Correct the code for me please
% Given data points
x = [0,0.1, 0.8, 0.6, 0.9, 1];
f = [-1,-1.2299,-3.455, -2.9949, -3.3929, -3];
% Part (a) – Construct the divided difference table
n = length(x);
d = zeros(n);
d(1,1) = f(1);
for i = 2:n
d(i,1) = (f(i) – f(i-1))/(x(i) – x(i-1));
for j = 2:i
d(i,j) = (d(i,j-1) – d(i-1,j-1))/(x(i) – x(i-j));
end
end
disp(‘Divided Difference Table:’)
disp(d)
% Part (b) – Evaluate the polynomial of order "n-1"
y = 0;
for i = 1:n
temp = f(1);
for j = 1:i
temp = temp * (0.5 – x(1:i-j)) + d(i,j);
end
y = y + temp;
end
fprintf(‘The value of the polynomial at x = 0.5 is %.4fn’, y)
% Part (c) – Evaluate f(0.5)
f_interp = interp1(x,f,0.5);
fprintf(‘The value of f(0.5) is %.4fn’, f_interp)
% Part (d) – Check your answers using built-in MATLAB functions
p = polyfit(x,f,5);
y_polyfit = polyval(p,0.5);
fprintf(‘The value of the polynomial at x = 0.5 using polyfit is %.4fn’, y_polyfit)
f_interp_polyfit = interp1(x,f,0.5,’linear’);
fprintf(‘The value of f(0.5) using interp1 is %.4fn’, f_interp_polyfit)% Given data points
x = [0,0.1, 0.8, 0.6, 0.9, 1];
f = [-1,-1.2299,-3.455, -2.9949, -3.3929, -3];
% Part (a) – Construct the divided difference table
n = length(x);
d = zeros(n);
d(1,1) = f(1);
for i = 2:n
d(i,1) = (f(i) – f(i-1))/(x(i) – x(i-1));
for j = 2:i
d(i,j) = (d(i,j-1) – d(i-1,j-1))/(x(i) – x(i-j));
end
end
disp(‘Divided Difference Table:’)
disp(d)
% Part (b) – Evaluate the polynomial of order "n-1"
y = 0;
for i = 1:n
temp = f(1);
for j = 1:i
temp = temp * (0.5 – x(1:i-j)) + d(i,j);
end
y = y + temp;
end
fprintf(‘The value of the polynomial at x = 0.5 is %.4fn’, y)
% Part (c) – Evaluate f(0.5)
f_interp = interp1(x,f,0.5);
fprintf(‘The value of f(0.5) is %.4fn’, f_interp)
% Part (d) – Check your answers using built-in MATLAB functions
p = polyfit(x,f,5);
y_polyfit = polyval(p,0.5);
fprintf(‘The value of the polynomial at x = 0.5 using polyfit is %.4fn’, y_polyfit)
f_interp_polyfit = interp1(x,f,0.5,’linear’);
fprintf(‘The value of f(0.5) using interp1 is %.4fn’, f_interp_polyfit) % Given data points
x = [0,0.1, 0.8, 0.6, 0.9, 1];
f = [-1,-1.2299,-3.455, -2.9949, -3.3929, -3];
% Part (a) – Construct the divided difference table
n = length(x);
d = zeros(n);
d(1,1) = f(1);
for i = 2:n
d(i,1) = (f(i) – f(i-1))/(x(i) – x(i-1));
for j = 2:i
d(i,j) = (d(i,j-1) – d(i-1,j-1))/(x(i) – x(i-j));
end
end
disp(‘Divided Difference Table:’)
disp(d)
% Part (b) – Evaluate the polynomial of order "n-1"
y = 0;
for i = 1:n
temp = f(1);
for j = 1:i
temp = temp * (0.5 – x(1:i-j)) + d(i,j);
end
y = y + temp;
end
fprintf(‘The value of the polynomial at x = 0.5 is %.4fn’, y)
% Part (c) – Evaluate f(0.5)
f_interp = interp1(x,f,0.5);
fprintf(‘The value of f(0.5) is %.4fn’, f_interp)
% Part (d) – Check your answers using built-in MATLAB functions
p = polyfit(x,f,5);
y_polyfit = polyval(p,0.5);
fprintf(‘The value of the polynomial at x = 0.5 using polyfit is %.4fn’, y_polyfit)
f_interp_polyfit = interp1(x,f,0.5,’linear’);
fprintf(‘The value of f(0.5) using interp1 is %.4fn’, f_interp_polyfit) numerical MATLAB Answers — New Questions