Hello,
I am trying to filter my images to a certain cycles per degree (cpd). I have obtained the visual angle of the image, and I would like to low-pass filter my images to under 1 cpd using a Gaussian filter. However, I couldn’t figure out what sigma I should use in the imgaussfilt function. Is there a direct formula for the conversion?
I was looking at a similar question here, where we first calculate the visual angle, but it does not mention how it relates to the second formula to obtain sigma. Additionally, there is a constant k in the formula, but I am not sure how to determine what is an appropriate k to use. I would appreciate any help. Thank you!Hello,
I am trying to filter my images to a certain cycles per degree (cpd). I have obtained the visual angle of the image, and I would like to low-pass filter my images to under 1 cpd using a Gaussian filter. However, I couldn’t figure out what sigma I should use in the imgaussfilt function. Is there a direct formula for the conversion?
I was looking at a similar question here, where we first calculate the visual angle, but it does not mention how it relates to the second formula to obtain sigma. Additionally, there is a constant k in the formula, but I am not sure how to determine what is an appropriate k to use. I would appreciate any help. Thank you! Hello,
I am trying to filter my images to a certain cycles per degree (cpd). I have obtained the visual angle of the image, and I would like to low-pass filter my images to under 1 cpd using a Gaussian filter. However, I couldn’t figure out what sigma I should use in the imgaussfilt function. Is there a direct formula for the conversion?
I was looking at a similar question here, where we first calculate the visual angle, but it does not mention how it relates to the second formula to obtain sigma. Additionally, there is a constant k in the formula, but I am not sure how to determine what is an appropriate k to use. I would appreciate any help. Thank you! spatial frequency, image processing, imgaussfilt, gaussian MATLAB Answers — New Questions

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