Hi,
Why does Matlab calculate the settling time which measures the time for the error to fall below 2% of the peak value of the error for the closed-loop function T given below differently from the calculated value?
Cheers,

T= 4/( s^2 + 1.6 s+4)

Calculated settling time=4/(wn*zeta)=5 s;
where wn=2, zeta=0.4.

s = stepinfo(T)
s =

struct with fields:

RiseTime: 0.7326
TransientTime: 4.2047
SettlingTime: 4.2047
SettlingMin: 0.9065
SettlingMax: 1.2537
Overshoot: 25.3741
Undershoot: 0
Peak: 1.2537
PeakTime: 1.7269Hi,
Why does Matlab calculate the settling time which measures the time for the error to fall below 2% of the peak value of the error for the closed-loop function T given below differently from the calculated value?
Cheers,

T= 4/( s^2 + 1.6 s+4)

Calculated settling time=4/(wn*zeta)=5 s;
where wn=2, zeta=0.4.

s = stepinfo(T)
s =

struct with fields:

RiseTime: 0.7326
TransientTime: 4.2047
SettlingTime: 4.2047
SettlingMin: 0.9065
SettlingMax: 1.2537
Overshoot: 25.3741
Undershoot: 0
Peak: 1.2537
PeakTime: 1.7269 Hi,
Why does Matlab calculate the settling time which measures the time for the error to fall below 2% of the peak value of the error for the closed-loop function T given below differently from the calculated value?
Cheers,

T= 4/( s^2 + 1.6 s+4)

Calculated settling time=4/(wn*zeta)=5 s;
where wn=2, zeta=0.4.

s = stepinfo(T)
s =

struct with fields:

RiseTime: 0.7326
TransientTime: 4.2047
SettlingTime: 4.2047
SettlingMin: 0.9065
SettlingMax: 1.2537
Overshoot: 25.3741
Undershoot: 0
Peak: 1.2537
PeakTime: 1.7269 the settling time in matlab differs MATLAB Answers — New Questions

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