I’m currently using Matlab 2020b
The doumentation for the double function states that ‘Converting a string that does not represent a single numeric value to double will produce a NaN result’. Based on this, I am using isnan(double(string(‘chars’))) to check whether a user inputted character vector represents a number or not. One particular case I wish to guard against is users entering a ‘,’ instaed of ‘.’. This works very well, except if the vector in question has a comma followed by exactly 3 numerals, in which case double tells me it is a number. For example, the vector ‘1.23’ will produce NaN, but ‘1,234’ gives the number 1234. Any other number of characters after the comma gives NaN (as far as I can tell).
Does anybody understand why this is and is there a way to get it to do what I actually want?
ThanksI’m currently using Matlab 2020b
The doumentation for the double function states that ‘Converting a string that does not represent a single numeric value to double will produce a NaN result’. Based on this, I am using isnan(double(string(‘chars’))) to check whether a user inputted character vector represents a number or not. One particular case I wish to guard against is users entering a ‘,’ instaed of ‘.’. This works very well, except if the vector in question has a comma followed by exactly 3 numerals, in which case double tells me it is a number. For example, the vector ‘1.23’ will produce NaN, but ‘1,234’ gives the number 1234. Any other number of characters after the comma gives NaN (as far as I can tell).
Does anybody understand why this is and is there a way to get it to do what I actually want?
Thanks I’m currently using Matlab 2020b
The doumentation for the double function states that ‘Converting a string that does not represent a single numeric value to double will produce a NaN result’. Based on this, I am using isnan(double(string(‘chars’))) to check whether a user inputted character vector represents a number or not. One particular case I wish to guard against is users entering a ‘,’ instaed of ‘.’. This works very well, except if the vector in question has a comma followed by exactly 3 numerals, in which case double tells me it is a number. For example, the vector ‘1.23’ will produce NaN, but ‘1,234’ gives the number 1234. Any other number of characters after the comma gives NaN (as far as I can tell).
Does anybody understand why this is and is there a way to get it to do what I actually want?
Thanks double MATLAB Answers — New Questions

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Hi,
I’m trying to create error bars on my bar plot.
I get the error: "Input arguments must be numeric, datetime, duration, or categorical."
I’m not sure what I’m doing wrong. Even when I make err equal to two numbers it still doesn’t work.
AMean = 656631
BMean = 1130
ASTD = 237027
BSTD = 209
AHeight = 10
BHeight = 11

Names = ["A"; "B" ] ;
Averages = [AMean; BMean] ;
StandDev = [ASTD ; BSTD] ;
SampSize = [AHeight; BHeight] ;
NewTable = table(Names, Averages, StandDev, SampSize) ;

x = NewTable.Names ;
y = NewTable.Averages ;
err = StandDev ./ sqrt(SampSize) ;

bar(x, y)
errorbar(x,y,err)Hi,
I’m trying to create error bars on my bar plot.
I get the error: "Input arguments must be numeric, datetime, duration, or categorical."
I’m not sure what I’m doing wrong. Even when I make err equal to two numbers it still doesn’t work.
AMean = 656631
BMean = 1130
ASTD = 237027
BSTD = 209
AHeight = 10
BHeight = 11

Names = ["A"; "B" ] ;
Averages = [AMean; BMean] ;
StandDev = [ASTD ; BSTD] ;
SampSize = [AHeight; BHeight] ;
NewTable = table(Names, Averages, StandDev, SampSize) ;

x = NewTable.Names ;
y = NewTable.Averages ;
err = StandDev ./ sqrt(SampSize) ;

bar(x, y)
errorbar(x,y,err) Hi,
I’m trying to create error bars on my bar plot.
I get the error: "Input arguments must be numeric, datetime, duration, or categorical."
I’m not sure what I’m doing wrong. Even when I make err equal to two numbers it still doesn’t work.
AMean = 656631
BMean = 1130
ASTD = 237027
BSTD = 209
AHeight = 10
BHeight = 11

Names = ["A"; "B" ] ;
Averages = [AMean; BMean] ;
StandDev = [ASTD ; BSTD] ;
SampSize = [AHeight; BHeight] ;
NewTable = table(Names, Averages, StandDev, SampSize) ;

x = NewTable.Names ;
y = NewTable.Averages ;
err = StandDev ./ sqrt(SampSize) ;

bar(x, y)
errorbar(x,y,err) error bar, graphing MATLAB Answers — New Questions

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I used this Mathworks post to implement an intermittent file logging method in my real-time app running on Speedgoat.
I created a long duration (10’s on minutes) timer with a callback. The callback performs stopRecording() and then startRecording(), which should create a new log file.

The timer looks something like this:
timer(‘ExecutionMode’, ‘fixedRate’, ‘Period’, 600, ‘TimerFcn’, @(~,~)app.createNewLogFile(app))

createNewLogFile() does the following:
stopRecording(app.tg)
short pause()
startRecording(app.tg)
Checks whether a new log file was created (it should be from stopping/restarting)

This works the majority of the time, but fails intermittently. I performed basic troubleshooting to see that it fails to log for a period of time when the callback fails. I can see that it stopped recording but did not restart within that failed callback.

Extra info:
There is no Enable Log File block in the model because its documentation page says that it can affect the usage of recording functions
I have tried giving the stop/restart calls multiple attempts within the same timer callback. It seems that if it fails the first attempt in a timer callback, it fails repeatedly within that callback
I want the timed log functionality to be in the App because I want the ability for an App user to toggle it. Meaning that in-model default timer solutions don’t work as an alternative
I would like to learn how to fish here. What can I do to truly understand why/how a startRecording() call would not work? Is there something about housing this behavior within a timer callback on the host side that makes it unreliable for sending commands to the target? It doesn’t seem like it should be since the timer is very long duration in comparison to the callback commands.
If I understand the documentation correctly, there is a target->host ACK built in to the stopRecording() and startRecording() functions? So I would expect the restart to fail the acknowledge step if it did not go through. But I don’t see a failure.
Thanks for any insight here.I used this Mathworks post to implement an intermittent file logging method in my real-time app running on Speedgoat.
I created a long duration (10’s on minutes) timer with a callback. The callback performs stopRecording() and then startRecording(), which should create a new log file.

The timer looks something like this:
timer(‘ExecutionMode’, ‘fixedRate’, ‘Period’, 600, ‘TimerFcn’, @(~,~)app.createNewLogFile(app))

createNewLogFile() does the following:
stopRecording(app.tg)
short pause()
startRecording(app.tg)
Checks whether a new log file was created (it should be from stopping/restarting)

This works the majority of the time, but fails intermittently. I performed basic troubleshooting to see that it fails to log for a period of time when the callback fails. I can see that it stopped recording but did not restart within that failed callback.

Extra info:
There is no Enable Log File block in the model because its documentation page says that it can affect the usage of recording functions
I have tried giving the stop/restart calls multiple attempts within the same timer callback. It seems that if it fails the first attempt in a timer callback, it fails repeatedly within that callback
I want the timed log functionality to be in the App because I want the ability for an App user to toggle it. Meaning that in-model default timer solutions don’t work as an alternative
I would like to learn how to fish here. What can I do to truly understand why/how a startRecording() call would not work? Is there something about housing this behavior within a timer callback on the host side that makes it unreliable for sending commands to the target? It doesn’t seem like it should be since the timer is very long duration in comparison to the callback commands.
If I understand the documentation correctly, there is a target->host ACK built in to the stopRecording() and startRecording() functions? So I would expect the restart to fail the acknowledge step if it did not go through. But I don’t see a failure.
Thanks for any insight here. I used this Mathworks post to implement an intermittent file logging method in my real-time app running on Speedgoat.
I created a long duration (10’s on minutes) timer with a callback. The callback performs stopRecording() and then startRecording(), which should create a new log file.

The timer looks something like this:
timer(‘ExecutionMode’, ‘fixedRate’, ‘Period’, 600, ‘TimerFcn’, @(~,~)app.createNewLogFile(app))

createNewLogFile() does the following:
stopRecording(app.tg)
short pause()
startRecording(app.tg)
Checks whether a new log file was created (it should be from stopping/restarting)

This works the majority of the time, but fails intermittently. I performed basic troubleshooting to see that it fails to log for a period of time when the callback fails. I can see that it stopped recording but did not restart within that failed callback.

Extra info:
There is no Enable Log File block in the model because its documentation page says that it can affect the usage of recording functions
I have tried giving the stop/restart calls multiple attempts within the same timer callback. It seems that if it fails the first attempt in a timer callback, it fails repeatedly within that callback
I want the timed log functionality to be in the App because I want the ability for an App user to toggle it. Meaning that in-model default timer solutions don’t work as an alternative
I would like to learn how to fish here. What can I do to truly understand why/how a startRecording() call would not work? Is there something about housing this behavior within a timer callback on the host side that makes it unreliable for sending commands to the target? It doesn’t seem like it should be since the timer is very long duration in comparison to the callback commands.
If I understand the documentation correctly, there is a target->host ACK built in to the stopRecording() and startRecording() functions? So I would expect the restart to fail the acknowledge step if it did not go through. But I don’t see a failure.
Thanks for any insight here. app designer, timer, real-time MATLAB Answers — New Questions

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Hi… I have designed a fuzzy controller that I want to tune. The dataset I currently have contains output from another software, recorded over time. Consider that I read two inputs and generate an output, and the resulting table provides data over a 60-second period. How can I import this dataset into MATLAB and use it for tuning my fuzzy controller?
Fuzzy Controller designed in Fuzzy Logic Designer app:

Data sample:Hi… I have designed a fuzzy controller that I want to tune. The dataset I currently have contains output from another software, recorded over time. Consider that I read two inputs and generate an output, and the resulting table provides data over a 60-second period. How can I import this dataset into MATLAB and use it for tuning my fuzzy controller?
Fuzzy Controller designed in Fuzzy Logic Designer app:

Data sample: Hi… I have designed a fuzzy controller that I want to tune. The dataset I currently have contains output from another software, recorded over time. Consider that I read two inputs and generate an output, and the resulting table provides data over a 60-second period. How can I import this dataset into MATLAB and use it for tuning my fuzzy controller?
Fuzzy Controller designed in Fuzzy Logic Designer app:

Data sample: fuzzy logic controller, fuzzy logic designer MATLAB Answers — New Questions

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answer = questdlg(quest,dlgtitle,btn1,btn2,btn3,defbtn)
When the dialogue box is opened, the default button is selected, but pressing ENTER won’t click the button, and pressing ESC won’t close the dialogue box.answer = questdlg(quest,dlgtitle,btn1,btn2,btn3,defbtn)
When the dialogue box is opened, the default button is selected, but pressing ENTER won’t click the button, and pressing ESC won’t close the dialogue box. answer = questdlg(quest,dlgtitle,btn1,btn2,btn3,defbtn)
When the dialogue box is opened, the default button is selected, but pressing ENTER won’t click the button, and pressing ESC won’t close the dialogue box. matlab gui, nevermind – works now MATLAB Answers — New Questions

​

Hello,

I am new to image processing and had a conceptual question. I am currently trying to perform a 2D convolution of an image and a kernel (filter) in simulink using the 2D convolution block. I have code that transposes the image, then flips it, then performs the 2D convolution with the kernel. However from my (very limited) understanding convolution already flips the filter that I want to apply. I was told that the output of me transposing and flipping the image, then convolving with the kernel looks correct, however from my understanding I would be transposing and flipping the image once then convolving, which involves another flip, so therefore not actually convolving? I have read that this would just produce instead a correlation?

Hoping someone who knows more may be able to help give me a better understanding.

Thank you!Hello,

I am new to image processing and had a conceptual question. I am currently trying to perform a 2D convolution of an image and a kernel (filter) in simulink using the 2D convolution block. I have code that transposes the image, then flips it, then performs the 2D convolution with the kernel. However from my (very limited) understanding convolution already flips the filter that I want to apply. I was told that the output of me transposing and flipping the image, then convolving with the kernel looks correct, however from my understanding I would be transposing and flipping the image once then convolving, which involves another flip, so therefore not actually convolving? I have read that this would just produce instead a correlation?

Hoping someone who knows more may be able to help give me a better understanding.

Thank you! Hello,

I am new to image processing and had a conceptual question. I am currently trying to perform a 2D convolution of an image and a kernel (filter) in simulink using the 2D convolution block. I have code that transposes the image, then flips it, then performs the 2D convolution with the kernel. However from my (very limited) understanding convolution already flips the filter that I want to apply. I was told that the output of me transposing and flipping the image, then convolving with the kernel looks correct, however from my understanding I would be transposing and flipping the image once then convolving, which involves another flip, so therefore not actually convolving? I have read that this would just produce instead a correlation?

Hoping someone who knows more may be able to help give me a better understanding.

Thank you! convolution, simulink, image processing MATLAB Answers — New Questions

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Here are the steps that lead to the results:
1) You start by running app2_tester that leads to app3_tester ( for making the problem simpler, I have just made it possible choosing just one combination of salts, NaCl KCl and ZnBr2: so that I don’t need to attach many function files, though there are listed up many salts in the listbox of app3_tester.
2) Each time you have pressed the choices for every zone, you press the button “done with the zone”, for instance when you in start have chosen that there are two zones, you first begin to selecting information for zone1 then do the same for zone 2
3) When you have finished pressing info about both zones, you press “ computed water activity and osmotic pressure” in app2_tester

I have problems in app2_tester and app3_tester. The other apps and some functions that are needed to run the apps are correct. I get error in app3_tester. So what I am wondering is:

Why am I not getting the zone nr 2 writtten in my osmotic table data that is printed out when I press on the button “display results from all zones”, and neither the names of the different combinations of salts in the column called combination_of_salts in my table?

The error I get says:
Error using table (line 231)
All input variables must have the same number of rows.

Error in app3_tester/StartanalysisButtonPushed (line 259)
app.Callingapp.Osmotisk_data(app.zone_now,:) = table(app.zone_now, app.combinations_of_salts, app.vekt_prosent_best_salt_1,app.vekt_prosent_best_salt_2, app.samlet_vannaktivitet,P,effect);Here are the steps that lead to the results:
1) You start by running app2_tester that leads to app3_tester ( for making the problem simpler, I have just made it possible choosing just one combination of salts, NaCl KCl and ZnBr2: so that I don’t need to attach many function files, though there are listed up many salts in the listbox of app3_tester.
2) Each time you have pressed the choices for every zone, you press the button “done with the zone”, for instance when you in start have chosen that there are two zones, you first begin to selecting information for zone1 then do the same for zone 2
3) When you have finished pressing info about both zones, you press “ computed water activity and osmotic pressure” in app2_tester

I have problems in app2_tester and app3_tester. The other apps and some functions that are needed to run the apps are correct. I get error in app3_tester. So what I am wondering is:

Why am I not getting the zone nr 2 writtten in my osmotic table data that is printed out when I press on the button “display results from all zones”, and neither the names of the different combinations of salts in the column called combination_of_salts in my table?

The error I get says:
Error using table (line 231)
All input variables must have the same number of rows.

Error in app3_tester/StartanalysisButtonPushed (line 259)
app.Callingapp.Osmotisk_data(app.zone_now,:) = table(app.zone_now, app.combinations_of_salts, app.vekt_prosent_best_salt_1,app.vekt_prosent_best_salt_2, app.samlet_vannaktivitet,P,effect); Here are the steps that lead to the results:
1) You start by running app2_tester that leads to app3_tester ( for making the problem simpler, I have just made it possible choosing just one combination of salts, NaCl KCl and ZnBr2: so that I don’t need to attach many function files, though there are listed up many salts in the listbox of app3_tester.
2) Each time you have pressed the choices for every zone, you press the button “done with the zone”, for instance when you in start have chosen that there are two zones, you first begin to selecting information for zone1 then do the same for zone 2
3) When you have finished pressing info about both zones, you press “ computed water activity and osmotic pressure” in app2_tester

I have problems in app2_tester and app3_tester. The other apps and some functions that are needed to run the apps are correct. I get error in app3_tester. So what I am wondering is:

Why am I not getting the zone nr 2 writtten in my osmotic table data that is printed out when I press on the button “display results from all zones”, and neither the names of the different combinations of salts in the column called combination_of_salts in my table?

The error I get says:
Error using table (line 231)
All input variables must have the same number of rows.

Error in app3_tester/StartanalysisButtonPushed (line 259)
app.Callingapp.Osmotisk_data(app.zone_now,:) = table(app.zone_now, app.combinations_of_salts, app.vekt_prosent_best_salt_1,app.vekt_prosent_best_salt_2, app.samlet_vannaktivitet,P,effect); appdesigner, table MATLAB Answers — New Questions

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Hey there, recently I’ve updated from 2024b to 2025a and immediately the thing that grabbed my attention was the fact that plots created in live editor and command window are vastly different in resolution and smoothness. I’ve tried searching for people with similar experience in Matlab answers but couldn’t find anything related. Some had issues with the gpu or renderer but my problem is only happening in live editor.
Here’s a comparison between a plot created in two environments:
clear; close; clc

t = linspace(0, 2*pi, 1000);
f = 4;
y = 0.8*sin(2*pi*f*t);

figure
plot(t, y)
axis tight
Lower res from live editor:

Higher res from work space:

I’ve also attached the plots incase uploding them corrupts the quality.
Now the interesting thing is that when I open up the figure window of the same plot that I had created in live editor then suddenly the quality is high again. I tried my luck with chat gpt and grok but they were pulling their results from the same forums that I had already visited so nothing useful was found that way.Hey there, recently I’ve updated from 2024b to 2025a and immediately the thing that grabbed my attention was the fact that plots created in live editor and command window are vastly different in resolution and smoothness. I’ve tried searching for people with similar experience in Matlab answers but couldn’t find anything related. Some had issues with the gpu or renderer but my problem is only happening in live editor.
Here’s a comparison between a plot created in two environments:
clear; close; clc

t = linspace(0, 2*pi, 1000);
f = 4;
y = 0.8*sin(2*pi*f*t);

figure
plot(t, y)
axis tight
Lower res from live editor:

Higher res from work space:

I’ve also attached the plots incase uploding them corrupts the quality.
Now the interesting thing is that when I open up the figure window of the same plot that I had created in live editor then suddenly the quality is high again. I tried my luck with chat gpt and grok but they were pulling their results from the same forums that I had already visited so nothing useful was found that way. Hey there, recently I’ve updated from 2024b to 2025a and immediately the thing that grabbed my attention was the fact that plots created in live editor and command window are vastly different in resolution and smoothness. I’ve tried searching for people with similar experience in Matlab answers but couldn’t find anything related. Some had issues with the gpu or renderer but my problem is only happening in live editor.
Here’s a comparison between a plot created in two environments:
clear; close; clc

t = linspace(0, 2*pi, 1000);
f = 4;
y = 0.8*sin(2*pi*f*t);

figure
plot(t, y)
axis tight
Lower res from live editor:

Higher res from work space:

I’ve also attached the plots incase uploding them corrupts the quality.
Now the interesting thing is that when I open up the figure window of the same plot that I had created in live editor then suddenly the quality is high again. I tried my luck with chat gpt and grok but they were pulling their results from the same forums that I had already visited so nothing useful was found that way. low resolution plot, live editor MATLAB Answers — New Questions

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Hello, I am new to Simulink so please go easy on me. I am trying to implement this particular example using system objects from the related toolboxes.
https://www.mathworks.com/help/phased/ug/integrated-sensing-and-communication-2-communication-centric-approach-using-mimo-ofdm.html
I have tried using different transmitters available but it does not seem to work. Any idea to create the Tx/Rx arras and set their locations? Thanks.Hello, I am new to Simulink so please go easy on me. I am trying to implement this particular example using system objects from the related toolboxes.
https://www.mathworks.com/help/phased/ug/integrated-sensing-and-communication-2-communication-centric-approach-using-mimo-ofdm.html
I have tried using different transmitters available but it does not seem to work. Any idea to create the Tx/Rx arras and set their locations? Thanks. Hello, I am new to Simulink so please go easy on me. I am trying to implement this particular example using system objects from the related toolboxes.
https://www.mathworks.com/help/phased/ug/integrated-sensing-and-communication-2-communication-centric-approach-using-mimo-ofdm.html
I have tried using different transmitters available but it does not seem to work. Any idea to create the Tx/Rx arras and set their locations? Thanks. simulink, phased array MATLAB Answers — New Questions

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