Apply 2-D logical mask to obtain masked third dimension values in 3-D array

This is difficult to describe in words so I have given an example below. I have a 3-D array. Some of the values are NaNs (although this is not directly relevant to my question). I want to apply a 2-D mask to the first two dimensions and arrange all the third dimensions behind the mask as sequential rows in a 2-D array. I’m looking for a way to do this without ‘for’ loops.
Here’s the example:
% Set up the example 3-D array and mask

BW = logical([0,0,1; 0,1,1; 1,1,0; 1,0,0]); %create a mask

A = 9*ones(4,3,3); % create a 3 dimensional array
A(:,:,2) = 8*ones(4,3); % Make the second ‘slice’ 8s
A(:,:,3) = 7*ones(4,3); % Make the third ‘slice’ 8s
A(1,3,1) = NaN; % add a NaN
A(3,2,3) = NaN; % add another NaN
A(4,1,2) = NaN % add another NaN
% Apply the mask and organise the masked third dimension values into a 2-D array
my2Darray = zeros(1,size(A,3));

for row=1:(size(A,1))
for col=1:(size(A,2))
if (BW(row,col))
mySpectrum = squeeze (A(row, col,:))’;
my2Darray = cat (1, my2Darray, mySpectrum);
end
end
end

my2Darray(1,:) = [] % Get rid of the first row of zeros
The outcome is correct. The total number of rows in my2Darray should be equal to sum(sum(BW)).
But is there an elegant way to reshape this that doesn’t require the ‘for’ loops, please?This is difficult to describe in words so I have given an example below. I have a 3-D array. Some of the values are NaNs (although this is not directly relevant to my question). I want to apply a 2-D mask to the first two dimensions and arrange all the third dimensions behind the mask as sequential rows in a 2-D array. I’m looking for a way to do this without ‘for’ loops.
Here’s the example:
% Set up the example 3-D array and mask

BW = logical([0,0,1; 0,1,1; 1,1,0; 1,0,0]); %create a mask

for row=1:(size(A,1))
for col=1:(size(A,2))
if (BW(row,col))
mySpectrum = squeeze (A(row, col,:))’;
my2Darray = cat (1, my2Darray, mySpectrum);
end
end
end

my2Darray(1,:) = [] % Get rid of the first row of zeros
The outcome is correct. The total number of rows in my2Darray should be equal to sum(sum(BW)).
But is there an elegant way to reshape this that doesn’t require the ‘for’ loops, please? This is difficult to describe in words so I have given an example below. I have a 3-D array. Some of the values are NaNs (although this is not directly relevant to my question). I want to apply a 2-D mask to the first two dimensions and arrange all the third dimensions behind the mask as sequential rows in a 2-D array. I’m looking for a way to do this without ‘for’ loops.
Here’s the example:
% Set up the example 3-D array and mask

BW = logical([0,0,1; 0,1,1; 1,1,0; 1,0,0]); %create a mask

for row=1:(size(A,1))
for col=1:(size(A,2))
if (BW(row,col))
mySpectrum = squeeze (A(row, col,:))’;
my2Darray = cat (1, my2Darray, mySpectrum);
end
end
end

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