Category: Matlab
Category Archives: Matlab
Can classes or class variables be used in stateflow charts / test sequences
I’m creating a test sequence for a test harness and would like to use an object in the steps. However, I receive a message that Data type of ‘<initialized object variable name>’ is not supported in Stateflow charts. I know I can perform function calls, but I need some state maintenance to drive function behavior and would like to use an object’s methods instead of raw functions.
Is this possible?I’m creating a test sequence for a test harness and would like to use an object in the steps. However, I receive a message that Data type of ‘<initialized object variable name>’ is not supported in Stateflow charts. I know I can perform function calls, but I need some state maintenance to drive function behavior and would like to use an object’s methods instead of raw functions.
Is this possible? I’m creating a test sequence for a test harness and would like to use an object in the steps. However, I receive a message that Data type of ‘<initialized object variable name>’ is not supported in Stateflow charts. I know I can perform function calls, but I need some state maintenance to drive function behavior and would like to use an object’s methods instead of raw functions.
Is this possible? stateflow chart, object, test harness, test sequence, simulink MATLAB Answers — New Questions
Changing the shell for system commands to mingw-w64
Hi community,
I’ve been trying to use ‘system’ commands in MATLAB to execute operating system command (from MRtrix3 to be specific). However, to do so I need to change the shell from default to mingw-w64 for my windows laptop, which I’ve been struggling to do. While I’ve tryied things like:
setenv MATLAB_SHELL C:msys2mingw64.exe
inside my script before calling system comamnds, it doesn’t actually work.
I wonder what can I do about this / what i did wrong.
Many thanks in advanceHi community,
I’ve been trying to use ‘system’ commands in MATLAB to execute operating system command (from MRtrix3 to be specific). However, to do so I need to change the shell from default to mingw-w64 for my windows laptop, which I’ve been struggling to do. While I’ve tryied things like:
setenv MATLAB_SHELL C:msys2mingw64.exe
inside my script before calling system comamnds, it doesn’t actually work.
I wonder what can I do about this / what i did wrong.
Many thanks in advance Hi community,
I’ve been trying to use ‘system’ commands in MATLAB to execute operating system command (from MRtrix3 to be specific). However, to do so I need to change the shell from default to mingw-w64 for my windows laptop, which I’ve been struggling to do. While I’ve tryied things like:
setenv MATLAB_SHELL C:msys2mingw64.exe
inside my script before calling system comamnds, it doesn’t actually work.
I wonder what can I do about this / what i did wrong.
Many thanks in advance shell, system MATLAB Answers — New Questions
I’m having trouble seperating two body from phasing into one another
Hi, I’m a beginer at using simulink and matlab, and I have been having trouble seperating a quadcopter model from falling through my supposely ground surface block. I’ve have tried looking into the Simscape Multibody Contact Forces Library, but I do not find a solution there. Any ideas to resolve this issue would be appreciated? Thank you.Hi, I’m a beginer at using simulink and matlab, and I have been having trouble seperating a quadcopter model from falling through my supposely ground surface block. I’ve have tried looking into the Simscape Multibody Contact Forces Library, but I do not find a solution there. Any ideas to resolve this issue would be appreciated? Thank you. Hi, I’m a beginer at using simulink and matlab, and I have been having trouble seperating a quadcopter model from falling through my supposely ground surface block. I’ve have tried looking into the Simscape Multibody Contact Forces Library, but I do not find a solution there. Any ideas to resolve this issue would be appreciated? Thank you. simscape MATLAB Answers — New Questions
What is the difference between rcosdesign and fdesign.pulseshaping?
The <https://www.mathworks.com/help/signal/release-notes.html?searchHighlight=firrcos&s_tid=doc_srchtitle release notes on the Signal Processing Toolbox> say that firrcos and fdesign.pulseshaping are deprecated by rcosdesign, and a little bit farther it gives specific code for converting from fdesign.pulseshaping to rcosdesign. Specifically, it says:
n1n = rcosdesign(Beta,span,sps);
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is equivalent to:
sps = 6;
span = 4;
Beta = 0.25;
f1 = fdesign.pulseshaping(sps, …
‘Square Root Raised Cosine’, …
‘Nsym,Beta’,span,Beta);
d1 = design(f1);
n1 = d1.Numerator
which appears to be true. However, can anyone explain what the
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is doing? In other words, what is the difference between these two functions such that some connector code is needed to go from one to the other? From a rough understanding, it looks like it is normalizing the values, but then not really sure on the rest.The <https://www.mathworks.com/help/signal/release-notes.html?searchHighlight=firrcos&s_tid=doc_srchtitle release notes on the Signal Processing Toolbox> say that firrcos and fdesign.pulseshaping are deprecated by rcosdesign, and a little bit farther it gives specific code for converting from fdesign.pulseshaping to rcosdesign. Specifically, it says:
n1n = rcosdesign(Beta,span,sps);
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is equivalent to:
sps = 6;
span = 4;
Beta = 0.25;
f1 = fdesign.pulseshaping(sps, …
‘Square Root Raised Cosine’, …
‘Nsym,Beta’,span,Beta);
d1 = design(f1);
n1 = d1.Numerator
which appears to be true. However, can anyone explain what the
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is doing? In other words, what is the difference between these two functions such that some connector code is needed to go from one to the other? From a rough understanding, it looks like it is normalizing the values, but then not really sure on the rest. The <https://www.mathworks.com/help/signal/release-notes.html?searchHighlight=firrcos&s_tid=doc_srchtitle release notes on the Signal Processing Toolbox> say that firrcos and fdesign.pulseshaping are deprecated by rcosdesign, and a little bit farther it gives specific code for converting from fdesign.pulseshaping to rcosdesign. Specifically, it says:
n1n = rcosdesign(Beta,span,sps);
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is equivalent to:
sps = 6;
span = 4;
Beta = 0.25;
f1 = fdesign.pulseshaping(sps, …
‘Square Root Raised Cosine’, …
‘Nsym,Beta’,span,Beta);
d1 = design(f1);
n1 = d1.Numerator
which appears to be true. However, can anyone explain what the
n1n = n1n / max(n1n) * (-1/(pi*sps) …
* (pi*(Beta-1) – 4*Beta))
is doing? In other words, what is the difference between these two functions such that some connector code is needed to go from one to the other? From a rough understanding, it looks like it is normalizing the values, but then not really sure on the rest. fir, filter, dsp MATLAB Answers — New Questions
applying the Parsen Window using a specific frequency for the width estimation
Hello, I would like to estimate Parsen window of 0.1Hz This value is used to smooth the Fourier Amplitude. However, I realized that it provides a higher smoothing effect that can alter the amplitudes compared to the unmoothed FAS of the signal (attached as txt file). I found out the following to estimate the Parsen window:
signal=load(signal.txt);
window_width_Parsen=0.1; % 0.1Hz suggested that does not alter the amplitudes compared to the unmoothed FAS
fs: 200 % Sample frequency of the signal and the FAS
w_Parsen=(1/window_width_Parsen)*fs;
w_Parsen=round(w_Parsen,0);Hello, I would like to estimate Parsen window of 0.1Hz This value is used to smooth the Fourier Amplitude. However, I realized that it provides a higher smoothing effect that can alter the amplitudes compared to the unmoothed FAS of the signal (attached as txt file). I found out the following to estimate the Parsen window:
signal=load(signal.txt);
window_width_Parsen=0.1; % 0.1Hz suggested that does not alter the amplitudes compared to the unmoothed FAS
fs: 200 % Sample frequency of the signal and the FAS
w_Parsen=(1/window_width_Parsen)*fs;
w_Parsen=round(w_Parsen,0); Hello, I would like to estimate Parsen window of 0.1Hz This value is used to smooth the Fourier Amplitude. However, I realized that it provides a higher smoothing effect that can alter the amplitudes compared to the unmoothed FAS of the signal (attached as txt file). I found out the following to estimate the Parsen window:
signal=load(signal.txt);
window_width_Parsen=0.1; % 0.1Hz suggested that does not alter the amplitudes compared to the unmoothed FAS
fs: 200 % Sample frequency of the signal and the FAS
w_Parsen=(1/window_width_Parsen)*fs;
w_Parsen=round(w_Parsen,0); parsen window MATLAB Answers — New Questions
Trying to ubderstand the power distribution in fft plot
clear all
close all
clc
L=10;
n=1.45;
c=2.9979e8;
dt = 6e-12;
T=10*2*L*n/c;
eps0=8.854e-12;
A=80e-12;
t = (-T/2/dt:1:T/2/dt)*dt;
Nt=round(T/dt);
fsine = 1e9;
vsine = 1;
phi = vsine*sin(2*pi*fsine*t);
EL1t=1.274e7*exp(1i*phi);
FP=fft(phi);
fs=1/dt/Nt;
Fs=(-1/dt/2:fs:1/dt/2-1);
figure
Z=plot(Fs,fftshift(abs(fft(EL1t/Nt).^2*2*n*c*eps0*A)));
As you see from the obtained fft plot , the peak of the graph at 0Hz is around 60W , but I am struggling to understand how the power is distributed throughout the plot.
The given input power is 100W I think. Shouldn’t the central frequency at 0Hz be around 100W.
Where did the rest of power is what I am not understanding…clear all
close all
clc
L=10;
n=1.45;
c=2.9979e8;
dt = 6e-12;
T=10*2*L*n/c;
eps0=8.854e-12;
A=80e-12;
t = (-T/2/dt:1:T/2/dt)*dt;
Nt=round(T/dt);
fsine = 1e9;
vsine = 1;
phi = vsine*sin(2*pi*fsine*t);
EL1t=1.274e7*exp(1i*phi);
FP=fft(phi);
fs=1/dt/Nt;
Fs=(-1/dt/2:fs:1/dt/2-1);
figure
Z=plot(Fs,fftshift(abs(fft(EL1t/Nt).^2*2*n*c*eps0*A)));
As you see from the obtained fft plot , the peak of the graph at 0Hz is around 60W , but I am struggling to understand how the power is distributed throughout the plot.
The given input power is 100W I think. Shouldn’t the central frequency at 0Hz be around 100W.
Where did the rest of power is what I am not understanding… clear all
close all
clc
L=10;
n=1.45;
c=2.9979e8;
dt = 6e-12;
T=10*2*L*n/c;
eps0=8.854e-12;
A=80e-12;
t = (-T/2/dt:1:T/2/dt)*dt;
Nt=round(T/dt);
fsine = 1e9;
vsine = 1;
phi = vsine*sin(2*pi*fsine*t);
EL1t=1.274e7*exp(1i*phi);
FP=fft(phi);
fs=1/dt/Nt;
Fs=(-1/dt/2:fs:1/dt/2-1);
figure
Z=plot(Fs,fftshift(abs(fft(EL1t/Nt).^2*2*n*c*eps0*A)));
As you see from the obtained fft plot , the peak of the graph at 0Hz is around 60W , but I am struggling to understand how the power is distributed throughout the plot.
The given input power is 100W I think. Shouldn’t the central frequency at 0Hz be around 100W.
Where did the rest of power is what I am not understanding… fft, plot, power, psd MATLAB Answers — New Questions
Rewriting in columns of Excel sheet
%% After running the code for p1 = 0.01; p2 = 0.0; p3 = 0.0;
%Matlab writes the calculations of ‘Cf’ and ‘Nu’ in an excel sheet of Columns ‘I’ and ‘J’ respectively.
%% But I want to run the code 03 times with different values (i) p1 = 0.01; p2 = 0.0; p3 = 0.0;
% (ii) p1 = 0.01; p2 = 0.01; p3 = 0.0;(iii)p1 = 0.01;p2 = 0.01;p3 = 0.01;
% (other values are fixed as in Excel sheet)
%% Now I want Matlab to write the values of ‘Cf’ in the Columns " I, J, K " and the values of ‘Nu’ in the Columns " L, M, N" respectively. (SAME EXCEL SHEET)
%% Here is my try, please modify
status = mkdir(‘D:PK79’); cd D:PK79
filePath = ‘D:PK79ADM3A.xlsx’; filename = ‘ADM3A.xlsx’;
d = readtable(filename);
T = fillmissing(d,"previous");
p1 = 0.01; p2 = 0.0; p3 = 0.0;
K = T.K; M = T.M; Pr = T.Pr; Ec = T.Ec; Q = T.Qe; D = T.D; b = T.b; Bi = T.Bi;
Cp = 1;rf = 7;kf = 0.6;sf = 5.5; C1 = 7;rhos1 = 1;k1 = 4;s1 = 1;
C2 = 5;r2 = 2;k2 = .5;s2 = 2.7; C3 = 6.2;r3 = 2;k3 = .9;s3 = 6.2;
H1 = ((1-p1)*(1-p2)*(1-p3))^-2.5; H2 = (1-p3)*( (1-p2)*( 1-p1 + p1*rhos1/rf ) + p2*r2/rf ) + p3*r3/rf;
H3 = (1-p3)*( (1-p2)*(1-p1 + p1*rhos1*C1/(rf*Cp)) + p2*r2*C2/(rf*Cp) ) + p3*r3*C3/(rf*Cp);
C2 = ( (s1+2*sf-2*p1*(sf-s1))/(s1+2*sf+p1*(sf-s1)));
C3 = ( (s2+2*C2-2*p2*(C2-s2))/(s2+2*C2+p2*(C2-s2)) );
A3 = ( (s3+2*C3-2*p3*(C3-s3))/(s3+2*C3+p3*(C3-s3)) );
B1 = ( (k1+2*kf-2*p1*(kf-k1))/(k1+2*kf+p1*(kf-k1)) );
B2 = ( (k2+2*B1-2*p2*(B1-k2))/(k2+2*B1+p2*(B1-k2)) );
H4 = ( (k3+2*B2-2*p3*(B2-k3))/(k3+2*B2+p3*(B2-k3)) );
N = size(T,1); Cf = zeros(N,1); Nu = zeros(N,1);
for k = 1:N
ODE = @(x,y)[y(2); y(3); y(4);
M(k)*(x+K(k)).^2*(A3/H1).*(y(2) + (x+K(k)).*y(3)) – 2*y(4)./(x+K(k)) + y(3)./(x+K(k)).^2 – y(2)./(x+K(k)).^3 – (H2/H1)*K(k)*((x+K(k)).^2.*(y(1)*y(4) – y(2)*y(3))) – y(1)*y(2) + (x+K(k)).*(y(1)*y(3)-y(2)^2);
y(6); – (Pr(k)/H4)*( Q(k)*(y(5) + exp(-D(k)*x)) + H3*K(k)*y(1)*y(6) + M(k)*Ec(k)*A3*y(2)^2 ) – y(6) ];
BC = @(ya,yb)[ya(1); ya(2)-1-b(k)*(ya(3)-ya(2)/K(k)); ya(6)-Bi(k)*(ya(5)-1); yb([2;3;5])];
xa = 0; xb = 6;
x = linspace(xa,xb,101);
solinit = bvpinit(x,[0 1 0 1 0 1]);
sol = bvp5c(ODE,BC,solinit);
S = deval(sol,x);
Cf(k) = H1*( S(3,1) – S(2,1)/K(k));
Nu(k) = -H4*S(6,1);
end
T.Cf = Cf; T.Nu = Nu;
vars = T.Properties.VariableNames;
T = removevars(T,vars(startsWith(vars,’Var’)));
writetable(T,filename,’WriteMode’,’overwritesheet’)
T = readtable(filename) % check the result:%% After running the code for p1 = 0.01; p2 = 0.0; p3 = 0.0;
%Matlab writes the calculations of ‘Cf’ and ‘Nu’ in an excel sheet of Columns ‘I’ and ‘J’ respectively.
%% But I want to run the code 03 times with different values (i) p1 = 0.01; p2 = 0.0; p3 = 0.0;
% (ii) p1 = 0.01; p2 = 0.01; p3 = 0.0;(iii)p1 = 0.01;p2 = 0.01;p3 = 0.01;
% (other values are fixed as in Excel sheet)
%% Now I want Matlab to write the values of ‘Cf’ in the Columns " I, J, K " and the values of ‘Nu’ in the Columns " L, M, N" respectively. (SAME EXCEL SHEET)
%% Here is my try, please modify
status = mkdir(‘D:PK79’); cd D:PK79
filePath = ‘D:PK79ADM3A.xlsx’; filename = ‘ADM3A.xlsx’;
d = readtable(filename);
T = fillmissing(d,"previous");
p1 = 0.01; p2 = 0.0; p3 = 0.0;
K = T.K; M = T.M; Pr = T.Pr; Ec = T.Ec; Q = T.Qe; D = T.D; b = T.b; Bi = T.Bi;
Cp = 1;rf = 7;kf = 0.6;sf = 5.5; C1 = 7;rhos1 = 1;k1 = 4;s1 = 1;
C2 = 5;r2 = 2;k2 = .5;s2 = 2.7; C3 = 6.2;r3 = 2;k3 = .9;s3 = 6.2;
H1 = ((1-p1)*(1-p2)*(1-p3))^-2.5; H2 = (1-p3)*( (1-p2)*( 1-p1 + p1*rhos1/rf ) + p2*r2/rf ) + p3*r3/rf;
H3 = (1-p3)*( (1-p2)*(1-p1 + p1*rhos1*C1/(rf*Cp)) + p2*r2*C2/(rf*Cp) ) + p3*r3*C3/(rf*Cp);
C2 = ( (s1+2*sf-2*p1*(sf-s1))/(s1+2*sf+p1*(sf-s1)));
C3 = ( (s2+2*C2-2*p2*(C2-s2))/(s2+2*C2+p2*(C2-s2)) );
A3 = ( (s3+2*C3-2*p3*(C3-s3))/(s3+2*C3+p3*(C3-s3)) );
B1 = ( (k1+2*kf-2*p1*(kf-k1))/(k1+2*kf+p1*(kf-k1)) );
B2 = ( (k2+2*B1-2*p2*(B1-k2))/(k2+2*B1+p2*(B1-k2)) );
H4 = ( (k3+2*B2-2*p3*(B2-k3))/(k3+2*B2+p3*(B2-k3)) );
N = size(T,1); Cf = zeros(N,1); Nu = zeros(N,1);
for k = 1:N
ODE = @(x,y)[y(2); y(3); y(4);
M(k)*(x+K(k)).^2*(A3/H1).*(y(2) + (x+K(k)).*y(3)) – 2*y(4)./(x+K(k)) + y(3)./(x+K(k)).^2 – y(2)./(x+K(k)).^3 – (H2/H1)*K(k)*((x+K(k)).^2.*(y(1)*y(4) – y(2)*y(3))) – y(1)*y(2) + (x+K(k)).*(y(1)*y(3)-y(2)^2);
y(6); – (Pr(k)/H4)*( Q(k)*(y(5) + exp(-D(k)*x)) + H3*K(k)*y(1)*y(6) + M(k)*Ec(k)*A3*y(2)^2 ) – y(6) ];
BC = @(ya,yb)[ya(1); ya(2)-1-b(k)*(ya(3)-ya(2)/K(k)); ya(6)-Bi(k)*(ya(5)-1); yb([2;3;5])];
xa = 0; xb = 6;
x = linspace(xa,xb,101);
solinit = bvpinit(x,[0 1 0 1 0 1]);
sol = bvp5c(ODE,BC,solinit);
S = deval(sol,x);
Cf(k) = H1*( S(3,1) – S(2,1)/K(k));
Nu(k) = -H4*S(6,1);
end
T.Cf = Cf; T.Nu = Nu;
vars = T.Properties.VariableNames;
T = removevars(T,vars(startsWith(vars,’Var’)));
writetable(T,filename,’WriteMode’,’overwritesheet’)
T = readtable(filename) % check the result: %% After running the code for p1 = 0.01; p2 = 0.0; p3 = 0.0;
%Matlab writes the calculations of ‘Cf’ and ‘Nu’ in an excel sheet of Columns ‘I’ and ‘J’ respectively.
%% But I want to run the code 03 times with different values (i) p1 = 0.01; p2 = 0.0; p3 = 0.0;
% (ii) p1 = 0.01; p2 = 0.01; p3 = 0.0;(iii)p1 = 0.01;p2 = 0.01;p3 = 0.01;
% (other values are fixed as in Excel sheet)
%% Now I want Matlab to write the values of ‘Cf’ in the Columns " I, J, K " and the values of ‘Nu’ in the Columns " L, M, N" respectively. (SAME EXCEL SHEET)
%% Here is my try, please modify
status = mkdir(‘D:PK79’); cd D:PK79
filePath = ‘D:PK79ADM3A.xlsx’; filename = ‘ADM3A.xlsx’;
d = readtable(filename);
T = fillmissing(d,"previous");
p1 = 0.01; p2 = 0.0; p3 = 0.0;
K = T.K; M = T.M; Pr = T.Pr; Ec = T.Ec; Q = T.Qe; D = T.D; b = T.b; Bi = T.Bi;
Cp = 1;rf = 7;kf = 0.6;sf = 5.5; C1 = 7;rhos1 = 1;k1 = 4;s1 = 1;
C2 = 5;r2 = 2;k2 = .5;s2 = 2.7; C3 = 6.2;r3 = 2;k3 = .9;s3 = 6.2;
H1 = ((1-p1)*(1-p2)*(1-p3))^-2.5; H2 = (1-p3)*( (1-p2)*( 1-p1 + p1*rhos1/rf ) + p2*r2/rf ) + p3*r3/rf;
H3 = (1-p3)*( (1-p2)*(1-p1 + p1*rhos1*C1/(rf*Cp)) + p2*r2*C2/(rf*Cp) ) + p3*r3*C3/(rf*Cp);
C2 = ( (s1+2*sf-2*p1*(sf-s1))/(s1+2*sf+p1*(sf-s1)));
C3 = ( (s2+2*C2-2*p2*(C2-s2))/(s2+2*C2+p2*(C2-s2)) );
A3 = ( (s3+2*C3-2*p3*(C3-s3))/(s3+2*C3+p3*(C3-s3)) );
B1 = ( (k1+2*kf-2*p1*(kf-k1))/(k1+2*kf+p1*(kf-k1)) );
B2 = ( (k2+2*B1-2*p2*(B1-k2))/(k2+2*B1+p2*(B1-k2)) );
H4 = ( (k3+2*B2-2*p3*(B2-k3))/(k3+2*B2+p3*(B2-k3)) );
N = size(T,1); Cf = zeros(N,1); Nu = zeros(N,1);
for k = 1:N
ODE = @(x,y)[y(2); y(3); y(4);
M(k)*(x+K(k)).^2*(A3/H1).*(y(2) + (x+K(k)).*y(3)) – 2*y(4)./(x+K(k)) + y(3)./(x+K(k)).^2 – y(2)./(x+K(k)).^3 – (H2/H1)*K(k)*((x+K(k)).^2.*(y(1)*y(4) – y(2)*y(3))) – y(1)*y(2) + (x+K(k)).*(y(1)*y(3)-y(2)^2);
y(6); – (Pr(k)/H4)*( Q(k)*(y(5) + exp(-D(k)*x)) + H3*K(k)*y(1)*y(6) + M(k)*Ec(k)*A3*y(2)^2 ) – y(6) ];
BC = @(ya,yb)[ya(1); ya(2)-1-b(k)*(ya(3)-ya(2)/K(k)); ya(6)-Bi(k)*(ya(5)-1); yb([2;3;5])];
xa = 0; xb = 6;
x = linspace(xa,xb,101);
solinit = bvpinit(x,[0 1 0 1 0 1]);
sol = bvp5c(ODE,BC,solinit);
S = deval(sol,x);
Cf(k) = H1*( S(3,1) – S(2,1)/K(k));
Nu(k) = -H4*S(6,1);
end
T.Cf = Cf; T.Nu = Nu;
vars = T.Properties.VariableNames;
T = removevars(T,vars(startsWith(vars,’Var’)));
writetable(T,filename,’WriteMode’,’overwritesheet’)
T = readtable(filename) % check the result: rewriting in columns of excel sheet MATLAB Answers — New Questions
Setting color to certain data in 3d plot, keeping rest of data following colormap
I am plotting data in a 3d heatmap using the bar3 command. I’d like to set some of the data to a certain color that is not included in the colorscheme of the legend bar, while keeping the rest of the data following the color map. The code I’m currently using is:
b=bar3(error);
set(gca,’XTickLabel’,[2.5 5 7.5 10])
set(gca,’YTickLabel’,[0 50 100 150 200 250])
ylim([0 20.5]);
colorbar
colormap turbo;
caxis([0 100]);
for k = 1:length(b)
zdata = b(k).ZData;
b(k).CData = zdata;
b(k).FaceColor = ‘interp’;
endI am plotting data in a 3d heatmap using the bar3 command. I’d like to set some of the data to a certain color that is not included in the colorscheme of the legend bar, while keeping the rest of the data following the color map. The code I’m currently using is:
b=bar3(error);
set(gca,’XTickLabel’,[2.5 5 7.5 10])
set(gca,’YTickLabel’,[0 50 100 150 200 250])
ylim([0 20.5]);
colorbar
colormap turbo;
caxis([0 100]);
for k = 1:length(b)
zdata = b(k).ZData;
b(k).CData = zdata;
b(k).FaceColor = ‘interp’;
end I am plotting data in a 3d heatmap using the bar3 command. I’d like to set some of the data to a certain color that is not included in the colorscheme of the legend bar, while keeping the rest of the data following the color map. The code I’m currently using is:
b=bar3(error);
set(gca,’XTickLabel’,[2.5 5 7.5 10])
set(gca,’YTickLabel’,[0 50 100 150 200 250])
ylim([0 20.5]);
colorbar
colormap turbo;
caxis([0 100]);
for k = 1:length(b)
zdata = b(k).ZData;
b(k).CData = zdata;
b(k).FaceColor = ‘interp’;
end bar3, bar color MATLAB Answers — New Questions
why does the switch exist at the speed reference in PMSM control?
https://kr.mathworks.com/help/mcb/gs/foc-pmsm-using-si-units.html
I’m going to use this PMSM control blockset, and I found that there’s a switch at the speed reference.
As shown in the attached photo, I simulated with the speed reference set to 1000(green circle), and there’s a step signal that applied to the output by the initial reference (blue circle) from the switch(red circle).
If I remove this switch, then the output immediately apply a speed reference to the input, the step output disappears, so I wonder why the switch was installed.https://kr.mathworks.com/help/mcb/gs/foc-pmsm-using-si-units.html
I’m going to use this PMSM control blockset, and I found that there’s a switch at the speed reference.
As shown in the attached photo, I simulated with the speed reference set to 1000(green circle), and there’s a step signal that applied to the output by the initial reference (blue circle) from the switch(red circle).
If I remove this switch, then the output immediately apply a speed reference to the input, the step output disappears, so I wonder why the switch was installed. https://kr.mathworks.com/help/mcb/gs/foc-pmsm-using-si-units.html
I’m going to use this PMSM control blockset, and I found that there’s a switch at the speed reference.
As shown in the attached photo, I simulated with the speed reference set to 1000(green circle), and there’s a step signal that applied to the output by the initial reference (blue circle) from the switch(red circle).
If I remove this switch, then the output immediately apply a speed reference to the input, the step output disappears, so I wonder why the switch was installed. pmsm, foc, switch, control system MATLAB Answers — New Questions
Dynamic Load Block MATLAB documenation
I am lloking for Dynamic Load change using the block provided in "openExample(‘simscapeelectricalsps/DynamicLoadExample’)"
Can you please provide me proper ducmentaion how to use the block "Three-Phase Dynamic Load"?
Lookking for answer.I am lloking for Dynamic Load change using the block provided in "openExample(‘simscapeelectricalsps/DynamicLoadExample’)"
Can you please provide me proper ducmentaion how to use the block "Three-Phase Dynamic Load"?
Lookking for answer. I am lloking for Dynamic Load change using the block provided in "openExample(‘simscapeelectricalsps/DynamicLoadExample’)"
Can you please provide me proper ducmentaion how to use the block "Three-Phase Dynamic Load"?
Lookking for answer. load, dynamic change, transient MATLAB Answers — New Questions
Plateau followed by one phase decay
Good morning, I am trying to figure out how to compute tau constants from my data
My data could be be fitted by such plateau followed by one phase decay function:
Here is an example:
x = 0:0.5:20; % time in seconds
Y0 = -0.6; % signal baseline value
Plateau = -1; % singnal plateu after trigger/stimulus, maximum change from baseline
tau = 0.6; % exponenential decay constant
K = 1/tau; % rate constant in units reciprocal of the x-axis units
X0 = 5; % trigger time
y = Y0*(x<=X0)+(Plateau+(Y0-Plateau)*exp(-K*(x-X0))).*(x>X0);
figure;plot(x,y,’k’);
Given example raw data below, could you please support me with fitting of the function above and paramters extraction?
x = 0:0.5:20;
y = [-0.137055262721364 -0.118841612584876 -0.274602636741299 -0.117324828772196 …
-0.173528150754918 -0.280491919000118 -0.244300356226590 -0.367583069701879 …
-0.423274105143034 -0.529129050767333 -0.774173830727337 -0.676677606159725 …
-0.730062482232667 -0.863905715495076 -0.831675679632950 -0.987303352625066 …
-0.949979744575626 -0.865710605996821 -0.901728879393798 -0.877082148456042 …
-0.944693953430828 -1.07404346760035 -0.915521627715257 -0.901789963321291 …
-0.955365771797851 -0.941530617721837 -0.945983148775748 -1.01735658137382 …
-0.965635004813717 -1.06321643780048 -0.956807780654745 -1.09208906741553 …
-1.04341265165344 -1.08982901817714 -1.07984413818039 -0.934740294823467 …
-0.960591807908718 -1.03623550995537 -0.909687220130007 -1.09290177705358 …
-1.01208835337351];
Best regardsGood morning, I am trying to figure out how to compute tau constants from my data
My data could be be fitted by such plateau followed by one phase decay function:
Here is an example:
x = 0:0.5:20; % time in seconds
Y0 = -0.6; % signal baseline value
Plateau = -1; % singnal plateu after trigger/stimulus, maximum change from baseline
tau = 0.6; % exponenential decay constant
K = 1/tau; % rate constant in units reciprocal of the x-axis units
X0 = 5; % trigger time
y = Y0*(x<=X0)+(Plateau+(Y0-Plateau)*exp(-K*(x-X0))).*(x>X0);
figure;plot(x,y,’k’);
Given example raw data below, could you please support me with fitting of the function above and paramters extraction?
x = 0:0.5:20;
y = [-0.137055262721364 -0.118841612584876 -0.274602636741299 -0.117324828772196 …
-0.173528150754918 -0.280491919000118 -0.244300356226590 -0.367583069701879 …
-0.423274105143034 -0.529129050767333 -0.774173830727337 -0.676677606159725 …
-0.730062482232667 -0.863905715495076 -0.831675679632950 -0.987303352625066 …
-0.949979744575626 -0.865710605996821 -0.901728879393798 -0.877082148456042 …
-0.944693953430828 -1.07404346760035 -0.915521627715257 -0.901789963321291 …
-0.955365771797851 -0.941530617721837 -0.945983148775748 -1.01735658137382 …
-0.965635004813717 -1.06321643780048 -0.956807780654745 -1.09208906741553 …
-1.04341265165344 -1.08982901817714 -1.07984413818039 -0.934740294823467 …
-0.960591807908718 -1.03623550995537 -0.909687220130007 -1.09290177705358 …
-1.01208835337351];
Best regards Good morning, I am trying to figure out how to compute tau constants from my data
My data could be be fitted by such plateau followed by one phase decay function:
Here is an example:
x = 0:0.5:20; % time in seconds
Y0 = -0.6; % signal baseline value
Plateau = -1; % singnal plateu after trigger/stimulus, maximum change from baseline
tau = 0.6; % exponenential decay constant
K = 1/tau; % rate constant in units reciprocal of the x-axis units
X0 = 5; % trigger time
y = Y0*(x<=X0)+(Plateau+(Y0-Plateau)*exp(-K*(x-X0))).*(x>X0);
figure;plot(x,y,’k’);
Given example raw data below, could you please support me with fitting of the function above and paramters extraction?
x = 0:0.5:20;
y = [-0.137055262721364 -0.118841612584876 -0.274602636741299 -0.117324828772196 …
-0.173528150754918 -0.280491919000118 -0.244300356226590 -0.367583069701879 …
-0.423274105143034 -0.529129050767333 -0.774173830727337 -0.676677606159725 …
-0.730062482232667 -0.863905715495076 -0.831675679632950 -0.987303352625066 …
-0.949979744575626 -0.865710605996821 -0.901728879393798 -0.877082148456042 …
-0.944693953430828 -1.07404346760035 -0.915521627715257 -0.901789963321291 …
-0.955365771797851 -0.941530617721837 -0.945983148775748 -1.01735658137382 …
-0.965635004813717 -1.06321643780048 -0.956807780654745 -1.09208906741553 …
-1.04341265165344 -1.08982901817714 -1.07984413818039 -0.934740294823467 …
-0.960591807908718 -1.03623550995537 -0.909687220130007 -1.09290177705358 …
-1.01208835337351];
Best regards curve fitting MATLAB Answers — New Questions
Find number of clusters remaining after doing agglomerative hierarchical clustering
I used agglomerative hierarchical clustering and stopeed clutering by giving a cutoff value. now I need to get the number of clusters in that particular image in order to proceed. Can someone help me?I used agglomerative hierarchical clustering and stopeed clutering by giving a cutoff value. now I need to get the number of clusters in that particular image in order to proceed. Can someone help me? I used agglomerative hierarchical clustering and stopeed clutering by giving a cutoff value. now I need to get the number of clusters in that particular image in order to proceed. Can someone help me? hierarchical clustering, stopping criteria, number of clusters MATLAB Answers — New Questions
How to train one agent and don’t update another one in multi-agent reinforcement learning setup?
Hi, I have a multi-agent reinforcment learning environment with two agents. One agent is pretrained (agentA) and the perofrmance is good. I need to train another one (agentB) to cooperate with agentA. I’m wondering if I can only train agentB and keep agentA unchanged so its performance will not be influenced.
Thanks!Hi, I have a multi-agent reinforcment learning environment with two agents. One agent is pretrained (agentA) and the perofrmance is good. I need to train another one (agentB) to cooperate with agentA. I’m wondering if I can only train agentB and keep agentA unchanged so its performance will not be influenced.
Thanks! Hi, I have a multi-agent reinforcment learning environment with two agents. One agent is pretrained (agentA) and the perofrmance is good. I need to train another one (agentB) to cooperate with agentA. I’m wondering if I can only train agentB and keep agentA unchanged so its performance will not be influenced.
Thanks! multi-agent reinforcement learning MATLAB Answers — New Questions
Hydraulic control of an excavator
Hello,
I have a submarine excavator which uses hydraulic pumps and hoses for its motions. Sometimes the excavator stays at the bottom of the sea for days, so when i stop the oil pumps ,I need to compensate the neggative pressure of the water by adding positive pressure in my oil circuit and keep it constand. For example at 50 meters depth i have to keep 5 bar of oil pressure inside my circuit. Which type of oil pressure valve can I use?
thank you.Hello,
I have a submarine excavator which uses hydraulic pumps and hoses for its motions. Sometimes the excavator stays at the bottom of the sea for days, so when i stop the oil pumps ,I need to compensate the neggative pressure of the water by adding positive pressure in my oil circuit and keep it constand. For example at 50 meters depth i have to keep 5 bar of oil pressure inside my circuit. Which type of oil pressure valve can I use?
thank you. Hello,
I have a submarine excavator which uses hydraulic pumps and hoses for its motions. Sometimes the excavator stays at the bottom of the sea for days, so when i stop the oil pumps ,I need to compensate the neggative pressure of the water by adding positive pressure in my oil circuit and keep it constand. For example at 50 meters depth i have to keep 5 bar of oil pressure inside my circuit. Which type of oil pressure valve can I use?
thank you. oil circuit control MATLAB Answers — New Questions
Index exceeds the number of array elements. Index must not exceed 1. Error in Sim (line 82) time_to_50_percent = t(idx_50_percent)-t(peak_time_idx) ; Error in KFKB_3D_plot (
Index exceeds the number of array elements. Index must not exceed 1.
Error in Sim (line 82)
time_to_50_percent = t(idx_50_percent)-t(peak_time_idx) ;
Error in KFKB_3D_plot (line 36)
Rpeak,T_peak_Afterligand ,remaining_ligand,Ratio_After_ligand,Delta1 ,KF_LMaxA, KF_LMaxB, kf_L, kb_1] = Sim(Kf1Max, L_Active, L_min, TauKFON, TauKFOFF, …Index exceeds the number of array elements. Index must not exceed 1.
Error in Sim (line 82)
time_to_50_percent = t(idx_50_percent)-t(peak_time_idx) ;
Error in KFKB_3D_plot (line 36)
Rpeak,T_peak_Afterligand ,remaining_ligand,Ratio_After_ligand,Delta1 ,KF_LMaxA, KF_LMaxB, kf_L, kb_1] = Sim(Kf1Max, L_Active, L_min, TauKFON, TauKFOFF, … Index exceeds the number of array elements. Index must not exceed 1.
Error in Sim (line 82)
time_to_50_percent = t(idx_50_percent)-t(peak_time_idx) ;
Error in KFKB_3D_plot (line 36)
Rpeak,T_peak_Afterligand ,remaining_ligand,Ratio_After_ligand,Delta1 ,KF_LMaxA, KF_LMaxB, kf_L, kb_1] = Sim(Kf1Max, L_Active, L_min, TauKFON, TauKFOFF, … @voss, @diymanjosh MATLAB Answers — New Questions
Creating a submatrix from a matrix
I want a code to create a matrix which consist of rows and columns of another matrix.
i.e. A (4X4) = [ 1 2 3 4; 5 6 7 8; 1 3 5 7; 2 4 6 8; ]
The submatrix B consist of the { 1, 2, 4 }rows of A and the { 2,3 }columns of A:
Β (3Χ2) = [ 2 3; 6 7; 4 6; ]
Any help could be useful.
Thanks in advance!I want a code to create a matrix which consist of rows and columns of another matrix.
i.e. A (4X4) = [ 1 2 3 4; 5 6 7 8; 1 3 5 7; 2 4 6 8; ]
The submatrix B consist of the { 1, 2, 4 }rows of A and the { 2,3 }columns of A:
Β (3Χ2) = [ 2 3; 6 7; 4 6; ]
Any help could be useful.
Thanks in advance! I want a code to create a matrix which consist of rows and columns of another matrix.
i.e. A (4X4) = [ 1 2 3 4; 5 6 7 8; 1 3 5 7; 2 4 6 8; ]
The submatrix B consist of the { 1, 2, 4 }rows of A and the { 2,3 }columns of A:
Β (3Χ2) = [ 2 3; 6 7; 4 6; ]
Any help could be useful.
Thanks in advance! matrix manipulation, submatrix MATLAB Answers — New Questions
Error Using Integers in MATLAB
How to correct the following error:
Error using +
Integers can only be combined with integers of the same class, or scalar doubles.
Error in Computerassignment5b042824 (line 28)
received_signal_low = modulated_bits + noise_low;
clc;
clear all;
% Task 1: Simulate transmission of lenna.pgm image using BPSK
% Read the image
img = imread(‘lenna.png’);
% Convert image to bits
img_bits = reshape(de2bi(img(:), 8, ‘left-msb’).’, [], 1);
% BPSK modulation
modulated_bits = 2*img_bits – 1;
% Eb/No values in dB
EbNo_low = 0;
EbNo_high = 4;
% Additive White Gaussian Noise (AWGN) channel
SNR_low = 10^(EbNo_low/10);
SNR_high = 10^(EbNo_high/10);
% Generate noise
noise_low = sqrt(1/SNR_low)*randn(size(modulated_bits));
noise_high = sqrt(1/SNR_high)*randn(size(modulated_bits));
% Received signals at low and high SNR
received_signal_low = modulated_bits + noise_low;
received_signal_high = modulated_bits + noise_high;
% BPSK demodulation
demodulated_bits_low = sign(received_signal_low);
demodulated_bits_high = sign(received_signal_high);
% Convert bits back to image
received_img_low = reshape((demodulated_bits_low + 1) / 2, 8, []).’;
received_img_high = reshape((demodulated_bits_high + 1) / 2, 8, []).’;
% Display images
figure;
subplot(2,2,1);
imshow(img);
title(‘Original Image’);
subplot(2,2,2);
imshow(received_img_low, []);
title(‘Received Image (0 dB SNR)’);
subplot(2,2,3);
imshow(received_img_high, []);
title(‘Received Image (4 dB SNR)’);
% Task 2: Employ a linear error detection code (only detection and no correction)
% Count re-transmission requests at different SNR levels
EbNo_values = [0, 2, 4, 6, 8, 10];
retrans_requests = zeros(size(EbNo_values));
for i = 1:length(EbNo_values)
SNR = 10^(EbNo_values(i)/10);
noise = sqrt(1/SNR)*randn(size(modulated_bits));
received_signal = modulated_bits + noise;
demodulated_bits = sign(received_signal);
% Linear error detection code
% Let’s use a simple parity check code
error_idx = mod(sum(demodulated_bits == -1), 2) == 1;
if any(error_idx)
retrans_requests(i) = sum(error_idx);
else
break; % No errors, stop transmission
end
end
% Plot number of retransmission requests against SNR values
figure;
plot(EbNo_values(1:i), retrans_requests(1:i), ‘-o’);
xlabel(‘Eb/No (dB)’);
ylabel(‘Number of Retransmission Requests’);
title(‘Retransmission Requests vs. SNR’);
% Task 3: Use an error correction code using syndrome lookup table
% Error correction code
% Let’s use a (7, 4) Hamming code
enc = comm.HammingEncoder;
dec = comm.HammingDecoder;
% Corrected images at 0 dB and 4 dB SNR
corrected_img_low = correct_image(received_signal_low, enc, dec);
corrected_img_high = correct_image(received_signal_high, enc, dec);
% Display corrected images
figure;
subplot(1,2,1);
imshow(corrected_img_low, []);
title(‘Corrected Image (0 dB SNR)’);
subplot(1,2,2);
imshow(corrected_img_high, []);
title(‘Corrected Image (4 dB SNR)’);
% Function to correct image using error correction code
function corrected_img = correct_image(received_signal, enc, dec)
% BPSK demodulation
demodulated_bits = sign(received_signal);
% Perform error detection and correction
detected_bits = step(dec, demodulated_bits);
% Convert bits back to image
corrected_img = reshape((detected_bits + 1) / 2, 8, []).’;
endHow to correct the following error:
Error using +
Integers can only be combined with integers of the same class, or scalar doubles.
Error in Computerassignment5b042824 (line 28)
received_signal_low = modulated_bits + noise_low;
clc;
clear all;
% Task 1: Simulate transmission of lenna.pgm image using BPSK
% Read the image
img = imread(‘lenna.png’);
% Convert image to bits
img_bits = reshape(de2bi(img(:), 8, ‘left-msb’).’, [], 1);
% BPSK modulation
modulated_bits = 2*img_bits – 1;
% Eb/No values in dB
EbNo_low = 0;
EbNo_high = 4;
% Additive White Gaussian Noise (AWGN) channel
SNR_low = 10^(EbNo_low/10);
SNR_high = 10^(EbNo_high/10);
% Generate noise
noise_low = sqrt(1/SNR_low)*randn(size(modulated_bits));
noise_high = sqrt(1/SNR_high)*randn(size(modulated_bits));
% Received signals at low and high SNR
received_signal_low = modulated_bits + noise_low;
received_signal_high = modulated_bits + noise_high;
% BPSK demodulation
demodulated_bits_low = sign(received_signal_low);
demodulated_bits_high = sign(received_signal_high);
% Convert bits back to image
received_img_low = reshape((demodulated_bits_low + 1) / 2, 8, []).’;
received_img_high = reshape((demodulated_bits_high + 1) / 2, 8, []).’;
% Display images
figure;
subplot(2,2,1);
imshow(img);
title(‘Original Image’);
subplot(2,2,2);
imshow(received_img_low, []);
title(‘Received Image (0 dB SNR)’);
subplot(2,2,3);
imshow(received_img_high, []);
title(‘Received Image (4 dB SNR)’);
% Task 2: Employ a linear error detection code (only detection and no correction)
% Count re-transmission requests at different SNR levels
EbNo_values = [0, 2, 4, 6, 8, 10];
retrans_requests = zeros(size(EbNo_values));
for i = 1:length(EbNo_values)
SNR = 10^(EbNo_values(i)/10);
noise = sqrt(1/SNR)*randn(size(modulated_bits));
received_signal = modulated_bits + noise;
demodulated_bits = sign(received_signal);
% Linear error detection code
% Let’s use a simple parity check code
error_idx = mod(sum(demodulated_bits == -1), 2) == 1;
if any(error_idx)
retrans_requests(i) = sum(error_idx);
else
break; % No errors, stop transmission
end
end
% Plot number of retransmission requests against SNR values
figure;
plot(EbNo_values(1:i), retrans_requests(1:i), ‘-o’);
xlabel(‘Eb/No (dB)’);
ylabel(‘Number of Retransmission Requests’);
title(‘Retransmission Requests vs. SNR’);
% Task 3: Use an error correction code using syndrome lookup table
% Error correction code
% Let’s use a (7, 4) Hamming code
enc = comm.HammingEncoder;
dec = comm.HammingDecoder;
% Corrected images at 0 dB and 4 dB SNR
corrected_img_low = correct_image(received_signal_low, enc, dec);
corrected_img_high = correct_image(received_signal_high, enc, dec);
% Display corrected images
figure;
subplot(1,2,1);
imshow(corrected_img_low, []);
title(‘Corrected Image (0 dB SNR)’);
subplot(1,2,2);
imshow(corrected_img_high, []);
title(‘Corrected Image (4 dB SNR)’);
% Function to correct image using error correction code
function corrected_img = correct_image(received_signal, enc, dec)
% BPSK demodulation
demodulated_bits = sign(received_signal);
% Perform error detection and correction
detected_bits = step(dec, demodulated_bits);
% Convert bits back to image
corrected_img = reshape((detected_bits + 1) / 2, 8, []).’;
end How to correct the following error:
Error using +
Integers can only be combined with integers of the same class, or scalar doubles.
Error in Computerassignment5b042824 (line 28)
received_signal_low = modulated_bits + noise_low;
clc;
clear all;
% Task 1: Simulate transmission of lenna.pgm image using BPSK
% Read the image
img = imread(‘lenna.png’);
% Convert image to bits
img_bits = reshape(de2bi(img(:), 8, ‘left-msb’).’, [], 1);
% BPSK modulation
modulated_bits = 2*img_bits – 1;
% Eb/No values in dB
EbNo_low = 0;
EbNo_high = 4;
% Additive White Gaussian Noise (AWGN) channel
SNR_low = 10^(EbNo_low/10);
SNR_high = 10^(EbNo_high/10);
% Generate noise
noise_low = sqrt(1/SNR_low)*randn(size(modulated_bits));
noise_high = sqrt(1/SNR_high)*randn(size(modulated_bits));
% Received signals at low and high SNR
received_signal_low = modulated_bits + noise_low;
received_signal_high = modulated_bits + noise_high;
% BPSK demodulation
demodulated_bits_low = sign(received_signal_low);
demodulated_bits_high = sign(received_signal_high);
% Convert bits back to image
received_img_low = reshape((demodulated_bits_low + 1) / 2, 8, []).’;
received_img_high = reshape((demodulated_bits_high + 1) / 2, 8, []).’;
% Display images
figure;
subplot(2,2,1);
imshow(img);
title(‘Original Image’);
subplot(2,2,2);
imshow(received_img_low, []);
title(‘Received Image (0 dB SNR)’);
subplot(2,2,3);
imshow(received_img_high, []);
title(‘Received Image (4 dB SNR)’);
% Task 2: Employ a linear error detection code (only detection and no correction)
% Count re-transmission requests at different SNR levels
EbNo_values = [0, 2, 4, 6, 8, 10];
retrans_requests = zeros(size(EbNo_values));
for i = 1:length(EbNo_values)
SNR = 10^(EbNo_values(i)/10);
noise = sqrt(1/SNR)*randn(size(modulated_bits));
received_signal = modulated_bits + noise;
demodulated_bits = sign(received_signal);
% Linear error detection code
% Let’s use a simple parity check code
error_idx = mod(sum(demodulated_bits == -1), 2) == 1;
if any(error_idx)
retrans_requests(i) = sum(error_idx);
else
break; % No errors, stop transmission
end
end
% Plot number of retransmission requests against SNR values
figure;
plot(EbNo_values(1:i), retrans_requests(1:i), ‘-o’);
xlabel(‘Eb/No (dB)’);
ylabel(‘Number of Retransmission Requests’);
title(‘Retransmission Requests vs. SNR’);
% Task 3: Use an error correction code using syndrome lookup table
% Error correction code
% Let’s use a (7, 4) Hamming code
enc = comm.HammingEncoder;
dec = comm.HammingDecoder;
% Corrected images at 0 dB and 4 dB SNR
corrected_img_low = correct_image(received_signal_low, enc, dec);
corrected_img_high = correct_image(received_signal_high, enc, dec);
% Display corrected images
figure;
subplot(1,2,1);
imshow(corrected_img_low, []);
title(‘Corrected Image (0 dB SNR)’);
subplot(1,2,2);
imshow(corrected_img_high, []);
title(‘Corrected Image (4 dB SNR)’);
% Function to correct image using error correction code
function corrected_img = correct_image(received_signal, enc, dec)
% BPSK demodulation
demodulated_bits = sign(received_signal);
% Perform error detection and correction
detected_bits = step(dec, demodulated_bits);
% Convert bits back to image
corrected_img = reshape((detected_bits + 1) / 2, 8, []).’;
end integer error MATLAB Answers — New Questions
Create a MATLAB code to convert Equations of Motion for Multi DOF system (2nd Order ODEs with multiple Variables) into matrix form(Coefficient Matrices)
I got 6 Equations of Motion (second order ODEs with 6 independent variables) for a 6 DOF system by using the following Code:-
clear all;
clc;
syms L T P D M1 M2 I1 I2 x1(t) x2(t) x3(t) x4(t) x5(t) x6(t) t K1 K2 K3 K4 K5 K6 C1 C2 C3 C4 C5 C6 a b c d e f1 f2 f3 f4 f5 f6;
f1 = (M1*(diff(x1,t,2))+2*(C1+C3)*diff(x1,t)-2*C3*diff(x4)+2*(K1+K3)*x1-2*K3*x4)
f2 = (M1*(diff(x2,t,2))+2*(C2+C4)*diff(x2,t)-2*C4*diff(x5)+2*(K2+K4)*x2-2*K4*x5)
f3 = (I1*(diff(x3,t,2))+2*(C1*b^2+C2*a^2+C3*c^2+C4*e^2)*diff(x3,t))-2*(C3*c*d+C4*e^2)*diff(x6)+2*(K1*b^2+K2*a^2+K3*c^2+K4*e^2)*x3-2*(K3*c*d+K4*e^2)*x6
f4 = (M2*(diff(x4,t,2))-2*C3*diff(x1,t)+2*C3*diff(x4)-2*K3*x1+2*K3*x4)
f5 = (M2*(diff(x5,t,2))-2*C4*diff(x2,t)+2*C4*diff(x5)-2*K4*x2+2*K4*x5)
f6 = (I1*(diff(x6,t,2))+2*(C3*d^2+C4*e^2)*diff(x6,t))-2*(C3*c*d+C4*e^2)*diff(x3)+2*(K3*d^2+K4*e^2)*x6-2*(K3*c*d+K4*e^2)*x3
U can see that all Mass Coefficients are with second order derivates only, Damping(C) terms with single order derivates and Stiffness(K) terms with zero order derivates. In state space Matrix form, it can be seen as [M][Ẍ]+[C][ẋ]+[K][x] = F.
Now, I need to convert these ODEs to State space form i.e. extract the M, C & K coefficients and make 6X6 matrices.
Presently, I am manually collecting all the terms and create the matrices. However, I want a matlab code which can auto populate the matrices.
Please create a code. Thank you.I got 6 Equations of Motion (second order ODEs with 6 independent variables) for a 6 DOF system by using the following Code:-
clear all;
clc;
syms L T P D M1 M2 I1 I2 x1(t) x2(t) x3(t) x4(t) x5(t) x6(t) t K1 K2 K3 K4 K5 K6 C1 C2 C3 C4 C5 C6 a b c d e f1 f2 f3 f4 f5 f6;
f1 = (M1*(diff(x1,t,2))+2*(C1+C3)*diff(x1,t)-2*C3*diff(x4)+2*(K1+K3)*x1-2*K3*x4)
f2 = (M1*(diff(x2,t,2))+2*(C2+C4)*diff(x2,t)-2*C4*diff(x5)+2*(K2+K4)*x2-2*K4*x5)
f3 = (I1*(diff(x3,t,2))+2*(C1*b^2+C2*a^2+C3*c^2+C4*e^2)*diff(x3,t))-2*(C3*c*d+C4*e^2)*diff(x6)+2*(K1*b^2+K2*a^2+K3*c^2+K4*e^2)*x3-2*(K3*c*d+K4*e^2)*x6
f4 = (M2*(diff(x4,t,2))-2*C3*diff(x1,t)+2*C3*diff(x4)-2*K3*x1+2*K3*x4)
f5 = (M2*(diff(x5,t,2))-2*C4*diff(x2,t)+2*C4*diff(x5)-2*K4*x2+2*K4*x5)
f6 = (I1*(diff(x6,t,2))+2*(C3*d^2+C4*e^2)*diff(x6,t))-2*(C3*c*d+C4*e^2)*diff(x3)+2*(K3*d^2+K4*e^2)*x6-2*(K3*c*d+K4*e^2)*x3
U can see that all Mass Coefficients are with second order derivates only, Damping(C) terms with single order derivates and Stiffness(K) terms with zero order derivates. In state space Matrix form, it can be seen as [M][Ẍ]+[C][ẋ]+[K][x] = F.
Now, I need to convert these ODEs to State space form i.e. extract the M, C & K coefficients and make 6X6 matrices.
Presently, I am manually collecting all the terms and create the matrices. However, I want a matlab code which can auto populate the matrices.
Please create a code. Thank you. I got 6 Equations of Motion (second order ODEs with 6 independent variables) for a 6 DOF system by using the following Code:-
clear all;
clc;
syms L T P D M1 M2 I1 I2 x1(t) x2(t) x3(t) x4(t) x5(t) x6(t) t K1 K2 K3 K4 K5 K6 C1 C2 C3 C4 C5 C6 a b c d e f1 f2 f3 f4 f5 f6;
f1 = (M1*(diff(x1,t,2))+2*(C1+C3)*diff(x1,t)-2*C3*diff(x4)+2*(K1+K3)*x1-2*K3*x4)
f2 = (M1*(diff(x2,t,2))+2*(C2+C4)*diff(x2,t)-2*C4*diff(x5)+2*(K2+K4)*x2-2*K4*x5)
f3 = (I1*(diff(x3,t,2))+2*(C1*b^2+C2*a^2+C3*c^2+C4*e^2)*diff(x3,t))-2*(C3*c*d+C4*e^2)*diff(x6)+2*(K1*b^2+K2*a^2+K3*c^2+K4*e^2)*x3-2*(K3*c*d+K4*e^2)*x6
f4 = (M2*(diff(x4,t,2))-2*C3*diff(x1,t)+2*C3*diff(x4)-2*K3*x1+2*K3*x4)
f5 = (M2*(diff(x5,t,2))-2*C4*diff(x2,t)+2*C4*diff(x5)-2*K4*x2+2*K4*x5)
f6 = (I1*(diff(x6,t,2))+2*(C3*d^2+C4*e^2)*diff(x6,t))-2*(C3*c*d+C4*e^2)*diff(x3)+2*(K3*d^2+K4*e^2)*x6-2*(K3*c*d+K4*e^2)*x3
U can see that all Mass Coefficients are with second order derivates only, Damping(C) terms with single order derivates and Stiffness(K) terms with zero order derivates. In state space Matrix form, it can be seen as [M][Ẍ]+[C][ẋ]+[K][x] = F.
Now, I need to convert these ODEs to State space form i.e. extract the M, C & K coefficients and make 6X6 matrices.
Presently, I am manually collecting all the terms and create the matrices. However, I want a matlab code which can auto populate the matrices.
Please create a code. Thank you. second order ode, state space form MATLAB Answers — New Questions
How can I perform time averaging of a signal acquired with an accelerometer?
Hi, I’m trying to process some acceleration datas of a vibrating object acquired with an accelerometer. I want to perform time averaging in order to reduce noise as much as I can, but I’m not quite sure about how to compute it. Any suggestions would be highly appreciated and I thank you all in advance.Hi, I’m trying to process some acceleration datas of a vibrating object acquired with an accelerometer. I want to perform time averaging in order to reduce noise as much as I can, but I’m not quite sure about how to compute it. Any suggestions would be highly appreciated and I thank you all in advance. Hi, I’m trying to process some acceleration datas of a vibrating object acquired with an accelerometer. I want to perform time averaging in order to reduce noise as much as I can, but I’m not quite sure about how to compute it. Any suggestions would be highly appreciated and I thank you all in advance. signal processing MATLAB Answers — New Questions
If Else if statement problem
Write a program that takes the grades of several students as a vector and
Do the following(the grade should be between 0to 20):
Use the “for”and conditional commands end-else-if to check each grade
and change them as follows:
Change scores less than 5 to 9
Change scores between 5 and 8 to 9.5.
Change scores between 8 and 10 to 10.
Increase scores between 10 and 15 by 1 score
To increase scores more than 15 and less than 20 by 0.5 points.Write a program that takes the grades of several students as a vector and
Do the following(the grade should be between 0to 20):
Use the “for”and conditional commands end-else-if to check each grade
and change them as follows:
Change scores less than 5 to 9
Change scores between 5 and 8 to 9.5.
Change scores between 8 and 10 to 10.
Increase scores between 10 and 15 by 1 score
To increase scores more than 15 and less than 20 by 0.5 points. Write a program that takes the grades of several students as a vector and
Do the following(the grade should be between 0to 20):
Use the “for”and conditional commands end-else-if to check each grade
and change them as follows:
Change scores less than 5 to 9
Change scores between 5 and 8 to 9.5.
Change scores between 8 and 10 to 10.
Increase scores between 10 and 15 by 1 score
To increase scores more than 15 and less than 20 by 0.5 points. #if MATLAB Answers — New Questions