syms x t%a g d l1 m1
%%%%%%%%%%%%%%%% Fractional Order%
alpha=2;
beta=1;
%%%%%%%%%%%% initilization of variable%%%%%%
U=zeros(1,2,’sym’);
V=zeros(1,2,’sym’);
A=zeros(1,2,’sym’);
B=zeros(1,2,’sym’);
C=zeros(1,2,’sym’);
D=zeros(1,2,’sym’);
E=zeros(1,2,’sym’);
F=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
series1(x,t)=sym(zeros(1,1));
series2(x,t)=sym(zeros(1,1));
a=1;
g=0.01;
d=0.01;
l1=-(4/9)*g^4*d+(16/27)*g^6-(5/9)*g^2*d^2-(5/54)*d^3;
m1=20*g^4*d-16*g^6+5*g^2*d^2;
U(1)=a-2*g*cot(g*x);
U(2)=-2*g^2*d*csc(g*x)*csc(g*x);
V(1)=l1-(1/9)*m1*cot(g*x)*cot(g*x);
for k=1:3
A(1)=0;
B(1)=0;
C(1)=0;
D(1)=0;
E(1)=0;
F(1)=0;
G(1)=0;
for r=1:k
A(1)=A(1)+diff(U(r),x,2)*diff(U(k-r+1),x,3);
B(1)=B(1)+diff(U(r),x,1)*diff(U(k-r+1),x,4);
D(1)=D(1)+diff(U(r),x,2)*(k-r+1)*U(k-r+1);
E(1)=E(1)+diff(U(r),x,1)*(k-r+1)*diff(U(k-r+1),x,1);
F(1)=F(1)+diff(V(r),x,1)*diff(U(k-r+1),x,1);
G(1)=G(1)+V(r)*diff(U(k-r+1),x,2);
for l=1:r
C(1)=C(1)+diff(U(l),x,1)*diff(U(r-l+1),x,1)*diff(U(k-r+1),x,2);% 4th term
end
end
U(k+2)=gamma(((k-1)*alpha)+1)/gamma((alpha*(k+1-1))+1)*((1/5)*diff(U(k),x,6)+3*A(1)+3*B(1)+9*C(1)-(k)*diff(U(k+1),x,2)-3*D(1)-3*E(1)+(18/5)*diff(V(k),x,1))
V(k+1)=gamma(((k-1)*beta)+1)/gamma((beta*(k+1-1))+1)*(diff(V(k),x,3)+3*F(1)+3*G(1));
end
for k=1:2
series1(x,t)=simplify(series1(x,t)+U(k)*power(t,k-1));
series2(x,t)=simplify(series2(x,t)+V(k)*power(t,k-1));
end
series1
series2
row=0
for r=1:10:110
row=row+1;
col=0;
e=r-1
for t=1
col=col+1;
f=t+19
C1(row,col)=series1(e,f);
C2(row,col)=series2(e,f);
end
end
vpa(C1,15)
vpa(C2,15)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
x=10:10:100
t=20
row=0
for i=1:length(x)
row=row+1
col=col+1
for j=1:length(t)
C1(row, col) =series1(x(i), t(i))
C2(row,col) =series2(x(i),t(i))
end
end
This two for loop shows thw different value of C1 and C2 . The first for loop gives the correct value for C1 but not C2. But the second loop give both wrong
.
I want know the value of x anf t are same then why for loop show two different valuesyms x t%a g d l1 m1
%%%%%%%%%%%%%%%% Fractional Order%
alpha=2;
beta=1;
%%%%%%%%%%%% initilization of variable%%%%%%
U=zeros(1,2,’sym’);
V=zeros(1,2,’sym’);
A=zeros(1,2,’sym’);
B=zeros(1,2,’sym’);
C=zeros(1,2,’sym’);
D=zeros(1,2,’sym’);
E=zeros(1,2,’sym’);
F=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
series1(x,t)=sym(zeros(1,1));
series2(x,t)=sym(zeros(1,1));
a=1;
g=0.01;
d=0.01;
l1=-(4/9)*g^4*d+(16/27)*g^6-(5/9)*g^2*d^2-(5/54)*d^3;
m1=20*g^4*d-16*g^6+5*g^2*d^2;
U(1)=a-2*g*cot(g*x);
U(2)=-2*g^2*d*csc(g*x)*csc(g*x);
V(1)=l1-(1/9)*m1*cot(g*x)*cot(g*x);
for k=1:3
A(1)=0;
B(1)=0;
C(1)=0;
D(1)=0;
E(1)=0;
F(1)=0;
G(1)=0;
for r=1:k
A(1)=A(1)+diff(U(r),x,2)*diff(U(k-r+1),x,3);
B(1)=B(1)+diff(U(r),x,1)*diff(U(k-r+1),x,4);
D(1)=D(1)+diff(U(r),x,2)*(k-r+1)*U(k-r+1);
E(1)=E(1)+diff(U(r),x,1)*(k-r+1)*diff(U(k-r+1),x,1);
F(1)=F(1)+diff(V(r),x,1)*diff(U(k-r+1),x,1);
G(1)=G(1)+V(r)*diff(U(k-r+1),x,2);
for l=1:r
C(1)=C(1)+diff(U(l),x,1)*diff(U(r-l+1),x,1)*diff(U(k-r+1),x,2);% 4th term
end
end
U(k+2)=gamma(((k-1)*alpha)+1)/gamma((alpha*(k+1-1))+1)*((1/5)*diff(U(k),x,6)+3*A(1)+3*B(1)+9*C(1)-(k)*diff(U(k+1),x,2)-3*D(1)-3*E(1)+(18/5)*diff(V(k),x,1))
V(k+1)=gamma(((k-1)*beta)+1)/gamma((beta*(k+1-1))+1)*(diff(V(k),x,3)+3*F(1)+3*G(1));
end
for k=1:2
series1(x,t)=simplify(series1(x,t)+U(k)*power(t,k-1));
series2(x,t)=simplify(series2(x,t)+V(k)*power(t,k-1));
end
series1
series2
row=0
for r=1:10:110
row=row+1;
col=0;
e=r-1
for t=1
col=col+1;
f=t+19
C1(row,col)=series1(e,f);
C2(row,col)=series2(e,f);
end
end
vpa(C1,15)
vpa(C2,15)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
x=10:10:100
t=20
row=0
for i=1:length(x)
row=row+1
col=col+1
for j=1:length(t)
C1(row, col) =series1(x(i), t(i))
C2(row,col) =series2(x(i),t(i))
end
end
This two for loop shows thw different value of C1 and C2 . The first for loop gives the correct value for C1 but not C2. But the second loop give both wrong
.
I want know the value of x anf t are same then why for loop show two different value syms x t%a g d l1 m1
%%%%%%%%%%%%%%%% Fractional Order%
alpha=2;
beta=1;
%%%%%%%%%%%% initilization of variable%%%%%%
U=zeros(1,2,’sym’);
V=zeros(1,2,’sym’);
A=zeros(1,2,’sym’);
B=zeros(1,2,’sym’);
C=zeros(1,2,’sym’);
D=zeros(1,2,’sym’);
E=zeros(1,2,’sym’);
F=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
series1(x,t)=sym(zeros(1,1));
series2(x,t)=sym(zeros(1,1));
a=1;
g=0.01;
d=0.01;
l1=-(4/9)*g^4*d+(16/27)*g^6-(5/9)*g^2*d^2-(5/54)*d^3;
m1=20*g^4*d-16*g^6+5*g^2*d^2;
U(1)=a-2*g*cot(g*x);
U(2)=-2*g^2*d*csc(g*x)*csc(g*x);
V(1)=l1-(1/9)*m1*cot(g*x)*cot(g*x);
for k=1:3
A(1)=0;
B(1)=0;
C(1)=0;
D(1)=0;
E(1)=0;
F(1)=0;
G(1)=0;
for r=1:k
A(1)=A(1)+diff(U(r),x,2)*diff(U(k-r+1),x,3);
B(1)=B(1)+diff(U(r),x,1)*diff(U(k-r+1),x,4);
D(1)=D(1)+diff(U(r),x,2)*(k-r+1)*U(k-r+1);
E(1)=E(1)+diff(U(r),x,1)*(k-r+1)*diff(U(k-r+1),x,1);
F(1)=F(1)+diff(V(r),x,1)*diff(U(k-r+1),x,1);
G(1)=G(1)+V(r)*diff(U(k-r+1),x,2);
for l=1:r
C(1)=C(1)+diff(U(l),x,1)*diff(U(r-l+1),x,1)*diff(U(k-r+1),x,2);% 4th term
end
end
U(k+2)=gamma(((k-1)*alpha)+1)/gamma((alpha*(k+1-1))+1)*((1/5)*diff(U(k),x,6)+3*A(1)+3*B(1)+9*C(1)-(k)*diff(U(k+1),x,2)-3*D(1)-3*E(1)+(18/5)*diff(V(k),x,1))
V(k+1)=gamma(((k-1)*beta)+1)/gamma((beta*(k+1-1))+1)*(diff(V(k),x,3)+3*F(1)+3*G(1));
end
for k=1:2
series1(x,t)=simplify(series1(x,t)+U(k)*power(t,k-1));
series2(x,t)=simplify(series2(x,t)+V(k)*power(t,k-1));
end
series1
series2
row=0
for r=1:10:110
row=row+1;
col=0;
e=r-1
for t=1
col=col+1;
f=t+19
C1(row,col)=series1(e,f);
C2(row,col)=series2(e,f);
end
end
vpa(C1,15)
vpa(C2,15)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
x=10:10:100
t=20
row=0
for i=1:length(x)
row=row+1
col=col+1
for j=1:length(t)
C1(row, col) =series1(x(i), t(i))
C2(row,col) =series2(x(i),t(i))
end
end
This two for loop shows thw different value of C1 and C2 . The first for loop gives the correct value for C1 but not C2. But the second loop give both wrong
.
I want know the value of x anf t are same then why for loop show two different value for loop error MATLAB Answers — New Questions

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