Author: PuTI
Error when trying to export a trained deep learning model to ONNX format in MATLAB due to the “SplitComplexInputs”
I followed the tutorial on MATLAB’s official website for modulation classification using deep learning:
Modulation Classification with Deep Learning
After training the network, I attempted to export the trained model to ONNX using the following command:
exportONNXNetwork(trainedNet, "www.onnx");
However, I received the following error message:
Error using nnet.internal.cnn.onnx.ConverterForSequenceInputLayer/toOnnx (line 55)
Unsupported input layer option for layer ‘Input Layer’. To export networks with an
input layer, the SplitComplexInputs property must be 0 (false).
Error in nnet.internal.cnn.onnx.ConverterForNetwork/networkToGraphProto (line 109)
= toOnnx(layerConverter, nodeProtos, TensorNameMap, TensorLayoutMap);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.ConverterForNetwork/toOnnx (line 45)
modelProto.graph = networkToGraphProto(this);
^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.exportONNXNetwork (line 22)
modelProto = toOnnx(converter);
^^^^^^^^^^^^^^^^^
Error in exportONNXNetwork (line 44)
nnet.internal.cnn.onnx.exportONNXNetwork(Network, filename, varargin{:});
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
It seems that my network’s input layer has the SplitComplexInputs property set to true, which prevents ONNX export. How can I modify the network to allow exporting it in ONNX format for use in Python?I followed the tutorial on MATLAB’s official website for modulation classification using deep learning:
Modulation Classification with Deep Learning
After training the network, I attempted to export the trained model to ONNX using the following command:
exportONNXNetwork(trainedNet, "www.onnx");
However, I received the following error message:
Error using nnet.internal.cnn.onnx.ConverterForSequenceInputLayer/toOnnx (line 55)
Unsupported input layer option for layer ‘Input Layer’. To export networks with an
input layer, the SplitComplexInputs property must be 0 (false).
Error in nnet.internal.cnn.onnx.ConverterForNetwork/networkToGraphProto (line 109)
= toOnnx(layerConverter, nodeProtos, TensorNameMap, TensorLayoutMap);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.ConverterForNetwork/toOnnx (line 45)
modelProto.graph = networkToGraphProto(this);
^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.exportONNXNetwork (line 22)
modelProto = toOnnx(converter);
^^^^^^^^^^^^^^^^^
Error in exportONNXNetwork (line 44)
nnet.internal.cnn.onnx.exportONNXNetwork(Network, filename, varargin{:});
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
It seems that my network’s input layer has the SplitComplexInputs property set to true, which prevents ONNX export. How can I modify the network to allow exporting it in ONNX format for use in Python? I followed the tutorial on MATLAB’s official website for modulation classification using deep learning:
Modulation Classification with Deep Learning
After training the network, I attempted to export the trained model to ONNX using the following command:
exportONNXNetwork(trainedNet, "www.onnx");
However, I received the following error message:
Error using nnet.internal.cnn.onnx.ConverterForSequenceInputLayer/toOnnx (line 55)
Unsupported input layer option for layer ‘Input Layer’. To export networks with an
input layer, the SplitComplexInputs property must be 0 (false).
Error in nnet.internal.cnn.onnx.ConverterForNetwork/networkToGraphProto (line 109)
= toOnnx(layerConverter, nodeProtos, TensorNameMap, TensorLayoutMap);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.ConverterForNetwork/toOnnx (line 45)
modelProto.graph = networkToGraphProto(this);
^^^^^^^^^^^^^^^^^^^^^^^^^
Error in nnet.internal.cnn.onnx.exportONNXNetwork (line 22)
modelProto = toOnnx(converter);
^^^^^^^^^^^^^^^^^
Error in exportONNXNetwork (line 44)
nnet.internal.cnn.onnx.exportONNXNetwork(Network, filename, varargin{:});
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
It seems that my network’s input layer has the SplitComplexInputs property set to true, which prevents ONNX export. How can I modify the network to allow exporting it in ONNX format for use in Python? machine learning, deep learning, model MATLAB Answers — New Questions
How to write in multiple lines simultaneously in Matlab Editor ?
I have seen the new funcionalities in version 2021b and it appears that you can put the cursor in multiples lines for writing code.I have seen the new funcionalities in version 2021b and it appears that you can put the cursor in multiples lines for writing code. I have seen the new funcionalities in version 2021b and it appears that you can put the cursor in multiples lines for writing code. multiple lines, editor MATLAB Answers — New Questions
MATLAB Simulink Task 5 Power Systems Simulation Incorrect Output Description
I’m working on the MATLAB Simulink Power Systems Simulation Onramp, specifically Task 5. I changed the Wye-Connected Load block component structure to Series RL and set the default value to 12∠0° (A) for inductive reactive power, as required. I also used the filter from the previous task to extract the reactive power from the Q port of the Power Sensor and connected the filtered measurement to the Signal Assessment block. However, I still receive an incorrect output error.
Could anyone help identify what might be wrong?I’m working on the MATLAB Simulink Power Systems Simulation Onramp, specifically Task 5. I changed the Wye-Connected Load block component structure to Series RL and set the default value to 12∠0° (A) for inductive reactive power, as required. I also used the filter from the previous task to extract the reactive power from the Q port of the Power Sensor and connected the filtered measurement to the Signal Assessment block. However, I still receive an incorrect output error.
Could anyone help identify what might be wrong? I’m working on the MATLAB Simulink Power Systems Simulation Onramp, specifically Task 5. I changed the Wye-Connected Load block component structure to Series RL and set the default value to 12∠0° (A) for inductive reactive power, as required. I also used the filter from the previous task to extract the reactive power from the Q port of the Power Sensor and connected the filtered measurement to the Signal Assessment block. However, I still receive an incorrect output error.
Could anyone help identify what might be wrong? simulink, power systems, onramp, signal assessment MATLAB Answers — New Questions
MATLAB 2023b Keeps Crashing on My Windows Desktop But Works on Laptop
Hey everyone,
I’m reaching out to see if anyone else has experienced similar issues or might have some advice. I’ve been running MATLAB 2023b on my Windows desktop, and it keeps crashing unexpectedly. What’s puzzling is that the same code runs perfectly fine on my laptop, so I’m inclined to think the problem isn’t with the code itself.
Here’s what I’ve observed:
No Error Logs or Dumps: When MATLAB crashes, it doesn’t generate any logs or dumps that I can check for clues. This makes it really challenging to diagnose the issue.
Consistent Crashes: The crashes seem to happen randomly, without any specific pattern or trigger that I can identify.
System Specs: My desktop has mush better spec than laptop, so I don’t think it’s a hardware limitation. Both my desktop and laptop are running Windows, but the desktop is where the issue persists. I have tried running with softwareopengl option, but that also does not help.
I’ve tried a few basic troubleshooting steps like reinstalling MATLAB, and ensuring Windows is up to date, but the problem persists.
If anyone has experienced something similar or has any suggestions on what I could try next, I’d really appreciate your input. It’s quite frustrating, and I’m hoping to get back to a stable working environment soon.Hey everyone,
I’m reaching out to see if anyone else has experienced similar issues or might have some advice. I’ve been running MATLAB 2023b on my Windows desktop, and it keeps crashing unexpectedly. What’s puzzling is that the same code runs perfectly fine on my laptop, so I’m inclined to think the problem isn’t with the code itself.
Here’s what I’ve observed:
No Error Logs or Dumps: When MATLAB crashes, it doesn’t generate any logs or dumps that I can check for clues. This makes it really challenging to diagnose the issue.
Consistent Crashes: The crashes seem to happen randomly, without any specific pattern or trigger that I can identify.
System Specs: My desktop has mush better spec than laptop, so I don’t think it’s a hardware limitation. Both my desktop and laptop are running Windows, but the desktop is where the issue persists. I have tried running with softwareopengl option, but that also does not help.
I’ve tried a few basic troubleshooting steps like reinstalling MATLAB, and ensuring Windows is up to date, but the problem persists.
If anyone has experienced something similar or has any suggestions on what I could try next, I’d really appreciate your input. It’s quite frustrating, and I’m hoping to get back to a stable working environment soon. Hey everyone,
I’m reaching out to see if anyone else has experienced similar issues or might have some advice. I’ve been running MATLAB 2023b on my Windows desktop, and it keeps crashing unexpectedly. What’s puzzling is that the same code runs perfectly fine on my laptop, so I’m inclined to think the problem isn’t with the code itself.
Here’s what I’ve observed:
No Error Logs or Dumps: When MATLAB crashes, it doesn’t generate any logs or dumps that I can check for clues. This makes it really challenging to diagnose the issue.
Consistent Crashes: The crashes seem to happen randomly, without any specific pattern or trigger that I can identify.
System Specs: My desktop has mush better spec than laptop, so I don’t think it’s a hardware limitation. Both my desktop and laptop are running Windows, but the desktop is where the issue persists. I have tried running with softwareopengl option, but that also does not help.
I’ve tried a few basic troubleshooting steps like reinstalling MATLAB, and ensuring Windows is up to date, but the problem persists.
If anyone has experienced something similar or has any suggestions on what I could try next, I’d really appreciate your input. It’s quite frustrating, and I’m hoping to get back to a stable working environment soon. crash, matlab, 2023b MATLAB Answers — New Questions
Simulink Threshold with action
I would like to create a simulink model that basically takes an input, lets say 2.5, and check if this value is between 6.5 to 8.5. Once checked, if below this range, then it must add 1 to the initial input. If it is betwen this range, all it needs to do is display the output that falls between the 6.5 to 8.5 range. If possible, I would like for it to show how many iterations it took to get between range.I would like to create a simulink model that basically takes an input, lets say 2.5, and check if this value is between 6.5 to 8.5. Once checked, if below this range, then it must add 1 to the initial input. If it is betwen this range, all it needs to do is display the output that falls between the 6.5 to 8.5 range. If possible, I would like for it to show how many iterations it took to get between range. I would like to create a simulink model that basically takes an input, lets say 2.5, and check if this value is between 6.5 to 8.5. Once checked, if below this range, then it must add 1 to the initial input. If it is betwen this range, all it needs to do is display the output that falls between the 6.5 to 8.5 range. If possible, I would like for it to show how many iterations it took to get between range. simulink MATLAB Answers — New Questions
nonlinear spline fit with unknown upper bound of interpolation domain
I want to fit the interpolation values of a spline, but I can not provide a good guess for the upper bound of the interpolation domain. That is, x(end) is so to speek an unknown too.
The value of the objective function is a pde residual and to compute it, the spline needs to be evaluated at certain points which can change during iterations. In the toy code below, I mock this by shrinking the interpolation domain over the iterations. For example, when fmincon does the last iteration, the spline was only evaluated at points xq in [0, 6] and the initial guess for the interpolation domain (x = linspace(3, 10, 5)) is not good anymore because the interpolation values defined at x > 6 have not been activated in the forward solve. As a consequence, no meaningful parameters are assigned at points x > 6.
So far, I did a multi-stage optimization: Optimizing with fixed points x, checking the final evaluation points, refining the points, optimizing again, etc. But this is very costly.
My ideas are the following:
Changing the interpolation points in some iterations (if required): At iteration k, the sampled points xq are in [0, 5]. So the initial points (x = linspace(3, 10, 5)) are changed to x = linspace(3, 5, 5)) in the next iteration. With this strategy I am keeping the number of parameters constant (there is probably no chance to dynamically change the number of parameters for any solver?) I am not sure if this violates differentiability assumptions of the solvers.
Since I really know x(end) roughly only, I may treat it as an unknown too. So the new parameter vector represents [y; x(end)]. However, in this strategy I want to guide the optimizer (via a penalty or so) in a way that it moves the current x(end) to the current active region. What I can do for instance is to compute the min/max of the evaluation points in every iteration. But I am not sure how to translate this into a penalty term since the min/max evaluation points are not constants.
Can you think of smarter ways to handle this? Maybe spline fit with unknown domain is a known problem.
% Define initial parameters
x = linspace(3, 10, 5); % Interpolation points
y0 = rand(size(x)); % Initial interpolation values
% Define optimization problem
options = optimoptions(‘fmincon’, ‘OutputFcn’, @output_function); % Track iteration count
% Call fmincon optimizer
global iter_count;
iter_count = 0; % Iteration counter
[y_opt, fval] = fmincon(@objective_func, y0, [], [], [], [], [], [], [], options);
% Display results
fprintf(‘Optimized objective function value: %.4fn’, fval);
fprintf(‘Optimized spline values: [%s]n’, num2str(y_opt, ‘%.2f ‘));
function obj_val = objective_func(y)
global iter_count;
% Re-compute interpolation points
x = linspace(3, 10, numel(y));
% Create spline f
f = spapi(4, x, y);
% Mock shrinking of evaluation domain
shrink_factor = 1 – exp(-0.1 * iter_count); % Exponential decay
shrinked_domain = 5 + (10 – 5) * (1 – shrink_factor); % Starts at 10, slowly shrinks to 5
xq = linspace(3, shrinked_domain, 10); % PDE evaluation points
% Evaluate the spline at xq
spline_values = fnval(f, xq);
% Compute mock PDE residual (sum of squared differences)
obj_val = sum((spline_values – mean(spline_values)).^2);
% Debug print
% fprintf(‘Iter %d – Eval points: [%s]n’, iter_count, num2str(xq, ‘%.2f ‘));
end
function stop = output_function(~, ~, state)
global iter_count;
if strcmp(state, ‘iter’)
iter_count = iter_count + 1; % Update iteration count
end
stop = false; % Continue optimization
endI want to fit the interpolation values of a spline, but I can not provide a good guess for the upper bound of the interpolation domain. That is, x(end) is so to speek an unknown too.
The value of the objective function is a pde residual and to compute it, the spline needs to be evaluated at certain points which can change during iterations. In the toy code below, I mock this by shrinking the interpolation domain over the iterations. For example, when fmincon does the last iteration, the spline was only evaluated at points xq in [0, 6] and the initial guess for the interpolation domain (x = linspace(3, 10, 5)) is not good anymore because the interpolation values defined at x > 6 have not been activated in the forward solve. As a consequence, no meaningful parameters are assigned at points x > 6.
So far, I did a multi-stage optimization: Optimizing with fixed points x, checking the final evaluation points, refining the points, optimizing again, etc. But this is very costly.
My ideas are the following:
Changing the interpolation points in some iterations (if required): At iteration k, the sampled points xq are in [0, 5]. So the initial points (x = linspace(3, 10, 5)) are changed to x = linspace(3, 5, 5)) in the next iteration. With this strategy I am keeping the number of parameters constant (there is probably no chance to dynamically change the number of parameters for any solver?) I am not sure if this violates differentiability assumptions of the solvers.
Since I really know x(end) roughly only, I may treat it as an unknown too. So the new parameter vector represents [y; x(end)]. However, in this strategy I want to guide the optimizer (via a penalty or so) in a way that it moves the current x(end) to the current active region. What I can do for instance is to compute the min/max of the evaluation points in every iteration. But I am not sure how to translate this into a penalty term since the min/max evaluation points are not constants.
Can you think of smarter ways to handle this? Maybe spline fit with unknown domain is a known problem.
% Define initial parameters
x = linspace(3, 10, 5); % Interpolation points
y0 = rand(size(x)); % Initial interpolation values
% Define optimization problem
options = optimoptions(‘fmincon’, ‘OutputFcn’, @output_function); % Track iteration count
% Call fmincon optimizer
global iter_count;
iter_count = 0; % Iteration counter
[y_opt, fval] = fmincon(@objective_func, y0, [], [], [], [], [], [], [], options);
% Display results
fprintf(‘Optimized objective function value: %.4fn’, fval);
fprintf(‘Optimized spline values: [%s]n’, num2str(y_opt, ‘%.2f ‘));
function obj_val = objective_func(y)
global iter_count;
% Re-compute interpolation points
x = linspace(3, 10, numel(y));
% Create spline f
f = spapi(4, x, y);
% Mock shrinking of evaluation domain
shrink_factor = 1 – exp(-0.1 * iter_count); % Exponential decay
shrinked_domain = 5 + (10 – 5) * (1 – shrink_factor); % Starts at 10, slowly shrinks to 5
xq = linspace(3, shrinked_domain, 10); % PDE evaluation points
% Evaluate the spline at xq
spline_values = fnval(f, xq);
% Compute mock PDE residual (sum of squared differences)
obj_val = sum((spline_values – mean(spline_values)).^2);
% Debug print
% fprintf(‘Iter %d – Eval points: [%s]n’, iter_count, num2str(xq, ‘%.2f ‘));
end
function stop = output_function(~, ~, state)
global iter_count;
if strcmp(state, ‘iter’)
iter_count = iter_count + 1; % Update iteration count
end
stop = false; % Continue optimization
end I want to fit the interpolation values of a spline, but I can not provide a good guess for the upper bound of the interpolation domain. That is, x(end) is so to speek an unknown too.
The value of the objective function is a pde residual and to compute it, the spline needs to be evaluated at certain points which can change during iterations. In the toy code below, I mock this by shrinking the interpolation domain over the iterations. For example, when fmincon does the last iteration, the spline was only evaluated at points xq in [0, 6] and the initial guess for the interpolation domain (x = linspace(3, 10, 5)) is not good anymore because the interpolation values defined at x > 6 have not been activated in the forward solve. As a consequence, no meaningful parameters are assigned at points x > 6.
So far, I did a multi-stage optimization: Optimizing with fixed points x, checking the final evaluation points, refining the points, optimizing again, etc. But this is very costly.
My ideas are the following:
Changing the interpolation points in some iterations (if required): At iteration k, the sampled points xq are in [0, 5]. So the initial points (x = linspace(3, 10, 5)) are changed to x = linspace(3, 5, 5)) in the next iteration. With this strategy I am keeping the number of parameters constant (there is probably no chance to dynamically change the number of parameters for any solver?) I am not sure if this violates differentiability assumptions of the solvers.
Since I really know x(end) roughly only, I may treat it as an unknown too. So the new parameter vector represents [y; x(end)]. However, in this strategy I want to guide the optimizer (via a penalty or so) in a way that it moves the current x(end) to the current active region. What I can do for instance is to compute the min/max of the evaluation points in every iteration. But I am not sure how to translate this into a penalty term since the min/max evaluation points are not constants.
Can you think of smarter ways to handle this? Maybe spline fit with unknown domain is a known problem.
% Define initial parameters
x = linspace(3, 10, 5); % Interpolation points
y0 = rand(size(x)); % Initial interpolation values
% Define optimization problem
options = optimoptions(‘fmincon’, ‘OutputFcn’, @output_function); % Track iteration count
% Call fmincon optimizer
global iter_count;
iter_count = 0; % Iteration counter
[y_opt, fval] = fmincon(@objective_func, y0, [], [], [], [], [], [], [], options);
% Display results
fprintf(‘Optimized objective function value: %.4fn’, fval);
fprintf(‘Optimized spline values: [%s]n’, num2str(y_opt, ‘%.2f ‘));
function obj_val = objective_func(y)
global iter_count;
% Re-compute interpolation points
x = linspace(3, 10, numel(y));
% Create spline f
f = spapi(4, x, y);
% Mock shrinking of evaluation domain
shrink_factor = 1 – exp(-0.1 * iter_count); % Exponential decay
shrinked_domain = 5 + (10 – 5) * (1 – shrink_factor); % Starts at 10, slowly shrinks to 5
xq = linspace(3, shrinked_domain, 10); % PDE evaluation points
% Evaluate the spline at xq
spline_values = fnval(f, xq);
% Compute mock PDE residual (sum of squared differences)
obj_val = sum((spline_values – mean(spline_values)).^2);
% Debug print
% fprintf(‘Iter %d – Eval points: [%s]n’, iter_count, num2str(xq, ‘%.2f ‘));
end
function stop = output_function(~, ~, state)
global iter_count;
if strcmp(state, ‘iter’)
iter_count = iter_count + 1; % Update iteration count
end
stop = false; % Continue optimization
end optimization, fmincon, spline, lsqnonlin MATLAB Answers — New Questions
WHY ITS TAKING TIME TO LAUNCH MATLAB EXE FILE IN VISUAL STUDIO C++?
I HAVE CREATED MATLAB EXE FILE TO CONTROL ON VVISUAL STUDIO BUT THE CODE WHICH IS TAKING 8 SEC IS TAKING 20 SEC WHEN WE CALL THROUGH EXE FILE . BUT WHEN WE KEEP THE TIMER IN MATLAB EXE CODE ITS SHOWING 9-10 SEC THAT MEANS ITS TAKING NEARLY 10 SEC TO LAUNCH . IAM GIVING INPUT FROM VISUAL STUDIO TO MATLLAB EXE FILE AND EXTRACTING OUTPUT FROM MATLAB EXE FILE TO VISUAL STUDIO. IS THERE ANY WAY TO SOLVE THIS ISSUSE ? IS THERE ANY WAY TO REDUCE THE LAUNCH TIME BY MATLAB EXE FILEI HAVE CREATED MATLAB EXE FILE TO CONTROL ON VVISUAL STUDIO BUT THE CODE WHICH IS TAKING 8 SEC IS TAKING 20 SEC WHEN WE CALL THROUGH EXE FILE . BUT WHEN WE KEEP THE TIMER IN MATLAB EXE CODE ITS SHOWING 9-10 SEC THAT MEANS ITS TAKING NEARLY 10 SEC TO LAUNCH . IAM GIVING INPUT FROM VISUAL STUDIO TO MATLLAB EXE FILE AND EXTRACTING OUTPUT FROM MATLAB EXE FILE TO VISUAL STUDIO. IS THERE ANY WAY TO SOLVE THIS ISSUSE ? IS THERE ANY WAY TO REDUCE THE LAUNCH TIME BY MATLAB EXE FILE I HAVE CREATED MATLAB EXE FILE TO CONTROL ON VVISUAL STUDIO BUT THE CODE WHICH IS TAKING 8 SEC IS TAKING 20 SEC WHEN WE CALL THROUGH EXE FILE . BUT WHEN WE KEEP THE TIMER IN MATLAB EXE CODE ITS SHOWING 9-10 SEC THAT MEANS ITS TAKING NEARLY 10 SEC TO LAUNCH . IAM GIVING INPUT FROM VISUAL STUDIO TO MATLLAB EXE FILE AND EXTRACTING OUTPUT FROM MATLAB EXE FILE TO VISUAL STUDIO. IS THERE ANY WAY TO SOLVE THIS ISSUSE ? IS THERE ANY WAY TO REDUCE THE LAUNCH TIME BY MATLAB EXE FILE application compiler, matlab compiler, c++ MATLAB Answers — New Questions
Plot multiple values in a single bar in bar plot
Lets say I have an array y1 = [1,3,5,7,9] and y2 = [2,4,6,8,10]. I want to make a barplot between these two where its a single bar for each. So bar for y1 goes to max value 9 but in the same bar i can see values 1,3,5 and 7 and similarily y2 bar goes to max value 10 but can see values 2,4,6 and 8. And they are both shown in the same position for x axis that is x = 1. How can I do this. It has to be a bar plot and not normal plot. Thank you.Lets say I have an array y1 = [1,3,5,7,9] and y2 = [2,4,6,8,10]. I want to make a barplot between these two where its a single bar for each. So bar for y1 goes to max value 9 but in the same bar i can see values 1,3,5 and 7 and similarily y2 bar goes to max value 10 but can see values 2,4,6 and 8. And they are both shown in the same position for x axis that is x = 1. How can I do this. It has to be a bar plot and not normal plot. Thank you. Lets say I have an array y1 = [1,3,5,7,9] and y2 = [2,4,6,8,10]. I want to make a barplot between these two where its a single bar for each. So bar for y1 goes to max value 9 but in the same bar i can see values 1,3,5 and 7 and similarily y2 bar goes to max value 10 but can see values 2,4,6 and 8. And they are both shown in the same position for x axis that is x = 1. How can I do this. It has to be a bar plot and not normal plot. Thank you. matlab MATLAB Answers — New Questions
Avoid negative sign with compose() when output is zero, e.g. ‘-0’ or ‘-0.0’
When compose outputs zero, it includes a negative sign if the number was negative, giving, e.g. -0 or -0.0. How can I avoid this? (Other than writing another function that does a string compare for every element output by compose and removes the negative sign if there are only zeros.)
num = -0.04;
compose(‘%.1f’, num)When compose outputs zero, it includes a negative sign if the number was negative, giving, e.g. -0 or -0.0. How can I avoid this? (Other than writing another function that does a string compare for every element output by compose and removes the negative sign if there are only zeros.)
num = -0.04;
compose(‘%.1f’, num) When compose outputs zero, it includes a negative sign if the number was negative, giving, e.g. -0 or -0.0. How can I avoid this? (Other than writing another function that does a string compare for every element output by compose and removes the negative sign if there are only zeros.)
num = -0.04;
compose(‘%.1f’, num) compose, round, rounding, negative, zero MATLAB Answers — New Questions
Is an SGP4 propagator provided with “Orbit Propagator” block in Simulink (Aerospace Blockset)
Hi All;
This question may be quite obvious (or perhaps trivial) but I am unable to find a standard SGP4 propagator offered by Orbit Propagator block in Aerospace Blockset. It seems there are commands that can be used in MATLAB, however I am trying to use the Simulink / Orbit Propagator. One would expect to see this option in the drop down menu "Main –> Propagation Methood" and then in the drop down (among "Numerical", "Kepler") select "SGP4" (which is not there) followed by a TLE entry box.
Can you let me know, if "SGP4" propagation is possible with this block?
Thanks
GökhanHi All;
This question may be quite obvious (or perhaps trivial) but I am unable to find a standard SGP4 propagator offered by Orbit Propagator block in Aerospace Blockset. It seems there are commands that can be used in MATLAB, however I am trying to use the Simulink / Orbit Propagator. One would expect to see this option in the drop down menu "Main –> Propagation Methood" and then in the drop down (among "Numerical", "Kepler") select "SGP4" (which is not there) followed by a TLE entry box.
Can you let me know, if "SGP4" propagation is possible with this block?
Thanks
Gökhan Hi All;
This question may be quite obvious (or perhaps trivial) but I am unable to find a standard SGP4 propagator offered by Orbit Propagator block in Aerospace Blockset. It seems there are commands that can be used in MATLAB, however I am trying to use the Simulink / Orbit Propagator. One would expect to see this option in the drop down menu "Main –> Propagation Methood" and then in the drop down (among "Numerical", "Kepler") select "SGP4" (which is not there) followed by a TLE entry box.
Can you let me know, if "SGP4" propagation is possible with this block?
Thanks
Gökhan sgp4, propagator, simulink MATLAB Answers — New Questions
Homework help.
You are given a data set (data2.mat) that must be fit to an equation for your lab assignment. You know that the data has the form y = a *e^bx^c . Find the coefficients a, b and c using a MATLAB function that you have written. Display a plot with a logarithmic y scale that shows the data as points and the line as a fit.
Can anyone help me figure this out. I tried using an exponential function program that used linear regression program in it but that didn’t work because it didn’t deal with the double power factor. So I really don’t know how to go about solving this. I’m in a matlab class for the first time and it’s week 3 and he’s dropping these sort of things on after not really teaching us how to do this. He clearly knows his stuff but he’s very bad at reiterating it to his students so we end up lost all the time. Any help would be great!
here’s the data
5.1000000e+001 -9.8614120e+000
4.0800000e+002 -9.3766162e+000
1.3770000e+003 -9.4949558e+000
3.2640000e+003 -9.2442098e+000
6.3750000e+003 -9.0007595e+000
1.1016000e+004 -8.8766913e+000
1.7493000e+004 -9.0074649e+000
2.6112000e+004 -8.9332435e+000
3.7179000e+004 -8.8126032e+000
5.1000000e+004 -8.8844865e+000
6.7881000e+004 -8.7144287e+000
8.8128000e+004 -8.3825442e+000
1.1204700e+005 -8.4576726e+000
1.3994400e+005 -8.5157210e+000
1.7212500e+005 -8.4781113e+000
2.0889600e+005 -8.2878923e+000
2.5056300e+005 -8.3766055e+000
2.9743200e+005 -8.2561491e+000
3.4980900e+005 -8.2137268e+000
4.0800000e+005 -8.0925150e+000
4.7231100e+005 -7.9257422e+000
5.4304800e+005 -7.9381544e+000
6.2051700e+005 -7.9537322e+000
7.0502400e+005 -7.8015010e+000
7.9687500e+005 -7.8356798e+000
8.9637600e+005 -7.6697667e+000
1.0038330e+006 -7.5605739e+000
1.1195520e+006 -7.8521843e+000
1.2438390e+006 -7.6577670e+000
1.3770000e+006 -7.6843260e+000
1.5193410e+006 -7.4819766e+000
1.6711680e+006 -7.4679223e+000
1.8327870e+006 -7.3088850e+000
2.0045040e+006 -7.3311661e+000
2.1866250e+006 -7.2934343e+000
2.3794560e+006 -7.1592624e+000
2.5833030e+006 -7.2461091e+000
2.7984720e+006 -7.0129888e+000
3.0252690e+006 -7.0599327e+000
3.2640000e+006 -6.9684428e+000
3.5149710e+006 -6.7472645e+000
3.7784880e+006 -6.8237334e+000
4.0548570e+006 -6.9460063e+000
4.3443840e+006 -6.8844682e+000
4.6473750e+006 -6.8276870e+000
4.9641360e+006 -6.7922145e+000
5.2949730e+006 -6.8443137e+000
5.6401920e+006 -6.7642609e+000
6.0000990e+006 -6.7283737e+000
6.3750000e+006 -6.5985129e+000
6.7652010e+006 -6.8035724e+000
7.1710080e+006 -6.6019244e+000
7.5927270e+006 -6.5038275e+000
8.0306640e+006 -6.5811262e+000
8.4851250e+006 -6.3259601e+000
8.9564160e+006 -6.6594903e+000
9.4448430e+006 -6.2945521e+000
9.9507120e+006 -6.3241126e+000
1.0474329e+007 -6.2211186e+000
1.1016000e+007 -6.2944763e+000
1.1576031e+007 -6.1571240e+000
1.2154728e+007 -6.0425808e+000
1.2752397e+007 -6.2450068e+000
1.3369344e+007 -6.0584327e+000
1.4005875e+007 -6.0119037e+000
1.4662296e+007 -5.9192135e+000
1.5338913e+007 -6.0227574e+000
1.6036032e+007 -5.9185951e+000
1.6753959e+007 -6.0416041e+000
1.7493000e+007 -5.8492313e+000
1.8253461e+007 -6.0539742e+000
1.9035648e+007 -5.8733411e+000
1.9839867e+007 -5.8752898e+000
2.0666424e+007 -5.7343361e+000
2.1515625e+007 -5.8322730e+000
2.2387776e+007 -5.7831574e+000
2.3283183e+007 -5.5679345e+000
2.4202152e+007 -5.6356530e+000
2.5144989e+007 -5.7559464e+000
2.6112000e+007 -5.7025321e+000
2.7103491e+007 -5.6388418e+000
2.8119768e+007 -5.6041841e+000
2.9161137e+007 -5.4867117e+000
3.0227904e+007 -5.4993242e+000
3.1320375e+007 -5.6516519e+000
3.2438856e+007 -5.4882504e+000
3.3583653e+007 -5.5297368e+000
3.4755072e+007 -5.3379112e+000
3.5953419e+007 -5.2417512e+000
3.7179000e+007 -5.1143483e+000
3.8432121e+007 -5.2538556e+000
3.9713088e+007 -5.2262771e+000
4.1022207e+007 -5.1662034e+000
4.2359784e+007 -5.2907350e+000
4.3726125e+007 -5.1033225e+000
4.5121536e+007 -5.0992933e+000
4.6546323e+007 -5.2062895e+000
4.8000792e+007 -5.1410342e+000
4.9485249e+007 -5.0594874e+000
5.1000000e+007 -5.1098396e+000You are given a data set (data2.mat) that must be fit to an equation for your lab assignment. You know that the data has the form y = a *e^bx^c . Find the coefficients a, b and c using a MATLAB function that you have written. Display a plot with a logarithmic y scale that shows the data as points and the line as a fit.
Can anyone help me figure this out. I tried using an exponential function program that used linear regression program in it but that didn’t work because it didn’t deal with the double power factor. So I really don’t know how to go about solving this. I’m in a matlab class for the first time and it’s week 3 and he’s dropping these sort of things on after not really teaching us how to do this. He clearly knows his stuff but he’s very bad at reiterating it to his students so we end up lost all the time. Any help would be great!
here’s the data
5.1000000e+001 -9.8614120e+000
4.0800000e+002 -9.3766162e+000
1.3770000e+003 -9.4949558e+000
3.2640000e+003 -9.2442098e+000
6.3750000e+003 -9.0007595e+000
1.1016000e+004 -8.8766913e+000
1.7493000e+004 -9.0074649e+000
2.6112000e+004 -8.9332435e+000
3.7179000e+004 -8.8126032e+000
5.1000000e+004 -8.8844865e+000
6.7881000e+004 -8.7144287e+000
8.8128000e+004 -8.3825442e+000
1.1204700e+005 -8.4576726e+000
1.3994400e+005 -8.5157210e+000
1.7212500e+005 -8.4781113e+000
2.0889600e+005 -8.2878923e+000
2.5056300e+005 -8.3766055e+000
2.9743200e+005 -8.2561491e+000
3.4980900e+005 -8.2137268e+000
4.0800000e+005 -8.0925150e+000
4.7231100e+005 -7.9257422e+000
5.4304800e+005 -7.9381544e+000
6.2051700e+005 -7.9537322e+000
7.0502400e+005 -7.8015010e+000
7.9687500e+005 -7.8356798e+000
8.9637600e+005 -7.6697667e+000
1.0038330e+006 -7.5605739e+000
1.1195520e+006 -7.8521843e+000
1.2438390e+006 -7.6577670e+000
1.3770000e+006 -7.6843260e+000
1.5193410e+006 -7.4819766e+000
1.6711680e+006 -7.4679223e+000
1.8327870e+006 -7.3088850e+000
2.0045040e+006 -7.3311661e+000
2.1866250e+006 -7.2934343e+000
2.3794560e+006 -7.1592624e+000
2.5833030e+006 -7.2461091e+000
2.7984720e+006 -7.0129888e+000
3.0252690e+006 -7.0599327e+000
3.2640000e+006 -6.9684428e+000
3.5149710e+006 -6.7472645e+000
3.7784880e+006 -6.8237334e+000
4.0548570e+006 -6.9460063e+000
4.3443840e+006 -6.8844682e+000
4.6473750e+006 -6.8276870e+000
4.9641360e+006 -6.7922145e+000
5.2949730e+006 -6.8443137e+000
5.6401920e+006 -6.7642609e+000
6.0000990e+006 -6.7283737e+000
6.3750000e+006 -6.5985129e+000
6.7652010e+006 -6.8035724e+000
7.1710080e+006 -6.6019244e+000
7.5927270e+006 -6.5038275e+000
8.0306640e+006 -6.5811262e+000
8.4851250e+006 -6.3259601e+000
8.9564160e+006 -6.6594903e+000
9.4448430e+006 -6.2945521e+000
9.9507120e+006 -6.3241126e+000
1.0474329e+007 -6.2211186e+000
1.1016000e+007 -6.2944763e+000
1.1576031e+007 -6.1571240e+000
1.2154728e+007 -6.0425808e+000
1.2752397e+007 -6.2450068e+000
1.3369344e+007 -6.0584327e+000
1.4005875e+007 -6.0119037e+000
1.4662296e+007 -5.9192135e+000
1.5338913e+007 -6.0227574e+000
1.6036032e+007 -5.9185951e+000
1.6753959e+007 -6.0416041e+000
1.7493000e+007 -5.8492313e+000
1.8253461e+007 -6.0539742e+000
1.9035648e+007 -5.8733411e+000
1.9839867e+007 -5.8752898e+000
2.0666424e+007 -5.7343361e+000
2.1515625e+007 -5.8322730e+000
2.2387776e+007 -5.7831574e+000
2.3283183e+007 -5.5679345e+000
2.4202152e+007 -5.6356530e+000
2.5144989e+007 -5.7559464e+000
2.6112000e+007 -5.7025321e+000
2.7103491e+007 -5.6388418e+000
2.8119768e+007 -5.6041841e+000
2.9161137e+007 -5.4867117e+000
3.0227904e+007 -5.4993242e+000
3.1320375e+007 -5.6516519e+000
3.2438856e+007 -5.4882504e+000
3.3583653e+007 -5.5297368e+000
3.4755072e+007 -5.3379112e+000
3.5953419e+007 -5.2417512e+000
3.7179000e+007 -5.1143483e+000
3.8432121e+007 -5.2538556e+000
3.9713088e+007 -5.2262771e+000
4.1022207e+007 -5.1662034e+000
4.2359784e+007 -5.2907350e+000
4.3726125e+007 -5.1033225e+000
4.5121536e+007 -5.0992933e+000
4.6546323e+007 -5.2062895e+000
4.8000792e+007 -5.1410342e+000
4.9485249e+007 -5.0594874e+000
5.1000000e+007 -5.1098396e+000 You are given a data set (data2.mat) that must be fit to an equation for your lab assignment. You know that the data has the form y = a *e^bx^c . Find the coefficients a, b and c using a MATLAB function that you have written. Display a plot with a logarithmic y scale that shows the data as points and the line as a fit.
Can anyone help me figure this out. I tried using an exponential function program that used linear regression program in it but that didn’t work because it didn’t deal with the double power factor. So I really don’t know how to go about solving this. I’m in a matlab class for the first time and it’s week 3 and he’s dropping these sort of things on after not really teaching us how to do this. He clearly knows his stuff but he’s very bad at reiterating it to his students so we end up lost all the time. Any help would be great!
here’s the data
5.1000000e+001 -9.8614120e+000
4.0800000e+002 -9.3766162e+000
1.3770000e+003 -9.4949558e+000
3.2640000e+003 -9.2442098e+000
6.3750000e+003 -9.0007595e+000
1.1016000e+004 -8.8766913e+000
1.7493000e+004 -9.0074649e+000
2.6112000e+004 -8.9332435e+000
3.7179000e+004 -8.8126032e+000
5.1000000e+004 -8.8844865e+000
6.7881000e+004 -8.7144287e+000
8.8128000e+004 -8.3825442e+000
1.1204700e+005 -8.4576726e+000
1.3994400e+005 -8.5157210e+000
1.7212500e+005 -8.4781113e+000
2.0889600e+005 -8.2878923e+000
2.5056300e+005 -8.3766055e+000
2.9743200e+005 -8.2561491e+000
3.4980900e+005 -8.2137268e+000
4.0800000e+005 -8.0925150e+000
4.7231100e+005 -7.9257422e+000
5.4304800e+005 -7.9381544e+000
6.2051700e+005 -7.9537322e+000
7.0502400e+005 -7.8015010e+000
7.9687500e+005 -7.8356798e+000
8.9637600e+005 -7.6697667e+000
1.0038330e+006 -7.5605739e+000
1.1195520e+006 -7.8521843e+000
1.2438390e+006 -7.6577670e+000
1.3770000e+006 -7.6843260e+000
1.5193410e+006 -7.4819766e+000
1.6711680e+006 -7.4679223e+000
1.8327870e+006 -7.3088850e+000
2.0045040e+006 -7.3311661e+000
2.1866250e+006 -7.2934343e+000
2.3794560e+006 -7.1592624e+000
2.5833030e+006 -7.2461091e+000
2.7984720e+006 -7.0129888e+000
3.0252690e+006 -7.0599327e+000
3.2640000e+006 -6.9684428e+000
3.5149710e+006 -6.7472645e+000
3.7784880e+006 -6.8237334e+000
4.0548570e+006 -6.9460063e+000
4.3443840e+006 -6.8844682e+000
4.6473750e+006 -6.8276870e+000
4.9641360e+006 -6.7922145e+000
5.2949730e+006 -6.8443137e+000
5.6401920e+006 -6.7642609e+000
6.0000990e+006 -6.7283737e+000
6.3750000e+006 -6.5985129e+000
6.7652010e+006 -6.8035724e+000
7.1710080e+006 -6.6019244e+000
7.5927270e+006 -6.5038275e+000
8.0306640e+006 -6.5811262e+000
8.4851250e+006 -6.3259601e+000
8.9564160e+006 -6.6594903e+000
9.4448430e+006 -6.2945521e+000
9.9507120e+006 -6.3241126e+000
1.0474329e+007 -6.2211186e+000
1.1016000e+007 -6.2944763e+000
1.1576031e+007 -6.1571240e+000
1.2154728e+007 -6.0425808e+000
1.2752397e+007 -6.2450068e+000
1.3369344e+007 -6.0584327e+000
1.4005875e+007 -6.0119037e+000
1.4662296e+007 -5.9192135e+000
1.5338913e+007 -6.0227574e+000
1.6036032e+007 -5.9185951e+000
1.6753959e+007 -6.0416041e+000
1.7493000e+007 -5.8492313e+000
1.8253461e+007 -6.0539742e+000
1.9035648e+007 -5.8733411e+000
1.9839867e+007 -5.8752898e+000
2.0666424e+007 -5.7343361e+000
2.1515625e+007 -5.8322730e+000
2.2387776e+007 -5.7831574e+000
2.3283183e+007 -5.5679345e+000
2.4202152e+007 -5.6356530e+000
2.5144989e+007 -5.7559464e+000
2.6112000e+007 -5.7025321e+000
2.7103491e+007 -5.6388418e+000
2.8119768e+007 -5.6041841e+000
2.9161137e+007 -5.4867117e+000
3.0227904e+007 -5.4993242e+000
3.1320375e+007 -5.6516519e+000
3.2438856e+007 -5.4882504e+000
3.3583653e+007 -5.5297368e+000
3.4755072e+007 -5.3379112e+000
3.5953419e+007 -5.2417512e+000
3.7179000e+007 -5.1143483e+000
3.8432121e+007 -5.2538556e+000
3.9713088e+007 -5.2262771e+000
4.1022207e+007 -5.1662034e+000
4.2359784e+007 -5.2907350e+000
4.3726125e+007 -5.1033225e+000
4.5121536e+007 -5.0992933e+000
4.6546323e+007 -5.2062895e+000
4.8000792e+007 -5.1410342e+000
4.9485249e+007 -5.0594874e+000
5.1000000e+007 -5.1098396e+000 linear regression, exponential, homework MATLAB Answers — New Questions
A new level unlocked
Today Microsoft released Muse, a first-of-its-kind generative AI model that we are applying to gaming. But it’s so much more than that. What we’re sharing today is a huge step forward for gameplay ideation. And what’s even more exciting is what this breakthrough represents in our journey of building and using generative AI, and what industries, developers and creators of all interests will be enabled to do next.
The impressive abilities we first witnessed with ChatGPT and GPT-4 to learn human language are now being matched by AI’s abilities to learn the mechanics of how things work, in effect developing a practical understanding of interactions in the world. As a computer scientist, this ability to understand and model a 3D world is something I and many other great researchers have pursued for over 10 years and, personally, I was not sure that it could be made possible with such speed and quality.
In the case of Muse, just from observing human gameplay, this model develops a deep understanding of the environment, including its dynamics and how it evolves over time in response to actions. This unlocks the ability to rapidly iterate, remix and create in video games so developers can eventually create immersive environments and unleash their full creativity.
Beyond gaming, I’m excited by the potential of this capability to enable AI assistants that understand and help visualize things, from reconfiguring the kitchen in your home to redesigning a retail space to building a digital twin of a factory floor to test and explore different scenarios. All these things are just now becoming possible with AI. From the perspective of computer science research, it’s pretty amazing, and the future applications of this are likely to be transformative for creators.
—
At Microsoft, we have a long history of collaboration between research and engineering. Today, as we release Muse, we are also announcing Azure AI Foundry Labs, where the AI community can explore the latest from Microsoft Research. Azure AI Foundry Labs will help accelerate the transition from research to solutions, bringing new ideas to the broader community to help shape the future of AI. Learn more.
The post A new level unlocked appeared first on The Official Microsoft Blog.
Today Microsoft released Muse, a first-of-its-kind generative AI model that we are applying to gaming. But it’s so much more than that. What we’re sharing today is a huge step forward for gameplay ideation. And what’s even more exciting is what this breakthrough represents in our journey of building and using generative AI, and what industries,…
The post A new level unlocked appeared first on The Official Microsoft Blog.Read More
Microsoft unveils Majorana 1
Satya Nadella, Chairman and CEO, shared the below communication on social media this morning.
The post Microsoft unveils Majorana 1 appeared first on The Official Microsoft Blog.
Satya Nadella, Chairman and CEO, shared the below communication on social media this morning. Click here to load media
The post Microsoft unveils Majorana 1 appeared first on The Official Microsoft Blog.Read More
3-phase inverter thermal modeling
All,
I’m looking for some regarding inverter thermal modeling with matlab/simulink/simcape – I just found pmsm with thermal model but not inverter thermally modelled, or ThreePhaseDiodeRectifierModel – is there any resources on two level 3-phase inverter modelling?All,
I’m looking for some regarding inverter thermal modeling with matlab/simulink/simcape – I just found pmsm with thermal model but not inverter thermally modelled, or ThreePhaseDiodeRectifierModel – is there any resources on two level 3-phase inverter modelling? All,
I’m looking for some regarding inverter thermal modeling with matlab/simulink/simcape – I just found pmsm with thermal model but not inverter thermally modelled, or ThreePhaseDiodeRectifierModel – is there any resources on two level 3-phase inverter modelling? inverter thermal modeling MATLAB Answers — New Questions
I am looking the instructions page for Online installation.
Hi
Where can I find instructions for online installation, hoping the installation nightmare ends ?
Please consider that I have already purchased the tool.
Thanks in advance.
ManolisHi
Where can I find instructions for online installation, hoping the installation nightmare ends ?
Please consider that I have already purchased the tool.
Thanks in advance.
Manolis Hi
Where can I find instructions for online installation, hoping the installation nightmare ends ?
Please consider that I have already purchased the tool.
Thanks in advance.
Manolis online installation. MATLAB Answers — New Questions
PLEASE HELP!! Matlab AppDesigner Putting a certain number of panels
Hello,
I have a problem with matlab app designer. I want to do something; when I select the amount in the list box and then click the button, that amount of panels are shown. How can I do that? I wrote function to get able to visibility of panel after push the button. But I cannot define the number of panels.
Thanks for help!
% Callbacks that handle component events
methods (Access = private)
% Code that executes after component creation
function startupFcn(app)
app.Panel.Visible = "off";
end
% Callback function
function ButtonGroupSelectionChange(app, event)
end
% Button pushed function: Button
function ButtonPushed(app, event)
app.Panel.Visible="on";
end
endHello,
I have a problem with matlab app designer. I want to do something; when I select the amount in the list box and then click the button, that amount of panels are shown. How can I do that? I wrote function to get able to visibility of panel after push the button. But I cannot define the number of panels.
Thanks for help!
% Callbacks that handle component events
methods (Access = private)
% Code that executes after component creation
function startupFcn(app)
app.Panel.Visible = "off";
end
% Callback function
function ButtonGroupSelectionChange(app, event)
end
% Button pushed function: Button
function ButtonPushed(app, event)
app.Panel.Visible="on";
end
end Hello,
I have a problem with matlab app designer. I want to do something; when I select the amount in the list box and then click the button, that amount of panels are shown. How can I do that? I wrote function to get able to visibility of panel after push the button. But I cannot define the number of panels.
Thanks for help!
% Callbacks that handle component events
methods (Access = private)
% Code that executes after component creation
function startupFcn(app)
app.Panel.Visible = "off";
end
% Callback function
function ButtonGroupSelectionChange(app, event)
end
% Button pushed function: Button
function ButtonPushed(app, event)
app.Panel.Visible="on";
end
end matlab app designer, app, button, push, panel, list, design, visibility MATLAB Answers — New Questions
Unsolved external symbol in C++ interface build
I have a C++ function which I can load on MATLAB with
loadlibrary(‘nc_driver_x64’)
and this works without problem using calllib.
On the other hand, if I try to create interface of the same function like this
clibgen.generateLibraryDefinition(fullfile(workPath,’nc_driver_x64.h’),…
"IncludePath", workPath,…
"Libraries", {fullfile(workPath,’nc_driver_x64.lib’), fullfile(workPath,’nc_driver_x64.dll’)},…
"Verbose",true)
It generates definenc_driver_x64.m and definenc_driver_x64.mlx, but then
build(definenc_driver_x64)
returns nc_driver_x64Interface.obj : error LNK2019: on all functions in this file.
.h, .lib and .dll files are all in the same folder and running on R2021b
I really appreciate if you could point out what I should check to make this work!I have a C++ function which I can load on MATLAB with
loadlibrary(‘nc_driver_x64’)
and this works without problem using calllib.
On the other hand, if I try to create interface of the same function like this
clibgen.generateLibraryDefinition(fullfile(workPath,’nc_driver_x64.h’),…
"IncludePath", workPath,…
"Libraries", {fullfile(workPath,’nc_driver_x64.lib’), fullfile(workPath,’nc_driver_x64.dll’)},…
"Verbose",true)
It generates definenc_driver_x64.m and definenc_driver_x64.mlx, but then
build(definenc_driver_x64)
returns nc_driver_x64Interface.obj : error LNK2019: on all functions in this file.
.h, .lib and .dll files are all in the same folder and running on R2021b
I really appreciate if you could point out what I should check to make this work! I have a C++ function which I can load on MATLAB with
loadlibrary(‘nc_driver_x64’)
and this works without problem using calllib.
On the other hand, if I try to create interface of the same function like this
clibgen.generateLibraryDefinition(fullfile(workPath,’nc_driver_x64.h’),…
"IncludePath", workPath,…
"Libraries", {fullfile(workPath,’nc_driver_x64.lib’), fullfile(workPath,’nc_driver_x64.dll’)},…
"Verbose",true)
It generates definenc_driver_x64.m and definenc_driver_x64.mlx, but then
build(definenc_driver_x64)
returns nc_driver_x64Interface.obj : error LNK2019: on all functions in this file.
.h, .lib and .dll files are all in the same folder and running on R2021b
I really appreciate if you could point out what I should check to make this work! clibgen MATLAB Answers — New Questions
Too many input arguments
clear all; close all;
syms k
z0=2; r=0.01; K=100;
t=0:20:500;
u=0.75; B=1;
H=@(r) B+r*(1+z0./K)*(u-1);
F=@(t) r*(1-z0./K)*u*t.^u;
z=(B*z0/H(r))* symsum((F(t)./H(r)).^k/gamma(k*u+1),k,0,20);
zfcn = matlabFunction(z);
figure
semilogy(zfcn(t))
grid onclear all; close all;
syms k
z0=2; r=0.01; K=100;
t=0:20:500;
u=0.75; B=1;
H=@(r) B+r*(1+z0./K)*(u-1);
F=@(t) r*(1-z0./K)*u*t.^u;
z=(B*z0/H(r))* symsum((F(t)./H(r)).^k/gamma(k*u+1),k,0,20);
zfcn = matlabFunction(z);
figure
semilogy(zfcn(t))
grid on clear all; close all;
syms k
z0=2; r=0.01; K=100;
t=0:20:500;
u=0.75; B=1;
H=@(r) B+r*(1+z0./K)*(u-1);
F=@(t) r*(1-z0./K)*u*t.^u;
z=(B*z0/H(r))* symsum((F(t)./H(r)).^k/gamma(k*u+1),k,0,20);
zfcn = matlabFunction(z);
figure
semilogy(zfcn(t))
grid on input MATLAB Answers — New Questions
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Securing containerized applications demands a multi-layered strategy that spans the entire lifecycle from development to production, a challenge Aqua has spent nearly a decade mastering. Aqua’s Container Security solution provides full lifecycle protection by identifying vulnerabilities early in the build phase, integrating acceptance gates in the CI/CD pipeline to minimize risks, and offering real-time runtime protection in production environments. With the Aqua Platform, organizations can secure container workloads across hybrid and multi-cloud environments, stop attacks as they happen, and maintain compliance, all without slowing development.Read More
How to run .net app with using matlab dll?
Hi, I’m using the matlab interface for .net 6, so I tried to do everything as stated here
https://www.mathworks.com/help/matlab/matlab_external/requirements-to-build-net-engine-programs.html#mw_bb950ae5-3428-44db-8556-ff6bad52f1ef
My project file:
My Program.cs file:
When I run application an error pops up:
So I added to my project file this:
and this happening:
What did I do wrong?Hi, I’m using the matlab interface for .net 6, so I tried to do everything as stated here
https://www.mathworks.com/help/matlab/matlab_external/requirements-to-build-net-engine-programs.html#mw_bb950ae5-3428-44db-8556-ff6bad52f1ef
My project file:
My Program.cs file:
When I run application an error pops up:
So I added to my project file this:
and this happening:
What did I do wrong? Hi, I’m using the matlab interface for .net 6, so I tried to do everything as stated here
https://www.mathworks.com/help/matlab/matlab_external/requirements-to-build-net-engine-programs.html#mw_bb950ae5-3428-44db-8556-ff6bad52f1ef
My project file:
My Program.cs file:
When I run application an error pops up:
So I added to my project file this:
and this happening:
What did I do wrong? .net, matlab, dll, path, c#, workspace MATLAB Answers — New Questions
