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plot an obtained function after several calculus
Good morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold offGood morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold off Good morning!
I want to plot the folloing function which is obtained after several calculus on Matlab,
syms s t a
Y=(sin(int(cos((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/9))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/18)))^2/100)^2*(exp(-2*s^(1/3)) + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s^(2/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/6)))^2/100)^2)^2, s, 0, 1))/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/18))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/36)))^2/100)*(exp(-2*t^(1/6)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t^(1/3)))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100))^2/100)*(exp(-2*t) + cos(int(sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(s^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/12)))^2/100)*(exp(-2*s^(1/2)) + sin(0.00008414709848078965066525023216303*cos(s^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/4)))^2/100 + cos(int(sin(0.00008414709848078965066525023216303*cos(a)^2 + 0.008414709848078965066525023216303*exp(-2*a^(1/2))) + 1, a, 0, s))^2/100)) + 1, s, 0, t^2))^2/100 + sin((sin(int(cos((0.00008414709848078965066525023216303*cos(s^(2/3))^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/3)))^2)^2, s, 0, 1))/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/6))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/12)))^2/100)*(exp(-2*t^(1/2)) + cos(int(sin(0.00008414709848078965066525023216303*cos(s)^2 + 0.008414709848078965066525023216303*exp(-2*s^(1/2))) + 1, s, 0, t))^2/100 + sin(0.00008414709848078965066525023216303*cos(t^(1/2))^2 + 0.008414709848078965066525023216303*exp(-2*t^(1/4)))^2/100))^2/100)
in this function another variable appeared (denoted by ‘ a’ ) so i add it in symbolique variable
To plot this function i used the folowing code:
t_vals=linspace(0, 1, 10);
figure(1)
hold on
y_eval = double(eval(subs(Y(i+1),t, t_vals)))
plot(t_vals, y_eval;
hold off plot, symbolique function MATLAB Answers — New Questions
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May I know which License is required to use Microsoft Purview Information Protection Client in Enterprise? Is there a Microsoft Document available to confirm that?
How would the external Users be able to access the document protected by this client?
Are there any drawbacks of using this Client?
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Windows 11 Insider Preview 10.0.22635.4005 (ni_release)
Install error – 0x80070002
Could Some one Help me with this & i am getting BSOD for IRQL NOT LESS OR EQUAL
Laptop frezzes More Frequently and i have to Restart Forcefully.
Windows 11 Insider Preview 10.0.22635.4005 (ni_release)Install error – 0x80070002 Could Some one Help me with this & i am getting BSOD for IRQL NOT LESS OR EQUAL Laptop frezzes More Frequently and i have to Restart Forcefully. Read More
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plot several equation and extract vertices
How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture?How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture? How can I plot in the same graph this 4 linear equations ?
y = 1
y = -4x + 1
x=4
2x+5y = 23
It’s possible to extract algebraically vertexes of the quadrilateral picture? plot, vertex, equation MATLAB Answers — New Questions
Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite
Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances)Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) Could you please help me to solve the following error.
I am triing to find integrl squer error for pi controller and get this error
Error using fun (line 16) Derivative of state ‘1’ in block ‘model4/PMSM /Integrator’ at time 1.09996 is not finite. The simulation will be stopped. There may be a singularity in the solution. If not, try reducing the step size (either by reducing the fixed step size or by tightening the error tolerances) simulink, power_electronics_control, power_conversion_control, electric_motor_control, control system, pi controllrt MATLAB Answers — New Questions
جلب الحبيب بالعلم 💞00.966578385.770💞قـــــ معالج روحاني ـــطـر
جلب الحبيب بالعلم :revolving_hearts:00.966578385.770:revolving_hearts:قـــــ معالج روحاني ـــطـر
جلب الحبيب بالعلم :revolving_hearts:00.966578385.770:revolving_hearts:قـــــ معالج روحاني ـــطـر Read More
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Hi,
I would like to know how can I generate a variable frequency controlled square pulse with 50% duty cycle in Simulink? I wish to vary the frequency in the range of 2KHz to 5.5KHz. It would be nice if you guys could help me.
Thanks a ton!Hi,
I would like to know how can I generate a variable frequency controlled square pulse with 50% duty cycle in Simulink? I wish to vary the frequency in the range of 2KHz to 5.5KHz. It would be nice if you guys could help me.
Thanks a ton! Hi,
I would like to know how can I generate a variable frequency controlled square pulse with 50% duty cycle in Simulink? I wish to vary the frequency in the range of 2KHz to 5.5KHz. It would be nice if you guys could help me.
Thanks a ton! simulink, pulse generator, variable frequency MATLAB Answers — New Questions
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Sharepoint Rest API filter query not returning items
Hi All,
I’m facing issue while working with Rest API in SPFX. I wanted to know if there is limitation in Rest API for filter queries like we can only apply ‘N’ numbers of filters?
I have applied a filter for lookup column and it contains more than 20 lookup conditions for e.g
https://<your-site-url>/_api/web/lists/getByTitle(‘<your-list-title>’)/items?$select=*,Author/EMail,Author/Title,SecondAssignee/Name,SecondAssignee/Title,AssignedTo/EMail,AssignedTo/Title,ProjectNameLookup/Id,ProjectNameLookup/ProjectName&$expand=Author,SecondAssignee,AssignedTo,ProjectNameLookup&$filter=Author/EMail eq ‘<author-email>’ or AssignedTo/EMail eq ‘<assignedto-email>’ or SecondAssignee/EMail eq ‘<secondassignee-email>’ or ProjectNameLookup/ProjectName eq ‘<project-name-1>’ or ProjectNameLookup/ProjectName eq ‘<project-name-2>’ or ProjectNameLookup/ProjectName eq ‘<project-name-3>’ or ProjectNameLookup/ProjectName eq ‘<project-name-4>’ or ProjectNameLookup/ProjectName eq ‘<project-name-5>’ or ProjectNameLookup/ProjectName eq ‘<project-name-6>’ or ProjectNameLookup/ProjectName eq ‘<project-name-7>’ or ProjectNameLookup/ProjectName eq ‘<project-name-8>’ or ProjectNameLookup/ProjectName eq ‘<project-name-9>’ or ProjectNameLookup/ProjectName eq ‘<project-name-10>’ or ProjectNameLookup/ProjectName eq ‘<project-name-11>’ or ProjectNameLookup/ProjectName eq ‘<project-name-12>’ or ProjectNameLookup/ProjectName eq ‘<project-name-13>’ or ProjectNameLookup/ProjectName eq ‘<project-name-14>’ or ProjectNameLookup/ProjectName eq ‘<project-name-15>’ or ProjectNameLookup/ProjectName eq ‘<project-name-16>’ or ProjectNameLookup/ProjectName eq ‘<project-name-17>’ or ProjectNameLookup/ProjectName eq ‘<project-name-18>’ or ProjectNameLookup/ProjectName eq ‘<project-name-19>’ or ProjectNameLookup/ProjectName eq ‘<project-name-20>’ or ProjectNameLookup/ProjectName eq ‘<project-name-21>’ or ProjectNameLookup/ProjectName eq ‘<project-name-22>’ or ProjectNameLookup/ProjectName eq ‘<project-name-23>’ or ProjectNameLookup/ProjectName eq ‘<project-name-24>’ or ProjectNameLookup/ProjectName eq ‘<project-name-25>’ or ProjectNameLookup/ProjectName eq ‘<project-name-26>’ or ProjectNameLookup/ProjectName eq ‘<project-name-27>’ or ProjectNameLookup/ProjectName eq ‘<project-name-28>’ or ProjectNameLookup/ProjectName eq ‘<project-name-29>’ or ProjectNameLookup/ProjectName eq ‘<project-name-30>’ or ProjectNameLookup/ProjectName eq ‘<project-name-31>’ or ProjectNameLookup/ProjectName eq ‘<project-name-32>’ or ProjectNameLookup/ProjectName eq ‘<project-name-33>’ or ProjectNameLookup/ProjectName eq ‘<project-name-34>’ or ProjectNameLookup/ProjectName eq ‘<project-name-35>’&$orderby=Created desc&$top=999
When I run above query, then its not reurning any items. but when I filter query, then it is returning the items.
I saw numbers of articles where they say the rest api has limit of 6000 char, some says 2048. So I am getting confsed here.
Hi All, I’m facing issue while working with Rest API in SPFX. I wanted to know if there is limitation in Rest API for filter queries like we can only apply ‘N’ numbers of filters? I have applied a filter for lookup column and it contains more than 20 lookup conditions for e.ghttps://<your-site-url>/_api/web/lists/getByTitle(‘<your-list-title>’)/items?$select=*,Author/EMail,Author/Title,SecondAssignee/Name,SecondAssignee/Title,AssignedTo/EMail,AssignedTo/Title,ProjectNameLookup/Id,ProjectNameLookup/ProjectName&$expand=Author,SecondAssignee,AssignedTo,ProjectNameLookup&$filter=Author/EMail eq ‘<author-email>’ or AssignedTo/EMail eq ‘<assignedto-email>’ or SecondAssignee/EMail eq ‘<secondassignee-email>’ or ProjectNameLookup/ProjectName eq ‘<project-name-1>’ or ProjectNameLookup/ProjectName eq ‘<project-name-2>’ or ProjectNameLookup/ProjectName eq ‘<project-name-3>’ or ProjectNameLookup/ProjectName eq ‘<project-name-4>’ or ProjectNameLookup/ProjectName eq ‘<project-name-5>’ or ProjectNameLookup/ProjectName eq ‘<project-name-6>’ or ProjectNameLookup/ProjectName eq ‘<project-name-7>’ or ProjectNameLookup/ProjectName eq ‘<project-name-8>’ or ProjectNameLookup/ProjectName eq ‘<project-name-9>’ or ProjectNameLookup/ProjectName eq ‘<project-name-10>’ or ProjectNameLookup/ProjectName eq ‘<project-name-11>’ or ProjectNameLookup/ProjectName eq ‘<project-name-12>’ or ProjectNameLookup/ProjectName eq ‘<project-name-13>’ or ProjectNameLookup/ProjectName eq ‘<project-name-14>’ or ProjectNameLookup/ProjectName eq ‘<project-name-15>’ or ProjectNameLookup/ProjectName eq ‘<project-name-16>’ or ProjectNameLookup/ProjectName eq ‘<project-name-17>’ or ProjectNameLookup/ProjectName eq ‘<project-name-18>’ or ProjectNameLookup/ProjectName eq ‘<project-name-19>’ or ProjectNameLookup/ProjectName eq ‘<project-name-20>’ or ProjectNameLookup/ProjectName eq ‘<project-name-21>’ or ProjectNameLookup/ProjectName eq ‘<project-name-22>’ or ProjectNameLookup/ProjectName eq ‘<project-name-23>’ or ProjectNameLookup/ProjectName eq ‘<project-name-24>’ or ProjectNameLookup/ProjectName eq ‘<project-name-25>’ or ProjectNameLookup/ProjectName eq ‘<project-name-26>’ or ProjectNameLookup/ProjectName eq ‘<project-name-27>’ or ProjectNameLookup/ProjectName eq ‘<project-name-28>’ or ProjectNameLookup/ProjectName eq ‘<project-name-29>’ or ProjectNameLookup/ProjectName eq ‘<project-name-30>’ or ProjectNameLookup/ProjectName eq ‘<project-name-31>’ or ProjectNameLookup/ProjectName eq ‘<project-name-32>’ or ProjectNameLookup/ProjectName eq ‘<project-name-33>’ or ProjectNameLookup/ProjectName eq ‘<project-name-34>’ or ProjectNameLookup/ProjectName eq ‘<project-name-35>’&$orderby=Created desc&$top=999 When I run above query, then its not reurning any items. but when I filter query, then it is returning the items. I saw numbers of articles where they say the rest api has limit of 6000 char, some says 2048. So I am getting confsed here. Read More
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फोनपे की शिकायत कैसे करें?
तो हमसे संपर्क करें” +91–9861~0719~54+ ✓ टोल फ्री करें… फोनपे का शिकायत फोनपे टोल फ्री नंबर पर -कॉल करें ऑनलाइन शिकायत कायत दर्ज करना चाहते हैंतो हमसे संपर्क करें” +91–9861~0719~54+ ✓ टोल फ्री करें… फोनपे का शिकायत फोनपे टोल फ्री नंबर पर -कॉल करें ऑनलाइन शिकायत कायत दर्ज करना चाहते हैं
तो हमसे संपर्क करें” +91–9861~0719~54+ ✓ टोल फ्री करें… फोनपे का शिकायत फोनपे टोल फ्री नंबर पर -कॉल करें ऑनलाइन शिकायत कायत दर्ज करना चाहते हैंतो हमसे संपर्क करें” +91–9861~0719~54+ ✓ टोल फ्री करें… फोनपे का शिकायत फोनपे टोल फ्री नंबर पर -कॉल करें ऑनलाइन शिकायत कायत दर्ज करना चाहते हैं Read More
شيخ روحاني خبيري ” 8443 009733402 ” تربة المحبة الأثرية
شيخ روحاني خبيري ” 8443 009733402 ” تربة المحبة الأثرية
شيخ روحاني خبيري ” 8443 009733402 ” تربة المحبة الأثرية Read More
Names of approvers not getting populated
A SharePoint site is being used for procedures pertaining to contracts. However, they have run into the following issue. The contract form has fields for the contract’s title, cost (USD), and the from and to dates of its validity. Next, we must choose the departments of the business that are participating in the contract from a dropdown list. Six departments in all are required for every contract. Of the six areas, two are dynamic and change based on customer needs, while the remaining four remain the same for all contracts. You must choose those two departments from a drop-down menu. Two more fields show on the contract page based on the department that is chosen from the dropdown list. The usernames of the department’s approvers must be entered in those fields. Subsequently, we must upload the contract-related PDF papers. The contract must then be submitted for approval. The issue now arises because, once submitting the contract, the names of the two dynamic departments’ approvers are not displayed on the contract page when we access the contract through the “Contracts” list. We must manually amend the list in order to add the names of those two approvers once more as a result of this issue. This wasn’t an issue previously, and manually updating the list each time would not be practical given the hundreds of contracts.
Can anyone please offer some advice on how to resolve this issue? Why is this problem occurring now when it did not previously exist?
Just so you know, the site is a SharePoint 2019 site with Nintex workflow.
A SharePoint site is being used for procedures pertaining to contracts. However, they have run into the following issue. The contract form has fields for the contract’s title, cost (USD), and the from and to dates of its validity. Next, we must choose the departments of the business that are participating in the contract from a dropdown list. Six departments in all are required for every contract. Of the six areas, two are dynamic and change based on customer needs, while the remaining four remain the same for all contracts. You must choose those two departments from a drop-down menu. Two more fields show on the contract page based on the department that is chosen from the dropdown list. The usernames of the department’s approvers must be entered in those fields. Subsequently, we must upload the contract-related PDF papers. The contract must then be submitted for approval. The issue now arises because, once submitting the contract, the names of the two dynamic departments’ approvers are not displayed on the contract page when we access the contract through the “Contracts” list. We must manually amend the list in order to add the names of those two approvers once more as a result of this issue. This wasn’t an issue previously, and manually updating the list each time would not be practical given the hundreds of contracts. Can anyone please offer some advice on how to resolve this issue? Why is this problem occurring now when it did not previously exist? Just so you know, the site is a SharePoint 2019 site with Nintex workflow. Read More
