Category: Matlab
Category Archives: Matlab
Replace gene sequence and conserve frame
Hello
How do I use bioinfiormatics toolbox to replace a gene sequence and conserve the reading frame?
G.Hello
How do I use bioinfiormatics toolbox to replace a gene sequence and conserve the reading frame?
G. Hello
How do I use bioinfiormatics toolbox to replace a gene sequence and conserve the reading frame?
G. bioinformatics, gene, replace MATLAB Answers — New Questions
how write a matrix with specific features
how can i wirte a weight matrix with following features i am confusedhow can i wirte a weight matrix with following features i am confused how can i wirte a weight matrix with following features i am confused matrix MATLAB Answers — New Questions
Create number of for loops depending on size of N
Hi, i have a question regarding number of nested loops:
In this case N would be 4 and hence there are 4 for loops
But if N = 2 in need 2 for loops and the formula also changes to i_1+1_2/N where N=2
is it possible to create code that creates the correct amount of for loops (corresponding to the value of N)
and also changes the formula for i_value in a correct way.
i_Max = 8
i_value = [];
i_real = [];
i_first = [];
i_second = [];
i_third = [];
i_forth = [];
tol = 0.01;
i_good = false;
while i_good == false
% generate new ratio’s
for i_1 = 1:0.1:i_Max
for i_2 = 1:0.1:i_Max
for i_3 = 1:0.1:i_Max
for i_4 = 1:0.1:i_Max
i_value(end+1) = (i_1+i_2+i_3+i_4)/N;
if (i_average-tol <i_value(end)) && (i_value(end)<i_average+tol)…
&& (i_1>i_2) && (i_2>i_3) && (i_3>i_4)
i_good =true;
i_real(end+1) = i_value(end);
i_first(end+1) = i_1;
i_second(end+1) = i_2;
i_third(end+1) = i_3;
i_forth(end+1) = i_4;
end
end
end
end
end
endHi, i have a question regarding number of nested loops:
In this case N would be 4 and hence there are 4 for loops
But if N = 2 in need 2 for loops and the formula also changes to i_1+1_2/N where N=2
is it possible to create code that creates the correct amount of for loops (corresponding to the value of N)
and also changes the formula for i_value in a correct way.
i_Max = 8
i_value = [];
i_real = [];
i_first = [];
i_second = [];
i_third = [];
i_forth = [];
tol = 0.01;
i_good = false;
while i_good == false
% generate new ratio’s
for i_1 = 1:0.1:i_Max
for i_2 = 1:0.1:i_Max
for i_3 = 1:0.1:i_Max
for i_4 = 1:0.1:i_Max
i_value(end+1) = (i_1+i_2+i_3+i_4)/N;
if (i_average-tol <i_value(end)) && (i_value(end)<i_average+tol)…
&& (i_1>i_2) && (i_2>i_3) && (i_3>i_4)
i_good =true;
i_real(end+1) = i_value(end);
i_first(end+1) = i_1;
i_second(end+1) = i_2;
i_third(end+1) = i_3;
i_forth(end+1) = i_4;
end
end
end
end
end
end Hi, i have a question regarding number of nested loops:
In this case N would be 4 and hence there are 4 for loops
But if N = 2 in need 2 for loops and the formula also changes to i_1+1_2/N where N=2
is it possible to create code that creates the correct amount of for loops (corresponding to the value of N)
and also changes the formula for i_value in a correct way.
i_Max = 8
i_value = [];
i_real = [];
i_first = [];
i_second = [];
i_third = [];
i_forth = [];
tol = 0.01;
i_good = false;
while i_good == false
% generate new ratio’s
for i_1 = 1:0.1:i_Max
for i_2 = 1:0.1:i_Max
for i_3 = 1:0.1:i_Max
for i_4 = 1:0.1:i_Max
i_value(end+1) = (i_1+i_2+i_3+i_4)/N;
if (i_average-tol <i_value(end)) && (i_value(end)<i_average+tol)…
&& (i_1>i_2) && (i_2>i_3) && (i_3>i_4)
i_good =true;
i_real(end+1) = i_value(end);
i_first(end+1) = i_1;
i_second(end+1) = i_2;
i_third(end+1) = i_3;
i_forth(end+1) = i_4;
end
end
end
end
end
end for loop, nested for loop MATLAB Answers — New Questions
Converting between x,y cartesian variables to angle in symbolic variables
Is there some way to write "Cartesian"-like constraints around symbolic variables? For example, is there any way to tell the toolbox that it should interpret x and y as Cartesian in the following code:
clear all;clc;close all
syms x y real
t=x/sqrt(x^2 + y^2);
And write "t" to be the cos of an angle between the (x,y) vector and the x-axis?Is there some way to write "Cartesian"-like constraints around symbolic variables? For example, is there any way to tell the toolbox that it should interpret x and y as Cartesian in the following code:
clear all;clc;close all
syms x y real
t=x/sqrt(x^2 + y^2);
And write "t" to be the cos of an angle between the (x,y) vector and the x-axis? Is there some way to write "Cartesian"-like constraints around symbolic variables? For example, is there any way to tell the toolbox that it should interpret x and y as Cartesian in the following code:
clear all;clc;close all
syms x y real
t=x/sqrt(x^2 + y^2);
And write "t" to be the cos of an angle between the (x,y) vector and the x-axis? symbolic, variables MATLAB Answers — New Questions
How to get the figures from IRI model?
Dear All,
I would like to use IRItest code that is written by Drew in this Matlab website, however I received an error that I do not know how to resolve it.
Would you please help me to run his code?
Here is the error that I have received.
Here is the link for code: https://www.mathworks.com/matlabcentral/fileexchange/34863-international-reference-ionosphere-iri-model
Thank you with my best regards,
Ara
Error in iritest (line 47)
parfor index = 1:NDear All,
I would like to use IRItest code that is written by Drew in this Matlab website, however I received an error that I do not know how to resolve it.
Would you please help me to run his code?
Here is the error that I have received.
Here is the link for code: https://www.mathworks.com/matlabcentral/fileexchange/34863-international-reference-ionosphere-iri-model
Thank you with my best regards,
Ara
Error in iritest (line 47)
parfor index = 1:N Dear All,
I would like to use IRItest code that is written by Drew in this Matlab website, however I received an error that I do not know how to resolve it.
Would you please help me to run his code?
Here is the error that I have received.
Here is the link for code: https://www.mathworks.com/matlabcentral/fileexchange/34863-international-reference-ionosphere-iri-model
Thank you with my best regards,
Ara
Error in iritest (line 47)
parfor index = 1:N iri MATLAB Answers — New Questions
Phase separation Contor graph of 2D Allen Cahn Equation
How can we plot the phase sepration contor graph for 2D Allen Cahn equation? The contor graph is changing with time and record the video.How can we plot the phase sepration contor graph for 2D Allen Cahn equation? The contor graph is changing with time and record the video. How can we plot the phase sepration contor graph for 2D Allen Cahn equation? The contor graph is changing with time and record the video. contor graph, image processing, allen cahn, phase sepration MATLAB Answers — New Questions
Hi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model. how can i proceed with it. any help please
Hi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help pleaseHi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help please Hi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help please transferred MATLAB Answers — New Questions
how to load mat file(trained neural ode) in simulink matlab function.
i have trained a neural ode and save in mat file. ánd use this mat file in simulink to simulate.i used matlab function and load the mat file in it but after run simulation it shows error.(The output of a call to ‘load’ is not assigned to a variable. Assign its output to a variable without subscripting.).
kindly help me is this issue.
or how i can use the trained neural ode in simulink.? might be my approch of using matlab function is wrong.i have trained a neural ode and save in mat file. ánd use this mat file in simulink to simulate.i used matlab function and load the mat file in it but after run simulation it shows error.(The output of a call to ‘load’ is not assigned to a variable. Assign its output to a variable without subscripting.).
kindly help me is this issue.
or how i can use the trained neural ode in simulink.? might be my approch of using matlab function is wrong. i have trained a neural ode and save in mat file. ánd use this mat file in simulink to simulate.i used matlab function and load the mat file in it but after run simulation it shows error.(The output of a call to ‘load’ is not assigned to a variable. Assign its output to a variable without subscripting.).
kindly help me is this issue.
or how i can use the trained neural ode in simulink.? might be my approch of using matlab function is wrong. neural ode in simulink MATLAB Answers — New Questions
How to load trained R-CNN model to SIMULINK
Below is the MATLAB code that I used to train my R-CNN Object Detector
rcnn = trainRCNNObjectDetector(ROI, cifar10Net, options, …
‘NegativeOverlapRange’, [0 0.3], ‘PositiveOverlapRange’,[0.5 1])
save(‘C:UsersPC1Desktoprcnn_Model_2.mat’,’rcnn’);
Now my problem is the blocks like ‘from File’ in SIMULINK can not take any MAT file that are not timeseries object.
Below in the data format that I saved using the codes above,
Name Size Bytes Class Attributes
rcnn 1×1 482631 rcnnObjectDetector
Below is the properties of the model after being loaded,
rcnn =
rcnnObjectDetector with properties:
Network: [1×1 SeriesNetwork]
ClassNames: {‘Left’ ‘Stop’ ‘Go’ ‘Right’ ‘Background’}
RegionProposalFcn: @rcnnObjectDetector.proposeRegions
So, is that any possible way to import the trained network to SIMULINK?Below is the MATLAB code that I used to train my R-CNN Object Detector
rcnn = trainRCNNObjectDetector(ROI, cifar10Net, options, …
‘NegativeOverlapRange’, [0 0.3], ‘PositiveOverlapRange’,[0.5 1])
save(‘C:UsersPC1Desktoprcnn_Model_2.mat’,’rcnn’);
Now my problem is the blocks like ‘from File’ in SIMULINK can not take any MAT file that are not timeseries object.
Below in the data format that I saved using the codes above,
Name Size Bytes Class Attributes
rcnn 1×1 482631 rcnnObjectDetector
Below is the properties of the model after being loaded,
rcnn =
rcnnObjectDetector with properties:
Network: [1×1 SeriesNetwork]
ClassNames: {‘Left’ ‘Stop’ ‘Go’ ‘Right’ ‘Background’}
RegionProposalFcn: @rcnnObjectDetector.proposeRegions
So, is that any possible way to import the trained network to SIMULINK? Below is the MATLAB code that I used to train my R-CNN Object Detector
rcnn = trainRCNNObjectDetector(ROI, cifar10Net, options, …
‘NegativeOverlapRange’, [0 0.3], ‘PositiveOverlapRange’,[0.5 1])
save(‘C:UsersPC1Desktoprcnn_Model_2.mat’,’rcnn’);
Now my problem is the blocks like ‘from File’ in SIMULINK can not take any MAT file that are not timeseries object.
Below in the data format that I saved using the codes above,
Name Size Bytes Class Attributes
rcnn 1×1 482631 rcnnObjectDetector
Below is the properties of the model after being loaded,
rcnn =
rcnnObjectDetector with properties:
Network: [1×1 SeriesNetwork]
ClassNames: {‘Left’ ‘Stop’ ‘Go’ ‘Right’ ‘Background’}
RegionProposalFcn: @rcnnObjectDetector.proposeRegions
So, is that any possible way to import the trained network to SIMULINK? r-cnn, neural networks MATLAB Answers — New Questions
c-mex S-Function error in desktop real-time external mode: Error occurred while executing External Mode MEX-file ‘sldrtext’: Error loading real-time image: undefined symbol
I have encountered some issues with an S-Function I developed using c-mex. The purpose of my S-Function is to add two inputs together, and I have implemented this functionality using external c source code and header files. Here are the contents of these files:
myadd.h
int myadd(int a, int b);
myadd.c
#include "myadd.h"
int myadd(int a, int b)
{
return a+b;
}
and my S-Function is mysfun.c, its output function is:
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
I compiled them along with my S-Function using the following command:
mex mysfun.c myadd.c
The compilation process showed no errors. Next, I tested the S-Function in normal mode in Simulink, and it indeed worked properly. However, when I switched to Simulink Desktop Real-Time’s external mode, I encountered the following error message:
”’
Error occurred while executing External Mode MEX-file ‘sldrtext’: Error loading real-time image: undefined symbol "myadd"
”’
But when I implement myadd() function directly in mysfun.c, like:
int myadd(int a, int b)
{
return a+b;
}
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
the execution in external mode worked properly. I have no idea what is the problem.
Could someone please help me understand this error message? Thank you!I have encountered some issues with an S-Function I developed using c-mex. The purpose of my S-Function is to add two inputs together, and I have implemented this functionality using external c source code and header files. Here are the contents of these files:
myadd.h
int myadd(int a, int b);
myadd.c
#include "myadd.h"
int myadd(int a, int b)
{
return a+b;
}
and my S-Function is mysfun.c, its output function is:
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
I compiled them along with my S-Function using the following command:
mex mysfun.c myadd.c
The compilation process showed no errors. Next, I tested the S-Function in normal mode in Simulink, and it indeed worked properly. However, when I switched to Simulink Desktop Real-Time’s external mode, I encountered the following error message:
”’
Error occurred while executing External Mode MEX-file ‘sldrtext’: Error loading real-time image: undefined symbol "myadd"
”’
But when I implement myadd() function directly in mysfun.c, like:
int myadd(int a, int b)
{
return a+b;
}
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
the execution in external mode worked properly. I have no idea what is the problem.
Could someone please help me understand this error message? Thank you! I have encountered some issues with an S-Function I developed using c-mex. The purpose of my S-Function is to add two inputs together, and I have implemented this functionality using external c source code and header files. Here are the contents of these files:
myadd.h
int myadd(int a, int b);
myadd.c
#include "myadd.h"
int myadd(int a, int b)
{
return a+b;
}
and my S-Function is mysfun.c, its output function is:
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
I compiled them along with my S-Function using the following command:
mex mysfun.c myadd.c
The compilation process showed no errors. Next, I tested the S-Function in normal mode in Simulink, and it indeed worked properly. However, when I switched to Simulink Desktop Real-Time’s external mode, I encountered the following error message:
”’
Error occurred while executing External Mode MEX-file ‘sldrtext’: Error loading real-time image: undefined symbol "myadd"
”’
But when I implement myadd() function directly in mysfun.c, like:
int myadd(int a, int b)
{
return a+b;
}
static void mdlOutputs(SimStruct *S, int_T tid)
{
const real_T *u = (const real_T*) ssGetInputPortSignal(S,0);
real_T *y = ssGetOutputPortSignal(S,0);
y[0] = myadd((int)u[0],10);
}
the execution in external mode worked properly. I have no idea what is the problem.
Could someone please help me understand this error message? Thank you! c-mex, s-function, real-time MATLAB Answers — New Questions
How do I install MFE toolbox to my current MATLAB software?
Hi All,
Could anyone advice how can I install the MFE toolbox by https://www.kevinsheppard.com/code/matlab/mfe-toolbox/ into the program?
I really need to use the model in the toolbox.
Many Thanks,Hi All,
Could anyone advice how can I install the MFE toolbox by https://www.kevinsheppard.com/code/matlab/mfe-toolbox/ into the program?
I really need to use the model in the toolbox.
Many Thanks, Hi All,
Could anyone advice how can I install the MFE toolbox by https://www.kevinsheppard.com/code/matlab/mfe-toolbox/ into the program?
I really need to use the model in the toolbox.
Many Thanks, mfe toolbox, toolbox install MATLAB Answers — New Questions
loading lstm trained model in simulink
Hi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help pleaseHi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help please Hi everyone , i have LSTM trained model (time series sequence) which i want to load in my simulink model.
how can i proceed with it. any help please #lstm MATLAB Answers — New Questions
plot the output c(t) using mathlab and show setting time on you graphf
syms t tau;
A = [0 2; -2 -5];
B = [0; 1];
C = [2 1];
x0 = [1; 2];
Phi_t = expm(A*t);
x_h = Phi_t * x0;
u_tau = 1; % Unit step function
x_p = int(Phi_t * B, tau, 0, t);
x_t = x_h + x_p;
y_t = C * x_t;
disp(‘State-transition matrix Phi(t):’);
disp(Phi_t);
fplot(Phi_t(1,1))
disp(‘Homogeneous solution x_h(t):’);
disp(x_h);
fplot(x_h)
disp(‘Particular solution x_p(t):’);
disp(x_p);
disp(‘Full state vector x(t):’);
disp(x_t);
disp(‘Output y(t):’);
disp(y_t);syms t tau;
A = [0 2; -2 -5];
B = [0; 1];
C = [2 1];
x0 = [1; 2];
Phi_t = expm(A*t);
x_h = Phi_t * x0;
u_tau = 1; % Unit step function
x_p = int(Phi_t * B, tau, 0, t);
x_t = x_h + x_p;
y_t = C * x_t;
disp(‘State-transition matrix Phi(t):’);
disp(Phi_t);
fplot(Phi_t(1,1))
disp(‘Homogeneous solution x_h(t):’);
disp(x_h);
fplot(x_h)
disp(‘Particular solution x_p(t):’);
disp(x_p);
disp(‘Full state vector x(t):’);
disp(x_t);
disp(‘Output y(t):’);
disp(y_t); syms t tau;
A = [0 2; -2 -5];
B = [0; 1];
C = [2 1];
x0 = [1; 2];
Phi_t = expm(A*t);
x_h = Phi_t * x0;
u_tau = 1; % Unit step function
x_p = int(Phi_t * B, tau, 0, t);
x_t = x_h + x_p;
y_t = C * x_t;
disp(‘State-transition matrix Phi(t):’);
disp(Phi_t);
fplot(Phi_t(1,1))
disp(‘Homogeneous solution x_h(t):’);
disp(x_h);
fplot(x_h)
disp(‘Particular solution x_p(t):’);
disp(x_p);
disp(‘Full state vector x(t):’);
disp(x_t);
disp(‘Output y(t):’);
disp(y_t); first order system MATLAB Answers — New Questions
How to make Matlab recognize that an expression rewritten by using subexpr() is equal to the original expression?
I would expect the isAlways() function below to return 1 but for some reason Matlab does not recognize that x=x_2. Is there a way to solve this problem?
syms a b c d e f x
x = a + (a+b+c+d+e)^(1/2) + c*(e+f+(a+b+c+d+e)^(1/2));
x_2 = subexpr(x)
isAlways(x_2==x)I would expect the isAlways() function below to return 1 but for some reason Matlab does not recognize that x=x_2. Is there a way to solve this problem?
syms a b c d e f x
x = a + (a+b+c+d+e)^(1/2) + c*(e+f+(a+b+c+d+e)^(1/2));
x_2 = subexpr(x)
isAlways(x_2==x) I would expect the isAlways() function below to return 1 but for some reason Matlab does not recognize that x=x_2. Is there a way to solve this problem?
syms a b c d e f x
x = a + (a+b+c+d+e)^(1/2) + c*(e+f+(a+b+c+d+e)^(1/2));
x_2 = subexpr(x)
isAlways(x_2==x) symbolic MATLAB Answers — New Questions
Plot between Nu vs Ra
I need to plot for Nu vs Ra.
The given code is giving multiple plots.
I need a single plot for Nu vs Ra.
Please check the code for single plot. Thanks in advance.
D = 0.1;
L = 0.1;
B = 0.1;
xi = 0.1;
sigma1 = B^3 * D^2 * L^3;
sigma2 = D^2 * L^3;
Ra_values = 10:100:100000;
solutions = zeros(length(Ra_values), 7);
for i = 1:length(Ra_values)
Ra = Ra_values(i);
R = Ra * xi;
f1 = @(A) -((5*A(2)*A(6)*pi^5*B^2*D^2*L^4)/8 + (A(2)*A(6)*pi^5*D^4*L^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/4 – (A(1)*L^4*pi^4)/2 – (32*A(5)*L^4*Ra)/9 + (A(1)*L^4*R*pi^2)/2 + (5*A(4)*A(7)*D^2*L^2*pi^5)/8))/sigma2;
f2 = @(A) -(B^2 * (A(2)*A(5)*D^2*L^4*pi^5 – (A(2)*D^2*L^4*pi^4)/2 – (A(1)*A(6)*D^2*L^4*pi^5)/8 – (4*A(6)*D^2*L^4*Ra)/9 + (A(4)*A(7)*D^2*L^4*pi^5)/2 + (3*A(4)*A(7)*D^4*L^2*pi^5)/16 + (A(2)*D^2*L^4*R*pi^2)/4) – (A(2)*D^4*L^4*pi^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/8 – (A(2)*L^4*pi^4)/4 – (16*A(6)*L^4*Ra)/9 + (A(2)*L^4*R*pi^2)/4 + (5*A(4)*A(7)*D^2*L^2*pi^5)/16))/sigma2;
f3 = @(A) (B * ((16*A(7)*L^4*Ra)/9 + (A(3)*D^4*pi^4)/4 + (A(3)*L^4*pi^4)/4 – (A(3)*L^4*R*pi^2)/4 + (A(3)*D^2*L^2*pi^4)/2 + (A(1)*A(7)*D^2*L^2*pi^5)/8 – A(3)*A(5)*D^2*L^2*pi^5 – (A(4)*A(6)*D^2*L^2*pi^5)/2))/sigma2 – (B^2 * ((3*A(4)*A(6)*pi^5*D^4*L^2)/16 + (5*A(4)*A(6)*pi^5*D^2*L^4)/16) + (A(4)*A(6)*D^4*L^4*pi^5)/8)/sigma1;
f4 = @(A) (B * pi^2 * (2*A(4)*D^4*pi^2 – 2*A(4)*L^4*R + 2*A(4)*L^4*pi^2 + 4*A(4)*D^2*L^2*pi^2 + A(2)*A(7)*D^2*L^2*pi^3 – 8*A(3)*A(6)*D^2*L^2*pi^3 – 8*A(4)*A(5)*D^2*L^2*pi^3))/(16*D^2*L^3) – ((B^2 * pi^2 * (2*A(4)*D^2*L^4*R – 4*A(4)*D^2*L^4*pi^2 – 4*A(4)*D^4*L^2*pi^2 + 8*A(2)*A(7)*D^2*L^4*pi^3 + A(2)*A(7)*D^4*L^2*pi^3 – A(3)*A(6)*D^2*L^4*pi^3 + A(3)*A(6)*D^4*L^2*pi^3 + 8*A(4)*A(5)*D^2*L^4*pi^3))/16 – (A(4)*D^4*L^4*pi^4)/8)/sigma1;
f5 = @(A) (B^2 * ((pi^5*A(2)^2*D^2*L^4)/4 + (pi^5*A(4)^2*D^4*L^2)/4 + (pi^5*A(4)^2*D^2*L^4)/8) + (A(2)^2*D^4*L^4*pi^5)/4 + (A(4)^2*D^4*L^4*pi^5)/8)/sigma1 + (B * ((A(3)^2*D^4*pi^5)/4 + (A(4)^2*D^4*pi^5)/8 + (8*A(1)*L^4*Ra)/9 + 8*A(5)*L^4*pi^4 – 2*A(5)*L^4*R*pi^2 + (A(3)^2*D^2*L^2*pi^5)/4 + (A(4)^2*D^2*L^2*pi^5)/8))/sigma2;
f6 = @(A) (B^2 * ((4*A(2)*D^2*L^4*Ra)/9 + 2*A(6)*D^2*L^4*pi^4 + (A(1)*A(2)*D^2*L^4*pi^5)/8 + (A(3)*A(4)*D^2*L^4*pi^5)/16 + (3*A(3)*A(4)*D^4*L^2*pi^5)/16 – (A(6)*D^2*L^4*R*pi^2)/4) + (A(6)*D^4*L^4*pi^4)/4)/sigma1 + (B * (4*A(2)*L^4*Ra)/9 + 4*A(6)*L^4*pi^4 + (A(3)*A(4)*D^4*pi^5)/4 – A(6)*L^4*R*pi^2 + (A(3)*A(4)*D^2*L^2*pi^5)/4)/sigma2;
f7 = @(A) (B * ((4*A(3)*L^4*Ra)/9 + (A(7)*D^4*pi^4)/4 + 4*A(7)*L^4*pi^4 – A(7)*L^4*R*pi^2 + 2*A(7)*D^2*L^2*pi^4 + (A(1)*A(3)*D^2*L^2*pi^5)/8 + (A(2)*A(4)*D^2*L^2*pi^5)/16))/sigma2 + (B^2 * ((3*A(2)*A(4)*pi^5*D^4*L^2)/16 + (A(2)*A(4)*pi^5*D^2*L^4)/4) + (A(2)*A(4)*D^4*L^4*pi^5)/4)/sigma1;
F = @(A) [f1(A); f2(A); f3(A); f4(A); f5(A); f6(A); f7(A)];
A0 = [0.001, 0.001, 0.001, 0.001, 0.001, 0.001, 0.001];
A = fsolve(F, A0);
solutions(i, 🙂 = A;
end
A1_1_1 = solutions(:, 1);
A2_1_1 = solutions(:, 5);
Nu = xi – 1./2 – (pi^3 ./ Ra_values) .* A1_1_1 – (8 * pi^3 ./ Ra_values) .* A2_1_1;
plot(Ra_values, Nu);
xlabel(‘Ra’);
ylabel(‘Nu’);I need to plot for Nu vs Ra.
The given code is giving multiple plots.
I need a single plot for Nu vs Ra.
Please check the code for single plot. Thanks in advance.
D = 0.1;
L = 0.1;
B = 0.1;
xi = 0.1;
sigma1 = B^3 * D^2 * L^3;
sigma2 = D^2 * L^3;
Ra_values = 10:100:100000;
solutions = zeros(length(Ra_values), 7);
for i = 1:length(Ra_values)
Ra = Ra_values(i);
R = Ra * xi;
f1 = @(A) -((5*A(2)*A(6)*pi^5*B^2*D^2*L^4)/8 + (A(2)*A(6)*pi^5*D^4*L^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/4 – (A(1)*L^4*pi^4)/2 – (32*A(5)*L^4*Ra)/9 + (A(1)*L^4*R*pi^2)/2 + (5*A(4)*A(7)*D^2*L^2*pi^5)/8))/sigma2;
f2 = @(A) -(B^2 * (A(2)*A(5)*D^2*L^4*pi^5 – (A(2)*D^2*L^4*pi^4)/2 – (A(1)*A(6)*D^2*L^4*pi^5)/8 – (4*A(6)*D^2*L^4*Ra)/9 + (A(4)*A(7)*D^2*L^4*pi^5)/2 + (3*A(4)*A(7)*D^4*L^2*pi^5)/16 + (A(2)*D^2*L^4*R*pi^2)/4) – (A(2)*D^4*L^4*pi^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/8 – (A(2)*L^4*pi^4)/4 – (16*A(6)*L^4*Ra)/9 + (A(2)*L^4*R*pi^2)/4 + (5*A(4)*A(7)*D^2*L^2*pi^5)/16))/sigma2;
f3 = @(A) (B * ((16*A(7)*L^4*Ra)/9 + (A(3)*D^4*pi^4)/4 + (A(3)*L^4*pi^4)/4 – (A(3)*L^4*R*pi^2)/4 + (A(3)*D^2*L^2*pi^4)/2 + (A(1)*A(7)*D^2*L^2*pi^5)/8 – A(3)*A(5)*D^2*L^2*pi^5 – (A(4)*A(6)*D^2*L^2*pi^5)/2))/sigma2 – (B^2 * ((3*A(4)*A(6)*pi^5*D^4*L^2)/16 + (5*A(4)*A(6)*pi^5*D^2*L^4)/16) + (A(4)*A(6)*D^4*L^4*pi^5)/8)/sigma1;
f4 = @(A) (B * pi^2 * (2*A(4)*D^4*pi^2 – 2*A(4)*L^4*R + 2*A(4)*L^4*pi^2 + 4*A(4)*D^2*L^2*pi^2 + A(2)*A(7)*D^2*L^2*pi^3 – 8*A(3)*A(6)*D^2*L^2*pi^3 – 8*A(4)*A(5)*D^2*L^2*pi^3))/(16*D^2*L^3) – ((B^2 * pi^2 * (2*A(4)*D^2*L^4*R – 4*A(4)*D^2*L^4*pi^2 – 4*A(4)*D^4*L^2*pi^2 + 8*A(2)*A(7)*D^2*L^4*pi^3 + A(2)*A(7)*D^4*L^2*pi^3 – A(3)*A(6)*D^2*L^4*pi^3 + A(3)*A(6)*D^4*L^2*pi^3 + 8*A(4)*A(5)*D^2*L^4*pi^3))/16 – (A(4)*D^4*L^4*pi^4)/8)/sigma1;
f5 = @(A) (B^2 * ((pi^5*A(2)^2*D^2*L^4)/4 + (pi^5*A(4)^2*D^4*L^2)/4 + (pi^5*A(4)^2*D^2*L^4)/8) + (A(2)^2*D^4*L^4*pi^5)/4 + (A(4)^2*D^4*L^4*pi^5)/8)/sigma1 + (B * ((A(3)^2*D^4*pi^5)/4 + (A(4)^2*D^4*pi^5)/8 + (8*A(1)*L^4*Ra)/9 + 8*A(5)*L^4*pi^4 – 2*A(5)*L^4*R*pi^2 + (A(3)^2*D^2*L^2*pi^5)/4 + (A(4)^2*D^2*L^2*pi^5)/8))/sigma2;
f6 = @(A) (B^2 * ((4*A(2)*D^2*L^4*Ra)/9 + 2*A(6)*D^2*L^4*pi^4 + (A(1)*A(2)*D^2*L^4*pi^5)/8 + (A(3)*A(4)*D^2*L^4*pi^5)/16 + (3*A(3)*A(4)*D^4*L^2*pi^5)/16 – (A(6)*D^2*L^4*R*pi^2)/4) + (A(6)*D^4*L^4*pi^4)/4)/sigma1 + (B * (4*A(2)*L^4*Ra)/9 + 4*A(6)*L^4*pi^4 + (A(3)*A(4)*D^4*pi^5)/4 – A(6)*L^4*R*pi^2 + (A(3)*A(4)*D^2*L^2*pi^5)/4)/sigma2;
f7 = @(A) (B * ((4*A(3)*L^4*Ra)/9 + (A(7)*D^4*pi^4)/4 + 4*A(7)*L^4*pi^4 – A(7)*L^4*R*pi^2 + 2*A(7)*D^2*L^2*pi^4 + (A(1)*A(3)*D^2*L^2*pi^5)/8 + (A(2)*A(4)*D^2*L^2*pi^5)/16))/sigma2 + (B^2 * ((3*A(2)*A(4)*pi^5*D^4*L^2)/16 + (A(2)*A(4)*pi^5*D^2*L^4)/4) + (A(2)*A(4)*D^4*L^4*pi^5)/4)/sigma1;
F = @(A) [f1(A); f2(A); f3(A); f4(A); f5(A); f6(A); f7(A)];
A0 = [0.001, 0.001, 0.001, 0.001, 0.001, 0.001, 0.001];
A = fsolve(F, A0);
solutions(i, 🙂 = A;
end
A1_1_1 = solutions(:, 1);
A2_1_1 = solutions(:, 5);
Nu = xi – 1./2 – (pi^3 ./ Ra_values) .* A1_1_1 – (8 * pi^3 ./ Ra_values) .* A2_1_1;
plot(Ra_values, Nu);
xlabel(‘Ra’);
ylabel(‘Nu’); I need to plot for Nu vs Ra.
The given code is giving multiple plots.
I need a single plot for Nu vs Ra.
Please check the code for single plot. Thanks in advance.
D = 0.1;
L = 0.1;
B = 0.1;
xi = 0.1;
sigma1 = B^3 * D^2 * L^3;
sigma2 = D^2 * L^3;
Ra_values = 10:100:100000;
solutions = zeros(length(Ra_values), 7);
for i = 1:length(Ra_values)
Ra = Ra_values(i);
R = Ra * xi;
f1 = @(A) -((5*A(2)*A(6)*pi^5*B^2*D^2*L^4)/8 + (A(2)*A(6)*pi^5*D^4*L^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/4 – (A(1)*L^4*pi^4)/2 – (32*A(5)*L^4*Ra)/9 + (A(1)*L^4*R*pi^2)/2 + (5*A(4)*A(7)*D^2*L^2*pi^5)/8))/sigma2;
f2 = @(A) -(B^2 * (A(2)*A(5)*D^2*L^4*pi^5 – (A(2)*D^2*L^4*pi^4)/2 – (A(1)*A(6)*D^2*L^4*pi^5)/8 – (4*A(6)*D^2*L^4*Ra)/9 + (A(4)*A(7)*D^2*L^4*pi^5)/2 + (3*A(4)*A(7)*D^4*L^2*pi^5)/16 + (A(2)*D^2*L^4*R*pi^2)/4) – (A(2)*D^4*L^4*pi^4)/4)/sigma1 – (B * ((A(4)*A(7)*D^4*pi^5)/8 – (A(2)*L^4*pi^4)/4 – (16*A(6)*L^4*Ra)/9 + (A(2)*L^4*R*pi^2)/4 + (5*A(4)*A(7)*D^2*L^2*pi^5)/16))/sigma2;
f3 = @(A) (B * ((16*A(7)*L^4*Ra)/9 + (A(3)*D^4*pi^4)/4 + (A(3)*L^4*pi^4)/4 – (A(3)*L^4*R*pi^2)/4 + (A(3)*D^2*L^2*pi^4)/2 + (A(1)*A(7)*D^2*L^2*pi^5)/8 – A(3)*A(5)*D^2*L^2*pi^5 – (A(4)*A(6)*D^2*L^2*pi^5)/2))/sigma2 – (B^2 * ((3*A(4)*A(6)*pi^5*D^4*L^2)/16 + (5*A(4)*A(6)*pi^5*D^2*L^4)/16) + (A(4)*A(6)*D^4*L^4*pi^5)/8)/sigma1;
f4 = @(A) (B * pi^2 * (2*A(4)*D^4*pi^2 – 2*A(4)*L^4*R + 2*A(4)*L^4*pi^2 + 4*A(4)*D^2*L^2*pi^2 + A(2)*A(7)*D^2*L^2*pi^3 – 8*A(3)*A(6)*D^2*L^2*pi^3 – 8*A(4)*A(5)*D^2*L^2*pi^3))/(16*D^2*L^3) – ((B^2 * pi^2 * (2*A(4)*D^2*L^4*R – 4*A(4)*D^2*L^4*pi^2 – 4*A(4)*D^4*L^2*pi^2 + 8*A(2)*A(7)*D^2*L^4*pi^3 + A(2)*A(7)*D^4*L^2*pi^3 – A(3)*A(6)*D^2*L^4*pi^3 + A(3)*A(6)*D^4*L^2*pi^3 + 8*A(4)*A(5)*D^2*L^4*pi^3))/16 – (A(4)*D^4*L^4*pi^4)/8)/sigma1;
f5 = @(A) (B^2 * ((pi^5*A(2)^2*D^2*L^4)/4 + (pi^5*A(4)^2*D^4*L^2)/4 + (pi^5*A(4)^2*D^2*L^4)/8) + (A(2)^2*D^4*L^4*pi^5)/4 + (A(4)^2*D^4*L^4*pi^5)/8)/sigma1 + (B * ((A(3)^2*D^4*pi^5)/4 + (A(4)^2*D^4*pi^5)/8 + (8*A(1)*L^4*Ra)/9 + 8*A(5)*L^4*pi^4 – 2*A(5)*L^4*R*pi^2 + (A(3)^2*D^2*L^2*pi^5)/4 + (A(4)^2*D^2*L^2*pi^5)/8))/sigma2;
f6 = @(A) (B^2 * ((4*A(2)*D^2*L^4*Ra)/9 + 2*A(6)*D^2*L^4*pi^4 + (A(1)*A(2)*D^2*L^4*pi^5)/8 + (A(3)*A(4)*D^2*L^4*pi^5)/16 + (3*A(3)*A(4)*D^4*L^2*pi^5)/16 – (A(6)*D^2*L^4*R*pi^2)/4) + (A(6)*D^4*L^4*pi^4)/4)/sigma1 + (B * (4*A(2)*L^4*Ra)/9 + 4*A(6)*L^4*pi^4 + (A(3)*A(4)*D^4*pi^5)/4 – A(6)*L^4*R*pi^2 + (A(3)*A(4)*D^2*L^2*pi^5)/4)/sigma2;
f7 = @(A) (B * ((4*A(3)*L^4*Ra)/9 + (A(7)*D^4*pi^4)/4 + 4*A(7)*L^4*pi^4 – A(7)*L^4*R*pi^2 + 2*A(7)*D^2*L^2*pi^4 + (A(1)*A(3)*D^2*L^2*pi^5)/8 + (A(2)*A(4)*D^2*L^2*pi^5)/16))/sigma2 + (B^2 * ((3*A(2)*A(4)*pi^5*D^4*L^2)/16 + (A(2)*A(4)*pi^5*D^2*L^4)/4) + (A(2)*A(4)*D^4*L^4*pi^5)/4)/sigma1;
F = @(A) [f1(A); f2(A); f3(A); f4(A); f5(A); f6(A); f7(A)];
A0 = [0.001, 0.001, 0.001, 0.001, 0.001, 0.001, 0.001];
A = fsolve(F, A0);
solutions(i, 🙂 = A;
end
A1_1_1 = solutions(:, 1);
A2_1_1 = solutions(:, 5);
Nu = xi – 1./2 – (pi^3 ./ Ra_values) .* A1_1_1 – (8 * pi^3 ./ Ra_values) .* A2_1_1;
plot(Ra_values, Nu);
xlabel(‘Ra’);
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