Cuando intento abrir el programa, no hace absolutamente nada. No da codigo de error, no abre ninguna ventana, solo queda como si no lo hubiera tocado. Como puedo solucionar éste problema?Cuando intento abrir el programa, no hace absolutamente nada. No da codigo de error, no abre ninguna ventana, solo queda como si no lo hubiera tocado. Como puedo solucionar éste problema? Cuando intento abrir el programa, no hace absolutamente nada. No da codigo de error, no abre ninguna ventana, solo queda como si no lo hubiera tocado. Como puedo solucionar éste problema? inicio fallido MATLAB Answers — New Questions

​

I am using a newport power meter (91936-R) with RS232. I set up the communication with the following code beow. I am running into a weird situation.
The readlinerespone is The first is ""PM:CALDATE?" However when I send the readline command again I get the right response "30NOV2022". Its almost like readline stops once it reaches the first termination character and doesnt continue. I tried adding a pause incase I am reading the port too fast but no sucess.

I am not sure and matlab doesnt have more documention online on serial port so I was hoping someone can answer this.

clear s
clear all
s = serialport("COM12",38400);
configureTerminator(s,"CR/LF","CR");
writeline(s,"PM:CALDATE?")
% pause(4)
readline(s)
%readline(s)I am using a newport power meter (91936-R) with RS232. I set up the communication with the following code beow. I am running into a weird situation.
The readlinerespone is The first is ""PM:CALDATE?" However when I send the readline command again I get the right response "30NOV2022". Its almost like readline stops once it reaches the first termination character and doesnt continue. I tried adding a pause incase I am reading the port too fast but no sucess.

I am not sure and matlab doesnt have more documention online on serial port so I was hoping someone can answer this.

clear s
clear all
s = serialport("COM12",38400);
configureTerminator(s,"CR/LF","CR");
writeline(s,"PM:CALDATE?")
% pause(4)
readline(s)
%readline(s) I am using a newport power meter (91936-R) with RS232. I set up the communication with the following code beow. I am running into a weird situation.
The readlinerespone is The first is ""PM:CALDATE?" However when I send the readline command again I get the right response "30NOV2022". Its almost like readline stops once it reaches the first termination character and doesnt continue. I tried adding a pause incase I am reading the port too fast but no sucess.

I am not sure and matlab doesnt have more documention online on serial port so I was hoping someone can answer this.

clear s
clear all
s = serialport("COM12",38400);
configureTerminator(s,"CR/LF","CR");
writeline(s,"PM:CALDATE?")
% pause(4)
readline(s)
%readline(s) serial, readline, writeline MATLAB Answers — New Questions

​

I want to perform 3D integrations of some functions over a region defined by the following 16 planes. As an example, consider the function . The region is bounded by:
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
8 planes which are penpendicular to the vectors – given in below code at mid point of these vector ().
Code to visulize the last 8 planes. First 8 planes are quite eays to imagine.
clear; clc;

figure; hold on;
axis([-1 1 -1 1 -1 1])

% function to calculate the 8 vectors:
f = @(vec) vec(1)*[-1 1 1] + vec(2)*[1 -1 1] + vec(3)*[1 1 -1];

% 8 vectors:
v1 = f([1, 1, 1]);
v2 = f([-1, -1, -1]);
v3 = f([0, 1, 0]);
v4 = f([0, -1, 0]);
v5 = f([0, 0, 1]);
v6 = f([0, 0, -1]);
v7 = f([1, 0, 0]);
v8 = f([-1, 0, 0]);

% draw planes perpendicular to v vectors at v/2 point:
draw_plane(v1)
draw_plane(v2)
draw_plane(v3)
draw_plane(v4)
draw_plane(v5)
draw_plane(v6)
draw_plane(v7)
draw_plane(v8)

xlabel(‘x’);
ylabel(‘y’);
zlabel(‘z’);
box on;
set(gca,’fontname’,’times’,’fontsize’,16)
view([-21 19])
hold off;

function [] = draw_plane(v)

% I took this algorithem from ChatGPT to draw a plane perpendicular to v

plane_size = 3;
midpoint = v./2;
normal_vector = v / norm(v);
perpendicular_vectors = null(normal_vector)’;

[t1, t2] = meshgrid(linspace(-plane_size, plane_size, 100));
plane_points = midpoint + t1(:) * perpendicular_vectors(1,:) + t2(:) * perpendicular_vectors(2,:);
X = reshape(plane_points(:,1), size(t1));
Y = reshape(plane_points(:,2), size(t1));
Z = reshape(plane_points(:,3), size(t1));
surf(X, Y, Z, ‘FaceAlpha’, 0.5, ‘EdgeColor’, ‘none’);
plot3(midpoint(1), midpoint(2), midpoint(3), ‘go’, ‘MarkerSize’, 10, ‘MarkerFaceColor’, ‘g’);
text(midpoint(1), midpoint(2), midpoint(3), [‘(‘,num2str(v(1)),’,’,num2str(v(2)),’,’,num2str(v(3)),’)’]);

endI want to perform 3D integrations of some functions over a region defined by the following 16 planes. As an example, consider the function . The region is bounded by:
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
8 planes which are penpendicular to the vectors – given in below code at mid point of these vector ().
Code to visulize the last 8 planes. First 8 planes are quite eays to imagine.
clear; clc;

figure; hold on;
axis([-1 1 -1 1 -1 1])

% function to calculate the 8 vectors:
f = @(vec) vec(1)*[-1 1 1] + vec(2)*[1 -1 1] + vec(3)*[1 1 -1];

% 8 vectors:
v1 = f([1, 1, 1]);
v2 = f([-1, -1, -1]);
v3 = f([0, 1, 0]);
v4 = f([0, -1, 0]);
v5 = f([0, 0, 1]);
v6 = f([0, 0, -1]);
v7 = f([1, 0, 0]);
v8 = f([-1, 0, 0]);

% draw planes perpendicular to v vectors at v/2 point:
draw_plane(v1)
draw_plane(v2)
draw_plane(v3)
draw_plane(v4)
draw_plane(v5)
draw_plane(v6)
draw_plane(v7)
draw_plane(v8)

xlabel(‘x’);
ylabel(‘y’);
zlabel(‘z’);
box on;
set(gca,’fontname’,’times’,’fontsize’,16)
view([-21 19])
hold off;

function [] = draw_plane(v)

% I took this algorithem from ChatGPT to draw a plane perpendicular to v

plane_size = 3;
midpoint = v./2;
normal_vector = v / norm(v);
perpendicular_vectors = null(normal_vector)’;

[t1, t2] = meshgrid(linspace(-plane_size, plane_size, 100));
plane_points = midpoint + t1(:) * perpendicular_vectors(1,:) + t2(:) * perpendicular_vectors(2,:);
X = reshape(plane_points(:,1), size(t1));
Y = reshape(plane_points(:,2), size(t1));
Z = reshape(plane_points(:,3), size(t1));
surf(X, Y, Z, ‘FaceAlpha’, 0.5, ‘EdgeColor’, ‘none’);
plot3(midpoint(1), midpoint(2), midpoint(3), ‘go’, ‘MarkerSize’, 10, ‘MarkerFaceColor’, ‘g’);
text(midpoint(1), midpoint(2), midpoint(3), [‘(‘,num2str(v(1)),’,’,num2str(v(2)),’,’,num2str(v(3)),’)’]);

end I want to perform 3D integrations of some functions over a region defined by the following 16 planes. As an example, consider the function . The region is bounded by:
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
2 planes parallel to -plane at and .
8 planes which are penpendicular to the vectors – given in below code at mid point of these vector ().
Code to visulize the last 8 planes. First 8 planes are quite eays to imagine.
clear; clc;

figure; hold on;
axis([-1 1 -1 1 -1 1])

% function to calculate the 8 vectors:
f = @(vec) vec(1)*[-1 1 1] + vec(2)*[1 -1 1] + vec(3)*[1 1 -1];

% 8 vectors:
v1 = f([1, 1, 1]);
v2 = f([-1, -1, -1]);
v3 = f([0, 1, 0]);
v4 = f([0, -1, 0]);
v5 = f([0, 0, 1]);
v6 = f([0, 0, -1]);
v7 = f([1, 0, 0]);
v8 = f([-1, 0, 0]);

% draw planes perpendicular to v vectors at v/2 point:
draw_plane(v1)
draw_plane(v2)
draw_plane(v3)
draw_plane(v4)
draw_plane(v5)
draw_plane(v6)
draw_plane(v7)
draw_plane(v8)

xlabel(‘x’);
ylabel(‘y’);
zlabel(‘z’);
box on;
set(gca,’fontname’,’times’,’fontsize’,16)
view([-21 19])
hold off;

function [] = draw_plane(v)

% I took this algorithem from ChatGPT to draw a plane perpendicular to v

plane_size = 3;
midpoint = v./2;
normal_vector = v / norm(v);
perpendicular_vectors = null(normal_vector)’;

[t1, t2] = meshgrid(linspace(-plane_size, plane_size, 100));
plane_points = midpoint + t1(:) * perpendicular_vectors(1,:) + t2(:) * perpendicular_vectors(2,:);
X = reshape(plane_points(:,1), size(t1));
Y = reshape(plane_points(:,2), size(t1));
Z = reshape(plane_points(:,3), size(t1));
surf(X, Y, Z, ‘FaceAlpha’, 0.5, ‘EdgeColor’, ‘none’);
plot3(midpoint(1), midpoint(2), midpoint(3), ‘go’, ‘MarkerSize’, 10, ‘MarkerFaceColor’, ‘g’);
text(midpoint(1), midpoint(2), midpoint(3), [‘(‘,num2str(v(1)),’,’,num2str(v(2)),’,’,num2str(v(3)),’)’]);

end integral, integration, numerical integration MATLAB Answers — New Questions

​

I have problem when play my sound to Motu. There is "nuzzling sound" during the silence part of your audio, especially in the end of audio.
original audio
after_played_to_16ch

Am I correctly use this code to play in using Motu?

I don’t have any issue when I play directly from Audacity or Reaper.

Thanks

% Define the file and volume settings
audioFile = ‘chapel2m_0_order3_02_eight_new_shoes.wav’; % Path to your audio file
volumeLevel = 0.01; % Desired volume level (0 to 1)

% Get audio file information
info = audioinfo(audioFile);
fs = info.TotalSamples / info.Duration; % Sample rate of the audio file
numChannels = info.NumChannels; % Number of channels in the audio file

% Create an audio file reader
fileReader = dsp.AudioFileReader(audioFile, ‘PlayCount’, Inf);
fileReader.SamplesPerFrame = 8192; % Larger buffer size to avoid underflow/overflow

% Create an audio device writer with ASIO driver and MOTU Pro Audio device
deviceWriter = audioDeviceWriter(‘Driver’, ‘ASIO’, ‘Device’, ‘MOTU Pro Audio’, …
‘SampleRate’, fs, ‘ChannelMappingSource’, ‘Auto’);

% Setup the audio device writer with the correct sample rate and channel mapping
setup(deviceWriter, zeros(fileReader.SamplesPerFrame, numChannels));

% Process and play the audio
while ~isDone(fileReader)
% Read audio data
audioData = fileReader();

% Adjust the audio data by the volume level
audioData = audioData * volumeLevel;

% Write the adjusted audio data to the device
deviceWriter(audioData);
end

% Release resources
release(fileReader);
release(deviceWriter);I have problem when play my sound to Motu. There is "nuzzling sound" during the silence part of your audio, especially in the end of audio.
original audio
after_played_to_16ch

Am I correctly use this code to play in using Motu?

I don’t have any issue when I play directly from Audacity or Reaper.

Thanks

% Define the file and volume settings
audioFile = ‘chapel2m_0_order3_02_eight_new_shoes.wav’; % Path to your audio file
volumeLevel = 0.01; % Desired volume level (0 to 1)

% Get audio file information
info = audioinfo(audioFile);
fs = info.TotalSamples / info.Duration; % Sample rate of the audio file
numChannels = info.NumChannels; % Number of channels in the audio file

% Create an audio file reader
fileReader = dsp.AudioFileReader(audioFile, ‘PlayCount’, Inf);
fileReader.SamplesPerFrame = 8192; % Larger buffer size to avoid underflow/overflow

% Create an audio device writer with ASIO driver and MOTU Pro Audio device
deviceWriter = audioDeviceWriter(‘Driver’, ‘ASIO’, ‘Device’, ‘MOTU Pro Audio’, …
‘SampleRate’, fs, ‘ChannelMappingSource’, ‘Auto’);

% Setup the audio device writer with the correct sample rate and channel mapping
setup(deviceWriter, zeros(fileReader.SamplesPerFrame, numChannels));

% Process and play the audio
while ~isDone(fileReader)
% Read audio data
audioData = fileReader();

% Adjust the audio data by the volume level
audioData = audioData * volumeLevel;

% Write the adjusted audio data to the device
deviceWriter(audioData);
end

% Release resources
release(fileReader);
release(deviceWriter); I have problem when play my sound to Motu. There is "nuzzling sound" during the silence part of your audio, especially in the end of audio.
original audio
after_played_to_16ch

Am I correctly use this code to play in using Motu?

I don’t have any issue when I play directly from Audacity or Reaper.

Thanks

% Define the file and volume settings
audioFile = ‘chapel2m_0_order3_02_eight_new_shoes.wav’; % Path to your audio file
volumeLevel = 0.01; % Desired volume level (0 to 1)

% Get audio file information
info = audioinfo(audioFile);
fs = info.TotalSamples / info.Duration; % Sample rate of the audio file
numChannels = info.NumChannels; % Number of channels in the audio file

% Create an audio file reader
fileReader = dsp.AudioFileReader(audioFile, ‘PlayCount’, Inf);
fileReader.SamplesPerFrame = 8192; % Larger buffer size to avoid underflow/overflow

% Create an audio device writer with ASIO driver and MOTU Pro Audio device
deviceWriter = audioDeviceWriter(‘Driver’, ‘ASIO’, ‘Device’, ‘MOTU Pro Audio’, …
‘SampleRate’, fs, ‘ChannelMappingSource’, ‘Auto’);

% Setup the audio device writer with the correct sample rate and channel mapping
setup(deviceWriter, zeros(fileReader.SamplesPerFrame, numChannels));

% Process and play the audio
while ~isDone(fileReader)
% Read audio data
audioData = fileReader();

% Adjust the audio data by the volume level
audioData = audioData * volumeLevel;

% Write the adjusted audio data to the device
deviceWriter(audioData);
end

% Release resources
release(fileReader);
release(deviceWriter); audio, motu, 16-channel MATLAB Answers — New Questions

​

Greetings
I’m working on deploying deep learning on raspberry pi 4 with matlab version 2024a. I’m facing timeout error when output of entry-point function with PIL configuration is vector. however when configuration is mex, the code has successfully implemtned. Simple code below can demonstrate the issue.

Kindly, how the code with PIL configuration can be fixed so that the output from entry-point function is vector or matrix ?
the driver for this request is described in more details in my case study below.

% raspberry connection and configuration
r = raspi(‘raspberrypi’,’pi’,’raspberry’);

cfg = coder.config(‘lib’,’ecoder’,true);
cfg.VerificationMode = ‘PIL’;
cfg.TargetLang = ‘C++’;

dlcfg = coder.DeepLearningConfig(‘arm-compute’);
dlcfg.ArmComputeVersion = ‘20.02.1’;
dlcfg.ArmArchitecture = ‘armv7’;
cfg.DeepLearningConfig = dlcfg;
cfg.MATLABSourceComments = 1;

hw = coder.hardware(‘Raspberry Pi’);
cfg.Hardware = hw;
cfg.CodeExecutionProfiling = true;

Case 1: with mex configuration, successfuly implemented
type dummy

t = ones(1,3);
codegen dummy -args {t} -report -config:mex

% testing deployement
x=[1,2,3];
testDummy= dummy_mex(x);

Case 2: with pil configuraiton, timeout error generated
type dummy

cfg.Hardware.BuildDir = ‘~/dummy’;
t = ones(1,3);
codegen dummy -args {t} -report -config cfg

% testing deployement
x=[1,2,3];
testDummy= dummy_pil(x);
entry-point function
function out = dummy(in)
%#codegen
out = in;
end

Case Study
my case study has raw data consists of 8 channels where I need to extract features from wavelet scattering network then pass them into trained lstm network. My code is similar to the below example, but the difference is my input raw data is 8 channels, while the example is one channel. openExample(‘wavelet/CodeGenerationForFaultDetectionUsingWaveletAndRNNExample’).
I’m getting the below error:
Number of features of input passed to the predict method must be a code generation time constant

So, I decided to breakdown entry-point function into two functions for easier troubleshooting. First featureFunction is to extract wavelet features from raw data (batch: 500samples x 8 channels), the second predictFunction is to take the generated wavelet features (32 C x 102 T) into trained lstm network.
prdictFunction_pil worked find which accept input size (32 x 102), and get predicted labels.
featureFunction_pil gives the below error
Error using rtw.pil.SILPILInterface.throwMException (line 1774)
The timeout of 300 seconds for receiving data from the rtiostream interface has been exceeded. There might be multiple reasons for this communications failure.

You should:
(a) Check that the target hardware configuration is correct, for example, check that the byte ordering is correct.
(b) Confirm that the target application is running on the target hardware.
(c) Consider the possibility of application run-time failures (e.g. divide by zero exceptions, incorrect custom code integration, etc.).
Note (c): To identify possible reasons for the run-time failure, consider using SIL, which supports signal handlers and debugging.
If you cannot find a solution, consider using the method setTimeoutRecvSecs of rtw.connectivity.RtIOStreamHostCommunicator to increase the timeout value.Greetings
I’m working on deploying deep learning on raspberry pi 4 with matlab version 2024a. I’m facing timeout error when output of entry-point function with PIL configuration is vector. however when configuration is mex, the code has successfully implemtned. Simple code below can demonstrate the issue.

Kindly, how the code with PIL configuration can be fixed so that the output from entry-point function is vector or matrix ?
the driver for this request is described in more details in my case study below.

% raspberry connection and configuration
r = raspi(‘raspberrypi’,’pi’,’raspberry’);

cfg = coder.config(‘lib’,’ecoder’,true);
cfg.VerificationMode = ‘PIL’;
cfg.TargetLang = ‘C++’;

dlcfg = coder.DeepLearningConfig(‘arm-compute’);
dlcfg.ArmComputeVersion = ‘20.02.1’;
dlcfg.ArmArchitecture = ‘armv7’;
cfg.DeepLearningConfig = dlcfg;
cfg.MATLABSourceComments = 1;

hw = coder.hardware(‘Raspberry Pi’);
cfg.Hardware = hw;
cfg.CodeExecutionProfiling = true;

Case 1: with mex configuration, successfuly implemented
type dummy

t = ones(1,3);
codegen dummy -args {t} -report -config:mex

% testing deployement
x=[1,2,3];
testDummy= dummy_mex(x);

Case 2: with pil configuraiton, timeout error generated
type dummy

cfg.Hardware.BuildDir = ‘~/dummy’;
t = ones(1,3);
codegen dummy -args {t} -report -config cfg

% testing deployement
x=[1,2,3];
testDummy= dummy_pil(x);
entry-point function
function out = dummy(in)
%#codegen
out = in;
end

Case Study
my case study has raw data consists of 8 channels where I need to extract features from wavelet scattering network then pass them into trained lstm network. My code is similar to the below example, but the difference is my input raw data is 8 channels, while the example is one channel. openExample(‘wavelet/CodeGenerationForFaultDetectionUsingWaveletAndRNNExample’).
I’m getting the below error:
Number of features of input passed to the predict method must be a code generation time constant

So, I decided to breakdown entry-point function into two functions for easier troubleshooting. First featureFunction is to extract wavelet features from raw data (batch: 500samples x 8 channels), the second predictFunction is to take the generated wavelet features (32 C x 102 T) into trained lstm network.
prdictFunction_pil worked find which accept input size (32 x 102), and get predicted labels.
featureFunction_pil gives the below error
Error using rtw.pil.SILPILInterface.throwMException (line 1774)
The timeout of 300 seconds for receiving data from the rtiostream interface has been exceeded. There might be multiple reasons for this communications failure.

You should:
(a) Check that the target hardware configuration is correct, for example, check that the byte ordering is correct.
(b) Confirm that the target application is running on the target hardware.
(c) Consider the possibility of application run-time failures (e.g. divide by zero exceptions, incorrect custom code integration, etc.).
Note (c): To identify possible reasons for the run-time failure, consider using SIL, which supports signal handlers and debugging.
If you cannot find a solution, consider using the method setTimeoutRecvSecs of rtw.connectivity.RtIOStreamHostCommunicator to increase the timeout value. Greetings
I’m working on deploying deep learning on raspberry pi 4 with matlab version 2024a. I’m facing timeout error when output of entry-point function with PIL configuration is vector. however when configuration is mex, the code has successfully implemtned. Simple code below can demonstrate the issue.

Kindly, how the code with PIL configuration can be fixed so that the output from entry-point function is vector or matrix ?
the driver for this request is described in more details in my case study below.

% raspberry connection and configuration
r = raspi(‘raspberrypi’,’pi’,’raspberry’);

cfg = coder.config(‘lib’,’ecoder’,true);
cfg.VerificationMode = ‘PIL’;
cfg.TargetLang = ‘C++’;

dlcfg = coder.DeepLearningConfig(‘arm-compute’);
dlcfg.ArmComputeVersion = ‘20.02.1’;
dlcfg.ArmArchitecture = ‘armv7’;
cfg.DeepLearningConfig = dlcfg;
cfg.MATLABSourceComments = 1;

hw = coder.hardware(‘Raspberry Pi’);
cfg.Hardware = hw;
cfg.CodeExecutionProfiling = true;

Case 1: with mex configuration, successfuly implemented
type dummy

t = ones(1,3);
codegen dummy -args {t} -report -config:mex

% testing deployement
x=[1,2,3];
testDummy= dummy_mex(x);

Case 2: with pil configuraiton, timeout error generated
type dummy

cfg.Hardware.BuildDir = ‘~/dummy’;
t = ones(1,3);
codegen dummy -args {t} -report -config cfg

% testing deployement
x=[1,2,3];
testDummy= dummy_pil(x);
entry-point function
function out = dummy(in)
%#codegen
out = in;
end

Case Study
my case study has raw data consists of 8 channels where I need to extract features from wavelet scattering network then pass them into trained lstm network. My code is similar to the below example, but the difference is my input raw data is 8 channels, while the example is one channel. openExample(‘wavelet/CodeGenerationForFaultDetectionUsingWaveletAndRNNExample’).
I’m getting the below error:
Number of features of input passed to the predict method must be a code generation time constant

So, I decided to breakdown entry-point function into two functions for easier troubleshooting. First featureFunction is to extract wavelet features from raw data (batch: 500samples x 8 channels), the second predictFunction is to take the generated wavelet features (32 C x 102 T) into trained lstm network.
prdictFunction_pil worked find which accept input size (32 x 102), and get predicted labels.
featureFunction_pil gives the below error
Error using rtw.pil.SILPILInterface.throwMException (line 1774)
The timeout of 300 seconds for receiving data from the rtiostream interface has been exceeded. There might be multiple reasons for this communications failure.

You should:
(a) Check that the target hardware configuration is correct, for example, check that the byte ordering is correct.
(b) Confirm that the target application is running on the target hardware.
(c) Consider the possibility of application run-time failures (e.g. divide by zero exceptions, incorrect custom code integration, etc.).
Note (c): To identify possible reasons for the run-time failure, consider using SIL, which supports signal handlers and debugging.
If you cannot find a solution, consider using the method setTimeoutRecvSecs of rtw.connectivity.RtIOStreamHostCommunicator to increase the timeout value. code generation, matlab coder, raspberry, deployment MATLAB Answers — New Questions

​

Hello and thank you for taking the time to read my question!
I am trying to solve a system of differential equations for analytically and then numerically for and and plot the two for comparison. I also have to analytically find tension T in terms of theta then numerically find it in terms of time. The given equations for motion in normal-tangiential form are , and . The starting position is at rad with m=2 kg, g=9.81 m/s^2, and r=0.5 m.
Below is my code so far. I keep getting an error trying to run the ode45 function saying that inputs must be floats, namely a single or double. I have to use the ode45 function as a requirment for the assignment, but I’m not sure if I have to use the eom bit.

Error:
Error using superiorfloat (line 13)
Inputs must be floats,
namely single or double.

Error in odearguments (line 114)
dataType = superiorfloat(t0,y0,f0);

Error in ode45 (line 104)
odearguments(odeIsFuncHandle,odeTreatAsMFile, solver_name, ode, tspan, y0, options, varargin);

Error in ESCI204_M1_Myers (line 74)
[T,S] = ode45(@eom,linspace(0,2,101),[0,0]);

Code:
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens theta t thetaA
thetaA = linspace(-pi/6,pi/6,101);

% % DETERMINE ANALYTICALLY:————————————————
%Equation for angular velocity in terms of theta
thetadA = sqrt((-360*g/(pi*r))*(cos(theta0)-cos(thetaA)));

%Equation for Tension in terms of theta
TensA = 3*m*g*cos(thetaA)-2*m*g;

hold on
plot(thetaA,thetadA, ‘black’) %analytical solution for thetad(theta)
xlabel(‘Angular Position (rad) or time (t)’)
ylabel(‘Angular Velocity (rad/sec)’)

% % DETERMINE NUMERICALLY:
% 1) The angular velocity and angular position of the mass about point C
% as a function of time by integration of the equation of motion, thetadd
% 2) The tension in the string as a function of time.

function ds = eom(t,s) %S is current states – vector of current position and vel
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens

ds(1,1) = sqrt((Tens-m*g*cos(s(1)))/(m*r)); % Derivative of position (s(1) = thetad
ds(2,1) = (-g*sin(s(1)))/r; % Derivative of velocity = thetadd
end

[T,S] = ode45(@eom,linspace(0,2,101),[0,0]);Hello and thank you for taking the time to read my question!
I am trying to solve a system of differential equations for analytically and then numerically for and and plot the two for comparison. I also have to analytically find tension T in terms of theta then numerically find it in terms of time. The given equations for motion in normal-tangiential form are , and . The starting position is at rad with m=2 kg, g=9.81 m/s^2, and r=0.5 m.
Below is my code so far. I keep getting an error trying to run the ode45 function saying that inputs must be floats, namely a single or double. I have to use the ode45 function as a requirment for the assignment, but I’m not sure if I have to use the eom bit.

Error:
Error using superiorfloat (line 13)
Inputs must be floats,
namely single or double.

Error in odearguments (line 114)
dataType = superiorfloat(t0,y0,f0);

Error in ode45 (line 104)
odearguments(odeIsFuncHandle,odeTreatAsMFile, solver_name, ode, tspan, y0, options, varargin);

Error in ESCI204_M1_Myers (line 74)
[T,S] = ode45(@eom,linspace(0,2,101),[0,0]);

Code:
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens theta t thetaA
thetaA = linspace(-pi/6,pi/6,101);

% % DETERMINE ANALYTICALLY:————————————————
%Equation for angular velocity in terms of theta
thetadA = sqrt((-360*g/(pi*r))*(cos(theta0)-cos(thetaA)));

%Equation for Tension in terms of theta
TensA = 3*m*g*cos(thetaA)-2*m*g;

hold on
plot(thetaA,thetadA, ‘black’) %analytical solution for thetad(theta)
xlabel(‘Angular Position (rad) or time (t)’)
ylabel(‘Angular Velocity (rad/sec)’)

% % DETERMINE NUMERICALLY:
% 1) The angular velocity and angular position of the mass about point C
% as a function of time by integration of the equation of motion, thetadd
% 2) The tension in the string as a function of time.

function ds = eom(t,s) %S is current states – vector of current position and vel
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens

ds(1,1) = sqrt((Tens-m*g*cos(s(1)))/(m*r)); % Derivative of position (s(1) = thetad
ds(2,1) = (-g*sin(s(1)))/r; % Derivative of velocity = thetadd
end

[T,S] = ode45(@eom,linspace(0,2,101),[0,0]); Hello and thank you for taking the time to read my question!
I am trying to solve a system of differential equations for analytically and then numerically for and and plot the two for comparison. I also have to analytically find tension T in terms of theta then numerically find it in terms of time. The given equations for motion in normal-tangiential form are , and . The starting position is at rad with m=2 kg, g=9.81 m/s^2, and r=0.5 m.
Below is my code so far. I keep getting an error trying to run the ode45 function saying that inputs must be floats, namely a single or double. I have to use the ode45 function as a requirment for the assignment, but I’m not sure if I have to use the eom bit.

Error:
Error using superiorfloat (line 13)
Inputs must be floats,
namely single or double.

Error in odearguments (line 114)
dataType = superiorfloat(t0,y0,f0);

Error in ode45 (line 104)
odearguments(odeIsFuncHandle,odeTreatAsMFile, solver_name, ode, tspan, y0, options, varargin);

Error in ESCI204_M1_Myers (line 74)
[T,S] = ode45(@eom,linspace(0,2,101),[0,0]);

Code:
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens theta t thetaA
thetaA = linspace(-pi/6,pi/6,101);

% % DETERMINE ANALYTICALLY:————————————————
%Equation for angular velocity in terms of theta
thetadA = sqrt((-360*g/(pi*r))*(cos(theta0)-cos(thetaA)));

%Equation for Tension in terms of theta
TensA = 3*m*g*cos(thetaA)-2*m*g;

hold on
plot(thetaA,thetadA, ‘black’) %analytical solution for thetad(theta)
xlabel(‘Angular Position (rad) or time (t)’)
ylabel(‘Angular Velocity (rad/sec)’)

% % DETERMINE NUMERICALLY:
% 1) The angular velocity and angular position of the mass about point C
% as a function of time by integration of the equation of motion, thetadd
% 2) The tension in the string as a function of time.

function ds = eom(t,s) %S is current states – vector of current position and vel
%Givens:
theta0 = -pi/6;
m = 2;
g = 9.81;
r = 0.5;
syms Tens

ds(1,1) = sqrt((Tens-m*g*cos(s(1)))/(m*r)); % Derivative of position (s(1) = thetad
ds(2,1) = (-g*sin(s(1)))/r; % Derivative of velocity = thetadd
end

[T,S] = ode45(@eom,linspace(0,2,101),[0,0]); eom, ode45, code, error MATLAB Answers — New Questions

​

i got this error while simulating how to handle this please help me out
Derivative of state ‘1’ in block ‘flowermodelmppt/PV Array/Diode Rsh/BAL/Transfer Fcn’ at time 7.5E-7 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances)i got this error while simulating how to handle this please help me out
Derivative of state ‘1’ in block ‘flowermodelmppt/PV Array/Diode Rsh/BAL/Transfer Fcn’ at time 7.5E-7 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) i got this error while simulating how to handle this please help me out
Derivative of state ‘1’ in block ‘flowermodelmppt/PV Array/Diode Rsh/BAL/Transfer Fcn’ at time 7.5E-7 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) deravative MATLAB Answers — New Questions

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Hello,
I am receiving the following error when I try to use the DLL file I compiled:
"The procedure entry point ?xxxx@@YAXHAEAVmwarray@AEBV1@ could not be located in the dynamic library xxx"
I am using deployTool GUI to compile my m file
My executable ap calling the compiled DLL is compiled using Visual Studio C++ 2017 (VS 2017. community edition):
>> mbuild -setup
MBUILD configured to use ‘Microsoft Visual C++ 2017 (C)’ for C language compilation.
The path to Matlab in Windows 10, is set to be
C:Program FilesMATLABR2024a
Since the error message mentions mwarray, do I have to use an extra compilation switch for mbuild in deployTool?
Thank you.Hello,
I am receiving the following error when I try to use the DLL file I compiled:
"The procedure entry point ?xxxx@@YAXHAEAVmwarray@AEBV1@ could not be located in the dynamic library xxx"
I am using deployTool GUI to compile my m file
My executable ap calling the compiled DLL is compiled using Visual Studio C++ 2017 (VS 2017. community edition):
>> mbuild -setup
MBUILD configured to use ‘Microsoft Visual C++ 2017 (C)’ for C language compilation.
The path to Matlab in Windows 10, is set to be
C:Program FilesMATLABR2024a
Since the error message mentions mwarray, do I have to use an extra compilation switch for mbuild in deployTool?
Thank you. Hello,
I am receiving the following error when I try to use the DLL file I compiled:
"The procedure entry point ?xxxx@@YAXHAEAVmwarray@AEBV1@ could not be located in the dynamic library xxx"
I am using deployTool GUI to compile my m file
My executable ap calling the compiled DLL is compiled using Visual Studio C++ 2017 (VS 2017. community edition):
>> mbuild -setup
MBUILD configured to use ‘Microsoft Visual C++ 2017 (C)’ for C language compilation.
The path to Matlab in Windows 10, is set to be
C:Program FilesMATLABR2024a
Since the error message mentions mwarray, do I have to use an extra compilation switch for mbuild in deployTool?
Thank you. matlab compiler, mbuild MATLAB Answers — New Questions

​

Is NPRACH Detection Example available only on R2024 version?Is NPRACH Detection Example available only on R2024 version? Is NPRACH Detection Example available only on R2024 version? lte toolbox, nb-iot, matlab, commnunication toolbox MATLAB Answers — New Questions

​

eIs there an efficient way to round decimal numbers up to the n-decimal in a cell array?
In the following example, I would like to round the decimal numbers up to n=2, i.e. to the second decimal:
a = [
{[ 0.235089379668094 0]}
{[0.0793405810870535 0]}
{[ 0.142843392632868 0]}
{[ 0.639081029130393 0]}
{[ 0.970756532033504 0]}
{[ 1 0]}]

My desired output would be the following one:
a = [
{[0.24 0]}
{[0.08 0]}
{[0.14 0]}
{[0.64 0]}
{[0.97 0]}
{[ 1 0]}]eIs there an efficient way to round decimal numbers up to the n-decimal in a cell array?
In the following example, I would like to round the decimal numbers up to n=2, i.e. to the second decimal:
a = [
{[ 0.235089379668094 0]}
{[0.0793405810870535 0]}
{[ 0.142843392632868 0]}
{[ 0.639081029130393 0]}
{[ 0.970756532033504 0]}
{[ 1 0]}]

My desired output would be the following one:
a = [
{[0.24 0]}
{[0.08 0]}
{[0.14 0]}
{[0.64 0]}
{[0.97 0]}
{[ 1 0]}] eIs there an efficient way to round decimal numbers up to the n-decimal in a cell array?
In the following example, I would like to round the decimal numbers up to n=2, i.e. to the second decimal:
a = [
{[ 0.235089379668094 0]}
{[0.0793405810870535 0]}
{[ 0.142843392632868 0]}
{[ 0.639081029130393 0]}
{[ 0.970756532033504 0]}
{[ 1 0]}]

My desired output would be the following one:
a = [
{[0.24 0]}
{[0.08 0]}
{[0.14 0]}
{[0.64 0]}
{[0.97 0]}
{[ 1 0]}] round, decimal, cell, array MATLAB Answers — New Questions

​