When I export an existing fig graph, its size does not match the content within the display interface.
Initially I found there is an error in HiDPI adaption.
My coumputer’s screen is in 200% scale. When I export the figure, the size seems to be double itself. As I halving the lenght or the width, it become normal.When I export an existing fig graph, its size does not match the content within the display interface.
Initially I found there is an error in HiDPI adaption.
My coumputer’s screen is in 200% scale. When I export the figure, the size seems to be double itself. As I halving the lenght or the width, it become normal. When I export an existing fig graph, its size does not match the content within the display interface.
Initially I found there is an error in HiDPI adaption.
My coumputer’s screen is in 200% scale. When I export the figure, the size seems to be double itself. As I halving the lenght or the width, it become normal. figure, export MATLAB Answers — New Questions

​

I have been trying to follow the NI Targeting Workflow for IP Core generation for an USRP N310 SDR. I have installed Vivado and appended it to the system path, and have been successful in connecting with the SDR using the radioSetupWizard. In Simulink, using the SDRu Reciever block, I am successfully able to read data from the Rx channels of the radio, so there is no issue with the connectivity here.
However, when I try to use the HDL coder, it seems that the radio is not recognised. I can load the default fpga using sdruload, so I assume it’s not that I can’t access the fpga, but I cannot see it, nor any other NI radio (other than the E310 which appeared after running setupusrpe3xxrepositories;) as a target platform for the HDL coder.

I would expect to see this listed as USRP N310 as in the example, but it does not appear. I have tried uninstalling and reinstalling everything, so I am at a loss of how to proceed. Any help would be greatly appreciated.I have been trying to follow the NI Targeting Workflow for IP Core generation for an USRP N310 SDR. I have installed Vivado and appended it to the system path, and have been successful in connecting with the SDR using the radioSetupWizard. In Simulink, using the SDRu Reciever block, I am successfully able to read data from the Rx channels of the radio, so there is no issue with the connectivity here.
However, when I try to use the HDL coder, it seems that the radio is not recognised. I can load the default fpga using sdruload, so I assume it’s not that I can’t access the fpga, but I cannot see it, nor any other NI radio (other than the E310 which appeared after running setupusrpe3xxrepositories;) as a target platform for the HDL coder.

I would expect to see this listed as USRP N310 as in the example, but it does not appear. I have tried uninstalling and reinstalling everything, so I am at a loss of how to proceed. Any help would be greatly appreciated. I have been trying to follow the NI Targeting Workflow for IP Core generation for an USRP N310 SDR. I have installed Vivado and appended it to the system path, and have been successful in connecting with the SDR using the radioSetupWizard. In Simulink, using the SDRu Reciever block, I am successfully able to read data from the Rx channels of the radio, so there is no issue with the connectivity here.
However, when I try to use the HDL coder, it seems that the radio is not recognised. I can load the default fpga using sdruload, so I assume it’s not that I can’t access the fpga, but I cannot see it, nor any other NI radio (other than the E310 which appeared after running setupusrpe3xxrepositories;) as a target platform for the HDL coder.

I would expect to see this listed as USRP N310 as in the example, but it does not appear. I have tried uninstalling and reinstalling everything, so I am at a loss of how to proceed. Any help would be greatly appreciated. code generation, usrp, ip-core generation MATLAB Answers — New Questions

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So, I’ve got 2 pulses (imp and S0) and their sum (Si). I’ve got to find minimum of sum (Si). And I approximate the sum with a polynome. I took derivatives (1-st and 2-nd order) of the sum and polynome.
I analyze derivatives, and decided to look for minimum of sum (Si), polynome and 2-nd derivatives.
But, in some cases the result is just empty, but size of variable is 1×999 double.

lb = -5;
ub = 15;
x_imp = linspace(lb, ub, 1001);
x = linspace(lb, ub, 1001);

imp = sech(x_imp);
S0 = sech(x-10);

imp1 = sech(x – 1);
S1 = 0.5 * (imp1 + S0);

xmin = -1;
xmax = 10;
% find inflection point Si
range_x = x(x>=xmin & x<=xmax);
range_S1 = S1(x>=xmin & x<=xmax);
MinPtsS1 = islocalmin(range_S1);
fprintf (‘x_S1 = %f , y_S1 = %f .n’, range_x(MinPtsS1), range_S1(MinPtsS1));

% polynom approximation pv
[p_S1, ~, mu] = polyfit(x, S1, 26);
pv_S1 = polyval (p_S1, x, [], mu);

% find inflection point of polynom pv

range_x = x(x>=xmin & x<=xmax);
range_pvS1 = pv_S1(x>=xmin & x<=xmax);
MinPts_pvS1 = islocalmin(range_pvS1);
fprintf(‘x_pvS1 = %f , y_pvS1 = %f .n’, range_x(MinPts_pvS1), range_pvS1(MinPts_pvS1));

% DIFF find inflection of diff2 Si, corresponding to inflection point of Si
dS1 = 20*diff (S1);
d2S1 = 10*diff(dS1);
range_x = x(x>=xmin & x<=xmin);
range_d2S1 = d2S1(x>=xmin & x<=xmin);
MinPts_d2S1 = islocalmin(range_d2S1);
fprintf(‘x_d2S1 = %f , y_d2S1 = %f .n’, range_x(MinPts_d2S1), range_d2S1(MinPts_d2S1));
% DIFF find inflection of diff2 polynom Si, corresponding to inflection point of Si
dpS1 = 20*diff(pv_S1);
dp2S1 = 20*diff(dpS1);
range_x = x(x>=xmin & x<=xmax);
range_dp2S1 = dp2S1(x>=xmin & x<=xmax);
MinPts_dp2S1 = islocalmin(range_dp2S1);
fprintf(‘x_dp2S1 = %f , y_dp2S1 = %f .n’, range_x(MinPts_dp2S1), range_dp2S1(MinPts_dp2S1));So, I’ve got 2 pulses (imp and S0) and their sum (Si). I’ve got to find minimum of sum (Si). And I approximate the sum with a polynome. I took derivatives (1-st and 2-nd order) of the sum and polynome.
I analyze derivatives, and decided to look for minimum of sum (Si), polynome and 2-nd derivatives.
But, in some cases the result is just empty, but size of variable is 1×999 double.

lb = -5;
ub = 15;
x_imp = linspace(lb, ub, 1001);
x = linspace(lb, ub, 1001);

imp = sech(x_imp);
S0 = sech(x-10);

imp1 = sech(x – 1);
S1 = 0.5 * (imp1 + S0);

xmin = -1;
xmax = 10;
% find inflection point Si
range_x = x(x>=xmin & x<=xmax);
range_S1 = S1(x>=xmin & x<=xmax);
MinPtsS1 = islocalmin(range_S1);
fprintf (‘x_S1 = %f , y_S1 = %f .n’, range_x(MinPtsS1), range_S1(MinPtsS1));

% polynom approximation pv
[p_S1, ~, mu] = polyfit(x, S1, 26);
pv_S1 = polyval (p_S1, x, [], mu);

% find inflection point of polynom pv

range_x = x(x>=xmin & x<=xmax);
range_pvS1 = pv_S1(x>=xmin & x<=xmax);
MinPts_pvS1 = islocalmin(range_pvS1);
fprintf(‘x_pvS1 = %f , y_pvS1 = %f .n’, range_x(MinPts_pvS1), range_pvS1(MinPts_pvS1));

% DIFF find inflection of diff2 Si, corresponding to inflection point of Si
dS1 = 20*diff (S1);
d2S1 = 10*diff(dS1);
range_x = x(x>=xmin & x<=xmin);
range_d2S1 = d2S1(x>=xmin & x<=xmin);
MinPts_d2S1 = islocalmin(range_d2S1);
fprintf(‘x_d2S1 = %f , y_d2S1 = %f .n’, range_x(MinPts_d2S1), range_d2S1(MinPts_d2S1));
% DIFF find inflection of diff2 polynom Si, corresponding to inflection point of Si
dpS1 = 20*diff(pv_S1);
dp2S1 = 20*diff(dpS1);
range_x = x(x>=xmin & x<=xmax);
range_dp2S1 = dp2S1(x>=xmin & x<=xmax);
MinPts_dp2S1 = islocalmin(range_dp2S1);
fprintf(‘x_dp2S1 = %f , y_dp2S1 = %f .n’, range_x(MinPts_dp2S1), range_dp2S1(MinPts_dp2S1)); So, I’ve got 2 pulses (imp and S0) and their sum (Si). I’ve got to find minimum of sum (Si). And I approximate the sum with a polynome. I took derivatives (1-st and 2-nd order) of the sum and polynome.
I analyze derivatives, and decided to look for minimum of sum (Si), polynome and 2-nd derivatives.
But, in some cases the result is just empty, but size of variable is 1×999 double.

lb = -5;
ub = 15;
x_imp = linspace(lb, ub, 1001);
x = linspace(lb, ub, 1001);

imp = sech(x_imp);
S0 = sech(x-10);

imp1 = sech(x – 1);
S1 = 0.5 * (imp1 + S0);

xmin = -1;
xmax = 10;
% find inflection point Si
range_x = x(x>=xmin & x<=xmax);
range_S1 = S1(x>=xmin & x<=xmax);
MinPtsS1 = islocalmin(range_S1);
fprintf (‘x_S1 = %f , y_S1 = %f .n’, range_x(MinPtsS1), range_S1(MinPtsS1));

% polynom approximation pv
[p_S1, ~, mu] = polyfit(x, S1, 26);
pv_S1 = polyval (p_S1, x, [], mu);

% find inflection point of polynom pv

range_x = x(x>=xmin & x<=xmax);
range_pvS1 = pv_S1(x>=xmin & x<=xmax);
MinPts_pvS1 = islocalmin(range_pvS1);
fprintf(‘x_pvS1 = %f , y_pvS1 = %f .n’, range_x(MinPts_pvS1), range_pvS1(MinPts_pvS1));

% DIFF find inflection of diff2 Si, corresponding to inflection point of Si
dS1 = 20*diff (S1);
d2S1 = 10*diff(dS1);
range_x = x(x>=xmin & x<=xmin);
range_d2S1 = d2S1(x>=xmin & x<=xmin);
MinPts_d2S1 = islocalmin(range_d2S1);
fprintf(‘x_d2S1 = %f , y_d2S1 = %f .n’, range_x(MinPts_d2S1), range_d2S1(MinPts_d2S1));
% DIFF find inflection of diff2 polynom Si, corresponding to inflection point of Si
dpS1 = 20*diff(pv_S1);
dp2S1 = 20*diff(dpS1);
range_x = x(x>=xmin & x<=xmax);
range_dp2S1 = dp2S1(x>=xmin & x<=xmax);
MinPts_dp2S1 = islocalmin(range_dp2S1);
fprintf(‘x_dp2S1 = %f , y_dp2S1 = %f .n’, range_x(MinPts_dp2S1), range_dp2S1(MinPts_dp2S1)); empty output, derivative, diff, polyval MATLAB Answers — New Questions

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I have a point matrix p whose size is 3×98065;the triangulation matrix t whose size is 3×196124 ;
How to output the data as a STL model.Thank you.I have a point matrix p whose size is 3×98065;the triangulation matrix t whose size is 3×196124 ;
How to output the data as a STL model.Thank you. I have a point matrix p whose size is 3×98065;the triangulation matrix t whose size is 3×196124 ;
How to output the data as a STL model.Thank you. output stl format flie, triangulation matrix, point matrix, export stl, write stl MATLAB Answers — New Questions

​

i want to use ltpda and then plist. But if i use it as ‘ltpda_startup’ , matlab cant recognize it and after that ‘plist’. In 2016 and 2017 version of matlab it worked. How can i fix it in 2023 version or is there any alternative solutions for it?i want to use ltpda and then plist. But if i use it as ‘ltpda_startup’ , matlab cant recognize it and after that ‘plist’. In 2016 and 2017 version of matlab it worked. How can i fix it in 2023 version or is there any alternative solutions for it? i want to use ltpda and then plist. But if i use it as ‘ltpda_startup’ , matlab cant recognize it and after that ‘plist’. In 2016 and 2017 version of matlab it worked. How can i fix it in 2023 version or is there any alternative solutions for it? image processing, ltpda MATLAB Answers — New Questions

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I have a file of color map with known boundary coordinates and color bar scale either horizontal or vertical. How can we transform the color map into contour map, such that the value of contours expressed the same in the color bar values?I have a file of color map with known boundary coordinates and color bar scale either horizontal or vertical. How can we transform the color map into contour map, such that the value of contours expressed the same in the color bar values? I have a file of color map with known boundary coordinates and color bar scale either horizontal or vertical. How can we transform the color map into contour map, such that the value of contours expressed the same in the color bar values? colormap, contour map MATLAB Answers — New Questions

​

excelfilepath= ‘D:mirror1.xlsx’;
data =readtable(excelfilepath);
value=data{1,1};

app.EditField.Value = num2str(value);
end
what is wrong with code
it gives parse erorr
thanksexcelfilepath= ‘D:mirror1.xlsx’;
data =readtable(excelfilepath);
value=data{1,1};

app.EditField.Value = num2str(value);
end
what is wrong with code
it gives parse erorr
thanks excelfilepath= ‘D:mirror1.xlsx’;
data =readtable(excelfilepath);
value=data{1,1};

app.EditField.Value = num2str(value);
end
what is wrong with code
it gives parse erorr
thanks app designer, excel MATLAB Answers — New Questions

​

% Code for 3x+1 Problem
seed = 10^309; % Starting number
x = seed; % Initialize x with the seed
trajectory = x; % Store the trajectory
tic
while x ~= 1
if mod(x, 2) == 0 % Check if x is even
x = x / 2;
else % If x is odd
x = 3 * x + 1;
end
trajectory = [trajectory, x]; % Append x to trajectory
end
toc
% Plot the trajectory
figure;
plot(trajectory, ‘-o’, ‘LineWidth’, 1, ‘MarkerSize’, 5,’MarkerFaceColor’, ‘r’);
title(‘Plot of the Collatz Sequence for positive Seed 10^310’);
xlabel(‘Step’);
ylabel(‘Value’);
grid on;% Code for 3x+1 Problem
seed = 10^309; % Starting number
x = seed; % Initialize x with the seed
trajectory = x; % Store the trajectory
tic
while x ~= 1
if mod(x, 2) == 0 % Check if x is even
x = x / 2;
else % If x is odd
x = 3 * x + 1;
end
trajectory = [trajectory, x]; % Append x to trajectory
end
toc
% Plot the trajectory
figure;
plot(trajectory, ‘-o’, ‘LineWidth’, 1, ‘MarkerSize’, 5,’MarkerFaceColor’, ‘r’);
title(‘Plot of the Collatz Sequence for positive Seed 10^310’);
xlabel(‘Step’);
ylabel(‘Value’);
grid on; % Code for 3x+1 Problem
seed = 10^309; % Starting number
x = seed; % Initialize x with the seed
trajectory = x; % Store the trajectory
tic
while x ~= 1
if mod(x, 2) == 0 % Check if x is even
x = x / 2;
else % If x is odd
x = 3 * x + 1;
end
trajectory = [trajectory, x]; % Append x to trajectory
end
toc
% Plot the trajectory
figure;
plot(trajectory, ‘-o’, ‘LineWidth’, 1, ‘MarkerSize’, 5,’MarkerFaceColor’, ‘r’);
title(‘Plot of the Collatz Sequence for positive Seed 10^310’);
xlabel(‘Step’);
ylabel(‘Value’);
grid on; collatz conjecture, 3x +1 problem MATLAB Answers — New Questions

​

I am trying to add a bulleted list in a Matlab annotation textbox. I’ve tried using LaTex commands but all I get is: Unable to interpret latex string, such as

str = ‘begin{itemized} item First Line item Second Line end{itemized}’;
figure;
ha = annotation(‘textbox’, [0.5 0.5 0.4 0.2], ‘Interpreter’, ‘latex’);
set(ha, ‘String’, str)

This is similar to the way you put a table in an annotated textbox:

<http://www.mathworks.com/matlabcentral/answers/99523-how-do-i-create-a-latex-table-in-a-matlab-text-box Latex Table>I am trying to add a bulleted list in a Matlab annotation textbox. I’ve tried using LaTex commands but all I get is: Unable to interpret latex string, such as

str = ‘begin{itemized} item First Line item Second Line end{itemized}’;
figure;
ha = annotation(‘textbox’, [0.5 0.5 0.4 0.2], ‘Interpreter’, ‘latex’);
set(ha, ‘String’, str)

This is similar to the way you put a table in an annotated textbox:

<http://www.mathworks.com/matlabcentral/answers/99523-how-do-i-create-a-latex-table-in-a-matlab-text-box Latex Table> I am trying to add a bulleted list in a Matlab annotation textbox. I’ve tried using LaTex commands but all I get is: Unable to interpret latex string, such as

str = ‘begin{itemized} item First Line item Second Line end{itemized}’;
figure;
ha = annotation(‘textbox’, [0.5 0.5 0.4 0.2], ‘Interpreter’, ‘latex’);
set(ha, ‘String’, str)

This is similar to the way you put a table in an annotated textbox:

<http://www.mathworks.com/matlabcentral/answers/99523-how-do-i-create-a-latex-table-in-a-matlab-text-box Latex Table> latex, bulleted list, annotation MATLAB Answers — New Questions

​

I was working on my code like 10 days ago in 2025a, the code is running and the plot is showing correctly. I decided to run again to take some screenshot of my plot but my plot is no longer displaying correctly. If I print the plot, I will see the correct plot on the print dialog but the original plot window is showing up very bad. Screenshot applied. Please any immediate help will be appreciated as this is my school assignment.

My computer is Linux Ubuntu 22.04

clear all; close all; clc;

%% System Parameters
% Physical parameters of the DC motor
Ra = 1.0; % Armature resistance (Ohm)
La = 0.5; % Armature inductance (H)
J = 0.01; % Moment of inertia (Nms^2/rad)
b = 0.1; % Damping coefficient (Nms)
KT = 0.01; % Torque constant (Nm/A)
Ke = 0.01; % Back EMF constant (Nm/A)
K = Ke; % In SI units, Ke = Ki = K

%% Transfer Function Definition
% Open loop transfer function: θ(s)/Ea(s)
% G(s) = K / [(Js + b)(Las + Ra) + K^2]

% Coefficients calculation
num = K;
den_coeff = [J*La, (J*Ra + b*La), (b*Ra + K^2)];
den = den_coeff;

% Create transfer function
G = tf(num, den);

% Display the transfer function
fprintf(‘Open Loop Transfer Function:n’);
fprintf(‘G(s) = %.4f / (%.4fs^2 + %.4fs + %.4f)n’, num, den(1), den(2), den(3));

%% Performance Specifications
% Desired specifications:
% – Settling time (Ts) < 2 seconds
% – Percentage Overshoot (PO) < 5%
% – Steady State Error (SSE) < 1%

fprintf(‘nDesired Specifications:n’);
fprintf(‘- Settling time (Ts) < 2 secondsn’);
fprintf(‘- Percentage Overshoot (PO) < 5%%n’);
fprintf(‘- Steady State Error (SSE) < 1%%nn’);

%% Step 1: Open Loop Response
fprintf(‘=== STEP 1: OPEN LOOP RESPONSE ===n’);

figure(1);
[y1, t1] = step(G);
plot(t1, y1, ‘b-‘, ‘LineWidth’, 2);
title(‘Open Loop Step Response’);
xlabel(‘Time (seconds)’);
ylabel(‘Angular Position (rad)’);
grid on;

% Calculate performance metrics for open loop
stepinfo_ol = stepinfo(G);
fprintf(‘Open Loop Performance:n’);
fprintf(‘Rise Time (Tr): %.4f secondsn’, stepinfo_ol.RiseTime);
fprintf(‘Settling Time (Ts): %.4f secondsn’, stepinfo_ol.SettlingTime);
fprintf(‘Peak Overshoot: %.2f%%n’, stepinfo_ol.Overshoot);

% Steady state error calculation (for unit step)
% For Type 0 system: ess = 1/(1+Kp) where Kp = lim s->0 G(s)
Kp_ol = dcgain(G);
ess_ol = 1/(1+Kp_ol) * 100; % Convert to percentage
fprintf(‘Steady State Error: %.2f%%n’, ess_ol);
fprintf(‘Comments: Open loop system is unstable or has poor performancenn’);

Bad Plot

Print DialogI was working on my code like 10 days ago in 2025a, the code is running and the plot is showing correctly. I decided to run again to take some screenshot of my plot but my plot is no longer displaying correctly. If I print the plot, I will see the correct plot on the print dialog but the original plot window is showing up very bad. Screenshot applied. Please any immediate help will be appreciated as this is my school assignment.

My computer is Linux Ubuntu 22.04

clear all; close all; clc;

%% System Parameters
% Physical parameters of the DC motor
Ra = 1.0; % Armature resistance (Ohm)
La = 0.5; % Armature inductance (H)
J = 0.01; % Moment of inertia (Nms^2/rad)
b = 0.1; % Damping coefficient (Nms)
KT = 0.01; % Torque constant (Nm/A)
Ke = 0.01; % Back EMF constant (Nm/A)
K = Ke; % In SI units, Ke = Ki = K

%% Transfer Function Definition
% Open loop transfer function: θ(s)/Ea(s)
% G(s) = K / [(Js + b)(Las + Ra) + K^2]

% Coefficients calculation
num = K;
den_coeff = [J*La, (J*Ra + b*La), (b*Ra + K^2)];
den = den_coeff;

% Create transfer function
G = tf(num, den);

% Display the transfer function
fprintf(‘Open Loop Transfer Function:n’);
fprintf(‘G(s) = %.4f / (%.4fs^2 + %.4fs + %.4f)n’, num, den(1), den(2), den(3));

%% Performance Specifications
% Desired specifications:
% – Settling time (Ts) < 2 seconds
% – Percentage Overshoot (PO) < 5%
% – Steady State Error (SSE) < 1%

fprintf(‘nDesired Specifications:n’);
fprintf(‘- Settling time (Ts) < 2 secondsn’);
fprintf(‘- Percentage Overshoot (PO) < 5%%n’);
fprintf(‘- Steady State Error (SSE) < 1%%nn’);

%% Step 1: Open Loop Response
fprintf(‘=== STEP 1: OPEN LOOP RESPONSE ===n’);

figure(1);
[y1, t1] = step(G);
plot(t1, y1, ‘b-‘, ‘LineWidth’, 2);
title(‘Open Loop Step Response’);
xlabel(‘Time (seconds)’);
ylabel(‘Angular Position (rad)’);
grid on;

% Calculate performance metrics for open loop
stepinfo_ol = stepinfo(G);
fprintf(‘Open Loop Performance:n’);
fprintf(‘Rise Time (Tr): %.4f secondsn’, stepinfo_ol.RiseTime);
fprintf(‘Settling Time (Ts): %.4f secondsn’, stepinfo_ol.SettlingTime);
fprintf(‘Peak Overshoot: %.2f%%n’, stepinfo_ol.Overshoot);

% Steady state error calculation (for unit step)
% For Type 0 system: ess = 1/(1+Kp) where Kp = lim s->0 G(s)
Kp_ol = dcgain(G);
ess_ol = 1/(1+Kp_ol) * 100; % Convert to percentage
fprintf(‘Steady State Error: %.2f%%n’, ess_ol);
fprintf(‘Comments: Open loop system is unstable or has poor performancenn’);

Bad Plot

Print Dialog I was working on my code like 10 days ago in 2025a, the code is running and the plot is showing correctly. I decided to run again to take some screenshot of my plot but my plot is no longer displaying correctly. If I print the plot, I will see the correct plot on the print dialog but the original plot window is showing up very bad. Screenshot applied. Please any immediate help will be appreciated as this is my school assignment.

My computer is Linux Ubuntu 22.04

clear all; close all; clc;

%% System Parameters
% Physical parameters of the DC motor
Ra = 1.0; % Armature resistance (Ohm)
La = 0.5; % Armature inductance (H)
J = 0.01; % Moment of inertia (Nms^2/rad)
b = 0.1; % Damping coefficient (Nms)
KT = 0.01; % Torque constant (Nm/A)
Ke = 0.01; % Back EMF constant (Nm/A)
K = Ke; % In SI units, Ke = Ki = K

%% Transfer Function Definition
% Open loop transfer function: θ(s)/Ea(s)
% G(s) = K / [(Js + b)(Las + Ra) + K^2]

% Coefficients calculation
num = K;
den_coeff = [J*La, (J*Ra + b*La), (b*Ra + K^2)];
den = den_coeff;

% Create transfer function
G = tf(num, den);

% Display the transfer function
fprintf(‘Open Loop Transfer Function:n’);
fprintf(‘G(s) = %.4f / (%.4fs^2 + %.4fs + %.4f)n’, num, den(1), den(2), den(3));

%% Performance Specifications
% Desired specifications:
% – Settling time (Ts) < 2 seconds
% – Percentage Overshoot (PO) < 5%
% – Steady State Error (SSE) < 1%

fprintf(‘nDesired Specifications:n’);
fprintf(‘- Settling time (Ts) < 2 secondsn’);
fprintf(‘- Percentage Overshoot (PO) < 5%%n’);
fprintf(‘- Steady State Error (SSE) < 1%%nn’);

%% Step 1: Open Loop Response
fprintf(‘=== STEP 1: OPEN LOOP RESPONSE ===n’);

figure(1);
[y1, t1] = step(G);
plot(t1, y1, ‘b-‘, ‘LineWidth’, 2);
title(‘Open Loop Step Response’);
xlabel(‘Time (seconds)’);
ylabel(‘Angular Position (rad)’);
grid on;

% Calculate performance metrics for open loop
stepinfo_ol = stepinfo(G);
fprintf(‘Open Loop Performance:n’);
fprintf(‘Rise Time (Tr): %.4f secondsn’, stepinfo_ol.RiseTime);
fprintf(‘Settling Time (Ts): %.4f secondsn’, stepinfo_ol.SettlingTime);
fprintf(‘Peak Overshoot: %.2f%%n’, stepinfo_ol.Overshoot);

% Steady state error calculation (for unit step)
% For Type 0 system: ess = 1/(1+Kp) where Kp = lim s->0 G(s)
Kp_ol = dcgain(G);
ess_ol = 1/(1+Kp_ol) * 100; % Convert to percentage
fprintf(‘Steady State Error: %.2f%%n’, ess_ol);
fprintf(‘Comments: Open loop system is unstable or has poor performancenn’);

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