Hello!
I’ve run into a tricky situation when trying to work with a .NET library inside MATLAB. Normally, it appears that when a .NET method has a parameter with the out keyword, MATLAB makes it a parameter that is returned instead.
However, I have run into an unusual scenario where a function requires me to input a value for a parameter with the out keyword. I cannot find a public repository for the library in question; However, I’ve included below an example of how the .NET function in question, ZernikeLSF, is called in a C# script:

After going through the MATLAB documentation on its .NET integration, I have been unable to find a way to input a value for this parameter, zernike_order — I can only seem to have it be returned. Is there a method of inputting a value here with MATLAB? If not, are there any good workarounds?Hello!
I’ve run into a tricky situation when trying to work with a .NET library inside MATLAB. Normally, it appears that when a .NET method has a parameter with the out keyword, MATLAB makes it a parameter that is returned instead.
However, I have run into an unusual scenario where a function requires me to input a value for a parameter with the out keyword. I cannot find a public repository for the library in question; However, I’ve included below an example of how the .NET function in question, ZernikeLSF, is called in a C# script:

After going through the MATLAB documentation on its .NET integration, I have been unable to find a way to input a value for this parameter, zernike_order — I can only seem to have it be returned. Is there a method of inputting a value here with MATLAB? If not, are there any good workarounds? Hello!
I’ve run into a tricky situation when trying to work with a .NET library inside MATLAB. Normally, it appears that when a .NET method has a parameter with the out keyword, MATLAB makes it a parameter that is returned instead.
However, I have run into an unusual scenario where a function requires me to input a value for a parameter with the out keyword. I cannot find a public repository for the library in question; However, I’ve included below an example of how the .NET function in question, ZernikeLSF, is called in a C# script:

After going through the MATLAB documentation on its .NET integration, I have been unable to find a way to input a value for this parameter, zernike_order — I can only seem to have it be returned. Is there a method of inputting a value here with MATLAB? If not, are there any good workarounds? .net, handles MATLAB Answers — New Questions

​

I have an area bounded by a data set in the (-) plane as shown below. Is it mathematically possible to represent this area (blue color) in (-) plane?
clear; clc;

data = [1.0000 0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000 0 -0.1000 -0.2000 -0.3000 -0.4000 -0.5000 -0.6000 -0.6000 -0.6000 -0.6000 -0.6000 -0.5000 -0.4000 -0.3000 -0.2000 -0.1000 0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000
-2.1351 -2.1892 -2.2432 -2.2973 -2.3243 -2.3243 -2.3243 -2.3514 -2.2703 -2.2432 -2.2432 -2.2432 -2.2703 -2.2973 -2.2162 -2.1081 -2.0000 -1.0541 0.0270 1.1081 1.3243 2.6486 4.0270 5.2703 6.5676 7.5405 8.2973 9.1081 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000];

x = data(1, :);
y = data(2, :);

figure
fill(x, y, ‘b’,’FaceAlpha’,0.5)
xlabel(‘Q_2/Q_4+1’)
ylabel(‘Q/Q_4+5’)
set(gca,’FontName’,’times’,’fontsize’,14)I have an area bounded by a data set in the (-) plane as shown below. Is it mathematically possible to represent this area (blue color) in (-) plane?
clear; clc;

data = [1.0000 0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000 0 -0.1000 -0.2000 -0.3000 -0.4000 -0.5000 -0.6000 -0.6000 -0.6000 -0.6000 -0.6000 -0.5000 -0.4000 -0.3000 -0.2000 -0.1000 0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000
-2.1351 -2.1892 -2.2432 -2.2973 -2.3243 -2.3243 -2.3243 -2.3514 -2.2703 -2.2432 -2.2432 -2.2432 -2.2703 -2.2973 -2.2162 -2.1081 -2.0000 -1.0541 0.0270 1.1081 1.3243 2.6486 4.0270 5.2703 6.5676 7.5405 8.2973 9.1081 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000];

x = data(1, :);
y = data(2, :);

figure
fill(x, y, ‘b’,’FaceAlpha’,0.5)
xlabel(‘Q_2/Q_4+1’)
ylabel(‘Q/Q_4+5’)
set(gca,’FontName’,’times’,’fontsize’,14) I have an area bounded by a data set in the (-) plane as shown below. Is it mathematically possible to represent this area (blue color) in (-) plane?
clear; clc;

data = [1.0000 0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000 0 -0.1000 -0.2000 -0.3000 -0.4000 -0.5000 -0.6000 -0.6000 -0.6000 -0.6000 -0.6000 -0.5000 -0.4000 -0.3000 -0.2000 -0.1000 0 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000
-2.1351 -2.1892 -2.2432 -2.2973 -2.3243 -2.3243 -2.3243 -2.3514 -2.2703 -2.2432 -2.2432 -2.2432 -2.2703 -2.2973 -2.2162 -2.1081 -2.0000 -1.0541 0.0270 1.1081 1.3243 2.6486 4.0270 5.2703 6.5676 7.5405 8.2973 9.1081 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000 10.0000];

x = data(1, :);
y = data(2, :);

figure
fill(x, y, ‘b’,’FaceAlpha’,0.5)
xlabel(‘Q_2/Q_4+1’)
ylabel(‘Q/Q_4+5’)
set(gca,’FontName’,’times’,’fontsize’,14) logic, math, mathematics MATLAB Answers — New Questions

​

Dear Sir
please let me have a help

this is a simple set of statements that:
-define figure 1
-clear the figure
-define a matrix 2 x 82 ,where each column represent the coordinate of a point on a plane
these set of points represent a circle and a cross , centered inside

-then do a loop that draw each point at a time, as red dot

the "hold on" is needed because at each loop i wish to maintain the points already drawed

the purpose of this code is to visualize this figure first undeformed, and after, with some deformation gradient F applied to the set of points, (and) with another (more external) loop , to visualize the advance of the deformation making the gradient F varying
(F not present in the code below)
—————————————-
clear

figure(1),clf

p=[[cos(0:.1:1.9*pi) (-1:.2:1) 0*(-1:.2:1) ]’ [sin(0:.1:1.9*pi) 0*(-1:.2:1) (-1:.2:1) ]’]’

for j=1:max(size(p)) % visualize
figure(1),plot(p(1,j),p(2,j),’r.’),grid on, axis([-2 2 -2 2]),axis(‘square’)
hold on
end
—————————————-

now , to draw this simple figure it take roughly 1 second , so i ask were i’m wrong , and how can I speed up the execution of this code

the specification of the pc is as follow

Device name s.
Processor Intel(R) Pentium(R) CPU G860 @ 3.00GHz 3.00 GHz
Installed RAM 4.00 GB
Device ID ….8C39
Product ID …9
System type 64-bit operating system, x64-based processor
Pen and touch No pen or touch input is available for this display

Edition Windows 10 Home
Version 22H2
Installed on ‎11/‎7/‎2020
OS build 19045.4355
Experience Windows Feature Experience Pack 1000.19056.1000.0

Matlab :

ver
—————————————————————————————————–
MATLAB Version: 24.1.0.2689473 (R2024a) Update 6
MATLAB License Number: STUDENT
Operating System: Microsoft Windows 10 Home Version 10.0 (Build 19045)
Java Version: Java 1.8.0_202-b08 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
—————————————————————————————————–

MATLAB Version 24.1 (R2024a)
Symbolic Math Toolbox Version 24.1 (R2024a)
>>

Thankyou very much

Kind Regards

manu1965Dear Sir
please let me have a help

this is a simple set of statements that:
-define figure 1
-clear the figure
-define a matrix 2 x 82 ,where each column represent the coordinate of a point on a plane
these set of points represent a circle and a cross , centered inside

-then do a loop that draw each point at a time, as red dot

the "hold on" is needed because at each loop i wish to maintain the points already drawed

the purpose of this code is to visualize this figure first undeformed, and after, with some deformation gradient F applied to the set of points, (and) with another (more external) loop , to visualize the advance of the deformation making the gradient F varying
(F not present in the code below)
—————————————-
clear

figure(1),clf

p=[[cos(0:.1:1.9*pi) (-1:.2:1) 0*(-1:.2:1) ]’ [sin(0:.1:1.9*pi) 0*(-1:.2:1) (-1:.2:1) ]’]’

for j=1:max(size(p)) % visualize
figure(1),plot(p(1,j),p(2,j),’r.’),grid on, axis([-2 2 -2 2]),axis(‘square’)
hold on
end
—————————————-

now , to draw this simple figure it take roughly 1 second , so i ask were i’m wrong , and how can I speed up the execution of this code

the specification of the pc is as follow

Device name s.
Processor Intel(R) Pentium(R) CPU G860 @ 3.00GHz 3.00 GHz
Installed RAM 4.00 GB
Device ID ….8C39
Product ID …9
System type 64-bit operating system, x64-based processor
Pen and touch No pen or touch input is available for this display

Edition Windows 10 Home
Version 22H2
Installed on ‎11/‎7/‎2020
OS build 19045.4355
Experience Windows Feature Experience Pack 1000.19056.1000.0

Matlab :

ver
—————————————————————————————————–
MATLAB Version: 24.1.0.2689473 (R2024a) Update 6
MATLAB License Number: STUDENT
Operating System: Microsoft Windows 10 Home Version 10.0 (Build 19045)
Java Version: Java 1.8.0_202-b08 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
—————————————————————————————————–

MATLAB Version 24.1 (R2024a)
Symbolic Math Toolbox Version 24.1 (R2024a)
>>

Thankyou very much

Kind Regards

manu1965 Dear Sir
please let me have a help

this is a simple set of statements that:
-define figure 1
-clear the figure
-define a matrix 2 x 82 ,where each column represent the coordinate of a point on a plane
these set of points represent a circle and a cross , centered inside

-then do a loop that draw each point at a time, as red dot

the "hold on" is needed because at each loop i wish to maintain the points already drawed

the purpose of this code is to visualize this figure first undeformed, and after, with some deformation gradient F applied to the set of points, (and) with another (more external) loop , to visualize the advance of the deformation making the gradient F varying
(F not present in the code below)
—————————————-
clear

figure(1),clf

p=[[cos(0:.1:1.9*pi) (-1:.2:1) 0*(-1:.2:1) ]’ [sin(0:.1:1.9*pi) 0*(-1:.2:1) (-1:.2:1) ]’]’

for j=1:max(size(p)) % visualize
figure(1),plot(p(1,j),p(2,j),’r.’),grid on, axis([-2 2 -2 2]),axis(‘square’)
hold on
end
—————————————-

now , to draw this simple figure it take roughly 1 second , so i ask were i’m wrong , and how can I speed up the execution of this code

the specification of the pc is as follow

Device name s.
Processor Intel(R) Pentium(R) CPU G860 @ 3.00GHz 3.00 GHz
Installed RAM 4.00 GB
Device ID ….8C39
Product ID …9
System type 64-bit operating system, x64-based processor
Pen and touch No pen or touch input is available for this display

Edition Windows 10 Home
Version 22H2
Installed on ‎11/‎7/‎2020
OS build 19045.4355
Experience Windows Feature Experience Pack 1000.19056.1000.0

Matlab :

ver
—————————————————————————————————–
MATLAB Version: 24.1.0.2689473 (R2024a) Update 6
MATLAB License Number: STUDENT
Operating System: Microsoft Windows 10 Home Version 10.0 (Build 19045)
Java Version: Java 1.8.0_202-b08 with Oracle Corporation Java HotSpot(TM) 64-Bit Server VM mixed mode
—————————————————————————————————–

MATLAB Version 24.1 (R2024a)
Symbolic Math Toolbox Version 24.1 (R2024a)
>>

Thankyou very much

Kind Regards

manu1965 slow drawing of a set of points on a plane MATLAB Answers — New Questions

​

In the following image is plotted with the code:
load(‘data.mat’);

f = figure;
f.Position = [21,471,1883,333];
subplot(1,4,1);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd1,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD1’);

subplot(1,4,2);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd2,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD2’);

subplot(1,4,3);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd3,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD3’);

subplot(1,4,4);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,relangle,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
clim([0 30]);
title(cb, ‘alpha’);
Notice the colorbar labels "SD1", "SD2", "SD3" are clipped at the top and X and Y axes labels are far away from the axes.
Is there a setting to fix all these? I have been moving them manually with the editor but I have several of these figures and would like to make them as consistent as possible in terms of things like label positions. I think it is possible to scan the texts and set their positions semi-manually with code, but it would be much easier if there is a setting like "tight’ or something to move them closer. But "axis tight" does not work here, possibly due to the 3D nature of the plots.In the following image is plotted with the code:
load(‘data.mat’);

f = figure;
f.Position = [21,471,1883,333];
subplot(1,4,1);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd1,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD1’);

subplot(1,4,2);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd2,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD2’);

subplot(1,4,3);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd3,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD3’);

subplot(1,4,4);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,relangle,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
clim([0 30]);
title(cb, ‘alpha’);
Notice the colorbar labels "SD1", "SD2", "SD3" are clipped at the top and X and Y axes labels are far away from the axes.
Is there a setting to fix all these? I have been moving them manually with the editor but I have several of these figures and would like to make them as consistent as possible in terms of things like label positions. I think it is possible to scan the texts and set their positions semi-manually with code, but it would be much easier if there is a setting like "tight’ or something to move them closer. But "axis tight" does not work here, possibly due to the 3D nature of the plots. In the following image is plotted with the code:
load(‘data.mat’);

f = figure;
f.Position = [21,471,1883,333];
subplot(1,4,1);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd1,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD1’);

subplot(1,4,2);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd2,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD2’);

subplot(1,4,3);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,sd3,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
% clim([0 1]);
title(cb, ‘SD3’);

subplot(1,4,4);
S = 50;
scatter3(xCoord*1e6,yCoord*1e6,zCoord*1e6,S,relangle,’filled’);
xlabel(‘x (mum)’);
ylabel(‘y (mum)’);
zlabel(‘z (mum)’);
xlim([-15 15]);
ylim([-15 15]);
zlim([-15 15]);
xticks([-15 0 15]);
xticklabels({‘-15′,’0′,’15’});
yticks([-15 0 15]);
yticklabels({‘-15′,’0′,’15’});
zticks([-15 0 15]);
zticklabels({‘-15′,’0′,’15’});
% axis equal;
cb = colorbar();
clim([0 30]);
title(cb, ‘alpha’);
Notice the colorbar labels "SD1", "SD2", "SD3" are clipped at the top and X and Y axes labels are far away from the axes.
Is there a setting to fix all these? I have been moving them manually with the editor but I have several of these figures and would like to make them as consistent as possible in terms of things like label positions. I think it is possible to scan the texts and set their positions semi-manually with code, but it would be much easier if there is a setting like "tight’ or something to move them closer. But "axis tight" does not work here, possibly due to the 3D nature of the plots. plotting, text, position MATLAB Answers — New Questions

​