Category: News
How to convert csv to Heatmap?
Hello, I am relatively new to using MATLAB so I am coming across some issues. I want to convert a .csv file with A LOT of raw data and visualize it as a heatmap. It is a 36189×88 data table. This code I have so far shows something but it is not really giving me what I want. Any help or advice would be greatly appreciated.
clc;
clear
close all;
data = readtable("N303_M.2.csv");
%% Data Filtering/Processing
clc, clearvars -except data, format compact, close all
%convert from Table to Array
strain(:, 1:88) = table2array(data(:,1:88));
%% Data Visualizations
figure(1);
plot(strain(:, 1:88));
heatmap(strain(:, 1:88),’Colormap’, jet,)
title(‘Visual Data for Mat’)Hello, I am relatively new to using MATLAB so I am coming across some issues. I want to convert a .csv file with A LOT of raw data and visualize it as a heatmap. It is a 36189×88 data table. This code I have so far shows something but it is not really giving me what I want. Any help or advice would be greatly appreciated.
clc;
clear
close all;
data = readtable("N303_M.2.csv");
%% Data Filtering/Processing
clc, clearvars -except data, format compact, close all
%convert from Table to Array
strain(:, 1:88) = table2array(data(:,1:88));
%% Data Visualizations
figure(1);
plot(strain(:, 1:88));
heatmap(strain(:, 1:88),’Colormap’, jet,)
title(‘Visual Data for Mat’) Hello, I am relatively new to using MATLAB so I am coming across some issues. I want to convert a .csv file with A LOT of raw data and visualize it as a heatmap. It is a 36189×88 data table. This code I have so far shows something but it is not really giving me what I want. Any help or advice would be greatly appreciated.
clc;
clear
close all;
data = readtable("N303_M.2.csv");
%% Data Filtering/Processing
clc, clearvars -except data, format compact, close all
%convert from Table to Array
strain(:, 1:88) = table2array(data(:,1:88));
%% Data Visualizations
figure(1);
plot(strain(:, 1:88));
heatmap(strain(:, 1:88),’Colormap’, jet,)
title(‘Visual Data for Mat’) heatmap, csv, raw data, matlab MATLAB Answers — New Questions
How to callback same function for changes in multiple uiobjects?
I am creating a uifigure-based app programatically for de-noising the noisy images. The code for which is as follows:
function filteredImage
fig = uifigure;
g = uigridlayout(fig,[3 2]);
g.RowHeight = {30,30,’1x’};
g.ColumnSpacing = 10;
filterLabel = uilabel(g,"Text","Filter Type","WordWrap","on","FontSize",18,"FontWeight","bold");
filterLabel.Layout.Row = 1;
filterLabel.Layout.Column = 1;
% Choose type of filter to be displayed
filterType = uidropdown(g,"Editable","on","Position",[0 50 20 10],"FontSize",18);
filterType.Layout.Row = 1;
filterType.Layout.Column = 2;
filterType.Items = ["Arithmetic Mean Filter",
"Geometric Mean Filter",
"Weighted Average Filter"];
kernelDimlabel = uilabel("Parent",g,"Text","Kernel Dimensions","FontSize",18,"FontWeight","bold");
kernelDimlabel.Layout.Row = 2;
kernelDimlabel.Layout.Column = 1;
% Set the kernel size (since it is a square matrix, #rows = #columns)
kernelDim = uispinner("Parent",g,"Step",2,"Value",3,"Limits",[3 11],"FontSize",18);
kernelDim.Layout.Row = 2;
kernelDim.Layout.Column = 2;
% Noisy image displayed
im1 = uiimage(g,"ImageSource","poutsalt & pepper.png");
im1.Layout.Row = 3;
im1.Layout.Column = 1;
% Filtered image displayed
im2 = uiimage(g);
im2.Layout.Row = 3;
im2.Layout.Column = 2;
% Here, filterImage updates im2 whenever the value of filterType changes
filterType.ValueChangedFcn = @(src,event)filterImage(src,event,im1,im2,filterType,kernelDim);
% I want to update im2 when either the value of filterType changes OR when
% kernelDim changes
end
function filterImage(src,event,im1,im2,filterType,kernelDim)
kDim = kernelDim.Value;
I = imread(im1.ImageSource);
I_name = erase(im1.ImageSource,".png");
incr = floor(kDim/2);
im1_padded = double(padarray(I,[incr incr],0,’both’));
[r,c] = size(I);
switch filterType.Value
case "Arithmetic Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = (1/(kDim*kDim))*sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_amf"+"_"+ string(kDim) + ".png";
case "Geometric Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = prod(prod(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1))).^(1/(kDim*kDim));
end
end
ext = "_gmf"+"_"+ string(kDim) + ".png";
case "Weighted Average Filter"
if kDim == 3
kernel = (1/16)*[1 2 1;
2 4 2;
1 2 1];
else
kernel = (1/52)*[1 1 2 1 1;
1 2 4 2 1;
2 4 8 4 2;
1 2 4 2 1;
1 1 2 1 1];
end
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_waf"+"_"+ string(kDim) + ".png";
end
I_filtered = uint8(I_filtered);
filteredImagePath = strcat(I_name,ext);
imwrite(I_filtered,filteredImagePath);
im2.ImageSource = filteredImagePath;
end
As of now I am getting the filtered image output. Initially there’s no image in im2. But it appears only after I change the kernelDim followed by filterType. One obvious way is to explicitly write the code for initial values, but I want the function filterImage to somehow do it.
Please suggest techniques to do the same in an efficient manner.I am creating a uifigure-based app programatically for de-noising the noisy images. The code for which is as follows:
function filteredImage
fig = uifigure;
g = uigridlayout(fig,[3 2]);
g.RowHeight = {30,30,’1x’};
g.ColumnSpacing = 10;
filterLabel = uilabel(g,"Text","Filter Type","WordWrap","on","FontSize",18,"FontWeight","bold");
filterLabel.Layout.Row = 1;
filterLabel.Layout.Column = 1;
% Choose type of filter to be displayed
filterType = uidropdown(g,"Editable","on","Position",[0 50 20 10],"FontSize",18);
filterType.Layout.Row = 1;
filterType.Layout.Column = 2;
filterType.Items = ["Arithmetic Mean Filter",
"Geometric Mean Filter",
"Weighted Average Filter"];
kernelDimlabel = uilabel("Parent",g,"Text","Kernel Dimensions","FontSize",18,"FontWeight","bold");
kernelDimlabel.Layout.Row = 2;
kernelDimlabel.Layout.Column = 1;
% Set the kernel size (since it is a square matrix, #rows = #columns)
kernelDim = uispinner("Parent",g,"Step",2,"Value",3,"Limits",[3 11],"FontSize",18);
kernelDim.Layout.Row = 2;
kernelDim.Layout.Column = 2;
% Noisy image displayed
im1 = uiimage(g,"ImageSource","poutsalt & pepper.png");
im1.Layout.Row = 3;
im1.Layout.Column = 1;
% Filtered image displayed
im2 = uiimage(g);
im2.Layout.Row = 3;
im2.Layout.Column = 2;
% Here, filterImage updates im2 whenever the value of filterType changes
filterType.ValueChangedFcn = @(src,event)filterImage(src,event,im1,im2,filterType,kernelDim);
% I want to update im2 when either the value of filterType changes OR when
% kernelDim changes
end
function filterImage(src,event,im1,im2,filterType,kernelDim)
kDim = kernelDim.Value;
I = imread(im1.ImageSource);
I_name = erase(im1.ImageSource,".png");
incr = floor(kDim/2);
im1_padded = double(padarray(I,[incr incr],0,’both’));
[r,c] = size(I);
switch filterType.Value
case "Arithmetic Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = (1/(kDim*kDim))*sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_amf"+"_"+ string(kDim) + ".png";
case "Geometric Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = prod(prod(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1))).^(1/(kDim*kDim));
end
end
ext = "_gmf"+"_"+ string(kDim) + ".png";
case "Weighted Average Filter"
if kDim == 3
kernel = (1/16)*[1 2 1;
2 4 2;
1 2 1];
else
kernel = (1/52)*[1 1 2 1 1;
1 2 4 2 1;
2 4 8 4 2;
1 2 4 2 1;
1 1 2 1 1];
end
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_waf"+"_"+ string(kDim) + ".png";
end
I_filtered = uint8(I_filtered);
filteredImagePath = strcat(I_name,ext);
imwrite(I_filtered,filteredImagePath);
im2.ImageSource = filteredImagePath;
end
As of now I am getting the filtered image output. Initially there’s no image in im2. But it appears only after I change the kernelDim followed by filterType. One obvious way is to explicitly write the code for initial values, but I want the function filterImage to somehow do it.
Please suggest techniques to do the same in an efficient manner. I am creating a uifigure-based app programatically for de-noising the noisy images. The code for which is as follows:
function filteredImage
fig = uifigure;
g = uigridlayout(fig,[3 2]);
g.RowHeight = {30,30,’1x’};
g.ColumnSpacing = 10;
filterLabel = uilabel(g,"Text","Filter Type","WordWrap","on","FontSize",18,"FontWeight","bold");
filterLabel.Layout.Row = 1;
filterLabel.Layout.Column = 1;
% Choose type of filter to be displayed
filterType = uidropdown(g,"Editable","on","Position",[0 50 20 10],"FontSize",18);
filterType.Layout.Row = 1;
filterType.Layout.Column = 2;
filterType.Items = ["Arithmetic Mean Filter",
"Geometric Mean Filter",
"Weighted Average Filter"];
kernelDimlabel = uilabel("Parent",g,"Text","Kernel Dimensions","FontSize",18,"FontWeight","bold");
kernelDimlabel.Layout.Row = 2;
kernelDimlabel.Layout.Column = 1;
% Set the kernel size (since it is a square matrix, #rows = #columns)
kernelDim = uispinner("Parent",g,"Step",2,"Value",3,"Limits",[3 11],"FontSize",18);
kernelDim.Layout.Row = 2;
kernelDim.Layout.Column = 2;
% Noisy image displayed
im1 = uiimage(g,"ImageSource","poutsalt & pepper.png");
im1.Layout.Row = 3;
im1.Layout.Column = 1;
% Filtered image displayed
im2 = uiimage(g);
im2.Layout.Row = 3;
im2.Layout.Column = 2;
% Here, filterImage updates im2 whenever the value of filterType changes
filterType.ValueChangedFcn = @(src,event)filterImage(src,event,im1,im2,filterType,kernelDim);
% I want to update im2 when either the value of filterType changes OR when
% kernelDim changes
end
function filterImage(src,event,im1,im2,filterType,kernelDim)
kDim = kernelDim.Value;
I = imread(im1.ImageSource);
I_name = erase(im1.ImageSource,".png");
incr = floor(kDim/2);
im1_padded = double(padarray(I,[incr incr],0,’both’));
[r,c] = size(I);
switch filterType.Value
case "Arithmetic Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = (1/(kDim*kDim))*sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_amf"+"_"+ string(kDim) + ".png";
case "Geometric Mean Filter"
kernel = double(ones(kDim));
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = prod(prod(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1))).^(1/(kDim*kDim));
end
end
ext = "_gmf"+"_"+ string(kDim) + ".png";
case "Weighted Average Filter"
if kDim == 3
kernel = (1/16)*[1 2 1;
2 4 2;
1 2 1];
else
kernel = (1/52)*[1 1 2 1 1;
1 2 4 2 1;
2 4 8 4 2;
1 2 4 2 1;
1 1 2 1 1];
end
for i=1:r
for j=1:c
I_filtered(i+incr,j+incr) = sum(sum(kernel.*im1_padded(i:i+kDim-1,j:j+kDim-1)));
end
end
ext = "_waf"+"_"+ string(kDim) + ".png";
end
I_filtered = uint8(I_filtered);
filteredImagePath = strcat(I_name,ext);
imwrite(I_filtered,filteredImagePath);
im2.ImageSource = filteredImagePath;
end
As of now I am getting the filtered image output. Initially there’s no image in im2. But it appears only after I change the kernelDim followed by filterType. One obvious way is to explicitly write the code for initial values, but I want the function filterImage to somehow do it.
Please suggest techniques to do the same in an efficient manner. image-processing, uifigure MATLAB Answers — New Questions
2024-09 Cumulative Update for Windows 10 Version 22H2 for x64-based Systems (KB5043064)
I can’t install this, it quits at 7%, any info on what to do. Thanks. I cant get rid of it.
I can’t install this, it quits at 7%, any info on what to do. Thanks. I cant get rid of it. Read More
Automatic Task Assignment Based on Schedule
I kindly request assistance with creating a formula.
I have a an employee table with employee names and start times (A1:B5). I have a second table with the day’s tasks start times and their end times (D1:E17), all being 30 minutes to complete. I have a running count (G1:G17) of how many times an employee completed a task as the employee can only complete 4 total tasks and taken out of rotation and cannot be assigned anymore.
I need a result like in H1:H17 that follows the schedule and assigns a free employee (column A) based on their start times (column B), the 30 minutes to complete the task (column D and E), and on their running count of no more than 4 (column G)
I kindly request assistance with creating a formula. I have a an employee table with employee names and start times (A1:B5). I have a second table with the day’s tasks start times and their end times (D1:E17), all being 30 minutes to complete. I have a running count (G1:G17) of how many times an employee completed a task as the employee can only complete 4 total tasks and taken out of rotation and cannot be assigned anymore. I need a result like in H1:H17 that follows the schedule and assigns a free employee (column A) based on their start times (column B), the 30 minutes to complete the task (column D and E), and on their running count of no more than 4 (column G) Read More
Time zone/scheduled times changing for some reminder emails
Hi everyone,
My work team are using the Bookings app to manage training session bookings and registrations. Everything is set up in line with the MS Bookings guides. We have reminder emails set up to auto send 1 day before the session starts.
We have recently been notified that some of our reminder emails are advising of the incorrect time and stating UTC Coordinated Universal Time.
Our region and time zone settings are correct (UTC+10 Brisbane), and we have ticked Always show time slots in business time zone, however this shouldn’t be an issue as all of our current attendees are located within the same time zone.
The initial booking information and confirmation email states the correct time of the session, and majority of the reminder emails are correct, it’s just some of them that change the time. It’s not always the same session type either, or for everyone who has registered, it’s very sporadic. E.g. Two people registered for the same session, one reminder emails state the correct time, the other receives one that says the session is 12:30am-01:00am when the correct time is 10:30am-11:00am on the same day.
We have searched thoroughly through the Bookings system and are unable to find a resolution.
We have also checked with one of our attendees who received an incorrect reminder to check their time settings in Teams and 365 and all are correct.
Any information or how to resolve this would be most welcome.
Thanks,
Cara
Hi everyone,My work team are using the Bookings app to manage training session bookings and registrations. Everything is set up in line with the MS Bookings guides. We have reminder emails set up to auto send 1 day before the session starts.We have recently been notified that some of our reminder emails are advising of the incorrect time and stating UTC Coordinated Universal Time.Our region and time zone settings are correct (UTC+10 Brisbane), and we have ticked Always show time slots in business time zone, however this shouldn’t be an issue as all of our current attendees are located within the same time zone.The initial booking information and confirmation email states the correct time of the session, and majority of the reminder emails are correct, it’s just some of them that change the time. It’s not always the same session type either, or for everyone who has registered, it’s very sporadic. E.g. Two people registered for the same session, one reminder emails state the correct time, the other receives one that says the session is 12:30am-01:00am when the correct time is 10:30am-11:00am on the same day.We have searched thoroughly through the Bookings system and are unable to find a resolution.We have also checked with one of our attendees who received an incorrect reminder to check their time settings in Teams and 365 and all are correct.Any information or how to resolve this would be most welcome. Thanks,Cara Read More
Graph API for accessing Mail Info
Hi PowerShell Community,
I need to access the info below
Total Numbers of email by each mailboxTotal Attachments per email by each mailboxType of attachments (PDF, Word, Excel, PPT, Image, Etc..)Total email, each mailboxLast access
For which i need to know which Graph API I need for the info mentioned above. Can someone please help us in finding this.
Hi PowerShell Community, I need to access the info below Total Numbers of email by each mailboxTotal Attachments per email by each mailboxType of attachments (PDF, Word, Excel, PPT, Image, Etc..)Total email, each mailboxLast accessFor which i need to know which Graph API I need for the info mentioned above. Can someone please help us in finding this. Read More
Embedded Coder for STM32F446RE about CAN communication
Hello Matlab Support Team,
I am currently using Simulink to implement CAN communication with an STM32-NucleoF446RE board, but I am facing some difficulties and would like to request support.
At the moment, I have connected an MCU-230 transceiver to a 500 kbit/s CAN bus, with the RX-TX lines of the transceiver connected to the STM32 board. I have also ensured that the baud rate is set correctly, but the problem of not receiving any values through CAN Receive persists.
Attached are some images showing parts of the code I have written and screenshots from STM32 IDE.
If there is any information you need, feel free to ask, and I will provide it. Also, if I have made any mistakes, please don’t hesitate to contact me.Hello Matlab Support Team,
I am currently using Simulink to implement CAN communication with an STM32-NucleoF446RE board, but I am facing some difficulties and would like to request support.
At the moment, I have connected an MCU-230 transceiver to a 500 kbit/s CAN bus, with the RX-TX lines of the transceiver connected to the STM32 board. I have also ensured that the baud rate is set correctly, but the problem of not receiving any values through CAN Receive persists.
Attached are some images showing parts of the code I have written and screenshots from STM32 IDE.
If there is any information you need, feel free to ask, and I will provide it. Also, if I have made any mistakes, please don’t hesitate to contact me. Hello Matlab Support Team,
I am currently using Simulink to implement CAN communication with an STM32-NucleoF446RE board, but I am facing some difficulties and would like to request support.
At the moment, I have connected an MCU-230 transceiver to a 500 kbit/s CAN bus, with the RX-TX lines of the transceiver connected to the STM32 board. I have also ensured that the baud rate is set correctly, but the problem of not receiving any values through CAN Receive persists.
Attached are some images showing parts of the code I have written and screenshots from STM32 IDE.
If there is any information you need, feel free to ask, and I will provide it. Also, if I have made any mistakes, please don’t hesitate to contact me. can, stm32f4xx, embedded coder, simulink MATLAB Answers — New Questions
can some one tell me how to do the aspen plus excel matlab link ??
I need to use a user model subroutine in Aspen plus linked to Matlab and excel can some one tell me the procedure step by step please….I need to use a user model subroutine in Aspen plus linked to Matlab and excel can some one tell me the procedure step by step please…. I need to use a user model subroutine in Aspen plus linked to Matlab and excel can some one tell me the procedure step by step please…. aspen plus- excel- matlab link MATLAB Answers — New Questions
Simulink Desktop Real-Time issue under Matlab R2024a
I am trying to run SLDRT models with Matlab/Simulink R2024a.
The models were functionnal under Matlab R2023a
In Matlab/Simulink R2024a, the analog inputs of my NI-PCI 6321 card update at a very slow pace and the analog outputs never update.
To ensure that this is not a Windows 11 issue, I reverted back to Matlab/Simulink R2023a and the old models still worked fine.
Is there a real issue or am I missing something?I am trying to run SLDRT models with Matlab/Simulink R2024a.
The models were functionnal under Matlab R2023a
In Matlab/Simulink R2024a, the analog inputs of my NI-PCI 6321 card update at a very slow pace and the analog outputs never update.
To ensure that this is not a Windows 11 issue, I reverted back to Matlab/Simulink R2023a and the old models still worked fine.
Is there a real issue or am I missing something? I am trying to run SLDRT models with Matlab/Simulink R2024a.
The models were functionnal under Matlab R2023a
In Matlab/Simulink R2024a, the analog inputs of my NI-PCI 6321 card update at a very slow pace and the analog outputs never update.
To ensure that this is not a Windows 11 issue, I reverted back to Matlab/Simulink R2023a and the old models still worked fine.
Is there a real issue or am I missing something? simulink desktop real-time, matlab r2024a MATLAB Answers — New Questions
Simulating Levy walk in MATLAB. (Not Levy Flight)
I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off;I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off; I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off; randomwalk, biology, levywalk, physics MATLAB Answers — New Questions
Archive
Hi Outlook Team,
Good Day , Customer wants to clarify the following questions regarding the Archive Process.
According to the MRM policy applied to user mailboxes, emails do not immediately appear in the Archive folder. They become visible to end users after 7 days.
Where do these emails reside during those seven days, and is this behavior expected?
The customer wants to comprehend the behavior of email disappearance.
If email disappearance is intentional by design, the customer seeks a change in this process.
Hi Outlook Team,
Good Day , Customer wants to clarify the following questions regarding the Archive Process.
According to the MRM policy applied to user mailboxes, emails do not immediately appear in the Archive folder. They become visible to end users after 7 days.
Where do these emails reside during those seven days, and is this behavior expected?
The customer wants to comprehend the behavior of email disappearance.
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resolution of MDOF using ode45
i have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
endi have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
end i have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
end ode45, mdof MATLAB Answers — New Questions
Getting the Error “Not enough input arguments” but I did the exact same method earlier in the code without issue..
clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag);clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag); clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag); error MATLAB Answers — New Questions
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I’ve recently switched to a Mac (Mac 15 M3), and I’ve discovered that Visual Studio is no longer supported for Mac users. To work around this, I installed a Windows virtual machine on Parallels and attempted to install the latest version of Visual Studio 2022 Community Edition. However, I’m encountering an issue: the Azure Development workload is not appearing in the list of available workloads during installation. This problem doesn’t occur on a standard Windows machine but does persist on the virtual machine. I’ve tried several solutions without success. Could you assist me with this?
I’ve recently switched to a Mac (Mac 15 M3), and I’ve discovered that Visual Studio is no longer supported for Mac users. To work around this, I installed a Windows virtual machine on Parallels and attempted to install the latest version of Visual Studio 2022 Community Edition. However, I’m encountering an issue: the Azure Development workload is not appearing in the list of available workloads during installation. This problem doesn’t occur on a standard Windows machine but does persist on the virtual machine. I’ve tried several solutions without success. Could you assist me with this? Read More
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Thanks for your help.
Best Regards,
Tiffany Liu
Hi There, I am receiving auto-forwarded emails from a client’s account, but some emails are not coming through. The client’s IT team has confirmed all emails show as delivered, yet I am only receiving some of them. I have already checked my Junk folder and found nothing there. How should I further investigate this issue? Thanks for your help. Best Regards, Tiffany Liu Read More
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Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated!Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated! Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated! matlab, fortran MATLAB Answers — New Questions
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Would appreciate any feedback on this.
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Hello! I’m trying to rearrange and organize the files of our team by moving them from one channel to the other to optimize the storage that we have. I’ve been encountering an issue with this when the progress of moving the files gets stuck at a certain percentage for a long time. When I check the destination folder, the files are already there and at the same time, the origin folder is already empty but even with these the progress is still at 57% for some of the folders. Not sure if it’s already safe to cancel, close teams or shut down my computer without losing any of our files. Would appreciate any feedback on this. Thank you! Read More
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"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
Thanks!Hello!
I’m trying to access the Simscape Onramp course in browser mode and the Simulink window refuses to open even after waiting for a long time.
The one time it did open, it showed an error when clicking on Submit for the very first assignment.
"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
Thanks! Hello!
I’m trying to access the Simscape Onramp course in browser mode and the Simulink window refuses to open even after waiting for a long time.
The one time it did open, it showed an error when clicking on Submit for the very first assignment.
"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
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