A conical cup is to be made from a circular piece of paper having a radius of 8 cm by cutting out a sector from the paper. Find the maximum capacity of such a cup. derivatives with full solution and drawingA conical cup is to be made from a circular piece of paper having a radius of 8 cm by cutting out a sector from the paper. Find the maximum capacity of such a cup. derivatives with full solution and drawing A conical cup is to be made from a circular piece of paper having a radius of 8 cm by cutting out a sector from the paper. Find the maximum capacity of such a cup. derivatives with full solution and drawing please finf the maxima and maximum. MATLAB Answers — New Questions

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I have a excel template in which I export the matlab workspace variables
I am using this code –> writematrix(variables_1,’result.xlsx’,’Sheet’,1,’Range’,’B2′);
After extraction the file changes its column width which I fixed earlier as a templateI have a excel template in which I export the matlab workspace variables
I am using this code –> writematrix(variables_1,’result.xlsx’,’Sheet’,1,’Range’,’B2′);
After extraction the file changes its column width which I fixed earlier as a template I have a excel template in which I export the matlab workspace variables
I am using this code –> writematrix(variables_1,’result.xlsx’,’Sheet’,1,’Range’,’B2′);
After extraction the file changes its column width which I fixed earlier as a template exporting MATLAB Answers — New Questions

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Hello,
I need to simulate two helical gears engagement. One of them is not controllable in terms of revolution. So, it has random revolution per minute. The other one can be controlled in terms of torque and revolution. With a special method, I need to engage these gears. I need to copy behavior of uncontrollable one. After their revolutions are same and steady, at this point I need to engage them.
I may use a PID controller to monitorize and copy uncontrollable one. How can I simulate that?Hello,
I need to simulate two helical gears engagement. One of them is not controllable in terms of revolution. So, it has random revolution per minute. The other one can be controlled in terms of torque and revolution. With a special method, I need to engage these gears. I need to copy behavior of uncontrollable one. After their revolutions are same and steady, at this point I need to engage them.
I may use a PID controller to monitorize and copy uncontrollable one. How can I simulate that? Hello,
I need to simulate two helical gears engagement. One of them is not controllable in terms of revolution. So, it has random revolution per minute. The other one can be controlled in terms of torque and revolution. With a special method, I need to engage these gears. I need to copy behavior of uncontrollable one. After their revolutions are same and steady, at this point I need to engage them.
I may use a PID controller to monitorize and copy uncontrollable one. How can I simulate that? helical gears, pid, simulink, engagement MATLAB Answers — New Questions

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I’m trying to send the string below using the Matlab tcpclient. I need to send a string that contains two strings as shown below. I tried converting the entire string below to an asciiArray using the uint8(stringBelow) function and then fwrite(t, asciiArray, ‘uint8’) but that didn’t work either.
Is there a way to send the exact composite string shown below in tcpclient?

>> writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
↑
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax error.
To construct matrices, use brackets instead of parentheses.I’m trying to send the string below using the Matlab tcpclient. I need to send a string that contains two strings as shown below. I tried converting the entire string below to an asciiArray using the uint8(stringBelow) function and then fwrite(t, asciiArray, ‘uint8’) but that didn’t work either.
Is there a way to send the exact composite string shown below in tcpclient?

>> writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
↑
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax error.
To construct matrices, use brackets instead of parentheses. I’m trying to send the string below using the Matlab tcpclient. I need to send a string that contains two strings as shown below. I tried converting the entire string below to an asciiArray using the uint8(stringBelow) function and then fwrite(t, asciiArray, ‘uint8’) but that didn’t work either.
Is there a way to send the exact composite string shown below in tcpclient?

>> writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
writeline(t,"Unit.CommandAsText("myFile",1,"Millisecond")")
↑
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax error.
To construct matrices, use brackets instead of parentheses. tcpclient, string, nested string MATLAB Answers — New Questions

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The arrowhead is pointing the wrong way in the x-axis. See figure below.
Definerer alle landes forskydningsbæreevne
clc; clear; close all; clc ;

Forhold = 1/2 ;
Forhold2 = 54/228;

f_vk0 = 0.4 ; % Klæbningsbidrag [MPa]
mu_k = 0.65 ; % Friktionskoefficient
f_bt = 1.00 ; % Trækstyrke af sten [MPa]
f_k = 10.00 ; % Trykstyrke af sten [MPa]

sigma1 = -0.0:0.1:1.6 ;
sigma2 = 0.1:0.1:10.2;
sigma3 = 8.3:0.1:10 ;

sigma23 = 9.1:0.1:10 ;

Friction = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure = (f_k – sigma3) * 1/Forhold*(1/2) ;

Friction2 = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold2) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure2 = (f_k – sigma23) * 1/Forhold2*(1/2) ;

Plotter forskydningsbæreevnerne
hf = figure() ;
hold on
plot(sigma1, Friction,’–‘,’Color’,[0.4660 0.6740 0.1880],’LineWidth’,1.3)
plot(sigma2, Tension_failure,’–‘,’Color’,[0.9290 0.6940 0.1250],’LineWidth’,1.3)
plot(sigma3, Compression_failure,’–‘,’Color’,[0.4940 0.1840 0.5560],’LineWidth’,1.3)

plot(sigma1, Friction2,’LineWidth’,1.3)
plot(sigma2, Tension_failure,’Color’,[0.6350 0.0780 0.1840],’LineWidth’,1.3)
plot(sigma23, Compression_failure2,’Color’,[0.8500 0.3250 0.0980],’LineWidth’,1.3)

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);

grid on;

xlim([0 12])
ylim([0 2])

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
[x0,y0,~,~] = intersections(sigma1,Friction,sigma2, Tension_failure);
ind = (sigma1<x0);
sigma1b = [sigma1(ind) x0]; % add x0 of true intersection point
Frictionp = [Friction(ind) y0]; % add y0 of true intersection point
[x1,y1,~,~] = intersections(sigma1,Friction2,sigma2, Tension_failure);
ind = (sigma1<x1);
sigma1c = [sigma1(ind) x1]; % add x1 of true intersection point
Friction2p = [Friction2(ind) y1]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840],’FaceAlpha’,0.0,’EdgeColor’, ‘none’);
hatchfill2(tt,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

% Shade the area between [sigma3, Compression_failure] and [sigma3, Compression_failure2 ]
[x01,y01,~,~] = intersections(sigma3, Compression_failure,sigma2,Tension_failure);
ind = (sigma3>x01);
sigma1b = [x01 sigma3(ind)]; % add x0 of true intersection point
Frictionp = [y01 Compression_failure(ind)]; % add y0 of true intersection point
[x11,y11,~,~] = intersections(sigma23, Compression_failure2,sigma2,Tension_failure);
ind = (sigma23>x11);
sigma1c = [x11 sigma23(ind)]; % add x1 of true intersection point
Friction2p = [y11 Compression_failure2(ind)]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt2 = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840], ‘EdgeColor’, ‘none’,’FaceAlpha’,0.0);

hatchfill2(tt2,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

hax = gca;
hax.XDir = ‘reverse’; % flip axis direction
hax.YAxisLocation = ‘right’; % move ticks & labels to the other side

xlim([-2 12])
ylim([-0.5 2])

ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

%Define the variable
xac = -2; %x arrow coordinate
yac = 0; %y arrow coordinate
xas = 12; %x arrow shift
yas = 0; %y arrow shift

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [0 0];
ha.Y = [-0.4 2] ;

% remove old box and axes
box on
set(gca,’YColor’,get(gca,’Color’))
set(gca,’XColor’,get(gca,’Color’))
set(gca, ‘FontName’, ‘Times New Roman’, ‘FontSize’, 14)
set(gca, ‘XTickLabel’, {});
set(gca, ‘YTickLabel’, {});

legend({‘Friction failure (M&M)’,’Tension failure (M&M)’,’Compression failure (M&M)’,’Friction failure (DK)’,’Tension failure (DK)’,’Compression failure (DK)’},’Location’,’northeast’,’NumColumns’,1,’Orientation’,’vertical’)The arrowhead is pointing the wrong way in the x-axis. See figure below.
Definerer alle landes forskydningsbæreevne
clc; clear; close all; clc ;

Forhold = 1/2 ;
Forhold2 = 54/228;

f_vk0 = 0.4 ; % Klæbningsbidrag [MPa]
mu_k = 0.65 ; % Friktionskoefficient
f_bt = 1.00 ; % Trækstyrke af sten [MPa]
f_k = 10.00 ; % Trykstyrke af sten [MPa]

sigma1 = -0.0:0.1:1.6 ;
sigma2 = 0.1:0.1:10.2;
sigma3 = 8.3:0.1:10 ;

sigma23 = 9.1:0.1:10 ;

Friction = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure = (f_k – sigma3) * 1/Forhold*(1/2) ;

Friction2 = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold2) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure2 = (f_k – sigma23) * 1/Forhold2*(1/2) ;

Plotter forskydningsbæreevnerne
hf = figure() ;
hold on
plot(sigma1, Friction,’–‘,’Color’,[0.4660 0.6740 0.1880],’LineWidth’,1.3)
plot(sigma2, Tension_failure,’–‘,’Color’,[0.9290 0.6940 0.1250],’LineWidth’,1.3)
plot(sigma3, Compression_failure,’–‘,’Color’,[0.4940 0.1840 0.5560],’LineWidth’,1.3)

plot(sigma1, Friction2,’LineWidth’,1.3)
plot(sigma2, Tension_failure,’Color’,[0.6350 0.0780 0.1840],’LineWidth’,1.3)
plot(sigma23, Compression_failure2,’Color’,[0.8500 0.3250 0.0980],’LineWidth’,1.3)

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);

grid on;

xlim([0 12])
ylim([0 2])

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
[x0,y0,~,~] = intersections(sigma1,Friction,sigma2, Tension_failure);
ind = (sigma1<x0);
sigma1b = [sigma1(ind) x0]; % add x0 of true intersection point
Frictionp = [Friction(ind) y0]; % add y0 of true intersection point
[x1,y1,~,~] = intersections(sigma1,Friction2,sigma2, Tension_failure);
ind = (sigma1<x1);
sigma1c = [sigma1(ind) x1]; % add x1 of true intersection point
Friction2p = [Friction2(ind) y1]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840],’FaceAlpha’,0.0,’EdgeColor’, ‘none’);
hatchfill2(tt,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

% Shade the area between [sigma3, Compression_failure] and [sigma3, Compression_failure2 ]
[x01,y01,~,~] = intersections(sigma3, Compression_failure,sigma2,Tension_failure);
ind = (sigma3>x01);
sigma1b = [x01 sigma3(ind)]; % add x0 of true intersection point
Frictionp = [y01 Compression_failure(ind)]; % add y0 of true intersection point
[x11,y11,~,~] = intersections(sigma23, Compression_failure2,sigma2,Tension_failure);
ind = (sigma23>x11);
sigma1c = [x11 sigma23(ind)]; % add x1 of true intersection point
Friction2p = [y11 Compression_failure2(ind)]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt2 = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840], ‘EdgeColor’, ‘none’,’FaceAlpha’,0.0);

hatchfill2(tt2,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

hax = gca;
hax.XDir = ‘reverse’; % flip axis direction
hax.YAxisLocation = ‘right’; % move ticks & labels to the other side

xlim([-2 12])
ylim([-0.5 2])

ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

%Define the variable
xac = -2; %x arrow coordinate
yac = 0; %y arrow coordinate
xas = 12; %x arrow shift
yas = 0; %y arrow shift

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [0 0];
ha.Y = [-0.4 2] ;

% remove old box and axes
box on
set(gca,’YColor’,get(gca,’Color’))
set(gca,’XColor’,get(gca,’Color’))
set(gca, ‘FontName’, ‘Times New Roman’, ‘FontSize’, 14)
set(gca, ‘XTickLabel’, {});
set(gca, ‘YTickLabel’, {});

legend({‘Friction failure (M&M)’,’Tension failure (M&M)’,’Compression failure (M&M)’,’Friction failure (DK)’,’Tension failure (DK)’,’Compression failure (DK)’},’Location’,’northeast’,’NumColumns’,1,’Orientation’,’vertical’) The arrowhead is pointing the wrong way in the x-axis. See figure below.
Definerer alle landes forskydningsbæreevne
clc; clear; close all; clc ;

Forhold = 1/2 ;
Forhold2 = 54/228;

f_vk0 = 0.4 ; % Klæbningsbidrag [MPa]
mu_k = 0.65 ; % Friktionskoefficient
f_bt = 1.00 ; % Trækstyrke af sten [MPa]
f_k = 10.00 ; % Trykstyrke af sten [MPa]

sigma1 = -0.0:0.1:1.6 ;
sigma2 = 0.1:0.1:10.2;
sigma3 = 8.3:0.1:10 ;

sigma23 = 9.1:0.1:10 ;

Friction = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure = (f_k – sigma3) * 1/Forhold*(1/2) ;

Friction2 = (f_vk0 + mu_k * sigma1) / (1 + mu_k * 2 * Forhold2) ;
Tension_failure = f_bt / 2.3 * sqrt(1 + sigma2/f_bt) ;
Compression_failure2 = (f_k – sigma23) * 1/Forhold2*(1/2) ;

Plotter forskydningsbæreevnerne
hf = figure() ;
hold on
plot(sigma1, Friction,’–‘,’Color’,[0.4660 0.6740 0.1880],’LineWidth’,1.3)
plot(sigma2, Tension_failure,’–‘,’Color’,[0.9290 0.6940 0.1250],’LineWidth’,1.3)
plot(sigma3, Compression_failure,’–‘,’Color’,[0.4940 0.1840 0.5560],’LineWidth’,1.3)

plot(sigma1, Friction2,’LineWidth’,1.3)
plot(sigma2, Tension_failure,’Color’,[0.6350 0.0780 0.1840],’LineWidth’,1.3)
plot(sigma23, Compression_failure2,’Color’,[0.8500 0.3250 0.0980],’LineWidth’,1.3)

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);

grid on;

xlim([0 12])
ylim([0 2])

% Shade the area between [sigma1, Friction] and [sigma1, Friction2]
[x0,y0,~,~] = intersections(sigma1,Friction,sigma2, Tension_failure);
ind = (sigma1<x0);
sigma1b = [sigma1(ind) x0]; % add x0 of true intersection point
Frictionp = [Friction(ind) y0]; % add y0 of true intersection point
[x1,y1,~,~] = intersections(sigma1,Friction2,sigma2, Tension_failure);
ind = (sigma1<x1);
sigma1c = [sigma1(ind) x1]; % add x1 of true intersection point
Friction2p = [Friction2(ind) y1]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840],’FaceAlpha’,0.0,’EdgeColor’, ‘none’);
hatchfill2(tt,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

% Shade the area between [sigma3, Compression_failure] and [sigma3, Compression_failure2 ]
[x01,y01,~,~] = intersections(sigma3, Compression_failure,sigma2,Tension_failure);
ind = (sigma3>x01);
sigma1b = [x01 sigma3(ind)]; % add x0 of true intersection point
Frictionp = [y01 Compression_failure(ind)]; % add y0 of true intersection point
[x11,y11,~,~] = intersections(sigma23, Compression_failure2,sigma2,Tension_failure);
ind = (sigma23>x11);
sigma1c = [x11 sigma23(ind)]; % add x1 of true intersection point
Friction2p = [y11 Compression_failure2(ind)]; % add y1 of true intersection point

% fill([sigma1, fliplr(sigma1)], [Friction, fliplr(Friction2)], [0.7 0.7 0.7], ‘EdgeColor’, ‘none’);
tt2 = fill([sigma1b, fliplr(sigma1c)], [Frictionp, fliplr(Friction2p)], [0.6350 0.0780 0.1840], ‘EdgeColor’, ‘none’,’FaceAlpha’,0.0);

hatchfill2(tt2,’single’,’HatchAngle’,-45,’HatchDensity’,90,’HatchColor’,[0.6350 0.0780 0.1840],’HatchLineWidth’,1)

hax = gca;
hax.XDir = ‘reverse’; % flip axis direction
hax.YAxisLocation = ‘right’; % move ticks & labels to the other side

xlim([-2 12])
ylim([-0.5 2])

ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

%Define the variable
xac = -2; %x arrow coordinate
yac = 0; %y arrow coordinate
xas = 12; %x arrow shift
yas = 0; %y arrow shift

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [-1.5 11];
ha.Y = [0 0] ;

ha = annotation(‘arrow’);
ha.Parent = hf.CurrentAxes; % associate annotation with current axes
% now you can use data units
ha.X = [0 0];
ha.Y = [-0.4 2] ;

% remove old box and axes
box on
set(gca,’YColor’,get(gca,’Color’))
set(gca,’XColor’,get(gca,’Color’))
set(gca, ‘FontName’, ‘Times New Roman’, ‘FontSize’, 14)
set(gca, ‘XTickLabel’, {});
set(gca, ‘YTickLabel’, {});

legend({‘Friction failure (M&M)’,’Tension failure (M&M)’,’Compression failure (M&M)’,’Friction failure (DK)’,’Tension failure (DK)’,’Compression failure (DK)’},’Location’,’northeast’,’NumColumns’,1,’Orientation’,’vertical’) annotation(‘arrow’), ‘reverse’ MATLAB Answers — New Questions

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