I can’t edit this line of code no matter what I do to the extent that when I click on it instead of my cursor blinking being ready to type it remains solid. I can’t even hit the enter key in the line.I can’t edit this line of code no matter what I do to the extent that when I click on it instead of my cursor blinking being ready to type it remains solid. I can’t even hit the enter key in the line. I can’t edit this line of code no matter what I do to the extent that when I click on it instead of my cursor blinking being ready to type it remains solid. I can’t even hit the enter key in the line. can’t type, technical problems, solid cursor, code, livescript MATLAB Answers — New Questions

​

Hi, web power system onramp the task2 of 2/3 (three phase domain) is asking for 120V for the source rms line to line and 10ohm for the R load,
Even after following the hints and seeing the solution and applying it literally, the result is always "incorrect’ as the output voltage is not matching the plotted one,
appreciate a guidance,
regards.Hi, web power system onramp the task2 of 2/3 (three phase domain) is asking for 120V for the source rms line to line and 10ohm for the R load,
Even after following the hints and seeing the solution and applying it literally, the result is always "incorrect’ as the output voltage is not matching the plotted one,
appreciate a guidance,
regards. Hi, web power system onramp the task2 of 2/3 (three phase domain) is asking for 120V for the source rms line to line and 10ohm for the R load,
Even after following the hints and seeing the solution and applying it literally, the result is always "incorrect’ as the output voltage is not matching the plotted one,
appreciate a guidance,
regards. onramp power system MATLAB Answers — New Questions

​

Hello everyone,
I was wondering if anyone could help me understanding how to set up the training data for KeyPoint Detector Object (trainHRNETObjectKeypointDetector).
The help says:
"Keypoint locations, defined in spatial coordinates as an N-by-2 or N-by-3 numeric matrix with rows of the form [x y] or [x y v], respectively, where:
N is the number of keypoint classes.
x and y specify the spatial coordinates of a keypoint.
v specifies the visibility of a keypoint."
I was wondering how to setup the visibility flag v .
Is it 1 when the key point is visible and annotated and 0 when it is not. Or same as Yolo 0 = key point out of view and not labelled; 1 = key point present but not visible; 2 = key point visible ?

Thank you very much for your helpHello everyone,
I was wondering if anyone could help me understanding how to set up the training data for KeyPoint Detector Object (trainHRNETObjectKeypointDetector).
The help says:
"Keypoint locations, defined in spatial coordinates as an N-by-2 or N-by-3 numeric matrix with rows of the form [x y] or [x y v], respectively, where:
N is the number of keypoint classes.
x and y specify the spatial coordinates of a keypoint.
v specifies the visibility of a keypoint."
I was wondering how to setup the visibility flag v .
Is it 1 when the key point is visible and annotated and 0 when it is not. Or same as Yolo 0 = key point out of view and not labelled; 1 = key point present but not visible; 2 = key point visible ?

Thank you very much for your help Hello everyone,
I was wondering if anyone could help me understanding how to set up the training data for KeyPoint Detector Object (trainHRNETObjectKeypointDetector).
The help says:
"Keypoint locations, defined in spatial coordinates as an N-by-2 or N-by-3 numeric matrix with rows of the form [x y] or [x y v], respectively, where:
N is the number of keypoint classes.
x and y specify the spatial coordinates of a keypoint.
v specifies the visibility of a keypoint."
I was wondering how to setup the visibility flag v .
Is it 1 when the key point is visible and annotated and 0 when it is not. Or same as Yolo 0 = key point out of view and not labelled; 1 = key point present but not visible; 2 = key point visible ?

Thank you very much for your help deep learning, keypoint detector MATLAB Answers — New Questions

​

I am simulating a PMSM drive using Field-Oriented Control in Simulink.
The model uses Clarke and Park transforms to generate Id and Iq currents.

When I run the simulation, I get the following error:

"An input index exceeds its input width of 2"

The error points to the Park Transform block inside the PMSM controller.

I am feeding abc phase currents into the Clarke Transform and then into the Park Transform.
However, I am not sure whether the signal dimensions are correct or if I am missing a signal connection.

I have verified that:
– The abc signals are three-phase
– The electrical angle is connected
– No manual indexing is used

What is the correct signal dimension and connection for the Park Transform in a PMSM FOC model?I am simulating a PMSM drive using Field-Oriented Control in Simulink.
The model uses Clarke and Park transforms to generate Id and Iq currents.

When I run the simulation, I get the following error:

"An input index exceeds its input width of 2"

The error points to the Park Transform block inside the PMSM controller.

I am feeding abc phase currents into the Clarke Transform and then into the Park Transform.
However, I am not sure whether the signal dimensions are correct or if I am missing a signal connection.

I have verified that:
– The abc signals are three-phase
– The electrical angle is connected
– No manual indexing is used

What is the correct signal dimension and connection for the Park Transform in a PMSM FOC model? I am simulating a PMSM drive using Field-Oriented Control in Simulink.
The model uses Clarke and Park transforms to generate Id and Iq currents.

When I run the simulation, I get the following error:

"An input index exceeds its input width of 2"

The error points to the Park Transform block inside the PMSM controller.

I am feeding abc phase currents into the Clarke Transform and then into the Park Transform.
However, I am not sure whether the signal dimensions are correct or if I am missing a signal connection.

I have verified that:
– The abc signals are three-phase
– The electrical angle is connected
– No manual indexing is used

What is the correct signal dimension and connection for the Park Transform in a PMSM FOC model? simulink, pmsm, field-oriented-control, park-trans MATLAB Answers — New Questions

​

Simple simulink model converted to app via App Generator & App Designer.
Trying to load last values (from a .mat file) for a given item via callback on Start Button (app.StartStopButton), PreStartFcn.
I check if the file is available, load, then set app value (code below). This results in the GUI correctly displaying the value, however, the underlying component/value (referred to hereafter as the "model value") that the GUI is connected to doesn’t reflect the state of the GUI and is set to the underlying constant value defined in the model. Confirmed model value not loaded during startup via saving state of model value to file via File Log blocks and observing state via SDI. Can also verify value via calculation value is used for that is displayed on the GUI.
The GUI is definitely connected to the model value as when the GUI is updated by the user (after the Start button is pressed), the model value syncs to the GUI state… it is just this initial load that will only update the GUI.
function StartStopButtonPreStart(app, event) % Callback called on Start (pre or post, doesn’t matter).
if isfile(‘DST.mat’)
loadedData = load(‘DST.mat’);
app.DST_Enabled_Value.Value = loadedData.value; % This updates the GUI, but not underlying model value.
end
end

% generic code created by default when utilizing app generator & app
% designer
function startupFcn(app)
% … other setup …
hInst = slrealtime.Instrument();
DST_Enabled_Value_values = [0 1];
DST_Enabled_Value_labels = [0 1];
targetSelector = app.TargetSelector;
slrtcomp = slrealtime.ui.tool.ParameterTuner(app.UIFigure, ‘TargetSource’, targetSelector);
slrtcomp.Component = app.DST_Enabled_Value;
slrtcomp.BlockPath = ‘DST_TimeZone_Test/Subsystem Reference/DST_Enabled’;
slrtcomp.ParameterName = ‘Value’;
slrtcomp.ConvertToComponent = @(val)app.convertValueToValue(val, DST_Enabled_Value_values, DST_Enabled_Value_labels);
slrtcomp.ConvertToTarget = @(val)app.convertValueToValue(val, DST_Enabled_Value_labels, DST_Enabled_Value_values);

slrtInstrumentsComponent = slrealtime.ui.tool.InstrumentManager(app.UIFigure, ‘TargetSource’, targetSelector);
slrtInstrumentsComponent.Instruments = hInst;
% … other setup …
endSimple simulink model converted to app via App Generator & App Designer.
Trying to load last values (from a .mat file) for a given item via callback on Start Button (app.StartStopButton), PreStartFcn.
I check if the file is available, load, then set app value (code below). This results in the GUI correctly displaying the value, however, the underlying component/value (referred to hereafter as the "model value") that the GUI is connected to doesn’t reflect the state of the GUI and is set to the underlying constant value defined in the model. Confirmed model value not loaded during startup via saving state of model value to file via File Log blocks and observing state via SDI. Can also verify value via calculation value is used for that is displayed on the GUI.
The GUI is definitely connected to the model value as when the GUI is updated by the user (after the Start button is pressed), the model value syncs to the GUI state… it is just this initial load that will only update the GUI.
function StartStopButtonPreStart(app, event) % Callback called on Start (pre or post, doesn’t matter).
if isfile(‘DST.mat’)
loadedData = load(‘DST.mat’);
app.DST_Enabled_Value.Value = loadedData.value; % This updates the GUI, but not underlying model value.
end
end

% generic code created by default when utilizing app generator & app
% designer
function startupFcn(app)
% … other setup …
hInst = slrealtime.Instrument();
DST_Enabled_Value_values = [0 1];
DST_Enabled_Value_labels = [0 1];
targetSelector = app.TargetSelector;
slrtcomp = slrealtime.ui.tool.ParameterTuner(app.UIFigure, ‘TargetSource’, targetSelector);
slrtcomp.Component = app.DST_Enabled_Value;
slrtcomp.BlockPath = ‘DST_TimeZone_Test/Subsystem Reference/DST_Enabled’;
slrtcomp.ParameterName = ‘Value’;
slrtcomp.ConvertToComponent = @(val)app.convertValueToValue(val, DST_Enabled_Value_values, DST_Enabled_Value_labels);
slrtcomp.ConvertToTarget = @(val)app.convertValueToValue(val, DST_Enabled_Value_labels, DST_Enabled_Value_values);

slrtInstrumentsComponent = slrealtime.ui.tool.InstrumentManager(app.UIFigure, ‘TargetSource’, targetSelector);
slrtInstrumentsComponent.Instruments = hInst;
% … other setup …
end Simple simulink model converted to app via App Generator & App Designer.
Trying to load last values (from a .mat file) for a given item via callback on Start Button (app.StartStopButton), PreStartFcn.
I check if the file is available, load, then set app value (code below). This results in the GUI correctly displaying the value, however, the underlying component/value (referred to hereafter as the "model value") that the GUI is connected to doesn’t reflect the state of the GUI and is set to the underlying constant value defined in the model. Confirmed model value not loaded during startup via saving state of model value to file via File Log blocks and observing state via SDI. Can also verify value via calculation value is used for that is displayed on the GUI.
The GUI is definitely connected to the model value as when the GUI is updated by the user (after the Start button is pressed), the model value syncs to the GUI state… it is just this initial load that will only update the GUI.
function StartStopButtonPreStart(app, event) % Callback called on Start (pre or post, doesn’t matter).
if isfile(‘DST.mat’)
loadedData = load(‘DST.mat’);
app.DST_Enabled_Value.Value = loadedData.value; % This updates the GUI, but not underlying model value.
end
end

% generic code created by default when utilizing app generator & app
% designer
function startupFcn(app)
% … other setup …
hInst = slrealtime.Instrument();
DST_Enabled_Value_values = [0 1];
DST_Enabled_Value_labels = [0 1];
targetSelector = app.TargetSelector;
slrtcomp = slrealtime.ui.tool.ParameterTuner(app.UIFigure, ‘TargetSource’, targetSelector);
slrtcomp.Component = app.DST_Enabled_Value;
slrtcomp.BlockPath = ‘DST_TimeZone_Test/Subsystem Reference/DST_Enabled’;
slrtcomp.ParameterName = ‘Value’;
slrtcomp.ConvertToComponent = @(val)app.convertValueToValue(val, DST_Enabled_Value_values, DST_Enabled_Value_labels);
slrtcomp.ConvertToTarget = @(val)app.convertValueToValue(val, DST_Enabled_Value_labels, DST_Enabled_Value_values);

slrtInstrumentsComponent = slrealtime.ui.tool.InstrumentManager(app.UIFigure, ‘TargetSource’, targetSelector);
slrtInstrumentsComponent.Instruments = hInst;
% … other setup …
end simulink, startup loading, gui but not target MATLAB Answers — New Questions

​

Hi,
I am using copy graphics to copy my figures. I am running into a problem though.
figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","vector")
Will copy a plot that looks like this when pasted into microsoft Word:

Notice the extra padding at the bottom and on the right.
If I do the same code but with the image content type:

figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","image")
Then the resulting pasted image has no padding:

Note: the "Padding" option works, but when I add a "Padding" of 60 then I still have more padding on the right and bottom of the image.

I tried pasting it into another program, Inkscape, and it didn’t have the padding error. So it must be something to do with microsoft Word (and OneNote as well). I also can copy the axes from the toolstrip and it has the same padding error.
This error only occurs in Matlab 2025b. I also tried it in Matlab 2022a and that error is gone. So it must be something with the newer versions of matlab and it is something that matlab workers could fix.
If anyone has any idea what is going on that would be great.Hi,
I am using copy graphics to copy my figures. I am running into a problem though.
figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","vector")
Will copy a plot that looks like this when pasted into microsoft Word:

Notice the extra padding at the bottom and on the right.
If I do the same code but with the image content type:

figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","image")
Then the resulting pasted image has no padding:

Note: the "Padding" option works, but when I add a "Padding" of 60 then I still have more padding on the right and bottom of the image.

I tried pasting it into another program, Inkscape, and it didn’t have the padding error. So it must be something to do with microsoft Word (and OneNote as well). I also can copy the axes from the toolstrip and it has the same padding error.
This error only occurs in Matlab 2025b. I also tried it in Matlab 2022a and that error is gone. So it must be something with the newer versions of matlab and it is something that matlab workers could fix.
If anyone has any idea what is going on that would be great. Hi,
I am using copy graphics to copy my figures. I am running into a problem though.
figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","vector")
Will copy a plot that looks like this when pasted into microsoft Word:

Notice the extra padding at the bottom and on the right.
If I do the same code but with the image content type:

figure;
plot(randn(5,1));
copygraphics(gcf, "ContentType","image")
Then the resulting pasted image has no padding:

Note: the "Padding" option works, but when I add a "Padding" of 60 then I still have more padding on the right and bottom of the image.

I tried pasting it into another program, Inkscape, and it didn’t have the padding error. So it must be something to do with microsoft Word (and OneNote as well). I also can copy the axes from the toolstrip and it has the same padding error.
This error only occurs in Matlab 2025b. I also tried it in Matlab 2022a and that error is gone. So it must be something with the newer versions of matlab and it is something that matlab workers could fix.
If anyone has any idea what is going on that would be great. copygraphics, export MATLAB Answers — New Questions

​

Hello, I’m using this code

parfor k=1:10
[..]=pca(..)
end

I have 2 definitions of pca (the matlab package and another package). I’ve set the search path to use the matlab package by default, but inside the parloop the other function is used instead. I didn’t found a way to arrange this without removing the other package.
ThanksHello, I’m using this code

parfor k=1:10
[..]=pca(..)
end

I have 2 definitions of pca (the matlab package and another package). I’ve set the search path to use the matlab package by default, but inside the parloop the other function is used instead. I didn’t found a way to arrange this without removing the other package.
Thanks Hello, I’m using this code

parfor k=1:10
[..]=pca(..)
end

I have 2 definitions of pca (the matlab package and another package). I’ve set the search path to use the matlab package by default, but inside the parloop the other function is used instead. I didn’t found a way to arrange this without removing the other package.
Thanks parfor, path MATLAB Answers — New Questions

​

Windows devices using ARM hardware, such as the Snapdragon X Elite, have two ways to run applications. Applications built for Windows on ARM run natively, while apps built for x86-64 processors run in the Prism emulator. Is MATLAB supported on Windows ARM devices?Windows devices using ARM hardware, such as the Snapdragon X Elite, have two ways to run applications. Applications built for Windows on ARM run natively, while apps built for x86-64 processors run in the Prism emulator. Is MATLAB supported on Windows ARM devices? Windows devices using ARM hardware, such as the Snapdragon X Elite, have two ways to run applications. Applications built for Windows on ARM run natively, while apps built for x86-64 processors run in the Prism emulator. Is MATLAB supported on Windows ARM devices?  MATLAB Answers — New Questions

​

I have a scatterplot that forms multiple rays and I need to know the coordinates of the points at the ends of each ray.
My code is as follows:
data1 = readtable(‘600psi_15k_FT.txt’);
data2 = readtable(‘1000psi_10k_FT.txt’);
x1=data1.Var1;
y1=data1.Var2;
x2=data2.Var1;
y2=data2.Var2;
[peaks,locs]=findpeaks(y2,MinPeakHeight=0.003,MinPeakProminence=0.0006)
figure;
hold on;
plot(x1, y1, ‘b-‘, ‘DisplayName’, ‘600psi’);
plot(x2, y2, ‘r-‘, ‘DisplayName’, ‘1000psi’);
plot(x2(locs), peaks, ‘ro’, ‘MarkerFaceColor’, ‘r’, ‘DisplayName’, ‘Peaks’);
legend show;
hold off;

other_peaks = y1(locs);

scatter(peaks,other_peaks);
plot(peaks,other_peaks,’-o’)I have a scatterplot that forms multiple rays and I need to know the coordinates of the points at the ends of each ray.
My code is as follows:
data1 = readtable(‘600psi_15k_FT.txt’);
data2 = readtable(‘1000psi_10k_FT.txt’);
x1=data1.Var1;
y1=data1.Var2;
x2=data2.Var1;
y2=data2.Var2;
[peaks,locs]=findpeaks(y2,MinPeakHeight=0.003,MinPeakProminence=0.0006)
figure;
hold on;
plot(x1, y1, ‘b-‘, ‘DisplayName’, ‘600psi’);
plot(x2, y2, ‘r-‘, ‘DisplayName’, ‘1000psi’);
plot(x2(locs), peaks, ‘ro’, ‘MarkerFaceColor’, ‘r’, ‘DisplayName’, ‘Peaks’);
legend show;
hold off;

other_peaks = y1(locs);

scatter(peaks,other_peaks);
plot(peaks,other_peaks,’-o’) I have a scatterplot that forms multiple rays and I need to know the coordinates of the points at the ends of each ray.
My code is as follows:
data1 = readtable(‘600psi_15k_FT.txt’);
data2 = readtable(‘1000psi_10k_FT.txt’);
x1=data1.Var1;
y1=data1.Var2;
x2=data2.Var1;
y2=data2.Var2;
[peaks,locs]=findpeaks(y2,MinPeakHeight=0.003,MinPeakProminence=0.0006)
figure;
hold on;
plot(x1, y1, ‘b-‘, ‘DisplayName’, ‘600psi’);
plot(x2, y2, ‘r-‘, ‘DisplayName’, ‘1000psi’);
plot(x2(locs), peaks, ‘ro’, ‘MarkerFaceColor’, ‘r’, ‘DisplayName’, ‘Peaks’);
legend show;
hold off;

other_peaks = y1(locs);

scatter(peaks,other_peaks);
plot(peaks,other_peaks,’-o’) scatterplot, coordinates MATLAB Answers — New Questions

​

Dear all,
I am trying some tests with "isAlways" in order to check that a rater long algebraic expression is always positive, assuming that all its variables are positive.
One of the tests is the following
syms a b c d e f g real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0)
assumeAlso(a + b + c + d + e + f + g <=1)
isAlways(a+b<=1)

ans =

logical

1
which correctly says that if a,b,c,d,e,f,g are real and positive numbers with their sum less or equal to 1, then also the sum of the first two is less or equal to 1.
But when I try the same test with one additional variable, then
syms a b c d e f g m real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0 & m>=0)
assumeAlso(a + b + c + d + e + f + g +m <=1)
isAlways(a+b<=1)
Warning: Unable to prove ‘a + b <= 1’.
> In mupadengine/evalin2logical
In mupadengine/feval2logical
In sym/isAlways (line 39)

ans =

logical

0
How is this possible?Dear all,
I am trying some tests with "isAlways" in order to check that a rater long algebraic expression is always positive, assuming that all its variables are positive.
One of the tests is the following
syms a b c d e f g real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0)
assumeAlso(a + b + c + d + e + f + g <=1)
isAlways(a+b<=1)

ans =

logical

1
which correctly says that if a,b,c,d,e,f,g are real and positive numbers with their sum less or equal to 1, then also the sum of the first two is less or equal to 1.
But when I try the same test with one additional variable, then
syms a b c d e f g m real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0 & m>=0)
assumeAlso(a + b + c + d + e + f + g +m <=1)
isAlways(a+b<=1)
Warning: Unable to prove ‘a + b <= 1’.
> In mupadengine/evalin2logical
In mupadengine/feval2logical
In sym/isAlways (line 39)

ans =

logical

0
How is this possible? Dear all,
I am trying some tests with "isAlways" in order to check that a rater long algebraic expression is always positive, assuming that all its variables are positive.
One of the tests is the following
syms a b c d e f g real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0)
assumeAlso(a + b + c + d + e + f + g <=1)
isAlways(a+b<=1)

ans =

logical

1
which correctly says that if a,b,c,d,e,f,g are real and positive numbers with their sum less or equal to 1, then also the sum of the first two is less or equal to 1.
But when I try the same test with one additional variable, then
syms a b c d e f g m real
assume(a >=0 & b>=0 & c>=0 & d>=0 & e>=0 & f>=0 & g>=0 & m>=0)
assumeAlso(a + b + c + d + e + f + g +m <=1)
isAlways(a+b<=1)
Warning: Unable to prove ‘a + b <= 1’.
> In mupadengine/evalin2logical
In mupadengine/feval2logical
In sym/isAlways (line 39)

ans =

logical

0
How is this possible? isalways, positivity, assume, assumealso MATLAB Answers — New Questions

​