Hi, basically i’m trying to write a code to compare the values that i have on a table with a certain range and give it a value

if Accel >= 0.28 & Accel < 2.1 this is equal to number 1
if Accel >= 2.11 & Accel < 3.63 is equal to number 2
and then with both values use it to create a map.Hi, basically i’m trying to write a code to compare the values that i have on a table with a certain range and give it a value

if Accel >= 0.28 & Accel < 2.1 this is equal to number 1
if Accel >= 2.11 & Accel < 3.63 is equal to number 2
and then with both values use it to create a map. Hi, basically i’m trying to write a code to compare the values that i have on a table with a certain range and give it a value

if Accel >= 0.28 & Accel < 2.1 this is equal to number 1
if Accel >= 2.11 & Accel < 3.63 is equal to number 2
and then with both values use it to create a map. ds map MATLAB Answers — New Questions

​

Suppose a model is a dc dc converter with intermediate ac conversion means the system is dc-ac-dc. for that inverter we generally use switches with high frequency. now its output is connected to transformer for boosting. now the question is the output of inverter is of 100khz (supposed) & is fed to transformer. what is the frequency of transformer to be kept.
As of this a hf transformer is required. So how to model a hf transformer in simulink.
can anyone address this issue with step by step procedureSuppose a model is a dc dc converter with intermediate ac conversion means the system is dc-ac-dc. for that inverter we generally use switches with high frequency. now its output is connected to transformer for boosting. now the question is the output of inverter is of 100khz (supposed) & is fed to transformer. what is the frequency of transformer to be kept.
As of this a hf transformer is required. So how to model a hf transformer in simulink.
can anyone address this issue with step by step procedure Suppose a model is a dc dc converter with intermediate ac conversion means the system is dc-ac-dc. for that inverter we generally use switches with high frequency. now its output is connected to transformer for boosting. now the question is the output of inverter is of 100khz (supposed) & is fed to transformer. what is the frequency of transformer to be kept.
As of this a hf transformer is required. So how to model a hf transformer in simulink.
can anyone address this issue with step by step procedure hf transformer, dc dc converter MATLAB Answers — New Questions

​

I have modelled a UAV launcher based on Alexander Khrulev’s paper "Analysis of Pneumatic UAV Launcher Parameters" 2023, which is an open-source paper available at ScienceDirect. I am getting different errors, but the most concerning is that my temperature drops to 0K during working, leading to errors as well as unrealistic behavior. The system consists of 4 differential equations which are tightly coupled, so I am having trouble locating exactly where the problem is. I suspect the problem is in gas dynamics modelling, especially in the intermediate "phi" and "leakage flow rate dm/dt" modelling in the pressure subsystem. I have attached the paper, my workspace as well as my Simulink model in case someone wants to have a look or guide me through this problem. I will be most thankful.I have modelled a UAV launcher based on Alexander Khrulev’s paper "Analysis of Pneumatic UAV Launcher Parameters" 2023, which is an open-source paper available at ScienceDirect. I am getting different errors, but the most concerning is that my temperature drops to 0K during working, leading to errors as well as unrealistic behavior. The system consists of 4 differential equations which are tightly coupled, so I am having trouble locating exactly where the problem is. I suspect the problem is in gas dynamics modelling, especially in the intermediate "phi" and "leakage flow rate dm/dt" modelling in the pressure subsystem. I have attached the paper, my workspace as well as my Simulink model in case someone wants to have a look or guide me through this problem. I will be most thankful. I have modelled a UAV launcher based on Alexander Khrulev’s paper "Analysis of Pneumatic UAV Launcher Parameters" 2023, which is an open-source paper available at ScienceDirect. I am getting different errors, but the most concerning is that my temperature drops to 0K during working, leading to errors as well as unrealistic behavior. The system consists of 4 differential equations which are tightly coupled, so I am having trouble locating exactly where the problem is. I suspect the problem is in gas dynamics modelling, especially in the intermediate "phi" and "leakage flow rate dm/dt" modelling in the pressure subsystem. I have attached the paper, my workspace as well as my Simulink model in case someone wants to have a look or guide me through this problem. I will be most thankful. simulink, matlab, mathematical modelling MATLAB Answers — New Questions

​

I’m trying to simulate a plant with step input. This plant have two inputs and two outputs each input.
When i use ‘step’ command with MATLAB i’m getting 4 plots and that’s what i want.

But in simulink i can’t get 4 plots im getting just two.

and i’m using these simulink model;

How can get fix it ?
ThanksI’m trying to simulate a plant with step input. This plant have two inputs and two outputs each input.
When i use ‘step’ command with MATLAB i’m getting 4 plots and that’s what i want.

But in simulink i can’t get 4 plots im getting just two.

and i’m using these simulink model;

How can get fix it ?
Thanks I’m trying to simulate a plant with step input. This plant have two inputs and two outputs each input.
When i use ‘step’ command with MATLAB i’m getting 4 plots and that’s what i want.

But in simulink i can’t get 4 plots im getting just two.

and i’m using these simulink model;

How can get fix it ?
Thanks simulink, matlab, mimo MATLAB Answers — New Questions

​

Right now the only way I know how to open matlab is opening terminal and type
/usr/local/MATLAB/R2024b/bin/matlab
Is there any other alternative that is easier, more straightforward?Right now the only way I know how to open matlab is opening terminal and type
/usr/local/MATLAB/R2024b/bin/matlab
Is there any other alternative that is easier, more straightforward? Right now the only way I know how to open matlab is opening terminal and type
/usr/local/MATLAB/R2024b/bin/matlab
Is there any other alternative that is easier, more straightforward? installation, linux MATLAB Answers — New Questions

​

Hello everybody,
I am starting with Matlab to solve a system of 2 differential equations, second order.
My code is below. It works, but the output is totally wrong.
This code is something taken on matlab help center and adapted to my problem, to help me start.
I have written things in the code "#comment " where it’s not clear to me.
Your help would be very helpful to me.
Thanks a lot in advance.

clear all;
close all;

syms x(t) y(t)

%% Constants
Cd = 0,45 ;% drag coef aircraft [-]
Af = 2 ;% reference area aircraft [-]
m = 10 ;% total mass aircraft [kg]
g = 9.81 ;% acc° of gravity [m/s2]
Teta = 85 ;% launch angle [deg]
V0 = 83 ;% launch velocity [m/s]
rho_Air = 1,2 ;% air density [kg/m3]
t0 = 0; ;% time interval, initial t [s]
tf = 5400 ;% time interval, final t [s]

%% Initial Conditions
x_to = 0 ;% x(t=0)= 0 [m]
dx_t0 = V0*cosd(Teta) ;% x'(t=0)= V0*cosd(Teta) [m/s]
y_to = 0 ;% y'(t=0)= 0 [m]
dy_t0 = V0*sind(Teta) ;% x(t=0)= 0 [m/s]
y0 = [x_to dx_t0 y_to dy_t0 ] ;% vector initial conditions

%% System differential equations to be solved
eq1 = diff(x,2) == -( (Cd*Af*rho_Air)/(2*m) ) * diff(x,1) * (x^2 + y^2)^(1/2)
eq2 = diff(y,2) == – g – ( (Cd*Af*rho_Air)/(2*m) ) * diff(y,1) * ( (diff(x,1))^2 + (diff(y,1))^2 )^(1/2)

%% variables
vars = [x(t); y(t)]

V = odeToVectorField([eq1,eq2])
M = matlabFunction(V,’vars’, {‘t’,’Y’});
% #comment: why the variable x doesn’t appear here ? as I solve on x(t) and
% y(t) -> in V I call eq1 and eq2, then it’s x(t) and y(t)

interval = [t0 tf]; %time interval

ySol = ode45(M,interval,y0);
% #comment: vector y0 containts the boundary conditions for both x and y.
% As here I solve on y, why do we have boundary conditions in x as well ?
% is the function ode capable to make the difference in between boudady
% conditions for x and y ?
tValues = linspace(interval(1),interval(2),1000);
yValues = deval(ySol,tValues,1); %number 1 denotes first position likewise you can mention 2 to 6 for the next 5 positions

plot(tValues,yValues) %if you want to plot position vs time just swap here

% #comment: I need to solve on x as well
% thank you !Hello everybody,
I am starting with Matlab to solve a system of 2 differential equations, second order.
My code is below. It works, but the output is totally wrong.
This code is something taken on matlab help center and adapted to my problem, to help me start.
I have written things in the code "#comment " where it’s not clear to me.
Your help would be very helpful to me.
Thanks a lot in advance.

clear all;
close all;

syms x(t) y(t)

%% Constants
Cd = 0,45 ;% drag coef aircraft [-]
Af = 2 ;% reference area aircraft [-]
m = 10 ;% total mass aircraft [kg]
g = 9.81 ;% acc° of gravity [m/s2]
Teta = 85 ;% launch angle [deg]
V0 = 83 ;% launch velocity [m/s]
rho_Air = 1,2 ;% air density [kg/m3]
t0 = 0; ;% time interval, initial t [s]
tf = 5400 ;% time interval, final t [s]

%% Initial Conditions
x_to = 0 ;% x(t=0)= 0 [m]
dx_t0 = V0*cosd(Teta) ;% x'(t=0)= V0*cosd(Teta) [m/s]
y_to = 0 ;% y'(t=0)= 0 [m]
dy_t0 = V0*sind(Teta) ;% x(t=0)= 0 [m/s]
y0 = [x_to dx_t0 y_to dy_t0 ] ;% vector initial conditions

%% System differential equations to be solved
eq1 = diff(x,2) == -( (Cd*Af*rho_Air)/(2*m) ) * diff(x,1) * (x^2 + y^2)^(1/2)
eq2 = diff(y,2) == – g – ( (Cd*Af*rho_Air)/(2*m) ) * diff(y,1) * ( (diff(x,1))^2 + (diff(y,1))^2 )^(1/2)

%% variables
vars = [x(t); y(t)]

V = odeToVectorField([eq1,eq2])
M = matlabFunction(V,’vars’, {‘t’,’Y’});
% #comment: why the variable x doesn’t appear here ? as I solve on x(t) and
% y(t) -> in V I call eq1 and eq2, then it’s x(t) and y(t)

interval = [t0 tf]; %time interval

ySol = ode45(M,interval,y0);
% #comment: vector y0 containts the boundary conditions for both x and y.
% As here I solve on y, why do we have boundary conditions in x as well ?
% is the function ode capable to make the difference in between boudady
% conditions for x and y ?
tValues = linspace(interval(1),interval(2),1000);
yValues = deval(ySol,tValues,1); %number 1 denotes first position likewise you can mention 2 to 6 for the next 5 positions

plot(tValues,yValues) %if you want to plot position vs time just swap here

% #comment: I need to solve on x as well
% thank you ! Hello everybody,
I am starting with Matlab to solve a system of 2 differential equations, second order.
My code is below. It works, but the output is totally wrong.
This code is something taken on matlab help center and adapted to my problem, to help me start.
I have written things in the code "#comment " where it’s not clear to me.
Your help would be very helpful to me.
Thanks a lot in advance.

clear all;
close all;

syms x(t) y(t)

%% Constants
Cd = 0,45 ;% drag coef aircraft [-]
Af = 2 ;% reference area aircraft [-]
m = 10 ;% total mass aircraft [kg]
g = 9.81 ;% acc° of gravity [m/s2]
Teta = 85 ;% launch angle [deg]
V0 = 83 ;% launch velocity [m/s]
rho_Air = 1,2 ;% air density [kg/m3]
t0 = 0; ;% time interval, initial t [s]
tf = 5400 ;% time interval, final t [s]

%% Initial Conditions
x_to = 0 ;% x(t=0)= 0 [m]
dx_t0 = V0*cosd(Teta) ;% x'(t=0)= V0*cosd(Teta) [m/s]
y_to = 0 ;% y'(t=0)= 0 [m]
dy_t0 = V0*sind(Teta) ;% x(t=0)= 0 [m/s]
y0 = [x_to dx_t0 y_to dy_t0 ] ;% vector initial conditions

%% System differential equations to be solved
eq1 = diff(x,2) == -( (Cd*Af*rho_Air)/(2*m) ) * diff(x,1) * (x^2 + y^2)^(1/2)
eq2 = diff(y,2) == – g – ( (Cd*Af*rho_Air)/(2*m) ) * diff(y,1) * ( (diff(x,1))^2 + (diff(y,1))^2 )^(1/2)

%% variables
vars = [x(t); y(t)]

V = odeToVectorField([eq1,eq2])
M = matlabFunction(V,’vars’, {‘t’,’Y’});
% #comment: why the variable x doesn’t appear here ? as I solve on x(t) and
% y(t) -> in V I call eq1 and eq2, then it’s x(t) and y(t)

interval = [t0 tf]; %time interval

ySol = ode45(M,interval,y0);
% #comment: vector y0 containts the boundary conditions for both x and y.
% As here I solve on y, why do we have boundary conditions in x as well ?
% is the function ode capable to make the difference in between boudady
% conditions for x and y ?
tValues = linspace(interval(1),interval(2),1000);
yValues = deval(ySol,tValues,1); %number 1 denotes first position likewise you can mention 2 to 6 for the next 5 positions

plot(tValues,yValues) %if you want to plot position vs time just swap here

% #comment: I need to solve on x as well
% thank you ! solving ode, ode45, system 2 ode second order MATLAB Answers — New Questions

​

Hi all,
I’m trying to make a for loop to process some EEG data. The final output is (1×96) for each participant which is finally working great, however, now I’m having issues writing the data/ looping through the participants. I’ve attached what the output looks like for one particpant as that is how far I can get. Below is what I’m trying to use unnsuccessfully. Any help is greatly appreciated!

SubjectNum = { ’01-02′ ’01-03′ };

resultsFileName = [fullfile(baseDir, ‘MATLAB_Output’, ‘DIVINE.75results.xlsx’)];

for k = 1:length(SubjectNum)

…. (whole bunch of steps)

RelativePowerResults = table(ID,channelsLabel,relativeDelta2,relativeTheta2,relativeAlpha2,relativeBeta2,relativeGamma2)

% unstack resulting in (1 row with 96 columns)
RelativePowerResults_Wide = unstack(RelativePowerResults,"relative"+["Alpha2","Delta2","Theta2","Beta2","Gamma2"],’channelsLabel’);

if k == 1
% First subject, with variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’, RANGE{k});

else
% For subsequent subjects, write without variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’,RANGE{k}, ‘WriteVariableNames’, false);

endHi all,
I’m trying to make a for loop to process some EEG data. The final output is (1×96) for each participant which is finally working great, however, now I’m having issues writing the data/ looping through the participants. I’ve attached what the output looks like for one particpant as that is how far I can get. Below is what I’m trying to use unnsuccessfully. Any help is greatly appreciated!

SubjectNum = { ’01-02′ ’01-03′ };

resultsFileName = [fullfile(baseDir, ‘MATLAB_Output’, ‘DIVINE.75results.xlsx’)];

for k = 1:length(SubjectNum)

…. (whole bunch of steps)

RelativePowerResults = table(ID,channelsLabel,relativeDelta2,relativeTheta2,relativeAlpha2,relativeBeta2,relativeGamma2)

% unstack resulting in (1 row with 96 columns)
RelativePowerResults_Wide = unstack(RelativePowerResults,"relative"+["Alpha2","Delta2","Theta2","Beta2","Gamma2"],’channelsLabel’);

if k == 1
% First subject, with variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’, RANGE{k});

else
% For subsequent subjects, write without variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’,RANGE{k}, ‘WriteVariableNames’, false);

end Hi all,
I’m trying to make a for loop to process some EEG data. The final output is (1×96) for each participant which is finally working great, however, now I’m having issues writing the data/ looping through the participants. I’ve attached what the output looks like for one particpant as that is how far I can get. Below is what I’m trying to use unnsuccessfully. Any help is greatly appreciated!

SubjectNum = { ’01-02′ ’01-03′ };

resultsFileName = [fullfile(baseDir, ‘MATLAB_Output’, ‘DIVINE.75results.xlsx’)];

for k = 1:length(SubjectNum)

…. (whole bunch of steps)

RelativePowerResults = table(ID,channelsLabel,relativeDelta2,relativeTheta2,relativeAlpha2,relativeBeta2,relativeGamma2)

% unstack resulting in (1 row with 96 columns)
RelativePowerResults_Wide = unstack(RelativePowerResults,"relative"+["Alpha2","Delta2","Theta2","Beta2","Gamma2"],’channelsLabel’);

if k == 1
% First subject, with variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’, RANGE{k});

else
% For subsequent subjects, write without variable names
writetable(RelativePowerResults_Wide, resultsFileName, ‘Sheet’, 1, ‘Range’,RANGE{k}, ‘WriteVariableNames’, false);

end for loop, eeg MATLAB Answers — New Questions

​

Hello. I designed the DTMF decoder function based on goertzel algorithm. When I put input with 123-456-7890_40 and 404-894-2714_30, The function prints out with output with 123-456-7890 and 404-894-2714. However, when I put input with 123-555-4709_25, output is ,
Invalid number or insufficient digits
‘. I tried to fix the code, but I am not sure what should I do. Could you please let me know what should I add or edit? Thanks.Hello. I designed the DTMF decoder function based on goertzel algorithm. When I put input with 123-456-7890_40 and 404-894-2714_30, The function prints out with output with 123-456-7890 and 404-894-2714. However, when I put input with 123-555-4709_25, output is ,
Invalid number or insufficient digits
‘. I tried to fix the code, but I am not sure what should I do. Could you please let me know what should I add or edit? Thanks. Hello. I designed the DTMF decoder function based on goertzel algorithm. When I put input with 123-456-7890_40 and 404-894-2714_30, The function prints out with output with 123-456-7890 and 404-894-2714. However, when I put input with 123-555-4709_25, output is ,
Invalid number or insufficient digits
‘. I tried to fix the code, but I am not sure what should I do. Could you please let me know what should I add or edit? Thanks. dtmf, goertzel MATLAB Answers — New Questions

​

Hello,
I am working with multiple plots in MATLAB and I would like to use three different "y" axis for the different axes within a single figure. I have no problem using two "y" axes with yyaxis, I can’t include that function in my for loop (this loop reads the data from each column to be plotted from the Excel file). I read about a function called addaxis, but I don’t know how to use it.
Also, I would like the plots to have different colors for each "y" axis, since MATLAB defaults to red for Y1 and blue for Y2. Any ideas on how to achieve this?
Any suggestions would be greatly appreciated!
Best Regards!
Lucas.

clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB’, ‘NumberTitle’,’off’, ‘Color’, ‘w’);
hold on;
grid on;

for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 100
yyaxis right
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘r’);
end
if max(y_i) > 100
yyaxis left
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end

title(‘Gráfica Interactiva’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’;
axis tight;
ax.XAxis.SecondaryLabelFormatMode = ‘manual’;
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]);
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g;

This code is working but It can only plot 2 "y" axes; but if I try the addaxis in order to implement the third "y" axis, my code It´s not working:
clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB DQA’, ‘NumberTitle’,’off’, ‘Color’, ‘w’); %Preguntar si NumberTitle on o off
hold on;
grid on;
for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 20
addaxis(t, y_i, [0 20],’LineWidth’,1.3,’Color’,’b’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, ‘SeriesIndex’, 1, ‘Marker’, ‘.’, ‘MarkerSize’, 1, ‘Color’, ‘green’);
end
if 20 < max(y_i) && max(y_i) <= 100
addaxis(t, y_i, [0 100], ‘LineWidth’,1.3,’Color’,’r’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘red’); %[‘Y_’ num2str(i-1)]
end
if max(y_i) > 100
addaxis(t, y_i, [0 max(y_i)],’LineWidth’,1.3,’Color’,’g’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end
title(‘Gráfica Interactiva DiagnóstiQA’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’; %QUITAR ESTA LINEA DE CODIGO SI PREFERIMOS FORMATO TEMPORAL mm:ss
axis tight; %INSTRUCCIONES: tight, tickaligned o padded %en vez de axis puedo usar xlim o ylim si solo quiero ajustar 1 de los ejes
ax.XAxis.SecondaryLabelFormatMode = ‘manual’; %ESTO SOLUCIONA EL 31 -1!
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]); %El segundo numero es el margen desde el borde inferior de la ventana y el cuarto número es la altura de los ejes
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g;Hello,
I am working with multiple plots in MATLAB and I would like to use three different "y" axis for the different axes within a single figure. I have no problem using two "y" axes with yyaxis, I can’t include that function in my for loop (this loop reads the data from each column to be plotted from the Excel file). I read about a function called addaxis, but I don’t know how to use it.
Also, I would like the plots to have different colors for each "y" axis, since MATLAB defaults to red for Y1 and blue for Y2. Any ideas on how to achieve this?
Any suggestions would be greatly appreciated!
Best Regards!
Lucas.

clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB’, ‘NumberTitle’,’off’, ‘Color’, ‘w’);
hold on;
grid on;

for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 100
yyaxis right
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘r’);
end
if max(y_i) > 100
yyaxis left
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end

title(‘Gráfica Interactiva’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’;
axis tight;
ax.XAxis.SecondaryLabelFormatMode = ‘manual’;
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]);
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g;

This code is working but It can only plot 2 "y" axes; but if I try the addaxis in order to implement the third "y" axis, my code It´s not working:
clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB DQA’, ‘NumberTitle’,’off’, ‘Color’, ‘w’); %Preguntar si NumberTitle on o off
hold on;
grid on;
for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 20
addaxis(t, y_i, [0 20],’LineWidth’,1.3,’Color’,’b’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, ‘SeriesIndex’, 1, ‘Marker’, ‘.’, ‘MarkerSize’, 1, ‘Color’, ‘green’);
end
if 20 < max(y_i) && max(y_i) <= 100
addaxis(t, y_i, [0 100], ‘LineWidth’,1.3,’Color’,’r’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘red’); %[‘Y_’ num2str(i-1)]
end
if max(y_i) > 100
addaxis(t, y_i, [0 max(y_i)],’LineWidth’,1.3,’Color’,’g’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end
title(‘Gráfica Interactiva DiagnóstiQA’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’; %QUITAR ESTA LINEA DE CODIGO SI PREFERIMOS FORMATO TEMPORAL mm:ss
axis tight; %INSTRUCCIONES: tight, tickaligned o padded %en vez de axis puedo usar xlim o ylim si solo quiero ajustar 1 de los ejes
ax.XAxis.SecondaryLabelFormatMode = ‘manual’; %ESTO SOLUCIONA EL 31 -1!
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]); %El segundo numero es el margen desde el borde inferior de la ventana y el cuarto número es la altura de los ejes
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g; Hello,
I am working with multiple plots in MATLAB and I would like to use three different "y" axis for the different axes within a single figure. I have no problem using two "y" axes with yyaxis, I can’t include that function in my for loop (this loop reads the data from each column to be plotted from the Excel file). I read about a function called addaxis, but I don’t know how to use it.
Also, I would like the plots to have different colors for each "y" axis, since MATLAB defaults to red for Y1 and blue for Y2. Any ideas on how to achieve this?
Any suggestions would be greatly appreciated!
Best Regards!
Lucas.

clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB’, ‘NumberTitle’,’off’, ‘Color’, ‘w’);
hold on;
grid on;

for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 100
yyaxis right
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘r’);
end
if max(y_i) > 100
yyaxis left
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end

title(‘Gráfica Interactiva’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’;
axis tight;
ax.XAxis.SecondaryLabelFormatMode = ‘manual’;
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]);
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g;

This code is working but It can only plot 2 "y" axes; but if I try the addaxis in order to implement the third "y" axis, my code It´s not working:
clc;
clear;
nombre_excel = ‘Hoja_fuente.xlsx’;
datos = readtable (nombre_excel);
encabezados = datos.Properties.VariableNames(2:end);
encabezados = strrep(encabezados, ‘_’, ‘ ‘);
t = datetime(datos.Tiempo,’ConvertFrom’, ‘datenum’, ‘Format’, ‘HH:mm:ss’); %Si da probemas: sustituir ‘datenum’ por ‘excel’
numero_columnas=size(datos,2) – 1;
fig = figure(‘Name’,’Representación interactiva MATLAB DQA’, ‘NumberTitle’,’off’, ‘Color’, ‘w’); %Preguntar si NumberTitle on o off
hold on;
grid on;
for i=2:numero_columnas+1
y_i = datos(:,i);
y_i = table2array(y_i);
if max(y_i) <= 20
addaxis(t, y_i, [0 20],’LineWidth’,1.3,’Color’,’b’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, ‘SeriesIndex’, 1, ‘Marker’, ‘.’, ‘MarkerSize’, 1, ‘Color’, ‘green’);
end
if 20 < max(y_i) && max(y_i) <= 100
addaxis(t, y_i, [0 100], ‘LineWidth’,1.3,’Color’,’r’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘red’); %[‘Y_’ num2str(i-1)]
end
if max(y_i) > 100
addaxis(t, y_i, [0 max(y_i)],’LineWidth’,1.3,’Color’,’g’)
plot(t, y_i, ‘LineWidth’, 1.5, ‘DisplayName’, encabezados{i-1}, SeriesIndex = 1, marker=’.’, markersize = 1, color = ‘b’); %[‘Y_’ num2str(i-1)]
end
end
title(‘Gráfica Interactiva DiagnóstiQA’);
legend(‘show’);
xlabel(‘Tiempo( hh:mm:ss )’, ‘FontSize’, 12);
%ylabel(encabezados, ‘Rotation’, 0, ‘Color’, ‘b’);
ax=gca;
ax.XAxis.Exponent = 0;
ax.XAxis.TickLabelFormat = ‘HH:mm:ss’; %QUITAR ESTA LINEA DE CODIGO SI PREFERIMOS FORMATO TEMPORAL mm:ss
axis tight; %INSTRUCCIONES: tight, tickaligned o padded %en vez de axis puedo usar xlim o ylim si solo quiero ajustar 1 de los ejes
ax.XAxis.SecondaryLabelFormatMode = ‘manual’; %ESTO SOLUCIONA EL 31 -1!
set(gca, ‘Position’, [0.056770833333333,0.157667386609071,0.894270833333333,0.809935205183586]); %El segundo numero es el margen desde el borde inferior de la ventana y el cuarto número es la altura de los ejes
legend(‘Location’, ‘southoutside’, ‘NumColumns’, 6, ‘Orientation’, ‘horizontal’, ‘NumColumnsMode’,’manual’, ‘Interpreter’,’none’, ‘FontSize’, 8, ‘FontWeight’, ‘bold’, ‘FontName’, ‘Arial Narrow’, ‘box’, ‘on’);
set(legend, ‘IconColumnWidth’, 15, ‘Position’, [0.004678527128273,0.041036717062635,0.988802104021113,0.058815920456996]);
format long g; plot, label MATLAB Answers — New Questions

​

I’m trying to get sprintf to print out a line that says:
‘for event —– stations pass the criteria test=’
where it will list the results for my stations vertically like:

U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and so on. I can’t seem to get it to do this..it keeps combining my stations together something like UUU00452648BBBB….HHHHHZZZZZfffff. I’m looking at the help pages but there are few examples, any suggestions? This is what I’ve written so far:

u=char(files(keep==1));
str1=sprintf(‘for event %s stations passed criteria
test=%fn’,char(dirs(i)),char(u));
disp(str1)

where u=
U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and dirs(i) corresponds to my directories. Any suggestions or help in what I’m doing wrong?

KayleI’m trying to get sprintf to print out a line that says:
‘for event —– stations pass the criteria test=’
where it will list the results for my stations vertically like:

U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and so on. I can’t seem to get it to do this..it keeps combining my stations together something like UUU00452648BBBB….HHHHHZZZZZfffff. I’m looking at the help pages but there are few examples, any suggestions? This is what I’ve written so far:

u=char(files(keep==1));
str1=sprintf(‘for event %s stations passed criteria
test=%fn’,char(dirs(i)),char(u));
disp(str1)

where u=
U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and dirs(i) corresponds to my directories. Any suggestions or help in what I’m doing wrong?

Kayle I’m trying to get sprintf to print out a line that says:
‘for event —– stations pass the criteria test=’
where it will list the results for my stations vertically like:

U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and so on. I can’t seem to get it to do this..it keeps combining my stations together something like UUU00452648BBBB….HHHHHZZZZZfffff. I’m looking at the help pages but there are few examples, any suggestions? This is what I’ve written so far:

u=char(files(keep==1));
str1=sprintf(‘for event %s stations passed criteria
test=%fn’,char(dirs(i)),char(u));
disp(str1)

where u=
U02B.HHZf

U04B.HHZf

U05B.HHZf

U06B.HHZf

and dirs(i) corresponds to my directories. Any suggestions or help in what I’m doing wrong?

Kayle sprintf MATLAB Answers — New Questions

​