Hi I am trying to verify on simulations that the covariance matrix of the estimation errror is equal to the matrix P provided by the Riccati Solution of a continuous kalman filter. However when I use lsim to simulate and get the covariance of the estimator error vectors the results are different from P. But if I do P*Ts I can see the equivalence.

Why this factor Ts is appearing?
I am using the following code:

clear
close all
clc

% System

A = [-10 -20;35 -50];
B = [1; 1;];
C = [1 0];
D = 0;

Fs = 50000; % Frequency
Ts = 1/Fs; %
t = 0:Ts:10;
L = length(t);

W = [20 0;0 10];
V = 1;
rng(10,’twister’);
w = chol(W, ‘lower’)*randn(2,L);
v = chol(V, ‘lower’)*randn(1,L);

mw = mean(w,2);
mv = mean(v);

v = v – mean(v)*ones(1,length(v));
w = w – mw.*ones(2,length(v));

cov_w = cov(w’);
cov_v = cov(v);

[Lk,P] = lqe(A,eye(2),C,W,V);

% Augmented system with plant and Kalman filter

Aak = [A zeros(2,2); Lk*C A-Lk*C];
Bak = [B eye(2) zeros(2,1); B zeros(2,2) Lk];

sys_obs_mak = ss(Aak,Bak,eye(4),0);

u(1,:) = 1*heaviside(t);

[yk,t,xk] = lsim(sys_obs_mak,[u’ w’ v’],t,[0 0 0 0]); % Simulation

erro = xk(:,1:2)-xk(:,3:4);
cov_erro_lsim = cov(erro)
PTs = P*Ts
PHi I am trying to verify on simulations that the covariance matrix of the estimation errror is equal to the matrix P provided by the Riccati Solution of a continuous kalman filter. However when I use lsim to simulate and get the covariance of the estimator error vectors the results are different from P. But if I do P*Ts I can see the equivalence.

Why this factor Ts is appearing?
I am using the following code:

clear
close all
clc

% System

A = [-10 -20;35 -50];
B = [1; 1;];
C = [1 0];
D = 0;

Fs = 50000; % Frequency
Ts = 1/Fs; %
t = 0:Ts:10;
L = length(t);

W = [20 0;0 10];
V = 1;
rng(10,’twister’);
w = chol(W, ‘lower’)*randn(2,L);
v = chol(V, ‘lower’)*randn(1,L);

mw = mean(w,2);
mv = mean(v);

v = v – mean(v)*ones(1,length(v));
w = w – mw.*ones(2,length(v));

cov_w = cov(w’);
cov_v = cov(v);

[Lk,P] = lqe(A,eye(2),C,W,V);

% Augmented system with plant and Kalman filter

Aak = [A zeros(2,2); Lk*C A-Lk*C];
Bak = [B eye(2) zeros(2,1); B zeros(2,2) Lk];

sys_obs_mak = ss(Aak,Bak,eye(4),0);

u(1,:) = 1*heaviside(t);

[yk,t,xk] = lsim(sys_obs_mak,[u’ w’ v’],t,[0 0 0 0]); % Simulation

erro = xk(:,1:2)-xk(:,3:4);
cov_erro_lsim = cov(erro)
PTs = P*Ts
P Hi I am trying to verify on simulations that the covariance matrix of the estimation errror is equal to the matrix P provided by the Riccati Solution of a continuous kalman filter. However when I use lsim to simulate and get the covariance of the estimator error vectors the results are different from P. But if I do P*Ts I can see the equivalence.

Why this factor Ts is appearing?
I am using the following code:

clear
close all
clc

% System

A = [-10 -20;35 -50];
B = [1; 1;];
C = [1 0];
D = 0;

Fs = 50000; % Frequency
Ts = 1/Fs; %
t = 0:Ts:10;
L = length(t);

W = [20 0;0 10];
V = 1;
rng(10,’twister’);
w = chol(W, ‘lower’)*randn(2,L);
v = chol(V, ‘lower’)*randn(1,L);

mw = mean(w,2);
mv = mean(v);

v = v – mean(v)*ones(1,length(v));
w = w – mw.*ones(2,length(v));

cov_w = cov(w’);
cov_v = cov(v);

[Lk,P] = lqe(A,eye(2),C,W,V);

% Augmented system with plant and Kalman filter

Aak = [A zeros(2,2); Lk*C A-Lk*C];
Bak = [B eye(2) zeros(2,1); B zeros(2,2) Lk];

sys_obs_mak = ss(Aak,Bak,eye(4),0);

u(1,:) = 1*heaviside(t);

[yk,t,xk] = lsim(sys_obs_mak,[u’ w’ v’],t,[0 0 0 0]); % Simulation

erro = xk(:,1:2)-xk(:,3:4);
cov_erro_lsim = cov(erro)
PTs = P*Ts
P kalman filter MATLAB Answers — New Questions

​

I am doing a medical imaging project with MRI images. I hope to develop a deep learning model for this task. But the data I collected is not labelled and I have to label them for each category. Can someone suggest me a method to automate this labelling process where it will be greatly save my time. Thanks in advance. !I am doing a medical imaging project with MRI images. I hope to develop a deep learning model for this task. But the data I collected is not labelled and I have to label them for each category. Can someone suggest me a method to automate this labelling process where it will be greatly save my time. Thanks in advance. ! I am doing a medical imaging project with MRI images. I hope to develop a deep learning model for this task. But the data I collected is not labelled and I have to label them for each category. Can someone suggest me a method to automate this labelling process where it will be greatly save my time. Thanks in advance. ! deep learning, image analysis, image processing, image labelling MATLAB Answers — New Questions

​

train_x_n为36×2double，train_y_n为36×9double，但model=TreeBagger(tree(i,j), train_x_n, train_y_n, ……一行报错“数据类型无效。响应必须为双精度或单精度向量。”（Invalid data type. Response must be a double or single vector.)
当把train_y_n改成36×1时便不报错，请问如何使它能训练多输出数据？
train_x_n=ones(36,2);
train_y_n=ones(36,9);
[tree,leaf] = meshgrid(80:10:200,1:1:10);
bestRMSE_RF = 1;
% 网格搜索
for i=1:size(leaf,1)
for j=1:size(tree,2)
model=TreeBagger(tree(i,j), train_x_n, train_y_n, OOBPredictorImportance=’on’,Method=’regression’, OOBPrediction=’on’,MinLeafSize=leaf(i,j));
[~,~,RMSE,~]=Test(model,train_x_n,train_y,PSo);
if RMSE<bestRMSE_RF
bestRMSE_RF=RMSE;
besttree=tree(i,j);
bestleaf=leaf(i,j);
model_RF=model;
end
end
endtrain_x_n为36×2double，train_y_n为36×9double，但model=TreeBagger(tree(i,j), train_x_n, train_y_n, ……一行报错“数据类型无效。响应必须为双精度或单精度向量。”（Invalid data type. Response must be a double or single vector.)
当把train_y_n改成36×1时便不报错，请问如何使它能训练多输出数据？
train_x_n=ones(36,2);
train_y_n=ones(36,9);
[tree,leaf] = meshgrid(80:10:200,1:1:10);
bestRMSE_RF = 1;
% 网格搜索
for i=1:size(leaf,1)
for j=1:size(tree,2)
model=TreeBagger(tree(i,j), train_x_n, train_y_n, OOBPredictorImportance=’on’,Method=’regression’, OOBPrediction=’on’,MinLeafSize=leaf(i,j));
[~,~,RMSE,~]=Test(model,train_x_n,train_y,PSo);
if RMSE<bestRMSE_RF
bestRMSE_RF=RMSE;
besttree=tree(i,j);
bestleaf=leaf(i,j);
model_RF=model;
end
end
end train_x_n为36×2double，train_y_n为36×9double，但model=TreeBagger(tree(i,j), train_x_n, train_y_n, ……一行报错“数据类型无效。响应必须为双精度或单精度向量。”（Invalid data type. Response must be a double or single vector.)
当把train_y_n改成36×1时便不报错，请问如何使它能训练多输出数据？
train_x_n=ones(36,2);
train_y_n=ones(36,9);
[tree,leaf] = meshgrid(80:10:200,1:1:10);
bestRMSE_RF = 1;
% 网格搜索
for i=1:size(leaf,1)
for j=1:size(tree,2)
model=TreeBagger(tree(i,j), train_x_n, train_y_n, OOBPredictorImportance=’on’,Method=’regression’, OOBPrediction=’on’,MinLeafSize=leaf(i,j));
[~,~,RMSE,~]=Test(model,train_x_n,train_y,PSo);
if RMSE<bestRMSE_RF
bestRMSE_RF=RMSE;
besttree=tree(i,j);
bestleaf=leaf(i,j);
model_RF=model;
end
end
end machine learning, 机器学习, 多输出, multi-output MATLAB Answers — New Questions

​

Folks,
Here’s the scenario:
Arduino Uno + Matlab Arduino Hardware Support + Simulink Arduino Board Support Package, running on macOS Sonoma 14.5, Intel silicone.
All installs well; correct device special file setup during install; hardware tests OK with the Matlab Arduino hardwware support (server uploaded …etc). Simulink: sme think, except that it will just report some unknown function call in the main Matlab window during install, but all goes weel and installs.
Now the fun (or lack thereof ?) beings
Following the basic instructions to get the first LED example working, both starting from a blank model, or using the pre-existing model, said to be for the Mega250.
In the case of starting from a blank model, I’m using the Arduino digital output + a pulse generator, as per the example and screenshot below:

When I come to configure the model, there’s no option, anywhere to select the board and port, let alone to deploy and run it, as shown below:

There’s just the option to download the board support package (which I downloaded and installed), and round, and round, and round we go.
If I use the pre-bundled example, I now get the Atmege250 in the list, but not my Uno (which, yes, I installed and configured earlier …etc):

Can someone tell me what’s going on, and help please?

Thanks in advance,

Ahmed.Folks,
Here’s the scenario:
Arduino Uno + Matlab Arduino Hardware Support + Simulink Arduino Board Support Package, running on macOS Sonoma 14.5, Intel silicone.
All installs well; correct device special file setup during install; hardware tests OK with the Matlab Arduino hardwware support (server uploaded …etc). Simulink: sme think, except that it will just report some unknown function call in the main Matlab window during install, but all goes weel and installs.
Now the fun (or lack thereof ?) beings
Following the basic instructions to get the first LED example working, both starting from a blank model, or using the pre-existing model, said to be for the Mega250.
In the case of starting from a blank model, I’m using the Arduino digital output + a pulse generator, as per the example and screenshot below:

When I come to configure the model, there’s no option, anywhere to select the board and port, let alone to deploy and run it, as shown below:

There’s just the option to download the board support package (which I downloaded and installed), and round, and round, and round we go.
If I use the pre-bundled example, I now get the Atmege250 in the list, but not my Uno (which, yes, I installed and configured earlier …etc):

Can someone tell me what’s going on, and help please?

Thanks in advance,

Ahmed. Folks,
Here’s the scenario:
Arduino Uno + Matlab Arduino Hardware Support + Simulink Arduino Board Support Package, running on macOS Sonoma 14.5, Intel silicone.
All installs well; correct device special file setup during install; hardware tests OK with the Matlab Arduino hardwware support (server uploaded …etc). Simulink: sme think, except that it will just report some unknown function call in the main Matlab window during install, but all goes weel and installs.
Now the fun (or lack thereof ?) beings
Following the basic instructions to get the first LED example working, both starting from a blank model, or using the pre-existing model, said to be for the Mega250.
In the case of starting from a blank model, I’m using the Arduino digital output + a pulse generator, as per the example and screenshot below:

When I come to configure the model, there’s no option, anywhere to select the board and port, let alone to deploy and run it, as shown below:

There’s just the option to download the board support package (which I downloaded and installed), and round, and round, and round we go.
If I use the pre-bundled example, I now get the Atmege250 in the list, but not my Uno (which, yes, I installed and configured earlier …etc):

Can someone tell me what’s going on, and help please?

Thanks in advance,

Ahmed. arduino, simulink, macos MATLAB Answers — New Questions

​

I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
Due to the "Class labes", it is difficult.
Thank you,

openfig(‘0001.fig’)
openfig(‘0002.fig’)I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
Due to the "Class labes", it is difficult.
Thank you,

openfig(‘0001.fig’)
openfig(‘0002.fig’) I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
Due to the "Class labes", it is difficult.
Thank you,

openfig(‘0001.fig’)
openfig(‘0002.fig’) tiledlayout MATLAB Answers — New Questions

​

I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
I used previous answer by "Voss" as below, but doesn’t work for these figures, in this case, where "Class labels" exist.
Thank you very much,
% open the fig files in two new figures
f1 = openfig(‘0001.fig’,’invisible’);
f2 = openfig(‘0002.fig’,’invisible’);

% get the ConfusionMatrixChart in each figure
cmc1 = f1.Children;
cmc2 = f2.Children;
% alternate way to get the ConfusionMatrixChart in each figure
% cmc1 = findall(f1,’Type’,’ConfusionMatrixChart’);
% cmc2 = findall(f2,’Type’,’ConfusionMatrixChart’);

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,1,2);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;
% same thing, now with a vertical layout

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,2,1);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;

% delete the original figures
delete([f1 f2])I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
I used previous answer by "Voss" as below, but doesn’t work for these figures, in this case, where "Class labels" exist.
Thank you very much,
% open the fig files in two new figures
f1 = openfig(‘0001.fig’,’invisible’);
f2 = openfig(‘0002.fig’,’invisible’);

% get the ConfusionMatrixChart in each figure
cmc1 = f1.Children;
cmc2 = f2.Children;
% alternate way to get the ConfusionMatrixChart in each figure
% cmc1 = findall(f1,’Type’,’ConfusionMatrixChart’);
% cmc2 = findall(f2,’Type’,’ConfusionMatrixChart’);

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,1,2);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;
% same thing, now with a vertical layout

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,2,1);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;

% delete the original figures
delete([f1 f2]) I have two existing figures (‘0001.fig" and "0002.fig"), and want to put in one figure together vertically.
I used previous answer by "Voss" as below, but doesn’t work for these figures, in this case, where "Class labels" exist.
Thank you very much,
% open the fig files in two new figures
f1 = openfig(‘0001.fig’,’invisible’);
f2 = openfig(‘0002.fig’,’invisible’);

% get the ConfusionMatrixChart in each figure
cmc1 = f1.Children;
cmc2 = f2.Children;
% alternate way to get the ConfusionMatrixChart in each figure
% cmc1 = findall(f1,’Type’,’ConfusionMatrixChart’);
% cmc2 = findall(f2,’Type’,’ConfusionMatrixChart’);

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,1,2);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;
% same thing, now with a vertical layout

% create a new figure with a tiledlayout
f = figure();
t = tiledlayout(f,2,1);
% copy the charts into the tiledlayout
h1 = copyobj(cmc1,t);
h2 = copyobj(cmc2,t);
% place them correctly
h1.Layout.Tile = 1;
h2.Layout.Tile = 2;

% delete the original figures
delete([f1 f2]) tiledlayout MATLAB Answers — New Questions

​

Hi, I have a fucntion called "edit" which I want to apply to all columns of all tables in all cells in "results_velocity_diff" (see attachment).
I tried it using this code as a test:
% Get the first table from the first cell
first_table = results_velocity_diff{1, 1};

% Initialize a cell array to store the results
results = cell(1, width(first_table));

% Apply edit to each column in the first table
for col = 1:width(first_table)
results{col} = edit(first_table{:, col}, 0, 0, 0);
end
That worked fine. But when I try and apply it to the rest of the columns in the tables of the cells using this code:
% Initialize results_edit to store the results
results_edit = {};

% Iterate through each cell array
for i = 1:numel(results_velocity_diff)
sub_cell_array = results_velocity_diff{i};

% Initialize a new sub cell array for the results
edit_sub_cell_array = {};

% Iterate through each table in the sub cell array
for j = 1:numel(sub_cell_array)
table_data = sub_cell_array{j};
edit_table = table(); % Initialize an empty table to store results

% Iterate through each column in the table
for col = 1:width(table_data)
% Apply the edit function to the current column
edit_result = edit(table_data{:, col}, 0, 0, 0);

% Store the result in the edit table
% Creating a new variable name dynamically
var_name = table_data.Properties.VariableNames{col};
edit_table.(var_name) = edit_result;
end

% Store the table in the sub cell array
edit_sub_cell_array{end+1} = edit_table;
end

% Store the sub cell array in results_edit
results_edit{end+1} = edit_sub_cell_array;
end

Then I get the error:
Error using {}
Subscripting into a table using one subscript (as in t(i)) is not supported. Specify a row subscript and a variable subscript, as in t(rows,vars). To select variables, use t(:,i) or for one
variable t.(i). To select rows, use t(i,:).
Error in
table_data = sub_cell_array{j};

What am I doing wrong?Hi, I have a fucntion called "edit" which I want to apply to all columns of all tables in all cells in "results_velocity_diff" (see attachment).
I tried it using this code as a test:
% Get the first table from the first cell
first_table = results_velocity_diff{1, 1};

% Initialize a cell array to store the results
results = cell(1, width(first_table));

% Apply edit to each column in the first table
for col = 1:width(first_table)
results{col} = edit(first_table{:, col}, 0, 0, 0);
end
That worked fine. But when I try and apply it to the rest of the columns in the tables of the cells using this code:
% Initialize results_edit to store the results
results_edit = {};

% Iterate through each cell array
for i = 1:numel(results_velocity_diff)
sub_cell_array = results_velocity_diff{i};

% Initialize a new sub cell array for the results
edit_sub_cell_array = {};

% Iterate through each table in the sub cell array
for j = 1:numel(sub_cell_array)
table_data = sub_cell_array{j};
edit_table = table(); % Initialize an empty table to store results

% Iterate through each column in the table
for col = 1:width(table_data)
% Apply the edit function to the current column
edit_result = edit(table_data{:, col}, 0, 0, 0);

% Store the result in the edit table
% Creating a new variable name dynamically
var_name = table_data.Properties.VariableNames{col};
edit_table.(var_name) = edit_result;
end

% Store the table in the sub cell array
edit_sub_cell_array{end+1} = edit_table;
end

% Store the sub cell array in results_edit
results_edit{end+1} = edit_sub_cell_array;
end

Then I get the error:
Error using {}
Subscripting into a table using one subscript (as in t(i)) is not supported. Specify a row subscript and a variable subscript, as in t(rows,vars). To select variables, use t(:,i) or for one
variable t.(i). To select rows, use t(i,:).
Error in
table_data = sub_cell_array{j};

What am I doing wrong? Hi, I have a fucntion called "edit" which I want to apply to all columns of all tables in all cells in "results_velocity_diff" (see attachment).
I tried it using this code as a test:
% Get the first table from the first cell
first_table = results_velocity_diff{1, 1};

% Initialize a cell array to store the results
results = cell(1, width(first_table));

% Apply edit to each column in the first table
for col = 1:width(first_table)
results{col} = edit(first_table{:, col}, 0, 0, 0);
end
That worked fine. But when I try and apply it to the rest of the columns in the tables of the cells using this code:
% Initialize results_edit to store the results
results_edit = {};

% Iterate through each cell array
for i = 1:numel(results_velocity_diff)
sub_cell_array = results_velocity_diff{i};

% Initialize a new sub cell array for the results
edit_sub_cell_array = {};

% Iterate through each table in the sub cell array
for j = 1:numel(sub_cell_array)
table_data = sub_cell_array{j};
edit_table = table(); % Initialize an empty table to store results

% Iterate through each column in the table
for col = 1:width(table_data)
% Apply the edit function to the current column
edit_result = edit(table_data{:, col}, 0, 0, 0);

% Store the result in the edit table
% Creating a new variable name dynamically
var_name = table_data.Properties.VariableNames{col};
edit_table.(var_name) = edit_result;
end

% Store the table in the sub cell array
edit_sub_cell_array{end+1} = edit_table;
end

% Store the sub cell array in results_edit
results_edit{end+1} = edit_sub_cell_array;
end

Then I get the error:
Error using {}
Subscripting into a table using one subscript (as in t(i)) is not supported. Specify a row subscript and a variable subscript, as in t(rows,vars). To select variables, use t(:,i) or for one
variable t.(i). To select rows, use t(i,:).
Error in
table_data = sub_cell_array{j};

What am I doing wrong? function, error, subscripting, table MATLAB Answers — New Questions

​

The conductive heat transfer block is set to planar, when i try to change it to cylndrical for more realistic model as the regenerator is in fact cylindrical.
My inputs are as follows:
Inner Diameter = geometry.displacer_piston.radius
Outer Diameter = geometry.displacer_piston.radius + geometry.displacer_piston.glass_thickness
Length = regenerator.geometry.length
Conductivity (K) = regenerator.conductionHeater.k
For both of the conductive blocks, when i do that the engine simply fails to operate.
I used temperature sensors and in original model the temperature between heater and ambient are about 1550 but when i do the cylindrical modification it starts at that difference then decrease to zero as time move on
I want to understand why am i doing wrong.The conductive heat transfer block is set to planar, when i try to change it to cylndrical for more realistic model as the regenerator is in fact cylindrical.
My inputs are as follows:
Inner Diameter = geometry.displacer_piston.radius
Outer Diameter = geometry.displacer_piston.radius + geometry.displacer_piston.glass_thickness
Length = regenerator.geometry.length
Conductivity (K) = regenerator.conductionHeater.k
For both of the conductive blocks, when i do that the engine simply fails to operate.
I used temperature sensors and in original model the temperature between heater and ambient are about 1550 but when i do the cylindrical modification it starts at that difference then decrease to zero as time move on
I want to understand why am i doing wrong. The conductive heat transfer block is set to planar, when i try to change it to cylndrical for more realistic model as the regenerator is in fact cylindrical.
My inputs are as follows:
Inner Diameter = geometry.displacer_piston.radius
Outer Diameter = geometry.displacer_piston.radius + geometry.displacer_piston.glass_thickness
Length = regenerator.geometry.length
Conductivity (K) = regenerator.conductionHeater.k
For both of the conductive blocks, when i do that the engine simply fails to operate.
I used temperature sensors and in original model the temperature between heater and ambient are about 1550 but when i do the cylindrical modification it starts at that difference then decrease to zero as time move on
I want to understand why am i doing wrong. simscape, model MATLAB Answers — New Questions

​

This is more of a recommendation to the MathWorks website developers rather than a quesiton.
I don’t use File Exchange (FEX) often, but when I do, I typically access it through the browser rather than the AddOn button in Matlab. Recently, I noticed that the search bar is missing from FEX, making it impossible to find anything. Upon closer inspection, and five minutes later, I eventually realized that the search option a tiny, barely visible, icon tucked away in the corner of the browser.
To the MathWorks developers responsible for this significant usablity change: why would you hide such a fundamental feature on FEX, which is such a tremendous resource for Matlab users? This change makes it much harder for the users (espicailly those new to Matlab and unfamiliar with FEX) to find what they need and could potentially discourage some from using Matlab.This is more of a recommendation to the MathWorks website developers rather than a quesiton.
I don’t use File Exchange (FEX) often, but when I do, I typically access it through the browser rather than the AddOn button in Matlab. Recently, I noticed that the search bar is missing from FEX, making it impossible to find anything. Upon closer inspection, and five minutes later, I eventually realized that the search option a tiny, barely visible, icon tucked away in the corner of the browser.
To the MathWorks developers responsible for this significant usablity change: why would you hide such a fundamental feature on FEX, which is such a tremendous resource for Matlab users? This change makes it much harder for the users (espicailly those new to Matlab and unfamiliar with FEX) to find what they need and could potentially discourage some from using Matlab. This is more of a recommendation to the MathWorks website developers rather than a quesiton.
I don’t use File Exchange (FEX) often, but when I do, I typically access it through the browser rather than the AddOn button in Matlab. Recently, I noticed that the search bar is missing from FEX, making it impossible to find anything. Upon closer inspection, and five minutes later, I eventually realized that the search option a tiny, barely visible, icon tucked away in the corner of the browser.
To the MathWorks developers responsible for this significant usablity change: why would you hide such a fundamental feature on FEX, which is such a tremendous resource for Matlab users? This change makes it much harder for the users (espicailly those new to Matlab and unfamiliar with FEX) to find what they need and could potentially discourage some from using Matlab. file exchange MATLAB Answers — New Questions

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Failed to download the third-party software:
Sourcery G++ Lite

This is required by:
Simulink Support Package for Parrot Minidrones
I’m getting this error when installing the mini drone package. I’m using Windows 11. I can’t find a solution. does anyone know the solution?
My Matlab version is R2023BFailed to download the third-party software:
Sourcery G++ Lite

This is required by:
Simulink Support Package for Parrot Minidrones
I’m getting this error when installing the mini drone package. I’m using Windows 11. I can’t find a solution. does anyone know the solution?
My Matlab version is R2023B Failed to download the third-party software:
Sourcery G++ Lite

This is required by:
Simulink Support Package for Parrot Minidrones
I’m getting this error when installing the mini drone package. I’m using Windows 11. I can’t find a solution. does anyone know the solution?
My Matlab version is R2023B mini drone MATLAB Answers — New Questions

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