August 2024 | Application Package Repository Telkom University

Month: August 2024

Microsoft

i am unable to get M365 insider in excel

/ 2024-08-26

i am unable to get M365 insider in excel

i am unable to get M365 insider in excel Read More

Microsoft

mdatp configuration and errors on RHEL 8

/ 2024-08-26

I’ve installed mdatp 101.24062.0001 on a couple of our servers to see how well it works with the applications.

I’ve followed the instructions for installation and it’s registered in the defender portal. So it’s seems to scan and communicate with the portal. As far as that goes, it’s working.

I have been looking at the log files however.

I get this error repeated constantly

[error]: Could not connect to audisp plugin. Trying again.
[1257445][140468005836544][2024-08-26 01:32:14.404491 UTC][error]: {“code”:{“category”:”generic”,”value”:111,”message”:”Connection refused”},”call_stack”:{“frames”:[{“file”:”socket.cpp”,”line”:234}]},”context”:[“Error connecting to server socket”]}
[1257445][140468005836544][2024-08-26 01:32:14.404499 UTC][error]: {“code”:{“category”:”generic”,”value”:107,”message”:”Transport endpoint is not connected”},”call_stack”:{“frames”:[{“file”:”auditd_connector.cpp”,”line”:216}]},”context”:[]}
[1257445][140468005836544][2024-08-26 01:32:14.404506 UTC][warning]: Operation failed, retrying in 10000 ms…

Now, a couple of points here. Looks like it’s trying to connect to audisp daemon. My understanding was that auditd and audisp was deprecated in RHEL 8.

Audit 3.0 replaces audispd with auditd in RHEL 8 – Red Hat Customer Portal

So, why’s it trying to connect to it? Why isn’t it being a bit more vocal about something being not working

Also, the default is to have eBPF enabled on this version of the client. I thought the whole point of that was to bypass the need for contacting the audit daemon.

I also then get a bunch of

[error]: File descriptor is empty, kauth.action: 2097152 request.type: 2

Which, yeah, informative. About as useful as a chocolate fire guard.

Some other questions.

How do you create a policy for the client to act on. For example, how do I define a policy for quarantine. Is it supposed to magically get one from the central defender server? In which case i’m assuming the one defined for our windows hosts will be fairly useless.

Can you create a local one. Looks like you can create various .json files to configure it locally ?

I am using this on a email server to scan incoming and outgoing mail. I’ve set it to realtime protection mode for that. Is that a valid config in that environment?

HiI’ve installed mdatp 101.24062.0001 on a couple of our servers to see how well it works with the applications. I’ve followed the instructions for installation and it’s registered in the defender portal. So it’s seems to scan and communicate with the portal. As far as that goes, it’s working.I have been looking at the log files however. I get this error repeated constantly[error]: Could not connect to audisp plugin. Trying again.
[1257445][140468005836544][2024-08-26 01:32:14.404491 UTC][error]: {“code”:{“category”:”generic”,”value”:111,”message”:”Connection refused”},”call_stack”:{“frames”:[{“file”:”socket.cpp”,”line”:234}]},”context”:[“Error connecting to server socket”]}
[1257445][140468005836544][2024-08-26 01:32:14.404499 UTC][error]: {“code”:{“category”:”generic”,”value”:107,”message”:”Transport endpoint is not connected”},”call_stack”:{“frames”:[{“file”:”auditd_connector.cpp”,”line”:216}]},”context”:[]}
[1257445][140468005836544][2024-08-26 01:32:14.404506 UTC][warning]: Operation failed, retrying in 10000 ms…Now, a couple of points here. Looks like it’s trying to connect to audisp daemon. My understanding was that auditd and audisp was deprecated in RHEL 8. Audit 3.0 replaces audispd with auditd in RHEL 8 – Red Hat Customer PortalSo, why’s it trying to connect to it? Why isn’t it being a bit more vocal about something being not workingAlso, the default is to have eBPF enabled on this version of the client. I thought the whole point of that was to bypass the need for contacting the audit daemon. I also then get a bunch of [error]: File descriptor is empty, kauth.action: 2097152 request.type: 2Which, yeah, informative. About as useful as a chocolate fire guard. Some other questions. How do you create a policy for the client to act on. For example, how do I define a policy for quarantine. Is it supposed to magically get one from the central defender server? In which case i’m assuming the one defined for our windows hosts will be fairly useless. Can you create a local one. Looks like you can create various .json files to configure it locally ? I am using this on a email server to scan incoming and outgoing mail. I’ve set it to realtime protection mode for that. Is that a valid config in that environment? Read More

Microsoft

Excel Formula Error

/ 2024-08-26

Hello, i’ve been struggling with this problem for a week now.

I inserted a formula in a cell, it worked just fine for only a certain condition (the month January), but it didn’t work with other months. And i think there’s nothing wrong with the formula or the resource data, so what’s wrong with my worksheet? Thank you for your help.

it works in januaryerrors with other months

Hello, i’ve been struggling with this problem for a week now.I inserted a formula in a cell, it worked just fine for only a certain condition (the month January), but it didn’t work with other months. And i think there’s nothing wrong with the formula or the resource data, so what’s wrong with my worksheet? Thank you for your help. it works in januaryerrors with other months Read More

Matlab

Extracting Nodes in MATLAB

/ 2024-08-26

I have generated a RVE. After meshing, i want to extract the nodes of the two opposite edges in MATLAB. I have use the code below, but it is giving blank.
clear;
fileID = fopen(‘new.txt’);
formatSpec = ‘%s’;
N = 8;
% reads file data, using the formatSpec N times
% c_h: cell header
c_h = textscan(fileID,formatSpec,N,’delimiter’,’|’);
% Read coordinates for nodes on the two opposite surfaces
% Save them in a cell array whose first and fourth columns are node #
% rest columns are x,y,z coordinates
% c_cord
c_cord = textscan(fileID,’%d %f %f %f %d %f %f %f’);
fclose(fileID);
%%
% Turn cell array which stored coordinates info. for points on left and
% right side of RVE into a sorted matrix
% Initialize matrix
cordMatrix=[];
for i=1:N
c1_cell=c_cord(1,i);
c1_elem=c1_cell{1,1};
cordMatrix(:,i)=c1_elem;
end
% Sort the matrix by the third column-Y coordinates
% sortedMatrixByLy-sorted matrix by left y coordinates
sortedMatrixByLy=sortrows(cordMatrix, 3);
% sortedMatrixByRy-sorted matrix by right y coordinates
sortedMatrixByRy=sortrows(cordMatrix, 3);
%%
% pairwise distance between left and right side sets of points
% # of points on Left side and right side do NOT have to the the same
Left=sortedMatrixByLy(:,1:4);
Right=sortedMatrixByRy(:,5:8);
% Fetch the x,y,z coordinates of left side points
LC=Left(:,2:4);
% Fetch the x,y,z coordinates of right side points
RC=Right(:,2:4);
% Compute all the distances between points on left and right side
% i.e. left has M points, right has N points, size of D matrix is M*N
D = pdist2(LC,RC);
%%
% Find the minimum distance value in each row of D and
% return the corresponding indices
DD=D;
[Sml,ind] = min(DD,[],2);
for j=1:size(DD,1)
[Sml(j),ind(j)] = min(DD(j,:),[],2);
% Replace the value in the same column of ind(j) by a very large number
% eg.999999 in here to avoid duplicat indice (i.e. the same point on one
% side used more than once)
DD(:,ind(j))=999999;
end
% Based on the returned indices find the paired points on left and right
% sides which has minimum distances
% The paired nodes then can be incorporated into FEA package Abaqus input file to
% define Periodic Boundary Conditions by using "Equations" in Abaqus
% pn:parid nodes
pn=[Left(:,1) Right(ind,1)]I have generated a RVE. After meshing, i want to extract the nodes of the two opposite edges in MATLAB. I have use the code below, but it is giving blank.
clear;
fileID = fopen(‘new.txt’);
formatSpec = ‘%s’;
N = 8;
% reads file data, using the formatSpec N times
% c_h: cell header
c_h = textscan(fileID,formatSpec,N,’delimiter’,’|’);
% Read coordinates for nodes on the two opposite surfaces
% Save them in a cell array whose first and fourth columns are node #
% rest columns are x,y,z coordinates
% c_cord
c_cord = textscan(fileID,’%d %f %f %f %d %f %f %f’);
fclose(fileID);
%%
% Turn cell array which stored coordinates info. for points on left and
% right side of RVE into a sorted matrix
% Initialize matrix
cordMatrix=[];
for i=1:N
c1_cell=c_cord(1,i);
c1_elem=c1_cell{1,1};
cordMatrix(:,i)=c1_elem;
end
% Sort the matrix by the third column-Y coordinates
% sortedMatrixByLy-sorted matrix by left y coordinates
sortedMatrixByLy=sortrows(cordMatrix, 3);
% sortedMatrixByRy-sorted matrix by right y coordinates
sortedMatrixByRy=sortrows(cordMatrix, 3);
%%
% pairwise distance between left and right side sets of points
% # of points on Left side and right side do NOT have to the the same
Left=sortedMatrixByLy(:,1:4);
Right=sortedMatrixByRy(:,5:8);
% Fetch the x,y,z coordinates of left side points
LC=Left(:,2:4);
% Fetch the x,y,z coordinates of right side points
RC=Right(:,2:4);
% Compute all the distances between points on left and right side
% i.e. left has M points, right has N points, size of D matrix is M*N
D = pdist2(LC,RC);
%%
% Find the minimum distance value in each row of D and
% return the corresponding indices
DD=D;
[Sml,ind] = min(DD,[],2);
for j=1:size(DD,1)
[Sml(j),ind(j)] = min(DD(j,:),[],2);
% Replace the value in the same column of ind(j) by a very large number
% eg.999999 in here to avoid duplicat indice (i.e. the same point on one
% side used more than once)
DD(:,ind(j))=999999;
end
% Based on the returned indices find the paired points on left and right
% sides which has minimum distances
% The paired nodes then can be incorporated into FEA package Abaqus input file to
% define Periodic Boundary Conditions by using "Equations" in Abaqus
% pn:parid nodes
pn=[Left(:,1) Right(ind,1)] I have generated a RVE. After meshing, i want to extract the nodes of the two opposite edges in MATLAB. I have use the code below, but it is giving blank.
clear;
fileID = fopen(‘new.txt’);
formatSpec = ‘%s’;
N = 8;
% reads file data, using the formatSpec N times
% c_h: cell header
c_h = textscan(fileID,formatSpec,N,’delimiter’,’|’);
% Read coordinates for nodes on the two opposite surfaces
% Save them in a cell array whose first and fourth columns are node #
% rest columns are x,y,z coordinates
% c_cord
c_cord = textscan(fileID,’%d %f %f %f %d %f %f %f’);
fclose(fileID);
%%
% Turn cell array which stored coordinates info. for points on left and
% right side of RVE into a sorted matrix
% Initialize matrix
cordMatrix=[];
for i=1:N
c1_cell=c_cord(1,i);
c1_elem=c1_cell{1,1};
cordMatrix(:,i)=c1_elem;
end
% Sort the matrix by the third column-Y coordinates
% sortedMatrixByLy-sorted matrix by left y coordinates
sortedMatrixByLy=sortrows(cordMatrix, 3);
% sortedMatrixByRy-sorted matrix by right y coordinates
sortedMatrixByRy=sortrows(cordMatrix, 3);
%%
% pairwise distance between left and right side sets of points
% # of points on Left side and right side do NOT have to the the same
Left=sortedMatrixByLy(:,1:4);
Right=sortedMatrixByRy(:,5:8);
% Fetch the x,y,z coordinates of left side points
LC=Left(:,2:4);
% Fetch the x,y,z coordinates of right side points
RC=Right(:,2:4);
% Compute all the distances between points on left and right side
% i.e. left has M points, right has N points, size of D matrix is M*N
D = pdist2(LC,RC);
%%
% Find the minimum distance value in each row of D and
% return the corresponding indices
DD=D;
[Sml,ind] = min(DD,[],2);
for j=1:size(DD,1)
[Sml(j),ind(j)] = min(DD(j,:),[],2);
% Replace the value in the same column of ind(j) by a very large number
% eg.999999 in here to avoid duplicat indice (i.e. the same point on one
% side used more than once)
DD(:,ind(j))=999999;
end
% Based on the returned indices find the paired points on left and right
% sides which has minimum distances
% The paired nodes then can be incorporated into FEA package Abaqus input file to
% define Periodic Boundary Conditions by using "Equations" in Abaqus
% pn:parid nodes
pn=[Left(:,1) Right(ind,1)] nodes, rve MATLAB Answers — New Questions

Matlab

I put a breaker model in my circuit. And i found that it closes when the current is zero and the external signal is 0.

/ 2024-08-26

The circuit is a systhetic circuit usually used for circuit breaker. I add a half sine current on the breaker, and then put a very high voltage Oscillating voltage on it. The half sine current (20kA) meets zero at the 0.01s, and the extern signal for breaker is 0.009s, which means that it will open at the 0.01s. And it actually did. The Oscillating volatge source is added at 0.011s. However, when I reduce the half sine current to about 5kA, something magical happened. The breaker closes again and there is another current that flows through the breaker. And this problem still existed even when I changed the time stamp to put a very high voltage Oscillating voltage to 0.015s as I thought it needed enough time to open the breaker.
I really want to know why this happens and how to solve the problem that the breaker doesn’t opens as i think.
Here is the current that flows through breaker.

Here is my breaker configurations.The circuit is a systhetic circuit usually used for circuit breaker. I add a half sine current on the breaker, and then put a very high voltage Oscillating voltage on it. The half sine current (20kA) meets zero at the 0.01s, and the extern signal for breaker is 0.009s, which means that it will open at the 0.01s. And it actually did. The Oscillating volatge source is added at 0.011s. However, when I reduce the half sine current to about 5kA, something magical happened. The breaker closes again and there is another current that flows through the breaker. And this problem still existed even when I changed the time stamp to put a very high voltage Oscillating voltage to 0.015s as I thought it needed enough time to open the breaker.
I really want to know why this happens and how to solve the problem that the breaker doesn’t opens as i think.
Here is the current that flows through breaker.

Here is my breaker configurations. The circuit is a systhetic circuit usually used for circuit breaker. I add a half sine current on the breaker, and then put a very high voltage Oscillating voltage on it. The half sine current (20kA) meets zero at the 0.01s, and the extern signal for breaker is 0.009s, which means that it will open at the 0.01s. And it actually did. The Oscillating volatge source is added at 0.011s. However, when I reduce the half sine current to about 5kA, something magical happened. The breaker closes again and there is another current that flows through the breaker. And this problem still existed even when I changed the time stamp to put a very high voltage Oscillating voltage to 0.015s as I thought it needed enough time to open the breaker.
I really want to know why this happens and how to solve the problem that the breaker doesn’t opens as i think.
Here is the current that flows through breaker.

Here is my breaker configurations. breaker MATLAB Answers — New Questions

Microsoft

could able to create clone test case to the test suite but it isn’ display in the related test suite

/ 2024-08-26

could able to create clone test case to the test suite but it isn’t display in the related test suite.

could able to create clone test case to the test suite but it isn’t display in the related test suite. Read More

Matlab

How to get shapley value for Neural Network trained on matlab? it keeps error…

/ 2024-08-26

Hi there,
I wanted to get shapley value of my pre-trained ANN.
it is regression model.
it’s input’s shape is 7*5120 double
and output is 1*5120 double.

I’m confused with idea of shapley.. sorryHi there,
I wanted to get shapley value of my pre-trained ANN.
it is regression model.
it’s input’s shape is 7*5120 double
and output is 1*5120 double.

I’m confused with idea of shapley.. sorry Hi there,
I wanted to get shapley value of my pre-trained ANN.
it is regression model.
it’s input’s shape is 7*5120 double
and output is 1*5120 double.

I’m confused with idea of shapley.. sorry shapley value, neural network MATLAB Answers — New Questions

Matlab

How to normalise segregated surface emg signals into the same number of data points?

/ 2024-08-26

Hi everyone,
I have a cell array containing multiple gait cycles of an SEMG signal. Each cycle represents the push phase and recovery phase of a wheelchair. I want to get the average of the SEMG signal of all the cycles however, each cycle contains a different amount of data points. How do I normalise the cycles to contain a certain amount of data points without disrupting the signals? I also have a cell array containg the times of propulsion.

If anyone could point me in the right direction that would be great!

Thanks,Hi everyone,
I have a cell array containing multiple gait cycles of an SEMG signal. Each cycle represents the push phase and recovery phase of a wheelchair. I want to get the average of the SEMG signal of all the cycles however, each cycle contains a different amount of data points. How do I normalise the cycles to contain a certain amount of data points without disrupting the signals? I also have a cell array containg the times of propulsion.

If anyone could point me in the right direction that would be great!

Thanks, Hi everyone,
I have a cell array containing multiple gait cycles of an SEMG signal. Each cycle represents the push phase and recovery phase of a wheelchair. I want to get the average of the SEMG signal of all the cycles however, each cycle contains a different amount of data points. How do I normalise the cycles to contain a certain amount of data points without disrupting the signals? I also have a cell array containg the times of propulsion.

If anyone could point me in the right direction that would be great!

Thanks, signal processing, semg MATLAB Answers — New Questions

Microsoft

Team Meeting Recording using shared mailbox/calendar – recordings saved in that account

/ 2024-08-26

All of our shared mailboxes don’t have O365 licence because they a shared mailboxes, linked to existing users accounts that do have an O365 licence.

But recently we’ve had few of our users complain they can’t access their recorded meetings since the meeting was created in a shared mailbox/calendar and seems the videos are saved on that account now.

I have read that according to Microsoft’s roadmap, since June, Team recordings will be saved to the meeting organizer’s OneDrive for Business instead of to the OneDrive for Business folder of the person who initiated the recording.

Therefore now requires IT to add an F3 or E3 licence to the shared mailbox so Onedrive can be enabled, log into a computer with that shared mailbox account, get the videos to transfer to user’s onedrive or sharepoint, then remove the O365 licence.

Has anyone else had this issue with people creating their Team meetings on shared mailbox calendars?

I think the solutions is to advise all staff not to make any more bookings in Shared mailboxes as we don’t be adding O365 licences to them for this reason.

All of our shared mailboxes don’t have O365 licence because they a shared mailboxes, linked to existing users accounts that do have an O365 licence.But recently we’ve had few of our users complain they can’t access their recorded meetings since the meeting was created in a shared mailbox/calendar and seems the videos are saved on that account now. I have read that according to Microsoft’s roadmap, since June, Team recordings will be saved to the meeting organizer’s OneDrive for Business instead of to the OneDrive for Business folder of the person who initiated the recording. Therefore now requires IT to add an F3 or E3 licence to the shared mailbox so Onedrive can be enabled, log into a computer with that shared mailbox account, get the videos to transfer to user’s onedrive or sharepoint, then remove the O365 licence.Has anyone else had this issue with people creating their Team meetings on shared mailbox calendars?I think the solutions is to advise all staff not to make any more bookings in Shared mailboxes as we don’t be adding O365 licences to them for this reason. Read More

Microsoft

How to disable SAS token on consumption/Premium plan hosted function apps

/ 2024-08-26

As we are aware, Azure Files currently does not support identity-based connections. This means that even if we can use identity-based host connections to replace the AzureWebjobsStorage, which uses a SAS token, we still cannot remove the file share connection strings (WEBSITE_CONTENTAZUREFILECONNECTIONSTRING) that also rely on a SAS token. Therefore, we are unable to disable the SAS token in the storage account.

For now, when creating function apps in the consumption/EP plan, we have the option to create an app without Azure File. In this scenario, we can bypass the SAS token requirement for Azure Files and solely utilize managed identity to access the storage account.

To run your app without relying on Azure file share, you need to fulfill the following requirements:

1. Deploy your package to a remote Azure Blob storage container.
2. Set the URL that grants access to the package as the WEBSITE_RUN_FROM_PACKAGE app setting.
This approach allows you to store your app content in Blob storage, which does support managed identities, instead of Azure Files.

Now let’s see how to proceed replace file share and SAS token conncetion in consumption/EP function app.

1. To create a function app without a file share, you can uncheck the “Add an Azure Files connection” option under the “Storage” panel when creating the function app through the Azure Portal.

2. After the creation, navigate to the function app and enable the System Assigned identity.

3. Go to the Storage account and navigate to IAM. Assign the Storage Blob Data contributor role to the function app.

4. Create a new blob container to store your function app’s zip package and copy the URL of the file.

5. Now, return to the function app and proceed with replacing the SAS token. Navigate to Environment variables and modify the AzureWebjobsStorage to AzureWebJobsStorage__accountname, setting its value to the storage account name. Then, set the app to run from the URL by adding the app setting WEBSITE_RUN_FROM_PACKAGE and setting its value to the file URL copied in the previous step.

6. Please note that when specifying a URL for the app to read, you must manually sync triggers after publishing an updated package. You can sync triggers using one of the following methods:

Restart your function app in the Azure portal.
Send an HTTP POST request to https://{functionappname}.azurewebsites.net/admin/host/synctriggers?code=<API_KEY> using the master key.
Send an HTTP POST request to https://management.azure.com/subscriptions/<SUBSCRIPTION_ID>/resourceGroups/<RESOURCE_GROUP_NAME>/providers/Microsoft.Web/sites/<FUNCTION_APP_NAME>/syncfunctiontriggers?api-version=2016-08-01. Replace the placeholders with your subscription ID, resource group name, and the name of your function app. This request requires an access token in the Authorization request header.

Microsoft Tech Community – Latest Blogs –Read More

Matlab

Plotting random number in a line

/ 2024-08-26

Hi Matlab Team,

I have X = rand(1,100), and I want to plot X such that points be in X axis. At the moment, when I use plot(X, ‘*’), we have index 1 to 100 on x-axis and X is in the vertical axis. This is not, what I want !!!

ThanksHi Matlab Team,

Thanks Hi Matlab Team,

Thanks plot, random number MATLAB Answers — New Questions

Matlab

the question is on linear programming problems

/ 2024-08-26

A farm manufacturers three products P1, P2 and P3 using two machines M1 and M2. The product yield a contribution of sh.3 sh.2 and sh.4 respectively. Machine M1 and M2 have 2000 and 2500 machine hours respectively. There is an agreement with trading association to manufacture at least 100 units of P1, 200 units of P2 and 50 units of P3 but not more than 150 units of P1. The table below shows the processing time in hours for each machine on each product.
products
machines P1 P2 P3
M1 4 3 5
M2 2 2 4

required:
i. The production plan that maximizes contributionA farm manufacturers three products P1, P2 and P3 using two machines M1 and M2. The product yield a contribution of sh.3 sh.2 and sh.4 respectively. Machine M1 and M2 have 2000 and 2500 machine hours respectively. There is an agreement with trading association to manufacture at least 100 units of P1, 200 units of P2 and 50 units of P3 but not more than 150 units of P1. The table below shows the processing time in hours for each machine on each product.
products
machines P1 P2 P3
M1 4 3 5
M2 2 2 4

required:
i. The production plan that maximizes contribution A farm manufacturers three products P1, P2 and P3 using two machines M1 and M2. The product yield a contribution of sh.3 sh.2 and sh.4 respectively. Machine M1 and M2 have 2000 and 2500 machine hours respectively. There is an agreement with trading association to manufacture at least 100 units of P1, 200 units of P2 and 50 units of P3 but not more than 150 units of P1. The table below shows the processing time in hours for each machine on each product.
products
machines P1 P2 P3
M1 4 3 5
M2 2 2 4

required:
i. The production plan that maximizes contribution #operarions research MATLAB Answers — New Questions

Microsoft

How to use conditional formatting to highlight cells with time between 8:30am-17:30pm

/ 2024-08-26

Hello!

Each week I need to format a call logs report where column A is the date + time of the call.

I have been trying to figure out the conditional formatting formula to highlight rows between 8:30am – 17:30pm in red, but I can only seem to make it work for whole hours (8am-5pm)

I am currently using the following formula:

=OR(HOUR(A1)=8, HOUR(A1)=9, HOUR(A1)=10, HOUR(A1)=11, HOUR(A1)=12, HOUR(A1)=13, HOUR(A1)=14, HOUR(A1)=15, HOUR(A1)=16, HOUR(A1)=17)

Is there a way to get this to work for 8:30-17:30? I have tried making it HOUR(A1)=8,3,0 with no luck.

Thank you!

Hello!Each week I need to format a call logs report where column A is the date + time of the call.I have been trying to figure out the conditional formatting formula to highlight rows between 8:30am – 17:30pm in red, but I can only seem to make it work for whole hours (8am-5pm) I am currently using the following formula:=OR(HOUR(A1)=8, HOUR(A1)=9, HOUR(A1)=10, HOUR(A1)=11, HOUR(A1)=12, HOUR(A1)=13, HOUR(A1)=14, HOUR(A1)=15, HOUR(A1)=16, HOUR(A1)=17) Is there a way to get this to work for 8:30-17:30? I have tried making it HOUR(A1)=8,3,0 with no luck. Thank you! Read More

Matlab

Measuring average intensity of pixels for multiple images.

/ 2024-08-26

I am trying to read multiple similar images located in a folder and find the average intensity of pixels of the images. Following is the code I wrote initially which works fine:
Location = ‘D:\dummy location’;

B = dir(fullfile(sprintf(Location),sprintf(‘BLACK’), ‘*.tif’));
B_0 = numel(B);
for k = 1:B_0
F = fullfile(sprintf(Location),sprintf(‘BLACK’),B(k).name);
I{k} = imread(F);
end
B1 = cat(3,I{:});
black = mean(B1,3);
However, upon getting suggested to use vectorization to make the process faster, I wrote the following code:
Location = ‘D:\dummy location’;

B = dir(fullfile(sprintf(Location),sprintf(‘BLACK’), ‘*.tif’));
B_0 = numel(B);
k = 1:B_0;
F = fullfile(sprintf(Location),sprintf(‘BLACK’),B(k).name);
I{k} = imread(F);

B1 = cat(3,I{:});
black = mean(B1,3);
I am getting the following error:
Error using dir
Pathname ‘D:dummy locationBLACK1.tif10.tif100.tif101.tif102.tif103.tif104.tif105.tif106.tif107.tif108.tif109.tif11.tif110.tif111.tif112.tif113.tif114.tif115.tif116.tif117.tif118.tif119.tif12.tif120.tif121.tif122.tif123.tif124.tif125.tif126.tif127.tif128.tif129.tif13.tif130.tif131.tif132.tif133.tif134.tif135.tif136.tif137.tif138.tif139.tif14.tif140.tif141.tif142.tif143.tif144.tif145.tif146.tif147.tif148.tif149.tif15.tif150.tif151.tif152.tif153.tif154.tif155.tif156.tif157.tif158.tif159.tif16.tif160.tif161.tif162.tif163.tif164.tif165.tif166.tif167.tif168.tif169.tif17.tif170.tif171.tif172.tif173.tif174.tif175.tif176.tif177.tif178.tif179.tif18.tif180.tif181.tif182.tif183.tif184.tif185.tif186.tif187.tif188.tif189.tif19.tif190.tif191.tif192.tif193.tif194.tif195.tif196.tif197.tif198.tif199.tif2.tif20.tif200.tif201.tif202.tif203.tif204.tif205.tif206.tif207.tif208.tif209.tif21.tif210.tif211.tif212.tif213.tif214.tif215.tif216.tif217.tif218.tif219.tif22.tif220.tif221.tif222.tif223.tif224.tif225.tif226.tif227.tif228.tif229.tif23.tif230.tif231.tif232.tif233.tif234.tif235.tif236.tif237.tif238.tif239.tif24.tif240.tif241.tif242.tif243.tif244.tif245.tif246.tif247.tif248.tif249.tif25.tif250.tif251.tif252.tif253.tif254.tif255.tif256.tif257.tif258.tif259.tif26.tif260.tif261.tif262.tif263.tif264.tif265.tif266.tif267.tif268.tif269.tif27.tif270.tif271.tif272.tif273.tif274.tif275.tif276.tif277.tif278.tif279.tif28.tif280.tif281.tif282.tif283.tif284.tif285.tif286.tif287.tif288.tif289.tif29.tif290.tif291.tif292.tif293.tif294.tif295.tif296.tif297.tif298.tif299.tif3.tif30.tif300.tif301.tif302.tif303.tif304.tif305.tif306.tif307.tif308.tif309.tif31.tif310.tif311.tif312.tif313.tif314.tif315.tif316.tif317.tif318.tif319.tif32.tif320.tif321.tif322.tif323.tif324.tif325.tif326.tif327.tif328.tif329.tif33.tif330.tif331.tif332.tif333.tif334.tif335.tif336.tif337.tif338.tif339.tif34.tif340.tif341.tif342.tif343.tif344.tif345.tif346.tif347.tif348.tif349.tif35.tif350.tif351.tif352.tif353.tif354.tif355.tif356.tif357.tif358.tif359.tif36.tif360.tif361.tif362.tif363.tif364.tif365.tif366.tif367.tif368.tif369.tif37.tif370.tif371.tif372.tif373.tif374.tif375.tif376.tif377.tif378.tif379.tif38.tif380.tif381.tif382.tif383.tif384.tif385.tif386.tif387.tif388.tif389.tif39.tif390.tif391.tif392.tif393.tif394.tif395.tif396.tif397.tif398.tif399.tif4.tif40.tif400.tif401.tif402.tif403.tif404.tif405.tif406.tif407.tif408.tif409.tif41.tif410.tif411.tif412.tif413.tif414.tif415.tif416.tif417.tif418.tif419.tif42.tif420.tif421.tif422.tif423.tif424.tif425.tif426.tif427.tif428.tif429.tif43.tif430.tif431.tif432.tif433.tif434.tif435.tif436.tif437.tif438.tif439.tif44.tif440.tif441.tif442.tif443.tif444.tif445.tif446.tif447.tif448.tif449.tif45.tif450.tif451.tif452.tif453.tif454.tif455.tif456.tif457.tif458.tif459.tif46.tif460.tif461.tif462.tif463.tif464.tif465.tif466.tif467.tif468.tif469.tif47.tif470.tif471.tif472.tif473.tif474.tif475.tif476.tif477.tif478.tif479.tif48.tif480.tif481.tif482.tif483.tif484.tif485.tif486.tif487.tif488.tif489.tif49.tif490.tif491.tif492.tif493.tif494.tif495.tif496.tif497.tif498.tif499.tif5.tif50.tif500.tif51.tif52.tif53.tif54.tif55.tif56.tif57.tif58.tif59.tif6.tif60.tif61.tif62.tif63.tif64.tif65.tif66.tif67.tif68.tif69.tif7.tif70.tif71.tif72.tif73.tif74.tif75.tif76.tif77.tif78.tif79.tif8.tif80.tif81.tif82.tif83.tif84.tif85.tif86.tif87.tif88.tif89.tif9.tif90.tif91.tif92.tif93.tif94.tif95.tif96.tif97.tif98.tif99.tif’
is too long.

Error in imread>get_full_filename (line 560)
if ~isempty(dir(filename))

Error in imread (line 371)
fullname = get_full_filename(filename);

Error in avg_new (line 12)
I{k} = imread(F);
Can anyone please help me correcting this error to get the same result as my first code?I am trying to read multiple similar images located in a folder and find the average intensity of pixels of the images. Following is the code I wrote initially which works fine:
Location = ‘D:\dummy location’;

B = dir(fullfile(sprintf(Location),sprintf(‘BLACK’), ‘*.tif’));
B_0 = numel(B);
k = 1:B_0;
F = fullfile(sprintf(Location),sprintf(‘BLACK’),B(k).name);
I{k} = imread(F);

Error in imread>get_full_filename (line 560)
if ~isempty(dir(filename))

Error in imread (line 371)
fullname = get_full_filename(filename);

Error in avg_new (line 12)
I{k} = imread(F);
Can anyone please help me correcting this error to get the same result as my first code? I am trying to read multiple similar images located in a folder and find the average intensity of pixels of the images. Following is the code I wrote initially which works fine:
Location = ‘D:\dummy location’;

B = dir(fullfile(sprintf(Location),sprintf(‘BLACK’), ‘*.tif’));
B_0 = numel(B);
k = 1:B_0;
F = fullfile(sprintf(Location),sprintf(‘BLACK’),B(k).name);
I{k} = imread(F);

Error in imread>get_full_filename (line 560)
if ~isempty(dir(filename))

Error in imread (line 371)
fullname = get_full_filename(filename);

Error in avg_new (line 12)
I{k} = imread(F);
Can anyone please help me correcting this error to get the same result as my first code? vectorization, image analysis, image processing MATLAB Answers — New Questions

Matlab

How to interpret Anomaly Scores for One Class Support Vector Machines

/ 2024-08-26

I am using One Class Support Vector Machines for anomaly detection. Here is the anomaly scores histogram (attached) for the model trained with 274 samples and tested with 31 samples. How do I determine the true/false prediction rates from the anomaly scores histogram.
Thank YouI am using One Class Support Vector Machines for anomaly detection. Here is the anomaly scores histogram (attached) for the model trained with 274 samples and tested with 31 samples. How do I determine the true/false prediction rates from the anomaly scores histogram.
Thank You I am using One Class Support Vector Machines for anomaly detection. Here is the anomaly scores histogram (attached) for the model trained with 274 samples and tested with 31 samples. How do I determine the true/false prediction rates from the anomaly scores histogram.
Thank You anomaly, one class svm, scores MATLAB Answers — New Questions

Microsoft

Adding a Calcualted column to a site content type for a custom list which contain 1,200,000 items

/ 2024-08-26

[DueDate] + 750/(24*60)

But when i submitted the calculated column info >> i got this page for more than 4 hours now:-

and the column did not get added to the site content type… so is this just a time matter? or i will never be able to add calculated column to a large list?

I have a custom list which contain around 1,200,000 items. and this custom list is linked to a site content type. now inside the site content type i tried to add a calculated column of type Date/Time , where i define the formula which is :-[DueDate] + 750/(24*60)But when i submitted the calculated column info >> i got this page for more than 4 hours now:- and the column did not get added to the site content type… so is this just a time matter? or i will never be able to add calculated column to a large list? Read More

Matlab

How do I fix this error?

/ 2024-08-26

deltat=0.1;
nsamples=2^10;
fs=1/deltat;
time=[0 : deltat : deltat*(nsamples-1)];
psdtot(1:nsamples/2+1) = zeros(1,nsamples/2+1);
nblock = 10;
for k=1:nblock
for i=1: nsamples
ydata(i,:) =5+10*cos(2*pi*time+pi/6)+15* randn(1);
end
[pxx,f] = periodogram(ydata,rectwin(nsamples),nsamples,fs);
size(psdtot)
size(pxx)
psdtot = psdtot + pxx/nblock;

end

figure(1);
plot(time,ydata);
I’m trying to generate Gaussian noise from x(t)=5+10*cos(2*pi*t+pi/6)+G(sigma,t)
G(sigma,t) is Gaussian noise with a standard deviation of 15 (sigma G=15), detat=0.1(s), and nsample=2^10.
It is the start of calculating Power Spectral Density with FFT.
The overall variance of the signal is (sigma g)^2+(A)^2/2 as expected.
The generated random signal should be sinusoidal because X(t) has the cosine factor.deltat=0.1;
nsamples=2^10;
fs=1/deltat;
time=[0 : deltat : deltat*(nsamples-1)];
psdtot(1:nsamples/2+1) = zeros(1,nsamples/2+1);
nblock = 10;
for k=1:nblock
for i=1: nsamples
ydata(i,:) =5+10*cos(2*pi*time+pi/6)+15* randn(1);
end
[pxx,f] = periodogram(ydata,rectwin(nsamples),nsamples,fs);
size(psdtot)
size(pxx)
psdtot = psdtot + pxx/nblock;

end

figure(1);
plot(time,ydata);
I’m trying to generate Gaussian noise from x(t)=5+10*cos(2*pi*t+pi/6)+G(sigma,t)
G(sigma,t) is Gaussian noise with a standard deviation of 15 (sigma G=15), detat=0.1(s), and nsample=2^10.
It is the start of calculating Power Spectral Density with FFT.
The overall variance of the signal is (sigma g)^2+(A)^2/2 as expected.
The generated random signal should be sinusoidal because X(t) has the cosine factor. deltat=0.1;
nsamples=2^10;
fs=1/deltat;
time=[0 : deltat : deltat*(nsamples-1)];
psdtot(1:nsamples/2+1) = zeros(1,nsamples/2+1);
nblock = 10;
for k=1:nblock
for i=1: nsamples
ydata(i,:) =5+10*cos(2*pi*time+pi/6)+15* randn(1);
end
[pxx,f] = periodogram(ydata,rectwin(nsamples),nsamples,fs);
size(psdtot)
size(pxx)
psdtot = psdtot + pxx/nblock;

end

Microsoft

Remove Auto Login to MS Sites

/ 2024-08-26

Hi,

Every time I open my webbrowser to come to this site the system tries to auto log me in using another persons credentials. A client used my pc, once, to log into their portal so we could fix something.

The browser (firefox) doesnt store that password. It isnt in a list of Ms credentials accessible via Control Panel .

I removed the folder under C:Users%username%AppDataLocalPackagesMicrosoft.AAD.BrokerPlugin_* “

It is still starting auto login. It flashes up the choose account page, then immediately moves to password page. There is no way to go back to add another credential. There is no way to remove this security flaw.

How do you remove this stuff? This PC only has a local account.

Hi, Every time I open my webbrowser to come to this site the system tries to auto log me in using another persons credentials. A client used my pc, once, to log into their portal so we could fix something. The browser (firefox) doesnt store that password. It isnt in a list of Ms credentials accessible via Control Panel . I removed the folder under C:Users%username%AppDataLocalPackagesMicrosoft.AAD.BrokerPlugin_* ” It is still starting auto login. It flashes up the choose account page, then immediately moves to password page. There is no way to go back to add another credential. There is no way to remove this security flaw. How do you remove this stuff? This PC only has a local account. Read More

Microsoft

Automatic Regeneration of Connection ACL keys in VS Code Extension

/ 2024-08-26

Starting with version 4.57.6, the Azure Logic Apps (Standard) extension for Visual Studio Code will automatically regenerate the keys required to allow the extension to access Azure Managed Connections. This will allow the same Azure Managed Connection to be used for projects for longer than 7 days without any user intervention.

Notice that this will not renew the key, for security purposes, but generate a new key and update the configuration to use the newly generated key instead.

The ACL connection keys will be evaluated at two points in time to make sure the Azure Managed Connection ACL connection keys are not expired:

When the project is opened in VS Code – guaranteeing that if the ACL connection key is required during design time, to access dynamically generated values, for example, the key is valid.
When a project is executed – before the Logic Apps Standard host starts, – guaranteeing that the connection can be used during runtime.

What are those ACL connection keys anyway?

When a logic app need to use Azure Managed Connections, that logic app requires authorization to access the connection, since each Azure Managed Connection is a discreet resource in Azure. That was always the case – both on Logic Apps Consumption and Logic Apps Standard. In the Consumption sku, all of this is managed by the engine behind the scenes. For Logic Apps Standard, on the other hand, each application must have its own authorization, guaranteeing that only authorized applications have access to those connections.

This ACL can be authorized using two methods:

Managed identity authorization – this is the default method when you associate an action to a connection in a workflow using the portal designer, or when you deploy the logic app to the portal via VS Code.
Raw authorization using connection keys – this is the only supported method of authorization when you associate an action to a connection in a workflow using the designer in VS Code. Those keys are valid for 7 days.

Microsoft Tech Community – Latest Blogs –Read More

Matlab

Thermal Image analysis on legs

/ 2024-08-26

I am trying to edit the below code so that it gives me an image of the area selected that is above the average temperature of the lower limb.
I would be grateful for any tips
clc;
close all;
clear;
workspace;
format long g;
format compact;

% Read the thermal image
thermalImage = imread(‘thermal_image_side_leg_2 .jpeg’); % Replace ‘thermal_image.jpg’ with the filename of your thermal image

% Display the thermal image
figure;
imshow(thermalImage);
title(‘Original Thermal Image’);

% Convert the thermal image to grayscale
thermalImageGray = rgb2gray(thermalImage);

% Display the grayscale thermal image
figure;
imshow(thermalImageGray);
title(‘Grayscale Thermal Image’);

% Select the area of interest using the imfreehand function
figure;
imshow(thermalImageGray);
title(‘Select Area of Interest’);
roi = imfreehand; % This allows you to draw a freehand region of interest (ROI) on the grayscale thermal image
binaryMask = createMask(roi);

% Apply the binary mask to the grayscale image
maskedGrayImage = thermalImageGray .* uint8(binaryMask);

% Display the masked grayscale image
figure;
imshow(maskedGrayImage);
title(‘Masked Grayscale Image’);

% Define the temperature scale using the color bar
colorBarImage = imread(‘Color_bar_side_leg_2.png’); % Replace ‘colorbar_image.jpg’ with the filename of your color bar image
temperatureRange = [26, 38]; % Replace with the temperature range provided by the color bar

% Calibrate the masked grayscale image using the temperature range
calibratedImage = (double(maskedGrayImage) – double(min(thermalImageGray(:)))) * (temperatureRange(2) – temperatureRange(1)) / (double(max(thermalImageGray(:))) – double(min(thermalImageGray(:)))) + temperatureRange(1);

% Display the calibrated image
figure;
imshow(calibratedImage);
title(‘Calibrated Image’);

% Calculate the average temperature of the ROI
averageTemperature = mean(calibratedImage(binaryMask));

% Display the average temperature
disp([‘The average temperature of the selected area is: ‘, num2str(averageTemperature), ‘ °C’]);

% Calculate the average temperature of the ROI
averageTemperature = mean(calibratedImage(binaryMask));

% Display the average temperature
disp([‘The average temperature of the selected area is: ‘, num2str(averageTemperature), ‘ °C’]);

% Threshold the calibrated image to create a binary mask for temperatures above the average
binaryAboveAverage = calibratedImage > averageTemperature;

% Display the binary mask
figure;
imshow(binaryAboveAverage);
title(‘Areas above Average Temperature’);

% Apply the binary mask to the original image
thresholdedImage = thermalImage;
thresholdedImage(repmat(~binaryAboveAverage, [1, 1, 3])) = 0;

% Display the thresholded image
figure;
imshow(thresholdedImage);
title(‘Thresholded Image’);I am trying to edit the below code so that it gives me an image of the area selected that is above the average temperature of the lower limb.
I would be grateful for any tips
clc;
close all;
clear;
workspace;
format long g;
format compact;