I have my license at home I’m leaving for holidays, bringing my work from home on a new laptop I go to deactivate the license on the 2 PCs but when installed on the new laptop it continues to give me an error…(I read the discussions on the matter but I don’t understand)
how can I use matlab on my new laptop?I have my license at home I’m leaving for holidays, bringing my work from home on a new laptop I go to deactivate the license on the 2 PCs but when installed on the new laptop it continues to give me an error…(I read the discussions on the matter but I don’t understand)
how can I use matlab on my new laptop? I have my license at home I’m leaving for holidays, bringing my work from home on a new laptop I go to deactivate the license on the 2 PCs but when installed on the new laptop it continues to give me an error…(I read the discussions on the matter but I don’t understand)
how can I use matlab on my new laptop? "error 354 " MATLAB Answers — New Questions

​

Suppose I have the finite field F_3={0,1,2}. Suppose I have the following equations:
1=x_1+x_4+x_5
0=x_2+x_5+x_6
0=x_3+x_4+x_6
where each x_i is a member of F_3. How Can I obtain the set of all possible combinations for the solutions of the above equations?

Thanks for any help in advance.Suppose I have the finite field F_3={0,1,2}. Suppose I have the following equations:
1=x_1+x_4+x_5
0=x_2+x_5+x_6
0=x_3+x_4+x_6
where each x_i is a member of F_3. How Can I obtain the set of all possible combinations for the solutions of the above equations?

Thanks for any help in advance. Suppose I have the finite field F_3={0,1,2}. Suppose I have the following equations:
1=x_1+x_4+x_5
0=x_2+x_5+x_6
0=x_3+x_4+x_6
where each x_i is a member of F_3. How Can I obtain the set of all possible combinations for the solutions of the above equations?

Thanks for any help in advance. system of equations, modular arithmetic, finite field MATLAB Answers — New Questions

​

Hello everyone,

I am trying to solve some differential equation in matlab using ode45. The equations are as shown below:

I have written the equations in state space form where ydot_1(i) is , ydot_2(i) is , ydot_3(i) is and ydot_4(i) is . In the equation of motion of x, eq.2, x terms are not in terms of “ i “ but I have written them like that (so ydot_3(i) is and ydot_4(i) is ) because of the loop that I use on the function below. So the “for” loop, for each time step, solves first the ydot terms for each mode for i = 1:n and then gets out of the loop, goes to the new time step and then solve again for each mode. However, since for each time step it will start from the first mode, and ydot_1(i) and ydot_2(i) depend on ydot_3(i) and ydot_4(i) , then I am solving the equation of x, eq.2, for each mode. For the new time step, before starting with the first mode again I am defining the
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

so it can start with the data from the previous first mode (first mode of the previous time step).

My problem is that when I solve for 1 mode only, so for n=1 and get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); and then solve for n=2 but still get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); for the first mode only, these first modes do not match. The solution have the same shape but differ in amplitude. The same happens with I use n=20, for example, but again plot only the first mode du_1. The solution changes from the first mode obtained when n=2 and from the first mode obtained for n=1. I have checked for days and cant see my mistake so have reached desperation.
Would really appreciate your help! Thank youuu!

clear all
clc
global xi xi_b r_w r_m mu_s mu_k v alpha P l a w l_0 n x_c_prev x_c_prev_modes
dt=0.01;
tspan = (0:dt:150).’;
% parameters
xi=0.14;
xi_b=0.0025;
r_w=4.5;
r_m=4.8;
mu_s=0.5;
mu_k=0.2 ;
alpha=300;
P=0.002;
l=1/75;
l_0=0.25;
a=0;
w=9;

v=0.005;
% Initialize y_c_prev and the array to store x_c values
x_c_prev = 0;
global t_values x_c_values; % Declare t_values and x_c_values as global
t_values = tspan; % Store time values
x_c_values = zeros(size(tspan)); % Initialize array to store x_c values
n=1;
y0 = zeros(4*n,1);
y0(3*n+1) = -v;
% Initialize y_c_prev
x_c_prev = 0;
% Define your initial value for x_c_prev
x_c_prev_initial = 0;
% Initialize x_c_prev_modes, assuming you have ‘n’ modes
x_c_prev_modes = cell(1, n);
% Initialize the first mode’s x_c_prev
x_c_prev_modes{1} = x_c_prev_initial;
[t,y] = ode45(@rhs_cont4,tspan,y0);
zero_indices = find(x_c_values == 0);
% Iterate over zero indices and replace with mean of neighboring non-zero elements
for i = 1:length(zero_indices)
idx = zero_indices(i);
left_idx = idx – 1;
right_idx = idx + 1;
% Find the nearest non-zero elements
while left_idx > 0 && x_c_values(left_idx) == 0
left_idx = left_idx – 1;
end
while right_idx <= length(x_c_values) && x_c_values(right_idx) == 0
right_idx = right_idx + 1;
end
% Replace zero with mean of neighboring non-zero elements
if left_idx > 0 && right_idx <= length(x_c_values)
x_c_values(idx) = (x_c_values(left_idx) + x_c_values(right_idx)) / 2;
elseif left_idx > 0
x_c_values(idx) = x_c_values(left_idx);
elseif right_idx <= length(x_c_values)
x_c_values(idx) = x_c_values(right_idx);
else
% If there are no non-zero neighbors, we can’t replace it, so skip
continue;
end
end
x_c_values_new=x_c_values;
for i=1:1

u_1= y(:,i).*sin(i*pi.* x_c_values_new);
du_1= y(:,n+i).*sin(i*pi.* x_c_values_new);

end
figure
plot(t,du_1)
legend("beam vel mode 1")

and the function is saved separately
function ydot=rhs_cont4(t,y)
global xi xi_b r_w r_m mu_s mu_k v alpha P a w l_0 n x_c_prev x_c_prev_modes
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

for i = 1:n

x_m=y(i)*sin(i*pi*x_c_prev)+x_m;
x_c=y(2*n+i)+v*t+l_0-x_m;
x_c_prev = x_c; % Update x_c_prev for the next iteration
x_c_prev_modes{i} = x_c_prev;
%Store x_c values at the corresponding time step
global t_values x_c_values; % Access global variables
[~, idx] = min(abs(t – t_values)); % Find the index of the closest time step
x_c_values(idx) = x_c; % Store x_c at the corresponding time step
v_m=y(n+i)*sin(i*pi*x_c)+v_m;
ydot_1(i) = y(n+i);
ydot_2(i) = -2*xi_b*r_w*y(n+i)-(r_w*i)^2*y(i)+2*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P*sin(i*pi*x_c);
ydot_3(i) =y(3*n+i);
ydot_4(i) =-2*xi*y(3*n+i)-y(2*n+i)-r_m*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P+a*w^2*sin(w*t);

end
ydot = [ydot_1; ydot_2; ydot_3; ydot_4];
endHello everyone,

I am trying to solve some differential equation in matlab using ode45. The equations are as shown below:

I have written the equations in state space form where ydot_1(i) is , ydot_2(i) is , ydot_3(i) is and ydot_4(i) is . In the equation of motion of x, eq.2, x terms are not in terms of “ i “ but I have written them like that (so ydot_3(i) is and ydot_4(i) is ) because of the loop that I use on the function below. So the “for” loop, for each time step, solves first the ydot terms for each mode for i = 1:n and then gets out of the loop, goes to the new time step and then solve again for each mode. However, since for each time step it will start from the first mode, and ydot_1(i) and ydot_2(i) depend on ydot_3(i) and ydot_4(i) , then I am solving the equation of x, eq.2, for each mode. For the new time step, before starting with the first mode again I am defining the
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

so it can start with the data from the previous first mode (first mode of the previous time step).

My problem is that when I solve for 1 mode only, so for n=1 and get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); and then solve for n=2 but still get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); for the first mode only, these first modes do not match. The solution have the same shape but differ in amplitude. The same happens with I use n=20, for example, but again plot only the first mode du_1. The solution changes from the first mode obtained when n=2 and from the first mode obtained for n=1. I have checked for days and cant see my mistake so have reached desperation.
Would really appreciate your help! Thank youuu!

clear all
clc
global xi xi_b r_w r_m mu_s mu_k v alpha P l a w l_0 n x_c_prev x_c_prev_modes
dt=0.01;
tspan = (0:dt:150).’;
% parameters
xi=0.14;
xi_b=0.0025;
r_w=4.5;
r_m=4.8;
mu_s=0.5;
mu_k=0.2 ;
alpha=300;
P=0.002;
l=1/75;
l_0=0.25;
a=0;
w=9;

v=0.005;
% Initialize y_c_prev and the array to store x_c values
x_c_prev = 0;
global t_values x_c_values; % Declare t_values and x_c_values as global
t_values = tspan; % Store time values
x_c_values = zeros(size(tspan)); % Initialize array to store x_c values
n=1;
y0 = zeros(4*n,1);
y0(3*n+1) = -v;
% Initialize y_c_prev
x_c_prev = 0;
% Define your initial value for x_c_prev
x_c_prev_initial = 0;
% Initialize x_c_prev_modes, assuming you have ‘n’ modes
x_c_prev_modes = cell(1, n);
% Initialize the first mode’s x_c_prev
x_c_prev_modes{1} = x_c_prev_initial;
[t,y] = ode45(@rhs_cont4,tspan,y0);
zero_indices = find(x_c_values == 0);
% Iterate over zero indices and replace with mean of neighboring non-zero elements
for i = 1:length(zero_indices)
idx = zero_indices(i);
left_idx = idx – 1;
right_idx = idx + 1;
% Find the nearest non-zero elements
while left_idx > 0 && x_c_values(left_idx) == 0
left_idx = left_idx – 1;
end
while right_idx <= length(x_c_values) && x_c_values(right_idx) == 0
right_idx = right_idx + 1;
end
% Replace zero with mean of neighboring non-zero elements
if left_idx > 0 && right_idx <= length(x_c_values)
x_c_values(idx) = (x_c_values(left_idx) + x_c_values(right_idx)) / 2;
elseif left_idx > 0
x_c_values(idx) = x_c_values(left_idx);
elseif right_idx <= length(x_c_values)
x_c_values(idx) = x_c_values(right_idx);
else
% If there are no non-zero neighbors, we can’t replace it, so skip
continue;
end
end
x_c_values_new=x_c_values;
for i=1:1

u_1= y(:,i).*sin(i*pi.* x_c_values_new);
du_1= y(:,n+i).*sin(i*pi.* x_c_values_new);

end
figure
plot(t,du_1)
legend("beam vel mode 1")

and the function is saved separately
function ydot=rhs_cont4(t,y)
global xi xi_b r_w r_m mu_s mu_k v alpha P a w l_0 n x_c_prev x_c_prev_modes
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

for i = 1:n

x_m=y(i)*sin(i*pi*x_c_prev)+x_m;
x_c=y(2*n+i)+v*t+l_0-x_m;
x_c_prev = x_c; % Update x_c_prev for the next iteration
x_c_prev_modes{i} = x_c_prev;
%Store x_c values at the corresponding time step
global t_values x_c_values; % Access global variables
[~, idx] = min(abs(t – t_values)); % Find the index of the closest time step
x_c_values(idx) = x_c; % Store x_c at the corresponding time step
v_m=y(n+i)*sin(i*pi*x_c)+v_m;
ydot_1(i) = y(n+i);
ydot_2(i) = -2*xi_b*r_w*y(n+i)-(r_w*i)^2*y(i)+2*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P*sin(i*pi*x_c);
ydot_3(i) =y(3*n+i);
ydot_4(i) =-2*xi*y(3*n+i)-y(2*n+i)-r_m*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P+a*w^2*sin(w*t);

end
ydot = [ydot_1; ydot_2; ydot_3; ydot_4];
end Hello everyone,

I am trying to solve some differential equation in matlab using ode45. The equations are as shown below:

I have written the equations in state space form where ydot_1(i) is , ydot_2(i) is , ydot_3(i) is and ydot_4(i) is . In the equation of motion of x, eq.2, x terms are not in terms of “ i “ but I have written them like that (so ydot_3(i) is and ydot_4(i) is ) because of the loop that I use on the function below. So the “for” loop, for each time step, solves first the ydot terms for each mode for i = 1:n and then gets out of the loop, goes to the new time step and then solve again for each mode. However, since for each time step it will start from the first mode, and ydot_1(i) and ydot_2(i) depend on ydot_3(i) and ydot_4(i) , then I am solving the equation of x, eq.2, for each mode. For the new time step, before starting with the first mode again I am defining the
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

so it can start with the data from the previous first mode (first mode of the previous time step).

My problem is that when I solve for 1 mode only, so for n=1 and get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); and then solve for n=2 but still get the solution du_1= y(:,n+i).*sin(i*pi.* x_c_values_new); for the first mode only, these first modes do not match. The solution have the same shape but differ in amplitude. The same happens with I use n=20, for example, but again plot only the first mode du_1. The solution changes from the first mode obtained when n=2 and from the first mode obtained for n=1. I have checked for days and cant see my mistake so have reached desperation.
Would really appreciate your help! Thank youuu!

clear all
clc
global xi xi_b r_w r_m mu_s mu_k v alpha P l a w l_0 n x_c_prev x_c_prev_modes
dt=0.01;
tspan = (0:dt:150).’;
% parameters
xi=0.14;
xi_b=0.0025;
r_w=4.5;
r_m=4.8;
mu_s=0.5;
mu_k=0.2 ;
alpha=300;
P=0.002;
l=1/75;
l_0=0.25;
a=0;
w=9;

v=0.005;
% Initialize y_c_prev and the array to store x_c values
x_c_prev = 0;
global t_values x_c_values; % Declare t_values and x_c_values as global
t_values = tspan; % Store time values
x_c_values = zeros(size(tspan)); % Initialize array to store x_c values
n=1;
y0 = zeros(4*n,1);
y0(3*n+1) = -v;
% Initialize y_c_prev
x_c_prev = 0;
% Define your initial value for x_c_prev
x_c_prev_initial = 0;
% Initialize x_c_prev_modes, assuming you have ‘n’ modes
x_c_prev_modes = cell(1, n);
% Initialize the first mode’s x_c_prev
x_c_prev_modes{1} = x_c_prev_initial;
[t,y] = ode45(@rhs_cont4,tspan,y0);
zero_indices = find(x_c_values == 0);
% Iterate over zero indices and replace with mean of neighboring non-zero elements
for i = 1:length(zero_indices)
idx = zero_indices(i);
left_idx = idx – 1;
right_idx = idx + 1;
% Find the nearest non-zero elements
while left_idx > 0 && x_c_values(left_idx) == 0
left_idx = left_idx – 1;
end
while right_idx <= length(x_c_values) && x_c_values(right_idx) == 0
right_idx = right_idx + 1;
end
% Replace zero with mean of neighboring non-zero elements
if left_idx > 0 && right_idx <= length(x_c_values)
x_c_values(idx) = (x_c_values(left_idx) + x_c_values(right_idx)) / 2;
elseif left_idx > 0
x_c_values(idx) = x_c_values(left_idx);
elseif right_idx <= length(x_c_values)
x_c_values(idx) = x_c_values(right_idx);
else
% If there are no non-zero neighbors, we can’t replace it, so skip
continue;
end
end
x_c_values_new=x_c_values;
for i=1:1

u_1= y(:,i).*sin(i*pi.* x_c_values_new);
du_1= y(:,n+i).*sin(i*pi.* x_c_values_new);

end
figure
plot(t,du_1)
legend("beam vel mode 1")

and the function is saved separately
function ydot=rhs_cont4(t,y)
global xi xi_b r_w r_m mu_s mu_k v alpha P a w l_0 n x_c_prev x_c_prev_modes
ydot_1=y(1:n); %displacement beam
ydot_2=y(n+1:2*n); %velocity beam
ydot_3=y(2*n+1:3*n); %displacement mass
ydot_4=y(3*n+1:4*n); %velocity mass
v_m=0;
x_m=0;
x_c_prev = x_c_prev_modes{1};

for i = 1:n

x_m=y(i)*sin(i*pi*x_c_prev)+x_m;
x_c=y(2*n+i)+v*t+l_0-x_m;
x_c_prev = x_c; % Update x_c_prev for the next iteration
x_c_prev_modes{i} = x_c_prev;
%Store x_c values at the corresponding time step
global t_values x_c_values; % Access global variables
[~, idx] = min(abs(t – t_values)); % Find the index of the closest time step
x_c_values(idx) = x_c; % Store x_c at the corresponding time step
v_m=y(n+i)*sin(i*pi*x_c)+v_m;
ydot_1(i) = y(n+i);
ydot_2(i) = -2*xi_b*r_w*y(n+i)-(r_w*i)^2*y(i)+2*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P*sin(i*pi*x_c);
ydot_3(i) =y(3*n+i);
ydot_4(i) =-2*xi*y(3*n+i)-y(2*n+i)-r_m*sign(y(3*n+i)+v-v_m)*(mu_k+(mu_s-mu_k)*exp(-alpha*abs(y(3*n+i)+v-v_m)))*P+a*w^2*sin(w*t);

end
ydot = [ydot_1; ydot_2; ydot_3; ydot_4];
end ode45, differential equations, for loop MATLAB Answers — New Questions

​

I am trying to plot data from multiple text csv files in a folder. This is the first part of my code:
folder_path = ‘C:userspowerdownloadsstar capillary files’; % Replace with your folder path
% List all TXT files in the folder
txt_files = dir(fullfile(folder_path, ‘*.txt’));
for file_idx = 1:length(txt_files)
filename = fullfile(folder_path, txt_files(file_idx).name);

% Load the TXT file
data = readtable(filename, ‘Delimiter’, ‘,’);

Matlab is not recognizing that there are text files in my folder, though there are. I wrote a similar code to make calculations from a single txt file in that folder and it works. Does anyone know why it might not be recognizing txt files with this code? I added the folder to path in the matlab software by right clicking. Any help would be extremely appreciated!I am trying to plot data from multiple text csv files in a folder. This is the first part of my code:
folder_path = ‘C:userspowerdownloadsstar capillary files’; % Replace with your folder path
% List all TXT files in the folder
txt_files = dir(fullfile(folder_path, ‘*.txt’));
for file_idx = 1:length(txt_files)
filename = fullfile(folder_path, txt_files(file_idx).name);

% Load the TXT file
data = readtable(filename, ‘Delimiter’, ‘,’);

Matlab is not recognizing that there are text files in my folder, though there are. I wrote a similar code to make calculations from a single txt file in that folder and it works. Does anyone know why it might not be recognizing txt files with this code? I added the folder to path in the matlab software by right clicking. Any help would be extremely appreciated! I am trying to plot data from multiple text csv files in a folder. This is the first part of my code:
folder_path = ‘C:userspowerdownloadsstar capillary files’; % Replace with your folder path
% List all TXT files in the folder
txt_files = dir(fullfile(folder_path, ‘*.txt’));
for file_idx = 1:length(txt_files)
filename = fullfile(folder_path, txt_files(file_idx).name);

% Load the TXT file
data = readtable(filename, ‘Delimiter’, ‘,’);

Matlab is not recognizing that there are text files in my folder, though there are. I wrote a similar code to make calculations from a single txt file in that folder and it works. Does anyone know why it might not be recognizing txt files with this code? I added the folder to path in the matlab software by right clicking. Any help would be extremely appreciated! text file MATLAB Answers — New Questions

​

Hello all,
For a project, I am making use of the For Each subsystem in my Simulink model. I have a set of values for one of the input variables of the block and the goal is to have Simulink generate a set of outputs for each input value. The number of input and output will be different with configurations "N". The For Each subsystem works great for this purpose, but unfortunately the Coder cannot convert it to C code. How could I make use an N as exportgloabl with For Each subsystem?Hello all,
For a project, I am making use of the For Each subsystem in my Simulink model. I have a set of values for one of the input variables of the block and the goal is to have Simulink generate a set of outputs for each input value. The number of input and output will be different with configurations "N". The For Each subsystem works great for this purpose, but unfortunately the Coder cannot convert it to C code. How could I make use an N as exportgloabl with For Each subsystem? Hello all,
For a project, I am making use of the For Each subsystem in my Simulink model. I have a set of values for one of the input variables of the block and the goal is to have Simulink generate a set of outputs for each input value. The number of input and output will be different with configurations "N". The For Each subsystem works great for this purpose, but unfortunately the Coder cannot convert it to C code. How could I make use an N as exportgloabl with For Each subsystem? for each, config, global MATLAB Answers — New Questions

​

Is there a function which seeks through the stacked plot as a video. I have a 15000 data points,
s=stackedplot(data)
Can we save this stacked plot as a video ?Is there a function which seeks through the stacked plot as a video. I have a 15000 data points,
s=stackedplot(data)
Can we save this stacked plot as a video ? Is there a function which seeks through the stacked plot as a video. I have a 15000 data points,
s=stackedplot(data)
Can we save this stacked plot as a video ? stackedplot, video, graph to video MATLAB Answers — New Questions

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Let’s say I have a set of numbers A=-5,-4,-3,-2,-1,0,1,2,3,4,5
and I want to pick those pairs that give a sum of 1. For example, -2 and 3 is one possible pair, but how do we display all such pairs?

Any help will be much appreciated.Let’s say I have a set of numbers A=-5,-4,-3,-2,-1,0,1,2,3,4,5
and I want to pick those pairs that give a sum of 1. For example, -2 and 3 is one possible pair, but how do we display all such pairs?

Any help will be much appreciated. Let’s say I have a set of numbers A=-5,-4,-3,-2,-1,0,1,2,3,4,5
and I want to pick those pairs that give a sum of 1. For example, -2 and 3 is one possible pair, but how do we display all such pairs?

Any help will be much appreciated. matlab code, selecting elements from a set MATLAB Answers — New Questions

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I can no longer determine what update release number of MATLAB I am using when running the following commands

&gt;&gt; version -description

ans =

  0×0 empty char array

&gt;&gt; ver -support
MATLAB Version: 9.13.0.2049777 (R2022b)
It is important to know which version of MATLAB my team members and I are using. Please advise me on where I can find this information.I can no longer determine what update release number of MATLAB I am using when running the following commands

&gt;&gt; version -description

ans =

  0×0 empty char array

&gt;&gt; ver -support
MATLAB Version: 9.13.0.2049777 (R2022b)
It is important to know which version of MATLAB my team members and I are using. Please advise me on where I can find this information. I can no longer determine what update release number of MATLAB I am using when running the following commands

&gt;&gt; version -description

ans =

  0×0 empty char array

&gt;&gt; ver -support
MATLAB Version: 9.13.0.2049777 (R2022b)
It is important to know which version of MATLAB my team members and I are using. Please advise me on where I can find this information. package, release, number, version MATLAB Answers — New Questions

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I use a lot of customizable block for the simulation demo like vertical gauge, slider, etc.
now i want to create standalone app, which i believe i need to create a new GUI using app designer.
However, there is no customizable vertical gauge on App designer’s library component.
Is there any way to "copy+paste" simulink dashboard to App designer ?I use a lot of customizable block for the simulation demo like vertical gauge, slider, etc.
now i want to create standalone app, which i believe i need to create a new GUI using app designer.
However, there is no customizable vertical gauge on App designer’s library component.
Is there any way to "copy+paste" simulink dashboard to App designer ? I use a lot of customizable block for the simulation demo like vertical gauge, slider, etc.
now i want to create standalone app, which i believe i need to create a new GUI using app designer.
However, there is no customizable vertical gauge on App designer’s library component.
Is there any way to "copy+paste" simulink dashboard to App designer ? simulink dashboard, appdesigner, standalone application MATLAB Answers — New Questions

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Is there a block ready to be used to model a shell and tube flooded evaporator using Ammonia as a refrigerant?Is there a block ready to be used to model a shell and tube flooded evaporator using Ammonia as a refrigerant? Is there a block ready to be used to model a shell and tube flooded evaporator using Ammonia as a refrigerant? heat-transfer, evaporators, simulink, fluids MATLAB Answers — New Questions

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