Hello,

I have a function that traces raypaths given input criteria. I then have a second function that solves for error at a given point in space. I am able to find the launch angles that would result in bracketing the target.
My question is this: having solved for launch angles that bracket the point, how do I find the launch angle that results in zero error? An excerpt of the code I am working with is below

rayangle = (-90:.1:90)
nray=length(rayangle)
for ii=1:nray
theta0=rayangle(ii)
z_r=raysolver(z0,theta0,cmat,nstep,rstep); %calling the function that traces the rays

z_r_theta0(ii,:)=z_r(1,:); %Saving the path of each ray in z_r_theta0
end
%% Finding error

%target co-ordinates
r=50000;
z=1100;

d_error=deptherror(r,z,z_r_theta0); %gives me depth error for each launch angle

bracket_ray=crossray(d_error)%this gives me all the launch angles that bracket the target.

%what I need is to find theta0 for each set of bracketing launch angles
%that result in d_error == 0Hello,

I have a function that traces raypaths given input criteria. I then have a second function that solves for error at a given point in space. I am able to find the launch angles that would result in bracketing the target.
My question is this: having solved for launch angles that bracket the point, how do I find the launch angle that results in zero error? An excerpt of the code I am working with is below

rayangle = (-90:.1:90)
nray=length(rayangle)
for ii=1:nray
theta0=rayangle(ii)
z_r=raysolver(z0,theta0,cmat,nstep,rstep); %calling the function that traces the rays

z_r_theta0(ii,:)=z_r(1,:); %Saving the path of each ray in z_r_theta0
end
%% Finding error

%target co-ordinates
r=50000;
z=1100;

d_error=deptherror(r,z,z_r_theta0); %gives me depth error for each launch angle

bracket_ray=crossray(d_error)%this gives me all the launch angles that bracket the target.

%what I need is to find theta0 for each set of bracketing launch angles
%that result in d_error == 0 Hello,

I have a function that traces raypaths given input criteria. I then have a second function that solves for error at a given point in space. I am able to find the launch angles that would result in bracketing the target.
My question is this: having solved for launch angles that bracket the point, how do I find the launch angle that results in zero error? An excerpt of the code I am working with is below

rayangle = (-90:.1:90)
nray=length(rayangle)
for ii=1:nray
theta0=rayangle(ii)
z_r=raysolver(z0,theta0,cmat,nstep,rstep); %calling the function that traces the rays

z_r_theta0(ii,:)=z_r(1,:); %Saving the path of each ray in z_r_theta0
end
%% Finding error

%target co-ordinates
r=50000;
z=1100;

d_error=deptherror(r,z,z_r_theta0); %gives me depth error for each launch angle

bracket_ray=crossray(d_error)%this gives me all the launch angles that bracket the target.

%what I need is to find theta0 for each set of bracketing launch angles
%that result in d_error == 0 zero solver MATLAB Answers — New Questions

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