Category: Matlab
Category Archives: Matlab
How to load .mat file into base workspace using app designer
I want to run my model in app desinger.
Therefore, all parameters from the .mat file are required to run the model.
How to load all parameters from mat file into base workspace?I want to run my model in app desinger.
Therefore, all parameters from the .mat file are required to run the model.
How to load all parameters from mat file into base workspace? I want to run my model in app desinger.
Therefore, all parameters from the .mat file are required to run the model.
How to load all parameters from mat file into base workspace? appdesigner MATLAB Answers — New Questions
How to implement constraints (conditions) to the estimation of parameters by fitting?
Hi to everyone!
How to implement in the Simbiology interface so that the estimated parameters in a fit satisfy a given condition? For example, estimate by a fit the values of the kinetic constants k1 and k-1 for a serie of experimental data, which satisfy the value of the equilibrium constant Keq (Keq= k1/k-1) within a given interval, such as K= 10±2.
Thank you in advance!Hi to everyone!
How to implement in the Simbiology interface so that the estimated parameters in a fit satisfy a given condition? For example, estimate by a fit the values of the kinetic constants k1 and k-1 for a serie of experimental data, which satisfy the value of the equilibrium constant Keq (Keq= k1/k-1) within a given interval, such as K= 10±2.
Thank you in advance! Hi to everyone!
How to implement in the Simbiology interface so that the estimated parameters in a fit satisfy a given condition? For example, estimate by a fit the values of the kinetic constants k1 and k-1 for a serie of experimental data, which satisfy the value of the equilibrium constant Keq (Keq= k1/k-1) within a given interval, such as K= 10±2.
Thank you in advance! simbiology MATLAB Answers — New Questions
Readmatrix reading csv files incorrectly by replacing values with NaN and adding a third column
Hi all,
I have 10 ".csv" files which I am importing into MATLAB using the readmatrix function. All of these files are identical as follows:
Rows: 1000001 – First row has headers (Time [s], Volts [V]))
Columns: 2
All but two files are not being imported correctly. I have tried opening them in text editors to verify the comma delimiter and it is correct. I do not know what the issue is. For these two files, MATLAB reads the second (Volts) column as NaN and adds a third NaN column to it.
Kindly please help.
The line of code I am using is: variable_x = readmatrix(‘filename’);
A short excript is as follows:
Important to note that I have also tried the ‘range’ and ‘delimiter’ options explicitly to no avail. Might be a bug. I am using R2023bHi all,
I have 10 ".csv" files which I am importing into MATLAB using the readmatrix function. All of these files are identical as follows:
Rows: 1000001 – First row has headers (Time [s], Volts [V]))
Columns: 2
All but two files are not being imported correctly. I have tried opening them in text editors to verify the comma delimiter and it is correct. I do not know what the issue is. For these two files, MATLAB reads the second (Volts) column as NaN and adds a third NaN column to it.
Kindly please help.
The line of code I am using is: variable_x = readmatrix(‘filename’);
A short excript is as follows:
Important to note that I have also tried the ‘range’ and ‘delimiter’ options explicitly to no avail. Might be a bug. I am using R2023b Hi all,
I have 10 ".csv" files which I am importing into MATLAB using the readmatrix function. All of these files are identical as follows:
Rows: 1000001 – First row has headers (Time [s], Volts [V]))
Columns: 2
All but two files are not being imported correctly. I have tried opening them in text editors to verify the comma delimiter and it is correct. I do not know what the issue is. For these two files, MATLAB reads the second (Volts) column as NaN and adds a third NaN column to it.
Kindly please help.
The line of code I am using is: variable_x = readmatrix(‘filename’);
A short excript is as follows:
Important to note that I have also tried the ‘range’ and ‘delimiter’ options explicitly to no avail. Might be a bug. I am using R2023b readmatrix, csv, nan MATLAB Answers — New Questions
Error in demodulation QAM-16 signal
% This code, after demodulation, produces a sequence of 4 values, although the number of values should be equal to the modulation factor M. What could be the problem?
clc
close all
clear all
M = 16;
L=10000;
T=10;
W=43; %SNR
bits1 = randi([0 M-1], 1, L);
bits2 = randi([0 3], 1, L/T);
mod1 = qammod(bits1, M,’UnitAveragePower’, true);
% scatterplot(mod1)
mod2 = qammod(bits2, 4, ‘UnitAveragePower’,true);
% scatterplot(mod2)
for i = 1:length(bits2)
sym(i,:)=[mod1((i-1)*T+1:i*T) mod2(i)];
end
f=0;
for k=1:L/T
for j=1:T+1
f=f+1;
symbols(f)=sym(k,j);
end
end
% scatterplot(symbols)
% symbols = awgn(symbols,W,"measured");
pnoise = comm.PhaseNoise(‘Level’,[-70 -104 -110],’FrequencyOffset’,[1e4 1e5 2e5], ‘SampleRate’, 28e6);
symbols2 = pnoise([zeros(1e5,1);symbols’]);
% symbols2 = pnoise(symbols);
fc = 1e6; % Carrier frequency in Hz
fs = 28e6; % Sample rate in Hz.
phNzLevel = [-70 -104 -110]; % in dBc/Hz
phNzFreqOff = [1e4 1e5 2e5]; % in Hz
Nspf = 6e6; % Number of Samples per frame
freqSpan = 400e3; % in Hz, for spectrum computation
sinewave = dsp.SineWave( …
Amplitude=1, …
Frequency=fc, …
SampleRate=fs, …
SamplesPerFrame=Nspf, …
ComplexOutput=true);
pnoise = comm.PhaseNoise( …
Level=phNzLevel, …
FrequencyOffset=phNzFreqOff, …
SampleRate=fs);
sascopeRBW100 = spectrumAnalyzer( …
SampleRate=fs, …
Method="welch", …
FrequencySpan="Span and center frequency", …
CenterFrequency=fc, …
Span=freqSpan, …
RBWSource="Property", …
RBW=100, …
SpectrumType="Power density", …
SpectralAverages=10, …
SpectrumUnits="dBW", …
YLimits=[-150 10], …
Title="Resolution Bandwidth 100 Hz", …
ChannelNames={‘signal’,’signal with phase noise’}, …
Position=[79 147 605 374]);
x = sinewave();
y = pnoise(x);
sascopeRBW100(x,y)
symbols2 = symbols2(1e5+1:end);
prim(1,:)=symbols2(1:T);
for i = 1:length(bits2)-1
prim(i+1,:)=symbols2(i*T+i+1:i*T+i+T);
end
for b = 1:length(mod2)
qam4(b)=symbols2((T+1)*b);
end
h=0;
for u=1:L/T
for l=1:T
h=h+1;
priem(h)=prim(u,l);
end
end
for g = 1:L/T
phase_error(g) = angle(qam4(g) / mod2(g));
compensated4(g) = qam4(g) .* exp(-1i * phase_error(g));
end
for v = 1:L/T
phase_errorM((v-1)*T+1:v*T)=phase_error(v);
end
for f = 1:L
compensatedM(f) = priem(f) .* exp(-1i*phase_errorM(f));
end
demod=qamdemod(compensatedM, M, ‘bin’,’OutputType’,’bit’);
% scatterplot(qam4)
% scatterplot(symbols2)
% scatterplot(compensatedM)
[number,ratio]=biterr(bits1,demod);
evm = lteEVM(demod,bits1);
figure(‘Position’,[200 200 1080 540])
subplot(1,2,1)
scatter(real(symbols2),imag(symbols2),300,".")
subplot(1,2,2)
scatter(real(compensatedM),imag(compensatedM),300,".")% This code, after demodulation, produces a sequence of 4 values, although the number of values should be equal to the modulation factor M. What could be the problem?
clc
close all
clear all
M = 16;
L=10000;
T=10;
W=43; %SNR
bits1 = randi([0 M-1], 1, L);
bits2 = randi([0 3], 1, L/T);
mod1 = qammod(bits1, M,’UnitAveragePower’, true);
% scatterplot(mod1)
mod2 = qammod(bits2, 4, ‘UnitAveragePower’,true);
% scatterplot(mod2)
for i = 1:length(bits2)
sym(i,:)=[mod1((i-1)*T+1:i*T) mod2(i)];
end
f=0;
for k=1:L/T
for j=1:T+1
f=f+1;
symbols(f)=sym(k,j);
end
end
% scatterplot(symbols)
% symbols = awgn(symbols,W,"measured");
pnoise = comm.PhaseNoise(‘Level’,[-70 -104 -110],’FrequencyOffset’,[1e4 1e5 2e5], ‘SampleRate’, 28e6);
symbols2 = pnoise([zeros(1e5,1);symbols’]);
% symbols2 = pnoise(symbols);
fc = 1e6; % Carrier frequency in Hz
fs = 28e6; % Sample rate in Hz.
phNzLevel = [-70 -104 -110]; % in dBc/Hz
phNzFreqOff = [1e4 1e5 2e5]; % in Hz
Nspf = 6e6; % Number of Samples per frame
freqSpan = 400e3; % in Hz, for spectrum computation
sinewave = dsp.SineWave( …
Amplitude=1, …
Frequency=fc, …
SampleRate=fs, …
SamplesPerFrame=Nspf, …
ComplexOutput=true);
pnoise = comm.PhaseNoise( …
Level=phNzLevel, …
FrequencyOffset=phNzFreqOff, …
SampleRate=fs);
sascopeRBW100 = spectrumAnalyzer( …
SampleRate=fs, …
Method="welch", …
FrequencySpan="Span and center frequency", …
CenterFrequency=fc, …
Span=freqSpan, …
RBWSource="Property", …
RBW=100, …
SpectrumType="Power density", …
SpectralAverages=10, …
SpectrumUnits="dBW", …
YLimits=[-150 10], …
Title="Resolution Bandwidth 100 Hz", …
ChannelNames={‘signal’,’signal with phase noise’}, …
Position=[79 147 605 374]);
x = sinewave();
y = pnoise(x);
sascopeRBW100(x,y)
symbols2 = symbols2(1e5+1:end);
prim(1,:)=symbols2(1:T);
for i = 1:length(bits2)-1
prim(i+1,:)=symbols2(i*T+i+1:i*T+i+T);
end
for b = 1:length(mod2)
qam4(b)=symbols2((T+1)*b);
end
h=0;
for u=1:L/T
for l=1:T
h=h+1;
priem(h)=prim(u,l);
end
end
for g = 1:L/T
phase_error(g) = angle(qam4(g) / mod2(g));
compensated4(g) = qam4(g) .* exp(-1i * phase_error(g));
end
for v = 1:L/T
phase_errorM((v-1)*T+1:v*T)=phase_error(v);
end
for f = 1:L
compensatedM(f) = priem(f) .* exp(-1i*phase_errorM(f));
end
demod=qamdemod(compensatedM, M, ‘bin’,’OutputType’,’bit’);
% scatterplot(qam4)
% scatterplot(symbols2)
% scatterplot(compensatedM)
[number,ratio]=biterr(bits1,demod);
evm = lteEVM(demod,bits1);
figure(‘Position’,[200 200 1080 540])
subplot(1,2,1)
scatter(real(symbols2),imag(symbols2),300,".")
subplot(1,2,2)
scatter(real(compensatedM),imag(compensatedM),300,".") % This code, after demodulation, produces a sequence of 4 values, although the number of values should be equal to the modulation factor M. What could be the problem?
clc
close all
clear all
M = 16;
L=10000;
T=10;
W=43; %SNR
bits1 = randi([0 M-1], 1, L);
bits2 = randi([0 3], 1, L/T);
mod1 = qammod(bits1, M,’UnitAveragePower’, true);
% scatterplot(mod1)
mod2 = qammod(bits2, 4, ‘UnitAveragePower’,true);
% scatterplot(mod2)
for i = 1:length(bits2)
sym(i,:)=[mod1((i-1)*T+1:i*T) mod2(i)];
end
f=0;
for k=1:L/T
for j=1:T+1
f=f+1;
symbols(f)=sym(k,j);
end
end
% scatterplot(symbols)
% symbols = awgn(symbols,W,"measured");
pnoise = comm.PhaseNoise(‘Level’,[-70 -104 -110],’FrequencyOffset’,[1e4 1e5 2e5], ‘SampleRate’, 28e6);
symbols2 = pnoise([zeros(1e5,1);symbols’]);
% symbols2 = pnoise(symbols);
fc = 1e6; % Carrier frequency in Hz
fs = 28e6; % Sample rate in Hz.
phNzLevel = [-70 -104 -110]; % in dBc/Hz
phNzFreqOff = [1e4 1e5 2e5]; % in Hz
Nspf = 6e6; % Number of Samples per frame
freqSpan = 400e3; % in Hz, for spectrum computation
sinewave = dsp.SineWave( …
Amplitude=1, …
Frequency=fc, …
SampleRate=fs, …
SamplesPerFrame=Nspf, …
ComplexOutput=true);
pnoise = comm.PhaseNoise( …
Level=phNzLevel, …
FrequencyOffset=phNzFreqOff, …
SampleRate=fs);
sascopeRBW100 = spectrumAnalyzer( …
SampleRate=fs, …
Method="welch", …
FrequencySpan="Span and center frequency", …
CenterFrequency=fc, …
Span=freqSpan, …
RBWSource="Property", …
RBW=100, …
SpectrumType="Power density", …
SpectralAverages=10, …
SpectrumUnits="dBW", …
YLimits=[-150 10], …
Title="Resolution Bandwidth 100 Hz", …
ChannelNames={‘signal’,’signal with phase noise’}, …
Position=[79 147 605 374]);
x = sinewave();
y = pnoise(x);
sascopeRBW100(x,y)
symbols2 = symbols2(1e5+1:end);
prim(1,:)=symbols2(1:T);
for i = 1:length(bits2)-1
prim(i+1,:)=symbols2(i*T+i+1:i*T+i+T);
end
for b = 1:length(mod2)
qam4(b)=symbols2((T+1)*b);
end
h=0;
for u=1:L/T
for l=1:T
h=h+1;
priem(h)=prim(u,l);
end
end
for g = 1:L/T
phase_error(g) = angle(qam4(g) / mod2(g));
compensated4(g) = qam4(g) .* exp(-1i * phase_error(g));
end
for v = 1:L/T
phase_errorM((v-1)*T+1:v*T)=phase_error(v);
end
for f = 1:L
compensatedM(f) = priem(f) .* exp(-1i*phase_errorM(f));
end
demod=qamdemod(compensatedM, M, ‘bin’,’OutputType’,’bit’);
% scatterplot(qam4)
% scatterplot(symbols2)
% scatterplot(compensatedM)
[number,ratio]=biterr(bits1,demod);
evm = lteEVM(demod,bits1);
figure(‘Position’,[200 200 1080 540])
subplot(1,2,1)
scatter(real(symbols2),imag(symbols2),300,".")
subplot(1,2,2)
scatter(real(compensatedM),imag(compensatedM),300,".") qam16, demodulation, ber MATLAB Answers — New Questions
Serdes toolbox adapted results log
I generated an IBIS-AMI model using the serdes toolbox. After running the model in Keysight ADS, i can’t figureout where the final CTLE and DFE adapted values are logged. How can I find out to what value the CTLE and DFE converged too?
ThanksI generated an IBIS-AMI model using the serdes toolbox. After running the model in Keysight ADS, i can’t figureout where the final CTLE and DFE adapted values are logged. How can I find out to what value the CTLE and DFE converged too?
Thanks I generated an IBIS-AMI model using the serdes toolbox. After running the model in Keysight ADS, i can’t figureout where the final CTLE and DFE adapted values are logged. How can I find out to what value the CTLE and DFE converged too?
Thanks serdes, serdes toolbox, ibis-ami MATLAB Answers — New Questions
Plotting the Evolution of Spatially Localized Initial Conditions for Discrete Klein-Gordon Equation
Ιn continuation of the study with which I have been fascinated Numerical Simulation of a Damped, Driven Nonlinear Wave System with Spatially Extended Initial Conditions
Now we examine the role of damping in the structure of the branches of equilibrium points. In this study, we consider localized initial conditions of the form:
where is the distance between the nodes, and is the amplitude. We assume zero initial velocity
We also note that if we consider an infinite chain, the initial conditions $(1)$ satisfy the Dirichlet boundary conditions only asymptotically. However, since the smallest half-length of the chain has been set to $ L/2 = 100$, the error is of the order of $ 10^{-44} $, which does not affect numerical computations.
The figure shows the dynamics of the initial condition (1) for parameters: and . In the first image of Figure, we observe the profile of the initial condition.
The subsequent images show the dynamics of the system for different values of the damping force . For , the convergence takes place at the equilibrium point which is the basic state.
I want to create the red and the blue plots
Now I have tried but as you can see the result are different. What should I change?
% Parameters
L = 200; % Length of the system
K = 99; % Number of spatial points
omega_d = 1; % Characteristic frequency
beta = 1; % Nonlinearity parameter
delta_values = [0.1, 0.05, 0.01]; % Damping coefficients
% Spatial grid
h = L / (K + 1);
n = linspace(-L/2, L/2, K+1); % Spatial points
N = length(n);
omegaDScaled = h * omega_d;
% Time parameters
dt = 1; % Time step
tmax = 3000; % Maximum time
tspan = 0:dt:tmax; % Time vector
% Values of amplitude ‘a’ to iterate over
a_values = [2]; % Initial amplitude for the initial condition plot
% Differential equation solver function
function dYdt = odefun(~, Y, N, h, omegaDScaled, deltaScaled, beta)
U = Y(1:N);
Udot = Y(N+1:end);
Uddot = zeros(size(U));
% Laplacian (discrete second derivative)
for k = 2:N-1
Uddot(k) = (U(k+1) – 2 * U(k) + U(k-1)) ;
end
% System of equations
dUdt = Udot;
dUdotdt = Uddot – deltaScaled * Udot + omegaDScaled^2 * (U – beta * U.^3);
% Pack derivatives
dYdt = [dUdt; dUdotdt];
end
% Create a figure for subplots
figure;
% Loop through each value of ‘delta’ and generate the plot
for i = 1:length(delta_values)
delta = delta_values(i);
deltaScaled = h * delta;
a = a_values(1);
% Initial conditions
U0 = a * sech(-L/2 + n*h); % Initial displacement
U0(1) = 0; % Boundary condition at n = 0
U0(end) = 0; % Boundary condition at n = K+1
Udot0 = zeros(size(U0)); % Initial velocity
% Pack initial conditions
Y0 = [U0, Udot0];
% Solve ODE
opts = odeset(‘RelTol’, 1e-5, ‘AbsTol’, 1e-6);
[t, Y] = ode45(@(t, Y) odefun(t, Y, N, h, omegaDScaled, deltaScaled, beta), tspan, Y0, opts);
% Extract solutions
U = Y(:, 1:N);
Udot = Y(:, N+1:end);
% Plot final displacement profile
subplot(2, 2, i+1);
plot(n, U(end,:), ‘b.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title([‘$t=3000$, $delta=’, num2str(delta), ‘$’], ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-2 2]);
grid on;
end
% Initial plot
subplot(2, 2, 1);
a_init = 2; % Example initial amplitude for the initial condition plot
U0_init = a_init * sech(-L/2 + n*h); % Initial displacement
U0_init(1) = 0; % Boundary condition at n = 0
U0_init(end) = 0; % Boundary condition at n = K+1
plot(n, U0_init, ‘r.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title(‘$t=0$’, ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-3 3]);
grid on;
% Adjust layout
set(gcf, ‘Position’, [100, 100, 1200, 900]); % Adjust figure size as neededΙn continuation of the study with which I have been fascinated Numerical Simulation of a Damped, Driven Nonlinear Wave System with Spatially Extended Initial Conditions
Now we examine the role of damping in the structure of the branches of equilibrium points. In this study, we consider localized initial conditions of the form:
where is the distance between the nodes, and is the amplitude. We assume zero initial velocity
We also note that if we consider an infinite chain, the initial conditions $(1)$ satisfy the Dirichlet boundary conditions only asymptotically. However, since the smallest half-length of the chain has been set to $ L/2 = 100$, the error is of the order of $ 10^{-44} $, which does not affect numerical computations.
The figure shows the dynamics of the initial condition (1) for parameters: and . In the first image of Figure, we observe the profile of the initial condition.
The subsequent images show the dynamics of the system for different values of the damping force . For , the convergence takes place at the equilibrium point which is the basic state.
I want to create the red and the blue plots
Now I have tried but as you can see the result are different. What should I change?
% Parameters
L = 200; % Length of the system
K = 99; % Number of spatial points
omega_d = 1; % Characteristic frequency
beta = 1; % Nonlinearity parameter
delta_values = [0.1, 0.05, 0.01]; % Damping coefficients
% Spatial grid
h = L / (K + 1);
n = linspace(-L/2, L/2, K+1); % Spatial points
N = length(n);
omegaDScaled = h * omega_d;
% Time parameters
dt = 1; % Time step
tmax = 3000; % Maximum time
tspan = 0:dt:tmax; % Time vector
% Values of amplitude ‘a’ to iterate over
a_values = [2]; % Initial amplitude for the initial condition plot
% Differential equation solver function
function dYdt = odefun(~, Y, N, h, omegaDScaled, deltaScaled, beta)
U = Y(1:N);
Udot = Y(N+1:end);
Uddot = zeros(size(U));
% Laplacian (discrete second derivative)
for k = 2:N-1
Uddot(k) = (U(k+1) – 2 * U(k) + U(k-1)) ;
end
% System of equations
dUdt = Udot;
dUdotdt = Uddot – deltaScaled * Udot + omegaDScaled^2 * (U – beta * U.^3);
% Pack derivatives
dYdt = [dUdt; dUdotdt];
end
% Create a figure for subplots
figure;
% Loop through each value of ‘delta’ and generate the plot
for i = 1:length(delta_values)
delta = delta_values(i);
deltaScaled = h * delta;
a = a_values(1);
% Initial conditions
U0 = a * sech(-L/2 + n*h); % Initial displacement
U0(1) = 0; % Boundary condition at n = 0
U0(end) = 0; % Boundary condition at n = K+1
Udot0 = zeros(size(U0)); % Initial velocity
% Pack initial conditions
Y0 = [U0, Udot0];
% Solve ODE
opts = odeset(‘RelTol’, 1e-5, ‘AbsTol’, 1e-6);
[t, Y] = ode45(@(t, Y) odefun(t, Y, N, h, omegaDScaled, deltaScaled, beta), tspan, Y0, opts);
% Extract solutions
U = Y(:, 1:N);
Udot = Y(:, N+1:end);
% Plot final displacement profile
subplot(2, 2, i+1);
plot(n, U(end,:), ‘b.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title([‘$t=3000$, $delta=’, num2str(delta), ‘$’], ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-2 2]);
grid on;
end
% Initial plot
subplot(2, 2, 1);
a_init = 2; % Example initial amplitude for the initial condition plot
U0_init = a_init * sech(-L/2 + n*h); % Initial displacement
U0_init(1) = 0; % Boundary condition at n = 0
U0_init(end) = 0; % Boundary condition at n = K+1
plot(n, U0_init, ‘r.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title(‘$t=0$’, ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-3 3]);
grid on;
% Adjust layout
set(gcf, ‘Position’, [100, 100, 1200, 900]); % Adjust figure size as needed Ιn continuation of the study with which I have been fascinated Numerical Simulation of a Damped, Driven Nonlinear Wave System with Spatially Extended Initial Conditions
Now we examine the role of damping in the structure of the branches of equilibrium points. In this study, we consider localized initial conditions of the form:
where is the distance between the nodes, and is the amplitude. We assume zero initial velocity
We also note that if we consider an infinite chain, the initial conditions $(1)$ satisfy the Dirichlet boundary conditions only asymptotically. However, since the smallest half-length of the chain has been set to $ L/2 = 100$, the error is of the order of $ 10^{-44} $, which does not affect numerical computations.
The figure shows the dynamics of the initial condition (1) for parameters: and . In the first image of Figure, we observe the profile of the initial condition.
The subsequent images show the dynamics of the system for different values of the damping force . For , the convergence takes place at the equilibrium point which is the basic state.
I want to create the red and the blue plots
Now I have tried but as you can see the result are different. What should I change?
% Parameters
L = 200; % Length of the system
K = 99; % Number of spatial points
omega_d = 1; % Characteristic frequency
beta = 1; % Nonlinearity parameter
delta_values = [0.1, 0.05, 0.01]; % Damping coefficients
% Spatial grid
h = L / (K + 1);
n = linspace(-L/2, L/2, K+1); % Spatial points
N = length(n);
omegaDScaled = h * omega_d;
% Time parameters
dt = 1; % Time step
tmax = 3000; % Maximum time
tspan = 0:dt:tmax; % Time vector
% Values of amplitude ‘a’ to iterate over
a_values = [2]; % Initial amplitude for the initial condition plot
% Differential equation solver function
function dYdt = odefun(~, Y, N, h, omegaDScaled, deltaScaled, beta)
U = Y(1:N);
Udot = Y(N+1:end);
Uddot = zeros(size(U));
% Laplacian (discrete second derivative)
for k = 2:N-1
Uddot(k) = (U(k+1) – 2 * U(k) + U(k-1)) ;
end
% System of equations
dUdt = Udot;
dUdotdt = Uddot – deltaScaled * Udot + omegaDScaled^2 * (U – beta * U.^3);
% Pack derivatives
dYdt = [dUdt; dUdotdt];
end
% Create a figure for subplots
figure;
% Loop through each value of ‘delta’ and generate the plot
for i = 1:length(delta_values)
delta = delta_values(i);
deltaScaled = h * delta;
a = a_values(1);
% Initial conditions
U0 = a * sech(-L/2 + n*h); % Initial displacement
U0(1) = 0; % Boundary condition at n = 0
U0(end) = 0; % Boundary condition at n = K+1
Udot0 = zeros(size(U0)); % Initial velocity
% Pack initial conditions
Y0 = [U0, Udot0];
% Solve ODE
opts = odeset(‘RelTol’, 1e-5, ‘AbsTol’, 1e-6);
[t, Y] = ode45(@(t, Y) odefun(t, Y, N, h, omegaDScaled, deltaScaled, beta), tspan, Y0, opts);
% Extract solutions
U = Y(:, 1:N);
Udot = Y(:, N+1:end);
% Plot final displacement profile
subplot(2, 2, i+1);
plot(n, U(end,:), ‘b.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title([‘$t=3000$, $delta=’, num2str(delta), ‘$’], ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-2 2]);
grid on;
end
% Initial plot
subplot(2, 2, 1);
a_init = 2; % Example initial amplitude for the initial condition plot
U0_init = a_init * sech(-L/2 + n*h); % Initial displacement
U0_init(1) = 0; % Boundary condition at n = 0
U0_init(end) = 0; % Boundary condition at n = K+1
plot(n, U0_init, ‘r.-‘, ‘LineWidth’, 1.5, ‘MarkerSize’, 10); % Line and marker plot
xlabel(‘$x_n$’, ‘Interpreter’, ‘latex’);
ylabel(‘$U_n$’, ‘Interpreter’, ‘latex’);
title(‘$t=0$’, ‘Interpreter’, ‘latex’);
set(gca, ‘FontSize’, 12, ‘FontName’, ‘Times’);
xlim([-L/2 L/2]);
ylim([-3 3]);
grid on;
% Adjust layout
set(gcf, ‘Position’, [100, 100, 1200, 900]); % Adjust figure size as needed differential equations, plotting, subplot, plot, equation, mathematics MATLAB Answers — New Questions
FFT for analog read from Arduino Uno
I was able to obtain correct analog values through the Arduino Uno using Matlab Simulink, and I want to calculate FFT and THD, how to do itI was able to obtain correct analog values through the Arduino Uno using Matlab Simulink, and I want to calculate FFT and THD, how to do it I was able to obtain correct analog values through the Arduino Uno using Matlab Simulink, and I want to calculate FFT and THD, how to do it fft MATLAB Answers — New Questions
Is there a way to use existing c++ interfaces wrapped in differing namespaces in Stateflow without redefining them to C-Style enums?
*Problem Description:*
Given a large project with interfaces defined in the form:
namespace ns1
{
class MyClass
{
public:
enum myEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myEnum m_myEnum;
}
}
namespace ns2
{
class MyOtherClass
{
enum myOtherEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myOtherEnum m_myOtherEnum;
}
}
Within C++, the value of the first enum could be accessed using ns1::MyClass::myEnum. In order to write on variables using these interfaces from a Stateflow generated C-File, I only came up with one solution so far: to have the Code Generator redefine both interfaces in C-Style, based on the values entered within Stateflow:
typedef enum
{
NS2_MYCLASS_MY_ENUM_FOO = 0,
NS2_MYCLASS_MY_ENUM_BAR = 1,
NS2_MYCLASS_MY_ENUM_FOOBAR = 2,
} MY_ENUM
typedef enum
{
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOO = 0,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_BAR = 1,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOOBAR = 2,
} MY_OTHER_ENUM
To get these values back on variables, defined in the form of the original enums, there have to be static casts implemented like e.g.
instanceOfMyClass.m_myEnum = static_cast<ns1::MyClass::myEnum>(MY_ENUM)
instanceOfMyOtherClass.m_myOtherEnum = static_cast<ns2::MyOtherClass::myOtherEnum>(MY_OTHER_ENUM)
The disadvantages are:
* redefinition is extra work, prone to errors and a lot of work to keep in sync
* static casting is dangerous, especially, when e.g. the order of the values within the enumeration changes
* the principle of single source of truth is violated which leads to these disadvantages
*Question:*
* Is there a way to directly use the original, C++-Style enums without recreating them and having all the stated disadvantages?
* I’m thinking about a solution where I can enter the names and paths of the original interfaces directly within StateFlow and generating C++ code that is therefore already integrated – without any wrapping and extra, error prone work.*Problem Description:*
Given a large project with interfaces defined in the form:
namespace ns1
{
class MyClass
{
public:
enum myEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myEnum m_myEnum;
}
}
namespace ns2
{
class MyOtherClass
{
enum myOtherEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myOtherEnum m_myOtherEnum;
}
}
Within C++, the value of the first enum could be accessed using ns1::MyClass::myEnum. In order to write on variables using these interfaces from a Stateflow generated C-File, I only came up with one solution so far: to have the Code Generator redefine both interfaces in C-Style, based on the values entered within Stateflow:
typedef enum
{
NS2_MYCLASS_MY_ENUM_FOO = 0,
NS2_MYCLASS_MY_ENUM_BAR = 1,
NS2_MYCLASS_MY_ENUM_FOOBAR = 2,
} MY_ENUM
typedef enum
{
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOO = 0,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_BAR = 1,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOOBAR = 2,
} MY_OTHER_ENUM
To get these values back on variables, defined in the form of the original enums, there have to be static casts implemented like e.g.
instanceOfMyClass.m_myEnum = static_cast<ns1::MyClass::myEnum>(MY_ENUM)
instanceOfMyOtherClass.m_myOtherEnum = static_cast<ns2::MyOtherClass::myOtherEnum>(MY_OTHER_ENUM)
The disadvantages are:
* redefinition is extra work, prone to errors and a lot of work to keep in sync
* static casting is dangerous, especially, when e.g. the order of the values within the enumeration changes
* the principle of single source of truth is violated which leads to these disadvantages
*Question:*
* Is there a way to directly use the original, C++-Style enums without recreating them and having all the stated disadvantages?
* I’m thinking about a solution where I can enter the names and paths of the original interfaces directly within StateFlow and generating C++ code that is therefore already integrated – without any wrapping and extra, error prone work. *Problem Description:*
Given a large project with interfaces defined in the form:
namespace ns1
{
class MyClass
{
public:
enum myEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myEnum m_myEnum;
}
}
namespace ns2
{
class MyOtherClass
{
enum myOtherEnum : int8
{
FOO = 0,
BAR = 1,
FOOBAR = 2
};
myOtherEnum m_myOtherEnum;
}
}
Within C++, the value of the first enum could be accessed using ns1::MyClass::myEnum. In order to write on variables using these interfaces from a Stateflow generated C-File, I only came up with one solution so far: to have the Code Generator redefine both interfaces in C-Style, based on the values entered within Stateflow:
typedef enum
{
NS2_MYCLASS_MY_ENUM_FOO = 0,
NS2_MYCLASS_MY_ENUM_BAR = 1,
NS2_MYCLASS_MY_ENUM_FOOBAR = 2,
} MY_ENUM
typedef enum
{
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOO = 0,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_BAR = 1,
NS2_MYOTHERCLASS_MY_OTHER_ENUM_FOOBAR = 2,
} MY_OTHER_ENUM
To get these values back on variables, defined in the form of the original enums, there have to be static casts implemented like e.g.
instanceOfMyClass.m_myEnum = static_cast<ns1::MyClass::myEnum>(MY_ENUM)
instanceOfMyOtherClass.m_myOtherEnum = static_cast<ns2::MyOtherClass::myOtherEnum>(MY_OTHER_ENUM)
The disadvantages are:
* redefinition is extra work, prone to errors and a lot of work to keep in sync
* static casting is dangerous, especially, when e.g. the order of the values within the enumeration changes
* the principle of single source of truth is violated which leads to these disadvantages
*Question:*
* Is there a way to directly use the original, C++-Style enums without recreating them and having all the stated disadvantages?
* I’m thinking about a solution where I can enter the names and paths of the original interfaces directly within StateFlow and generating C++ code that is therefore already integrated – without any wrapping and extra, error prone work. stateflow, c++, enum, namespace, class MATLAB Answers — New Questions
Create ‘siteviewer’ object without displaying it?
Hello,
Is there a way to create a ‘siteviewer’ object without actually displaying it? I know there’s the option of running the command siteviewer(‘Visible’,’off’), but this command does display the object, even if it closes it inmediataely after. Is there some way to just create the object and have no display of it at all?
Thanks in advance,
GuillemHello,
Is there a way to create a ‘siteviewer’ object without actually displaying it? I know there’s the option of running the command siteviewer(‘Visible’,’off’), but this command does display the object, even if it closes it inmediataely after. Is there some way to just create the object and have no display of it at all?
Thanks in advance,
Guillem Hello,
Is there a way to create a ‘siteviewer’ object without actually displaying it? I know there’s the option of running the command siteviewer(‘Visible’,’off’), but this command does display the object, even if it closes it inmediataely after. Is there some way to just create the object and have no display of it at all?
Thanks in advance,
Guillem siteviewer, site, viewer, matlab, matlab gui, raytrace MATLAB Answers — New Questions
Error cannot open output file while building PIL Block
I was trying to run a PIL Simulation using Simulink. When deploying my controller subsystem to Arduino everything worked perfectly until it tried to build the PIL block for my controller and i get error [Cannot open output file "E:DocumentsUsersCodePID0_pbs.mexw64"] and the PIL block can’t be build. Can someone help me how to solve this error?I was trying to run a PIL Simulation using Simulink. When deploying my controller subsystem to Arduino everything worked perfectly until it tried to build the PIL block for my controller and i get error [Cannot open output file "E:DocumentsUsersCodePID0_pbs.mexw64"] and the PIL block can’t be build. Can someone help me how to solve this error? I was trying to run a PIL Simulation using Simulink. When deploying my controller subsystem to Arduino everything worked perfectly until it tried to build the PIL block for my controller and i get error [Cannot open output file "E:DocumentsUsersCodePID0_pbs.mexw64"] and the PIL block can’t be build. Can someone help me how to solve this error? pil, simulink, pid, pil block MATLAB Answers — New Questions
exportgraphics with ‘patch’ crashing Matlab 2024a
I’ve recently changed from Matlab 2022a to 2024a and some plotting and saving scripts are crashing Matlab (the ones that don’t crash take much more time to save).
I am plotting patches and saving them as vector images (‘eps’)
In the script below, there is one example. This exampe don’t crash Matlab 2024a, but the exportgraphics function time jumps from 12 seconds (2022a) to 16 minutes (2024a). EPS file size is around 20mb.
I am aware that the plot may seem to big to be vectored (lots of points), but a big change has happened between 2022 and 2024 to raise this issue
figure
L1_color = [0.7 1 0.8];
L2_color = [1 1 0.6];
L3_color = [1 0.6 0.6];
t = 0:0.001:95;
x = 0.5*sin(t)+1;
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*0.25, L3_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*0.25, L3_color)
tic
exportgraphics(gcf,’Test001.eps’,’Resolution’,150,’ContentType’,’vector’)
tocI’ve recently changed from Matlab 2022a to 2024a and some plotting and saving scripts are crashing Matlab (the ones that don’t crash take much more time to save).
I am plotting patches and saving them as vector images (‘eps’)
In the script below, there is one example. This exampe don’t crash Matlab 2024a, but the exportgraphics function time jumps from 12 seconds (2022a) to 16 minutes (2024a). EPS file size is around 20mb.
I am aware that the plot may seem to big to be vectored (lots of points), but a big change has happened between 2022 and 2024 to raise this issue
figure
L1_color = [0.7 1 0.8];
L2_color = [1 1 0.6];
L3_color = [1 0.6 0.6];
t = 0:0.001:95;
x = 0.5*sin(t)+1;
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*0.25, L3_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*0.25, L3_color)
tic
exportgraphics(gcf,’Test001.eps’,’Resolution’,150,’ContentType’,’vector’)
toc I’ve recently changed from Matlab 2022a to 2024a and some plotting and saving scripts are crashing Matlab (the ones that don’t crash take much more time to save).
I am plotting patches and saving them as vector images (‘eps’)
In the script below, there is one example. This exampe don’t crash Matlab 2024a, but the exportgraphics function time jumps from 12 seconds (2022a) to 16 minutes (2024a). EPS file size is around 20mb.
I am aware that the plot may seem to big to be vectored (lots of points), but a big change has happened between 2022 and 2024 to raise this issue
figure
L1_color = [0.7 1 0.8];
L2_color = [1 1 0.6];
L3_color = [1 0.6 0.6];
t = 0:0.001:95;
x = 0.5*sin(t)+1;
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], 3-[x , 0, 0, x(1)]*0.25, L3_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)], L1_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*.5, L2_color)
patch([t , t(end), t(1), t(1)], [x , 0, 0, x(1)]*0.25, L3_color)
tic
exportgraphics(gcf,’Test001.eps’,’Resolution’,150,’ContentType’,’vector’)
toc exportgraphics, vector MATLAB Answers — New Questions
CLASSIFYING GRAPH DATA TO CATEGORICAL LABEL USING LSTM
Hi I have the following code here, in which I was trying to train an LSTM to classify input data to catergorical lables as see below:
I get the following error
Error using trainnet (line 46)
Number of observations in predictors (1) and targets (897) must match. Check that the data and network are
consistent.
Error in LSTMGomz (line 40)
net = trainnet(XTrain,TTrain,layers,"crossentropy",options);
>>
Please help where did I go wrong
label = strings(997,1);
label(1:200) = ‘graphtype1’;
label(201:399) = ‘graphtype2’;
label(400:598) = ‘graphtype3’;
label(599:798) = ‘graphtype4’;
label(799:997) = ‘graphtype5’;
className = categorical(label);
className2 = categories(className);
Datain = xlsread(‘C:UsersernesOneDriveDocumentsMATLABLSTMdataIn.xlsx’);
% Above Datain has 997 graphs each with 100 samples
% E.g for graphs Datain(1:200,:) – graphtype 1
% graphs Datain(201:399) – graphtype 2 and so on
%So my objective is to train my LSTM using the graphs to labels
numObservations = 997;
[idxTrain,idxTest] = trainingPartitions(numObservations,[0.9 0.1]);
XTrain = Datain(idxTrain,:);% in Xtrain – there are 897 graphs each with 100 values, so
% Xtrain is 897 x 100,
TTrain = className(idxTrain,:);
numHiddenUnits = 120;
numClasses = 5;
layers = [
sequenceInputLayer(100) % I am not sure about this input, because my data comes in 1 by 100 arrys of a seq
%,with 1 – 100 ms timestamps
bilstmLayer(numHiddenUnits,OutputMode="last")
fullyConnectedLayer(numClasses)
softmaxLayer]
options = trainingOptions("adam", …
MaxEpochs=200, …
InitialLearnRate=0.002,…
GradientThreshold=1, …
Shuffle="never", …
Plots="training-progress", …
Metrics="accuracy", …
Verbose=false);
net = trainnet(XTrain,TTrain,layers,"crossentropy",options);Hi I have the following code here, in which I was trying to train an LSTM to classify input data to catergorical lables as see below:
I get the following error
Error using trainnet (line 46)
Number of observations in predictors (1) and targets (897) must match. Check that the data and network are
consistent.
Error in LSTMGomz (line 40)
net = trainnet(XTrain,TTrain,layers,"crossentropy",options);
>>
Please help where did I go wrong
label = strings(997,1);
label(1:200) = ‘graphtype1’;
label(201:399) = ‘graphtype2’;
label(400:598) = ‘graphtype3’;
label(599:798) = ‘graphtype4’;
label(799:997) = ‘graphtype5’;
className = categorical(label);
className2 = categories(className);
Datain = xlsread(‘C:UsersernesOneDriveDocumentsMATLABLSTMdataIn.xlsx’);
% Above Datain has 997 graphs each with 100 samples
% E.g for graphs Datain(1:200,:) – graphtype 1
% graphs Datain(201:399) – graphtype 2 and so on
%So my objective is to train my LSTM using the graphs to labels
numObservations = 997;
[idxTrain,idxTest] = trainingPartitions(numObservations,[0.9 0.1]);
XTrain = Datain(idxTrain,:);% in Xtrain – there are 897 graphs each with 100 values, so
% Xtrain is 897 x 100,
TTrain = className(idxTrain,:);
numHiddenUnits = 120;
numClasses = 5;
layers = [
sequenceInputLayer(100) % I am not sure about this input, because my data comes in 1 by 100 arrys of a seq
%,with 1 – 100 ms timestamps
bilstmLayer(numHiddenUnits,OutputMode="last")
fullyConnectedLayer(numClasses)
softmaxLayer]
options = trainingOptions("adam", …
MaxEpochs=200, …
InitialLearnRate=0.002,…
GradientThreshold=1, …
Shuffle="never", …
Plots="training-progress", …
Metrics="accuracy", …
Verbose=false);
net = trainnet(XTrain,TTrain,layers,"crossentropy",options); Hi I have the following code here, in which I was trying to train an LSTM to classify input data to catergorical lables as see below:
I get the following error
Error using trainnet (line 46)
Number of observations in predictors (1) and targets (897) must match. Check that the data and network are
consistent.
Error in LSTMGomz (line 40)
net = trainnet(XTrain,TTrain,layers,"crossentropy",options);
>>
Please help where did I go wrong
label = strings(997,1);
label(1:200) = ‘graphtype1’;
label(201:399) = ‘graphtype2’;
label(400:598) = ‘graphtype3’;
label(599:798) = ‘graphtype4’;
label(799:997) = ‘graphtype5’;
className = categorical(label);
className2 = categories(className);
Datain = xlsread(‘C:UsersernesOneDriveDocumentsMATLABLSTMdataIn.xlsx’);
% Above Datain has 997 graphs each with 100 samples
% E.g for graphs Datain(1:200,:) – graphtype 1
% graphs Datain(201:399) – graphtype 2 and so on
%So my objective is to train my LSTM using the graphs to labels
numObservations = 997;
[idxTrain,idxTest] = trainingPartitions(numObservations,[0.9 0.1]);
XTrain = Datain(idxTrain,:);% in Xtrain – there are 897 graphs each with 100 values, so
% Xtrain is 897 x 100,
TTrain = className(idxTrain,:);
numHiddenUnits = 120;
numClasses = 5;
layers = [
sequenceInputLayer(100) % I am not sure about this input, because my data comes in 1 by 100 arrys of a seq
%,with 1 – 100 ms timestamps
bilstmLayer(numHiddenUnits,OutputMode="last")
fullyConnectedLayer(numClasses)
softmaxLayer]
options = trainingOptions("adam", …
MaxEpochs=200, …
InitialLearnRate=0.002,…
GradientThreshold=1, …
Shuffle="never", …
Plots="training-progress", …
Metrics="accuracy", …
Verbose=false);
net = trainnet(XTrain,TTrain,layers,"crossentropy",options); lstm sequence to text MATLAB Answers — New Questions
spiral analysis and removal of background
Hi i am attaching an image. this has a computer generated spiral and a hand drawn spiral. i want to remove the numbers (angles) writeen on the image and check how the patient drawn spiral is different from the system generated.
please help me remove the numbers in thisHi i am attaching an image. this has a computer generated spiral and a hand drawn spiral. i want to remove the numbers (angles) writeen on the image and check how the patient drawn spiral is different from the system generated.
please help me remove the numbers in this Hi i am attaching an image. this has a computer generated spiral and a hand drawn spiral. i want to remove the numbers (angles) writeen on the image and check how the patient drawn spiral is different from the system generated.
please help me remove the numbers in this spiral, background, image analysis MATLAB Answers — New Questions
EMACS key bindings in App designer?
I use the EMACS key bindings in the Matlab editor (even on Windows). But I can’t find a way to change the key bindings for the App Designer. My fingers are used to the EMACS bindings and this is driving me crazy!
Is there a some way of changing the App Designer key bindings that I am missing? Thanks!I use the EMACS key bindings in the Matlab editor (even on Windows). But I can’t find a way to change the key bindings for the App Designer. My fingers are used to the EMACS bindings and this is driving me crazy!
Is there a some way of changing the App Designer key bindings that I am missing? Thanks! I use the EMACS key bindings in the Matlab editor (even on Windows). But I can’t find a way to change the key bindings for the App Designer. My fingers are used to the EMACS bindings and this is driving me crazy!
Is there a some way of changing the App Designer key bindings that I am missing? Thanks! appdesigner MATLAB Answers — New Questions
How to apply a linear ramp to start and end of several EEG epochs to attenuate the abrupt onset and offset?
Hey there! I have a set of auditory EEG data recorded collected with the presentation of auditory stimuli, where each stimulus consists of a 3-second speech with a 5-second inter-stimulus interval. Each stimulus onset is marked by an S1 trigger. Currently I have cut off the EEG data without audio input, but for the remain EEG data with auditory stimulation I would like to apply a linear ramp to to both sides of each trial corresponded neural response (10% at each side) to attenuate the abrupt onset and offset. Could you please help me with the code to accomplish this task? Thanks a lot!Hey there! I have a set of auditory EEG data recorded collected with the presentation of auditory stimuli, where each stimulus consists of a 3-second speech with a 5-second inter-stimulus interval. Each stimulus onset is marked by an S1 trigger. Currently I have cut off the EEG data without audio input, but for the remain EEG data with auditory stimulation I would like to apply a linear ramp to to both sides of each trial corresponded neural response (10% at each side) to attenuate the abrupt onset and offset. Could you please help me with the code to accomplish this task? Thanks a lot! Hey there! I have a set of auditory EEG data recorded collected with the presentation of auditory stimuli, where each stimulus consists of a 3-second speech with a 5-second inter-stimulus interval. Each stimulus onset is marked by an S1 trigger. Currently I have cut off the EEG data without audio input, but for the remain EEG data with auditory stimulation I would like to apply a linear ramp to to both sides of each trial corresponded neural response (10% at each side) to attenuate the abrupt onset and offset. Could you please help me with the code to accomplish this task? Thanks a lot! auditory eeg, matlab, linear ramp, smoothing eeg MATLAB Answers — New Questions
How to train a vector multiple-input multiple-output network
I want to train a vector multi-input, multi-output network, but I get the error “Number of input data formats (1) and number of network inputs (2) must match”. This is the code,
clear
input1ds=signalDatastore("input1.csv")
input2ds=signalDatastore("input2.csv")
output1ds=signalDatastore("output1.csv")
output2ds=signalDatastore("output2.csv")
ds=combine(input1ds,input2ds,output1ds,output2ds)
isShuffleable(ds)
% 入力とターゲット
% x = [[0:0.1:10]’ [0:0.1:10]’]
% t = sin(x)
net=dlnetwork
% ニューラルネットワークの定義
layers1 = [
featureInputLayer(1,"name","input1")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
layers2 = [
featureInputLayer(1,"Name","input2")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
net=addLayers(net,layers1)
net=addLayers(net,layers2)
net.plot
% layers=layerGraph()
% layers=addLayers(layers,layers1)
% layers=addLayers(layers,layers2)
% オプションの設定
options = trainingOptions(‘sgdm’, … % 最適化アルゴリズム
‘MaxEpochs’, 500, … % 最大エポック数
‘MiniBatchSize’, 2^3, … % ミニバッチサイズ
‘Verbose’, true,…% 進行状況の表示
‘InputDataFormats’, {‘SB’} …
)
% ニューラルネットワークのトレーニング
customLossFunction = @(Y, T) customloss(Y, T);
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
The “input1.csv” and “output1.csv” all contain a single column of vertical vectors. This time, it is a 2-input, 2-output network.
The function “customloss” is a function I defined myself. This is the error statement.
Error using trainnet (line 46)
Number of input data formats (1) and number of network inputs (2) must match.
Error in parallel_learn_test (line 53)
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
What is wrong? And what solutions are available?I want to train a vector multi-input, multi-output network, but I get the error “Number of input data formats (1) and number of network inputs (2) must match”. This is the code,
clear
input1ds=signalDatastore("input1.csv")
input2ds=signalDatastore("input2.csv")
output1ds=signalDatastore("output1.csv")
output2ds=signalDatastore("output2.csv")
ds=combine(input1ds,input2ds,output1ds,output2ds)
isShuffleable(ds)
% 入力とターゲット
% x = [[0:0.1:10]’ [0:0.1:10]’]
% t = sin(x)
net=dlnetwork
% ニューラルネットワークの定義
layers1 = [
featureInputLayer(1,"name","input1")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
layers2 = [
featureInputLayer(1,"Name","input2")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
net=addLayers(net,layers1)
net=addLayers(net,layers2)
net.plot
% layers=layerGraph()
% layers=addLayers(layers,layers1)
% layers=addLayers(layers,layers2)
% オプションの設定
options = trainingOptions(‘sgdm’, … % 最適化アルゴリズム
‘MaxEpochs’, 500, … % 最大エポック数
‘MiniBatchSize’, 2^3, … % ミニバッチサイズ
‘Verbose’, true,…% 進行状況の表示
‘InputDataFormats’, {‘SB’} …
)
% ニューラルネットワークのトレーニング
customLossFunction = @(Y, T) customloss(Y, T);
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
The “input1.csv” and “output1.csv” all contain a single column of vertical vectors. This time, it is a 2-input, 2-output network.
The function “customloss” is a function I defined myself. This is the error statement.
Error using trainnet (line 46)
Number of input data formats (1) and number of network inputs (2) must match.
Error in parallel_learn_test (line 53)
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
What is wrong? And what solutions are available? I want to train a vector multi-input, multi-output network, but I get the error “Number of input data formats (1) and number of network inputs (2) must match”. This is the code,
clear
input1ds=signalDatastore("input1.csv")
input2ds=signalDatastore("input2.csv")
output1ds=signalDatastore("output1.csv")
output2ds=signalDatastore("output2.csv")
ds=combine(input1ds,input2ds,output1ds,output2ds)
isShuffleable(ds)
% 入力とターゲット
% x = [[0:0.1:10]’ [0:0.1:10]’]
% t = sin(x)
net=dlnetwork
% ニューラルネットワークの定義
layers1 = [
featureInputLayer(1,"name","input1")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
layers2 = [
featureInputLayer(1,"Name","input2")
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(10) % 10ユニットの全結合層
tanhLayer
fullyConnectedLayer(1) % 1ユニットの全結合層
];
net=addLayers(net,layers1)
net=addLayers(net,layers2)
net.plot
% layers=layerGraph()
% layers=addLayers(layers,layers1)
% layers=addLayers(layers,layers2)
% オプションの設定
options = trainingOptions(‘sgdm’, … % 最適化アルゴリズム
‘MaxEpochs’, 500, … % 最大エポック数
‘MiniBatchSize’, 2^3, … % ミニバッチサイズ
‘Verbose’, true,…% 進行状況の表示
‘InputDataFormats’, {‘SB’} …
)
% ニューラルネットワークのトレーニング
customLossFunction = @(Y, T) customloss(Y, T);
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
The “input1.csv” and “output1.csv” all contain a single column of vertical vectors. This time, it is a 2-input, 2-output network.
The function “customloss” is a function I defined myself. This is the error statement.
Error using trainnet (line 46)
Number of input data formats (1) and number of network inputs (2) must match.
Error in parallel_learn_test (line 53)
net = trainnet(ds,net,customLossFunction,options) % x,tは縦ベクトル
What is wrong? And what solutions are available? deep learning, neural networks MATLAB Answers — New Questions
Does fread use cast when reading non-integer byte data
Using fread to read in binary containing 14bit ADC data streamed from an FPGA.
Wondering if fread does a cast when you use ubitn or bitn for the precision input.
Currently My fread setup similar to the code below spits out int16.
Output_data=fread(FID,Inf,’*bit14′)
When I go to get this into a double will this int16 need to be bitsliced or cast.Using fread to read in binary containing 14bit ADC data streamed from an FPGA.
Wondering if fread does a cast when you use ubitn or bitn for the precision input.
Currently My fread setup similar to the code below spits out int16.
Output_data=fread(FID,Inf,’*bit14′)
When I go to get this into a double will this int16 need to be bitsliced or cast. Using fread to read in binary containing 14bit ADC data streamed from an FPGA.
Wondering if fread does a cast when you use ubitn or bitn for the precision input.
Currently My fread setup similar to the code below spits out int16.
Output_data=fread(FID,Inf,’*bit14′)
When I go to get this into a double will this int16 need to be bitsliced or cast. fread, binary, cast, fixed-point MATLAB Answers — New Questions
How do I label the points in a multidimensional scaling plot?
I am studying how to do multidimensional scaling in matlab. I am able to reproduce the output (2D plot) from a published example (http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/).
The output is based on the data table found in the Swiss Fertility and Socioeconomic Indicators (1888) (https://rpubs.com/krishnakuyate/Swiss_FS_Data).
I constructed a 47×47 array of Euclidean distances (D) of the Swiss Fertility and Socioeconomic Indicators and ran Y=cmdscale(D,2) to obtain a plot of these data:
My plot looks very similar (but inverted mirror image) to the published plot from http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/:
But how can I get matlab to label the points in my plot as is done above in the published figure?I am studying how to do multidimensional scaling in matlab. I am able to reproduce the output (2D plot) from a published example (http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/).
The output is based on the data table found in the Swiss Fertility and Socioeconomic Indicators (1888) (https://rpubs.com/krishnakuyate/Swiss_FS_Data).
I constructed a 47×47 array of Euclidean distances (D) of the Swiss Fertility and Socioeconomic Indicators and ran Y=cmdscale(D,2) to obtain a plot of these data:
My plot looks very similar (but inverted mirror image) to the published plot from http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/:
But how can I get matlab to label the points in my plot as is done above in the published figure? I am studying how to do multidimensional scaling in matlab. I am able to reproduce the output (2D plot) from a published example (http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/).
The output is based on the data table found in the Swiss Fertility and Socioeconomic Indicators (1888) (https://rpubs.com/krishnakuyate/Swiss_FS_Data).
I constructed a 47×47 array of Euclidean distances (D) of the Swiss Fertility and Socioeconomic Indicators and ran Y=cmdscale(D,2) to obtain a plot of these data:
My plot looks very similar (but inverted mirror image) to the published plot from http://www.sthda.com/english/articles/31-principal-component-methods-in-r-practical-guide/122-multidimensional-scaling-essentials-algorithms-and-r-code/:
But how can I get matlab to label the points in my plot as is done above in the published figure? multidimensional scaliing, 2d plot, label plot MATLAB Answers — New Questions
How can we get the latitude and longitude of the pixels of a georeferenced image in MATLAB and put them in separate matrices?
Georefrence image Get latitude &longitude ID telegram:@khodesalivanGeorefrence image Get latitude &longitude ID telegram:@khodesalivan Georefrence image Get latitude &longitude ID telegram:@khodesalivan #dem, #latitude, #georefrence, image, image processing MATLAB Answers — New Questions
when i try to install Simulink in Matlab an error is coming, something unexpected occur, try rerunning Matlab
when i try to install Simulink in Matlab an error is coming, something unexpected occur, try rerunning Matlabwhen i try to install Simulink in Matlab an error is coming, something unexpected occur, try rerunning Matlab when i try to install Simulink in Matlab an error is coming, something unexpected occur, try rerunning Matlab simulink MATLAB Answers — New Questions