-05-08T20:26:48.000-07:009.2 2024-05-08T20:36:48.000-07:009.2 2024-05-08T20:46:48.000-07:009.2 2024-05-08T20:56:47.000-07:009.2 2024-05-08T21:06:49.000-07:009.2 2024-05-08T21:16:50.000-07:009.2 2024-05-08T21:26:47.000-07:009.2 2024-05-08T21:36:47.000-07:009.2 2024-05-08T21:46:47.000-07:009.2 2024-05-08T21:56:46.000-07:009.2 2024-05-08T22:06:46.000-07:009.2 2024-05-08T22:16:46.000-07:008.9 2024-05-08T22:26:45.000-07:008.9 2024-05-08T22:36:45.000-07:009.2 2024-05-08T22:46:45.000-07:008.9 2024-05-08T22:56:44.000-07:009.2 2024-05-08T23:06:45.000-07:008.9 2024-05-08T23:16:45.000-07:008.9 2024-05-08T23:26:45.000-07:008.9 2024-05-08T23:36:44.000-07:008.9 2024-05-08T23:46:44.000-07:008.9 2024-05-08T23:56:44.000-07:008.9 2024-05-09T00:06:43.000-07:008.9 2024-05-09T00:16:43.000-07:008.9 2024-05-09T00:26:43.000-07:008.9 2024-05-09T00:36:42.000-07:008.9 2024-05-09T00:46:42.000-07:008.9 2024-05-09T00:56:42.000-07:008.9 2024-05-09T01:06:42.000-07:008.9 2024-05-09T01:16:42.000-07:008.9 2024-05-09T01:26:42.000-07:008.9 2024-05-09T01:36:40.000-07:008.9 2024-05-09T01:46:39.000-07:008.9 2024-05-09T01:56:39.000-07:008.5 2024-05-09T02:06:41.000-07:008.5
I am struggling with getting this in a format that I can associate with other similar data.
Please let me know if you have any tips.
Thank You,
Ben
Folks, I am a little new to excel’s data processing features. I’ve done all the basic stuff for years, but I am diving in deeper. I am having trouble with correlating data streams from multiple sources that have specific time stamps. I need to utilize the date and hour times with the associated data, but I can’t figure out how to correlate this between multiple data streams. I am having trouble trying to associate the time values between different data streams. I am sure there is a way to do this. Each data stream has a unique time stamp with DATE HH:MM:SS. I need to match up the dates and hours on the different streams. I want to plot multiple data streams on one graph or interactive pivot table. I can’t figure out how to get excel to ignore minutes and seconds between readings and incorporate it together. I really just want one hourly reading instead of the 6 reading every ten-ish minutes. For Example. I have this record. My other records are a few seconds or minutes off. Some data missing for hours or days. I cannot figure out how to correlate this sort of data together. Any advice would be appreciated. TimeLevel Sensor 1 [ft]Temperature Sensor 2 [°F]2024-05-08T09:05:58.800-07:00 2024-05-08T13:09:23.000-07:000322024-05-08T13:24:03.000-07:0012.532.92024-05-08T13:34:02.000-07:0011.8 2024-05-08T13:44:02.000-07:0011.2 2024-05-08T13:54:02.000-07:0010.5 2024-05-08T14:04:01.000-07:0010.5 2024-05-08T14:14:01.000-07:0010.2 2024-05-08T14:24:01.000-07:0010.2 2024-05-08T14:34:01.000-07:009.8 2024-05-08T14:35:16.000-07:009.8 2024-05-08T14:45:57.000-07:009.8 2024-05-08T14:55:56.000-07:009.8 2024-05-08T15:05:56.000-07:009.5 2024-05-08T15:15:57.000-07:009.5 2024-05-08T15:25:56.000-07:009.5 2024-05-08T15:35:56.000-07:009.5 2024-05-08T15:45:56.000-07:009.5 2024-05-08T15:55:55.000-07:009.5 2024-05-08T16:05:55.000-07:009.2 2024-05-08T16:15:55.000-07:009.5 2024-05-08T16:25:54.000-07:009.2 2024-05-08T16:35:54.000-07:0017.1 2024-05-08T16:45:53.000-07:008.9 2024-05-08T16:55:53.000-07:009.2 2024-05-08T17:05:54.000-07:009.2 2024-05-08T17:15:53.000-07:009.5 2024-05-08T17:25:53.000-07:009.5 2024-05-08T17:35:53.000-07:009.5 2024-05-08T17:45:52.000-07:009.5 2024-05-08T17:55:52.000-07:009.5 2024-05-08T18:05:52.000-07:009.5 2024-05-08T18:15:51.000-07:009.5 2024-05-08T18:25:51.000-07:009.5 2024-05-08T18:35:51.000-07:009.5 2024-05-08T18:45:50.000-07:009.5 2024-05-08T18:55:50.000-07:009.5 2024-05-08T19:05:51.000-07:009.5 2024-05-08T19:15:50.000-07:009.5 2024-05-08T19:25:50.000-07:009.5 2024-05-08T19:35:51.000-07:009.2 2024-05-08T19:45:49.000-07:009.5 2024-05-08T19:56:50.000-07:009.2 2024-05-08T20:06:49.000-07:009.2 2024-05-08T20:16:48.000-07:009.2 2024-05-08T20:26:48.000-07:009.2 2024-05-08T20:36:48.000-07:009.2 2024-05-08T20:46:48.000-07:009.2 2024-05-08T20:56:47.000-07:009.2 2024-05-08T21:06:49.000-07:009.2 2024-05-08T21:16:50.000-07:009.2 2024-05-08T21:26:47.000-07:009.2 2024-05-08T21:36:47.000-07:009.2 2024-05-08T21:46:47.000-07:009.2 2024-05-08T21:56:46.000-07:009.2 2024-05-08T22:06:46.000-07:009.2 2024-05-08T22:16:46.000-07:008.9 2024-05-08T22:26:45.000-07:008.9 2024-05-08T22:36:45.000-07:009.2 2024-05-08T22:46:45.000-07:008.9 2024-05-08T22:56:44.000-07:009.2 2024-05-08T23:06:45.000-07:008.9 2024-05-08T23:16:45.000-07:008.9 2024-05-08T23:26:45.000-07:008.9 2024-05-08T23:36:44.000-07:008.9 2024-05-08T23:46:44.000-07:008.9 2024-05-08T23:56:44.000-07:008.9 2024-05-09T00:06:43.000-07:008.9 2024-05-09T00:16:43.000-07:008.9 2024-05-09T00:26:43.000-07:008.9 2024-05-09T00:36:42.000-07:008.9 2024-05-09T00:46:42.000-07:008.9 2024-05-09T00:56:42.000-07:008.9 2024-05-09T01:06:42.000-07:008.9 2024-05-09T01:16:42.000-07:008.9 2024-05-09T01:26:42.000-07:008.9 2024-05-09T01:36:40.000-07:008.9 2024-05-09T01:46:39.000-07:008.9 2024-05-09T01:56:39.000-07:008.5 2024-05-09T02:06:41.000-07:008.5 I am struggling with getting this in a format that I can associate with other similar data. Please let me know if you have any tips. Thank You,Ben Read More
