have a problem while zooming in in the scope, it isn’t working.
I’m working on matlab 2015b for mac.have a problem while zooming in in the scope, it isn’t working.
I’m working on matlab 2015b for mac. have a problem while zooming in in the scope, it isn’t working.
I’m working on matlab 2015b for mac. simulink, scope, matlab for osx MATLAB Answers — New Questions

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Is there any way to write all of an if-statement in a single line?

if A == 1 B = 2 elseif B = 3 endIs there any way to write all of an if-statement in a single line?

if A == 1 B = 2 elseif B = 3 end Is there any way to write all of an if-statement in a single line?

if A == 1 B = 2 elseif B = 3 end if-statements MATLAB Answers — New Questions

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Hi,
I good patients data. I did population fit ‘mixed effect’. The fits for individual patients were very good but the population fit was not good for a few parameters. How could I solve that?

Also, for a few parameters, the population estimated parameters values were the same as individual estimated parameters values. I don’t know why did that happen. How could I solve that?

Thank you.Hi,
I good patients data. I did population fit ‘mixed effect’. The fits for individual patients were very good but the population fit was not good for a few parameters. How could I solve that?

Also, for a few parameters, the population estimated parameters values were the same as individual estimated parameters values. I don’t know why did that happen. How could I solve that?

Thank you. Hi,
I good patients data. I did population fit ‘mixed effect’. The fits for individual patients were very good but the population fit was not good for a few parameters. How could I solve that?

Also, for a few parameters, the population estimated parameters values were the same as individual estimated parameters values. I don’t know why did that happen. How could I solve that?

Thank you. population fit miyed effect MATLAB Answers — New Questions

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Hello,
I am recieving the following error:
Error:External Mode Open Protocol Connect command failed
Caused by:
Could not connect to target application: XCP internal error: timeout expired, in response to XCP CONNECT command

I have seen numorous people ask about this error on this forum. None of the proposed solutions have worked for me. I have checked my add-ons. I have checked device manager. I have made sure I am using the right .ccxml file.

The model:

Device Manager:

Hardware Implementation:

Since the other discussion on this forum haven’t helped, I am wondering if I am experiencing something with a more uncommon cause. Thank you for your help!Hello,
I am recieving the following error:
Error:External Mode Open Protocol Connect command failed
Caused by:
Could not connect to target application: XCP internal error: timeout expired, in response to XCP CONNECT command

I have seen numorous people ask about this error on this forum. None of the proposed solutions have worked for me. I have checked my add-ons. I have checked device manager. I have made sure I am using the right .ccxml file.

The model:

Device Manager:

Hardware Implementation:

Since the other discussion on this forum haven’t helped, I am wondering if I am experiencing something with a more uncommon cause. Thank you for your help! Hello,
I am recieving the following error:
Error:External Mode Open Protocol Connect command failed
Caused by:
Could not connect to target application: XCP internal error: timeout expired, in response to XCP CONNECT command

I have seen numorous people ask about this error on this forum. None of the proposed solutions have worked for me. I have checked my add-ons. I have checked device manager. I have made sure I am using the right .ccxml file.

The model:

Device Manager:

Hardware Implementation:

Since the other discussion on this forum haven’t helped, I am wondering if I am experiencing something with a more uncommon cause. Thank you for your help! simulink, code generation, c2000, xcd MATLAB Answers — New Questions

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I have a gas tank (lets say 1m3 volume) with a hole in it. The gas at 6 bar pressure starts leaking through the hole. How do I model the gas pressure in the tank with respect to time after the leakage begins? I want to model it in the simscape.I have a gas tank (lets say 1m3 volume) with a hole in it. The gas at 6 bar pressure starts leaking through the hole. How do I model the gas pressure in the tank with respect to time after the leakage begins? I want to model it in the simscape. I have a gas tank (lets say 1m3 volume) with a hole in it. The gas at 6 bar pressure starts leaking through the hole. How do I model the gas pressure in the tank with respect to time after the leakage begins? I want to model it in the simscape. simscape, gas, simulink MATLAB Answers — New Questions

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I am using Matlab on a remote system. I use the -nodesktop flag and interact via command line.
I use trainnet to train deep learning networks. I would like to save and export the training-progress plots for viewing on a local system. Is this possible and if so, how do I do it?
Thank you.I am using Matlab on a remote system. I use the -nodesktop flag and interact via command line.
I use trainnet to train deep learning networks. I would like to save and export the training-progress plots for viewing on a local system. Is this possible and if so, how do I do it?
Thank you. I am using Matlab on a remote system. I use the -nodesktop flag and interact via command line.
I use trainnet to train deep learning networks. I would like to save and export the training-progress plots for viewing on a local system. Is this possible and if so, how do I do it?
Thank you. trainnet MATLAB Answers — New Questions

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(3^.5)*sind(x)*(p.)+cosd(x)*(p.)-800(3^.5)*sind(x)*(p.)+cosd(x)*(p.)-800 (3^.5)*sind(x)*(p.)+cosd(x)*(p.)-800 matlab code MATLAB Answers — New Questions

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I want to find what’s in my table that’s in a category column 1
If you read through you will see what I tries and how I finally figured it out. I’m posing the question because I can’t be the only person that wanted to do this simple (but not clearly and simply documented)
Starting with a text file:
HEADER that is ignored
R 0 5
L 5 0
Set up how I want the table (not that MATLAB will pay any attention)
app.StimInputTable.Data = table(‘Size’,[4 3],…
‘VariableTypes’,{‘categorical’,’uint8′,’uint8′});
What did I get? Got what I asked for
K>> class (app.StimInputTable.Data.Var1)
ans =
‘categorical’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘uint8’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘uint8’
Read in the file
app.StimInputTable.Data = readtable(infile);
MATLAB changes all the types
K>> class (app.StimInputTable.Data.Var1)
ans =
‘cell’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘double’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘double’
I can redo the .. table(… VariableTypes), but then it tosses all my category data instead of converting
So here’s my table, I can deal with the cells
K>> app.StimInputTable.Data
ans =
2×3 table
Var1 Var2 Var3
_____ ____ ____
{‘L’} 5 0
{‘R’} 0 5
So the char is considered a cell, ok I’ve seen a warning about how chars (or char vectors) get put into cells, but my users are not going to type "R" 5 0 etc these files already exist.
K>> app.StimInputTable.Data(jj,1)
ans =
table
Var1
{‘L’}
Try to pull it out and I get another table, not the cell
OK so I pull it this way
K>> app.StimInputTable.Data{jj,1}
ans =
1×1 cell array
{‘L’}
Now I have a more simple 1×1 cell array, now to the character out of the cell or compare cell to cell
How about I compare it to a cell with the char in it
K>> {‘L’}
ans =
1×1 cell array
{‘L’}
That looks good, same types, lets try it
K>> app.StimInputTable.Data{jj,1} == {‘L’}
Operator ‘==’ is not supported for operands of type ‘cell’.
So that didn’t work, so I’ll try
K>> cl = app.StimInputTable.Data{jj,1}
cl =
1×1 cell array
{‘L’}
Get the char out of the cell
K>> cl{1,1}
ans =
‘L’
K>> cl{1,1}== ‘L’
ans =
logical
1
Finally!
cl = app.StimInputTable.Data{jj,1}
if cl{1,1}== ‘L’
…
end
Is this really what I have to do? It took way too long to figure out. I never could find Help on how to extract the single cell of data out of a table. I have R and L as catagories when I use them later but can’t read them in as such initing the table size and variabletypes gets ignored by the read()
Wait a moment
app.StimInputTable.Data{j,1} % This gives a cell as above, but
app.StimInputTable.Data.Var1{j} % is going to work? Where is that documented?
ans =
‘L’
So now
if app.StimInputTable.Data.Var1{j} == ‘L’
Apparently using .Var1{i} is not the same as indexing with {j}
This works but where will you find it documented? Good luckI want to find what’s in my table that’s in a category column 1
If you read through you will see what I tries and how I finally figured it out. I’m posing the question because I can’t be the only person that wanted to do this simple (but not clearly and simply documented)
Starting with a text file:
HEADER that is ignored
R 0 5
L 5 0
Set up how I want the table (not that MATLAB will pay any attention)
app.StimInputTable.Data = table(‘Size’,[4 3],…
‘VariableTypes’,{‘categorical’,’uint8′,’uint8′});
What did I get? Got what I asked for
K>> class (app.StimInputTable.Data.Var1)
ans =
‘categorical’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘uint8’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘uint8’
Read in the file
app.StimInputTable.Data = readtable(infile);
MATLAB changes all the types
K>> class (app.StimInputTable.Data.Var1)
ans =
‘cell’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘double’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘double’
I can redo the .. table(… VariableTypes), but then it tosses all my category data instead of converting
So here’s my table, I can deal with the cells
K>> app.StimInputTable.Data
ans =
2×3 table
Var1 Var2 Var3
_____ ____ ____
{‘L’} 5 0
{‘R’} 0 5
So the char is considered a cell, ok I’ve seen a warning about how chars (or char vectors) get put into cells, but my users are not going to type "R" 5 0 etc these files already exist.
K>> app.StimInputTable.Data(jj,1)
ans =
table
Var1
{‘L’}
Try to pull it out and I get another table, not the cell
OK so I pull it this way
K>> app.StimInputTable.Data{jj,1}
ans =
1×1 cell array
{‘L’}
Now I have a more simple 1×1 cell array, now to the character out of the cell or compare cell to cell
How about I compare it to a cell with the char in it
K>> {‘L’}
ans =
1×1 cell array
{‘L’}
That looks good, same types, lets try it
K>> app.StimInputTable.Data{jj,1} == {‘L’}
Operator ‘==’ is not supported for operands of type ‘cell’.
So that didn’t work, so I’ll try
K>> cl = app.StimInputTable.Data{jj,1}
cl =
1×1 cell array
{‘L’}
Get the char out of the cell
K>> cl{1,1}
ans =
‘L’
K>> cl{1,1}== ‘L’
ans =
logical
1
Finally!
cl = app.StimInputTable.Data{jj,1}
if cl{1,1}== ‘L’
…
end
Is this really what I have to do? It took way too long to figure out. I never could find Help on how to extract the single cell of data out of a table. I have R and L as catagories when I use them later but can’t read them in as such initing the table size and variabletypes gets ignored by the read()
Wait a moment
app.StimInputTable.Data{j,1} % This gives a cell as above, but
app.StimInputTable.Data.Var1{j} % is going to work? Where is that documented?
ans =
‘L’
So now
if app.StimInputTable.Data.Var1{j} == ‘L’
Apparently using .Var1{i} is not the same as indexing with {j}
This works but where will you find it documented? Good luck I want to find what’s in my table that’s in a category column 1
If you read through you will see what I tries and how I finally figured it out. I’m posing the question because I can’t be the only person that wanted to do this simple (but not clearly and simply documented)
Starting with a text file:
HEADER that is ignored
R 0 5
L 5 0
Set up how I want the table (not that MATLAB will pay any attention)
app.StimInputTable.Data = table(‘Size’,[4 3],…
‘VariableTypes’,{‘categorical’,’uint8′,’uint8′});
What did I get? Got what I asked for
K>> class (app.StimInputTable.Data.Var1)
ans =
‘categorical’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘uint8’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘uint8’
Read in the file
app.StimInputTable.Data = readtable(infile);
MATLAB changes all the types
K>> class (app.StimInputTable.Data.Var1)
ans =
‘cell’
K>> class (app.StimInputTable.Data.Var2)
ans =
‘double’
K>> class (app.StimInputTable.Data.Var3)
ans =
‘double’
I can redo the .. table(… VariableTypes), but then it tosses all my category data instead of converting
So here’s my table, I can deal with the cells
K>> app.StimInputTable.Data
ans =
2×3 table
Var1 Var2 Var3
_____ ____ ____
{‘L’} 5 0
{‘R’} 0 5
So the char is considered a cell, ok I’ve seen a warning about how chars (or char vectors) get put into cells, but my users are not going to type "R" 5 0 etc these files already exist.
K>> app.StimInputTable.Data(jj,1)
ans =
table
Var1
{‘L’}
Try to pull it out and I get another table, not the cell
OK so I pull it this way
K>> app.StimInputTable.Data{jj,1}
ans =
1×1 cell array
{‘L’}
Now I have a more simple 1×1 cell array, now to the character out of the cell or compare cell to cell
How about I compare it to a cell with the char in it
K>> {‘L’}
ans =
1×1 cell array
{‘L’}
That looks good, same types, lets try it
K>> app.StimInputTable.Data{jj,1} == {‘L’}
Operator ‘==’ is not supported for operands of type ‘cell’.
So that didn’t work, so I’ll try
K>> cl = app.StimInputTable.Data{jj,1}
cl =
1×1 cell array
{‘L’}
Get the char out of the cell
K>> cl{1,1}
ans =
‘L’
K>> cl{1,1}== ‘L’
ans =
logical
1
Finally!
cl = app.StimInputTable.Data{jj,1}
if cl{1,1}== ‘L’
…
end
Is this really what I have to do? It took way too long to figure out. I never could find Help on how to extract the single cell of data out of a table. I have R and L as catagories when I use them later but can’t read them in as such initing the table size and variabletypes gets ignored by the read()
Wait a moment
app.StimInputTable.Data{j,1} % This gives a cell as above, but
app.StimInputTable.Data.Var1{j} % is going to work? Where is that documented?
ans =
‘L’
So now
if app.StimInputTable.Data.Var1{j} == ‘L’
Apparently using .Var1{i} is not the same as indexing with {j}
This works but where will you find it documented? Good luck get data in a cell MATLAB Answers — New Questions

​

I recently changed my OS system from Fedora to Ubuntu 24.04. On Fedora I could setup a thread-based parallel pool with 10 threads no problem (parpool(‘threads’, 10). When I try doing the same thing in Ubuntu, I get the following error:
‘A minimum pool size of 10 was requested. The maximum thread-based pool size is currently 2.’
I’ve tried a couple of things with no luck
maxNumCompThreads(10)
I checked nproc to make sure that Ubuntu recognizes all the CPU’s – it does
reinstalled the parallel computing toolbox
Varying the settings in cluster profile manager
Is there anything else I could try?I recently changed my OS system from Fedora to Ubuntu 24.04. On Fedora I could setup a thread-based parallel pool with 10 threads no problem (parpool(‘threads’, 10). When I try doing the same thing in Ubuntu, I get the following error:
‘A minimum pool size of 10 was requested. The maximum thread-based pool size is currently 2.’
I’ve tried a couple of things with no luck
maxNumCompThreads(10)
I checked nproc to make sure that Ubuntu recognizes all the CPU’s – it does
reinstalled the parallel computing toolbox
Varying the settings in cluster profile manager
Is there anything else I could try? I recently changed my OS system from Fedora to Ubuntu 24.04. On Fedora I could setup a thread-based parallel pool with 10 threads no problem (parpool(‘threads’, 10). When I try doing the same thing in Ubuntu, I get the following error:
‘A minimum pool size of 10 was requested. The maximum thread-based pool size is currently 2.’
I’ve tried a couple of things with no luck
maxNumCompThreads(10)
I checked nproc to make sure that Ubuntu recognizes all the CPU’s – it does
reinstalled the parallel computing toolbox
Varying the settings in cluster profile manager
Is there anything else I could try? parallel computing, ubuntu, parfor, linux MATLAB Answers — New Questions

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A=imread(‘appRasterNEDAPIService1708354512850-756880040.tif’);
X=1:324;
Y=1:194;
[X,Y]=meshgrid(X,Y);
surf(X,Y,A)
Hello. I have this terrain data. The size of A matrix is 194×324 and contain elevation data. I want to fill below the terrain from the elevation of the data to the 0 (mean sea level). I use fill code
hFill = fill3(X, Y, A, patchColor, ‘LineWidth’, 1, ‘EdgeColor’, patchColor, …
‘FaceAlpha’, 0.5);
However, it only fill below the surface with thin layer. I try to fill from the elevation to the 0 (mean sea level).
Thank you,A=imread(‘appRasterNEDAPIService1708354512850-756880040.tif’);
X=1:324;
Y=1:194;
[X,Y]=meshgrid(X,Y);
surf(X,Y,A)
Hello. I have this terrain data. The size of A matrix is 194×324 and contain elevation data. I want to fill below the terrain from the elevation of the data to the 0 (mean sea level). I use fill code
hFill = fill3(X, Y, A, patchColor, ‘LineWidth’, 1, ‘EdgeColor’, patchColor, …
‘FaceAlpha’, 0.5);
However, it only fill below the surface with thin layer. I try to fill from the elevation to the 0 (mean sea level).
Thank you, A=imread(‘appRasterNEDAPIService1708354512850-756880040.tif’);
X=1:324;
Y=1:194;
[X,Y]=meshgrid(X,Y);
surf(X,Y,A)
Hello. I have this terrain data. The size of A matrix is 194×324 and contain elevation data. I want to fill below the terrain from the elevation of the data to the 0 (mean sea level). I use fill code
hFill = fill3(X, Y, A, patchColor, ‘LineWidth’, 1, ‘EdgeColor’, patchColor, …
‘FaceAlpha’, 0.5);
However, it only fill below the surface with thin layer. I try to fill from the elevation to the 0 (mean sea level).
Thank you, image processing MATLAB Answers — New Questions

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