Month: August 2024
جـلب الــحبيب البحرين 🔅 34328955 : 00.973 🔅 نمبر معالج روحاني بحريني ، السعودية قطر الامارات الكوي
جـلب الــحبيب البحرين :dim_button: 34328955 : 00.973 :dim_button: نمبر معالج روحاني بحريني ، السعودية قطر الامارات الكويت
رد المطلقة
فك السحر
خاتم روحاني
رقم شيخ روحاني
رقم معالج روحاني
جلب الحبيب السعودية
أحجار كريمة
فرج الضبعة
عرق السواحل
جـلب الــحبيب البحرين :dim_button: 34328955 : 00.973 :dim_button: نمبر معالج روحاني بحريني ، السعودية قطر الامارات الكويترد المطلقةفك السحرخاتم روحانيرقم شيخ روحانيرقم معالج روحانيجلب الحبيب السعوديةأحجار كريمة فرج الضبعةعرق السواحل Read More
جـلب الــحبيب كالبرق🔅 34328955 : 00.973 🔅 تلفون معالج روحاني بالمحرق، البحرين السعودية قطر الامار
جـلب الــحبيب كالبرق:dim_button: 34328955 : 00.973 :dim_button: تلفون معالج روحاني بالمحرق، البحرين السعودية قطر الامارات الكويت
رد المطلقة
فك السحر
خاتم روحاني
رقم شيخ روحاني
رقم معالج روحاني
جلب الحبيب السعودية
أحجار كريمة
فرج الضبعة
عرق السواحل
جـلب الــحبيب كالبرق:dim_button: 34328955 : 00.973 :dim_button: تلفون معالج روحاني بالمحرق، البحرين السعودية قطر الامارات الكويت رد المطلقةفك السحرخاتم روحانيرقم شيخ روحانيرقم معالج روحانيجلب الحبيب السعوديةأحجار كريمة فرج الضبعةعرق السواحل Read More
Microsoft Project / Planner question
Hello, new to this so I hope I’ve posted this question in the right place. I have been emailed a Microsoft Project .mpp file.
At present I don’t have the correct software to open and amend this file.
I am exploring whether I need to but an online subscription or make a one off purchase. the online subscription option suggests that I need to subscribe to Microsoft Planner. My queries is, will this allow me to import/load the file I’ve been emailed to allow me to edit it?
If it doesn’t presumably my only option is to make the one off purchase?
Many thanks in advance if there is anyone that can assist.
Hello, new to this so I hope I’ve posted this question in the right place. I have been emailed a Microsoft Project .mpp file.At present I don’t have the correct software to open and amend this file.I am exploring whether I need to but an online subscription or make a one off purchase. the online subscription option suggests that I need to subscribe to Microsoft Planner. My queries is, will this allow me to import/load the file I’ve been emailed to allow me to edit it?If it doesn’t presumably my only option is to make the one off purchase?Many thanks in advance if there is anyone that can assist. Read More
Test Discussion
Hello All,
Hum!!! It seems that my original posts are not added to the discussions.
I am sending this Test post to see if that is true and if you see it would you please let me know. I will wait for a couple of days to see if this is happening.
Thanks
GiGi.
Hello All, Hum!!! It seems that my original posts are not added to the discussions. I am sending this Test post to see if that is true and if you see it would you please let me know. I will wait for a couple of days to see if this is happening. Thanks GiGi. Read More
جلب الحبيب بقاديشر 🩵-81277 010405 002- شيخ روحاني لجلب الحبيب #
جلب الحبيب – شيخ روحاني – رقم شيخ روحاني – جلب الحبيب السعودية – شيخ روحاني لجلب الحبيب – شيخ روحاني فى السعودية – شيخ روحاني فى الاردن – جلب الحبيب قطر – شيخ روحاني فى الكويت – جلب الحبيب للزواج – شيخ روحاني فى الامارات – جلب الحبيب السعودية – شيخ روحاني فى عمان – رد المطلقة – Read More
جلب الحبيب بنغمات البيانو # 🟡00.973.33766.836
جلب الحبيب بنغمات البيانو # 🟡00.973.33766.836
جلب الحبيب بنغمات البيانو # 🟡00.973.33766.836 Read More
جلب الحبيب| #الشيخ_روحاني (5849264 0096655 )
جلب الحبيب| #الشيخ_روحاني (5849264 0096655 )
السعودية
قطر
البحرين
الإمارات
الكويت
عُمان
جلب الحبيب| #الشيخ_روحاني (5849264 0096655 )السعوديةقطرالبحرينالإماراتالكويتعُمان Read More
جـلب الــحبيب المانيا 🔅 34328955 : 00.973 🔅 تنزيل الأموال بالمجربة
جـلب الــحبيب المانيا :dim_button: 34328955 : 00.973 :dim_button: تنزيل الأموال بالمجربة
رد المطلقة
فك السحر
رقم شيخ روحاني
رقم معالج روحاني
زواج العانس
السعودية الكويت قطر الامارات عُمان البحرين
جـلب الــحبيب المانيا :dim_button: 34328955 : 00.973 :dim_button: تنزيل الأموال بالمجربةرد المطلقةفك السحر رقم شيخ روحانيرقم معالج روحانيزواج العانسالسعودية الكويت قطر الامارات عُمان البحرين Read More
جلب الحبيب بالاسم -581277 01040 002- شيخ روحاني متمكن قوى #
شيخ روحاني ، جلب الحبيب بالظريامك، شيخ روحاني عجرمى ، جلب الحبيب للزواج ، شيخ روحاني فى مكة ، شيخ روحاني فى جدة ، جلب الحبيب الرياض ، شيخ روحاني بالسعودية ، الشيخ الروحاني
شيخ روحاني ، جلب الحبيب بالظريامك، شيخ روحاني عجرمى ، جلب الحبيب للزواج ، شيخ روحاني فى مكة ، شيخ روحاني فى جدة ، جلب الحبيب الرياض ، شيخ روحاني بالسعودية ، الشيخ الروحاني Read More
جلب الحبيب| شيخ روحاني 🔴 ـ1277 4058 010 002- رقم شيخ روحاني ¥
جلب الحبيب الرياض ، شيخ روحاني المدينة المنورة ، رقم شيخ روحاني السعودية ، شيخ روحاني فى السعودية ، شيخ روحاني فى الرياض ، شيخ روحاني فى الاردن ، شيخ روحاني فى جدة ، جلب الحبيب السعودية ، شيخ روحاني فى الكويت ، شيخ روحاني فى الامارات ، جلب الحبيب للزواج شيخ روحاني فى عمان
جلب الحبيب الرياض ، شيخ روحاني المدينة المنورة ، رقم شيخ روحاني السعودية ، شيخ روحاني فى السعودية ، شيخ روحاني فى الرياض ، شيخ روحاني فى الاردن ، شيخ روحاني فى جدة ، جلب الحبيب السعودية ، شيخ روحاني فى الكويت ، شيخ روحاني فى الامارات ، جلب الحبيب للزواج شيخ روحاني فى عمان Read More
شيخـ جلب الحبيب♻️ -٩ِ٦ِ٦ِْ٥ِ٥٥ِْ٨ِْ٤ِ٩ِ٢ِِ٦ِ٤ ٠َ٠ -♻️رد المطلقة | فك السحر | رقم شيخ روحاني الــســع
شيخـ جلب الحبيب:recycling_symbol: -٩ِ٦ِ٦ِْ٥ِ٥٥ِْ٨ِْ٤ِ٩ِ٢ِِ٦ِ٤ ٠َ٠ -:recycling_symbol:رد المطلقة | فك السحر | رقم شيخ روحاني الــســعـوديـة
شيخـ جلب الحبيب:recycling_symbol: -٩ِ٦ِ٦ِْ٥ِ٥٥ِْ٨ِْ٤ِ٩ِ٢ِِ٦ِ٤ ٠َ٠ -:recycling_symbol:رد المطلقة | فك السحر | رقم شيخ روحاني الــســعـوديـةفك السحر ، رد المطلقة ، جلب الحبيب، خواتم روحانية، عرق السواحل، فرج الضبعة، تزويج البائر، تسهيل الزواج ، علاج العقم، تفريق وطلاق ، طاعة عمياء، عقد لسان الظالم ، جلب الحبيب السعودية ، جلب الحبيب قطر ، جلب الحبيب الكويت ، جلب الحبيب الإمارات ، سحر سفلي ، سحر علوي ،جلب البنت للبنت ، جلب الشاب للشاب ، شيخ روحاني، شيخة، روحانية، ساحر، مشعوذ، سحر أسود، سحر تفريق، سحر علوي ، جلب الحبيب البحرين، جلب الحبيب عُمان Read More
جلب الحبيب بسرعة نارية -🍁0ِ0ِ9ِ73ِ34ِ31ِ09ِ9ِ5 – شيخ روحاني مشهور
جلب الحبيب بسرعة نارية -:maple_leaf:0ِ0ِ9ِ73ِ34ِ31ِ09ِ9ِ5 – شيخ روحاني مشهور
جلب الحبيب بسرعة نارية -:maple_leaf:0ِ0ِ9ِ73ِ34ِ31ِ09ِ9ِ5 – شيخ روحاني مشهور Read More
How can I plot a bar chart with 4 different y-axis and standard deviation?
Hello,
I would like to have a bar plot with 4 different categories. Each has got its own y-axis, as shown in the attached picture.
<</matlabcentral/answers/uploaded_files/79925/bar_4y-axis.JPG>>
I figured out that there is a possibility to add mutlitple axis to a plot <https://de.mathworks.com/matlabcentral/fileexchange/9016-addaxis (addaxis)>. I’m using MATLAB R2014a, but I have access to R2017a at my university, if needed.
This is my current code, based on this <https://de.mathworks.com/matlabcentral/answers/136433-how-to-add-errorbars example>:
function[]=test_multiple_axis_2()
w=[1.0,2.5,3.9,9.8,5.5,6.6,8.8,5.4,7.4,6.5];
x=[11.1,21.5,23.7,19.8,14.7,15.6,12.7,13.8,14.9,11.4];
y=[15.7,16.8,25.9,18.6,16.9,20.4,23.8,19.9,17.8,21.8];
z=[21.5,26.8,17.7,18.9,16.5,25.6,29.3,18.9,26.8,24.5];
std_w=[0.7,1.7,1.7,4.5,0.1,4.8,1.2,4.1,1.4,1.0];
std_x=[2.2,5.4,3.3,5.2,1.9,4.8,5.4,3.2,4.7,6.2];
std_y=[6.2,2.5,2.6,3.9,7.8,4.1,5.6,4.2,6.6,7.1];
std_z=[8.7,5.4,6.5,7.4,2.3,2.2,1.9,9.2,1.7,7.5];
hb = bar([1 2 3 4 5 6 7 8 9 10],[w’ x’ y’ z’])
legend(‘w’,’x’,’y’,’z’);
set(gca, ‘FontSize’,12,’XTick’,[1 2 3 4 5 6 7 8 9 10],’XTickLabel’,{‘A’,’B’,’C’,’D’,’E’,’F’,’G’,’H’,’I’,’J’});
ylabel(‘unit w’)%Here should be the addaxis code
errbar = [std_w; std_x; std_y; std_z]; % CREATE ‘errbar’ MATRIX
yd = [w’ x’ y’ z’]’;
keyboard %i didn’t understand the following code
hold on
for k1 = 1:3
errorbar([1:3]+.22*(k1-2), yd(k1,:), errbar(k1,:), ‘.k’, ‘LineWidth’,2)
end
hold off
returnHello,
I would like to have a bar plot with 4 different categories. Each has got its own y-axis, as shown in the attached picture.
<</matlabcentral/answers/uploaded_files/79925/bar_4y-axis.JPG>>
I figured out that there is a possibility to add mutlitple axis to a plot <https://de.mathworks.com/matlabcentral/fileexchange/9016-addaxis (addaxis)>. I’m using MATLAB R2014a, but I have access to R2017a at my university, if needed.
This is my current code, based on this <https://de.mathworks.com/matlabcentral/answers/136433-how-to-add-errorbars example>:
function[]=test_multiple_axis_2()
w=[1.0,2.5,3.9,9.8,5.5,6.6,8.8,5.4,7.4,6.5];
x=[11.1,21.5,23.7,19.8,14.7,15.6,12.7,13.8,14.9,11.4];
y=[15.7,16.8,25.9,18.6,16.9,20.4,23.8,19.9,17.8,21.8];
z=[21.5,26.8,17.7,18.9,16.5,25.6,29.3,18.9,26.8,24.5];
std_w=[0.7,1.7,1.7,4.5,0.1,4.8,1.2,4.1,1.4,1.0];
std_x=[2.2,5.4,3.3,5.2,1.9,4.8,5.4,3.2,4.7,6.2];
std_y=[6.2,2.5,2.6,3.9,7.8,4.1,5.6,4.2,6.6,7.1];
std_z=[8.7,5.4,6.5,7.4,2.3,2.2,1.9,9.2,1.7,7.5];
hb = bar([1 2 3 4 5 6 7 8 9 10],[w’ x’ y’ z’])
legend(‘w’,’x’,’y’,’z’);
set(gca, ‘FontSize’,12,’XTick’,[1 2 3 4 5 6 7 8 9 10],’XTickLabel’,{‘A’,’B’,’C’,’D’,’E’,’F’,’G’,’H’,’I’,’J’});
ylabel(‘unit w’)%Here should be the addaxis code
errbar = [std_w; std_x; std_y; std_z]; % CREATE ‘errbar’ MATRIX
yd = [w’ x’ y’ z’]’;
keyboard %i didn’t understand the following code
hold on
for k1 = 1:3
errorbar([1:3]+.22*(k1-2), yd(k1,:), errbar(k1,:), ‘.k’, ‘LineWidth’,2)
end
hold off
return Hello,
I would like to have a bar plot with 4 different categories. Each has got its own y-axis, as shown in the attached picture.
<</matlabcentral/answers/uploaded_files/79925/bar_4y-axis.JPG>>
I figured out that there is a possibility to add mutlitple axis to a plot <https://de.mathworks.com/matlabcentral/fileexchange/9016-addaxis (addaxis)>. I’m using MATLAB R2014a, but I have access to R2017a at my university, if needed.
This is my current code, based on this <https://de.mathworks.com/matlabcentral/answers/136433-how-to-add-errorbars example>:
function[]=test_multiple_axis_2()
w=[1.0,2.5,3.9,9.8,5.5,6.6,8.8,5.4,7.4,6.5];
x=[11.1,21.5,23.7,19.8,14.7,15.6,12.7,13.8,14.9,11.4];
y=[15.7,16.8,25.9,18.6,16.9,20.4,23.8,19.9,17.8,21.8];
z=[21.5,26.8,17.7,18.9,16.5,25.6,29.3,18.9,26.8,24.5];
std_w=[0.7,1.7,1.7,4.5,0.1,4.8,1.2,4.1,1.4,1.0];
std_x=[2.2,5.4,3.3,5.2,1.9,4.8,5.4,3.2,4.7,6.2];
std_y=[6.2,2.5,2.6,3.9,7.8,4.1,5.6,4.2,6.6,7.1];
std_z=[8.7,5.4,6.5,7.4,2.3,2.2,1.9,9.2,1.7,7.5];
hb = bar([1 2 3 4 5 6 7 8 9 10],[w’ x’ y’ z’])
legend(‘w’,’x’,’y’,’z’);
set(gca, ‘FontSize’,12,’XTick’,[1 2 3 4 5 6 7 8 9 10],’XTickLabel’,{‘A’,’B’,’C’,’D’,’E’,’F’,’G’,’H’,’I’,’J’});
ylabel(‘unit w’)%Here should be the addaxis code
errbar = [std_w; std_x; std_y; std_z]; % CREATE ‘errbar’ MATRIX
yd = [w’ x’ y’ z’]’;
keyboard %i didn’t understand the following code
hold on
for k1 = 1:3
errorbar([1:3]+.22*(k1-2), yd(k1,:), errbar(k1,:), ‘.k’, ‘LineWidth’,2)
end
hold off
return bar plot, standard deviation, multiple axis MATLAB Answers — New Questions
plot an obtained function after several calculus
Good morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold offGood morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold off Good morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold off plot, symbolique function MATLAB Answers — New Questions
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plot several equation and extract vertices
How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture?How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture? How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture? plot, vertex, equation MATLAB Answers — New Questions
Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite
Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances)Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) simulink, power_electronics_control, power_conversion_control, electric_motor_control, control system, pi controllrt MATLAB Answers — New Questions
