Hello,
In the Matlab example, you have the dot product of the following two vectors A and B and its answer is vector C.
A = [1+i 1-i -1+i -1-i];
B = [3-4i 6-2i 1+2i 4+3i];
Calculate the dot product of A and B.
C = dot(A,B)
C = 1.0000 – 5.0000i
However, when I calculate it, I have vector C = 7 – 17i
That is, I have C vector results as follows below
(1+i) * (3-4i) + (1-i) * (6-2i) + (-1+i) * (1+2i) + (-1-i) * (4+3i) =
(7-i) +( 4-8i) + (-3-i) + (-1-7i) =
7 – 17i.
Hence, could you please tell me how the Matlab got the results (or show me manually how Matlab got the dot product answer) as I have different results than Matlab calculated using dot product?
Thank you,
CharlesHello,
In the Matlab example, you have the dot product of the following two vectors A and B and its answer is vector C.
A = [1+i 1-i -1+i -1-i];
B = [3-4i 6-2i 1+2i 4+3i];
Calculate the dot product of A and B.
C = dot(A,B)
C = 1.0000 – 5.0000i
However, when I calculate it, I have vector C = 7 – 17i
That is, I have C vector results as follows below
(1+i) * (3-4i) + (1-i) * (6-2i) + (-1+i) * (1+2i) + (-1-i) * (4+3i) =
(7-i) +( 4-8i) + (-3-i) + (-1-7i) =
7 – 17i.
Hence, could you please tell me how the Matlab got the results (or show me manually how Matlab got the dot product answer) as I have different results than Matlab calculated using dot product?
Thank you,
Charles Hello,
In the Matlab example, you have the dot product of the following two vectors A and B and its answer is vector C.
A = [1+i 1-i -1+i -1-i];
B = [3-4i 6-2i 1+2i 4+3i];
Calculate the dot product of A and B.
C = dot(A,B)
C = 1.0000 – 5.0000i
However, when I calculate it, I have vector C = 7 – 17i
That is, I have C vector results as follows below
(1+i) * (3-4i) + (1-i) * (6-2i) + (-1+i) * (1+2i) + (-1-i) * (4+3i) =
(7-i) +( 4-8i) + (-3-i) + (-1-7i) =
7 – 17i.
Hence, could you please tell me how the Matlab got the results (or show me manually how Matlab got the dot product answer) as I have different results than Matlab calculated using dot product?
Thank you,
Charles dot product MATLAB Answers — New Questions
