Hello,

I have a GigE IDS camera. How can I connect it to MATLAB?

Is there a work around without using IMAQ toolbox?

THANKS!Hello,

I have a GigE IDS camera. How can I connect it to MATLAB?

Is there a work around without using IMAQ toolbox?

THANKS! Hello,

I have a GigE IDS camera. How can I connect it to MATLAB?

Is there a work around without using IMAQ toolbox?

THANKS! ids camera MATLAB Answers — New Questions

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I have an variant Subsystem. For the condition I would like to use and simulink.signal.

Variant1 = Simulink.Variant(‘ _simulink.Signal_==0’);

Variant2 = Simulink.Variant(‘ _simulink.Signal_==1’);

Is that possible?

Best regards

JanI have an variant Subsystem. For the condition I would like to use and simulink.signal.

Variant1 = Simulink.Variant(‘ _simulink.Signal_==0’);

Variant2 = Simulink.Variant(‘ _simulink.Signal_==1’);

Is that possible?

Best regards

Jan I have an variant Subsystem. For the condition I would like to use and simulink.signal.

Variant1 = Simulink.Variant(‘ _simulink.Signal_==0’);

Variant2 = Simulink.Variant(‘ _simulink.Signal_==1’);

Is that possible?

Best regards

Jan variant system, simulink.signal MATLAB Answers — New Questions

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In the PBPK model established using simbiology, the value of the parameter is not changed, and only the unit of the parameter is changed. For example, the 12 nanogram / day is changed to 12 nanogram / hour. Why does the output result not change ? The parameter values and units are modified together, such as 24 nanogram / day to 1 nanogram / hour, but the output results are changed ?In the PBPK model established using simbiology, the value of the parameter is not changed, and only the unit of the parameter is changed. For example, the 12 nanogram / day is changed to 12 nanogram / hour. Why does the output result not change ? The parameter values and units are modified together, such as 24 nanogram / day to 1 nanogram / hour, but the output results are changed ? In the PBPK model established using simbiology, the value of the parameter is not changed, and only the unit of the parameter is changed. For example, the 12 nanogram / day is changed to 12 nanogram / hour. Why does the output result not change ? The parameter values and units are modified together, such as 24 nanogram / day to 1 nanogram / hour, but the output results are changed ? simbiology, pbpk MATLAB Answers — New Questions

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Hi Matlab Family.
I have to deal with this trouble with my code.
I have a matrix and i need to connect the points in every row. However, when there is a blank between two points ( "blank distance" >1), the code will skip the blank and continue to the end. It is quite easy to solve if i use my code below, draw point to point.

v = [1 2 3 4 5 8 9 10 20 21 22 30 31 32];
c = [1];
figure()
[QQ,KK]=size(v);
s=1;
for n =1:KK-2;
if v(n+1)- v(n)== 1;

x= [(v(n)),(v(n+1))];
y= [(c(1)),(c(1))];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

elseif v(n+1) – v(n)> 1;

x= [v(n+1),v(n+2)];
y= [c(1),c(1)];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n_’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

end
end
The problem is that the code becomes very slow and when the number of rows increases, the point coordinate files that are extracted from the code are too many. So please help to optimize the code by connecting a point to the furthest point as it can while ignoring the middle points. Thanks so much! Have a good day.Hi Matlab Family.
I have to deal with this trouble with my code.
I have a matrix and i need to connect the points in every row. However, when there is a blank between two points ( "blank distance" >1), the code will skip the blank and continue to the end. It is quite easy to solve if i use my code below, draw point to point.

v = [1 2 3 4 5 8 9 10 20 21 22 30 31 32];
c = [1];
figure()
[QQ,KK]=size(v);
s=1;
for n =1:KK-2;
if v(n+1)- v(n)== 1;

x= [(v(n)),(v(n+1))];
y= [(c(1)),(c(1))];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

elseif v(n+1) – v(n)> 1;

x= [v(n+1),v(n+2)];
y= [c(1),c(1)];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n_’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

end
end
The problem is that the code becomes very slow and when the number of rows increases, the point coordinate files that are extracted from the code are too many. So please help to optimize the code by connecting a point to the furthest point as it can while ignoring the middle points. Thanks so much! Have a good day. Hi Matlab Family.
I have to deal with this trouble with my code.
I have a matrix and i need to connect the points in every row. However, when there is a blank between two points ( "blank distance" >1), the code will skip the blank and continue to the end. It is quite easy to solve if i use my code below, draw point to point.

v = [1 2 3 4 5 8 9 10 20 21 22 30 31 32];
c = [1];
figure()
[QQ,KK]=size(v);
s=1;
for n =1:KK-2;
if v(n+1)- v(n)== 1;

x= [(v(n)),(v(n+1))];
y= [(c(1)),(c(1))];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

elseif v(n+1) – v(n)> 1;

x= [v(n+1),v(n+2)];
y= [c(1),c(1)];
%data1xy=[x’ y’];
plot(x.*s,y.*s,’k’)
axis square
ylim([0 2])
xlim([0 35])
%dlmwrite([‘n_’,num2str(n),’.txt’],data1xy,’delimiter’,’t’);
hold on

end
end
The problem is that the code becomes very slow and when the number of rows increases, the point coordinate files that are extracted from the code are too many. So please help to optimize the code by connecting a point to the furthest point as it can while ignoring the middle points. Thanks so much! Have a good day. matlab, plot, point, matrix, optimize MATLAB Answers — New Questions

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Is reinforcement learning toolbox available in 1 month trial version of Matlab?Is reinforcement learning toolbox available in 1 month trial version of Matlab? Is reinforcement learning toolbox available in 1 month trial version of Matlab? 1 month trial, rl toolbox MATLAB Answers — New Questions

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Hi, I’m a bit confused with how Percent contrast is calculated within Imaging software (eg 0% to 100%). This may be more a mathematical question than a MATLAB question, but I’ll post the code. I have an matrix image "Im" let’s say [1024 1024] with various intensity values. I understand a subset of intensity values is stretched to the desired output range, let’s assume linearly, to change contrast. But what in the world does a "percentage" mean? 50% on most programs denotes no change in contrast. Contrast stretching is given by the following equation (which is a pixel operation)

Im_new = a.*(Im – Imid)+Imid

(brightness has been taken out of this equation). This is how I think it is performed in most imaging softwares, where a is some coefficient that should be

a = (highestIntensityOutput – lowestIntensityOutput)/(highestIntensityInitial-lowestIntensityInitial).

If a>1, some percentage of histogram above and below certain mid-range intensity values is threshholded, but I may be wrong.

Here is my code for adjusting contrast display manually: (Im is for original image)

%% Create and Show histogram
vec = I(:);
minn =min(vec);
maxx =max(vec);
nbins = maxx-minn;
edges = linspace(minn,maxx,nbins);
hist_c = histcounts(vec,nbins);
% bar(edges(1:nbins), hist_c); hold on; % if want bar plot
plot(edges(1:nbins), hist_c); %easier to work with a plot

Now let’s say you have chosen to use a subset of the intensity values in the image and have selected loValue and hiValue as the range for your intensity values. Then we find the midpoint of this range for our contrast calculation (Note: this may be either wrong, or clunky).

%% calculate midpoint intensity within desired intensity range
lo = abs(edges-loValue);
hi = abs(edges-hiValue);
[~, i] = sort(lo);
[~,j]=sort(hi);
mid = round((j(1)-i(1))/2)+i(1);
midI = edges(mid);

Now we have the mid-Intensity value about which we will adjust the contrast.
For the desired percent <50% contrast, I would assume the following (and this is where I might be horribly wrong), where cPer is "percent contrast". Note, this is only for percent contrast <50%.

a = (cPer/100)*2;
Ig = a.*(I-midI)+midI; %calculate new image Ig
Ig(Ig<loValue) = loValue; %threshhold with desired min/max intensity values permitted
Ig(Ig>hiValue) = hiValue;

Is this correct? Is this how the "percent contrast" is calculated below 50% (I will make another post for above 50%). Comparison to the software tells me no. What I essentially did was map 0 (%) to 50(%) to values from 0 to 1 for the "a" stretch coefficient, which is what I assumed the software was doing. Sorry if this is such a confusing question, I’m probably making it 50x more complicated than it actually is.Hi, I’m a bit confused with how Percent contrast is calculated within Imaging software (eg 0% to 100%). This may be more a mathematical question than a MATLAB question, but I’ll post the code. I have an matrix image "Im" let’s say [1024 1024] with various intensity values. I understand a subset of intensity values is stretched to the desired output range, let’s assume linearly, to change contrast. But what in the world does a "percentage" mean? 50% on most programs denotes no change in contrast. Contrast stretching is given by the following equation (which is a pixel operation)

Im_new = a.*(Im – Imid)+Imid

(brightness has been taken out of this equation). This is how I think it is performed in most imaging softwares, where a is some coefficient that should be

a = (highestIntensityOutput – lowestIntensityOutput)/(highestIntensityInitial-lowestIntensityInitial).

If a>1, some percentage of histogram above and below certain mid-range intensity values is threshholded, but I may be wrong.

Here is my code for adjusting contrast display manually: (Im is for original image)

%% Create and Show histogram
vec = I(:);
minn =min(vec);
maxx =max(vec);
nbins = maxx-minn;
edges = linspace(minn,maxx,nbins);
hist_c = histcounts(vec,nbins);
% bar(edges(1:nbins), hist_c); hold on; % if want bar plot
plot(edges(1:nbins), hist_c); %easier to work with a plot

Now let’s say you have chosen to use a subset of the intensity values in the image and have selected loValue and hiValue as the range for your intensity values. Then we find the midpoint of this range for our contrast calculation (Note: this may be either wrong, or clunky).

%% calculate midpoint intensity within desired intensity range
lo = abs(edges-loValue);
hi = abs(edges-hiValue);
[~, i] = sort(lo);
[~,j]=sort(hi);
mid = round((j(1)-i(1))/2)+i(1);
midI = edges(mid);

Now we have the mid-Intensity value about which we will adjust the contrast.
For the desired percent <50% contrast, I would assume the following (and this is where I might be horribly wrong), where cPer is "percent contrast". Note, this is only for percent contrast <50%.

a = (cPer/100)*2;
Ig = a.*(I-midI)+midI; %calculate new image Ig
Ig(Ig<loValue) = loValue; %threshhold with desired min/max intensity values permitted
Ig(Ig>hiValue) = hiValue;

Is this correct? Is this how the "percent contrast" is calculated below 50% (I will make another post for above 50%). Comparison to the software tells me no. What I essentially did was map 0 (%) to 50(%) to values from 0 to 1 for the "a" stretch coefficient, which is what I assumed the software was doing. Sorry if this is such a confusing question, I’m probably making it 50x more complicated than it actually is. Hi, I’m a bit confused with how Percent contrast is calculated within Imaging software (eg 0% to 100%). This may be more a mathematical question than a MATLAB question, but I’ll post the code. I have an matrix image "Im" let’s say [1024 1024] with various intensity values. I understand a subset of intensity values is stretched to the desired output range, let’s assume linearly, to change contrast. But what in the world does a "percentage" mean? 50% on most programs denotes no change in contrast. Contrast stretching is given by the following equation (which is a pixel operation)

Im_new = a.*(Im – Imid)+Imid

(brightness has been taken out of this equation). This is how I think it is performed in most imaging softwares, where a is some coefficient that should be

a = (highestIntensityOutput – lowestIntensityOutput)/(highestIntensityInitial-lowestIntensityInitial).

If a>1, some percentage of histogram above and below certain mid-range intensity values is threshholded, but I may be wrong.

Here is my code for adjusting contrast display manually: (Im is for original image)

%% Create and Show histogram
vec = I(:);
minn =min(vec);
maxx =max(vec);
nbins = maxx-minn;
edges = linspace(minn,maxx,nbins);
hist_c = histcounts(vec,nbins);
% bar(edges(1:nbins), hist_c); hold on; % if want bar plot
plot(edges(1:nbins), hist_c); %easier to work with a plot

Now let’s say you have chosen to use a subset of the intensity values in the image and have selected loValue and hiValue as the range for your intensity values. Then we find the midpoint of this range for our contrast calculation (Note: this may be either wrong, or clunky).

%% calculate midpoint intensity within desired intensity range
lo = abs(edges-loValue);
hi = abs(edges-hiValue);
[~, i] = sort(lo);
[~,j]=sort(hi);
mid = round((j(1)-i(1))/2)+i(1);
midI = edges(mid);

Now we have the mid-Intensity value about which we will adjust the contrast.
For the desired percent <50% contrast, I would assume the following (and this is where I might be horribly wrong), where cPer is "percent contrast". Note, this is only for percent contrast <50%.

a = (cPer/100)*2;
Ig = a.*(I-midI)+midI; %calculate new image Ig
Ig(Ig<loValue) = loValue; %threshhold with desired min/max intensity values permitted
Ig(Ig>hiValue) = hiValue;

Is this correct? Is this how the "percent contrast" is calculated below 50% (I will make another post for above 50%). Comparison to the software tells me no. What I essentially did was map 0 (%) to 50(%) to values from 0 to 1 for the "a" stretch coefficient, which is what I assumed the software was doing. Sorry if this is such a confusing question, I’m probably making it 50x more complicated than it actually is. adjusting contrast of image; percent contrast, contrast MATLAB Answers — New Questions

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Hi does anyone know why the blocks show color after running the simulation? and how to set this? I want to link this simulink to my python code. Any recommendations and reply will be appreciate.Hi does anyone know why the blocks show color after running the simulation? and how to set this? I want to link this simulink to my python code. Any recommendations and reply will be appreciate. Hi does anyone know why the blocks show color after running the simulation? and how to set this? I want to link this simulink to my python code. Any recommendations and reply will be appreciate. simulink, python MATLAB Answers — New Questions

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How to display the image of a scope in simulink in real time on matlab app designer?How to display the image of a scope in simulink in real time on matlab app designer? How to display the image of a scope in simulink in real time on matlab app designer? app designer, simulink MATLAB Answers — New Questions

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Currently I have this code where I have 7 predictors Age, Weight, …MaxPulse where Oxygen is the response variable

which gives the following output

However I want to modify the code such that in place of Var1, Var2, Var3, ….Var7 I have the predictors Intercept, Age, Weight, ….,MaxPulse.Currently I have this code where I have 7 predictors Age, Weight, …MaxPulse where Oxygen is the response variable

which gives the following output

However I want to modify the code such that in place of Var1, Var2, Var3, ….Var7 I have the predictors Intercept, Age, Weight, ….,MaxPulse. Currently I have this code where I have 7 predictors Age, Weight, …MaxPulse where Oxygen is the response variable

which gives the following output

However I want to modify the code such that in place of Var1, Var2, Var3, ….Var7 I have the predictors Intercept, Age, Weight, ….,MaxPulse. collin test MATLAB Answers — New Questions

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load_demand=readtable("Demand_timeseries_1hourResolution.xlsx");
TR=table2timetable(load_demand);
Time=TR({’05-05-2020′,’05-06-2020 00:00:00′},:);
T = timetable2table(Time)
x=T{2:end,1}
y=T{2:end,3}
plot(x,y)
I am trying to plot my timetable, but it will only plot a single point for it. So instead of plotting the whole data series for ‘Time’ it only plots for the first point. I tried converting it to an array but that didn’t work out too well. Hopefully somebody can help meload_demand=readtable("Demand_timeseries_1hourResolution.xlsx");
TR=table2timetable(load_demand);
Time=TR({’05-05-2020′,’05-06-2020 00:00:00′},:);
T = timetable2table(Time)
x=T{2:end,1}
y=T{2:end,3}
plot(x,y)
I am trying to plot my timetable, but it will only plot a single point for it. So instead of plotting the whole data series for ‘Time’ it only plots for the first point. I tried converting it to an array but that didn’t work out too well. Hopefully somebody can help me load_demand=readtable("Demand_timeseries_1hourResolution.xlsx");
TR=table2timetable(load_demand);
Time=TR({’05-05-2020′,’05-06-2020 00:00:00′},:);
T = timetable2table(Time)
x=T{2:end,1}
y=T{2:end,3}
plot(x,y)
I am trying to plot my timetable, but it will only plot a single point for it. So instead of plotting the whole data series for ‘Time’ it only plots for the first point. I tried converting it to an array but that didn’t work out too well. Hopefully somebody can help me timetable, plotting MATLAB Answers — New Questions

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