How to make binary to gray scale
Dear All,
I created the image. My coding as below.
Z = zeros(99); % create square matrix of zeroes
origin = [round((size(Z,2)-1)/2+1) round((size(Z,1)-1)/2+1)]; % "center" of the matrix
radius = round(sqrt(numel(Z)/(2*pi))); % radius for a circle that fills half the area of the matrix
[xx,yy] = meshgrid((1:size(Z,2))-origin(1),(1:size(Z,1))-origin(2)); % create x and y grid
Z(sqrt(xx.^2 + yy.^2) <= radius) = 1; % set points inside the radius equal to one
imshow(Z); % show the "image"
NOW my pixel number just 1 and 0 (binary).
Do you know how to make the pixel number is gray scale. I mean is the gradient pixel number from center to edge is decending?Dear All,
I created the image. My coding as below.
Z = zeros(99); % create square matrix of zeroes
origin = [round((size(Z,2)-1)/2+1) round((size(Z,1)-1)/2+1)]; % "center" of the matrix
radius = round(sqrt(numel(Z)/(2*pi))); % radius for a circle that fills half the area of the matrix
[xx,yy] = meshgrid((1:size(Z,2))-origin(1),(1:size(Z,1))-origin(2)); % create x and y grid
Z(sqrt(xx.^2 + yy.^2) <= radius) = 1; % set points inside the radius equal to one
imshow(Z); % show the "image"
NOW my pixel number just 1 and 0 (binary).
Do you know how to make the pixel number is gray scale. I mean is the gradient pixel number from center to edge is decending? Dear All,
I created the image. My coding as below.
Z = zeros(99); % create square matrix of zeroes
origin = [round((size(Z,2)-1)/2+1) round((size(Z,1)-1)/2+1)]; % "center" of the matrix
radius = round(sqrt(numel(Z)/(2*pi))); % radius for a circle that fills half the area of the matrix
[xx,yy] = meshgrid((1:size(Z,2))-origin(1),(1:size(Z,1))-origin(2)); % create x and y grid
Z(sqrt(xx.^2 + yy.^2) <= radius) = 1; % set points inside the radius equal to one
imshow(Z); % show the "image"
NOW my pixel number just 1 and 0 (binary).
Do you know how to make the pixel number is gray scale. I mean is the gradient pixel number from center to edge is decending? image analysis, image processing, image acquisition, image segmentation, digital image processing MATLAB Answers — New Questions