I want to hightlight the defect in croppedImage.mat by convHull.mat.
It’s better set transparent.
the size of two figures is same.I want to hightlight the defect in croppedImage.mat by convHull.mat.
It’s better set transparent.
the size of two figures is same. I want to hightlight the defect in croppedImage.mat by convHull.mat.
It’s better set transparent.
the size of two figures is same. highlight area MATLAB Answers — New Questions

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In my regression model I have four(04) input varibales (Al2O3, TiO2, Pressure, Speed) and there are one responce (Surface roughness(Ra)), So I don’t have idea how find optimum vales for four control factors to minimze the Surface roughness.
To develop this model I have done 16 experiments and the predicted values are shon below
Ra
0.064
0.039
0.071
0.238
3.256
3.910
2.786
0.037
3.604
0.043
0.037
0.060
0.049
0.023
0.061
1.113
Developed Regession Model
Ra = 28.66 + 50.01 Al2O3 + 35.80 TiO2 – 6.925 Pressure – 0.4221 Speed – 182.6 Al2O3*Al2O3 – 3.741 TiO2*TiO2 + 0.7566 Pressure*Pressure + 0.001753 Speed*Speed + 8.210 Al2O3*TiO2 – 2.541 Al2O3*Pressure – 0.04987 Al2O3*Speed – 3.373 TiO2*Pressure – 0.2407 TiO2*Speed + 0.03294 Pressure*Speed + 179.8 Al2O3*Al2O3*Al2O3
Can anyone help me to develop the Maltlab code to solve this problem ? thanks for your valuble time spend on thisIn my regression model I have four(04) input varibales (Al2O3, TiO2, Pressure, Speed) and there are one responce (Surface roughness(Ra)), So I don’t have idea how find optimum vales for four control factors to minimze the Surface roughness.
To develop this model I have done 16 experiments and the predicted values are shon below
Ra
0.064
0.039
0.071
0.238
3.256
3.910
2.786
0.037
3.604
0.043
0.037
0.060
0.049
0.023
0.061
1.113
Developed Regession Model
Ra = 28.66 + 50.01 Al2O3 + 35.80 TiO2 – 6.925 Pressure – 0.4221 Speed – 182.6 Al2O3*Al2O3 – 3.741 TiO2*TiO2 + 0.7566 Pressure*Pressure + 0.001753 Speed*Speed + 8.210 Al2O3*TiO2 – 2.541 Al2O3*Pressure – 0.04987 Al2O3*Speed – 3.373 TiO2*Pressure – 0.2407 TiO2*Speed + 0.03294 Pressure*Speed + 179.8 Al2O3*Al2O3*Al2O3
Can anyone help me to develop the Maltlab code to solve this problem ? thanks for your valuble time spend on this In my regression model I have four(04) input varibales (Al2O3, TiO2, Pressure, Speed) and there are one responce (Surface roughness(Ra)), So I don’t have idea how find optimum vales for four control factors to minimze the Surface roughness.
To develop this model I have done 16 experiments and the predicted values are shon below
Ra
0.064
0.039
0.071
0.238
3.256
3.910
2.786
0.037
3.604
0.043
0.037
0.060
0.049
0.023
0.061
1.113
Developed Regession Model
Ra = 28.66 + 50.01 Al2O3 + 35.80 TiO2 – 6.925 Pressure – 0.4221 Speed – 182.6 Al2O3*Al2O3 – 3.741 TiO2*TiO2 + 0.7566 Pressure*Pressure + 0.001753 Speed*Speed + 8.210 Al2O3*TiO2 – 2.541 Al2O3*Pressure – 0.04987 Al2O3*Speed – 3.373 TiO2*Pressure – 0.2407 TiO2*Speed + 0.03294 Pressure*Speed + 179.8 Al2O3*Al2O3*Al2O3
Can anyone help me to develop the Maltlab code to solve this problem ? thanks for your valuble time spend on this fmincon, optimization MATLAB Answers — New Questions

​

I have for example X,Y,Z coordinates of 8 points which form an irregular shape. How can I calculate the volume with in this shape? Eg. coordinates area:

0 0 384,67
0 26,6 385,25
-47,85 26,6 385,9
-47,85 0 385,3
0 0 387,32
0 26,6 387,32
-47,85 26,6 387,32
-47,85 0 387,32I have for example X,Y,Z coordinates of 8 points which form an irregular shape. How can I calculate the volume with in this shape? Eg. coordinates area:

0 0 384,67
0 26,6 385,25
-47,85 26,6 385,9
-47,85 0 385,3
0 0 387,32
0 26,6 387,32
-47,85 26,6 387,32
-47,85 0 387,32 I have for example X,Y,Z coordinates of 8 points which form an irregular shape. How can I calculate the volume with in this shape? Eg. coordinates area:

0 0 384,67
0 26,6 385,25
-47,85 26,6 385,9
-47,85 0 385,3
0 0 387,32
0 26,6 387,32
-47,85 26,6 387,32
-47,85 0 387,32 voleme, convexhul MATLAB Answers — New Questions

​

Hi,I found a microstrip model in the RF Blockset section, but when I placed it in the circuit and ran the simulation, the oscilloscope did not capture any reflection waves(like ADS). Is it because I didn’t set it up correctly, or is this system just unable to simulate reflection waves?Thanks!Hi,I found a microstrip model in the RF Blockset section, but when I placed it in the circuit and ran the simulation, the oscilloscope did not capture any reflection waves(like ADS). Is it because I didn’t set it up correctly, or is this system just unable to simulate reflection waves?Thanks! Hi,I found a microstrip model in the RF Blockset section, but when I placed it in the circuit and ran the simulation, the oscilloscope did not capture any reflection waves(like ADS). Is it because I didn’t set it up correctly, or is this system just unable to simulate reflection waves?Thanks! microstrip line, reflection MATLAB Answers — New Questions

​

Due to the mask, the histogram contains zeros, which is incorrect. How can I remove the zeros from the histogram, or how can I adjust the histogram function to exclude the zeros? This would ensure that the result will not affect the result of the imhistmatch function.
Thank you.Due to the mask, the histogram contains zeros, which is incorrect. How can I remove the zeros from the histogram, or how can I adjust the histogram function to exclude the zeros? This would ensure that the result will not affect the result of the imhistmatch function.
Thank you. Due to the mask, the histogram contains zeros, which is incorrect. How can I remove the zeros from the histogram, or how can I adjust the histogram function to exclude the zeros? This would ensure that the result will not affect the result of the imhistmatch function.
Thank you. histogram, imhistmatchn, matlab, zeros MATLAB Answers — New Questions

​

I am looking for ideas on how to construct a class that generalizes the interface Matlab uses for creating and manipulating complex variables. The general idea is that one could construct a "pets" object by simplying typing:
mypets = 2dogs + 3cats
which would create an object of the pets class.
I can think of a few clunky ways to do this, such as having the constructor parse a string like this:
mypets = pets(‘2dogs + 3cats’).
Another slightly nicer way would be to leave out the parenthesis like this:
pets 2dogs + 3cats
but this still requires an explicit constructor reference. Any ideas anyone?I am looking for ideas on how to construct a class that generalizes the interface Matlab uses for creating and manipulating complex variables. The general idea is that one could construct a "pets" object by simplying typing:
mypets = 2dogs + 3cats
which would create an object of the pets class.
I can think of a few clunky ways to do this, such as having the constructor parse a string like this:
mypets = pets(‘2dogs + 3cats’).
Another slightly nicer way would be to leave out the parenthesis like this:
pets 2dogs + 3cats
but this still requires an explicit constructor reference. Any ideas anyone? I am looking for ideas on how to construct a class that generalizes the interface Matlab uses for creating and manipulating complex variables. The general idea is that one could construct a "pets" object by simplying typing:
mypets = 2dogs + 3cats
which would create an object of the pets class.
I can think of a few clunky ways to do this, such as having the constructor parse a string like this:
mypets = pets(‘2dogs + 3cats’).
Another slightly nicer way would be to leave out the parenthesis like this:
pets 2dogs + 3cats
but this still requires an explicit constructor reference. Any ideas anyone? generalize complex MATLAB Answers — New Questions

​

Hello,
I have some figures that I saved in MATLAB R2024b with New Desktop on my work computer. When I try to open the figure on my home computer using MATLAB R2024b with Old Desktop, it freezes at FigureController.m at the sendACT function. The exact same thing happens with MATLAB Online too. It freezes at the exact same point. However, if I switch to New Desktop on my local computer, I can see the figures again. The figures are not big at all, they are 100kB maximum.
Is there a solution to this?Hello,
I have some figures that I saved in MATLAB R2024b with New Desktop on my work computer. When I try to open the figure on my home computer using MATLAB R2024b with Old Desktop, it freezes at FigureController.m at the sendACT function. The exact same thing happens with MATLAB Online too. It freezes at the exact same point. However, if I switch to New Desktop on my local computer, I can see the figures again. The figures are not big at all, they are 100kB maximum.
Is there a solution to this? Hello,
I have some figures that I saved in MATLAB R2024b with New Desktop on my work computer. When I try to open the figure on my home computer using MATLAB R2024b with Old Desktop, it freezes at FigureController.m at the sendACT function. The exact same thing happens with MATLAB Online too. It freezes at the exact same point. However, if I switch to New Desktop on my local computer, I can see the figures again. The figures are not big at all, they are 100kB maximum.
Is there a solution to this? matlab, figure, matlab gui MATLAB Answers — New Questions

​

Hello all! I am trying to create a simple program that creates a fractal. It is supposed to be putting complex values into an array from the initial conditions and I will plot them later.
My Questions are:
1. What is the correct way to implement an Anonymous Function?
2. What is the best practice in Matlab for a recursion loop?
The answer to question 1 may not be necessary if the answer to 2 does not use Anonymous Functions.

clear all
clc
F = @(z) z^2 + c;
Re = [];
Im = [];
x = 1;
y = 1;
a = 2;
b = 3;
n = 10;
c = x+y*1i;
z0 = a+b*1i;
% Placing values in arrays to be plotted
Re(1,1) = real(z0 + c);
Im(1,1) = imag(z0 + c);
F(z0) = z; % First step of the recursion outside for loop?
% Second values for the array
Re(2,1) = real(z);
Im(2,1) = imag(z);
for h = (3:n) % Begin recursion
F(z) = z;
Re(h,1) = real(z);
Im(h,1) = imag(z);
h = h + 1;
endHello all! I am trying to create a simple program that creates a fractal. It is supposed to be putting complex values into an array from the initial conditions and I will plot them later.
My Questions are:
1. What is the correct way to implement an Anonymous Function?
2. What is the best practice in Matlab for a recursion loop?
The answer to question 1 may not be necessary if the answer to 2 does not use Anonymous Functions.

clear all
clc
F = @(z) z^2 + c;
Re = [];
Im = [];
x = 1;
y = 1;
a = 2;
b = 3;
n = 10;
c = x+y*1i;
z0 = a+b*1i;
% Placing values in arrays to be plotted
Re(1,1) = real(z0 + c);
Im(1,1) = imag(z0 + c);
F(z0) = z; % First step of the recursion outside for loop?
% Second values for the array
Re(2,1) = real(z);
Im(2,1) = imag(z);
for h = (3:n) % Begin recursion
F(z) = z;
Re(h,1) = real(z);
Im(h,1) = imag(z);
h = h + 1;
end Hello all! I am trying to create a simple program that creates a fractal. It is supposed to be putting complex values into an array from the initial conditions and I will plot them later.
My Questions are:
1. What is the correct way to implement an Anonymous Function?
2. What is the best practice in Matlab for a recursion loop?
The answer to question 1 may not be necessary if the answer to 2 does not use Anonymous Functions.

clear all
clc
F = @(z) z^2 + c;
Re = [];
Im = [];
x = 1;
y = 1;
a = 2;
b = 3;
n = 10;
c = x+y*1i;
z0 = a+b*1i;
% Placing values in arrays to be plotted
Re(1,1) = real(z0 + c);
Im(1,1) = imag(z0 + c);
F(z0) = z; % First step of the recursion outside for loop?
% Second values for the array
Re(2,1) = real(z);
Im(2,1) = imag(z);
for h = (3:n) % Begin recursion
F(z) = z;
Re(h,1) = real(z);
Im(h,1) = imag(z);
h = h + 1;
end anonymous function, recursion, fractal MATLAB Answers — New Questions

​

I need the help of people who have excellent talents in calculating using Matlab.
The equations to be implemented through Matlab coding is as follows.

The results to be obtained through this coding is written in "Answer) ~" above.
And, the data related to this problem(or eqution) is below.

I have tried with the following coding but kept getting the same results as the title. I would like to get helpful advice on this part.
I would appreciate it if you could give me a guide on the solution or error cause.
v1 = [393 393 393 393 393 393 393 393 393 393 ; 3850 4340 4760 5320 5740 6160 6580 7140 7980 8960];
v2 = [408 408 408 408 408 408 408 408 408 408 ; 3300 3720 4080 4560 4920 5280 5640 6120 6840 7680];
v3 = [423 423 423 423 423 423 423 423 423 423 ; 2750 3100 3400 3800 4100 4400 4700 5100 5700 6400];

syms B; % parameter Beta
syms BB; % parameter B
syms C;

%————- equation 1 ————-%
a1_v1 = 0;
a1_v2 = 0;
a1_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a1_v1 = N*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a1_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a1_v2 = N*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a1_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a1_v3 = N*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a1_v3;
end

a2_v1 = 0;
a2_v2 = 0;
a2_v3 = 0;

i = 1; % "Stress Lv. 1" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a2_v1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a2_v1;
end

i = 1; % "Stress Lv. 2" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a2_v2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a2_v2;
end

i = 1; % "Stress Lv. 3" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a2_v3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a2_v3;
end

a1 = a1_v1 + a1_v2 + a1_v3;
a2 = a2_v1 + a2_v2 + a2_v3;
N = numel(v1(1,:)) + numel(v2(1,:))+ numel(v3(1,:)); % the first term of ∂Λ/∂β(equation 1)

one = N/B + a1 – a2;

%————- equation 2 ————-%
b1_v1 = 0;
b1_v2 = 0;
b1_v3 = 0;

i = 1; % "Stress Lv. 1" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b1_v1 = N/v1(i,j) + b1_v1;
end

i = 1; % "Stress Lv. 2" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b1_v2 = N/v2(i,j) + b1_v2;
end

i = 1; % "Stress Lv. 3" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b1_v3 = N/v3(i,j) + b1_v3;
end

b2_v1 = 0;
b2_v2 = 0;
b2_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b2_v1 = N/v1(i,j)*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+b2_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b2_v2 = N/v2(i,j)*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+b2_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b2_v3 = N/v3(i,j)*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+b2_v3;
end

b1 = b1_v1 + b1_v2 + b1_v3;
b2 = b2_v1 + b2_v2 + b2_v3;

two = B*(- b1 + b2);

%————- equation 3 ————-%
c1 = 0;
c2 = 0;
c3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
c1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+c1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
c2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+c2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
c3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+c3;
end

N = numel(v1(1,:)) + numel(v2(1,:)) + numel(v3(1,:)); % the first term of ∂Λ/∂C(equation 3)
three = B/C*(- N + (c1 + c2 + c3));

eqns = [one == 0, two == 0, three == 0];
vars = [B BB C];
answer = solve(eqns, vars);
vpa(answer.B)
vpa(answer.BB)
vpa(answer.C)I need the help of people who have excellent talents in calculating using Matlab.
The equations to be implemented through Matlab coding is as follows.

The results to be obtained through this coding is written in "Answer) ~" above.
And, the data related to this problem(or eqution) is below.

I have tried with the following coding but kept getting the same results as the title. I would like to get helpful advice on this part.
I would appreciate it if you could give me a guide on the solution or error cause.
v1 = [393 393 393 393 393 393 393 393 393 393 ; 3850 4340 4760 5320 5740 6160 6580 7140 7980 8960];
v2 = [408 408 408 408 408 408 408 408 408 408 ; 3300 3720 4080 4560 4920 5280 5640 6120 6840 7680];
v3 = [423 423 423 423 423 423 423 423 423 423 ; 2750 3100 3400 3800 4100 4400 4700 5100 5700 6400];

syms B; % parameter Beta
syms BB; % parameter B
syms C;

%————- equation 1 ————-%
a1_v1 = 0;
a1_v2 = 0;
a1_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a1_v1 = N*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a1_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a1_v2 = N*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a1_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a1_v3 = N*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a1_v3;
end

a2_v1 = 0;
a2_v2 = 0;
a2_v3 = 0;

i = 1; % "Stress Lv. 1" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a2_v1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a2_v1;
end

i = 1; % "Stress Lv. 2" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a2_v2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a2_v2;
end

i = 1; % "Stress Lv. 3" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a2_v3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a2_v3;
end

a1 = a1_v1 + a1_v2 + a1_v3;
a2 = a2_v1 + a2_v2 + a2_v3;
N = numel(v1(1,:)) + numel(v2(1,:))+ numel(v3(1,:)); % the first term of ∂Λ/∂β(equation 1)

one = N/B + a1 – a2;

%————- equation 2 ————-%
b1_v1 = 0;
b1_v2 = 0;
b1_v3 = 0;

i = 1; % "Stress Lv. 1" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b1_v1 = N/v1(i,j) + b1_v1;
end

i = 1; % "Stress Lv. 2" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b1_v2 = N/v2(i,j) + b1_v2;
end

i = 1; % "Stress Lv. 3" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b1_v3 = N/v3(i,j) + b1_v3;
end

b2_v1 = 0;
b2_v2 = 0;
b2_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b2_v1 = N/v1(i,j)*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+b2_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b2_v2 = N/v2(i,j)*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+b2_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b2_v3 = N/v3(i,j)*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+b2_v3;
end

b1 = b1_v1 + b1_v2 + b1_v3;
b2 = b2_v1 + b2_v2 + b2_v3;

two = B*(- b1 + b2);

%————- equation 3 ————-%
c1 = 0;
c2 = 0;
c3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
c1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+c1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
c2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+c2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
c3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+c3;
end

N = numel(v1(1,:)) + numel(v2(1,:)) + numel(v3(1,:)); % the first term of ∂Λ/∂C(equation 3)
three = B/C*(- N + (c1 + c2 + c3));

eqns = [one == 0, two == 0, three == 0];
vars = [B BB C];
answer = solve(eqns, vars);
vpa(answer.B)
vpa(answer.BB)
vpa(answer.C) I need the help of people who have excellent talents in calculating using Matlab.
The equations to be implemented through Matlab coding is as follows.

The results to be obtained through this coding is written in "Answer) ~" above.
And, the data related to this problem(or eqution) is below.

I have tried with the following coding but kept getting the same results as the title. I would like to get helpful advice on this part.
I would appreciate it if you could give me a guide on the solution or error cause.
v1 = [393 393 393 393 393 393 393 393 393 393 ; 3850 4340 4760 5320 5740 6160 6580 7140 7980 8960];
v2 = [408 408 408 408 408 408 408 408 408 408 ; 3300 3720 4080 4560 4920 5280 5640 6120 6840 7680];
v3 = [423 423 423 423 423 423 423 423 423 423 ; 2750 3100 3400 3800 4100 4400 4700 5100 5700 6400];

syms B; % parameter Beta
syms BB; % parameter B
syms C;

%————- equation 1 ————-%
a1_v1 = 0;
a1_v2 = 0;
a1_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a1_v1 = N*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a1_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a1_v2 = N*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a1_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a1_v3 = N*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a1_v3;
end

a2_v1 = 0;
a2_v2 = 0;
a2_v3 = 0;

i = 1; % "Stress Lv. 1" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
a2_v1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B*log(v1(i+1,j)/C/exp(BB/v1(i,j))) + a2_v1;
end

i = 1; % "Stress Lv. 2" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
a2_v2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B*log(v2(i+1,j)/C/exp(BB/v2(i,j))) + a2_v2;
end

i = 1; % "Stress Lv. 3" in the third term of ∂Λ/∂β(equation 1)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
a2_v3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B*log(v3(i+1,j)/C/exp(BB/v3(i,j))) + a2_v3;
end

a1 = a1_v1 + a1_v2 + a1_v3;
a2 = a2_v1 + a2_v2 + a2_v3;
N = numel(v1(1,:)) + numel(v2(1,:))+ numel(v3(1,:)); % the first term of ∂Λ/∂β(equation 1)

one = N/B + a1 – a2;

%————- equation 2 ————-%
b1_v1 = 0;
b1_v2 = 0;
b1_v3 = 0;

i = 1; % "Stress Lv. 1" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b1_v1 = N/v1(i,j) + b1_v1;
end

i = 1; % "Stress Lv. 2" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b1_v2 = N/v2(i,j) + b1_v2;
end

i = 1; % "Stress Lv. 3" in the first term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b1_v3 = N/v3(i,j) + b1_v3;
end

b2_v1 = 0;
b2_v2 = 0;
b2_v3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
b2_v1 = N/v1(i,j)*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+b2_v1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
b2_v2 = N/v2(i,j)*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+b2_v2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂B(equation 2)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
b2_v3 = N/v3(i,j)*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+b2_v3;
end

b1 = b1_v1 + b1_v2 + b1_v3;
b2 = b2_v1 + b2_v2 + b2_v3;

two = B*(- b1 + b2);

%————- equation 3 ————-%
c1 = 0;
c2 = 0;
c3 = 0;

i = 1; % "Stress Lv. 1" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v1(i, :)))
N = numel(v1(i,j));
c1 = N*(v1(i+1,j)/C/exp(BB/v1(i,j)))^B+c1;
end

i = 1; % "Stress Lv. 2" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v2(i, :)))
N = numel(v2(i,j));
c2 = N*(v2(i+1,j)/C/exp(BB/v2(i,j)))^B+c2;
end

i = 1; % "Stress Lv. 3" in the second term of ∂Λ/∂C(equation 3)
for j = 1:(numel(v3(i, :)))
N = numel(v3(i,j));
c3 = N*(v3(i+1,j)/C/exp(BB/v3(i,j)))^B+c3;
end

N = numel(v1(1,:)) + numel(v2(1,:)) + numel(v3(1,:)); % the first term of ∂Λ/∂C(equation 3)
three = B/C*(- N + (c1 + c2 + c3));

eqns = [one == 0, two == 0, three == 0];
vars = [B BB C];
answer = solve(eqns, vars);
vpa(answer.B)
vpa(answer.BB)
vpa(answer.C) vpa, equation, 0-by-1, threeparameteres, solve, stresslevel MATLAB Answers — New Questions

​

I asked before with a long question and got no answers, so let’s keep it simpler.
Serial port is connected to Arduino
Arduino resets, so I need to:
1. Detect that it’s gone without throwing an error
2. Reconnect
Results:
Connected and callback set
K>> app.Pico
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
Hit reset on Pico get following error message ( but it doesn’t stop my program from running)
Unable to detect connection to the serialport device. Ensure that the device is plugged in and create a new serialport object.
If there is no "keep alive" function for serial ports ( Walter Roberson in https://www.mathworks.com/matlabcentral/answers/1722140-cant-read-the-serial-port) then what is generating this error? How can I catch it without constantly checking the connection myself?
If I could trap the error here that would be a great start.
So let’s look at where we are:
K>> app.PicoCom
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Not useful, but I can check it right?
K>> isvalid(app.PicoCom)
ans =
logical
1
Really? It’s still valid? Let’s try
K>> serialportlist("available")
ans =
1×2 string array
"COM1" "COM16"
OK, at least I can see it’s back in the list of available ports. Is this the best (fastest) way to find out?
Also I can’t check in the input call back because then it’s too late. Error thrown already.
K>> delete(app.PicoCom)
K>> app.PicoCom
ans =
handle to deleted Serialport
K>> isvalid(app.PicoCom)
ans =
logical
0
At least once deleted it’s not valid. Let’s reconnect:
K>> app.PicoCom = serialport()
K>> app.PicoCom
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
ByteOrder: "little-endian"
DataBits: 8
StopBits: 1
Parity: "none"
FlowControl: "none"
Timeout: 10
Terminator: "CR/LF"
Back to normal as soon as I add
K>> configureCallback(app.PicoCom,"terminator",@app.PicoInput);
So I think I’ve got recovery OK. How about detecting when coms are lost?

BTW serialportfind is only useful when teh prot is there. If it’s missing then looking throws an error…
K>> serialportfind
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Apparently it’s a valid question to ask, just not a useful answer.
K>> isvalid(serialportfind)’
ans =
logical
1I asked before with a long question and got no answers, so let’s keep it simpler.
Serial port is connected to Arduino
Arduino resets, so I need to:
1. Detect that it’s gone without throwing an error
2. Reconnect
Results:
Connected and callback set
K>> app.Pico
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
Hit reset on Pico get following error message ( but it doesn’t stop my program from running)
Unable to detect connection to the serialport device. Ensure that the device is plugged in and create a new serialport object.
If there is no "keep alive" function for serial ports ( Walter Roberson in https://www.mathworks.com/matlabcentral/answers/1722140-cant-read-the-serial-port) then what is generating this error? How can I catch it without constantly checking the connection myself?
If I could trap the error here that would be a great start.
So let’s look at where we are:
K>> app.PicoCom
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Not useful, but I can check it right?
K>> isvalid(app.PicoCom)
ans =
logical
1
Really? It’s still valid? Let’s try
K>> serialportlist("available")
ans =
1×2 string array
"COM1" "COM16"
OK, at least I can see it’s back in the list of available ports. Is this the best (fastest) way to find out?
Also I can’t check in the input call back because then it’s too late. Error thrown already.
K>> delete(app.PicoCom)
K>> app.PicoCom
ans =
handle to deleted Serialport
K>> isvalid(app.PicoCom)
ans =
logical
0
At least once deleted it’s not valid. Let’s reconnect:
K>> app.PicoCom = serialport()
K>> app.PicoCom
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
ByteOrder: "little-endian"
DataBits: 8
StopBits: 1
Parity: "none"
FlowControl: "none"
Timeout: 10
Terminator: "CR/LF"
Back to normal as soon as I add
K>> configureCallback(app.PicoCom,"terminator",@app.PicoInput);
So I think I’ve got recovery OK. How about detecting when coms are lost?

BTW serialportfind is only useful when teh prot is there. If it’s missing then looking throws an error…
K>> serialportfind
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Apparently it’s a valid question to ask, just not a useful answer.
K>> isvalid(serialportfind)’
ans =
logical
1 I asked before with a long question and got no answers, so let’s keep it simpler.
Serial port is connected to Arduino
Arduino resets, so I need to:
1. Detect that it’s gone without throwing an error
2. Reconnect
Results:
Connected and callback set
K>> app.Pico
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
Hit reset on Pico get following error message ( but it doesn’t stop my program from running)
Unable to detect connection to the serialport device. Ensure that the device is plugged in and create a new serialport object.
If there is no "keep alive" function for serial ports ( Walter Roberson in https://www.mathworks.com/matlabcentral/answers/1722140-cant-read-the-serial-port) then what is generating this error? How can I catch it without constantly checking the connection myself?
If I could trap the error here that would be a great start.
So let’s look at where we are:
K>> app.PicoCom
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Not useful, but I can check it right?
K>> isvalid(app.PicoCom)
ans =
logical
1
Really? It’s still valid? Let’s try
K>> serialportlist("available")
ans =
1×2 string array
"COM1" "COM16"
OK, at least I can see it’s back in the list of available ports. Is this the best (fastest) way to find out?
Also I can’t check in the input call back because then it’s too late. Error thrown already.
K>> delete(app.PicoCom)
K>> app.PicoCom
ans =
handle to deleted Serialport
K>> isvalid(app.PicoCom)
ans =
logical
0
At least once deleted it’s not valid. Let’s reconnect:
K>> app.PicoCom = serialport()
K>> app.PicoCom
ans =
Serialport with properties:
Port: "COM16"
BaudRate: 57600
NumBytesAvailable: 0
ByteOrder: "little-endian"
DataBits: 8
StopBits: 1
Parity: "none"
FlowControl: "none"
Timeout: 10
Terminator: "CR/LF"
Back to normal as soon as I add
K>> configureCallback(app.PicoCom,"terminator",@app.PicoInput);
So I think I’ve got recovery OK. How about detecting when coms are lost?

BTW serialportfind is only useful when teh prot is there. If it’s missing then looking throws an error…
K>> serialportfind
ans =
Serialport with properties:
In ‘testmeaslib:CustomDisplay:PropertyWarning’,
data type supplied is incorrect for parameter {0}.
Apparently it’s a valid question to ask, just not a useful answer.
K>> isvalid(serialportfind)’
ans =
logical
1 serial, usb, reconnect MATLAB Answers — New Questions

​