The terminals are LC only, L=0.1H and C=0.25F with an initial voltage of 1V. The variable capacitor has an initial capacitance of 0.25F and is increased by 0.25F each time the voltage takes an extreme value. The judgment of the extreme value is made by the derivative block, which outputs an impulse signal when hitcrossing becomes 0. Q=CV, and since Q is conserved, C is increased so that V is attenuated.The circuit I am currently working on is as follows, but it does not work well.

The ideal graph is as follows.The terminals are LC only, L=0.1H and C=0.25F with an initial voltage of 1V. The variable capacitor has an initial capacitance of 0.25F and is increased by 0.25F each time the voltage takes an extreme value. The judgment of the extreme value is made by the derivative block, which outputs an impulse signal when hitcrossing becomes 0. Q=CV, and since Q is conserved, C is increased so that V is attenuated.The circuit I am currently working on is as follows, but it does not work well.

The ideal graph is as follows. The terminals are LC only, L=0.1H and C=0.25F with an initial voltage of 1V. The variable capacitor has an initial capacitance of 0.25F and is increased by 0.25F each time the voltage takes an extreme value. The judgment of the extreme value is made by the derivative block, which outputs an impulse signal when hitcrossing becomes 0. Q=CV, and since Q is conserved, C is increased so that V is attenuated.The circuit I am currently working on is as follows, but it does not work well.

The ideal graph is as follows. simulink, variable capacitor, lc MATLAB Answers — New Questions

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