## How to determe the Fatigue Damage according Miner’s Rule via rainflow counting

Dear Matlab Users,

I have difficulties calculating the total accumulated fatique damage for a set of data (see Attachements). I have determined the histogram based on Rainflow counting, and determined the line for the SN-curve (maximum allowable stress per cycle). The SN-curve has only one slope in this case.

To calculate the total accumulated fatique damage according Miner’s Rule, the number of cycles of the SN curve should be divided by the number of cycles of the histogram per stress range, and then be summed up.

My question is: How do I divide the values from the number of cycles of the SN-curve by the the values from the number of cycles of the histogram? How do I make the values of the same size? I want to divide the following (see script for clarification):

N=10.^(L_a1-m1*log(cigma_delta*(T/T_ref)^k)); with cigma_delta= [0:0.05:710]; % N-cycles SN-curve

by

C_7=histogram(‘BinEdges’,edges’,’BinCounts’,sum(hist,2), Orientation=’horizontal’) % Rainflow counting histogram

Thanks in advance!Dear Matlab Users,

I have difficulties calculating the total accumulated fatique damage for a set of data (see Attachements). I have determined the histogram based on Rainflow counting, and determined the line for the SN-curve (maximum allowable stress per cycle). The SN-curve has only one slope in this case.

To calculate the total accumulated fatique damage according Miner’s Rule, the number of cycles of the SN curve should be divided by the number of cycles of the histogram per stress range, and then be summed up.

My question is: How do I divide the values from the number of cycles of the SN-curve by the the values from the number of cycles of the histogram? How do I make the values of the same size? I want to divide the following (see script for clarification):

N=10.^(L_a1-m1*log(cigma_delta*(T/T_ref)^k)); with cigma_delta= [0:0.05:710]; % N-cycles SN-curve

by

C_7=histogram(‘BinEdges’,edges’,’BinCounts’,sum(hist,2), Orientation=’horizontal’) % Rainflow counting histogram

Thanks in advance! Dear Matlab Users,

I have difficulties calculating the total accumulated fatique damage for a set of data (see Attachements). I have determined the histogram based on Rainflow counting, and determined the line for the SN-curve (maximum allowable stress per cycle). The SN-curve has only one slope in this case.

To calculate the total accumulated fatique damage according Miner’s Rule, the number of cycles of the SN curve should be divided by the number of cycles of the histogram per stress range, and then be summed up.

My question is: How do I divide the values from the number of cycles of the SN-curve by the the values from the number of cycles of the histogram? How do I make the values of the same size? I want to divide the following (see script for clarification):

N=10.^(L_a1-m1*log(cigma_delta*(T/T_ref)^k)); with cigma_delta= [0:0.05:710]; % N-cycles SN-curve

by

C_7=histogram(‘BinEdges’,edges’,’BinCounts’,sum(hist,2), Orientation=’horizontal’) % Rainflow counting histogram

Thanks in advance! rainflow counting, miner’s rule, histogram, sn-curve, fatigue MATLAB Answers — New Questions