Hey guys I have a simple question:
I am using Matlab R2010a and trying to solve an equation with 1 variable like this:

solve(‘4-t^2=0’)

ans =

-2
2

No problem as you can see 😉
My question is, when I try to replace the *4* with a variable (lets call it A), it wont work how I want it to work:

solve(‘A-t^2=0’)

ans =

A^(1/2)
-A^(1/2)

All fine, solution found but A is not a variable, it has a defined value of 4, so that the solution would be -2,2.
Can anyone help me to find the solution to this problem if its possible?

Thanks a lot guys!Hey guys I have a simple question:
I am using Matlab R2010a and trying to solve an equation with 1 variable like this:

solve(‘4-t^2=0’)

ans =

-2
2

No problem as you can see 😉
My question is, when I try to replace the *4* with a variable (lets call it A), it wont work how I want it to work:

solve(‘A-t^2=0’)

ans =

A^(1/2)
-A^(1/2)

All fine, solution found but A is not a variable, it has a defined value of 4, so that the solution would be -2,2.
Can anyone help me to find the solution to this problem if its possible?

Thanks a lot guys! Hey guys I have a simple question:
I am using Matlab R2010a and trying to solve an equation with 1 variable like this:

solve(‘4-t^2=0’)

ans =

-2
2

No problem as you can see 😉
My question is, when I try to replace the *4* with a variable (lets call it A), it wont work how I want it to work:

solve(‘A-t^2=0’)

ans =

A^(1/2)
-A^(1/2)

All fine, solution found but A is not a variable, it has a defined value of 4, so that the solution would be -2,2.
Can anyone help me to find the solution to this problem if its possible?

Thanks a lot guys! solve, variable MATLAB Answers — New Questions

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