Tag Archives: matlab
Simulating Levy walk in MATLAB. (Not Levy Flight)
I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off;I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off; I am trying to simulate Levy Walk in 2D (Not Levy Flight). I do get the MSD and VCAF correctly, but I don’t get the step length distribution correctly ( Levy Walk step lengths have heavy tails). I don’t know my simulation is entirely correct. Can someone confirm my code ?
alpha=1.4;
x(1)=0;
y(1)=0;
n = 100; %
dt =0.1; % time step
v=1; % velocity
for i=1:n
t= round(abs((rand()).^(-1/alpha))./dt); % time before the change in direction taken from a simple stable distribution
theta = 2*pi*rand;
time(i)=t;
for j=1:t
x(end+1) = x(end) + v*dt*cos(theta);
y(end+1) = y(end) + v*dt*sin(theta);
end
end
figure(1);
plot(x, y, ‘-‘);
%% Distribution of step size
dx = diff(x);
dy = diff(y);
vxy=([dx, dy]);
bins = linspace(min(vxy), max(vxy), 75);
[count, edge]= histcounts(vxy, bins, ‘Normalization’, ‘PDF’);
pd= fitdist(transpose(vxy),’Normal’);
countfit=pdf(pd, edge(1:end-1));
figure(3)
semilogy(edge(1:end-1), count, ‘o’, ‘LineWidth’,2.0); hold on;
semilogy(edge(1:end-1),countfit,’-r’,’LineWidth’,2.0); hold off; randomwalk, biology, levywalk, physics MATLAB Answers — New Questions
resolution of MDOF using ode45
i have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
endi have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
end i have a problem solving the system with ode45. the code works but the displacement in graphed output is not what i would expect from a chirp signal. What could be the error in my code?
%MATRIX
M=diag([m1, m2, m3, m4, m5, m6, m7, m8, m9, m10, m11, m12, m13, m14, m15, m16, m17, m18, m19]);
% stiffness matrix 19×19
K = zeros(19,19);
K(1,1) = k1 + k4 + k7 + k8;
K(1,2) = -k1;
K(1,5) = -k4;
K(1,7) = -k7;
K(1,8) = -k8;
K(2,1) = -k1;
K(2,2) = k1 + k2;
K(2,3) = -k2;
K(3,2) = -k2;
K(3,3) = k2 + k3;
K(3,4) = -k3;
K(4,3) = -k3;
K(4,4) = k3;
K(5,1) = -k4;
K(5,5) = k4 + k5 + k6;
K(5,6) = -k5;
K(5,7) = -k6;
K(6,5) = -k5;
K(6,6) = k5 + k11;
K(6,11) = -k11;
K(7,1) = -k7;
K(7,5) = -k6;
K(7,7) = k6 + k7 + k23;
K(7,18) = -k23;
K(8,1) = -k8;
K(8,8) = k8 + k9;
K(8,9) = -k9;
K(9,8) = -k9;
K(9,9) = k9 + k10;
K(9,10) = -k10;
K(10,9) = -k10;
K(10,10) = k10;
K(11,6) = -k11;
K(11,7) = -k12;
K(11,11) = k11 + k12 + k13 + k14;
K(11,12) = -k13;
K(11,13) = -k14;
K(12,11) = -k13;
K(12,12) = k13 + k15;
K(12,14) = -k15;
K(13,11) = -k14;
K(13,13) = k14 + k16;
K(13,15) = -k16;
K(14,12) = -k15;
K(14,14) = k15 + k17;
K(14,16) = -k17;
K(15,13) = -k16;
K(15,15) = k16 + k18;
K(15,17) = -k18;
K(16,14) = -k17;
K(16,16) = k17 + k19;
K(17,15) = -k18;
K(17,17) = k18 + k20;
K(18,7) = -k23;
K(18,18) = k23 + k21 + k22;
K(18,19) = -k21 – k22;
K(19,18) = -k21 – k22;
K(19,19) = k21 + k22;
% damping matrix 19×19
C = zeros(19,19);
C(1,1) = c1 + c4 + c7 + c8;
C(1,2) = -c1;
C(1,5) = -c4;
C(1,7) = -c7;
C(1,8) = -c8;
C(2,1) = -c1;
C(2,2) = c1 + c2;
C(2,3) = -c2;
C(3,2) = -c2;
C(3,3) = c2 + c3;
C(3,4) = -c3;
C(4,3) = -c3;
C(4,4) = c3;
C(5,1) = -c4;
C(5,5) = c4 + c5 + c6;
C(5,6) = -c5;
C(5,7) = -c6;
C(6,5) = -c5;
C(6,6) = c5 + c11;
C(6,11) = -c11;
C(7,1) = -c7;
C(7,5) = -c6;
C(7,7) = c6 + c7 + c23;
C(7,18) = -c23;
C(8,1) = -c8;
C(8,8) = c8 + c9;
C(8,9) = -c9;
C(9,8) = -c9;
C(9,9) = c9 + c10;
C(9,10) = -c10;
C(10,9) = -c10;
C(10,10) = c10;
C(11,6) = -c11;
C(11,7) = -c12;
C(11,11) = c11 + c12 + c13 + c14;
C(11,12) = -c13;
C(11,13) = -c14;
C(12,11) = -c13;
C(12,12) = c13 + c15;
C(12,14) = -c15;
C(13,11) = -c14;
C(13,13) = c14 + c16;
C(13,15) = -c16;
C(14,12) = -c15;
C(14,14) = c15 + c17;
C(14,16) = -c17;
C(15,13) = -c16;
C(15,15) = c16 + c18;
C(15,17) = -c18;
C(16,14) = -c17;
C(16,16) = c17 + c19;
C(17,15) = -c18;
C(17,17) = c18 + c20;
C(18,7) = -c23;
C(18,18) = c23 + c21 + c22;
C(18,19) = -c21 – c22;
C(19,18) = -c21 – c22;
C(19,19) = c21 + c22;
n=19;
y0 = zeros(2*n,1);
tspan = [0 120];
% ode45
[t, y] = ode45(@(t, y) odefcn_standing(t, y, M, C, K), tspan, y0);
figure;
plot(t, y(:, 19));
xlabel(‘Time (s)’);
ylabel(‘Displacement (m)’);
% legend(‘y1’, ‘y2’, ‘y3’);
title(‘response of the system 19DOF’);
grid on;
function dy = odefcn_standing(t, y, M, C, K)
n = 19; % Numero di gradi di libertà
dy = zeros(2 * n, 1);
% Construction of matrix A
A = [zeros(n), eye(n);
-inv(M) * K, -inv(M) * C];
F = zeros(19, 1);
f0 = 0.5; % initial frequency
f1 = 80; % final frequency
t_f = 120; % duration of chirp signal
chirp_signal = chirp(t, f0, t_f, f1);
F(16,:) = 10*chirp_signal; % on mass 16
F(17,:) = 10*chirp_signal; % on mass 17
% Construction of matrix B
B = [zeros(n, n); inv(M)];
dy = A * y + B * F;
end ode45, mdof MATLAB Answers — New Questions
Getting the Error “Not enough input arguments” but I did the exact same method earlier in the code without issue..
clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag);clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag); clear all
close all
clc
% EMEC-342 Mini Project: 4-Bar Linkage Analysis
% Known Values
a=10; % cm
b=25; %cm
c=25; %cm
d = 20; % cm
AP=50; % cm
n=a/2;
q=c/2;
delta2=0;
delta3=0;
delta4=0;
w2=10; %rad/sec
alpha2=0;
oc=1;
t2=zeros(1,361); % rotation angle theta2 of O2A
for (i=1:361)
t2=i-1;
end
% Calculation of K1,K2,K3,K4,K5
K1=d/a;
K2=d/c;
K3=(a^2-b^2+c^2+d^2)/(2*a*c);
K4=d/b;
K5=(c^2-d^2-a^2-b^2)/(2*a*b);
%% Matlab Functions
function f=Grashof(lengths)
u=sort(lengths);
if((u(1)+u(4))<(u(2)+u(3)))
f=1;
elseif (u(1)+u(4))==(u(2)+u(3))
f=0;
else
f=-1;
end
end
%% Functions for calculation of angular orientations theta3, theta4
% of links AB and O4B
% Calculation of A
function AA=A(K1,K2,K3,t2)
AA=cos(t2)-K1-K2*cos(t2)+K3;
end
% Calculation of B
function BB=B(t2)
BB=-2*sin(t2);
end
% Calculation of C
function CC=C(K1,K2,K3,t2)
CC=K1-(K2+1)*cos(t2)+K3;
end
% Calculation of angular orientation theta4
function t4=theta4(K1,K2,K3,t2,oc)
AA = A(K1,K2,K3,theta2);
BB = B(theta2);
CC = C(K1,K2,K3,theta2);
t4=2*atan((-BB+oc*sqrt(BB^2-4*AA*CC))/(2*AA));
end
% Calculation of D
function DD=D(K1,K4,K5,t2)
DD=cos(t2)-K1+(K4*cos(t2))+K5;
end
% Calculation of E
function EE=E(t2)
EE=-2*sin(t2);
end
% Calculation of F
function FF=F(K1,K4,K5,t2)
FF=K1+(K4-1)*cos(t2)+K5;
end
% Calculation of angular orientation theta3
function t3=theta3(K1,K4,K5,t2,oc)
DD=D(K1,K4,K5,t2);
EE=E(t2);
FF=F(K1,K4,K5,t2);
t3=2*atan((-EE+oc*sqrt(EE^2-4*DD*FF))/(2*DD));
end
%% Functions for calculation of angular speeds omega3, omega4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
function as=angSpeed(a,b,c,w2,t2,t3,t4)
as=[w2*a/b*sin(t4-t2)/sin(t3-t4),w2*a/c*sin(t2-t3)/sin(t4-t3)];
end
%% Position Vectors
function r=RAO2(a,t2)
r= [a*cos(t2),a*sin(t2)];
end
function r=RPA(AP,t3,delta3)
r=AP*[cos(t3+delta3),sin(t3+delta3)];
end
function r=RPO2(a,PA,t2,t3,delta3)
r=RAO2(a,t2)+RPA(PA,t3,delta3);
end
%% Functions for calculation of angular acceleration alpha3, alpha4
% of links AB and O4B
%returns results as vector of x and y components
% returns x and y component
% Calculation of G
function GG=G(c,theta4)
GG=c*sin(theta4);
end
% Calculation of H
function HH=H(b,theta3)
HH=b*sin(theta3);
end
% Calculation of I
function II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4)
II=(a*alpha2*sin(t2))+(a*w2^2*cos(t2))+(b*omega3^2*cos(theta3))-(c*omega4^2*cos(theta4));
end
% Calculation of J
function JJ=J(c,theta4)
JJ=c*cos(theta4);
end
% Calculation of K
function KK=K(b,theta3)
KK=b*cos(theta3);
end
% Calculation of L
function LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4)
LL=(a*alpha2*cos(t2))+(a*w2^2*sin(t2))+(b*angSpeed(1)^2*sin(theta3))-(c*angSpeed(2)^2*sin(theta4));
end
function aa=angAccel(G,H,I,J,K,L)
GG=G(c,theta4);
HH=H(b,theta3);
II=I(a,b,c,alpha2,w2,omega3,omega4,t2,theta3,theta4);
JJ=J(c,theta4);
KK=K(b,theta3);
LL=L(a,b,c,alpha2,w2,angSpeed,t2,theta3,theta4);
aa=[(II*JJ-GG*LL)/(GG*KK-HH*JJ),(II*KK-HH*JJ)/(GG*KK-HH*JJ)];
end
%% Trace Point Velocity
function v=VA(a,w2,t2)
v=[-a*w2*sin(t2),a*w2*cos(t2)];
end
function v=VPA(AP,angSpeed,theta3,delta3)
v=AP*[-angSpeed(1)*sin(theta3+delta3),angSpeed(1)*cos(theta3+delta3)];
end
function v=VPO2(a,w2,angSpeed,t2,theta3,delta3,AP)
v=VA(a,w2,t2)+VPA(AP,angSpeed(1),theta3,delta3);
end
%% Trace Point Acceleration
function a=aA(a,alpha2,t2,w2)
a=[-a*alpha2*sin(t2),-a*w2^2*cos(t2)];
end
function a=APA(AP,angSpeed,theta3,delta3,angAccel)
a=AP*[-angAccel(1)*sin(theta3+delta3),-angSpeed(1)^2*cos(theta3+delta3)];
end
function a=APO2(a,w2,angSpeed,t2,theta3,delta3,AP)
a=aA(a,alpha2,t2,w2)+APA(AP,angSpeed(1),theta3,delta3,alpha3);
end
%% Tracepoint Acceleration N
function aN=ANO2(alpha2,t2,delta2,w2,RNO2)
aN=RNO2*[-alpha2*sin(t2+delta2)-(w2^2*cos(t2+deta2)),alpha2*cos(t2+delta2)-(w2^2*sin(t2+delta2))];
end
%% Plots
% Plot of theta3 and theta4 as functions of theta2
figure(1)
plot(t2,theta3,’r:’);
hold on
plot(t2,theta4,’b-‘);
% Plot of omega3 and omega4 as functions if theta2
figure(2)
plot(t2,angSpeed(1),’r:’);
hold on
plot(t2,angSpeed(2),’b-‘);
% Plot of alpha3 and alpha4 as functions of theta2
figure(3)
plot(t2,angAccel(1),’r:’);
hold on
plot(t2,angAccel(2),’b-‘);
% Plot of RPO2y as a function of RPO2x
figure(4)
plot(RPO2(1),RPO2(2));
% Plot of VPO2x as a function of RPO2x
figure(5)
plot(RPO2(1),VPO2(1));
% Plot of VPO2y as a function of RPO2y
figure(6)
plot(RPO2(2),VPO2(2));
% Plot of magnitude of VPO2 as a function of theta2
figure(7)
VPO2mag=sqrt(v(1,i)^2+v(2,i)^2);
plot(t2,VPO2mag);
% Plot of aPO2x as a function of RPO2x
figure(8)
plot(r(1),a(2));
% Plot of aPO2y as a function of RPO2y
figure(9)
plot(r(2),a(2));
% Plot of VPO2y as a function of RPO2y
figure(10)
aNO2mag=sqrt(aN(1,i)^2+aN(2,i)^2);
plot(t2,aNO2mag); error MATLAB Answers — New Questions
bitshift in matlab vs ishft in fortran
Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated!Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated! Hi,
I am trying to convert a large 64 bit number into 2x 32 bit numbers, Here is my code:
U = bitshift(v, -24);
L = bitand(v, 0x000000ffffffs64);
This is replicated off of fortran code:
U = ishft(v, -24)
L = iand(v, Z’000000ffffff’)
For value v = 2830037, the L’s agree, but "bitshift(2830037, -24) = 0" and "ishft(2830037, -24) = 1".
I am confused. Any help would be appreciated! matlab, fortran MATLAB Answers — New Questions
In the joint simulation of MATLAB (2021b) and NS-3 in Ubuntu (20.04.6), libmx.so => not found libmex.so => not found
How can I download these two missing files libmx.so and libmex.soHow can I download these two missing files libmx.so and libmex.so How can I download these two missing files libmx.so and libmex.so the joint simulation of matlab (2021b) and ns-3 MATLAB Answers — New Questions
Problem with Simscape Onramp
Hello!
I’m trying to access the Simscape Onramp course in browser mode and the Simulink window refuses to open even after waiting for a long time.
The one time it did open, it showed an error when clicking on Submit for the very first assignment.
"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
Thanks!Hello!
I’m trying to access the Simscape Onramp course in browser mode and the Simulink window refuses to open even after waiting for a long time.
The one time it did open, it showed an error when clicking on Submit for the very first assignment.
"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
Thanks! Hello!
I’m trying to access the Simscape Onramp course in browser mode and the Simulink window refuses to open even after waiting for a long time.
The one time it did open, it showed an error when clicking on Submit for the very first assignment.
"Unrecognized function or variable ‘simmechanics.sli.internal.register_datatypes’. (Figure atached)
Thanks! simscape onramp, courses MATLAB Answers — New Questions
How to connect to oscilloscope using MATLAB with Linux Ubuntu as operating system
I am running Linux ubuntu 22.04 as my operating system with MATLAB 2024a. I am trying to connect to a HDO9104 Lecroy oscilloscope using Instrument Control Toolbox via TCP/IP. However, MATLAB is unable to detect the oscilloscope.I am running Linux ubuntu 22.04 as my operating system with MATLAB 2024a. I am trying to connect to a HDO9104 Lecroy oscilloscope using Instrument Control Toolbox via TCP/IP. However, MATLAB is unable to detect the oscilloscope. I am running Linux ubuntu 22.04 as my operating system with MATLAB 2024a. I am trying to connect to a HDO9104 Lecroy oscilloscope using Instrument Control Toolbox via TCP/IP. However, MATLAB is unable to detect the oscilloscope. linux ubuntu, instrument control toolbox, tcp/ip, lecroy oscilloscope MATLAB Answers — New Questions
How to create an array from a ‘for loop’ of numeric data read from multiple excel files?
A list of excel files is made
The numeric data is imported from multiple excel files using ‘xlsread’ in a for loop.
>> facdata={‘1.csv’,’2.csv’,’3.csv’};
>> for fn=facdata
xlsread(fn{:},’D9:D9′);
endA list of excel files is made
The numeric data is imported from multiple excel files using ‘xlsread’ in a for loop.
>> facdata={‘1.csv’,’2.csv’,’3.csv’};
>> for fn=facdata
xlsread(fn{:},’D9:D9′);
end A list of excel files is made
The numeric data is imported from multiple excel files using ‘xlsread’ in a for loop.
>> facdata={‘1.csv’,’2.csv’,’3.csv’};
>> for fn=facdata
xlsread(fn{:},’D9:D9′);
end read multiple excel files, create list from excel data MATLAB Answers — New Questions
Asking for help with variables
1) I am developing a code and I have stored a column from a database (numerical values) inside a variable. When using the ‘ones’ function and utilizing the variable where I have stored the column, the code does not work. However, when I program the same function and call the column of values directly, it allows me to run the code. Is there any way to use the name of the variable that I created?
n_inter = length(data_inter.RSN); % Utilizado para regresion
n_intra = length(data_intra.RSN); % Utilizado para regresion
x_axis = PGA1100_inter; % variable seleccionada para eje x
X_inter = [ones(n_inter,1) data_inter.PGA1100]; (allows me)
X_intra = [ones(n_intra,1) x_axis]; (does not allow)
2) Also, I would like to know if it is possible to store the following code inside a table, meaning that the workspace looks much cleaner and all the generated variables are stored inside a table.
% Interplaca
[b_inter_PGA] = regress(data_inter.res_PGA, X_inter);
[b_inter_PGV] = regress(data_inter.res_PGV, X_inter);
[b_inter_002] = regress(data_inter.res_002, X_inter);
[b_inter_015] = regress(data_inter.res_015, X_inter);
[b_inter_02] = regress(data_inter.res_02, X_inter);
[b_inter_03] = regress(data_inter.res_03, X_inter);
[b_inter_1] = regress(data_inter.res_1, X_inter);
[b_inter_3] = regress(data_inter.res_3, X_inter);1) I am developing a code and I have stored a column from a database (numerical values) inside a variable. When using the ‘ones’ function and utilizing the variable where I have stored the column, the code does not work. However, when I program the same function and call the column of values directly, it allows me to run the code. Is there any way to use the name of the variable that I created?
n_inter = length(data_inter.RSN); % Utilizado para regresion
n_intra = length(data_intra.RSN); % Utilizado para regresion
x_axis = PGA1100_inter; % variable seleccionada para eje x
X_inter = [ones(n_inter,1) data_inter.PGA1100]; (allows me)
X_intra = [ones(n_intra,1) x_axis]; (does not allow)
2) Also, I would like to know if it is possible to store the following code inside a table, meaning that the workspace looks much cleaner and all the generated variables are stored inside a table.
% Interplaca
[b_inter_PGA] = regress(data_inter.res_PGA, X_inter);
[b_inter_PGV] = regress(data_inter.res_PGV, X_inter);
[b_inter_002] = regress(data_inter.res_002, X_inter);
[b_inter_015] = regress(data_inter.res_015, X_inter);
[b_inter_02] = regress(data_inter.res_02, X_inter);
[b_inter_03] = regress(data_inter.res_03, X_inter);
[b_inter_1] = regress(data_inter.res_1, X_inter);
[b_inter_3] = regress(data_inter.res_3, X_inter); 1) I am developing a code and I have stored a column from a database (numerical values) inside a variable. When using the ‘ones’ function and utilizing the variable where I have stored the column, the code does not work. However, when I program the same function and call the column of values directly, it allows me to run the code. Is there any way to use the name of the variable that I created?
n_inter = length(data_inter.RSN); % Utilizado para regresion
n_intra = length(data_intra.RSN); % Utilizado para regresion
x_axis = PGA1100_inter; % variable seleccionada para eje x
X_inter = [ones(n_inter,1) data_inter.PGA1100]; (allows me)
X_intra = [ones(n_intra,1) x_axis]; (does not allow)
2) Also, I would like to know if it is possible to store the following code inside a table, meaning that the workspace looks much cleaner and all the generated variables are stored inside a table.
% Interplaca
[b_inter_PGA] = regress(data_inter.res_PGA, X_inter);
[b_inter_PGV] = regress(data_inter.res_PGV, X_inter);
[b_inter_002] = regress(data_inter.res_002, X_inter);
[b_inter_015] = regress(data_inter.res_015, X_inter);
[b_inter_02] = regress(data_inter.res_02, X_inter);
[b_inter_03] = regress(data_inter.res_03, X_inter);
[b_inter_1] = regress(data_inter.res_1, X_inter);
[b_inter_3] = regress(data_inter.res_3, X_inter); variables, ones, database MATLAB Answers — New Questions
Demux out put port 1 is not connected
I have create a 100W solar system by watching a YT video. After I run the model it says Demux output port 1 is not connectd (There are 5 similar errors because there are 5 demux in the system). Also there is one Mux in the system, therefore it has a error showing input port of the Mux not connected.
How can I solve this?
And please note in the YT video I have follow, the are not connect anything to Demux nor Mux but there model working fine.
YT video I have followedI have create a 100W solar system by watching a YT video. After I run the model it says Demux output port 1 is not connectd (There are 5 similar errors because there are 5 demux in the system). Also there is one Mux in the system, therefore it has a error showing input port of the Mux not connected.
How can I solve this?
And please note in the YT video I have follow, the are not connect anything to Demux nor Mux but there model working fine.
YT video I have followed I have create a 100W solar system by watching a YT video. After I run the model it says Demux output port 1 is not connectd (There are 5 similar errors because there are 5 demux in the system). Also there is one Mux in the system, therefore it has a error showing input port of the Mux not connected.
How can I solve this?
And please note in the YT video I have follow, the are not connect anything to Demux nor Mux but there model working fine.
YT video I have followed simulink, demux, mux, solar, solar system, matlab, 100w, export, output MATLAB Answers — New Questions
Custom name for simulink test coverage report
Hello,
When I run my simulink test file and generate test report like in the below code, a folder is created for coverage report and it has a html file with random name like ‘tp576c882a_0284_4a8b_a3b1_8ad156fb7814.html’. (the test report has a link to this coverage report file.)
…
resultNormal = testFile.run;
testReportName = [‘Report_’, blockName, ‘.pdf’];
testReportPath = fullfile(pwd, testReportName);
sltest.testmanager.report(resultNormal, testReportPath, ‘Title’, [‘Test Report for ‘, blockName, ‘ in MIL mode.’], ‘IncludeMLVersion’, true, ‘IncludeComparisonSignalPlots’, true, ‘IncludeErrorMessages’, true, ‘IncludeTestResults’, 0, ‘IncludeCoverageResult’, true,’IncludeMATLABFigures’, true);
Everytime I run this script, a new html file name is created and so I have to replace the old file eveytime in my git. Is there a way to set a fixed name to this html file ?
Thanks.Hello,
When I run my simulink test file and generate test report like in the below code, a folder is created for coverage report and it has a html file with random name like ‘tp576c882a_0284_4a8b_a3b1_8ad156fb7814.html’. (the test report has a link to this coverage report file.)
…
resultNormal = testFile.run;
testReportName = [‘Report_’, blockName, ‘.pdf’];
testReportPath = fullfile(pwd, testReportName);
sltest.testmanager.report(resultNormal, testReportPath, ‘Title’, [‘Test Report for ‘, blockName, ‘ in MIL mode.’], ‘IncludeMLVersion’, true, ‘IncludeComparisonSignalPlots’, true, ‘IncludeErrorMessages’, true, ‘IncludeTestResults’, 0, ‘IncludeCoverageResult’, true,’IncludeMATLABFigures’, true);
Everytime I run this script, a new html file name is created and so I have to replace the old file eveytime in my git. Is there a way to set a fixed name to this html file ?
Thanks. Hello,
When I run my simulink test file and generate test report like in the below code, a folder is created for coverage report and it has a html file with random name like ‘tp576c882a_0284_4a8b_a3b1_8ad156fb7814.html’. (the test report has a link to this coverage report file.)
…
resultNormal = testFile.run;
testReportName = [‘Report_’, blockName, ‘.pdf’];
testReportPath = fullfile(pwd, testReportName);
sltest.testmanager.report(resultNormal, testReportPath, ‘Title’, [‘Test Report for ‘, blockName, ‘ in MIL mode.’], ‘IncludeMLVersion’, true, ‘IncludeComparisonSignalPlots’, true, ‘IncludeErrorMessages’, true, ‘IncludeTestResults’, 0, ‘IncludeCoverageResult’, true,’IncludeMATLABFigures’, true);
Everytime I run this script, a new html file name is created and so I have to replace the old file eveytime in my git. Is there a way to set a fixed name to this html file ?
Thanks. simulink test, coverage report MATLAB Answers — New Questions
In App Designed app: When does a function called within another function spawn a new thread?
I’m having SO much trouble! I think maybe when I call a function from within another function or callback it’s going into a new thread.
I want it to finish the function before moving on. Is the best way to do that to make the function return a (dummy) value?
Since there is nothing to return but completion do I need to declare
function finish = MyFunction(app);
does finish need a value assigned at the end?
or just short cut and call
fin = MyFunction %#ok suppress mLint about unused return value?I’m having SO much trouble! I think maybe when I call a function from within another function or callback it’s going into a new thread.
I want it to finish the function before moving on. Is the best way to do that to make the function return a (dummy) value?
Since there is nothing to return but completion do I need to declare
function finish = MyFunction(app);
does finish need a value assigned at the end?
or just short cut and call
fin = MyFunction %#ok suppress mLint about unused return value? I’m having SO much trouble! I think maybe when I call a function from within another function or callback it’s going into a new thread.
I want it to finish the function before moving on. Is the best way to do that to make the function return a (dummy) value?
Since there is nothing to return but completion do I need to declare
function finish = MyFunction(app);
does finish need a value assigned at the end?
or just short cut and call
fin = MyFunction %#ok suppress mLint about unused return value? threads, function calls MATLAB Answers — New Questions
Why I get error :Cannot find ‘get’ method for matlab.graphics.internal.GraphicsMetaProperty class?
Hello there
My code is:
function plot_kx2_slider()
% Create a figure with a slider and a plot
f = figure;
k=1
slider = uicontrol(‘Style’, ‘slider’, ‘Units’, ‘normalized’, …
‘Position’, [0.1, 0.9, 0.8, 0.05], …
‘Value’, 1, ‘Min’, -5, ‘Max’, 5);
axes_handle = axes(‘Position’, [0.1, 0.1, 0.8, 0.7]);
% Create a function to update the plot based on the slider value
function update_plot(source, eventdata)
% Get slider value using get function
k = get(source, ‘Value’);
x = linspace(-5, 5, 100);
y = k * x.^2;
plot(axes_handle, x, y);
title([‘f(x) = ‘, num2str(k), ‘x^2’]);
xlabel(‘x’);
ylabel(‘f(x)’);
end
% Set the initial plot
update_plot(slider, [0]);
% Add a listener to the slider to update the plot when the slider value changes
addlistener(slider, ‘Value’, ‘PostSet’, @update_plot);
end
this code should plot the function f(x)=kx^2 but MATLAB shows me these errors:
————————-
Warning: Error executing listener callback for PostSet event on Value dynamic property in object of
matlab.ui.control.UIControl class:
Error using get
Cannot find ‘get’ method for matlab.graphics.internal.GraphicsMetaProperty class.
Error in plot_kx2_slider/update_plot (line 13)
k = get(source, ‘Value’);
————————-
guys can you help me?Hello there
My code is:
function plot_kx2_slider()
% Create a figure with a slider and a plot
f = figure;
k=1
slider = uicontrol(‘Style’, ‘slider’, ‘Units’, ‘normalized’, …
‘Position’, [0.1, 0.9, 0.8, 0.05], …
‘Value’, 1, ‘Min’, -5, ‘Max’, 5);
axes_handle = axes(‘Position’, [0.1, 0.1, 0.8, 0.7]);
% Create a function to update the plot based on the slider value
function update_plot(source, eventdata)
% Get slider value using get function
k = get(source, ‘Value’);
x = linspace(-5, 5, 100);
y = k * x.^2;
plot(axes_handle, x, y);
title([‘f(x) = ‘, num2str(k), ‘x^2’]);
xlabel(‘x’);
ylabel(‘f(x)’);
end
% Set the initial plot
update_plot(slider, [0]);
% Add a listener to the slider to update the plot when the slider value changes
addlistener(slider, ‘Value’, ‘PostSet’, @update_plot);
end
this code should plot the function f(x)=kx^2 but MATLAB shows me these errors:
————————-
Warning: Error executing listener callback for PostSet event on Value dynamic property in object of
matlab.ui.control.UIControl class:
Error using get
Cannot find ‘get’ method for matlab.graphics.internal.GraphicsMetaProperty class.
Error in plot_kx2_slider/update_plot (line 13)
k = get(source, ‘Value’);
————————-
guys can you help me? Hello there
My code is:
function plot_kx2_slider()
% Create a figure with a slider and a plot
f = figure;
k=1
slider = uicontrol(‘Style’, ‘slider’, ‘Units’, ‘normalized’, …
‘Position’, [0.1, 0.9, 0.8, 0.05], …
‘Value’, 1, ‘Min’, -5, ‘Max’, 5);
axes_handle = axes(‘Position’, [0.1, 0.1, 0.8, 0.7]);
% Create a function to update the plot based on the slider value
function update_plot(source, eventdata)
% Get slider value using get function
k = get(source, ‘Value’);
x = linspace(-5, 5, 100);
y = k * x.^2;
plot(axes_handle, x, y);
title([‘f(x) = ‘, num2str(k), ‘x^2’]);
xlabel(‘x’);
ylabel(‘f(x)’);
end
% Set the initial plot
update_plot(slider, [0]);
% Add a listener to the slider to update the plot when the slider value changes
addlistener(slider, ‘Value’, ‘PostSet’, @update_plot);
end
this code should plot the function f(x)=kx^2 but MATLAB shows me these errors:
————————-
Warning: Error executing listener callback for PostSet event on Value dynamic property in object of
matlab.ui.control.UIControl class:
Error using get
Cannot find ‘get’ method for matlab.graphics.internal.GraphicsMetaProperty class.
Error in plot_kx2_slider/update_plot (line 13)
k = get(source, ‘Value’);
————————-
guys can you help me? error MATLAB Answers — New Questions
Error using odearguments Vector Length issue
I am not sure I understand the issue here. Any help would be appreciated
%% Initial Variables
s1=0.27; s2=1.04; s3=0.716; s4=0; s5=0; Vref=1.04; Pref=0.716;
%% Define Diferential Equations
function dsdt= pv_system(t,s)
%parameters
Ki=20; Kp=4; Kip=10; Kiq=10; Tr=0.02; TGpv=0.01; Rq=0; Rp=0.05;
Vref=1.04; Qactual=0.27; Vt=1.04;Pref=0.716;DeltaOmega=0;Pactual=0.716;
Qcmd =0.27;
%State Variables
s1=s(1); s2=s(2); s3=(s); s4=s(4); s5=s(4);
%diferential Equations
ds1dt=Ki*(Vref-s2-Rq*Qactual);
ds2dt = (1 / Tr) * (Vt – s2);
ds3dt = (1 / TGpv) * (Pref – (DeltaOmega / Rp) – s3);
ds4dt = Kip * (s3 – Pactual);
ds5dt = Kiq * (Qcmd – Qactual);
dsdt = [ds1dt; ds2dt; ds3dt; ds4dt; ds5dt];
end
%% inital Vector
s0 = [s1;s2;s3;s4;s5];
%% Time span for simulation
tspan = [0 10]; % 0 to 10 seconds
%% Solve using ode45
[t, s] = ode45(@pv_system, tspan, s0);I am not sure I understand the issue here. Any help would be appreciated
%% Initial Variables
s1=0.27; s2=1.04; s3=0.716; s4=0; s5=0; Vref=1.04; Pref=0.716;
%% Define Diferential Equations
function dsdt= pv_system(t,s)
%parameters
Ki=20; Kp=4; Kip=10; Kiq=10; Tr=0.02; TGpv=0.01; Rq=0; Rp=0.05;
Vref=1.04; Qactual=0.27; Vt=1.04;Pref=0.716;DeltaOmega=0;Pactual=0.716;
Qcmd =0.27;
%State Variables
s1=s(1); s2=s(2); s3=(s); s4=s(4); s5=s(4);
%diferential Equations
ds1dt=Ki*(Vref-s2-Rq*Qactual);
ds2dt = (1 / Tr) * (Vt – s2);
ds3dt = (1 / TGpv) * (Pref – (DeltaOmega / Rp) – s3);
ds4dt = Kip * (s3 – Pactual);
ds5dt = Kiq * (Qcmd – Qactual);
dsdt = [ds1dt; ds2dt; ds3dt; ds4dt; ds5dt];
end
%% inital Vector
s0 = [s1;s2;s3;s4;s5];
%% Time span for simulation
tspan = [0 10]; % 0 to 10 seconds
%% Solve using ode45
[t, s] = ode45(@pv_system, tspan, s0); I am not sure I understand the issue here. Any help would be appreciated
%% Initial Variables
s1=0.27; s2=1.04; s3=0.716; s4=0; s5=0; Vref=1.04; Pref=0.716;
%% Define Diferential Equations
function dsdt= pv_system(t,s)
%parameters
Ki=20; Kp=4; Kip=10; Kiq=10; Tr=0.02; TGpv=0.01; Rq=0; Rp=0.05;
Vref=1.04; Qactual=0.27; Vt=1.04;Pref=0.716;DeltaOmega=0;Pactual=0.716;
Qcmd =0.27;
%State Variables
s1=s(1); s2=s(2); s3=(s); s4=s(4); s5=s(4);
%diferential Equations
ds1dt=Ki*(Vref-s2-Rq*Qactual);
ds2dt = (1 / Tr) * (Vt – s2);
ds3dt = (1 / TGpv) * (Pref – (DeltaOmega / Rp) – s3);
ds4dt = Kip * (s3 – Pactual);
ds5dt = Kiq * (Qcmd – Qactual);
dsdt = [ds1dt; ds2dt; ds3dt; ds4dt; ds5dt];
end
%% inital Vector
s0 = [s1;s2;s3;s4;s5];
%% Time span for simulation
tspan = [0 10]; % 0 to 10 seconds
%% Solve using ode45
[t, s] = ode45(@pv_system, tspan, s0); ode45 MATLAB Answers — New Questions
Newton Forward difference method
% Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
forward_diff(i, j) = forward_diff(i+1, j-1) – forward_diff(i, j-1);
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
term = forward_diff(1, j);
for i = 1:j
term = term * (X – x(i));
end
P = P + term / factorial(j);
end
disp(‘Newton Forward Difference Polynomial:’);
disp(simplify(P));
Result Newton Forward Difference Polynomial: – (725*X^7)/1008 + (1651*X^6)/80 – (173233*X^5)/720 + (70651*X^4)/48 – (91321*X^3)/18 + (146407*X^2)/15 – (1996741*X)/210 + 3658
The problem now is that when I substitute each value of x, I don’t get the corresponding value of y as stated in the table. I need help on how to get the correct polynomial equation.% Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
forward_diff(i, j) = forward_diff(i+1, j-1) – forward_diff(i, j-1);
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
term = forward_diff(1, j);
for i = 1:j
term = term * (X – x(i));
end
P = P + term / factorial(j);
end
disp(‘Newton Forward Difference Polynomial:’);
disp(simplify(P));
Result Newton Forward Difference Polynomial: – (725*X^7)/1008 + (1651*X^6)/80 – (173233*X^5)/720 + (70651*X^4)/48 – (91321*X^3)/18 + (146407*X^2)/15 – (1996741*X)/210 + 3658
The problem now is that when I substitute each value of x, I don’t get the corresponding value of y as stated in the table. I need help on how to get the correct polynomial equation. % Confirmed case Sample data points (x, y)
data = [ 1, 88; 2, 49; 3, 47; 4, 8; 5, 34; 6, 762; 7, 98; 8, 40];
% Extract x and y values
x = data(:, 1);
y = data(:, 2);
n = length(x);
% Calculate forward differences
forward_diff = zeros(n, n);
forward_diff(:, 1) = y;
for j = 2:n
for i = 1:n-j+1
forward_diff(i, j) = forward_diff(i+1, j-1) – forward_diff(i, j-1);
end
end
% Construct the Newton Forward Difference polynomial
syms X;
P = y(1);
for j = 1:n-1
term = forward_diff(1, j);
for i = 1:j
term = term * (X – x(i));
end
P = P + term / factorial(j);
end
disp(‘Newton Forward Difference Polynomial:’);
disp(simplify(P));
Result Newton Forward Difference Polynomial: – (725*X^7)/1008 + (1651*X^6)/80 – (173233*X^5)/720 + (70651*X^4)/48 – (91321*X^3)/18 + (146407*X^2)/15 – (1996741*X)/210 + 3658
The problem now is that when I substitute each value of x, I don’t get the corresponding value of y as stated in the table. I need help on how to get the correct polynomial equation. newton forward difference method MATLAB Answers — New Questions
Gauss-Seidel for solving linear equations
Apply 4 iterations, by the Gauss-Seidel iterative method, to solve the system of linear equations,Check the solutions by matrix calculation.Apply 4 iterations, by the Gauss-Seidel iterative method, to solve the system of linear equations,Check the solutions by matrix calculation. Apply 4 iterations, by the Gauss-Seidel iterative method, to solve the system of linear equations,Check the solutions by matrix calculation. gauss-seidel MATLAB Answers — New Questions
How to find the parameters of Fraction order PID Controller?
I want to design a FOPID controller. I’ve been gone through a lot of documents and paper works but I can’t find about how to find the values of Kp, Ki, Kd, λ and μ. Can anyone suggest a website, idea or even codes to find the tuning parameters? My transfer function is 40/(7.5s + 1)I want to design a FOPID controller. I’ve been gone through a lot of documents and paper works but I can’t find about how to find the values of Kp, Ki, Kd, λ and μ. Can anyone suggest a website, idea or even codes to find the tuning parameters? My transfer function is 40/(7.5s + 1) I want to design a FOPID controller. I’ve been gone through a lot of documents and paper works but I can’t find about how to find the values of Kp, Ki, Kd, λ and μ. Can anyone suggest a website, idea or even codes to find the tuning parameters? My transfer function is 40/(7.5s + 1) fopid, pid, fractional order pid MATLAB Answers — New Questions
Which versions of Xilinx System Generator (now AMD Vitis Model Composer) support which MATLAB release?
Which versions of Xilinx System Generator for DSP / AMD Vitis Model Composer are compatible with which versions of MATLAB?Which versions of Xilinx System Generator for DSP / AMD Vitis Model Composer are compatible with which versions of MATLAB? Which versions of Xilinx System Generator for DSP / AMD Vitis Model Composer are compatible with which versions of MATLAB? xilinx, sysgen, compatibility, support MATLAB Answers — New Questions
using Gauss Jacobi method to solve a system of equations
I’m new to Matlab so don’t have the best understanding here, i need to use the jacobi method to find the values of C but i dont really know the code that i need to use.
My equations are:
(837*C3)/2000 – (6851*C2)/10000 – (1091*C1)/2500 – (821*C4)/2000
(1337*C1)/2000 + (437*C2)/2500 + (3899*C3)/10000 – (6087*C4)/10000
(1601*C2)/2500 – (2939*C1)/5000 – (477*C3)/10000 – (4921*C4)/10000
(1313*C1)/10000 – (3*C2)/10 – (8209*C3)/10000 – (292*C4)/625
A = [-0.4364 -0.6851 0.4185 -0.4105; 0.6685 0.1748 0.3899 -0.6087; -0.5878 0.6404 -0.0477 -0.4921; 0.1313 -0.3000 -0.8209 -0.4672];
B = [0;40;0;0];
please note that this is not diaganally dominant but ive been told to do it anyway – it is part of an assignment.
cheers.I’m new to Matlab so don’t have the best understanding here, i need to use the jacobi method to find the values of C but i dont really know the code that i need to use.
My equations are:
(837*C3)/2000 – (6851*C2)/10000 – (1091*C1)/2500 – (821*C4)/2000
(1337*C1)/2000 + (437*C2)/2500 + (3899*C3)/10000 – (6087*C4)/10000
(1601*C2)/2500 – (2939*C1)/5000 – (477*C3)/10000 – (4921*C4)/10000
(1313*C1)/10000 – (3*C2)/10 – (8209*C3)/10000 – (292*C4)/625
A = [-0.4364 -0.6851 0.4185 -0.4105; 0.6685 0.1748 0.3899 -0.6087; -0.5878 0.6404 -0.0477 -0.4921; 0.1313 -0.3000 -0.8209 -0.4672];
B = [0;40;0;0];
please note that this is not diaganally dominant but ive been told to do it anyway – it is part of an assignment.
cheers. I’m new to Matlab so don’t have the best understanding here, i need to use the jacobi method to find the values of C but i dont really know the code that i need to use.
My equations are:
(837*C3)/2000 – (6851*C2)/10000 – (1091*C1)/2500 – (821*C4)/2000
(1337*C1)/2000 + (437*C2)/2500 + (3899*C3)/10000 – (6087*C4)/10000
(1601*C2)/2500 – (2939*C1)/5000 – (477*C3)/10000 – (4921*C4)/10000
(1313*C1)/10000 – (3*C2)/10 – (8209*C3)/10000 – (292*C4)/625
A = [-0.4364 -0.6851 0.4185 -0.4105; 0.6685 0.1748 0.3899 -0.6087; -0.5878 0.6404 -0.0477 -0.4921; 0.1313 -0.3000 -0.8209 -0.4672];
B = [0;40;0;0];
please note that this is not diaganally dominant but ive been told to do it anyway – it is part of an assignment.
cheers. matlab, gauss jacobi MATLAB Answers — New Questions
Matlab not reading data fast enough from arduino.
My code is able to read data from the serial port correctly (it seems), however for some reason my dataIndex variable is not keeping up with the speed that I am trying to read data at (I think). While I should have 10000 data points using this code my dataIndex variable is ending at way short at about 816 instead. Has anybody else ever had an issue like this?
Another but not as important issue I have been having is this occassional error code:
Warning: Matching failure in format. The format specified for conversion, ‘%d’, is incorrect.
Unable to perform assignment because the left and right sides have a different number of elements.
It only comes up sometimes, and it seems like its because my value variable occasionally becomes a char.
Any advice that could be offered on any of this would be greatly appreciated!
%% Matlab code
clc;
clear;
close all;
% % Closes serial ports
fclose(instrfind());
% % Defines serial connection
arduino = serial(‘COM11′,’BaudRate’,9600);
% % Initializes serial connection
fopen(arduino);
% % Duration to record data(in seconds).
duration = 10;
% % Time interval between consecutive data reads.
stepTime = .001;
% % Total number of data samples to be recorded.
samples = duration/stepTime;
% % Initialize arrays for storing data and timestamps.
valueArray = zeros(1,samples);
dataIndex = 1;
tObj = tic;
while(toc(tObj) <= duration)
% % Gets data value from serial port
value = fscanf(arduino,’%d’);
% % Store the read data in the corresponding data array.
valueArray(dataIndex) = value;
dataIndex = dataIndex + 1;
% % Read data from Arduino pins in intervals specified by the variable ‘stepTime’.
pause(stepTime);
end
% % Closes serial ports
fclose(instrfind());
%% Arduino code
const int analogInPin = A0;
int sensorValue = 0;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
}
void loop() {
sensorValue = analogRead(analogInPin);
Serial.println(sensorValue);
delay(10);
}My code is able to read data from the serial port correctly (it seems), however for some reason my dataIndex variable is not keeping up with the speed that I am trying to read data at (I think). While I should have 10000 data points using this code my dataIndex variable is ending at way short at about 816 instead. Has anybody else ever had an issue like this?
Another but not as important issue I have been having is this occassional error code:
Warning: Matching failure in format. The format specified for conversion, ‘%d’, is incorrect.
Unable to perform assignment because the left and right sides have a different number of elements.
It only comes up sometimes, and it seems like its because my value variable occasionally becomes a char.
Any advice that could be offered on any of this would be greatly appreciated!
%% Matlab code
clc;
clear;
close all;
% % Closes serial ports
fclose(instrfind());
% % Defines serial connection
arduino = serial(‘COM11′,’BaudRate’,9600);
% % Initializes serial connection
fopen(arduino);
% % Duration to record data(in seconds).
duration = 10;
% % Time interval between consecutive data reads.
stepTime = .001;
% % Total number of data samples to be recorded.
samples = duration/stepTime;
% % Initialize arrays for storing data and timestamps.
valueArray = zeros(1,samples);
dataIndex = 1;
tObj = tic;
while(toc(tObj) <= duration)
% % Gets data value from serial port
value = fscanf(arduino,’%d’);
% % Store the read data in the corresponding data array.
valueArray(dataIndex) = value;
dataIndex = dataIndex + 1;
% % Read data from Arduino pins in intervals specified by the variable ‘stepTime’.
pause(stepTime);
end
% % Closes serial ports
fclose(instrfind());
%% Arduino code
const int analogInPin = A0;
int sensorValue = 0;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
}
void loop() {
sensorValue = analogRead(analogInPin);
Serial.println(sensorValue);
delay(10);
} My code is able to read data from the serial port correctly (it seems), however for some reason my dataIndex variable is not keeping up with the speed that I am trying to read data at (I think). While I should have 10000 data points using this code my dataIndex variable is ending at way short at about 816 instead. Has anybody else ever had an issue like this?
Another but not as important issue I have been having is this occassional error code:
Warning: Matching failure in format. The format specified for conversion, ‘%d’, is incorrect.
Unable to perform assignment because the left and right sides have a different number of elements.
It only comes up sometimes, and it seems like its because my value variable occasionally becomes a char.
Any advice that could be offered on any of this would be greatly appreciated!
%% Matlab code
clc;
clear;
close all;
% % Closes serial ports
fclose(instrfind());
% % Defines serial connection
arduino = serial(‘COM11′,’BaudRate’,9600);
% % Initializes serial connection
fopen(arduino);
% % Duration to record data(in seconds).
duration = 10;
% % Time interval between consecutive data reads.
stepTime = .001;
% % Total number of data samples to be recorded.
samples = duration/stepTime;
% % Initialize arrays for storing data and timestamps.
valueArray = zeros(1,samples);
dataIndex = 1;
tObj = tic;
while(toc(tObj) <= duration)
% % Gets data value from serial port
value = fscanf(arduino,’%d’);
% % Store the read data in the corresponding data array.
valueArray(dataIndex) = value;
dataIndex = dataIndex + 1;
% % Read data from Arduino pins in intervals specified by the variable ‘stepTime’.
pause(stepTime);
end
% % Closes serial ports
fclose(instrfind());
%% Arduino code
const int analogInPin = A0;
int sensorValue = 0;
void setup() {
// put your setup code here, to run once:
Serial.begin(9600);
}
void loop() {
sensorValue = analogRead(analogInPin);
Serial.println(sensorValue);
delay(10);
} arduino, serial, char MATLAB Answers — New Questions
