Hi,
after new instalation of MATLAB 2025b my program does not use function plot properly.
After command "plot(x)" MATLAB opens new window "Figures" as usual but there is no figure.
After this line program continues execution.
I could not find the explanation jet.
Thanks!Hi,
after new instalation of MATLAB 2025b my program does not use function plot properly.
After command "plot(x)" MATLAB opens new window "Figures" as usual but there is no figure.
After this line program continues execution.
I could not find the explanation jet.
Thanks! Hi,
after new instalation of MATLAB 2025b my program does not use function plot properly.
After command "plot(x)" MATLAB opens new window "Figures" as usual but there is no figure.
After this line program continues execution.
I could not find the explanation jet.
Thanks! plot, figures MATLAB Answers — New Questions

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Only version 2026a appears available for download as a trial.
I want version 2025b, but it does not appear as an option at https://www.mathworks.com/downloads/web_downloads/13799194.Only version 2026a appears available for download as a trial.
I want version 2025b, but it does not appear as an option at https://www.mathworks.com/downloads/web_downloads/13799194. Only version 2026a appears available for download as a trial.
I want version 2025b, but it does not appear as an option at https://www.mathworks.com/downloads/web_downloads/13799194. r2025a MATLAB Answers — New Questions

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I have hundreds of RGB images (one of the image is attached). For reference these are interference images and the RGB color values correspond to certain film thickness between a semi reflective glass surface and a steel surface. I apply electric potential across the surface and observed electric discharges which show as bright spots on the image (highlighted in red circle in attached image).
I want to write a script in MATLAB (2023a) that goes through the images, identify these bright spots stores there location in the XY cordinate system. The end goal is to show spatial distribution of the electric discharges.I have hundreds of RGB images (one of the image is attached). For reference these are interference images and the RGB color values correspond to certain film thickness between a semi reflective glass surface and a steel surface. I apply electric potential across the surface and observed electric discharges which show as bright spots on the image (highlighted in red circle in attached image).
I want to write a script in MATLAB (2023a) that goes through the images, identify these bright spots stores there location in the XY cordinate system. The end goal is to show spatial distribution of the electric discharges. I have hundreds of RGB images (one of the image is attached). For reference these are interference images and the RGB color values correspond to certain film thickness between a semi reflective glass surface and a steel surface. I apply electric potential across the surface and observed electric discharges which show as bright spots on the image (highlighted in red circle in attached image).
I want to write a script in MATLAB (2023a) that goes through the images, identify these bright spots stores there location in the XY cordinate system. The end goal is to show spatial distribution of the electric discharges. image analysis, image processing MATLAB Answers — New Questions

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Hello,

I am comparing two control strategies: one with fixed switching frequency and another with variable switching frequency.

Is it acceptable to use different powergui or sample times for each method so that both operate at a similar switching frequency range before comparing torque ripple?

Or should the same sample time always be used for both methods, even if their switching frequencies become very different?

Thank you.Hello,

I am comparing two control strategies: one with fixed switching frequency and another with variable switching frequency.

Is it acceptable to use different powergui or sample times for each method so that both operate at a similar switching frequency range before comparing torque ripple?

Or should the same sample time always be used for both methods, even if their switching frequencies become very different?

Thank you. Hello,

I am comparing two control strategies: one with fixed switching frequency and another with variable switching frequency.

Is it acceptable to use different powergui or sample times for each method so that both operate at a similar switching frequency range before comparing torque ripple?

Or should the same sample time always be used for both methods, even if their switching frequencies become very different?

Thank you. powergui, simulink, sample time, switching frequency MATLAB Answers — New Questions

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The code for the textscatter example at
textscatter – 2-D scatter plot of text – MATLAB
looks like it should produce text at those random points. Instead the figure there shows some text in unusual places, some points that dont belong to any specific label, and in general, the whole thing is mysterious.The code for the textscatter example at
textscatter – 2-D scatter plot of text – MATLAB
looks like it should produce text at those random points. Instead the figure there shows some text in unusual places, some points that dont belong to any specific label, and in general, the whole thing is mysterious. The code for the textscatter example at
textscatter – 2-D scatter plot of text – MATLAB
looks like it should produce text at those random points. Instead the figure there shows some text in unusual places, some points that dont belong to any specific label, and in general, the whole thing is mysterious. textscatter MATLAB Answers — New Questions

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I am trying to calculate small numbers from equations like the one below.

p = -1e17 + sqrt(1e34 + 1e18)

I have tried using ‘vpa(-1e17 + sqrt(1e34 + 1e18), 30) but the output always comes out as p = 0.0. But p is not exactly zero and this propagates errors in subsequent calculations that involve p. Is there another way to retain sig figs to avoid rounding errors?I am trying to calculate small numbers from equations like the one below.

p = -1e17 + sqrt(1e34 + 1e18)

I have tried using ‘vpa(-1e17 + sqrt(1e34 + 1e18), 30) but the output always comes out as p = 0.0. But p is not exactly zero and this propagates errors in subsequent calculations that involve p. Is there another way to retain sig figs to avoid rounding errors? I am trying to calculate small numbers from equations like the one below.

p = -1e17 + sqrt(1e34 + 1e18)

I have tried using ‘vpa(-1e17 + sqrt(1e34 + 1e18), 30) but the output always comes out as p = 0.0. But p is not exactly zero and this propagates errors in subsequent calculations that involve p. Is there another way to retain sig figs to avoid rounding errors? precision, digits MATLAB Answers — New Questions

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tic
syms x y m %alpha beta b lambda eta phi
phi=sqrt(0.5)
b=10
eta=1
alpha=2;
beta=1;
T=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
A=zeros(1,’sym’);
B=zeros(1,’sym’);
C=zeros(1,’sym’);
D=zeros(1,’sym’);
E=zeros(1,’sym’);
F=zeros(1,’sym’);
G_val=zeros(1,’sym’);
series(x)=sym(zeros(1,1));
series1(x)=sym(zeros(1,1));
% Transform Initial condition
T(1)=m;
T(2)=0;
% Initial transform value of exp function

for i=1:4
G(i)=y;
if i==1
E(1)=exp((eta*T(1))/(eta+T(1)));
else
A(1)=0;
for j=1:i-1
E(i)=A(1)+(j/(i-1))*G(j)*E(i-j);
end
B(1)=0;
for j=1:i
B(1)=B(1)+T(j)*G(i-j+1);
end
eq1=G(i)-T(i)+(1/eta)*B(1);
G_val=simplify(solve(eq1,y));
G(i)=simplify(G_val);
E_val=subs(E(i),y,G_val);
E(i)=E_val
end
C(1)=0
for r=1:i
C(1)=C(1)+T(r)*E(i-r+1);
end
T(i + alpha*beta) = (phi^2*C(1)-b*phi^2*E(i))*(gamma(1+(sym(i-1)/beta))/gamma(1+alpha+(sym(i-1)/beta)));
%T(i+2)=simplify((1/(i*(i+1)))*(phi^2*C(1)-b*phi^2*E(i)));
end

for k=1:3
series(x)=simplify(series(x)+T(k)*(power(x,((k-1)*beta))));
end
series
e1=subs(series,x,1);
format long
accuracy=input(‘enter the accuracy’)
f=e1(x)
g=inline(f)
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
while fa*fb>0
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
end
for i=1:50
c=(a+b)/2;
fc=feval(g,c);
disp([i a fa b fb c fc abs(b-a)])
if fc==accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif abs(b-a)<=accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif fa*fc<=0
b=c;
fb=fc;
else
a=c;
fa=fc;
end
end
fprintf(‘the value of c=%f’, c);
series1(x)=subs(series,m,c)
residualError=sym(zeros(1,1));
residual=sym(zeros(1,1));
residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1)))
residual_error=double(subs(residualError,x,0.2))
var =double(residual_error);
x=0:0.1:1
error=zeros(1)
row=0;
for i=1:length(x)
row=row+1;
error(row)=(residualErrorx(i))
max_error=max(error)
end
fprintf(‘The residual error is %fn’, max_error);
%—————————————————————–
the error appear as Error using mupadengine/evalin2double
Unable to convert expression containing symbolic variables into double array. Apply ‘subs’ function first to substitute values for variables.

Error in mupadengine/feval2double

Error in sym/double (line 756)
X = feval2double(symengine, "symobj::doubleDirect", S);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Related documentation
now i substutite the value of m using sysntax series1(x)=subs(series,m,c) but when i later on call series 1 in line residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1))) the final expression is having m and y . That is symbolic and craet an errortic
syms x y m %alpha beta b lambda eta phi
phi=sqrt(0.5)
b=10
eta=1
alpha=2;
beta=1;
T=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
A=zeros(1,’sym’);
B=zeros(1,’sym’);
C=zeros(1,’sym’);
D=zeros(1,’sym’);
E=zeros(1,’sym’);
F=zeros(1,’sym’);
G_val=zeros(1,’sym’);
series(x)=sym(zeros(1,1));
series1(x)=sym(zeros(1,1));
% Transform Initial condition
T(1)=m;
T(2)=0;
% Initial transform value of exp function

for i=1:4
G(i)=y;
if i==1
E(1)=exp((eta*T(1))/(eta+T(1)));
else
A(1)=0;
for j=1:i-1
E(i)=A(1)+(j/(i-1))*G(j)*E(i-j);
end
B(1)=0;
for j=1:i
B(1)=B(1)+T(j)*G(i-j+1);
end
eq1=G(i)-T(i)+(1/eta)*B(1);
G_val=simplify(solve(eq1,y));
G(i)=simplify(G_val);
E_val=subs(E(i),y,G_val);
E(i)=E_val
end
C(1)=0
for r=1:i
C(1)=C(1)+T(r)*E(i-r+1);
end
T(i + alpha*beta) = (phi^2*C(1)-b*phi^2*E(i))*(gamma(1+(sym(i-1)/beta))/gamma(1+alpha+(sym(i-1)/beta)));
%T(i+2)=simplify((1/(i*(i+1)))*(phi^2*C(1)-b*phi^2*E(i)));
end

for k=1:3
series(x)=simplify(series(x)+T(k)*(power(x,((k-1)*beta))));
end
series
e1=subs(series,x,1);
format long
accuracy=input(‘enter the accuracy’)
f=e1(x)
g=inline(f)
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
while fa*fb>0
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
end
for i=1:50
c=(a+b)/2;
fc=feval(g,c);
disp([i a fa b fb c fc abs(b-a)])
if fc==accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif abs(b-a)<=accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif fa*fc<=0
b=c;
fb=fc;
else
a=c;
fa=fc;
end
end
fprintf(‘the value of c=%f’, c);
series1(x)=subs(series,m,c)
residualError=sym(zeros(1,1));
residual=sym(zeros(1,1));
residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1)))
residual_error=double(subs(residualError,x,0.2))
var =double(residual_error);
x=0:0.1:1
error=zeros(1)
row=0;
for i=1:length(x)
row=row+1;
error(row)=(residualErrorx(i))
max_error=max(error)
end
fprintf(‘The residual error is %fn’, max_error);
%—————————————————————–
the error appear as Error using mupadengine/evalin2double
Unable to convert expression containing symbolic variables into double array. Apply ‘subs’ function first to substitute values for variables.

Error in mupadengine/feval2double

Error in sym/double (line 756)
X = feval2double(symengine, "symobj::doubleDirect", S);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Related documentation
now i substutite the value of m using sysntax series1(x)=subs(series,m,c) but when i later on call series 1 in line residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1))) the final expression is having m and y . That is symbolic and craet an error tic
syms x y m %alpha beta b lambda eta phi
phi=sqrt(0.5)
b=10
eta=1
alpha=2;
beta=1;
T=zeros(1,2,’sym’);
G=zeros(1,2,’sym’);
A=zeros(1,’sym’);
B=zeros(1,’sym’);
C=zeros(1,’sym’);
D=zeros(1,’sym’);
E=zeros(1,’sym’);
F=zeros(1,’sym’);
G_val=zeros(1,’sym’);
series(x)=sym(zeros(1,1));
series1(x)=sym(zeros(1,1));
% Transform Initial condition
T(1)=m;
T(2)=0;
% Initial transform value of exp function

for i=1:4
G(i)=y;
if i==1
E(1)=exp((eta*T(1))/(eta+T(1)));
else
A(1)=0;
for j=1:i-1
E(i)=A(1)+(j/(i-1))*G(j)*E(i-j);
end
B(1)=0;
for j=1:i
B(1)=B(1)+T(j)*G(i-j+1);
end
eq1=G(i)-T(i)+(1/eta)*B(1);
G_val=simplify(solve(eq1,y));
G(i)=simplify(G_val);
E_val=subs(E(i),y,G_val);
E(i)=E_val
end
C(1)=0
for r=1:i
C(1)=C(1)+T(r)*E(i-r+1);
end
T(i + alpha*beta) = (phi^2*C(1)-b*phi^2*E(i))*(gamma(1+(sym(i-1)/beta))/gamma(1+alpha+(sym(i-1)/beta)));
%T(i+2)=simplify((1/(i*(i+1)))*(phi^2*C(1)-b*phi^2*E(i)));
end

for k=1:3
series(x)=simplify(series(x)+T(k)*(power(x,((k-1)*beta))));
end
series
e1=subs(series,x,1);
format long
accuracy=input(‘enter the accuracy’)
f=e1(x)
g=inline(f)
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
while fa*fb>0
a=input(‘enter the ist approximation=’)
b=input(‘enter the 2nd approximation=’)
fa=feval(g,a)
fb=feval(g,b)
end
for i=1:50
c=(a+b)/2;
fc=feval(g,c);
disp([i a fa b fb c fc abs(b-a)])
if fc==accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif abs(b-a)<=accuracy
fprintf(‘the root of the equation is %f’,c)
break;
elseif fa*fc<=0
b=c;
fb=fc;
else
a=c;
fa=fc;
end
end
fprintf(‘the value of c=%f’, c);
series1(x)=subs(series,m,c)
residualError=sym(zeros(1,1));
residual=sym(zeros(1,1));
residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1)))
residual_error=double(subs(residualError,x,0.2))
var =double(residual_error);
x=0:0.1:1
error=zeros(1)
row=0;
for i=1:length(x)
row=row+1;
error(row)=(residualErrorx(i))
max_error=max(error)
end
fprintf(‘The residual error is %fn’, max_error);
%—————————————————————–
the error appear as Error using mupadengine/evalin2double
Unable to convert expression containing symbolic variables into double array. Apply ‘subs’ function first to substitute values for variables.

Error in mupadengine/feval2double

Error in sym/double (line 756)
X = feval2double(symengine, "symobj::doubleDirect", S);
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
Related documentation
now i substutite the value of m using sysntax series1(x)=subs(series,m,c) but when i later on call series 1 in line residualError(x) = abs(diff(series1,x,2)+ B*phi^2*(1-(series1)/B)*exp((eta*series1)/(eta+series1))) the final expression is having m and y . That is symbolic and craet an error symbolic compuational MATLAB Answers — New Questions

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I need to perform phase unwrapping in 2D using MATLAB, but the unwrap function seems to work only in 1D.
I want to have a routine similar to this one, available in a Python library:
http://scikit-image.org/docs/dev/auto_examples/filters/plot_phase_unwrap.html
Any suggestions?I need to perform phase unwrapping in 2D using MATLAB, but the unwrap function seems to work only in 1D.
I want to have a routine similar to this one, available in a Python library:
http://scikit-image.org/docs/dev/auto_examples/filters/plot_phase_unwrap.html
Any suggestions? I need to perform phase unwrapping in 2D using MATLAB, but the unwrap function seems to work only in 1D.
I want to have a routine similar to this one, available in a Python library:
http://scikit-image.org/docs/dev/auto_examples/filters/plot_phase_unwrap.html
Any suggestions? matlab, image analysis, signal processing MATLAB Answers — New Questions

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How do I create a protected model with hidden variables with a mask that provides additional variables? I want to hide the variables I provide to Simulink that would otherwise appear in the base (MATLAB) workspace.How do I create a protected model with hidden variables with a mask that provides additional variables? I want to hide the variables I provide to Simulink that would otherwise appear in the base (MATLAB) workspace. How do I create a protected model with hidden variables with a mask that provides additional variables? I want to hide the variables I provide to Simulink that would otherwise appear in the base (MATLAB) workspace. parameters, mask, modelreference, protected MATLAB Answers — New Questions

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After set all the data into int16, by using HDL coder advisor i got this error message:

"Error:Error: HDL code generation from Stateflow failed: Entry event for state ‘Target_Search’ implied in ‘aero_guidance_model/Guidance/subsystem/Guidance Processor’. This is not allowed for an HDL target.

HDL code generation failed for ‘Guidance/subsystem/Guidance Processor’ (#59). Consult the Diagnostic Viewer for additional information."

Is it possible to convert the stateflow inside guidance subsystem into HDL for running hardware in the loop? Needing advice to call a stop or continue if its possible.

Example can be obtained https://www.mathworks.com/help/simulink/slref/designing-a-guidance-system-in-matlab-and-simulink.htmlAfter set all the data into int16, by using HDL coder advisor i got this error message:

"Error:Error: HDL code generation from Stateflow failed: Entry event for state ‘Target_Search’ implied in ‘aero_guidance_model/Guidance/subsystem/Guidance Processor’. This is not allowed for an HDL target.

HDL code generation failed for ‘Guidance/subsystem/Guidance Processor’ (#59). Consult the Diagnostic Viewer for additional information."

Is it possible to convert the stateflow inside guidance subsystem into HDL for running hardware in the loop? Needing advice to call a stop or continue if its possible.

Example can be obtained https://www.mathworks.com/help/simulink/slref/designing-a-guidance-system-in-matlab-and-simulink.html After set all the data into int16, by using HDL coder advisor i got this error message:

"Error:Error: HDL code generation from Stateflow failed: Entry event for state ‘Target_Search’ implied in ‘aero_guidance_model/Guidance/subsystem/Guidance Processor’. This is not allowed for an HDL target.

HDL code generation failed for ‘Guidance/subsystem/Guidance Processor’ (#59). Consult the Diagnostic Viewer for additional information."

Is it possible to convert the stateflow inside guidance subsystem into HDL for running hardware in the loop? Needing advice to call a stop or continue if its possible.

Example can be obtained https://www.mathworks.com/help/simulink/slref/designing-a-guidance-system-in-matlab-and-simulink.html hdl coder, hardware-in-the-loop MATLAB Answers — New Questions

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