How to update a function with output from another function?

I am trying to solve for heat transfer coefficients so that I can use them to calculate gas and tank wall temperatures. Currently, I am using constant heat transfer coefficients to enable the calculation of the desired temperatures with ode45.
% Convective heat transfer coefficients
h_in = 25; % Convective heat transfer coefficient inside the tank (W/(m^2·K))
h_out = 6; % Convective heat transfer coefficient outside the tank (W/(m^2·K))

% Solve the coupled ODEs and PDE
[t, y] = ode45(@(t, y) odes(t, y, R, C_p_gas, k_liner, k_CFRP, rho_liner, rho_CFRP, C_p_liner, C_p_CFRP, h_in, h_out, T_ambient, A_in, A_out, dx_liner, dx_CFRP, N_liner, N_CFRP, V, mdot_out), tspan, initial_conditions);

% Extract time histories for inside and outside wall temperatures
T_wall_liner_interface = y(:,3); % Inside wall temperature (first point of the liner)
T_wall_CFRP_interface = y(:,end); % Outside wall temperature (last point of the CFRP layer)
What I would like to do is to use the output temperatures from the ode45 to solve for h_in and h_out, which will in turn be used by ode45 to solve for new temperatures. The h_in and h_out calculations look like this:
function [h_in, h_out]=heat_transfer_coefficients
Di = 0.230; % Internal diameter in meters
Do = 0.279; % External diameter in meters

T_gf = 266.17; %(K) – Type III hydrogen gas T at film temp
rho_gf = 39.16; %(kg/m^3) – Type III hydrogen gas density @ T_gf

Cp_gf = 0.01514*((T_gf/100)^4.789)+1002;
mu_gf = (-4.127*10^-7)*((T_gf/100)^2)+((7.258*10^-6)*(T_gf/100))+(4.094*10^-7);
lambda_gf = ((-3.77*10^-4)*(T_gf/100)^2)+((1.004*10^-2)*(T_gf/100))-(4.776*10^-4);
beta_gf = 1/T_gf; %volumetric thermal expansion coefficient
g = 9.81; %gravitational acceleration (m/s^2)

Rai = (rho_gf^2*(Di^3)*beta_gf*g*(T_wall_liner_interface-T_gas)*Cp_gf)/(mu_gf*lambda_gf); %Rayleigh number at inner wall

if Rai < 10^8
Nu_i = 1.15*Rai.^0.22;
else
Nu_i = 0.14*Rai.^0.333;
end

ki = 168.9e3; %thermal conductivity inside tank at T_g, Type III (W/m*K)
h_in = (Nu_i*ki)/Di;

T_ambf = 279.43; %(K) – Type III
rho_ambf = 1.263; %(kg/m^3) – density @ T_ambf
c_wind = 0; %(m/s) – cross wind velocity

Cp_ambf = 0.01514*((T_ambf/100)^4.789)+1002;
mu_ambf = (-4.127*10^-7)*((T_ambf/100)^2)+((7.258*10^-6)*(T_ambf/100))+(4.094*10^-7);
lambda_ambf = ((-3.77*10^-4)*(T_ambf/100)^2)+((1.004*10^-2)*(T_ambf/100))-(4.776*10^-4);
beta_ambf = 1/T_ambf; %volumetric thermal expansion coefficient

Re_Do = (rho_ambf*c_wind*Do)/(mu_ambf);
Pr_ambf = (mu_ambf*Cp_ambf)/lambda_ambf;

if Re_Do == 0
Nu_cylforced = 0;
Nu_sphforced = 0;
else
Nu_cylforced = 0.3+((0.62*(Re_Do^0.5)*(Pr_ambf^(1/3)))/(1+(0.4/((Pr_ambf))^(2/3)))^(1/4))…
*(1+(Re_Do/282000)^5/8)^4/5;
Nu_sphforced = 2 + ((Re_Do/4)+((3*10^-4)*Re_Do^1.6))^0.5;
end

Rao = (rho_ambf^2*(Do^3)*beta_ambf*g*(T_amb-T_wall_CFRP_interface)*Cp_ambf)/(mu_ambf*lambda_ambf); %Rayleigh number at inner wall

Nu_oforced = ((Nu_cylforced*0.72)+(Nu_sphforced*0.24))/(0.72+0.24);
Nu_ofree = (0.6+((0.387*(Rao.^(1/6)))/(1+(0.559/Pr_ambf)^(9/16)).^(8/27))).^2;
Nu_o = ((Nu_ofree.^4)+(Nu_oforced^4)).^0.25;

ko = 24.84e3; %thermal conductivity outside tank at T_wo, Type III (W/m*K)
h_out = (Nu_o*ko)/Do;
end
As can be seen in the above code, the h_in and h_out calculations require T_gas, T_wall_liner interface and T_wall_CFRP_interface, which currently are being calculated after h_in and h_out. Can somebody please show me a way I can incorporate the h_in and h_out calculations into the first section of code? For ease of explanation and solving, please feel free to use your own numbers for the constants in the ode45 solver line.I am trying to solve for heat transfer coefficients so that I can use them to calculate gas and tank wall temperatures. Currently, I am using constant heat transfer coefficients to enable the calculation of the desired temperatures with ode45.
% Convective heat transfer coefficients
h_in = 25; % Convective heat transfer coefficient inside the tank (W/(m^2·K))
h_out = 6; % Convective heat transfer coefficient outside the tank (W/(m^2·K))