Can integral2 left a variable inside?

Hi,everyone.There’re three variables in my function,x,y and w.
I want to integral x and y first,but there were a variable w stuck in my function.Can I left it and integral x,y first? Thank you.
clear

L=0.1;
section=50;
a=L/2;
b=L/section;
v=3e8;
f1=1.2e9;
f2=4.8e9;
f3=7.5e9;
f4=10e9;
w1=(2*pi*f1);
w2=(2*pi*f2);
w3=(2*pi*f3);
w4=(2*pi*f4);
Z01=50;
Z02=75;
a0=(log(Z02/Z01))./(2.*L);
T=a;
Ub=a;
Lb=-a;
ub=a;
lb=-a;
k=6;

syms x y w

l=0:(2*L)/(2*k):L % Approximate sections dvided

sec=numel(l)-1;

% Cm0

for s=1:1:sec

for t=1:1:sec

for m=1:1:k

P1=matlabFunction(((cos((m.*pi.*(y))./a)).*(cos(2.*(x-y).*w./v))));

P2(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),Lb+l(t),@(x)x);

P3(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),@(x)x,Lb+l(t+1));

P{s,t}=(P2+P3) % s section multiply t section

end

endHi,everyone.There’re three variables in my function,x,y and w.
I want to integral x and y first,but there were a variable w stuck in my function.Can I left it and integral x,y first? Thank you.
clear

syms x y w

l=0:(2*L)/(2*k):L % Approximate sections dvided

sec=numel(l)-1;

% Cm0

for s=1:1:sec

for t=1:1:sec

for m=1:1:k

P1=matlabFunction(((cos((m.*pi.*(y))./a)).*(cos(2.*(x-y).*w./v))));

P2(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),Lb+l(t),@(x)x);

P3(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),@(x)x,Lb+l(t+1));

P{s,t}=(P2+P3) % s section multiply t section

end

end Hi,everyone.There’re three variables in my function,x,y and w.
I want to integral x and y first,but there were a variable w stuck in my function.Can I left it and integral x,y first? Thank you.
clear

syms x y w

l=0:(2*L)/(2*k):L % Approximate sections dvided

sec=numel(l)-1;

% Cm0

for s=1:1:sec

for t=1:1:sec

for m=1:1:k

P1=matlabFunction(((cos((m.*pi.*(y))./a)).*(cos(2.*(x-y).*w./v))));

P2(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),Lb+l(t),@(x)x);

P3(1,m)=integral2(P1,Lb+l(s),Lb+l(s+1),@(x)x,Lb+l(t+1));

P{s,t}=(P2+P3) % s section multiply t section

end

end integral2 MATLAB Answers — New Questions

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