Hi,
How can i print in Text area box (with app designer), hyperlinks for files that located in local PC?

when im using the sprintf function rom conslue window i can see the print with hypelink, for example:
sprintf(‘<a href="matlab: winopen(”%s”)">%s</a>nn’, filepath, CurrentFileName),

but when im trying to print the same inside the text area its printing me the whole string:

How can i print hyperlink inside the text area?Hi,
How can i print in Text area box (with app designer), hyperlinks for files that located in local PC?

when im using the sprintf function rom conslue window i can see the print with hypelink, for example:
sprintf(‘<a href="matlab: winopen(”%s”)">%s</a>nn’, filepath, CurrentFileName),

but when im trying to print the same inside the text area its printing me the whole string:

How can i print hyperlink inside the text area? Hi,
How can i print in Text area box (with app designer), hyperlinks for files that located in local PC?

when im using the sprintf function rom conslue window i can see the print with hypelink, for example:
sprintf(‘<a href="matlab: winopen(”%s”)">%s</a>nn’, filepath, CurrentFileName),

but when im trying to print the same inside the text area its printing me the whole string:

How can i print hyperlink inside the text area? appdesigner, hyperlink MATLAB Answers — New Questions

​

I have a 291*291 velocity data from LES . I want to azimuthally average the data so that for any angle from the origin at a particular radial distance i get the same value of velocity.
please suggest the way to do it.

Following figure shows the pictorial reperesentation of velocity data in yz plane

here is the attached file for the dataI have a 291*291 velocity data from LES . I want to azimuthally average the data so that for any angle from the origin at a particular radial distance i get the same value of velocity.
please suggest the way to do it.

Following figure shows the pictorial reperesentation of velocity data in yz plane

here is the attached file for the data I have a 291*291 velocity data from LES . I want to azimuthally average the data so that for any angle from the origin at a particular radial distance i get the same value of velocity.
please suggest the way to do it.

Following figure shows the pictorial reperesentation of velocity data in yz plane

here is the attached file for the data azimuthally-average data MATLAB Answers — New Questions

​

I am writing a simple program with if loop inside a for loop but the program gets stopped in middle with error:
Index exceeds the number of array elements. Index must not exceed 1.

Error in newtrial (line 19)
Y(i) = Y(i) + 1;

and the plot is not generated as well even for values generated.

the code is:

clc
clear
x1 = 5
y1 = 3
x0 = 0
y0 = 0
dx = x1-x0
dy = y1-y0
e = dy-dx
X = x0
Y = y0
for i = 1:1:5;

X(i+1) = X(i) + 1

if e(i) >= 0
Y(i+1) = Y(i) + 1;
e(i+1) = e(i) – dx;
else
e(i+1) = e(i) + dy;
end
end
Y
plot(X,Y,’bo’)
axis([0 6 0 6])

I am new to this, so any help or correction in code is appreciated, thanks in advance.I am writing a simple program with if loop inside a for loop but the program gets stopped in middle with error:
Index exceeds the number of array elements. Index must not exceed 1.

Error in newtrial (line 19)
Y(i) = Y(i) + 1;

and the plot is not generated as well even for values generated.

the code is:

clc
clear
x1 = 5
y1 = 3
x0 = 0
y0 = 0
dx = x1-x0
dy = y1-y0
e = dy-dx
X = x0
Y = y0
for i = 1:1:5;

X(i+1) = X(i) + 1

if e(i) >= 0
Y(i+1) = Y(i) + 1;
e(i+1) = e(i) – dx;
else
e(i+1) = e(i) + dy;
end
end
Y
plot(X,Y,’bo’)
axis([0 6 0 6])

I am new to this, so any help or correction in code is appreciated, thanks in advance. I am writing a simple program with if loop inside a for loop but the program gets stopped in middle with error:
Index exceeds the number of array elements. Index must not exceed 1.

Error in newtrial (line 19)
Y(i) = Y(i) + 1;

and the plot is not generated as well even for values generated.

the code is:

clc
clear
x1 = 5
y1 = 3
x0 = 0
y0 = 0
dx = x1-x0
dy = y1-y0
e = dy-dx
X = x0
Y = y0
for i = 1:1:5;

X(i+1) = X(i) + 1

if e(i) >= 0
Y(i+1) = Y(i) + 1;
e(i+1) = e(i) – dx;
else
e(i+1) = e(i) + dy;
end
end
Y
plot(X,Y,’bo’)
axis([0 6 0 6])

I am new to this, so any help or correction in code is appreciated, thanks in advance. index error, loops MATLAB Answers — New Questions

​

"Simulink strings support 256 characters of the ISO/IEC 8859-1 character set" according to Simulink Strings in the Help Center.
I’ve created a "string constant" block called "String ãºç" in a simulink model where I’ve inserted the value "exampleàñçº".
The block’s name is exported correctly in UTF-8 ("String ãºç"), but what I get in the exported file for the value is "example340361347272" (octal values for extended characters in ISO/IEC 8859-1).
I was wondering if there was a way to export the string value in UTF-8."Simulink strings support 256 characters of the ISO/IEC 8859-1 character set" according to Simulink Strings in the Help Center.
I’ve created a "string constant" block called "String ãºç" in a simulink model where I’ve inserted the value "exampleàñçº".
The block’s name is exported correctly in UTF-8 ("String ãºç"), but what I get in the exported file for the value is "example340361347272" (octal values for extended characters in ISO/IEC 8859-1).
I was wondering if there was a way to export the string value in UTF-8. "Simulink strings support 256 characters of the ISO/IEC 8859-1 character set" according to Simulink Strings in the Help Center.
I’ve created a "string constant" block called "String ãºç" in a simulink model where I’ve inserted the value "exampleàñçº".
The block’s name is exported correctly in UTF-8 ("String ãºç"), but what I get in the exported file for the value is "example340361347272" (octal values for extended characters in ISO/IEC 8859-1).
I was wondering if there was a way to export the string value in UTF-8. block parameters, simulink, simulink coder, matlab coder, embedded coder, string, datatype, string constant, model configuration, encoding, latin-1, iso/iec 8859-1, utf-8, unicode MATLAB Answers — New Questions

​

Hi
What’s the CharacterEncoding option for Windows?
Example only lists ‘US-ASCII’, ‘UTF-8’, ‘latin1’, ‘Shift_JIS’, and’ISO-8859-1′.Hi
What’s the CharacterEncoding option for Windows?
Example only lists ‘US-ASCII’, ‘UTF-8’, ‘latin1’, ‘Shift_JIS’, and’ISO-8859-1′. Hi
What’s the CharacterEncoding option for Windows?
Example only lists ‘US-ASCII’, ‘UTF-8’, ‘latin1’, ‘Shift_JIS’, and’ISO-8859-1′. matlab MATLAB Answers — New Questions

​

clear all; clc;
% Parameters (units at m, C, W..)
L = 0.3; % Length of the cross section of square
H = 0.15; % Height of the cross section of square
T_flueinterior = 350; % Interior flue temperature
h_flueinterior = 100; % Interior flue convection coefficient
T_airexterior = 25; % Exterior air temperature
h_airexterior = 5; % Exterior air convection coefficient
k = 0.85; % Thermal conductivity of refractory brick
alpha = 5.5e-7; % Thermal diffusivity of refractory brick
Ti = 25; % Initial temperature of the wall
dx = 0.05; % Grid spacing at x direction
dy = 0.05; % Grid spacing at y direction
dt = 3600; % Time step in one hour in seconds
Nt = [1, 3, 10, 30]; % Time steps to output
% Converting Nt to seconds
Nt = Nt * 3600;
% Setting up the number of grid points in x and y direction
Nx = round(L/dx) + 1;
Ny = round(H/dy) + 1;
% Initializing temperature field
T = Ti * ones(Nx,Ny);
% Defining a coefficient to simplify the discretized FD equation
a = alpha * dt / dx^2;
% Time loop
for n = 1:max(Nt)/dt
T_new = T;
for j = 2:Ny-1
for i = 2:Nx-1
T_new(i,j) = T(i,j) + a * (T(i,j+1) + T(i,j-1) + T(i+1,j) + T(i-1,j) – 4 * T(i,j));
end
end
% Applying boundary conditions
% Left side flue
T_new(:,1) = T_flueinterior + (T(:,2) – T_flueinterior) / (1 + dx * h_flueinterior / k);
% Right side air
T_new(:,end) = T_airexterior + (T(:,end-1) – T_airexterior) / (1 + dx * h_airexterior / k);
% Top and bottom boundaries (adiabatic and insulated)
T_new(1,:) = T_new(2,:);
T_new(end, 🙂 = T_new(end-1, :);
% Re-update temperature field

T = T_new;
% Save results at the specified times
if any(n*dt == Nt)
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
colorbar;
title([‘Temperature Distribution at t = ‘, num2str(n*dt/3600), ‘hours’]);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);
end
end
% The final temperature distribution
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
title(‘Final Temperature Distribution’);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);

I am having the error in the title and am not sure how to fix it? I could use some helpclear all; clc;
% Parameters (units at m, C, W..)
L = 0.3; % Length of the cross section of square
H = 0.15; % Height of the cross section of square
T_flueinterior = 350; % Interior flue temperature
h_flueinterior = 100; % Interior flue convection coefficient
T_airexterior = 25; % Exterior air temperature
h_airexterior = 5; % Exterior air convection coefficient
k = 0.85; % Thermal conductivity of refractory brick
alpha = 5.5e-7; % Thermal diffusivity of refractory brick
Ti = 25; % Initial temperature of the wall
dx = 0.05; % Grid spacing at x direction
dy = 0.05; % Grid spacing at y direction
dt = 3600; % Time step in one hour in seconds
Nt = [1, 3, 10, 30]; % Time steps to output
% Converting Nt to seconds
Nt = Nt * 3600;
% Setting up the number of grid points in x and y direction
Nx = round(L/dx) + 1;
Ny = round(H/dy) + 1;
% Initializing temperature field
T = Ti * ones(Nx,Ny);
% Defining a coefficient to simplify the discretized FD equation
a = alpha * dt / dx^2;
% Time loop
for n = 1:max(Nt)/dt
T_new = T;
for j = 2:Ny-1
for i = 2:Nx-1
T_new(i,j) = T(i,j) + a * (T(i,j+1) + T(i,j-1) + T(i+1,j) + T(i-1,j) – 4 * T(i,j));
end
end
% Applying boundary conditions
% Left side flue
T_new(:,1) = T_flueinterior + (T(:,2) – T_flueinterior) / (1 + dx * h_flueinterior / k);
% Right side air
T_new(:,end) = T_airexterior + (T(:,end-1) – T_airexterior) / (1 + dx * h_airexterior / k);
% Top and bottom boundaries (adiabatic and insulated)
T_new(1,:) = T_new(2,:);
T_new(end, 🙂 = T_new(end-1, :);
% Re-update temperature field

T = T_new;
% Save results at the specified times
if any(n*dt == Nt)
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
colorbar;
title([‘Temperature Distribution at t = ‘, num2str(n*dt/3600), ‘hours’]);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);
end
end
% The final temperature distribution
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
title(‘Final Temperature Distribution’);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);

I am having the error in the title and am not sure how to fix it? I could use some help clear all; clc;
% Parameters (units at m, C, W..)
L = 0.3; % Length of the cross section of square
H = 0.15; % Height of the cross section of square
T_flueinterior = 350; % Interior flue temperature
h_flueinterior = 100; % Interior flue convection coefficient
T_airexterior = 25; % Exterior air temperature
h_airexterior = 5; % Exterior air convection coefficient
k = 0.85; % Thermal conductivity of refractory brick
alpha = 5.5e-7; % Thermal diffusivity of refractory brick
Ti = 25; % Initial temperature of the wall
dx = 0.05; % Grid spacing at x direction
dy = 0.05; % Grid spacing at y direction
dt = 3600; % Time step in one hour in seconds
Nt = [1, 3, 10, 30]; % Time steps to output
% Converting Nt to seconds
Nt = Nt * 3600;
% Setting up the number of grid points in x and y direction
Nx = round(L/dx) + 1;
Ny = round(H/dy) + 1;
% Initializing temperature field
T = Ti * ones(Nx,Ny);
% Defining a coefficient to simplify the discretized FD equation
a = alpha * dt / dx^2;
% Time loop
for n = 1:max(Nt)/dt
T_new = T;
for j = 2:Ny-1
for i = 2:Nx-1
T_new(i,j) = T(i,j) + a * (T(i,j+1) + T(i,j-1) + T(i+1,j) + T(i-1,j) – 4 * T(i,j));
end
end
% Applying boundary conditions
% Left side flue
T_new(:,1) = T_flueinterior + (T(:,2) – T_flueinterior) / (1 + dx * h_flueinterior / k);
% Right side air
T_new(:,end) = T_airexterior + (T(:,end-1) – T_airexterior) / (1 + dx * h_airexterior / k);
% Top and bottom boundaries (adiabatic and insulated)
T_new(1,:) = T_new(2,:);
T_new(end, 🙂 = T_new(end-1, :);
% Re-update temperature field

T = T_new;
% Save results at the specified times
if any(n*dt == Nt)
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
colorbar;
title([‘Temperature Distribution at t = ‘, num2str(n*dt/3600), ‘hours’]);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);
end
end
% The final temperature distribution
figure;
contourf(linspace(0,L,Nx), linspace(0,H,Ny), T, 20, ‘LineColor’, ‘none’);
title(‘Final Temperature Distribution’);
xlabel(‘x (in m)’);
ylabel(‘y (in m)’);

I am having the error in the title and am not sure how to fix it? I could use some help optimization, error, matlab MATLAB Answers — New Questions

​

Hello to all teachers
I have a solar cell simulation circuit with the gray wolf algorithm. I wanted to replace the resistance of the boost circuit connected to the solar cell with a variable resistor.
Due to various radiations of the resistance of the output circuit, the output power does not track well.
I want a variable resistance so that by increasing and decreasing the radiation to the cells, we can observe the maximum power on the scope.
Thank youHello to all teachers
I have a solar cell simulation circuit with the gray wolf algorithm. I wanted to replace the resistance of the boost circuit connected to the solar cell with a variable resistor.
Due to various radiations of the resistance of the output circuit, the output power does not track well.
I want a variable resistance so that by increasing and decreasing the radiation to the cells, we can observe the maximum power on the scope.
Thank you Hello to all teachers
I have a solar cell simulation circuit with the gray wolf algorithm. I wanted to replace the resistance of the boost circuit connected to the solar cell with a variable resistor.
Due to various radiations of the resistance of the output circuit, the output power does not track well.
I want a variable resistance so that by increasing and decreasing the radiation to the cells, we can observe the maximum power on the scope.
Thank you mppt, solar cell, simulink, variable resistor, rheosta MATLAB Answers — New Questions

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