Category: News
Android Device Enrollment Restriction- All Users Option Missing
We currently have a 3rd party MDM and are in the process of design and setup of the Intune solution. I wanted to create a default deny-all enrollment policy for personal devices until we get a solution developed so that personal smart devices don’t end up in Intune.
I set up the restriction policies for Windows, IOS and MacOS and assigned them to “All Users” just fine. When trying to do so for Android devices, the “All Users” option is missing. I have checked the all devices section and there are no devices enrolled.
Any thoughts? Thanks.
We currently have a 3rd party MDM and are in the process of design and setup of the Intune solution. I wanted to create a default deny-all enrollment policy for personal devices until we get a solution developed so that personal smart devices don’t end up in Intune. I set up the restriction policies for Windows, IOS and MacOS and assigned them to “All Users” just fine. When trying to do so for Android devices, the “All Users” option is missing. I have checked the all devices section and there are no devices enrolled. Any thoughts? Thanks. Read More
B2B Invite error
Hi,
Have been trying to invite some external users using the https://learn.microsoft.com/en-us/entra/external-id/bulk-invite-powershell.
When trying to run this line
$messageInfo = New-Object Microsoft.Open.MSGraph.Model.InvitedUserMessageInfo
I get this error
New-Object: Cannot find type [Microsoft.Open.MSGraph.Model.InvitedUserMessageInfo]: verify that the assembly containing this type is loaded.
I have tried uninstalling and reinstalling the Microsoft.Graph module.
Any ideas what I am doing wrong?
Thanks
Hi, Have been trying to invite some external users using the https://learn.microsoft.com/en-us/entra/external-id/bulk-invite-powershell.When trying to run this line $messageInfo = New-Object Microsoft.Open.MSGraph.Model.InvitedUserMessageInfoI get this errorNew-Object: Cannot find type [Microsoft.Open.MSGraph.Model.InvitedUserMessageInfo]: verify that the assembly containing this type is loaded. I have tried uninstalling and reinstalling the Microsoft.Graph module.Any ideas what I am doing wrong? Thanks Read More
Navigation Pane drag and drop to move
I am at a loss to understand why Outlook (new) doesn’t provided for a drag and drop feature so as to move folders and subfolders for quick organization. Being a convert to Windows from Apple, I am surprised to say the least. Apple mail has had this feature since inception. If you have a lot of Sub-folders then it gets really confusing to move them manually. Please correct me if this feature is offered or if not, is Outlook doing anything about it?
I am at a loss to understand why Outlook (new) doesn’t provided for a drag and drop feature so as to move folders and subfolders for quick organization. Being a convert to Windows from Apple, I am surprised to say the least. Apple mail has had this feature since inception. If you have a lot of Sub-folders then it gets really confusing to move them manually. Please correct me if this feature is offered or if not, is Outlook doing anything about it? Read More
ADSR Audio Envelope: How to get it?
How can I get the ADSR sample points of a audio file…Like:
"Fake" example:
[Amp, SR] = audioread(audio.file);
[a d s r] = get_ADSR(Amp);
% Results: The sample position of the Amp vector:
a = 85 % End of Attack -> Attack start = Amp(0)
d = 300 % End of Decay
s = 2456 % End of Sustain
r = 50000 % End of ReleaseHow can I get the ADSR sample points of a audio file…Like:
"Fake" example:
[Amp, SR] = audioread(audio.file);
[a d s r] = get_ADSR(Amp);
% Results: The sample position of the Amp vector:
a = 85 % End of Attack -> Attack start = Amp(0)
d = 300 % End of Decay
s = 2456 % End of Sustain
r = 50000 % End of Release How can I get the ADSR sample points of a audio file…Like:
"Fake" example:
[Amp, SR] = audioread(audio.file);
[a d s r] = get_ADSR(Amp);
% Results: The sample position of the Amp vector:
a = 85 % End of Attack -> Attack start = Amp(0)
d = 300 % End of Decay
s = 2456 % End of Sustain
r = 50000 % End of Release envelope, adsr, audio, wave MATLAB Answers — New Questions
App UIFigure Visibility Bug
I have Multi-Windows Application written with GUIDE. Currently I Tried to Migrate to App Designer.
My Problem: I Design An App, That Its Visibility Turned Off In App Startup Callback.
In Some Place, I Change The Position of That Windows (In Other Program Module), But Before User Decide to Click A Menu to show That App.
Its Very Odd That, The Windows Appears As Soon As Position Changed. I Tried to Turn It Visiblity Back to Off Again After Position Change Line. But It Didnt Work. Also Functions Like drawnow not useful (At First I Thought It is An Incomplete rendering problem).
This Is Secondary Windows That Should Be Invisible (app2):
function startupFcn(app)
app.UIFigure.Visible= "off"
end
In Master App, I Define ap2 Public Variable:
function startupFcn(app)
app.ap2= app2
end
And This Is Position Change In Some Callback That Tend To Show app2:
function ChangePositionButtonPushed(app, event)
app.ap2.UIFigure.Position= [100, 100, 1000, 700];
app.ap2.UIFigure.Visible
end
As you see, The 2nd Line Echo "off" Value for ap2.UIFigure, While It is shown.I have Multi-Windows Application written with GUIDE. Currently I Tried to Migrate to App Designer.
My Problem: I Design An App, That Its Visibility Turned Off In App Startup Callback.
In Some Place, I Change The Position of That Windows (In Other Program Module), But Before User Decide to Click A Menu to show That App.
Its Very Odd That, The Windows Appears As Soon As Position Changed. I Tried to Turn It Visiblity Back to Off Again After Position Change Line. But It Didnt Work. Also Functions Like drawnow not useful (At First I Thought It is An Incomplete rendering problem).
This Is Secondary Windows That Should Be Invisible (app2):
function startupFcn(app)
app.UIFigure.Visible= "off"
end
In Master App, I Define ap2 Public Variable:
function startupFcn(app)
app.ap2= app2
end
And This Is Position Change In Some Callback That Tend To Show app2:
function ChangePositionButtonPushed(app, event)
app.ap2.UIFigure.Position= [100, 100, 1000, 700];
app.ap2.UIFigure.Visible
end
As you see, The 2nd Line Echo "off" Value for ap2.UIFigure, While It is shown. I have Multi-Windows Application written with GUIDE. Currently I Tried to Migrate to App Designer.
My Problem: I Design An App, That Its Visibility Turned Off In App Startup Callback.
In Some Place, I Change The Position of That Windows (In Other Program Module), But Before User Decide to Click A Menu to show That App.
Its Very Odd That, The Windows Appears As Soon As Position Changed. I Tried to Turn It Visiblity Back to Off Again After Position Change Line. But It Didnt Work. Also Functions Like drawnow not useful (At First I Thought It is An Incomplete rendering problem).
This Is Secondary Windows That Should Be Invisible (app2):
function startupFcn(app)
app.UIFigure.Visible= "off"
end
In Master App, I Define ap2 Public Variable:
function startupFcn(app)
app.ap2= app2
end
And This Is Position Change In Some Callback That Tend To Show app2:
function ChangePositionButtonPushed(app, event)
app.ap2.UIFigure.Position= [100, 100, 1000, 700];
app.ap2.UIFigure.Visible
end
As you see, The 2nd Line Echo "off" Value for ap2.UIFigure, While It is shown. appdesigner, uifigure, visible, bug MATLAB Answers — New Questions
Accelerometer reading of pixhawk 6X using MATLAB 2024a
I’m now trying to setup the pixhawk 6X using UAV Toolbox Support Package for PX4 Autopilots (ver. 24.12).
I successfully finished the hardware setup.
Next, I created a simple simulink file as below.
I connected the hardware and tried to see the measurement values, but I could not find the values.
(The displayed values are zero.)
Please tell me how to solve this problem.I’m now trying to setup the pixhawk 6X using UAV Toolbox Support Package for PX4 Autopilots (ver. 24.12).
I successfully finished the hardware setup.
Next, I created a simple simulink file as below.
I connected the hardware and tried to see the measurement values, but I could not find the values.
(The displayed values are zero.)
Please tell me how to solve this problem. I’m now trying to setup the pixhawk 6X using UAV Toolbox Support Package for PX4 Autopilots (ver. 24.12).
I successfully finished the hardware setup.
Next, I created a simple simulink file as below.
I connected the hardware and tried to see the measurement values, but I could not find the values.
(The displayed values are zero.)
Please tell me how to solve this problem. pixhawk 6x, matlab, simulink, sensor, uav toolbox support package MATLAB Answers — New Questions
nxn matrix as an input argument in function
function x = matrix(b, L, U)
A= L * U
x= inv(A)*b
end
I am trying to write a function that solves for an matrix, a known vector and an unknown vector. How can I make the above work? In what form am I to input b, L and U into the function arguments?
For
b = $ begin{pmatrix}a\ b \ c end{pmatrix} $.
L =$ begin{pmatrix} d & e & f\ g & h & i \ j & k & lend{pmatrix} $
U=$ begin{pmatrix} m & n & o\ p & q & r \ s & t & uend{pmatrix} $
would my input be like this: matrix([a][b][c], [d,e,f][g,h,i][j,k,l], [m,n,o][p,q,r][s,t,u]) ??function x = matrix(b, L, U)
A= L * U
x= inv(A)*b
end
I am trying to write a function that solves for an matrix, a known vector and an unknown vector. How can I make the above work? In what form am I to input b, L and U into the function arguments?
For
b = $ begin{pmatrix}a\ b \ c end{pmatrix} $.
L =$ begin{pmatrix} d & e & f\ g & h & i \ j & k & lend{pmatrix} $
U=$ begin{pmatrix} m & n & o\ p & q & r \ s & t & uend{pmatrix} $
would my input be like this: matrix([a][b][c], [d,e,f][g,h,i][j,k,l], [m,n,o][p,q,r][s,t,u]) ?? function x = matrix(b, L, U)
A= L * U
x= inv(A)*b
end
I am trying to write a function that solves for an matrix, a known vector and an unknown vector. How can I make the above work? In what form am I to input b, L and U into the function arguments?
For
b = $ begin{pmatrix}a\ b \ c end{pmatrix} $.
L =$ begin{pmatrix} d & e & f\ g & h & i \ j & k & lend{pmatrix} $
U=$ begin{pmatrix} m & n & o\ p & q & r \ s & t & uend{pmatrix} $
would my input be like this: matrix([a][b][c], [d,e,f][g,h,i][j,k,l], [m,n,o][p,q,r][s,t,u]) ?? matrix MATLAB Answers — New Questions
doubt in the backpropagation algorithm
Hi
I’m studying neural networks and i’m doing a NN with 2 hidden layers and one neuron in the output layer
While I was studying and coding my NN, I faced one doubt.
In the backward step, the math behind this is clear:
to the output layer we have:
, where ⊙ is the hadamard product.
and to hidden layers, we have:
my problem is that, when I code this formulas, I need to change the second equation when I will calculate the the gradient of the first hidden layer (the hidden layer next to the input layer) to match the dimensions of the matrix as follow below:
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%update weights and biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
% I wrote this code partially in portuguese so let me explain a litlle.
%’delta_saida’ is the gradient of the output layer
%delta_h2 is the gradient of the second hidden layer
%delta_h1 is the gradient of the first hidden layer
%w_out,w2 and w1 are the weights of output, second hidden layer and first hidden layer, respectively.
%b_out,b2 and b1 are the biases of output, second hidden layer and first hidden layer, respectively.
% the function selecionar_funcao() is just to calculate the derivative accordingly with the activation function of the layer
%As you can see, I need to change delta_h1 to match the matrix dimensions
It is right to change the formula like i’m doing in my code ? I’m asking it because in my mind, the way that we calculate the gradient of all hidden layers must be the same, but in my case it isn’t true. I will share part of my code here to help anyone to see if i’m doing some mistake
%weights and biases initialization
w1 = randn(num_entradas,n_h1)*sqrt(2/num_entradas);
w2 = randn(n_h1,n_h2) *sqrt(2/n_h1);
w_out = randn(n_h2,n_out) *sqrt(2/n_h2);
b1 = randn(1, n_h1) * sqrt(2/num_entradas);
b2 = randn(1, n_h2) * sqrt(2/n_h1);
b_out = randn(1,n_out) * sqrt(2/n_h2);
%backpropagation
for epoch =1:max_epocas
soma_valid = 0;
soma_estim = 0;
%embaralhar os dados
conj_estim = embaralhar(conj_estim);
% conj_valid = embaralhar(conj_valid);
%Validating
for j=1:size(conj_valid,1)
enter_valid = conj_valid(j,2:end);
h1_in_valid = [enter_valid,1]*[w1;b1];
h1_out_valid = selecionar_funcao(h1_in_valid,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_valid = [h1_out_valid,1]*[w2;b2];
h2_out_valid = selecionar_funcao(h2_in_valid,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_valid = [h2_out_valid,1]*[w_out;b_out];
saida_out_valid = selecionar_funcao(saida_in_valid,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_valid = conj_valid(j,1) – saida_out_valid;
soma_valid = soma_valid + (erro_valid^2);
end
erro_atual_valid = (soma_valid/(2*size(conj_valid,1)));
erros_epoca_valid = [erros_epoca_valid;erro_atual_valid];
%trainning
for i =1:size(conj_estim,1)
enter_estim = conj_estim(i,2:end);
h1_in_estim = [enter_estim,1]*[w1;b1];
h1_out_estim = selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_estim = [h1_out_estim,1]*[w2;b2];
h2_out_estim = selecionar_funcao(h2_in_estim,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_estim = [h2_out_estim,1]*[w_out;b_out];
saida_out_estim = selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_estim = conj_estim(i,1) – saida_out_estim;
soma_estim = soma_estim + (erro_estim^2);
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%atualizar pesos e biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
end
erro_atual_estim = (soma_estim/(2*size(conj_estim,1)));
erros_epoca_estim = [erros_epoca_estim;erro_atual_estim];
if erros_epoca_estim(epoch) <limiar
break
else
end
endHi
I’m studying neural networks and i’m doing a NN with 2 hidden layers and one neuron in the output layer
While I was studying and coding my NN, I faced one doubt.
In the backward step, the math behind this is clear:
to the output layer we have:
, where ⊙ is the hadamard product.
and to hidden layers, we have:
my problem is that, when I code this formulas, I need to change the second equation when I will calculate the the gradient of the first hidden layer (the hidden layer next to the input layer) to match the dimensions of the matrix as follow below:
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%update weights and biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
% I wrote this code partially in portuguese so let me explain a litlle.
%’delta_saida’ is the gradient of the output layer
%delta_h2 is the gradient of the second hidden layer
%delta_h1 is the gradient of the first hidden layer
%w_out,w2 and w1 are the weights of output, second hidden layer and first hidden layer, respectively.
%b_out,b2 and b1 are the biases of output, second hidden layer and first hidden layer, respectively.
% the function selecionar_funcao() is just to calculate the derivative accordingly with the activation function of the layer
%As you can see, I need to change delta_h1 to match the matrix dimensions
It is right to change the formula like i’m doing in my code ? I’m asking it because in my mind, the way that we calculate the gradient of all hidden layers must be the same, but in my case it isn’t true. I will share part of my code here to help anyone to see if i’m doing some mistake
%weights and biases initialization
w1 = randn(num_entradas,n_h1)*sqrt(2/num_entradas);
w2 = randn(n_h1,n_h2) *sqrt(2/n_h1);
w_out = randn(n_h2,n_out) *sqrt(2/n_h2);
b1 = randn(1, n_h1) * sqrt(2/num_entradas);
b2 = randn(1, n_h2) * sqrt(2/n_h1);
b_out = randn(1,n_out) * sqrt(2/n_h2);
%backpropagation
for epoch =1:max_epocas
soma_valid = 0;
soma_estim = 0;
%embaralhar os dados
conj_estim = embaralhar(conj_estim);
% conj_valid = embaralhar(conj_valid);
%Validating
for j=1:size(conj_valid,1)
enter_valid = conj_valid(j,2:end);
h1_in_valid = [enter_valid,1]*[w1;b1];
h1_out_valid = selecionar_funcao(h1_in_valid,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_valid = [h1_out_valid,1]*[w2;b2];
h2_out_valid = selecionar_funcao(h2_in_valid,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_valid = [h2_out_valid,1]*[w_out;b_out];
saida_out_valid = selecionar_funcao(saida_in_valid,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_valid = conj_valid(j,1) – saida_out_valid;
soma_valid = soma_valid + (erro_valid^2);
end
erro_atual_valid = (soma_valid/(2*size(conj_valid,1)));
erros_epoca_valid = [erros_epoca_valid;erro_atual_valid];
%trainning
for i =1:size(conj_estim,1)
enter_estim = conj_estim(i,2:end);
h1_in_estim = [enter_estim,1]*[w1;b1];
h1_out_estim = selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_estim = [h1_out_estim,1]*[w2;b2];
h2_out_estim = selecionar_funcao(h2_in_estim,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_estim = [h2_out_estim,1]*[w_out;b_out];
saida_out_estim = selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_estim = conj_estim(i,1) – saida_out_estim;
soma_estim = soma_estim + (erro_estim^2);
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%atualizar pesos e biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
end
erro_atual_estim = (soma_estim/(2*size(conj_estim,1)));
erros_epoca_estim = [erros_epoca_estim;erro_atual_estim];
if erros_epoca_estim(epoch) <limiar
break
else
end
end Hi
I’m studying neural networks and i’m doing a NN with 2 hidden layers and one neuron in the output layer
While I was studying and coding my NN, I faced one doubt.
In the backward step, the math behind this is clear:
to the output layer we have:
, where ⊙ is the hadamard product.
and to hidden layers, we have:
my problem is that, when I code this formulas, I need to change the second equation when I will calculate the the gradient of the first hidden layer (the hidden layer next to the input layer) to match the dimensions of the matrix as follow below:
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%update weights and biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
% I wrote this code partially in portuguese so let me explain a litlle.
%’delta_saida’ is the gradient of the output layer
%delta_h2 is the gradient of the second hidden layer
%delta_h1 is the gradient of the first hidden layer
%w_out,w2 and w1 are the weights of output, second hidden layer and first hidden layer, respectively.
%b_out,b2 and b1 are the biases of output, second hidden layer and first hidden layer, respectively.
% the function selecionar_funcao() is just to calculate the derivative accordingly with the activation function of the layer
%As you can see, I need to change delta_h1 to match the matrix dimensions
It is right to change the formula like i’m doing in my code ? I’m asking it because in my mind, the way that we calculate the gradient of all hidden layers must be the same, but in my case it isn’t true. I will share part of my code here to help anyone to see if i’m doing some mistake
%weights and biases initialization
w1 = randn(num_entradas,n_h1)*sqrt(2/num_entradas);
w2 = randn(n_h1,n_h2) *sqrt(2/n_h1);
w_out = randn(n_h2,n_out) *sqrt(2/n_h2);
b1 = randn(1, n_h1) * sqrt(2/num_entradas);
b2 = randn(1, n_h2) * sqrt(2/n_h1);
b_out = randn(1,n_out) * sqrt(2/n_h2);
%backpropagation
for epoch =1:max_epocas
soma_valid = 0;
soma_estim = 0;
%embaralhar os dados
conj_estim = embaralhar(conj_estim);
% conj_valid = embaralhar(conj_valid);
%Validating
for j=1:size(conj_valid,1)
enter_valid = conj_valid(j,2:end);
h1_in_valid = [enter_valid,1]*[w1;b1];
h1_out_valid = selecionar_funcao(h1_in_valid,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_valid = [h1_out_valid,1]*[w2;b2];
h2_out_valid = selecionar_funcao(h2_in_valid,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_valid = [h2_out_valid,1]*[w_out;b_out];
saida_out_valid = selecionar_funcao(saida_in_valid,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_valid = conj_valid(j,1) – saida_out_valid;
soma_valid = soma_valid + (erro_valid^2);
end
erro_atual_valid = (soma_valid/(2*size(conj_valid,1)));
erros_epoca_valid = [erros_epoca_valid;erro_atual_valid];
%trainning
for i =1:size(conj_estim,1)
enter_estim = conj_estim(i,2:end);
h1_in_estim = [enter_estim,1]*[w1;b1];
h1_out_estim = selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’False’);
h2_in_estim = [h1_out_estim,1]*[w2;b2];
h2_out_estim = selecionar_funcao(h2_in_estim,ativ_h2,sig_a,tanh_a,tanh_b,’False’);
saida_in_estim = [h2_out_estim,1]*[w_out;b_out];
saida_out_estim = selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’False’);
erro_estim = conj_estim(i,1) – saida_out_estim;
soma_estim = soma_estim + (erro_estim^2);
% Backpropagation
delta_saida = erro_estim.*selecionar_funcao(saida_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h2 = (w_out’*delta_saida).*selecionar_funcao(h2_in_estim,ativ_out,sig_a,tanh_a,tanh_b,’True’);
delta_h1 = (w2*delta_h2′)’.*selecionar_funcao(h1_in_estim,ativ_h1,sig_a,tanh_a,tanh_b,’True’);
%atualizar pesos e biases
w_out = w_out + learning_rate*delta_saida*h2_out_estim’;
b_out = b_out + learning_rate*delta_saida;
w2 = w2 + learning_rate*(delta_h2’*h1_out_estim)’;
b2 = b2 + learning_rate*sum(delta_h2);
w1 = w1 + learning_rate*delta_h1’*enter_estim;
b1 = b1 + learning_rate*sum(delta_h2);
end
erro_atual_estim = (soma_estim/(2*size(conj_estim,1)));
erros_epoca_estim = [erros_epoca_estim;erro_atual_estim];
if erros_epoca_estim(epoch) <limiar
break
else
end
end machine learning, backpropagation MATLAB Answers — New Questions
Copilot Pro just not working for outlook
Hi,
I got free trail for copilot pro sub, It seems I can see copilot on all the other apps (Word, PowerPoint, Excel) but can’t find it on Outlook, I am looking to purchase the full license but not able to test it.
Thanks,
Hi, I got free trail for copilot pro sub, It seems I can see copilot on all the other apps (Word, PowerPoint, Excel) but can’t find it on Outlook, I am looking to purchase the full license but not able to test it. Thanks, Read More
UDP Communication slowing Simulink Model
Gday all,
For context, I am building a simulink model that will communicate with the simulator X-plane through UDP to control an aircraft. The Simulink model inputs a UDP connection and a live video feed. Using an object detection system to identify key features, a command direction will begiven, and outputted to X-plane through UDP communication.
My issue is that the UDP communication input significantly decreases the performance of the model. I have tried every UDP commenction block avaialble in Simulink. I have tested the simulation with other blocks, and I’m confident that the UDP communication input block (either of them) are the root of the issue. I havent had this issue with other models (such as image segmentation model). Nor does the UDP output show performance issues.
Is there a way to fix the performance issues seen in the model? Is there some UDP secret I dont know about? Workarounds? Would the UDP comminication block be interfereing with any other block (deep learning, PID…)?
Any quidence or tips would be appreciatedGday all,
For context, I am building a simulink model that will communicate with the simulator X-plane through UDP to control an aircraft. The Simulink model inputs a UDP connection and a live video feed. Using an object detection system to identify key features, a command direction will begiven, and outputted to X-plane through UDP communication.
My issue is that the UDP communication input significantly decreases the performance of the model. I have tried every UDP commenction block avaialble in Simulink. I have tested the simulation with other blocks, and I’m confident that the UDP communication input block (either of them) are the root of the issue. I havent had this issue with other models (such as image segmentation model). Nor does the UDP output show performance issues.
Is there a way to fix the performance issues seen in the model? Is there some UDP secret I dont know about? Workarounds? Would the UDP comminication block be interfereing with any other block (deep learning, PID…)?
Any quidence or tips would be appreciated Gday all,
For context, I am building a simulink model that will communicate with the simulator X-plane through UDP to control an aircraft. The Simulink model inputs a UDP connection and a live video feed. Using an object detection system to identify key features, a command direction will begiven, and outputted to X-plane through UDP communication.
My issue is that the UDP communication input significantly decreases the performance of the model. I have tried every UDP commenction block avaialble in Simulink. I have tested the simulation with other blocks, and I’m confident that the UDP communication input block (either of them) are the root of the issue. I havent had this issue with other models (such as image segmentation model). Nor does the UDP output show performance issues.
Is there a way to fix the performance issues seen in the model? Is there some UDP secret I dont know about? Workarounds? Would the UDP comminication block be interfereing with any other block (deep learning, PID…)?
Any quidence or tips would be appreciated simulink, deep learning MATLAB Answers — New Questions
Having Matlab import data from SharePoint
I have a line in my code where data is imported, and I wantto add a directory that can import the data from SharePoint so that anyone who is in the sharepoint can use the same code without having to change the directory. I can’t seem to figur eout how to do this without adding a shortcut, becaus enot everyone would have the same shortcut. If anyone could help with how I can set up the import so that anyone can use the code that would be great! Thanks!I have a line in my code where data is imported, and I wantto add a directory that can import the data from SharePoint so that anyone who is in the sharepoint can use the same code without having to change the directory. I can’t seem to figur eout how to do this without adding a shortcut, becaus enot everyone would have the same shortcut. If anyone could help with how I can set up the import so that anyone can use the code that would be great! Thanks! I have a line in my code where data is imported, and I wantto add a directory that can import the data from SharePoint so that anyone who is in the sharepoint can use the same code without having to change the directory. I can’t seem to figur eout how to do this without adding a shortcut, becaus enot everyone would have the same shortcut. If anyone could help with how I can set up the import so that anyone can use the code that would be great! Thanks! data import, sharepoint, import MATLAB Answers — New Questions
How to return matrix in Matlab using codegen with no c++ memory allocation?
I do not want any dynamic memory allocation to be done in the C++ codegen. Here is the relevant Matlab code:
% Calculate cross-correlation matrix from a set of vectors (whose length
% can vary from one call to another). All 4 channels will have the length.
function [R] = xcorr_matrix(ch0,ch1,ch2,ch3,channelCount)
% channelCount is 2 or 4
% R is either 2×2 or 4×4 complex double matrix.
% ch0 … ch3 are complex single vectors.
N = int32(size(ch0,1));
% Convert ch0, …, ch3 to complex double
x_in = coder.nullcopy(complex(zeros(N,channelCount,’double’)));
switch channelCount
case 2
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
case 4
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
x_in(1:N,3) = ch2(1:N);
x_in(1:N,4) = ch3(1:N);
end
R = (x_in’ * x_in); % Compute cross-correlation matrix
Here is the C++ codegen result:
void xcorr_matrix(const creal32_T ch0_data[], const int ch0_size[1], % all the 4 ch_size will be the same value
const creal32_T ch1_data[], const int ch1_size[1],
const creal32_T ch2_data[], const int ch2_size[1],
const creal32_T ch3_data[], const int ch3_size[1],
int channelCount,
::coder::array<creal_T, 2U> &R)
{
::coder::array<creal_T, 2U> x_in;
R.set_size(channelCount, channelCount);
x_in.set_size(N, channelCount);
…
}
I think I can eliminate the x_in.set_size by not using x_in, and replace the matrix multiply with nested for-loops and using double casting; but am unsure how to define R (either 2×2 or 4×4) so as to remove the R.set_size allocations.
One idea I had was to try making R a fixed length 16 element vector, and just use 4 elements for the 2×2 R, and all 16 for the 4×4 R. Would be nicer to be able to use two indices for rows and columns.
Thanks in advance for your help.
PaulI do not want any dynamic memory allocation to be done in the C++ codegen. Here is the relevant Matlab code:
% Calculate cross-correlation matrix from a set of vectors (whose length
% can vary from one call to another). All 4 channels will have the length.
function [R] = xcorr_matrix(ch0,ch1,ch2,ch3,channelCount)
% channelCount is 2 or 4
% R is either 2×2 or 4×4 complex double matrix.
% ch0 … ch3 are complex single vectors.
N = int32(size(ch0,1));
% Convert ch0, …, ch3 to complex double
x_in = coder.nullcopy(complex(zeros(N,channelCount,’double’)));
switch channelCount
case 2
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
case 4
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
x_in(1:N,3) = ch2(1:N);
x_in(1:N,4) = ch3(1:N);
end
R = (x_in’ * x_in); % Compute cross-correlation matrix
Here is the C++ codegen result:
void xcorr_matrix(const creal32_T ch0_data[], const int ch0_size[1], % all the 4 ch_size will be the same value
const creal32_T ch1_data[], const int ch1_size[1],
const creal32_T ch2_data[], const int ch2_size[1],
const creal32_T ch3_data[], const int ch3_size[1],
int channelCount,
::coder::array<creal_T, 2U> &R)
{
::coder::array<creal_T, 2U> x_in;
R.set_size(channelCount, channelCount);
x_in.set_size(N, channelCount);
…
}
I think I can eliminate the x_in.set_size by not using x_in, and replace the matrix multiply with nested for-loops and using double casting; but am unsure how to define R (either 2×2 or 4×4) so as to remove the R.set_size allocations.
One idea I had was to try making R a fixed length 16 element vector, and just use 4 elements for the 2×2 R, and all 16 for the 4×4 R. Would be nicer to be able to use two indices for rows and columns.
Thanks in advance for your help.
Paul I do not want any dynamic memory allocation to be done in the C++ codegen. Here is the relevant Matlab code:
% Calculate cross-correlation matrix from a set of vectors (whose length
% can vary from one call to another). All 4 channels will have the length.
function [R] = xcorr_matrix(ch0,ch1,ch2,ch3,channelCount)
% channelCount is 2 or 4
% R is either 2×2 or 4×4 complex double matrix.
% ch0 … ch3 are complex single vectors.
N = int32(size(ch0,1));
% Convert ch0, …, ch3 to complex double
x_in = coder.nullcopy(complex(zeros(N,channelCount,’double’)));
switch channelCount
case 2
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
case 4
x_in(1:N,1) = ch0(1:N);
x_in(1:N,2) = ch1(1:N);
x_in(1:N,3) = ch2(1:N);
x_in(1:N,4) = ch3(1:N);
end
R = (x_in’ * x_in); % Compute cross-correlation matrix
Here is the C++ codegen result:
void xcorr_matrix(const creal32_T ch0_data[], const int ch0_size[1], % all the 4 ch_size will be the same value
const creal32_T ch1_data[], const int ch1_size[1],
const creal32_T ch2_data[], const int ch2_size[1],
const creal32_T ch3_data[], const int ch3_size[1],
int channelCount,
::coder::array<creal_T, 2U> &R)
{
::coder::array<creal_T, 2U> x_in;
R.set_size(channelCount, channelCount);
x_in.set_size(N, channelCount);
…
}
I think I can eliminate the x_in.set_size by not using x_in, and replace the matrix multiply with nested for-loops and using double casting; but am unsure how to define R (either 2×2 or 4×4) so as to remove the R.set_size allocations.
One idea I had was to try making R a fixed length 16 element vector, and just use 4 elements for the 2×2 R, and all 16 for the 4×4 R. Would be nicer to be able to use two indices for rows and columns.
Thanks in advance for your help.
Paul matlab, codegen, embedded coder, c++, dynamic memory allocation MATLAB Answers — New Questions
Speed up nested loops with parfor
I’m trying to speed up this part of code. I have a constraint: the inputs of ReturnFn must all be scalars. If it was not for this restriction, I could easily vectorize the code. So I would like to know if there is a way to make the code below faster, while still satisfying this restriction of the inputs of ReturnFn.
Any help is really appreciated!
N_d = 50;
N_a = 300;
N_z = 10;
% ParamCell contains: K_to_L,alpha,delta,pen,gamma,crra
% I need the cell array to handle variable number of inputs in ReturnFn
Fmatrix=zeros(N_d*N_a,N_a,N_z);
parfor i4i5=1:N_z
Fmatrix_z=zeros(N_d*N_a,N_a);
for i3=1:N_a % a today
for i2=1:N_a % a’ tomorrow
for i1=1:N_d % d choice
Fmatrix_z(i1+(i2-1)*N_d,i3)=ReturnFn(d_gridvals(i1),a_gridvals(i2),a_gridvals(i3),z_gridvals(i4i5,1),z_gridvals(i4i5,2),ParamCell{:});
end
end
end
Fmatrix(:,:,i4i5)=Fmatrix_z;
end
function F = f_ReturnFn(d,aprime,a,e,age,K_to_L,alpha,delta,pen,gamma,crra)
% INPUTS (always 5 inputs, plus some extra parameter inputs)
% d: Hours worked
% aprime: Next-period’s assets
% a: Current period assets
% e: Labor efficiency shock
% age: Age of individual: young or old
% TOOLKIT NOTATION
% (d,aprime,a,z), where z = [e;age]
F = -inf;
r = alpha*K_to_L^(alpha-1)-delta;
w = (1-alpha)*K_to_L^alpha;
income = (w*e*d)*(age==1)+pen*(age==2)+r*a;
c = income+a-aprime; % Budget Constraint
if c>0
% NOTE: 0<d<1 is already built into the grid
% WARNING: this will not work if crra=1
inside = (c^gamma)*((1-d)^(1-gamma));
F = inside^(1-crra)/(1-crra);
end
endI’m trying to speed up this part of code. I have a constraint: the inputs of ReturnFn must all be scalars. If it was not for this restriction, I could easily vectorize the code. So I would like to know if there is a way to make the code below faster, while still satisfying this restriction of the inputs of ReturnFn.
Any help is really appreciated!
N_d = 50;
N_a = 300;
N_z = 10;
% ParamCell contains: K_to_L,alpha,delta,pen,gamma,crra
% I need the cell array to handle variable number of inputs in ReturnFn
Fmatrix=zeros(N_d*N_a,N_a,N_z);
parfor i4i5=1:N_z
Fmatrix_z=zeros(N_d*N_a,N_a);
for i3=1:N_a % a today
for i2=1:N_a % a’ tomorrow
for i1=1:N_d % d choice
Fmatrix_z(i1+(i2-1)*N_d,i3)=ReturnFn(d_gridvals(i1),a_gridvals(i2),a_gridvals(i3),z_gridvals(i4i5,1),z_gridvals(i4i5,2),ParamCell{:});
end
end
end
Fmatrix(:,:,i4i5)=Fmatrix_z;
end
function F = f_ReturnFn(d,aprime,a,e,age,K_to_L,alpha,delta,pen,gamma,crra)
% INPUTS (always 5 inputs, plus some extra parameter inputs)
% d: Hours worked
% aprime: Next-period’s assets
% a: Current period assets
% e: Labor efficiency shock
% age: Age of individual: young or old
% TOOLKIT NOTATION
% (d,aprime,a,z), where z = [e;age]
F = -inf;
r = alpha*K_to_L^(alpha-1)-delta;
w = (1-alpha)*K_to_L^alpha;
income = (w*e*d)*(age==1)+pen*(age==2)+r*a;
c = income+a-aprime; % Budget Constraint
if c>0
% NOTE: 0<d<1 is already built into the grid
% WARNING: this will not work if crra=1
inside = (c^gamma)*((1-d)^(1-gamma));
F = inside^(1-crra)/(1-crra);
end
end I’m trying to speed up this part of code. I have a constraint: the inputs of ReturnFn must all be scalars. If it was not for this restriction, I could easily vectorize the code. So I would like to know if there is a way to make the code below faster, while still satisfying this restriction of the inputs of ReturnFn.
Any help is really appreciated!
N_d = 50;
N_a = 300;
N_z = 10;
% ParamCell contains: K_to_L,alpha,delta,pen,gamma,crra
% I need the cell array to handle variable number of inputs in ReturnFn
Fmatrix=zeros(N_d*N_a,N_a,N_z);
parfor i4i5=1:N_z
Fmatrix_z=zeros(N_d*N_a,N_a);
for i3=1:N_a % a today
for i2=1:N_a % a’ tomorrow
for i1=1:N_d % d choice
Fmatrix_z(i1+(i2-1)*N_d,i3)=ReturnFn(d_gridvals(i1),a_gridvals(i2),a_gridvals(i3),z_gridvals(i4i5,1),z_gridvals(i4i5,2),ParamCell{:});
end
end
end
Fmatrix(:,:,i4i5)=Fmatrix_z;
end
function F = f_ReturnFn(d,aprime,a,e,age,K_to_L,alpha,delta,pen,gamma,crra)
% INPUTS (always 5 inputs, plus some extra parameter inputs)
% d: Hours worked
% aprime: Next-period’s assets
% a: Current period assets
% e: Labor efficiency shock
% age: Age of individual: young or old
% TOOLKIT NOTATION
% (d,aprime,a,z), where z = [e;age]
F = -inf;
r = alpha*K_to_L^(alpha-1)-delta;
w = (1-alpha)*K_to_L^alpha;
income = (w*e*d)*(age==1)+pen*(age==2)+r*a;
c = income+a-aprime; % Budget Constraint
if c>0
% NOTE: 0<d<1 is already built into the grid
% WARNING: this will not work if crra=1
inside = (c^gamma)*((1-d)^(1-gamma));
F = inside^(1-crra)/(1-crra);
end
end nested loops, parfor MATLAB Answers — New Questions
Insert COUNTA as a calculated field (pivot report)
Hello, I need help to insert a calculated field in a pivot report where the field counts notblank cells (see Number of yrs not blank). The point is to know for each donor how many years they have given. I am new to calculated field and I tried inserting COUNTA(b2:d2) in the formula field and it won’t accept it. Thanks!
Hello, I need help to insert a calculated field in a pivot report where the field counts notblank cells (see Number of yrs not blank). The point is to know for each donor how many years they have given. I am new to calculated field and I tried inserting COUNTA(b2:d2) in the formula field and it won’t accept it. Thanks! Read More
Prevent autoforwarding
I’ve been lookin at ways to reduce the risk of people setting up email auto-forwarding to external domains in exchange online. Appears to be a few ways and this site offers a few good options Block Email Auto-Forwarding to External Domain (admindroid.com)
However they all seem to offer a solution after the forwarder is setup.
Is there a way to prevent someone from even creating one in outlook to start with? For example I create a rule that forward everything to my gmail but before I can save it I get error saying against company policy and it blocks the creation of the rule in my outlook client in the first place.
I’ve been lookin at ways to reduce the risk of people setting up email auto-forwarding to external domains in exchange online. Appears to be a few ways and this site offers a few good options Block Email Auto-Forwarding to External Domain (admindroid.com)However they all seem to offer a solution after the forwarder is setup. Is there a way to prevent someone from even creating one in outlook to start with? For example I create a rule that forward everything to my gmail but before I can save it I get error saying against company policy and it blocks the creation of the rule in my outlook client in the first place. Read More
New Outlook for Windows: a guide for Executive Assistants and Delegates – part 3
This blog captures some mail tips to help executive assistants and delegates better navigate mailbox management in the new Outlook.
1. Mail filters and rules for executive admins
In the new Outlook, you can use the ‘has calendar invites’ email filter to easily find meeting invites.
You can also set up an ‘Email received for others’ rule for your executive’s account and automatically move it to a separate folder and categorize it as you like.
2. Drag and drop emails to create tasks
Effortlessly stay on top of things by dragging emails to My Day to turn them into tasks.
3. Pin emails for quick access
You can now pin an email to appear at the top of your inbox, saving you time from having to go back and search for it. Hover or right-click on the email and select ‘Pin’ to pin it.
4. Schedule when to send email
In today’s hybrid work world, your day might be someone else’s night, so you don’t want to send an email to someone in the middle of the night. With the new Outlook, it’s simple to send an email when you want to. Just select the dropdown arrow next to Send and choose Schedule send.
5. Snooze email
Sometimes an email is very important, but not yet. With the Snooze feature, you can schedule a time for the email to be re-delivered to your inbox, appearing at the time you want it to, so you can handle it when it’s the right time for you. Right-click any message and choose Snooze or select Snooze from the ribbon. Then choose the time you want it to be delivered.
Share feedback
We encourage you to try new Outlook and share your feedback. You can submit feedback on the new Outlook experience from Help > Feedback. Please mention – “I am an EA” Or “I am a delegate” when adding comments.
To stay updated with the latest features in new Outlook, follow the roadmap.
This guide will also be published as a support article that will be linked here once available.
Microsoft Tech Community – Latest Blogs –Read More
How to change the axes position in matlab
Hi Everybody!
I want to be able to relocate my axes/the origin (0, 0) of my plot to the middle of the graphics window. I don’t know how to manipulate the set command to do this. There must be a way. Regards
% Code explores advanced graphics properties
clf
x= 0:pi/10:pi;
angle = x.*180/pi;
y = -sind(angle);
h =plot(angle, y)
set(h, ‘color’, ‘red’)
set(h, ‘marker’,’s’)
set(h, ‘LineWidth’, 2)
h_axis =gca; % Manipulate theaxis next
set(h_axis, ‘LineWidth’, 2)Hi Everybody!
I want to be able to relocate my axes/the origin (0, 0) of my plot to the middle of the graphics window. I don’t know how to manipulate the set command to do this. There must be a way. Regards
% Code explores advanced graphics properties
clf
x= 0:pi/10:pi;
angle = x.*180/pi;
y = -sind(angle);
h =plot(angle, y)
set(h, ‘color’, ‘red’)
set(h, ‘marker’,’s’)
set(h, ‘LineWidth’, 2)
h_axis =gca; % Manipulate theaxis next
set(h_axis, ‘LineWidth’, 2) Hi Everybody!
I want to be able to relocate my axes/the origin (0, 0) of my plot to the middle of the graphics window. I don’t know how to manipulate the set command to do this. There must be a way. Regards
% Code explores advanced graphics properties
clf
x= 0:pi/10:pi;
angle = x.*180/pi;
y = -sind(angle);
h =plot(angle, y)
set(h, ‘color’, ‘red’)
set(h, ‘marker’,’s’)
set(h, ‘LineWidth’, 2)
h_axis =gca; % Manipulate theaxis next
set(h_axis, ‘LineWidth’, 2) programming MATLAB Answers — New Questions
Alerts in Data Loss Prevention
Hi Guys.
I have 3 DLP policies created and active. The rules within the policies are configured to generate an alert for each match. In the Activity Explorer, I can see the generated matches, but when I go to the Alerts menu, no information is displayed. Similarly, when I try to view these alerts from the Security portal, they do not appear. My account is a Global Admin. Is there any additional configuration that needs to be done?”
Hi Guys. I have 3 DLP policies created and active. The rules within the policies are configured to generate an alert for each match. In the Activity Explorer, I can see the generated matches, but when I go to the Alerts menu, no information is displayed. Similarly, when I try to view these alerts from the Security portal, they do not appear. My account is a Global Admin. Is there any additional configuration that needs to be done?” Read More
How can function argument declaration be introspected?
Is there a way to programmatically access the function argument validation declared in the argument block? meta.method introspection only allows to determine argument names, but I am interested in all of the validation features (dimensions, class, validation functions).
My need especially focuses on functions (not only class methods) and also on output arguments.Is there a way to programmatically access the function argument validation declared in the argument block? meta.method introspection only allows to determine argument names, but I am interested in all of the validation features (dimensions, class, validation functions).
My need especially focuses on functions (not only class methods) and also on output arguments. Is there a way to programmatically access the function argument validation declared in the argument block? meta.method introspection only allows to determine argument names, but I am interested in all of the validation features (dimensions, class, validation functions).
My need especially focuses on functions (not only class methods) and also on output arguments. introspection, argument validation, function MATLAB Answers — New Questions
Disable Windows Hello PIN for few devices
Hi Floks,
We want few devices to disable for Windows Hello PIN for customer needs,
we have tried below steps few
Method 1: Using Group policy settings.
Go to Computer Configuration -> Administrative Templates -> Windows Components -> BiometricsOn the right side, double-click on Allow the use of Biometrics and select Disabled.
Method 2: Disabling Windows Hello in Registry
As per few blogs we couldn’t find the below registry on those device
KEY_LOCAL_MACHINESOFTWAREMicrosoftPolicyManagerdefaultSettingsAllowSignInOptions
Even we have tried to apply and see via Intune to disable below settings. Any help how we can make disable via Intune. Thanks
Use Passport For Work (User)
TRUE
Use Passport For Work
TRUE
Hi Floks, We want few devices to disable for Windows Hello PIN for customer needs, we have tried below steps few Method 1: Using Group policy settings.Go to Computer Configuration -> Administrative Templates -> Windows Components -> BiometricsOn the right side, double-click on Allow the use of Biometrics and select Disabled.Method 2: Disabling Windows Hello in RegistryAs per few blogs we couldn’t find the below registry on those deviceKEY_LOCAL_MACHINESOFTWAREMicrosoftPolicyManagerdefaultSettingsAllowSignInOptionsEven we have tried to apply and see via Intune to disable below settings. Any help how we can make disable via Intune. Thanks Use Passport For Work (User)TRUEUse Passport For WorkTRUE Read More
