frequency equation for multiple degree freedom system
syms omega;
M = 5×5
1.8000 0 0 0 0
0 6.3000 0 0 0
0 0 5.4000 0 0
0 0 0 22.5000 0
0 0 0 0 54.0000
C = 5×5
10000 -10000 0 0 0
-10000 10500 -500 0 0
0 -500 2000 -1500 0
0 0 -1500 2600 -1100
0 0 0 -1100 1100
K = 5×5
100000000 -100000000 0 0 0
-100000000 100050000 -50000 0 0
0 -50000 125000 75000 0
0 0 -75000 85000 -10000
0 0 0 -10000 10000
the matrices for mass,frequency and damping coeffcinets are as above is it corrrect to to obtain the frequency equation from the following code
eliminant = det(-omega^2 * M + omega * C + K)
and also how to obtain non zero natural frequencies of the systemsyms omega;
M = 5×5
1.8000 0 0 0 0
0 6.3000 0 0 0
0 0 5.4000 0 0
0 0 0 22.5000 0
0 0 0 0 54.0000
C = 5×5
10000 -10000 0 0 0
-10000 10500 -500 0 0
0 -500 2000 -1500 0
0 0 -1500 2600 -1100
0 0 0 -1100 1100
K = 5×5
100000000 -100000000 0 0 0
-100000000 100050000 -50000 0 0
0 -50000 125000 75000 0
0 0 -75000 85000 -10000
0 0 0 -10000 10000
the matrices for mass,frequency and damping coeffcinets are as above is it corrrect to to obtain the frequency equation from the following code
eliminant = det(-omega^2 * M + omega * C + K)
and also how to obtain non zero natural frequencies of the system syms omega;
M = 5×5
1.8000 0 0 0 0
0 6.3000 0 0 0
0 0 5.4000 0 0
0 0 0 22.5000 0
0 0 0 0 54.0000
C = 5×5
10000 -10000 0 0 0
-10000 10500 -500 0 0
0 -500 2000 -1500 0
0 0 -1500 2600 -1100
0 0 0 -1100 1100
K = 5×5
100000000 -100000000 0 0 0
-100000000 100050000 -50000 0 0
0 -50000 125000 75000 0
0 0 -75000 85000 -10000
0 0 0 -10000 10000
the matrices for mass,frequency and damping coeffcinets are as above is it corrrect to to obtain the frequency equation from the following code
eliminant = det(-omega^2 * M + omega * C + K)
and also how to obtain non zero natural frequencies of the system vibration, matlab, matrices MATLAB Answers — New Questions