Is there a way that I can get the first occurrence of consecutively repeating values, even if the same value occurs at few different places in the matrix?

Say I have a matrix

X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6]

I want the result to be

ans=[2 -1 6 5 2 7 6].

I’ve checked a similar question <http://www.mathworks.com/matlabcentral/answers/16667-how-to-remove-repeating-elements-from-an-array How to remove repeating elements from an array> but using unique and keeping the same order as original matrix gives

ans=[2 -1 6 5 7].

I know I can use a loop like below. But I was wondering if there’s a function for this.

for i=1:(length(X)-1)
if (X(i+1,6)-X(i,6))~=0
ans(i,1)=X(i+1,6);
else
ans(i,1)=NaN;
end
end

A function to do this will be great.Is there a way that I can get the first occurrence of consecutively repeating values, even if the same value occurs at few different places in the matrix?

Say I have a matrix

X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6]

I want the result to be

ans=[2 -1 6 5 2 7 6].

I’ve checked a similar question <http://www.mathworks.com/matlabcentral/answers/16667-how-to-remove-repeating-elements-from-an-array How to remove repeating elements from an array> but using unique and keeping the same order as original matrix gives

ans=[2 -1 6 5 7].

I know I can use a loop like below. But I was wondering if there’s a function for this.

for i=1:(length(X)-1)
if (X(i+1,6)-X(i,6))~=0
ans(i,1)=X(i+1,6);
else
ans(i,1)=NaN;
end
end

A function to do this will be great. Is there a way that I can get the first occurrence of consecutively repeating values, even if the same value occurs at few different places in the matrix?

Say I have a matrix

X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6]

I want the result to be

ans=[2 -1 6 5 2 7 6].

I’ve checked a similar question <http://www.mathworks.com/matlabcentral/answers/16667-how-to-remove-repeating-elements-from-an-array How to remove repeating elements from an array> but using unique and keeping the same order as original matrix gives

ans=[2 -1 6 5 7].

I know I can use a loop like below. But I was wondering if there’s a function for this.

for i=1:(length(X)-1)
if (X(i+1,6)-X(i,6))~=0
ans(i,1)=X(i+1,6);
else
ans(i,1)=NaN;
end
end

A function to do this will be great. array, repeating elements, unique, sort, matrix, matrix manipulation MATLAB Answers — New Questions

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