Hello all, I have a dataset that includes both categorical and numerical features, and I’m looking to perform clustering on it. I’ve read that Gower’s Distance (code is available) is suitable for handling mixed data types. However, I am getting an "isnan" error. How can I fix the problem? Thanks for the help.
DataSet = readtable("Test.xlsx", ‘ReadVariableNames’, true);
GowerDst = gower(DataSet);
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst);

Error using isnan
Invalid data type. Argument must be numeric, char, or logical.
Error in kmedoids (line 220)
wasnan = any(isnan(X),2);
^^^^^^^^
Error in Gower_Distance (line 9)
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst);Hello all, I have a dataset that includes both categorical and numerical features, and I’m looking to perform clustering on it. I’ve read that Gower’s Distance (code is available) is suitable for handling mixed data types. However, I am getting an "isnan" error. How can I fix the problem? Thanks for the help.
DataSet = readtable("Test.xlsx", ‘ReadVariableNames’, true);
GowerDst = gower(DataSet);
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst);

Error using isnan
Invalid data type. Argument must be numeric, char, or logical.
Error in kmedoids (line 220)
wasnan = any(isnan(X),2);
^^^^^^^^
Error in Gower_Distance (line 9)
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst); Hello all, I have a dataset that includes both categorical and numerical features, and I’m looking to perform clustering on it. I’ve read that Gower’s Distance (code is available) is suitable for handling mixed data types. However, I am getting an "isnan" error. How can I fix the problem? Thanks for the help.
DataSet = readtable("Test.xlsx", ‘ReadVariableNames’, true);
GowerDst = gower(DataSet);
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst);

Error using isnan
Invalid data type. Argument must be numeric, char, or logical.
Error in kmedoids (line 220)
wasnan = any(isnan(X),2);
^^^^^^^^
Error in Gower_Distance (line 9)
[Idx, C] = kmedoids(DataSet, 2, ‘Distance’, GowerDst); gower’s distance, clustering MATLAB Answers — New Questions

​

clear
clc
clf
%***************************************************
% constants
rad=pi/180;
eps0=8.85e-12;
mu0=4*pi*1e-7;
eta0=sqrt(mu0/eps0); % free space
c=1/sqrt(eps0*mu0);
%***************************************************
% variables
d=2.5e-3; % thickness of the sample
f1=1e9; df=9e6; f2=10e9; Nf=floor((f2-f1)/df)+1; % frequency range and
% load raw data
M1r = csvread(‘sample.dat’,4); % Read the data
P1r = csvread(‘sample1.dat’,2); % Read the data
P2r = csvread(‘sample2.dat’,2); % Read the data
Mag1=M1r(:,2);
Mag2=M1r(:,3);
Ph1=-unwrap(P1r(:,2),180);
Ph2=-unwrap(P2r(:,2),180);
%*****************************************
% freqyency loop begin
for it=1:Nf
f=f1+(it-1)*df;
Fr(it)=f;
Fghz(it)=f/1e9;
fghz=f/1e9;
Z0=eta0; W=2*pi*Fr(it); beta0=W/c;
%*******************************************
% combine magnitude and phase of the S11 and S21
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);………………………………………………..error Index exceeds matrix dimensions.
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);
T(it)=Mag2(it)*exp(j*Ph2(it)*rad);
% m loop begin
Max=0; % ———m value set up
itt=0;
for m=-Max:Max
itt=itt+1;
%***************************************************
% using formulas from Robust method
Tp=T(it);
Z21(it)=sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
Z22(it)=-sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
expinkd1(it)=Tp/(1-R(it)*(Z21(it)-1)/(Z21(it)+1));
expinkd2(it)=Tp/(1-R(it)*(Z22(it)-1)/(Z22(it)+1));
if abs(real(Z21(it)))>=0.005 & real(Z21(it))>=0
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))>=0.005 & real(Z21(it))<0
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))<=1
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))>1
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
ni(it)=-1/(beta0*d)*j*real(log(expinkd(it))); % imag of n
nr(it,itt)=1/(beta0*d)*(imag(log(expinkd(it)))+2*m*pi); %real of n
n2(it,itt)=nr(it,itt)+ni(it);
Er2(it,itt)=n2(it,itt)/Z2(it);
Mr2(it,itt)=n2(it,itt)*Z2(it);
end % end of m loop
end % end of frequency loopclear
clc
clf
%***************************************************
% constants
rad=pi/180;
eps0=8.85e-12;
mu0=4*pi*1e-7;
eta0=sqrt(mu0/eps0); % free space
c=1/sqrt(eps0*mu0);
%***************************************************
% variables
d=2.5e-3; % thickness of the sample
f1=1e9; df=9e6; f2=10e9; Nf=floor((f2-f1)/df)+1; % frequency range and
% load raw data
M1r = csvread(‘sample.dat’,4); % Read the data
P1r = csvread(‘sample1.dat’,2); % Read the data
P2r = csvread(‘sample2.dat’,2); % Read the data
Mag1=M1r(:,2);
Mag2=M1r(:,3);
Ph1=-unwrap(P1r(:,2),180);
Ph2=-unwrap(P2r(:,2),180);
%*****************************************
% freqyency loop begin
for it=1:Nf
f=f1+(it-1)*df;
Fr(it)=f;
Fghz(it)=f/1e9;
fghz=f/1e9;
Z0=eta0; W=2*pi*Fr(it); beta0=W/c;
%*******************************************
% combine magnitude and phase of the S11 and S21
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);………………………………………………..error Index exceeds matrix dimensions.
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);
T(it)=Mag2(it)*exp(j*Ph2(it)*rad);
% m loop begin
Max=0; % ———m value set up
itt=0;
for m=-Max:Max
itt=itt+1;
%***************************************************
% using formulas from Robust method
Tp=T(it);
Z21(it)=sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
Z22(it)=-sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
expinkd1(it)=Tp/(1-R(it)*(Z21(it)-1)/(Z21(it)+1));
expinkd2(it)=Tp/(1-R(it)*(Z22(it)-1)/(Z22(it)+1));
if abs(real(Z21(it)))>=0.005 & real(Z21(it))>=0
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))>=0.005 & real(Z21(it))<0
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))<=1
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))>1
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
ni(it)=-1/(beta0*d)*j*real(log(expinkd(it))); % imag of n
nr(it,itt)=1/(beta0*d)*(imag(log(expinkd(it)))+2*m*pi); %real of n
n2(it,itt)=nr(it,itt)+ni(it);
Er2(it,itt)=n2(it,itt)/Z2(it);
Mr2(it,itt)=n2(it,itt)*Z2(it);
end % end of m loop
end % end of frequency loop clear
clc
clf
%***************************************************
% constants
rad=pi/180;
eps0=8.85e-12;
mu0=4*pi*1e-7;
eta0=sqrt(mu0/eps0); % free space
c=1/sqrt(eps0*mu0);
%***************************************************
% variables
d=2.5e-3; % thickness of the sample
f1=1e9; df=9e6; f2=10e9; Nf=floor((f2-f1)/df)+1; % frequency range and
% load raw data
M1r = csvread(‘sample.dat’,4); % Read the data
P1r = csvread(‘sample1.dat’,2); % Read the data
P2r = csvread(‘sample2.dat’,2); % Read the data
Mag1=M1r(:,2);
Mag2=M1r(:,3);
Ph1=-unwrap(P1r(:,2),180);
Ph2=-unwrap(P2r(:,2),180);
%*****************************************
% freqyency loop begin
for it=1:Nf
f=f1+(it-1)*df;
Fr(it)=f;
Fghz(it)=f/1e9;
fghz=f/1e9;
Z0=eta0; W=2*pi*Fr(it); beta0=W/c;
%*******************************************
% combine magnitude and phase of the S11 and S21
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);………………………………………………..error Index exceeds matrix dimensions.
R(it)=Mag1(it)*exp(j*Ph1(it)*rad);
T(it)=Mag2(it)*exp(j*Ph2(it)*rad);
% m loop begin
Max=0; % ———m value set up
itt=0;
for m=-Max:Max
itt=itt+1;
%***************************************************
% using formulas from Robust method
Tp=T(it);
Z21(it)=sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
Z22(it)=-sqrt(((1+R(it))^2-Tp^2)/((1-R(it))^2-Tp^2));
expinkd1(it)=Tp/(1-R(it)*(Z21(it)-1)/(Z21(it)+1));
expinkd2(it)=Tp/(1-R(it)*(Z22(it)-1)/(Z22(it)+1));
if abs(real(Z21(it)))>=0.005 & real(Z21(it))>=0
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))>=0.005 & real(Z21(it))<0
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))<=1
expinkd(it)=expinkd1(it);
Z2(it)=Z21(it);
end
if abs(real(Z21(it)))<0.005 & abs(expinkd1(it))>1
expinkd(it)=expinkd2(it);
Z2(it)=Z22(it);
end
ni(it)=-1/(beta0*d)*j*real(log(expinkd(it))); % imag of n
nr(it,itt)=1/(beta0*d)*(imag(log(expinkd(it)))+2*m*pi); %real of n
n2(it,itt)=nr(it,itt)+ni(it);
Er2(it,itt)=n2(it,itt)/Z2(it);
Mr2(it,itt)=n2(it,itt)*Z2(it);
end % end of m loop
end % end of frequency loop index exceeds matrix dimensions. error in check2 (line 37) r(it)=mag1(it)*exp(j*ph1(it)*rad) MATLAB Answers — New Questions

​

I am using some c++ code with mex. I would like to pass in a dictionary of parameters, do some computation and create some vectors, and then return the results as a dictionary. Something like the following:
// test_mex.cpp
#include "mex.h"

void mexFunction(int N_output, mxArray *output[], int N_input, const mxArray *input[]) {
// Check input
if (N_input != 1) {
mexErrMsgIdAndTxt("MyClass:InvalidInput", "One input required.");
}
if (!mxIsClass(input[0], "dictionary")) {
mexErrMsgIdAndTxt("MATLAB:invalidInput", "Input must be a dictionary.");
}

// Convert to a std::unordered_map
std::unordered_map<std::string, double> params = input[0];

// Compute
std::unordered_map<std::string, std::vector<double>> out;
out["C"] = std::vector<double>(params["A"], 1.0);

// Convert back to a dictionary and return
output[0] = out;
}
Called with:
mex test_mex; test_mex(dictionary(["A", "B"], {100, 1020}));I am using some c++ code with mex. I would like to pass in a dictionary of parameters, do some computation and create some vectors, and then return the results as a dictionary. Something like the following:
// test_mex.cpp
#include "mex.h"

void mexFunction(int N_output, mxArray *output[], int N_input, const mxArray *input[]) {
// Check input
if (N_input != 1) {
mexErrMsgIdAndTxt("MyClass:InvalidInput", "One input required.");
}
if (!mxIsClass(input[0], "dictionary")) {
mexErrMsgIdAndTxt("MATLAB:invalidInput", "Input must be a dictionary.");
}

// Convert to a std::unordered_map
std::unordered_map<std::string, double> params = input[0];

// Compute
std::unordered_map<std::string, std::vector<double>> out;
out["C"] = std::vector<double>(params["A"], 1.0);

// Convert back to a dictionary and return
output[0] = out;
}
Called with:
mex test_mex; test_mex(dictionary(["A", "B"], {100, 1020})); I am using some c++ code with mex. I would like to pass in a dictionary of parameters, do some computation and create some vectors, and then return the results as a dictionary. Something like the following:
// test_mex.cpp
#include "mex.h"

void mexFunction(int N_output, mxArray *output[], int N_input, const mxArray *input[]) {
// Check input
if (N_input != 1) {
mexErrMsgIdAndTxt("MyClass:InvalidInput", "One input required.");
}
if (!mxIsClass(input[0], "dictionary")) {
mexErrMsgIdAndTxt("MATLAB:invalidInput", "Input must be a dictionary.");
}

// Convert to a std::unordered_map
std::unordered_map<std::string, double> params = input[0];

// Compute
std::unordered_map<std::string, std::vector<double>> out;
out["C"] = std::vector<double>(params["A"], 1.0);

// Convert back to a dictionary and return
output[0] = out;
}
Called with:
mex test_mex; test_mex(dictionary(["A", "B"], {100, 1020})); mex, dictionary MATLAB Answers — New Questions

​

When I updated the latest 2025a, I tried to draw a picture with pcolor() and found that pixel blocks appeared on the picture drawn by the 2025a version, but not in the 2023b version, so I was a little confused why?
The code is as follows，and the data package and operation results are shown in the attachment
clc;clear;close all
load(‘test.mat’)
figure;
figWidth = 14;
figHeight = figWidth * (10 – (-5)) / (160 – 130);
set(gcf, ‘Units’, ‘centimeters’, ‘Position’, [10 10 figWidth figHeight]);
set(gcf, ‘Color’, ‘white’, ‘InvertHardcopy’, ‘off’);
h = pcolor(a, b, d);
shading interp
set(h, ‘EdgeColor’, ‘none’)
caxis([-1.2 1.2])
set(gca, ‘YDir’, ‘reverse’,’TickDir’,’out’, ‘FontSize’, 8, ‘Box’, ‘on’,’FontName’,’Arial’)
colorbar(‘Location’, ‘eastoutside’,’FontName’,’Arial’,’FontWeight’,’normal’);
exportgraphics(gca,’test.pdf’,’BackgroundColor’,’none’,’ContentType’,’vector’,’Resolution’,600)
close allWhen I updated the latest 2025a, I tried to draw a picture with pcolor() and found that pixel blocks appeared on the picture drawn by the 2025a version, but not in the 2023b version, so I was a little confused why?
The code is as follows，and the data package and operation results are shown in the attachment
clc;clear;close all
load(‘test.mat’)
figure;
figWidth = 14;
figHeight = figWidth * (10 – (-5)) / (160 – 130);
set(gcf, ‘Units’, ‘centimeters’, ‘Position’, [10 10 figWidth figHeight]);
set(gcf, ‘Color’, ‘white’, ‘InvertHardcopy’, ‘off’);
h = pcolor(a, b, d);
shading interp
set(h, ‘EdgeColor’, ‘none’)
caxis([-1.2 1.2])
set(gca, ‘YDir’, ‘reverse’,’TickDir’,’out’, ‘FontSize’, 8, ‘Box’, ‘on’,’FontName’,’Arial’)
colorbar(‘Location’, ‘eastoutside’,’FontName’,’Arial’,’FontWeight’,’normal’);
exportgraphics(gca,’test.pdf’,’BackgroundColor’,’none’,’ContentType’,’vector’,’Resolution’,600)
close all When I updated the latest 2025a, I tried to draw a picture with pcolor() and found that pixel blocks appeared on the picture drawn by the 2025a version, but not in the 2023b version, so I was a little confused why?
The code is as follows，and the data package and operation results are shown in the attachment
clc;clear;close all
load(‘test.mat’)
figure;
figWidth = 14;
figHeight = figWidth * (10 – (-5)) / (160 – 130);
set(gcf, ‘Units’, ‘centimeters’, ‘Position’, [10 10 figWidth figHeight]);
set(gcf, ‘Color’, ‘white’, ‘InvertHardcopy’, ‘off’);
h = pcolor(a, b, d);
shading interp
set(h, ‘EdgeColor’, ‘none’)
caxis([-1.2 1.2])
set(gca, ‘YDir’, ‘reverse’,’TickDir’,’out’, ‘FontSize’, 8, ‘Box’, ‘on’,’FontName’,’Arial’)
colorbar(‘Location’, ‘eastoutside’,’FontName’,’Arial’,’FontWeight’,’normal’);
exportgraphics(gca,’test.pdf’,’BackgroundColor’,’none’,’ContentType’,’vector’,’Resolution’,600)
close all pcolor, resolution MATLAB Answers — New Questions

​

I’m planning to start a personal scientific software project. I used to be familiar with Matlab (quite some time ago), so Matlab would be my first choice. But I keep hearing that Matlab is old stuff and I should use Julia or something like that. I wouldn’t find learning Julia difficult, so familiarity with Matlab is not an important factor. Neither is cost, because I can afford a home license for Matlab, Simulink and a few toolboxes. So I’m thinking. Please give me your input! Why should I use Matlab in 2025 instead of alternatives?I’m planning to start a personal scientific software project. I used to be familiar with Matlab (quite some time ago), so Matlab would be my first choice. But I keep hearing that Matlab is old stuff and I should use Julia or something like that. I wouldn’t find learning Julia difficult, so familiarity with Matlab is not an important factor. Neither is cost, because I can afford a home license for Matlab, Simulink and a few toolboxes. So I’m thinking. Please give me your input! Why should I use Matlab in 2025 instead of alternatives? I’m planning to start a personal scientific software project. I used to be familiar with Matlab (quite some time ago), so Matlab would be my first choice. But I keep hearing that Matlab is old stuff and I should use Julia or something like that. I wouldn’t find learning Julia difficult, so familiarity with Matlab is not an important factor. Neither is cost, because I can afford a home license for Matlab, Simulink and a few toolboxes. So I’m thinking. Please give me your input! Why should I use Matlab in 2025 instead of alternatives? matlab, julia MATLAB Answers — New Questions

​

Hi I am a student at University of Johannesburg. I created the MATLAB account online. I want to start the 30 day free trial but when I tap to student trial version, I am required to type in a zip code. Please help because I don not know the zip code.Hi I am a student at University of Johannesburg. I created the MATLAB account online. I want to start the 30 day free trial but when I tap to student trial version, I am required to type in a zip code. Please help because I don not know the zip code. Hi I am a student at University of Johannesburg. I created the MATLAB account online. I want to start the 30 day free trial but when I tap to student trial version, I am required to type in a zip code. Please help because I don not know the zip code. power_electronics_control MATLAB Answers — New Questions

​

Hi everyone, I am currently practicing this method on a simple function, however I keep getting this error and I do not know how to fix it.
Here is my programe:
fplot(@(x)myfun(x),[-10,10]);
alpha = 0.01;
x0 = -5;
% ——-using GD———————-
[x grad] = gradient(alpha,x0)
% hold on
% figure;
fprintf(‘x = %fn’,x);
fprintf(‘grad = %fn’,grad);
% ——————————
function f = myfun(x)
f = x^2+5*sin(x);
end

function [x,grad] = gradient(alpha,x0)
grad = 2*x0+5*cos(x0);
x = x0;
for i = 0:50
x = x – alpha*grad;
if abs(grad(x))< 0.01
break
display(x);
% grad = grad(x);
end
end
Here is the error that I got
Array indices must be positive integers or logical values.

Error in gradient (line 6)
if abs(grad(x))< 0.01

Error in Gradient_descent_1 (line 5)
[x grad] = gradient(alpha,x0)Hi everyone, I am currently practicing this method on a simple function, however I keep getting this error and I do not know how to fix it.
Here is my programe:
fplot(@(x)myfun(x),[-10,10]);
alpha = 0.01;
x0 = -5;
% ——-using GD———————-
[x grad] = gradient(alpha,x0)
% hold on
% figure;
fprintf(‘x = %fn’,x);
fprintf(‘grad = %fn’,grad);
% ——————————
function f = myfun(x)
f = x^2+5*sin(x);
end

function [x,grad] = gradient(alpha,x0)
grad = 2*x0+5*cos(x0);
x = x0;
for i = 0:50
x = x – alpha*grad;
if abs(grad(x))< 0.01
break
display(x);
% grad = grad(x);
end
end
Here is the error that I got
Array indices must be positive integers or logical values.

Error in gradient (line 6)
if abs(grad(x))< 0.01

Error in Gradient_descent_1 (line 5)
[x grad] = gradient(alpha,x0) Hi everyone, I am currently practicing this method on a simple function, however I keep getting this error and I do not know how to fix it.
Here is my programe:
fplot(@(x)myfun(x),[-10,10]);
alpha = 0.01;
x0 = -5;
% ——-using GD———————-
[x grad] = gradient(alpha,x0)
% hold on
% figure;
fprintf(‘x = %fn’,x);
fprintf(‘grad = %fn’,grad);
% ——————————
function f = myfun(x)
f = x^2+5*sin(x);
end

function [x,grad] = gradient(alpha,x0)
grad = 2*x0+5*cos(x0);
x = x0;
for i = 0:50
x = x – alpha*grad;
if abs(grad(x))< 0.01
break
display(x);
% grad = grad(x);
end
end
Here is the error that I got
Array indices must be positive integers or logical values.

Error in gradient (line 6)
if abs(grad(x))< 0.01

Error in Gradient_descent_1 (line 5)
[x grad] = gradient(alpha,x0) machine learning MATLAB Answers — New Questions

​

I have a camera mounted on a car capturing video. The car starts and stops frequently. I want to figure out when the car stops and starts. There is enough disturbance in the environment with uneven ground and even a breeze can cause huge changes in the environment. Just looking for difference from frame to frame does not give me what I need. I have tried that already. There are no markers either to distinguish when the car stops. This is not inline analysis. I have to do this offline.

Any ideas to try would be greatly appreciated.I have a camera mounted on a car capturing video. The car starts and stops frequently. I want to figure out when the car stops and starts. There is enough disturbance in the environment with uneven ground and even a breeze can cause huge changes in the environment. Just looking for difference from frame to frame does not give me what I need. I have tried that already. There are no markers either to distinguish when the car stops. This is not inline analysis. I have to do this offline.

Any ideas to try would be greatly appreciated. I have a camera mounted on a car capturing video. The car starts and stops frequently. I want to figure out when the car stops and starts. There is enough disturbance in the environment with uneven ground and even a breeze can cause huge changes in the environment. Just looking for difference from frame to frame does not give me what I need. I have tried that already. There are no markers either to distinguish when the car stops. This is not inline analysis. I have to do this offline.

Any ideas to try would be greatly appreciated. motion, image analysis, image processing, video analysis MATLAB Answers — New Questions

​

Hi, i recently upgraded from 2021b to 2025a and now the canvas of my figure is white and Matlab throws the warning:
Warning: An error occurred while drawing the scene: Error in web draw traversal: RangeError: Array buffer allocation failed
For better understanding:
I call the pcolor() function and the figure out of a Matlab app. Plotting that into the UIAxes in Matlab 2021b gave me the same error. My workaround was to create a standard figure and plot into this. Now with Matlab 2025a, i do not have this workaround anymore and i get the same error either way.Hi, i recently upgraded from 2021b to 2025a and now the canvas of my figure is white and Matlab throws the warning:
Warning: An error occurred while drawing the scene: Error in web draw traversal: RangeError: Array buffer allocation failed
For better understanding:
I call the pcolor() function and the figure out of a Matlab app. Plotting that into the UIAxes in Matlab 2021b gave me the same error. My workaround was to create a standard figure and plot into this. Now with Matlab 2025a, i do not have this workaround anymore and i get the same error either way. Hi, i recently upgraded from 2021b to 2025a and now the canvas of my figure is white and Matlab throws the warning:
Warning: An error occurred while drawing the scene: Error in web draw traversal: RangeError: Array buffer allocation failed
For better understanding:
I call the pcolor() function and the figure out of a Matlab app. Plotting that into the UIAxes in Matlab 2021b gave me the same error. My workaround was to create a standard figure and plot into this. Now with Matlab 2025a, i do not have this workaround anymore and i get the same error either way. figure MATLAB Answers — New Questions

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Hi everyone,
Im working for project euler and I try to do #9 (Special Pythagorean Triplet). I have encountered couples of errors, one of which is something that occurs from my trying to make 3 arrays probably, some of them are named Variable might be set by a nonscalar and other errors which I don’t understand.

function y = pythtrip(a,b,c)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
y = a*b*c;
a = 0:750;
b = 0:750;
c = 0:750;
while (a>b) && b>c && (a^2)+(b^2)==(c^2) && a+b+c == 1000;
pythtrip(a,b,c)
y;
endHi everyone,
Im working for project euler and I try to do #9 (Special Pythagorean Triplet). I have encountered couples of errors, one of which is something that occurs from my trying to make 3 arrays probably, some of them are named Variable might be set by a nonscalar and other errors which I don’t understand.

function y = pythtrip(a,b,c)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
y = a*b*c;
a = 0:750;
b = 0:750;
c = 0:750;
while (a>b) && b>c && (a^2)+(b^2)==(c^2) && a+b+c == 1000;
pythtrip(a,b,c)
y;
end Hi everyone,
Im working for project euler and I try to do #9 (Special Pythagorean Triplet). I have encountered couples of errors, one of which is something that occurs from my trying to make 3 arrays probably, some of them are named Variable might be set by a nonscalar and other errors which I don’t understand.

function y = pythtrip(a,b,c)
%UNTITLED Summary of this function goes here
% Detailed explanation goes here
y = a*b*c;
a = 0:750;
b = 0:750;
c = 0:750;
while (a>b) && b>c && (a^2)+(b^2)==(c^2) && a+b+c == 1000;
pythtrip(a,b,c)
y;
end project_euler, pythagorean triplet, arrays, while loop, function MATLAB Answers — New Questions

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