erroe in string(j,n)=string(k,n);

for k=1:Npop
for j=1:dim
busLocation(j,k)=busd(busLocation(j,k),1);
end
sdf= unique(busLocation(:,k));

while length(sdf)<dim
sdf=randi([2 length(busd(:,1))],dim,1);
for j=1:dim
sdf(j)=busd(sdf(j),1);
end
busLocation(:,k)=sdf;

sdf= unique(busLocation(:,k));
end
end
ndif = [0.28; 0.35; 0.39; 0.35; 0.27; 0.34; 0.40; 0.34; 0.25; 0.32];
for k = 1:Npop
mdif(k)= ndif(k);
end
nsw=length(string);
mpop = round(Npop/4);
for j = 1:mpop
minman = min(mdif(:));
for k = 1:Npop
if mdif(k)== minman
for n=1:nsw
string(j,n)=string(k,n);
end
mdif(k)= 1010;
break;
end
end
end
for j = 1:(Npop-mpop)
for bits=1:nsw
string(mpop +j,bits) = string(j,bits);
end
end ; enderroe in string(j,n)=string(k,n);

for k=1:Npop
for j=1:dim
busLocation(j,k)=busd(busLocation(j,k),1);
end
sdf= unique(busLocation(:,k));

while length(sdf)<dim
sdf=randi([2 length(busd(:,1))],dim,1);
for j=1:dim
sdf(j)=busd(sdf(j),1);
end
busLocation(:,k)=sdf;

sdf= unique(busLocation(:,k));
end
end
ndif = [0.28; 0.35; 0.39; 0.35; 0.27; 0.34; 0.40; 0.34; 0.25; 0.32];
for k = 1:Npop
mdif(k)= ndif(k);
end
nsw=length(string);
mpop = round(Npop/4);
for j = 1:mpop
minman = min(mdif(:));
for k = 1:Npop
if mdif(k)== minman
for n=1:nsw
string(j,n)=string(k,n);
end
mdif(k)= 1010;
break;
end
end
end
for j = 1:(Npop-mpop)
for bits=1:nsw
string(mpop +j,bits) = string(j,bits);
end
end ; end erroe in string(j,n)=string(k,n);

for k=1:Npop
for j=1:dim
busLocation(j,k)=busd(busLocation(j,k),1);
end
sdf= unique(busLocation(:,k));

while length(sdf)<dim
sdf=randi([2 length(busd(:,1))],dim,1);
for j=1:dim
sdf(j)=busd(sdf(j),1);
end
busLocation(:,k)=sdf;

sdf= unique(busLocation(:,k));
end
end
ndif = [0.28; 0.35; 0.39; 0.35; 0.27; 0.34; 0.40; 0.34; 0.25; 0.32];
for k = 1:Npop
mdif(k)= ndif(k);
end
nsw=length(string);
mpop = round(Npop/4);
for j = 1:mpop
minman = min(mdif(:));
for k = 1:Npop
if mdif(k)== minman
for n=1:nsw
string(j,n)=string(k,n);
end
mdif(k)= 1010;
break;
end
end
end
for j = 1:(Npop-mpop)
for bits=1:nsw
string(mpop +j,bits) = string(j,bits);
end
end ; end for study MATLAB Answers — New Questions

​

I’m trying to solve an ODE using Laplace method, but I’m stuck on solving the equation
Here’s my code:
syms t x(t) s X(s);

% PARAMETERS (tried to do symbolically but it was more diffcult)
m = 1;
k = 0.5;
xi = 1.2;
c = xi*2*sqrt(k*m)
f0 = 1;
w = 0.1;

dx = diff(x, t, 1);
ddx = diff(x, t, 2);

% INITIAL CONDITIONS
x0 = 0;
dx0 = 0;

newton = m*ddx+ c*dx +k*x;
f = f0*cos(w*t);

lteqn = laplace(newton, t, s)
lefteqn = subs(lteqn,{laplace(x(t), t, s), x(0),dx(0)},{X(s), x0, dx0})
F_s = laplace(f, t, s);
simplify(solve(lefteqn == F_s, X(s)))
I can’t believe MATLAB cannot solve this easy equation. I think I’m missing something.
Thank you guysI’m trying to solve an ODE using Laplace method, but I’m stuck on solving the equation
Here’s my code:
syms t x(t) s X(s);

% PARAMETERS (tried to do symbolically but it was more diffcult)
m = 1;
k = 0.5;
xi = 1.2;
c = xi*2*sqrt(k*m)
f0 = 1;
w = 0.1;

dx = diff(x, t, 1);
ddx = diff(x, t, 2);

% INITIAL CONDITIONS
x0 = 0;
dx0 = 0;

newton = m*ddx+ c*dx +k*x;
f = f0*cos(w*t);

lteqn = laplace(newton, t, s)
lefteqn = subs(lteqn,{laplace(x(t), t, s), x(0),dx(0)},{X(s), x0, dx0})
F_s = laplace(f, t, s);
simplify(solve(lefteqn == F_s, X(s)))
I can’t believe MATLAB cannot solve this easy equation. I think I’m missing something.
Thank you guys I’m trying to solve an ODE using Laplace method, but I’m stuck on solving the equation
Here’s my code:
syms t x(t) s X(s);

% PARAMETERS (tried to do symbolically but it was more diffcult)
m = 1;
k = 0.5;
xi = 1.2;
c = xi*2*sqrt(k*m)
f0 = 1;
w = 0.1;

dx = diff(x, t, 1);
ddx = diff(x, t, 2);

% INITIAL CONDITIONS
x0 = 0;
dx0 = 0;

newton = m*ddx+ c*dx +k*x;
f = f0*cos(w*t);

lteqn = laplace(newton, t, s)
lefteqn = subs(lteqn,{laplace(x(t), t, s), x(0),dx(0)},{X(s), x0, dx0})
F_s = laplace(f, t, s);
simplify(solve(lefteqn == F_s, X(s)))
I can’t believe MATLAB cannot solve this easy equation. I think I’m missing something.
Thank you guys solve, ode, laplace, matlab MATLAB Answers — New Questions

​

I have Matlab R2024A installed on a linux computer with no GUI (terminal only) I want to run matlab -licmode onlinelicensing but also pass my username and password in one line so I don’t have to input it in. Is that possible ?I have Matlab R2024A installed on a linux computer with no GUI (terminal only) I want to run matlab -licmode onlinelicensing but also pass my username and password in one line so I don’t have to input it in. Is that possible ? I have Matlab R2024A installed on a linux computer with no GUI (terminal only) I want to run matlab -licmode onlinelicensing but also pass my username and password in one line so I don’t have to input it in. Is that possible ? license MATLAB Answers — New Questions

​

Can I use the MATLAB Package Manager (MPM) on Windows without administrative privileges?Can I use the MATLAB Package Manager (MPM) on Windows without administrative privileges? Can I use the MATLAB Package Manager (MPM) on Windows without administrative privileges?  MATLAB Answers — New Questions

​

I am using webwrite and get the following error:
"Error connecting to [targeturl]: Recv failure: Connection was reset"
This is the matlab code:
options = weboptions(‘MediaType’,’application/x-www-form-urlencoded’,’Timeout’,Inf);
response = webwrite(url,data,options);
When I execute my equivalent url/data call from Chrome, it works just fine.
It’s knowingly a semi-long wait time for the response. (I’m requesting my target server to build a large CSV dataset then respond with the URL for the CSV). ‘response’ is simply a text string of the CSV url. (Separate code to fetch the CSV works just fine)
The url/data call used to work fine with a Timeout of 900s, then I increased my request to ask for a dataset about 10%-15% larger. Now I keep getting the above error, even though the Timeout upper limit should actually be a little over 2000s. I’ve also tried manual Timeout thesholds at 1000, 1200, 1800, etc to no avail.
It seems like even thought the Timeout is 2000+… something is still timing out…I am using webwrite and get the following error:
"Error connecting to [targeturl]: Recv failure: Connection was reset"
This is the matlab code:
options = weboptions(‘MediaType’,’application/x-www-form-urlencoded’,’Timeout’,Inf);
response = webwrite(url,data,options);
When I execute my equivalent url/data call from Chrome, it works just fine.
It’s knowingly a semi-long wait time for the response. (I’m requesting my target server to build a large CSV dataset then respond with the URL for the CSV). ‘response’ is simply a text string of the CSV url. (Separate code to fetch the CSV works just fine)
The url/data call used to work fine with a Timeout of 900s, then I increased my request to ask for a dataset about 10%-15% larger. Now I keep getting the above error, even though the Timeout upper limit should actually be a little over 2000s. I’ve also tried manual Timeout thesholds at 1000, 1200, 1800, etc to no avail.
It seems like even thought the Timeout is 2000+… something is still timing out… I am using webwrite and get the following error:
"Error connecting to [targeturl]: Recv failure: Connection was reset"
This is the matlab code:
options = weboptions(‘MediaType’,’application/x-www-form-urlencoded’,’Timeout’,Inf);
response = webwrite(url,data,options);
When I execute my equivalent url/data call from Chrome, it works just fine.
It’s knowingly a semi-long wait time for the response. (I’m requesting my target server to build a large CSV dataset then respond with the URL for the CSV). ‘response’ is simply a text string of the CSV url. (Separate code to fetch the CSV works just fine)
The url/data call used to work fine with a Timeout of 900s, then I increased my request to ask for a dataset about 10%-15% larger. Now I keep getting the above error, even though the Timeout upper limit should actually be a little over 2000s. I’ve also tried manual Timeout thesholds at 1000, 1200, 1800, etc to no avail.
It seems like even thought the Timeout is 2000+… something is still timing out… webwrite, timeout MATLAB Answers — New Questions

​

Greetings everyone, I am trying to look into a code found here corydodson/NozzleDesign: Design of supersonic nozzles (github.com). However, I run into an error whenever I run the code which reads "Matrix is singular, close to singular or badly scaled. Results may be inaccurate. RCOND = NaN. " I belive the error comes from this internalnode.m function. x,y are the coordinates, t0 is the temperature and d can be 0 or 1 depending on the user. Anyway I can resolve this? Any help is appreciated!
function [xOut,yOut,uOut,vOut] = internalnode(t0,species,moleFracs,x,y,u,v,d)
h0 = mixprop(‘h’,species,moleFracs,t0);
r = mixprop(‘r’,species,moleFracs)*1000;
L = length(x);
minus = logical([ones(L – 1,1);0]);
plus = logical([0;ones(L – 1,1)]);
xm = x(minus);
xmCalc = xm;
xp = x(plus);
ym = y(minus);
ymCalc = ym;
yp = y(plus);
ypCalc = yp;
um = u(minus);
umCalc = um;
up = u(plus);
upCalc = up;
vm = v(minus);
vmCalc = vm;
vp = v(plus);
vpCalc = vp;
sp = vm;
N = 20;
err = 1e-4;
notConv = true(1,4);
for i = 1:N

ymCalc = (ym + ymCalc)/2;
ypCalc = (yp + ypCalc)/2;
umCalc = (um + umCalc)/2;
upCalc = (up + upCalc)/2;
vmCalc = (vm + vmCalc)/2;
vpCalc = (vp + vpCalc)/2;

uCalc = [umCalc;upCalc(end)];
vCalc = [vmCalc;vpCalc(end)];

vMag = sqrt(uCalc.^2 + vCalc.^2);
h = h0 – vMag.^2/2000;
t = tempfromprop(species,moleFracs,’h’,h);
g = mixprop(‘gamma’,species,moleFracs,t);

a = sqrt(r*g.*t);
am = a(minus);
ap = a(plus);

mu = asind(a./vMag);
mum = mu(minus);
mup = mu(plus);

theta = atand(vCalc./uCalc);
thetam = theta(minus);
thetap = theta(plus);

lm = tand(thetam – mum);
lp = tand(thetap + mup);

q = uCalc.^2 – a.^2;
qm = q(minus);
qp = q(plus);

rm = 2*umCalc.*vmCalc – qm.*lm;
rp = 2*upCalc.*vpCalc – qp.*lp;

sm = d*am.^2.*vmCalc./ymCalc;
switch isempty(sp(ypCalc == 0))
case 1
sp = d*ap.^2.*vpCalc./ypCalc;
otherwise
sp(ypCalc ~= 0) = d*ap(ypCalc ~= 0).^2.*vpCalc(ypCalc ~= 0)./ypCalc(ypCalc ~= 0);
sp(ypCalc == 0) = sm(end);
end

A = zeros(L);
B = zeros(L,1);
for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [1,-lp(j);…
1,-lm(j)];
B(2*(j – 1) + 1:2*j) = [yp(j) – lp(j)*xp(j);…
ym(j) – lm(j)*xm(j)];
end

X = AB;
ymCalc = X(1:2:end);
ypCalc = ymCalc;
xmCalc = X(2:2:end);
xpCalc = xmCalc;

for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [qp(j),rp(j);…
qm(j),rm(j)];
B(2*(j – 1) + 1:2*j) = [sp(j)*(xpCalc(j) – xp(j)) + qp(j)*up(j) + rp(j)*vp(j);…
sm(j)*(xmCalc(j) – xm(j)) + qm(j)*um(j) + rm(j)*vm(j)];
end

X = AB;
umCalc = X(1:2:end);
upCalc = umCalc;
vmCalc = X(2:2:end);
vpCalc = vmCalc;

switch i ~= 1
case 1
notConv = abs([xmCalc,ymCalc,umCalc,vmCalc]./check0 – 1) > err;
end

check0 = [xmCalc,ymCalc,umCalc,vmCalc];

switch sum(sum(notConv)) == 0
case 1
break
end

switch isnan(xmCalc) | isnan(ymCalc) | isnan(umCalc) | isnan(vmCalc)
case 1
break
end

end
xOut = xmCalc;
yOut = ymCalc;
uOut = umCalc;
vOut = vmCalc;
endGreetings everyone, I am trying to look into a code found here corydodson/NozzleDesign: Design of supersonic nozzles (github.com). However, I run into an error whenever I run the code which reads "Matrix is singular, close to singular or badly scaled. Results may be inaccurate. RCOND = NaN. " I belive the error comes from this internalnode.m function. x,y are the coordinates, t0 is the temperature and d can be 0 or 1 depending on the user. Anyway I can resolve this? Any help is appreciated!
function [xOut,yOut,uOut,vOut] = internalnode(t0,species,moleFracs,x,y,u,v,d)
h0 = mixprop(‘h’,species,moleFracs,t0);
r = mixprop(‘r’,species,moleFracs)*1000;
L = length(x);
minus = logical([ones(L – 1,1);0]);
plus = logical([0;ones(L – 1,1)]);
xm = x(minus);
xmCalc = xm;
xp = x(plus);
ym = y(minus);
ymCalc = ym;
yp = y(plus);
ypCalc = yp;
um = u(minus);
umCalc = um;
up = u(plus);
upCalc = up;
vm = v(minus);
vmCalc = vm;
vp = v(plus);
vpCalc = vp;
sp = vm;
N = 20;
err = 1e-4;
notConv = true(1,4);
for i = 1:N

ymCalc = (ym + ymCalc)/2;
ypCalc = (yp + ypCalc)/2;
umCalc = (um + umCalc)/2;
upCalc = (up + upCalc)/2;
vmCalc = (vm + vmCalc)/2;
vpCalc = (vp + vpCalc)/2;

uCalc = [umCalc;upCalc(end)];
vCalc = [vmCalc;vpCalc(end)];

vMag = sqrt(uCalc.^2 + vCalc.^2);
h = h0 – vMag.^2/2000;
t = tempfromprop(species,moleFracs,’h’,h);
g = mixprop(‘gamma’,species,moleFracs,t);

a = sqrt(r*g.*t);
am = a(minus);
ap = a(plus);

mu = asind(a./vMag);
mum = mu(minus);
mup = mu(plus);

theta = atand(vCalc./uCalc);
thetam = theta(minus);
thetap = theta(plus);

lm = tand(thetam – mum);
lp = tand(thetap + mup);

q = uCalc.^2 – a.^2;
qm = q(minus);
qp = q(plus);

rm = 2*umCalc.*vmCalc – qm.*lm;
rp = 2*upCalc.*vpCalc – qp.*lp;

sm = d*am.^2.*vmCalc./ymCalc;
switch isempty(sp(ypCalc == 0))
case 1
sp = d*ap.^2.*vpCalc./ypCalc;
otherwise
sp(ypCalc ~= 0) = d*ap(ypCalc ~= 0).^2.*vpCalc(ypCalc ~= 0)./ypCalc(ypCalc ~= 0);
sp(ypCalc == 0) = sm(end);
end

A = zeros(L);
B = zeros(L,1);
for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [1,-lp(j);…
1,-lm(j)];
B(2*(j – 1) + 1:2*j) = [yp(j) – lp(j)*xp(j);…
ym(j) – lm(j)*xm(j)];
end

X = AB;
ymCalc = X(1:2:end);
ypCalc = ymCalc;
xmCalc = X(2:2:end);
xpCalc = xmCalc;

for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [qp(j),rp(j);…
qm(j),rm(j)];
B(2*(j – 1) + 1:2*j) = [sp(j)*(xpCalc(j) – xp(j)) + qp(j)*up(j) + rp(j)*vp(j);…
sm(j)*(xmCalc(j) – xm(j)) + qm(j)*um(j) + rm(j)*vm(j)];
end

X = AB;
umCalc = X(1:2:end);
upCalc = umCalc;
vmCalc = X(2:2:end);
vpCalc = vmCalc;

switch i ~= 1
case 1
notConv = abs([xmCalc,ymCalc,umCalc,vmCalc]./check0 – 1) > err;
end

check0 = [xmCalc,ymCalc,umCalc,vmCalc];

switch sum(sum(notConv)) == 0
case 1
break
end

switch isnan(xmCalc) | isnan(ymCalc) | isnan(umCalc) | isnan(vmCalc)
case 1
break
end

end
xOut = xmCalc;
yOut = ymCalc;
uOut = umCalc;
vOut = vmCalc;
end Greetings everyone, I am trying to look into a code found here corydodson/NozzleDesign: Design of supersonic nozzles (github.com). However, I run into an error whenever I run the code which reads "Matrix is singular, close to singular or badly scaled. Results may be inaccurate. RCOND = NaN. " I belive the error comes from this internalnode.m function. x,y are the coordinates, t0 is the temperature and d can be 0 or 1 depending on the user. Anyway I can resolve this? Any help is appreciated!
function [xOut,yOut,uOut,vOut] = internalnode(t0,species,moleFracs,x,y,u,v,d)
h0 = mixprop(‘h’,species,moleFracs,t0);
r = mixprop(‘r’,species,moleFracs)*1000;
L = length(x);
minus = logical([ones(L – 1,1);0]);
plus = logical([0;ones(L – 1,1)]);
xm = x(minus);
xmCalc = xm;
xp = x(plus);
ym = y(minus);
ymCalc = ym;
yp = y(plus);
ypCalc = yp;
um = u(minus);
umCalc = um;
up = u(plus);
upCalc = up;
vm = v(minus);
vmCalc = vm;
vp = v(plus);
vpCalc = vp;
sp = vm;
N = 20;
err = 1e-4;
notConv = true(1,4);
for i = 1:N

ymCalc = (ym + ymCalc)/2;
ypCalc = (yp + ypCalc)/2;
umCalc = (um + umCalc)/2;
upCalc = (up + upCalc)/2;
vmCalc = (vm + vmCalc)/2;
vpCalc = (vp + vpCalc)/2;

uCalc = [umCalc;upCalc(end)];
vCalc = [vmCalc;vpCalc(end)];

vMag = sqrt(uCalc.^2 + vCalc.^2);
h = h0 – vMag.^2/2000;
t = tempfromprop(species,moleFracs,’h’,h);
g = mixprop(‘gamma’,species,moleFracs,t);

a = sqrt(r*g.*t);
am = a(minus);
ap = a(plus);

mu = asind(a./vMag);
mum = mu(minus);
mup = mu(plus);

theta = atand(vCalc./uCalc);
thetam = theta(minus);
thetap = theta(plus);

lm = tand(thetam – mum);
lp = tand(thetap + mup);

q = uCalc.^2 – a.^2;
qm = q(minus);
qp = q(plus);

rm = 2*umCalc.*vmCalc – qm.*lm;
rp = 2*upCalc.*vpCalc – qp.*lp;

sm = d*am.^2.*vmCalc./ymCalc;
switch isempty(sp(ypCalc == 0))
case 1
sp = d*ap.^2.*vpCalc./ypCalc;
otherwise
sp(ypCalc ~= 0) = d*ap(ypCalc ~= 0).^2.*vpCalc(ypCalc ~= 0)./ypCalc(ypCalc ~= 0);
sp(ypCalc == 0) = sm(end);
end

A = zeros(L);
B = zeros(L,1);
for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [1,-lp(j);…
1,-lm(j)];
B(2*(j – 1) + 1:2*j) = [yp(j) – lp(j)*xp(j);…
ym(j) – lm(j)*xm(j)];
end

X = AB;
ymCalc = X(1:2:end);
ypCalc = ymCalc;
xmCalc = X(2:2:end);
xpCalc = xmCalc;

for j = 1:L – 1
A(2*(j – 1) + 1:2*j,2*(j – 1) + 1:2*j) = [qp(j),rp(j);…
qm(j),rm(j)];
B(2*(j – 1) + 1:2*j) = [sp(j)*(xpCalc(j) – xp(j)) + qp(j)*up(j) + rp(j)*vp(j);…
sm(j)*(xmCalc(j) – xm(j)) + qm(j)*um(j) + rm(j)*vm(j)];
end

X = AB;
umCalc = X(1:2:end);
upCalc = umCalc;
vmCalc = X(2:2:end);
vpCalc = vmCalc;

switch i ~= 1
case 1
notConv = abs([xmCalc,ymCalc,umCalc,vmCalc]./check0 – 1) > err;
end

check0 = [xmCalc,ymCalc,umCalc,vmCalc];

switch sum(sum(notConv)) == 0
case 1
break
end

switch isnan(xmCalc) | isnan(ymCalc) | isnan(umCalc) | isnan(vmCalc)
case 1
break
end

end
xOut = xmCalc;
yOut = ymCalc;
uOut = umCalc;
vOut = vmCalc;
end #matlab, #nozzle, #method of characteristics, #singular MATLAB Answers — New Questions

​

Using R2014b. I have a function called within a for loop which returns lots of outputs. I want to assign an index value for each output of the function as the loop runs. Something like:

for ind = 1:n
[output1(ind),output2(ind), …] = function(inputs)
end

This doesn’t appear to work (results in an error). Is there an easy way to code this without doing:

output1(ind) = output1;
output2(ind) = output2;

for each variable after the function call?Using R2014b. I have a function called within a for loop which returns lots of outputs. I want to assign an index value for each output of the function as the loop runs. Something like:

for ind = 1:n
[output1(ind),output2(ind), …] = function(inputs)
end

This doesn’t appear to work (results in an error). Is there an easy way to code this without doing:

output1(ind) = output1;
output2(ind) = output2;

for each variable after the function call? Using R2014b. I have a function called within a for loop which returns lots of outputs. I want to assign an index value for each output of the function as the loop runs. Something like:

for ind = 1:n
[output1(ind),output2(ind), …] = function(inputs)
end

This doesn’t appear to work (results in an error). Is there an easy way to code this without doing:

output1(ind) = output1;
output2(ind) = output2;

for each variable after the function call? function output indexing MATLAB Answers — New Questions

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Hi I want to ask is there any ways to change the geometry shape of antenna toolbox designing yagi antenna. The default shape is in rectangle shape, and I want it to be in cylindrical form as I want to create it physically. Is there any ways to change the shape?Hi I want to ask is there any ways to change the geometry shape of antenna toolbox designing yagi antenna. The default shape is in rectangle shape, and I want it to be in cylindrical form as I want to create it physically. Is there any ways to change the shape? Hi I want to ask is there any ways to change the geometry shape of antenna toolbox designing yagi antenna. The default shape is in rectangle shape, and I want it to be in cylindrical form as I want to create it physically. Is there any ways to change the shape? antenna, simulation, emf MATLAB Answers — New Questions

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Is there any way to remove only the red shaded area of an image like the one below?
The data is a binary image and is binarized.
The image we are recognizing is basically a figure like the one on the left, so we can use bwareafilt to extract the maximum structure.
However, sometimes we get images like the one on the right. It does not mean that every time they are attached.
It would be best if we could set a threshold (if they are too close together, we recognize them as one), since the degree of attachment of the two objects varies.
We would appreciate it if you could let us know.Is there any way to remove only the red shaded area of an image like the one below?
The data is a binary image and is binarized.
The image we are recognizing is basically a figure like the one on the left, so we can use bwareafilt to extract the maximum structure.
However, sometimes we get images like the one on the right. It does not mean that every time they are attached.
It would be best if we could set a threshold (if they are too close together, we recognize them as one), since the degree of attachment of the two objects varies.
We would appreciate it if you could let us know. Is there any way to remove only the red shaded area of an image like the one below?
The data is a binary image and is binarized.
The image we are recognizing is basically a figure like the one on the left, so we can use bwareafilt to extract the maximum structure.
However, sometimes we get images like the one on the right. It does not mean that every time they are attached.
It would be best if we could set a threshold (if they are too close together, we recognize them as one), since the degree of attachment of the two objects varies.
We would appreciate it if you could let us know. image analysis, image segmentation MATLAB Answers — New Questions

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When I change the roll angle of the gripper, as demonstrated in my example code, the number of reachable poses varies for each roll angle. I’ve tested this with the same number of reference bodies (bodyName). The results were 411, 540, 513, and 547 reachable poses for different roll angles. I understand that this variation arises because each roll angle results in a different final configuration for the robot, affecting the GIK (Generalized Inverse Kinematics) solution. However, for a UR5e robot, this variation should not occur in real, right ? In practical use, can the UR5e achieve all 547 (assuming it’s the maximum it’s capable of reaching in this case) reachable poses for each roll angle?
for orientationIdx = 1:size(orientationsToTest,1)
for rollIdx = 1:numRollAngles

orientationsToTest(:,3) = rollAngles(rollIdx);
currentOrientation = orientationsToTest(orientationIdx,:);

targetPose = constraintPoseTarget(gripper);
targetPose.ReferenceBody = bodyName; %reference body
targetPose.TargetTransform = trvec2tform([0 0 0]) * eul2tform(currentOrientation,"XYZ");

[qWaypoints(2,:),solutionInfo] = gik_Pick(q0,targetPose);

end
endWhen I change the roll angle of the gripper, as demonstrated in my example code, the number of reachable poses varies for each roll angle. I’ve tested this with the same number of reference bodies (bodyName). The results were 411, 540, 513, and 547 reachable poses for different roll angles. I understand that this variation arises because each roll angle results in a different final configuration for the robot, affecting the GIK (Generalized Inverse Kinematics) solution. However, for a UR5e robot, this variation should not occur in real, right ? In practical use, can the UR5e achieve all 547 (assuming it’s the maximum it’s capable of reaching in this case) reachable poses for each roll angle?
for orientationIdx = 1:size(orientationsToTest,1)
for rollIdx = 1:numRollAngles

orientationsToTest(:,3) = rollAngles(rollIdx);
currentOrientation = orientationsToTest(orientationIdx,:);

targetPose = constraintPoseTarget(gripper);
targetPose.ReferenceBody = bodyName; %reference body
targetPose.TargetTransform = trvec2tform([0 0 0]) * eul2tform(currentOrientation,"XYZ");

[qWaypoints(2,:),solutionInfo] = gik_Pick(q0,targetPose);

end
end When I change the roll angle of the gripper, as demonstrated in my example code, the number of reachable poses varies for each roll angle. I’ve tested this with the same number of reference bodies (bodyName). The results were 411, 540, 513, and 547 reachable poses for different roll angles. I understand that this variation arises because each roll angle results in a different final configuration for the robot, affecting the GIK (Generalized Inverse Kinematics) solution. However, for a UR5e robot, this variation should not occur in real, right ? In practical use, can the UR5e achieve all 547 (assuming it’s the maximum it’s capable of reaching in this case) reachable poses for each roll angle?
for orientationIdx = 1:size(orientationsToTest,1)
for rollIdx = 1:numRollAngles

orientationsToTest(:,3) = rollAngles(rollIdx);
currentOrientation = orientationsToTest(orientationIdx,:);

targetPose = constraintPoseTarget(gripper);
targetPose.ReferenceBody = bodyName; %reference body
targetPose.TargetTransform = trvec2tform([0 0 0]) * eul2tform(currentOrientation,"XYZ");

[qWaypoints(2,:),solutionInfo] = gik_Pick(q0,targetPose);

end
end matlab MATLAB Answers — New Questions

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